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  • List Directories and get the name of the Directory

    - by chrissygormley
    Hello, I am trying to get the code to list all the directories in a folder, change directory into that folder and get the name of the current folder. The code I have so far is below and isn't working at the minute. I seem to be getting the parent folder name. import os for directories in os.listdir(os.getcwd()): dir = os.path.join('/home/user/workspace', directories) os.chdir(dir) current = os.path.dirname(dir) new = str(current).split("-")[0] print new I also have other files in the folder but I do not want to list them. I have tried the below code but I haven't got it working yet either. for directories in os.path.isdir(os.listdir(os.getcwd())): Can anyone see where I am going wrong? Thanks

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  • Using Windows 7 taskbar features in PyQt

    - by Matze
    Hi all. I am looking for information on the integration of some of the new Windows 7 taskbar features into my PyQt applications. Specifically if there already exists the possibility to use the new progress indicator (see here) and the quick links (www.petri.co.il/wp-content/uploads/new_win7_taskbar_features_8.gif). If anyone could provide a few links or just a "not implemented yet", I'd be very grateful. Thanks a lot.

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  • How do I join three tables with SQLalchemy and keeping all of the columns in one of the tables?

    - by jimka
    So, I have three tables: The class defenitions: engine = create_engine('sqlite://test.db', echo=False) SQLSession = sessionmaker(bind=engine) Base = declarative_base() class Channel(Base): __tablename__ = 'channel' id = Column(Integer, primary_key = True) title = Column(String) description = Column(String) link = Column(String) pubDate = Column(DateTime) class User(Base): __tablename__ = 'user' id = Column(Integer, primary_key = True) username = Column(String) password = Column(String) sessionId = Column(String) class Subscription(Base): __tablename__ = 'subscription' userId = Column(Integer, ForeignKey('user.id'), primary_key=True) channelId = Column(Integer, ForeignKey('channel.id'), primary_key=True) And the SQL commands that are executed to create them: CREATE TABLE subscription ( "userId" INTEGER NOT NULL, "channelId" INTEGER NOT NULL, PRIMARY KEY ("userId", "channelId"), FOREIGN KEY("userId") REFERENCES user (id), FOREIGN KEY("channelId") REFERENCES channel (id) ); CREATE TABLE user ( id INTEGER NOT NULL, username VARCHAR, password VARCHAR, "sessionId" VARCHAR, PRIMARY KEY (id) ); CREATE TABLE channel ( id INTEGER NOT NULL, title VARCHAR, description VARCHAR, link VARCHAR, "pubDate" TIMESTAMP, PRIMARY KEY (id) ); NOTE: I know user.username should be unique, need to fix that, and I'm not sure why SQLalchemy creates some row names with the double-quotes. And I'm trying to come up with a way to retrieve all of the channels, as well as an indication on what channels one particular user (identified by user.sessionId together with user.id) has a subscription on. For example, say we have four channels: channel1, channel2, channel3, channel4; a user: user1; who has a subscription on channel1 and channel4. The query for user1 would return something like: channel.id | channel.title | subscribed --------------------------------------- 1 channel1 True 2 channel2 False 3 channel3 False 4 channel4 True This is a best-case result, but since I have absolutely no clue as how to accomplish the subscribed column, I've been instead trying to get the particular users id in the rows where the user has a subscription and where a subscription is missing, just leave it blank. The database engine that I'm using together with SQLalchemy atm. is sqlite3 I've been scratching my head over this for two days now, I've no problem joining together all three by way of the subscription table but then all of the channels where the user does not have a subscription gets omitted. I hope I've managed to describe my problem sufficiently, thanks in advance.

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  • Django says the "id may not be NULL" but why is it?

    - by Oli
    I'm going crazy today. I just tried to insert a new record and it threw back a "post_blogpost.id may not be NULL" error. Here's my model: class BlogPost(models.Model): title = models.CharField(max_length=100) slug = models.SlugField(max_length=100) who = models.ForeignKey(User, default=1) when = models.DateTimeField() intro = models.TextField(blank=True, null=True) content = models.TextField(blank=True, null=True) counter = models.PositiveIntegerField(default=0) published = models.BooleanField(default=False) css = models.TextField(blank=True, null=True) class Meta: ordering = ('-when', 'id') There are a number of functions beneath the model too but I won't include them in full here. Their names are: content_cache_key, clear_cache, __unicode__, reads, read, processed_content. I'm adding through the admin... And I'm running out of hair.

