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  • TTPhotoViewController: How to show small images

    - by Sali
    Hi, I posted this question on Three20 google group but did not get any response. So I thought I try this forum. I am using TTPhotoViewController to display photos. I am following sample code given in Three20 sample project: TTCatalog/PhotoTest1Controller.m. In my case some of the images are less than (320,480). The problem which I am facing is that when my image is 200*300 then TTPhotoViewController re-sizes it to full screen on load which distorts the image. I was wondering if there is a way to tell TTPhotoViewController to display image in its actual size and not to resize it. The only thing which I have changed is viewDidLoad function in PhotoTest1Controller.m. (void)viewDidLoad { self.photoSource = [[[MockPhotoSource alloc] initWithType:MockPhotoSourceNormal title:@"Photo 1" photos:[NSArray arrayWithObjects:[[[MockPhoto alloc] initWithURL:@"http://test/test.jpg" smallURL:@"http://test/test.jpg" size:CGSizeMake(200, 300) caption:@"This is a caption."] autorelease], nil] photos2:nil] autorelease]; } I will appreciate your help. Thanks

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  • Ready to Build? Own Website Construction Ramping Up

    Organisations around the world are becoming increasingly aware that the ability to Build their own website is critical for future growth. The onset of extremely effective "build my own website" programs and software is causing businesses to question the value of paying top dollar to have their online presence outsourced. Employees who develop the skills of website creation and internet marketing will become invaluable to their companies. Without employees who have developed these skills, businesses will find themselves falling way behind.

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  • How can I use multiple PHP header content types on the same page? is this possible?

    - by Jon
    Is it possible to use multiple header types in one document? For example: header("Content-type: image/jpeg"); header('Content-Type: text/html; charset=utf-8'); returns the whole page as text/html... while header('Content-Type: text/html; charset=utf-8'); header("Content-type: image/jpeg"); Returns the whole page as an image.... How can I use both types of content on the same page? I'm using ob_start() at the top and ob_end_flush() at the beginning.

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  • matlab: how to transform screen pixels into specific coordinates

    - by user3137385
    I have to draw a curve captured on a image using screen pixels (mouse clicks) into a coordinate system. E.g.: Pixels on the screen, from left to right (130 px to 970 px) correspond to the x-axis of my coordinate system (1000 to 6000). Pixels from bottom to top (670 to 99) correspond to the y-axis of coordinate system (0 to 1.2). How can this be done? Maybe there's a function in matlab doing something like that? Some more explanation: I have a jpg image of a curve on a coordinate system. I've got pixel positions (x,y) of several points on that curve. Now I want to plot same curve into a matlab figure with same x and y axis as on the jpg image.

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  • Bitmap.Save problems

    - by user284026
    Hello, can anyone tell me if you know to be a problem with Bitmap and steganography for WM 6? I am working on a project and i have to hide a digital signature in a bitmap. The algorithm works perfect, as in untill i have the image on the memory the bitmap contains the modified bytes. But after i save the image (Bitmap.Save()) and I reopen the image, than those bytes are lost. When i say lost i mean they are the orriginal bytes from when the picture was taken. Thank you.

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  • How to force Share Intent to open a specific app?

    - by AndroidUser99
    I like share intent, it is perfect to open sharing apps with image and text parameters. But now i'm researching the way to force share intent to open a specific app from the list, with the paramters given to the share intent. This is my actual code, it shows the list of sharing apps installed on the phone. Please, can somedone tell me what i should add to the code to force for example official twitter app? and official faccebok app? Intent sharingIntent = new Intent(Intent.ACTION_SEND); Uri screenshotUri = Uri.parse("file:///sdcard/test.jpg"); sharingIntent.setType("image/*"); sharingIntent.putExtra(Intent.EXTRA_TEXT, "body text"); sharingIntent.putExtra(Intent.EXTRA_STREAM, screenshotUri); startActivity(Intent.createChooser(sharingIntent, "Share image using")); Thanks

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  • iPhone SDK - How to display a photo taken with the camera inside a UINavigationController?

