Search Results

Search found 14399 results on 576 pages for 'python noob'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 368/576 | < Previous Page | 364 365 366 367 368 369 370 371 372 373 374 375  | Next Page >

  • How to replace empty string with zero in comma-separated string?

    - by dsaccount1
    "8,5,,1,4,7,,,,7,,1,9,3,6,,,8,6,3,9,,2,5,4,,,,,3,2,,,7,4,1,1,,4,,6,9,,5,,,,5,,,1,,6,3,,,6,5,,,,7,4,,1,7,6,,,,8,,5,,,7,1,,3,9," I'm doing a programming challenge where i need to parse this sequence into my sudoku script. Need to get the above sequence into 8,5,0,1,4,7,0,0,0,7,0,1,9,3,6,0,0,8......... I tried re but without success, help is appreciated, thanks.

    Read the article

  • Find subset with K elements that are closest to eachother

    - by Nima
    Given an array of integers size N, how can you efficiently find a subset of size K with elements that are closest to each other? Let the closeness for a subset (x1,x2,x3,..xk) be defined as: 2 <= N <= 10^5 2 <= K <= N constraints: Array may contain duplicates and is not guaranteed to be sorted. My brute force solution is very slow for large N, and it doesn't check if there's more than 1 solution: N = input() K = input() assert 2 <= N <= 10**5 assert 2 <= K <= N a = [] for i in xrange(0, N): a.append(input()) a.sort() minimum = sys.maxint startindex = 0 for i in xrange(0,N-K+1): last = i + K tmp = 0 for j in xrange(i, last): for l in xrange(j+1, last): tmp += abs(a[j]-a[l]) if(tmp > minimum): break if(tmp < minimum): minimum = tmp startindex = i #end index = startindex + K? Examples: N = 7 K = 3 array = [10,100,300,200,1000,20,30] result = [10,20,30] N = 10 K = 4 array = [1,2,3,4,10,20,30,40,100,200] result = [1,2,3,4]

    Read the article

  • Duplicate django query set?

    - by Piotr Czapla
    I have a simple django's query set like: qs = AModel.objects.exclude(state="F").order_by("order") I'd like to use it as follows: qs[0:3].update(state='F') expected = qs[3] # throws error here But last statement throws: "Cannot update a query once a slice has been taken." How can I duplicate the query set?

    Read the article

  • How do I use Django to insert a Geometry Field into the database?

    - by alex
    class LocationLog(models.Model): user = models.ForeignKey(User) utm = models.GeometryField(spatial_index=True) This is my database model. I would like to insert a row. I want to insert a circle at point -55, 333. With a radius of 10. How can I put this circle into the geometry field? Of course, then I would want to check which circles overlap a given circle. (my select statement)

    Read the article

  • Serve external template in Django

    - by AlexeyMK
    Hey, I want to do something like return render_to_response("http://docs.google.com/View?id=bla", args) and serve an external page with django arguments. Django doesn't like this (it looks for templates in very particular places). What's the easiest way make this work? Right now I'm thinking to use urllib to save the page to somewhere locally on my server and then serve with the templates pointing to there. Note: I'm not looking for anything particularly scalable here, I realize my proposal above is a little dirty.

    Read the article

  • Getting unpredictable data into a tabular format

    - by Acorn
    The situation: Each page I scrape has <input> elements with a title= and a value= I don't know what is going to be on the page. I want to have all my collected data in a single table at the end, with a column for each title. So basically, I need each row of data to line up with all the others, and if a row doesn't have a certain element, then it should be blank (but there must be something there to keep the alignment). eg. First page has: {animal: cat, colour: blue, fruit: lemon, day: monday} Second page has: {animal: fish, colour: green, day: saturday} Third page has: {animal: dog, number: 10, colour: yellow, fruit: mango, day: tuesday} Then my resulting table should be: animal | number | colour | fruit | day cat | none | blue | lemon | monday fish | none | green | none | saturday dog | 10 | yellow | mango | tuesday Although it would be good to keep the order of the title value pairs, which I know dictionaries wont do. So basically, I need to generate columns from all the titles (kept in order but somehow merged together) What would be the best way of going about this without knowing all the possible titles and explicitly specifying an order for the values to be put in?