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  • Extending rst container to output extra div attributes

    - by Manwe
    I'm starting to use pelican with reStructuredText rst page format. I have custom javascript (jQuery) things that I'd like to control with div attributes like data-default-tpl="basename" with nested content. What to extend and what. I've looked at Directives and nodes, but I just can't wrap my head around how to do it. .. rstdiv:: class1 class2 :name: namessid :extra: thisIsMyextra .. rstdiv:: nested class3 :name: nestedid :extra: data-default-tpl="basename" some text .. container:: This is normal rst container :name: contid text From rst to html with pelican. <div id="nameisid" class="class1 class2" thisIsMyextra> <div id="nestedid" class="nested class3" data-default-tpl="basename"> some text </div> </div> <div id="contid" class="container This is normal rst container"> text </div>

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  • Should I use fork or threads?

    - by shadyabhi
    In my script, I have a function foo which basically uses pynotify to notify user about something repeatedly after a time interval say 15 minutes. def foo: while True: """Does something""" time.sleep(900) My main script has to interact with user & does all other things so I just cant call the foo() function. directly. Whats the better way of doing it and why? Using fork or threads?

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  • Getting a specific bit value in a byte string

    - by ignoramus
    There is a byte at a specific index in a byte string which represents eight flags; one flag per bit in the byte. If a flag is set, its corresponding bit is 1, otherwise its 0. For example, if I've got b'\x21' the flags would be 0001 0101 # Three flags are set at indexes 3, 5 and 7 # and the others are not set What would be the best way to get each bit value in that byte, so I know whether a particular flag is set or not? (Preferably using bitwise operations)

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  • min() and max() give error: TypeError: 'float' object is not iterable

    - by PythonUser3.3
    markList=[] Lmark=0 Hmark=0 while True: mark=float(input("Enter your marks here(Click -1 to exit)")) if mark == -1: break markList.append(mark) markList.sort() mid = len(markList)//2 if len(markList)%2==0: median=(markList[mid]+ markList[mid-1])/2 print("Median:", median) else: print("Median:" , markList[mid]) Lmark==(min(mark)) print("The lowest mark is", Lmark) Hmark==(max(mark)) print("The highest mark is", Hmark) My program is a basic grade calculator using lists. My program asks the user to input their grades into a list in which it then calculates your average and finds your lowest and highest mark. I have found the average but I can't seem to figure out how to find the lowest and highest grade. Can you please show me pr tell me what to do?

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  • Django Grouping Query

    - by Matt
    I have the following (simplified) models: class Donation(models.Model): entry_date = models.DateTimeField() class Category(models.Model): name = models.CharField() class Item(models.Model): donation = models.ForeignKey(Donation) category = models.ForeignKey(Category) I'm trying to display the total number of items, per category, grouped by the donation year. I've tried this: Donation.objects.extra(select={'year': "django_date_trunc('year', %s.entry_date)" % Donation._meta.db_table}).values('year', 'item__category__name').annotate(items=Sum('item__quantity')) But I get a Field Error on item__category__name. I've also tried: Item.objects.extra(select={"year": "django_date_trunc('year', entry_date)"}, tables=["donations_donation"]).values("year", "category__name").annotate(items=Sum("quantity")).order_by() Which generally gets me what I want, but the item quantity count is multiplied by the number of donation records. Any ideas? Basically I want to display this: 2010 - Category 1: 10 items - Category 2: 17 items 2009 - Category 1: 5 items - Category 3: 8 items

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  • Google App Engine appcfg.py data_upload Authentication fail

    - by Pradeep Upadhyay
    Hi, I am using appcfg.py to upload data to datastore from a csv file. But every time I try, I am getting error: [info ] Authentication failed even if i am using Admin id and password. In my app.yaml file I am having: handlers: - url: /remote_api script: $PYTHON_LIB/google/appengine/ext/remote_api/handler.py login: admin - url: .* script: MainHandler.py Can anybody please help me? Thanks in advance.

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  • CherryPy and RESTful web api

    - by hyperboreean
    What's the best approach of creating a RESTful web api in CherryPy? I've been looking around for a few days now and nothing seems great. For Django it seems that are lots of tools to do this, but not for CherryPy or I am not aware of them

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  • How to clone a mercurial repository over an ssh connection initiated by fabric when http authorizati

    - by Monika Sulik
    I'm attempting to use fabric for the first time and I really like it so far, but at a certain point in my deployment script I want to clone a mercurial repository. When I get to that point I get an error: err: abort: http authorization required My repository requires http authorization and fabric doesn't prompt me for the user and password. I can get around this by changing my repository address from: https://hostname/repository to: https://user:password@hostname/repository But for various reasons I would prefer not to go this route. Are there any other ways in which I could bypass this problem?