    - by dan
    This is my code so far: /* class: myViewController @interface myViewController: UIViewController <UIImagePickerControllerDelegate, UINavigationControllerDelegate> */ - (IBAction) getPicture { UIImagePickerController * picker = [[UIImagePickerController alloc] init]; picker.delegate = self; picker.sourceType = UIImagePickerControllerSourceTypeCamera; [self presentModalViewController:picker animated:YES]; } - (void) imagePickerController:(UIImagePickerController *)thePicker didFinishPickingMediaWithInfo:(NSDictionary *)imageInfo { [[thePicker parentViewController] dismissModalViewControllerAnimated:YES]; UIImage *img = [imageInfo objectForKey:@"UIImagePickerControllerOriginalImage"]; self.myImageView.image = img; } So basically I'm trying to get a photo from the iPhone camera and display it in a UIImageView. This works perfectly fine as long the class myViewController is displayed as a standalone view. If I'm putting the View inside a UINavigationController the UIImageView won't display the image after taking one with the camera. But if I choose a picture from the library everything is fine again. So why does the UIImageView won't display a image taken with the camera inside a UINavigationController?

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  • copying the contents of a binary file

    - by Ganesh
    I am designing an image decoder and as a first step I tried to just copy the using c. i.e open the file, and write its contents to a new file. Below is the code that I used. while((c=getc(fp))!=EOF) fprintf(fp1,"%c",c); where fp is the source file and fp1 is the destination file. The program executes without any error, but the image file(".bmp") is not properly copied. I have observed that the size of the copied file is less and only 20% of the image is visible, all else is black. When I tried with simple text files, the copy was complete. Do you know what the problem is?

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  • Déploiement et configuration réseau (firewall) d'une instance CloudStack avec Apache préinstallé, troisième tutoriel d'une série sur Cloudstack

    Bonjour, Citation: CloudStack est un logiciel de cloud computing open source pour la création, la gestion et le déploiement de services de cloud d'infrastructure. Il utilise des hyperviseurs existants tels que KVM, vSphere, XenServer et / XCP pour la virtualisation. En plus de sa propre API, CloudStack prend également en charge les Amazon Web Services. Voici une série de tests effectués par Ikoula sur ce logiciel. Je vous présente ce troisième tutoriel sur Cloudstack:Déploiement...

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  • Série de tutoriels sur la réalisation d'un émulateur console complet, écrit par BestCoder

    Bonjour à tous,La rubrique 2D/3D/Jeux vous propose des tutoriels sur la création d'un émulateur Chip 8. Celui-ci vous introduira dans le monde l'émulation et vous apprendra à créer votre tout premier émulateur console.Ainsi, vous apprendrez à rechercher les informations nécessaires avant de vous lancer dans la lourde tâche de créer un émulateur, à simuler le comportement des processeurs d'une console, lire une ROM...Bonne lecture

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  • Where is the time spent?

    - by 280Z28
    Game development is a large process. In your experience, how are the total hours for releasing a game divided over the following major areas. I believe this is useful because few people (none?) are really good at all the areas, so this helps me balance the cost of items I'm not so good at when estimating the complexity of creating a game. Modeling and raw asset creation (textures, audio) Level design Gameplay design Programming Testing Marketing

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  • css background Outlook 2007

    - by user112976
    Hi, I creating a program which send newsletter with a background image. It works fine on Office 2000-2003, thunderbird, but the background image does not show on Outlook 2007. I read that Microsoft changed the rendering engine and did not support the background css property (it is possible but only applied to the Body). Is it achievable to create an email which will render like that : http://www.freeimagehosting.net/image.php?a7905f7d16.png on Outlook 2007 ? What is the solution ? Thank you for your help.

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  • ASP.Net Problem with View Control

    - by tking
    I admit, I'm an .NET n00b. Basically what I'm trying to do is I have a page with a text box on it and an image button. On click of the image button I want it to show a view control I have set up. Inside this view control is an image and some text. So this is what I have in my code-behind. protected void btnSubmit_Click(object sender, ImageClickEventArgs e) { string email = txtUnsubscribe.Text; vwSuccess.Visible = true; } Simple right? Well when I click on the button for submit, I get the "Object reference not set to an instance of an object." error message. Where am I going wrong?

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  • Quel EDI utilisez-vous pour vos développements Android ? Quels en sont les principaux atouts ?