    Read the article

  • Unable to control requests for static files on Google App Engine

    - by dan
    My simple GAE app is not redirecting to the /static directory for requests when url is multiple levels. Dir structure: /app/static/css/main.css App: I have two handlers one for /app and one for /app/new app.yaml: handlers: - url: /static static_dir: static - url: /app/static/(.*) static_dir: static\1 - url: /app/.* script: app.py login: required HTML: Description: When page is loaded from /app HTTP request for main.css is successful GET /static/css/main.css But when page is loaded from /app/new I see the following request: GET /app/static/css/main.cs That's when I tried adding the /app/static/(.*) in the app.yaml but it is not having any effect.

    Read the article

  • Performing non-blocking requests? - Django

    - by RadiantHex
    Hi folks, I have been playing with other frameworks, such as NodeJS, lately. I love the possibility to return a response, and still being able to do further operations. e.g. def view(request): do_something() return HttpResponse() do_more_stuff() #not possible!!! Maybe Django already offers a way to perform operations after returning a request, if that is the case that would be great. Help would be very much appreciated! =D

    Read the article

  • twisted reactor stops too early

    - by pygabriel
    I'm doing a batch script to connect to a tcp server and then exiting. My problem is that I can't stop the reactor, for example: cmd = raw_input("Command: ") # custom factory, the protocol just send a line reactor.connectTCP(HOST,PORT, CommandClientFactory(cmd) d = defer.Deferred() d.addCallback(lambda x: reactor.stop()) reactor.callWhenRunning(d.callback,None) reactor.run() In this code the reactor stops before that the tcp connection is done and the cmd is passed. How can I stop the reactor after that all the operation are finished?

    Read the article

  • How to make scipy.interpolate give a an extrapolated result beyond the input range?

    - by Salim Fadhley
    I'm trying to port a program which uses a hand-rolled interpolator (developed by a mathematitian colleage) over to use the interpolators provided by scipy. I'd like to use or wrap the scipy interpolator so that it has as close as possible behavior to the old interpolator. A key difference between the two functions is that in our original interpolator - if the input value is above or below the input range, our original interpolator will extrapolate the result. If you try this with the scipy interpolator it raises a ValueError. Consider this program as an example: import numpy as np from scipy import interpolate x = np.arange(0,10) y = np.exp(-x/3.0) f = interpolate.interp1d(x, y) print f(9) print f(11) # Causes ValueError, because it's greater than max(x) Is there a sensible way to make it so that instead of crashing, the final line will simply do a linear extrapolate, continuing the gradients defined by the first and last two pouints to infinity. Note, that in the real software I'm not actually using the exp function - that's here for illustration only!

    Read the article

  • Condition checking vs. Exception handling

    - by Aidas Bendoraitis
    When is exception handling more preferable than condition checking? There are many situations where I can choose using one or the other. For example, this is a summing function which uses a custom exception: # module mylibrary class WrongSummand(Exception): pass def sum_(a, b): """ returns the sum of two summands of the same type """ if type(a) != type(b): raise WrongSummand("given arguments are not of the same type") return a + b # module application using mylibrary from mylibrary import sum_, WrongSummand try: print sum_("A", 5) except WrongSummand: print "wrong arguments" And this is the same function, which avoids using exceptions # module mylibrary def sum_(a, b): """ returns the sum of two summands if they are both of the same type """ if type(a) == type(b): return a + b # module application using mylibrary from mylibrary import sum_ c = sum_("A", 5) if c is not None: print c else: print "wrong arguments" I think that using conditions is always more readable and manageable. Or am I wrong? What are the proper cases for defining APIs which raise exceptions and why?

    Read the article

  • How to create instances of related models in Django

    - by sevennineteen
    I'm working on a CMSy app for which I've implemented a set of models which allow for creation of custom Template instances, made up of a number of Fields and tied to a specific Customer. The end-goal is that one or more templates with a set of custom fields can be defined through the Admin interface and associated to a customer, so that customer can then create content objects in the format prescribed by the template. I seem to have gotten this hooked up such that I can create any number of Template objects, but I'm struggling with how to create instances - actual content objects - in those templates. For example, I can define a template "Basic Page" for customer "Acme" which has the fields "Title" and "Body", but I haven't figured out how to create Basic Page instances where these fields can be filled in. Here are my (somewhat elided) models... class Customer(models.Model): ... class Field(models.Model): ... class Template(models.Model): label = models.CharField(max_length=255) clients = models.ManyToManyField(Customer, blank=True) fields = models.ManyToManyField(Field, blank=True) class ContentObject(models.Model): label = models.CharField(max_length=255) template = models.ForeignKey(Template) author = models.ForeignKey(User) customer = models.ForeignKey(Customer) mod_date = models.DateTimeField('Modified Date', editable=False) def __unicode__(self): return '%s (%s)' % (self.label, self.template) def save(self): self.mod_date = datetime.datetime.now() super(ContentObject, self).save() Thanks in advance for any advice!

