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  • Send a "304 Not Modified" for images stored in the datastore

    - by Emilien
    I store user-uploaded images in the Google App Engine datastore as db.Blob, as proposed in the docs. I then serve those images on /images/<id>.jpg. The server always sends a 200 OK response, which means that the browser has to download the same image multiple time (== slower) and that the server has to send the same image multiple times (== more expensive). As most of those images will likely never change, I'd like to be able to send a 304 Not Modified response. I am thinking about calculating some kind of hash of the picture when the user uploads it, and then use this to know if the user already has this image (maybe send the hash as an Etag?) I have found this answer and this answer that explain the logic pretty well, but I have 2 questions: Is it possible to send an Etag in Google App Engine? Has anyone implemented such logic, and/or is there any code snippet available?

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  • django: Changing auto_id of ModelForm based form class

    - by Meilo
    Every time I create an instance of the TestForm specified below, I have to overwrite the standard id format with auto_id=True. How can this be done once only in the form class instead? Any hints are very welcome. views.py from django.forms import ModelForm from models import Test class TestForm(ModelForm): class Meta: model = Test def test(request): form = TestForm(auto_id=True)

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  • Simple XML over http web service

    - by Mark
    I have a simple html service, developed in django. You enter your name - it posts this, and returns a value (male/female). I need to ofer this as a web service. I have no idea where to start. I want to accept a xml request, and provide an xml response - thats it. Can anyone give ma any pointers - Googling it is difficult when you dont know what your searching for.

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  • Simple way to create possible case

    - by bugbug
    I have lists of data such as a = [1,2,3,4] b = ["a","b","c","d","e"] c = ["001","002","003"] And I want to create new another list that was mixed from all possible case of a,b,c like this d = ["1a001","1a002","1a003",...,"4e003"] Is there any module or method to generate d without write many for loop?

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  • Dropdown sorting in django-admin

    - by Andrey
    I'd like to know how can I sort values in the Django admin dropdowns. For example, I have a model called Article with a foreign key pointing to the Users model, smth like: class Article(models.Model): title = models.CharField(_('Title'), max_length=200) slug = models.SlugField(_('Slug'), unique_for_date='publish') author = models.ForeignKey(User) body = models.TextField(_('Body')) status = models.IntegerField(_('Status')) categories = models.ManyToManyField(Category, blank=True) publish = models.DateTimeField(_('Publish date')) I edit this model in django admin: class ArticleAdmin(admin.ModelAdmin): list_display = ('title', 'publish', 'status') list_filter = ('publish', 'categories', 'status') search_fields = ('title', 'body') prepopulated_fields = {'slug': ('title',)} admin.site.register(Article, ArticleAdmin) and of course it makes the nice user select dropdown for me, but it's not sorted and it takes a lot of time to find a user by username.

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  • SQLAlchemy returns tuple not dictionary

    - by Ivan
    Hi everyone, I've updated SQLAlchemy to 0.6 but it broke everything. I've noticed it returns tuple not a dictionary anymore. Here's a sample query: query = session.query(User.id, User.username, User.email).filter(and_(User.id == id, User.username == username)).limit(1) result = session.execute(query).fetchone() This piece of code used to return a dictionary in 0.5. My question is how can I return a dictionary?

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  • Inexpensive ways to add seek to a filetype object

    - by becomingGuru
    PdfFileReader reads the content from a pdf file to create an object. I am querying the pdf from a cdn via urllib.urlopen(), this provides me a file like object, which has no seek. PdfFileReader, however uses seek. What is the simple way to create a PdfFileReader object from a pdf downloaded via url. Now, what can I do to avoid writing to disk and reading it again via file(). Thanks in advance.