    Quel EDI utilisez-vous pour vos développements Android ? Quels en sont les principaux atouts ?L'écosystème mobile est en plein essor et de nombreux développeurs se sont déjà lancés dans la création d'applications pour plateformes mobiles.Android, de part son positionnement comme OS mobile dominant, bénéficie d'une attention particulière des développeurs.Si vous avez déjà développé une application Android (ou envisagez de le faire), quel environnement de développement intégré (EDI) avez-vous utilisé...

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  • What is wrong with my JPGEncoder

    - by hitek
    Here is my code if (event.target.content is Bitmap) { infotext.text = "got something"; var image:Bitmap = Bitmap(event.target.content); var bitmapData:BitmapData = image.bitmapData; this.addChild(image); var j:JPGEncoder = new JPGEncoder(100); var bytes:ByteArray = new ByteArray(); bytes=j.encode(bitmapData); } else { throw new Error("What the heck bob?"); } When I run a debug session everything works fine till it reaches to the line bytes=j.encode(bitmapData); after that nothing happens and my program just goes into limbo Please help

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  • Is there a way to cut and paste or clone CSS from one element to another using JQuery?

    - by Jared Christensen
    I have a situation where I'm wrapping an image with a span and I want to remove all the CSS from the image and apply it to the span. Is there a way to do this with JQuery? JQuery: $(img).wrap('<span />'); Style Sheet: img { border: 5px solid red; padding: 10px; … } I would like do to do this with out editing the HTML or CSS. For example adding a class to the image would not work very well in my situation. I need a way to truly remove the CSS from one element and place it on another.

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  • Right way to implement a n-to-m related

    - by ThreeFingerMark
    Hello, this is a part from my database structure: Table: Item Columns: ItemID, Title, Content, Price Table: Tag Columns: TagID, Title Table: ItemTag Columns: ItemID, TagID Table: Image Columns: ImageID, Path, Size, UploadDate Table: ItemImage Columns: ItemID, ImageID The items can have more than one image so i have a extra table "Image" and map this images to an items. I see now a problem with this structure. Before i can add Images i must enter an item. My question is now. Is this structure a good way to solve my problem with many images / tags for one item? Thank you

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  • External Javascript file fails to receive variables from previous javascript block

    - by Franc
    I've been searching the net for several hours and can't find an answer in the whole "external js file"-jungle. I hope you guys can help! In short: My external javascript file doesn't seem to get the variables which I defined in the main.php file.. On main.php I define php variables and "transform" them into javascript variables <head>... <script type="text/javascript"> var phpmain_img = <?php echo json_encode($main_img); ?>; var phpvar1_large = <?php echo json_encode($var1_large); ?>; var phpvar2_large = <?php echo json_encode($var2_large); ?>; var phpvar3_large = <?php echo json_encode($var3_large); ?>; var phpvar4_large = <?php echo json_encode($var4_large); ?>; </script> ... <script language="javascript" type="text/javascript" src="/wshop/ext.js"></script> </head> In my ext.js file I want to process those variables. In the ext.js file I defined a the function swapImage() that will be used back in the main PHP: var imgArray = new Array( phpmain_img, phpvar1_large, phpvar2_large, phpvar3_large ); function swapImage(imgID) { var theImage = document.getElementById('theImage'); var newImg; newImg = imgArray[imgID]; theImage.src = newImg; } function preloadImages() { for(var i = 0; i < imgArray.length; i++) { var tmpImg = new Image; tmpImg.src = imgArray[i]; } } Result: The swapImage() in the main.php... doesnt work <div id="image"> <img id="theImage" src="<?=$main_img; ?>" alt="" /> </div> <div id="thumbs"> <?php echo "<img src=\"<$main_img_small\" alt=\"\" onmouseover=\"swapImage(0);\">"; echo "<img src=\"$var1_small\" alt=\"\" onmouseover=\"swapImage(1);\">"; echo "<img src=\"$var2_small\" alt=\"\" onmouseover=\"swapImage(2);\">"; echo "<img src=\"$var3_small\" alt=\"\" onmouseover=\"swapImage(3);\">"; ?> <br /> </div> Any help is greatly appreciated! UPDATE: I don't get a specific error, the swapImage functions doesn't work at mouseover. However, I tried to output the variables with e.g. document.write(phpimg_main) but nothing appears which makes me believe that there's something wrong with the handing over of the variables... here's the source code browser output `<html> <head> <link href="../demo.css" rel="stylesheet" type="text/css" /> <style type="text/css"> .... </style> <script type="text/javascript"> var phpmain_img = {"0":"http:\/\/path\/to\/main\/image.jpg"}; var phpvar1_large = {"0":"http:\/\/path\/to\/image1.jpg"}; var phpvar2_large = {"0":"http:\/\/path\/to\/image2.jpg"}; var phpvar3_large = null; var phpvar4_large = null; </script> <script language="javascript" type="text/javascript" src="/wshop/ext.js"></script> </head> <body onload="preloadImages()"> <div id="image"> <img id="theImage" src="http://path-to-main-image.jpg" alt="" /> </div> <div id="thumbs"> <img src="http://path-to-main-image.jpg" alt="" onmouseover="swapImage(0);"><img src="http://path-to-image1.jpg" alt="" onmouseover="swapImage(1);"><img src="http://path-to-image2.jpg" alt="" onmouseover="swapImage(2);"> <br /> </div> </body> `