    Read the article

  • Generating two thumbnails from the same image in Django

    - by Titus
    Hello, this seems like quite an easy problem but I can't figure out what is going on here. Basically, what I'd like to do is create two different thumbnails from one image on a Django model. What ends up happening is that it seems to be looping and recreating the same image (while appending an underscore to it each time) until it throws up an error that the filename is to big. So, you end up something like: OSError: [Errno 36] File name too long: 'someimg________________etc.jpg' Here is the code: def save(self, *args, **kwargs): if self.image: iname = os.path.split(self.image.name)[-1] fname, ext = os.path.splitext(iname) tlname, tsname = fname + '_thumb_l' + ext, fname + '_thumb_s' + ext self.thumb_large.save(tlname, make_thumb(self.image, size=(250,250))) self.thumb_small.save(tsname, make_thumb(self.image, size=(100,100))) super(Artist, self).save(*args, **kwargs) def make_thumb(infile, size=(100,100)): infile.seek(0) image = Image.open(infile) if image.mode not in ('L', 'RGB'): image.convert('RGB') image.thumbnail(size, Image.ANTIALIAS) temp = StringIO() image.save(temp, 'png') return ContentFile(temp.getvalue()) I didn't show imports for the sake of brevity. Assume there are two ImageFields on the Artist model: thumb_large, and thumb_small. If this isn't the correct way to do it, I'd appreciate any feedback. Thanks!

    Read the article

  • Programmatically sync the db in Django

    - by Attila Oláh
    I'm trying to sync my db from a view, something like this: from django import http from django.core import management def syncdb(request): management.call_command('syncdb') return http.HttpResponse('Database synced.') The issue is, it will block the dev server by asking for user input from the terminal. How can I pass it the '--noinput' option to prevent asking me anything? I have other ways of marking users as super-user, so there's no need for the user input, but I really need to call syncdb (and flush) programmatically, without logging on to the server via ssh. Any help is appreciated.

    Read the article

  • mod_wsgi daemon mode vs threaded fastcgi

    - by t0ster
    Can someone explain the difference between apache mod_wsgi in daemon mode and django fastcgi in threaded mode. They both use threads for concurrency I think. Supposing that I'm using nginx as front end to apache mod_wsgi. UPDATE: I'm comparing django built in fastcgi(./manage.py method=threaded maxchildren=15) and mod_wsgi in 'daemon' mode(WSGIDaemonProcess example threads=15). They both use threads and acquire GIL, am I right?

    Read the article

  • Why wont numpy matrix let me print its rows?

    - by uberjumper
    Okay this is probably a really dumb question, however its really starting to hurt. I have a numpy matrix, and basically i print it out row by row. However i want to make each row be formatted and separated properly. >>> arr = numpy.matrix([[x for x in range(5)] for y in range(5)]) >>> arr matrix([[0, 1, 2, 3, 4], [0, 1, 2, 3, 4], [0, 1, 2, 3, 4], [0, 1, 2, 3, 4], [0, 1, 2, 3, 4]]) Lets say i want to print the first row, and add a '|' between each element: >>> '|'.join(map(str, arr[0,])) '[[0 1 2 3 4]]' Err... >>> '|'.join(map(lambda x: str(x[0]), arr[0])) '[[0 1 2 3 4]]' I am really confused by this behavior why does it do this?