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  • Pygame Sprite/Font rendering issues

    - by Grimless
    Hey guys. Here's my problem: I have a game class that maintains a HUD overlay that has a bunch of elements, including header and footer background sprites. Everything was working fine until I added a 1024x128 footer sprite. Now two of my text labels will not render, despite the fact that they DO exist in my Group and self.elements array. Is there something I'm missing? When I take out the footerHUDImage line, all of the labels render correctly and everything works fine. When I add the footerHUDImage, two of the labels (the first two) no longer render and the third only sometimes renders. HELP PLEASE! Here is the code: class AoWHUD (object): def __init__(self, screen, delegate, dataSource): self.delegate = delegate self.dataSource = dataSource self.elements = [] headerHudImage = KJRImage("HUDBackground.png") self.elements.append(headerHudImage) headerHudImage.userInteractionEnabled = True footerHUDImage = KJRImage("ControlsBackground.png") self.elements.append(footerHUDImage) footerHUDImage.rect.bottom = screen.get_rect().height footerHUDImage.userInteractionEnabled = True lumberMessage = "Lumber: " + str(self.dataSource.lumber) lumberLabel = KJRLabel(lumberMessage, size = 48, color = (240, 200, 10)) lumberLabel.rect.topleft = (_kSpacingMultiple * 0, 0) self.elements.append(lumberLabel) stoneMessage = "Stone: " + str(self.dataSource.stone) stoneLabel = KJRLabel(stoneMessage, size = 48, color = (240, 200, 10)) stoneLabel.rect.topleft = (_kSpacingMultiple * 1, 0) self.elements.append(stoneLabel) metalMessage = "Metal: " + str(self.dataSource.metal) metalLabel = KJRLabel(metalMessage, size = 48, color = (240, 200, 10)) metalLabel.rect.topleft = (_kSpacingMultiple * 2, 0) self.elements.append(metalLabel) foodMessage = "Food: " + str(len(self.dataSource.units)) + "/" + str(self.dataSource.food) foodLabel = KJRLabel(foodMessage, size = 48, color = (240, 200, 10)) foodLabel.rect.topleft = (_kSpacingMultiple * 3, 0) self.elements.append(foodLabel) self.selectionSprites = {32 : pygame.image.load("Selected32.png").convert_alpha(), 64 : pygame.image.load("Selected64.png")} self._sprites_ = pygame.sprite.Group() for e in self.elements: self._sprites_.add(e) print self.elements def draw(self, screen): if self.dataSource.resourcesChanged: lumberMessage = "Lumber: " + str(self.dataSource.lumber) stoneMessage = "Stone: " + str(self.dataSource.stone) metalMessage = "Metal: " + str(self.dataSource.metal) foodMessage = "Food: " + str(len(self.dataSource.units)) + "/" + str(self.dataSource.food) self.elements[2].setText(lumberMessage) self.elements[2].rect.topleft = (_kSpacingMultiple * 0, 0) self.elements[3].setText(stoneMessage) self.elements[3].rect.topleft = (_kSpacingMultiple * 1, 0) self.elements[4].setText(metalMessage) self.elements[4].rect.topleft = (_kSpacingMultiple * 2, 0) self.elements[5].setText(foodMessage) self.elements[5].rect.topleft = (_kSpacingMultiple * 3, 0) self.dataSource.resourcesChanged = False self._sprites_.draw(screen) if self.delegate.selectedUnit: theSelectionSprite = self.selectionSprites[self.delegate.selectedUnit.rect.width] screen.blit(theSelectionSprite, self.delegate.selectedUnit.rect)

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  • App only spawns one thread

    - by tipu
    I have what I thought was a thread-friendly app, and after doing some output I've concluded that of the 15 threads I am attempting to run, only one does. I have if __name__ == "__main__": fhf = FileHandlerFactory() tweet_manager = TweetManager("C:/Documents and Settings/Administrator/My Documents/My Dropbox/workspace/trie/Tweet Search Engine/data/partitioned_raw_tweets/raw_tweets.txt.001") start = time.time() for i in range(15): Indexer(tweet_manager, fhf).start() Then in my thread-entry point, I do def run(self): print(threading.current_thread()) self.index() That results in this: <Indexer(Thread-3, started 1168)> So of 15 threads that I thought were running, I'm only running one. Any idea as to why? Edit: code

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  • asyncore callbacks launching threads... ok to do?