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  • Technique to remove common words(and their plural versions) from a string

    - by Jake M
    I am attempting to find tags(keywords) for a recipe by parsing a long string of text. The text contains the recipe ingredients, directions and a short blurb. What do you think would be the most efficient way to remove common words from the tag list? By common words, I mean words like: 'the', 'at', 'there', 'their' etc. I have 2 methodologies I can use, which do you think is more efficient in terms of speed and do you know of a more efficient way I could do this? Methodology 1: - Determine the number of times each word occurs(using the library Collections) - Have a list of common words and remove all 'Common Words' from the Collection object by attempting to delete that key from the Collection object if it exists. - Therefore the speed will be determined by the length of the variable delims import collections from Counter delim = ['there','there\'s','theres','they','they\'re'] # the above will end up being a really long list! word_freq = Counter(recipe_str.lower().split()) for delim in set(delims): del word_freq[delim] return freq.most_common() Methodology 2: - For common words that can be plural, look at each word in the recipe string, and check if it partially contains the non-plural version of a common word. Eg; For the string "There's a test" check each word to see if it contains "there" and delete it if it does. delim = ['this','at','them'] # words that cant be plural partial_delim = ['there','they',] # words that could occur in many forms word_freq = Counter(recipe_str.lower().split()) for delim in set(delims): del word_freq[delim] # really slow for delim in set(partial_delims): for word in word_freq: if word.find(delim) != -1: del word_freq[delim] return freq.most_common()

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  • etree.findall: 'OR'-lookup?

    - by piquadrat
    I want to find all stylesheet definitions in a XHTML file with lxml.etree.findall. This could be as simple as elems = tree.findall('link[@rel="stylesheet"]') + tree.findall('style') But the problem with CSS style definitions is that the order matters, e.g. <link rel="stylesheet" type="text/css" href="/media/css/first.css" /> <style>body:{font-size: 10px;}</style> <link rel="stylesheet" type="text/css" href="/media/css/second.css" /> if the contents of the style tag is applied after the rules in the two link tags, the result may be completely different from the one where the rules are applied in order of definition. So, how would I do a lookup that inlcudes both link[@rel="stylesheet"] and style?

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  • List available languages for PyGTK UI strings

    - by detly
    I'm cleaning up some localisation and translation settings in our PyGTK application. The app is only intended to be used under GNU/Linux systems. One of the features we want is for users to select the language used for the applications (some prefer their native language, some prefer English for consistency, some like French because it sounds romantic, etc). For this to work, I need to actually show a combo box with the various languages available. How can I get this list? In fact, I need a list of pairs of the language code ("en", "ru", etc) and the language name in the native language ("English (US)", "???????"). If I had to implement a brute force method, I'd do something like: look in the system locale dir (eg. "/usr/share/locale") for all language code dirs (eg. "en/") containing the relative path "LC_MESSAGES/OurAppName.mo". Is there a more programmatic way?

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  • Simple way to create possible case

    - by bugbug
    I have lists of data such as a = [1,2,3,4] b = ["a","b","c","d","e"] c = ["001","002","003"] And I want to create new another list that was mixed from all possible case of a,b,c like this d = ["1a001","1a002","1a003",...,"4e003"] Is there any module or method to generate d without write many for loop?

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  • django on appengine

    - by aks
    I am impressed with django.Am am currenty a java developer.I want to make some cool websites for myself but i want to host it in some third pary environmet. Now the question is can i host the django application on appengine?If yes , how?? Are there any site built using django which are already hosted on appengine?

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  • Huge amount of time sending data with suds and proxy

    - by Roman
    Hi everyone, I have the following code to send data through a proxy using suds: import suds t = suds.transport.http.HttpTransport() proxy = urllib2.ProxyHandler({'http': 'http://192.168.3.217:3128'}) opener = urllib2.build_opener(proxy) t.urlopener = opener ws = suds.client.Client('http://xxxxxxx/web.asmx?WSDL', transport=t) req = ws.factory.create('ActionRequest.request') req.SerialNumber = 'asdf' req.HostName = 'hola' res = ws.service.ActionRequest(req) I don't know why, but it can be sending data above 2 or 3 minutes, or even more and it raises a "Gateway timeout" exception sometimes. If I don't use the proxy, the amount of time used is above 2 seconds or less. Here is the SOAP reply: (ActionResponse){ Id = None Action = "Action.None" Objects = "" } The proxy is running right with other requests through urllib2, or using normal web browsers like firefox. Does anyone have any idea what's happening here with suds? Thanks a lot in advance!!!