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  • jQuery IE7 on-the-fly images

    - by Scott Evernden
    The simplified version of the problem I am seeing in IE7 can be demonstated using FireBug Lite. On a page loaded with jQuery, I open FireBug Lite (via bookmarket) and I enter the following: image = $('<img src="http://example.com/boofar.jpg" border="12" width="95" height="95" title="Booya">')[0]; and the result echoed is: <img title="Booya" contentEditable="inherit" start="fileopen" loop="1" src="http://example.com/boofar.jpg" border="12"> Where are the width and height attributes? Furthermore, image.width; and image.attributes.width.value; return 0 and "0". Seen this with both jQuery 1.2.6 as well as 1.4.2. It does the right thing in IE8 and FF. Any ideas where those attributes went? Very annoying....

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  • Cell contents changing after I select rows present outside its height?

    - by wolverine
    I have set the size of the tableView that I show as the popoverController as 4*rowheight. And I am using 12cells in the tableView. Each cell contains an image and a label. I can see all the cells by scrolling. Upto 5th cell its ok. After th2 5th cell, the label and the image that I am using in the first four cells are being repeated for the remaining cells. And If I select the cell, the result is accurately shown. But when I again take the tableView, the image and labels are not accurate even for the first 5 cells. All are changed but the selection is giving the correct result. Did anyone got the idea what the problem is??

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  • How to match the word in jquery

    - by Mirage
    I have the image and i am fade in and fade out the image on click. But i want that if the same is present then it should not fadein/fadeout. My jquery code is switch(current_id) { case 'l1': $("#left_img img").fadeOut(500, function() { $(this).attr("src","rrr.gif").load( function() { $(this).fadeIn(500); }); }); break; case 'l3': $("#left_img img").fadeOut(500, function() { $(this).attr("src","cc1.gif").load( function() { $(this).fadeIn(500); }); }); break; If i click on link 1 then image A appears with fade effect. but if i click again link 1 agan , then again i see fade effect . Is there any way i can avoid that if same link is clicked again

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  • How to set cell's background in HTML table ?

    - by misha-moroshko
    I would like to set the background of a cell in HTML table to be like this. What are my options besides using an image as background ? Are there any predefined backgrounds like this ? Maybe dotted, or diagonal lines backgrounds ? In case of image background, if I don't know in advance what would be the size of the cell, what image size should I take ? How to make it be repetitive so it would look nice ? Any HTML/CSS/Javascript/jQuery suggestions are welcome :)

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  • How to make this jpeg compression faster

    - by Richard Knop
    I am using OpenCV to compress binary images from a camera: vector<int> p; p.push_back(CV_IMWRITE_JPEG_QUALITY); p.push_back(75); // JPG quality vector<unsigned char> jpegBuf; cv::imencode(".jpg", fIplImageHeader, jpegBuf, p); The code above compresses a binary RGB image stored in fIplImageHeader to a JPEG image. For a 640*480 image it takes about 0.25 seconds to execute the five lines above. Is there any way I could make it faster? I really need to repeat the compression more than 4 times a second.

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