    - by sbartell
    I'm unfamiliar with asyncore, and have very limited knowledge of asynchronous programming except for a few intro to twisted tutorials. I am most familiar with threads and use them in all my apps. One particular app uses a couchdb database as its interface. This involves longpolling the db looking for changes and updates. The module I use for couchdb is couchdbkit. It uses an asyncore loop to watch for these changes and send them to a callback. So, I figure from this callback is where I launch my worker threads. It seems a bit crude to mix asynchronous and threaded programming. I really like couchdbkit, but would rather not introduce issues into my program. So, my question is, is it safe to fire threads from an async callback? Here's some code... {{{ def dispatch(change): global jobs, db_url # jobs is my queue db = Database(db_url) work_order = db.get(change['id']) # change is an id to the document that changed. # i need to get the actual document (workorder) worker = Worker(work_order, db) # fire the thread jobs.append[worker] worker.start() return main() . . . consumer.wait(cb=dispatch, since=update_seq, timeout=10000) #wait constains the asyncloop. }}}

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  • Process Name with inotify tool

    - by Priyanka
    Hi ALl Is there a way to find out which process is causing a particular event to occur? In the inotify-tool version 3.13, in struct_kernel , pid,uid and gid are used but it is not handled in the source code. Is there any latest patch available for the same. Please let me know.

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  • How to reset Scrapy parameters? (always running under same parameters)

    - by Jean Ventura
    I've been running my Scrapy project with a couple of accounts (the project scrapes a especific site that requieres login credentials), but no matter the parameters I set, it always runs with the same ones (same credentials). I'm running under virtualenv. Is there a variable or setting I'm missing? Edit: It seems that this problem is Twisted related. Even when I run: scrapy crawl -a user='user' -a password='pass' -o items.json -t json SpiderName I still get an error saying: ERROR: twisted.internet.error.ReactorNotRestartable And all the information I get, is the last 'succesful' run of the spider.

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  • Why wont numpy matrix let me print its rows?

    - by uberjumper
    Okay this is probably a really dumb question, however its really starting to hurt. I have a numpy matrix, and basically i print it out row by row. However i want to make each row be formatted and separated properly. >>> arr = numpy.matrix([[x for x in range(5)] for y in range(5)]) >>> arr matrix([[0, 1, 2, 3, 4], [0, 1, 2, 3, 4], [0, 1, 2, 3, 4], [0, 1, 2, 3, 4], [0, 1, 2, 3, 4]]) Lets say i want to print the first row, and add a '|' between each element: >>> '|'.join(map(str, arr[0,])) '[[0 1 2 3 4]]' Err... >>> '|'.join(map(lambda x: str(x[0]), arr[0])) '[[0 1 2 3 4]]' I am really confused by this behavior why does it do this?

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  • Pylons error handling

    - by TJ Huffington
    Hello, I am just getting started with Pylons and am confused as to how to account for exceptions. What is the proper way to error check user input (ensure a correct email address, check that it doesn't yet exist in the database, etc ...)? Should these checks go inside the model classes or somewhere else? Sample code would be great.