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  • Fabric "TypeError: not all arguments converted during string formatting"

    - by Brian Carpio
    I have the following fabric task: @task def deploy_west_ec2_ami(name, puppetClass, size='m1.small', region='us-west-1', basedn='joe', ldap='arch-ldap-01', secret='secret', subnet='subnet-d43b8ab d', sgroup='sg-926578fe'): execute(deploy_ec2_ami, name='%s',puppetClass='%s',size='%s',region='%s',basedn='%s',ldap='%s',secret='%s',subnet='%s',sgroup='%s' %(name, puppetClass , size, region, basedn, ldap, secret, subnet, sgroup)) However when I run the command: fab deploy_west_ec2_ami:test,java I get the following Traceback: Traceback (most recent call last): File "/usr/local/lib/python2.6/dist-packages/fabric/main.py", line 710, in main *args, **kwargs File "/usr/local/lib/python2.6/dist-packages/fabric/tasks.py", line 321, in execute results['<local-only>'] = task.run(*args, **new_kwargs) File "/usr/local/lib/python2.6/dist-packages/fabric/tasks.py", line 113, in run return self.wrapped(*args, **kwargs) File "/home/bcarpio/Projects/githubenterprise/awsdeploy/fabfile.py", line 35, in deploy_west_ec2_ami execute(deploy_ec2_ami, name='%s',puppetClass='%s',size='%s',region='%s',basedn='%s',ldap='%s',secret='%s',subnet='%s',sgroup='%s' %(name, puppetClass, size, region, basedn, ldap, secret, subnet, sgroup)) TypeError: not all arguments converted during string formatting I am not sure I understand why. I am pretty sure I have all the values defined here just fine. Also when I run the execute task deploy_ec2_ami as so: deploy_ec2_ami:test,java,m1.small,us-west-1,'dc\=test\,dc\=net',ldap-01,secret,subnet-d43b8abd,sg-926578fe It works just fine

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  • Django Querysets -- need a less expensive way to do this..

    - by rh0dium
    Hi all, I have a problem with some code and I believe it is because of the expense of the queryset. I am looking for a much less expensive (in terms of time) way to to this.. log.info("Getting Users") employees = Employee.objects.filter(is_active = True) log.info("Have Users") if opt.supervisor: if opt.hierarchical: people = getSubs(employees, " ".join(args)) else: people = employees.filter(supervisor__name__icontains = " ".join(args)) else: log.info("Filtering Users") people = employees.filter(name__icontains = " ".join(args)) | \ employees.filter(unix_accounts__username__icontains = " ".join(args)) log.info("Filtered Users") log.info("Processing data") np = [] for person in people: unix, p4, bugz = "No", "No", "No" if len(person.unix_accounts.all()): unix = "Yes" if len(person.perforce_accounts.all()): p4 = "Yes" if len(person.bugzilla_accounts.all()): bugz = "Yes" if person.cell_phone != "": exphone = fixphone(person.cell_phone) elif person.other_phone != "": exphone = fixphone(person.other_phone) else: exphone = "" np.append({ 'name':person.name, 'office_phone': fixphone(person.office_phone), 'position': person.position, 'location': person.location.description, 'email': person.email, 'functional_area': person.functional_area.name, 'department': person.department.name, 'supervisor': person.supervisor.name, 'unix': unix, 'perforce': p4, 'bugzilla':bugz, 'cell_phone': fixphone(exphone), 'fax': fixphone(person.fax), 'last_update': person.last_update.ctime() }) log.info("Have data") Now this results in a log which looks like this.. 19:00:55 INFO phone phone Getting Users 19:00:57 INFO phone phone Have Users 19:00:57 INFO phone phone Processing data 19:01:30 INFO phone phone Have data As you can see it's taking over 30 seconds to simply iterate over the data. That is way too expensive. Can someone clue me into a more efficient way to do this. I thought that if I did the first filter that would make things easier but seems to have no effect. I'm at a loss on this one. Thanks To be clear this is about 1500 employees -- Not too many!!

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