    Read the article

  • Not able to pass multiple override parameters using nose-testconfig 0.6 plugin in nosetests

    - by Jaikit
    Hi, I am able to override multiple config parameters using nose-testconfig plugin only if i pass the overriding parameters on commandline. e.g. nosetests -c nose.cfg -s --tc=jack.env1:asl --tc=server2.env2:abc But when I define the same thing inside nose.cfg, than only the value for last parameter is modified. e.g. tc = server2.env2:abc tc = jack.env1:asl I checked the plugin code. It looks fine to me. I am pasting the part of plugin code below: parser.add_option( "--tc", action="append", dest="overrides", default = [], help="Option:Value specific overrides.") configure: if options.overrides: self.overrides = [] overrides = tolist(options.overrides) for override in overrides: keys, val = override.split(":") if options.exact: config[keys] = val else: ns = ''.join(['["%s"]' % i for i in keys.split(".") ]) # BUG: Breaks if the config value you're overriding is not # defined in the configuration file already. TBD exec('config%s = "%s"' % (ns, val)) Let me know if any one has any clue.

    Read the article

  • I am currently serving my static files in Django. How do I use Apache2 to do this?

    - by alex
    (r'^media/(?P<path>.*)$', 'django.views.static.serve',{'document_root': settings.MEDIA_ROOT}), As you can see, I have a directory called "media" under my Django project. I would like to delete this line in my urls.py and instead us Apache to serve my static files. What do I do to my Apache configs (which files do I change) in order to do this? By the way, I installed Apache2 like normal: sudo aptitude install apache2

    Read the article

  • Google App Engine with local Django 1.1 gets Intermittent Failures

    - by Jon Watte
    I'm using the Windows Launcher development environment for Google App Engine. I have downloaded Django 1.1.2 source, and un-tarrred the "django" subdirectory to live within my application directory (a peer of app.yaml) At the top of each .py source file, I do this: import settings import os os.environ["DJANGO_SETTINGS_MODULE"] = 'settings' In my file settings.py (which lives at the root of the app directory, as well), I do this: DEBUG = True TEMPLATE_DIRS = ('html') INSTALLED_APPS = ('filters') import os os.environ["DJANGO_SETTINGS_MODULE"] = 'settings' from google.appengine.dist import use_library use_library('django', '1.1') from django.template import loader Yes, this looks a bit like overkill, doesn't it? I only use django.template. I don't explicitly use any other part of django. However, intermittently I get one of two errors: 1) Django complains that DJANGO_SETTINGS_MODULE is not defined. 2) Django complains that common.html (a template I'm extending in other templates) doesn't exist. 95% of the time, these errors are not encountered, and they randomly just start happening. Once in that state, the local server seems "wedged" and re-booting it generally fixes it. What's causing this to happen, and what can I do about it? How can I even debug it? Here is the traceback from the error: Traceback (most recent call last): File "C:\code\kwbudget\edit_budget.py", line 34, in get self.response.out.write(t.render(template.Context(values))) File "C:\code\kwbudget\django\template\__init__.py", line 165, in render return self.nodelist.render(context) File "C:\code\kwbudget\django\template\__init__.py", line 784, in render bits.append(self.render_node(node, context)) File "C:\code\kwbudget\django\template\__init__.py", line 797, in render_node return node.render(context) File "C:\code\kwbudget\django\template\loader_tags.py", line 71, in render compiled_parent = self.get_parent(context) File "C:\code\kwbudget\django\template\loader_tags.py", line 66, in get_parent raise TemplateSyntaxError, "Template %r cannot be extended, because it doesn't exist" % parent TemplateSyntaxError: Template u'common.html' cannot be extended, because it doesn't exist And edit_budget.py starts with exactly the lines that I included up top. All templates live in a directory named "html" in my root directory, and "html/common.html" exists. I know the template engine finds them, because I start out with "html/edit_budget.html" which extends common.html. It looks as if the settings module somehow isn't applied (because that's what adds html to the search path for templates).

    Read the article

  • Is using os.path.abspath to validate an untrusted filename's location secure?

    - by mcmt
    I don't think I'm missing anything. Then again I'm kind of a newbie. def GET(self, filename): name = urllib.unquote(filename) full = path.abspath(path.join(STATIC_PATH, filename)) #Make sure request is not tricksy and tries to get out of #the directory, e.g. filename = "../.ssh/id_rsa". GET OUTTA HERE assert full[:len(STATIC_PATH)] == STATIC_PATH, "bad path" return open(full).read() Edit: I realize this will return the wrong HTTP error code if the file doesn't exist (at least under web.py). I will fix this.

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 364 365 366 367 368 369 370 371 372 373 374 375  | Next Page >