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  • Django and json request

    - by Hulk
    In a template i have the following code <script> var url="/mypjt/my_timer" $.post(url, paramarr, function callbackHandler(dict) { alert('got response back'); if (dict.flag == 2) { alert('1'); $.jGrowl("Data could not be saved"); } else if(dict.ret_status == 1) { alert('2'); $.jGrowl("Data saved successfully"); window.location = "/mypjt/display/" + dict.rid; } }, "json" ); </script> In views i have the following code, def my_timer(request): dict={} try: a= timer.objects.get(pk=1) dict({'flag':1}) return HttpResponse(simplejson.dumps(dict), mimetype='application/javascript') except: dict({'flag':1}) return HttpResponse(simplejson.dumps(dict), mimetype='application/javascript') My question is since we are making a json request and in the try block ,after setting the flag ,cant we return a page directly as return render_to_response('mypjt/display.html',context_instance=RequestContext(request,{'dict': dict})) instead of sending the response, because on success again in the html page we redirect the code Also if there is a exception then only can we return the json request. My only concern is that the interaction between client and server should be minimal. Thanks..

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  • How do I find the "concrete class" of a django model baseclass

    - by Mr Shark
    I'm trying to find the actual class of a django-model object, when using model-inheritance. Some code to describe the problem: class Base(models.model): def basemethod(self): ... class Child_1(Base): pass class Child_2(Base): pass If I create various objects of the two Child classes and the create a queryset containing them all: Child_1().save() Child_2().save() (o1, o2) = Base.objects.all() I want to determine if the object is of type Child_1 or Child_2 in basemethod, I can get to the child object via o1.child_1 and o2.child_2 but that reconquers knowledge about the childclasses in the baseclass. I have come up with the following code: def concrete_instance(self): instance = None for subclass in self._meta.get_all_related_objects(): acc_name = subclass.get_accessor_name() try: instance = self.__getattribute__(acc_name) return instance except Exception, e: pass But it feels brittle and I'm not sure of what happens when if I inherit in more levels.

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  • SQLAlchemy - relationship limited on more than just the foreign key

    - by Marian
    I have a wiki db layout with Page and Revisions. Each Revision has a page_id referencing the Page, a page relationship to the referenced page; each Page has a all_revisions relationship to all its revisions. So far so common. But I want to implement different epochs for the pages: If a page was deleted and is recreated, the new revisions have a new epoch. To help find the correct revisions, each page has a current_epoch field. Now I want to provide a revisions relation on the page that only contains its revisions, but only those where the epochs match. This is what I've tried: revisions = relationship('Revision', primaryjoin = and_( 'Page.id == Revision.page_id', 'Page.current_epoch == Revision.epoch', ), foreign_keys=['Page.id', 'Page.current_epoch'] ) Full code (you may run that as it is) However this always raises ArgumentError: Could not determine relationship direction for primaryjoin condition ...`, I've tried all I had come to mind, it didn't work. What am I doing wrong? Is this a bad approach for doing this, how could it be done other than with a relationship?

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  • foreignkey problem

    - by realshadow
    Hey, Imagine you have this model: class Category(models.Model): node_id = models.IntegerField(primary_key = True) type_id = models.IntegerField(max_length = 20) parent_id = models.IntegerField(max_length = 20) sort_order = models.IntegerField(max_length = 20) name = models.CharField(max_length = 45) lft = models.IntegerField(max_length = 20) rgt = models.IntegerField(max_length = 20) depth = models.IntegerField(max_length = 20) added_on = models.DateTimeField(auto_now = True) updated_on = models.DateTimeField(auto_now = True) status = models.IntegerField(max_length = 20) node = models.ForeignKey(Category_info, verbose_name = 'Category_info', to_field = 'node_id' The important part is the foreignkey. When I try: Category.objects.filter(type_id = 15, parent_id = offset, status = 1) I get an error that get returned more than category, which is fine, because it is supposed to return more than one. But I want to filter the results trough another field, which would be type id (from the second Model) Here it is: class Category_info(models.Model): objtree_label_id = models.AutoField(primary_key = True) node_id = models.IntegerField(unique = True) language_id = models.IntegerField() label = models.CharField(max_length = 255) type_id = models.IntegerField() The type_id can be any number from 1 - 5. I am desparately trying to get only one result where the type_id would be number 1. Here is what I want in sql: SELECT c.*, ci.* FROM category c JOIN category_info ci ON (c.node_id = ci.node_id) WHERE c.type_id = 15 AND c.parent_id = 50 AND ci.type_id = 1 Any help is GREATLY appreciated. Regards

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  • a simple smtp server

    - by fixxxer
    Could you please suggest a simple SMTP server with the very basic APIs(by very basic I mean, to read,write,delete email) that could be run on a linux box? I just need to convert the crux of the email into XML format and FTP it to another machine.

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  • Django: Determining if a user has voted or not

    - by TheLizardKing
    I have a long list of links that I spit out using the below code, total votes, submitted by, the usual stuff but I am not 100% on how to determine if the currently logged in user has voted on a link or not. I know how to do this from within my view but do I need to alter my below view code or can I make use of the way templates work to determine it? I have read http://stackoverflow.com/questions/1528583/django-vote-up-down-method but I don't quite understand what's going on ( and don't need any ofjavascriptery). Models (snippet): class Link(models.Model): category = models.ForeignKey(Category, blank=False, default=1) user = models.ForeignKey(User) created = models.DateTimeField(auto_now_add=True) modified = models.DateTimeField(auto_now=True) url = models.URLField(max_length=1024, unique=True, verify_exists=True) name = models.CharField(max_length=512) def __unicode__(self): return u'%s (%s)' % (self.name, self.url) class Vote(models.Model): link = models.ForeignKey(Link) user = models.ForeignKey(User) created = models.DateTimeField(auto_now_add=True) def __unicode__(self): return u'%s vote for %s' % (self.user, self.link) Views (snippet): links = Link.objects.select_related().annotate(votes=Count('vote')).order_by('-created')

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  • How to retrieve view of MultiIndex DataFrame

    - by Henry S. Harrison
    This question was inspired by this question. I had the same problem, updating a MultiIndex DataFrame by selection. The drop_level=False solution in Pandas 0.13 will allow me to achieve the same result, but I am still wondering why I cannot get a view from the MultiIndex DataFrame. In other words, why does this not work?: >>> sat = d.xs('sat', level='day', copy=False) Traceback (most recent call last): File "<stdin>", line 1, in <module> File "C:\Python27\lib\site-packages\pandas\core\frame.py", line 2248, in xs raise ValueError('Cannot retrieve view (copy=False)') ValueError: Cannot retrieve view (copy=False) Of course it could be only because it is not implemented, but is there a reason? Is it somehow ambiguous or impossible to implement? Returning a view is more intuitive to me than returning a copy then later updating the original. I looked through the source and it seems this situation is checked explicitly to raise an error. Alternatively, is it possible to get the same sort of view from any of the other indexing methods? I've experimented but have not been successful. [edit] Some potential implementations are discussed here. I guess with the last question above I'm wondering what the current best solution is to index into arbitrary multiindex slices and cross-sections.

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  • unit test for proxy checking

    - by zubin71
    Proxy configuration of a machine can be easily fetched using def check_proxy(): import urllib2 http_proxy = urllib2.getproxies().get('http') I need to write a test for the above written function. In order to do that I need to:- Set the system-wide proxy to an invalid URL during the test(sounds like a bad idea). Supply an invalid URL to http_proxy. How can I achieve either of the above?

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  • How to replace empty string with zero in comma-separated string?

    - by dsaccount1
    "8,5,,1,4,7,,,,7,,1,9,3,6,,,8,6,3,9,,2,5,4,,,,,3,2,,,7,4,1,1,,4,,6,9,,5,,,,5,,,1,,6,3,,,6,5,,,,7,4,,1,7,6,,,,8,,5,,,7,1,,3,9," I'm doing a programming challenge where i need to parse this sequence into my sudoku script. Need to get the above sequence into 8,5,0,1,4,7,0,0,0,7,0,1,9,3,6,0,0,8......... I tried re but without success, help is appreciated, thanks.

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