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  • Django Querysets -- need a less expensive way to do this..

    - by rh0dium
    Hi all, I have a problem with some code and I believe it is because of the expense of the queryset. I am looking for a much less expensive (in terms of time) way to to this.. log.info("Getting Users") employees = Employee.objects.filter(is_active = True) log.info("Have Users") if opt.supervisor: if opt.hierarchical: people = getSubs(employees, " ".join(args)) else: people = employees.filter(supervisor__name__icontains = " ".join(args)) else: log.info("Filtering Users") people = employees.filter(name__icontains = " ".join(args)) | \ employees.filter(unix_accounts__username__icontains = " ".join(args)) log.info("Filtered Users") log.info("Processing data") np = [] for person in people: unix, p4, bugz = "No", "No", "No" if len(person.unix_accounts.all()): unix = "Yes" if len(person.perforce_accounts.all()): p4 = "Yes" if len(person.bugzilla_accounts.all()): bugz = "Yes" if person.cell_phone != "": exphone = fixphone(person.cell_phone) elif person.other_phone != "": exphone = fixphone(person.other_phone) else: exphone = "" np.append({ 'name':person.name, 'office_phone': fixphone(person.office_phone), 'position': person.position, 'location': person.location.description, 'email': person.email, 'functional_area': person.functional_area.name, 'department': person.department.name, 'supervisor': person.supervisor.name, 'unix': unix, 'perforce': p4, 'bugzilla':bugz, 'cell_phone': fixphone(exphone), 'fax': fixphone(person.fax), 'last_update': person.last_update.ctime() }) log.info("Have data") Now this results in a log which looks like this.. 19:00:55 INFO phone phone Getting Users 19:00:57 INFO phone phone Have Users 19:00:57 INFO phone phone Processing data 19:01:30 INFO phone phone Have data As you can see it's taking over 30 seconds to simply iterate over the data. That is way too expensive. Can someone clue me into a more efficient way to do this. I thought that if I did the first filter that would make things easier but seems to have no effect. I'm at a loss on this one. Thanks To be clear this is about 1500 employees -- Not too many!!

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  • Form (or Formset?) to handle multiple table rows in Django

    - by Ben
    Hi, I'm working on my first Django application. In short, what it needs to do is to display a list of film titles, and allow users to give a rating (out of 10) to each film. I've been able to use the {{ form }} and {{ formset }} syntax in a template to produce a form which lets you rate one film at a time, which corresponds to one row in a MySQL table, but how do I produce a form that iterates over all the movie titles in the database and produces a form that lets you rate lots of them at once? At first, I thought this was what formsets were for, but I can't see any way to automatically iterate over the contents of a database table to produce items to go in the form, if you see what I mean. Currently, my views.py has this code: def survey(request): ScoreFormSet = formset_factory(ScoreForm) if request.method == 'POST': formset = ScoreFormSet(request.POST, request.FILES) if formset.is_valid(): return HttpResponseRedirect('/') else: formset = ScoreFormSet() return render_to_response('cf/survey.html', { 'formset':formset, }) And my survey.html has this: <form action="/survey/" method="POST"> <table> {{ formset }} </table> <input type = "submit" value = "Submit"> </form> Oh, and the definition of ScoreForm and Score from models.py are: class Score(models.Model): movie = models.ForeignKey(Movie) score = models.IntegerField() user = models.ForeignKey(User) class ScoreForm(ModelForm): class Meta: model = Score So, in case the above is not clear, what I'm aiming to produce is a form which has one row per movie, and each row shows a title, and has a box to allow the user to enter their score. If anyone can point me at the right sort of approach to this, I'd be most grateful. Thanks, Ben

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  • Create a color generator in matplotlib

    - by Brendan
    I have a series of lines that each need to be plotted with a separate colour. Each line is actually made up of several data sets (positive, negative regions etc.) and so I'd like to be able to create a generator that will feed one colour at a time across a spectrum, for example the gist_rainbow map shown here. I have found the following works but it seems very complicated and more importantly difficult to remember, from pylab import * NUM_COLORS = 22 mp = cm.datad['gist_rainbow'] get_color = matplotlib.colors.LinearSegmentedColormap.from_list(mp, colors=['r', 'b'], N=NUM_COLORS) ... # Then in a for loop this_color = get_color(float(i)/NUM_COLORS) Moreover, it does not cover the range of colours in the gist_rainbow map, I have to redefine a map. Maybe a generator is not the best way to do this, if so what is the accepted way?

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  • Django says the "id may not be NULL" but why is it?

    - by Oli
    I'm going crazy today. I just tried to insert a new record and it threw back a "post_blogpost.id may not be NULL" error. Here's my model: class BlogPost(models.Model): title = models.CharField(max_length=100) slug = models.SlugField(max_length=100) who = models.ForeignKey(User, default=1) when = models.DateTimeField() intro = models.TextField(blank=True, null=True) content = models.TextField(blank=True, null=True) counter = models.PositiveIntegerField(default=0) published = models.BooleanField(default=False) css = models.TextField(blank=True, null=True) class Meta: ordering = ('-when', 'id') There are a number of functions beneath the model too but I won't include them in full here. Their names are: content_cache_key, clear_cache, __unicode__, reads, read, processed_content. I'm adding through the admin... And I'm running out of hair.

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  • Content-Length header not returned from Pylons response

    - by Evgeny
    I'm still struggling to Stream a file to the HTTP response in Pylons. In addition to the original problem, I'm finding that I cannot return the Content-Length header, so that for large files the client cannot estimate how long the download will take. I've tried response.content_length = 12345 and I've tried response.headers['Content-Length'] = 12345 In both cases the HTTP response (viewed in Fiddler) simply does not contain the Content-Length header. How do I get Pylons to return this header? (Oh, and if you have any ideas on making it stream the file please reply to the original question - I'm all out of ideas there.)

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  • ImportError and Django driving me crazy

    - by John Peebles
    OK, I have the following directory structure (it's a django project): - project -- app and within the app folder, there is a scraper.py file which needs to reference a class defined within models.py I'm trying to do the following: import urllib2 import os import sys import time import datetime import re import BeautifulSoup sys.path.append('/home/userspace/Development/') os.environ['DJANGO_SETTINGS_MODULE'] = 'project.settings' from project.app.models import ClassName and this code just isn't working. I get an error of: Traceback (most recent call last): File "scraper.py", line 14, in from project.app.models import ClassName ImportError: No module named project.app.models This code above used to work, but broke somewhere along the line and I'm extremely confused as to why I'm having problems. On SnowLeopard using python2.5.

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  • How to add a context processor from a Django app

    - by Edan Maor
    Say I'm writing a Django app, and all the templates in the app require a certain variable. The "classic" way to deal with this, afaik, is to write a context processor and add it to TEMPLATE_CONTEXT_PROCESSORS in the settings.py. My question is, is this the right way to do it, considering that apps are supposed to be "independent" from the actual project using them? In other words, when deploying that app to a new project, is there any way to avoid the project having to explicitly mess around with its settings?

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  • Parsing names with pyparsing

    - by johnthexiii
    I have a file of names and ages, john 25 bob 30 john bob 35 Here is what I have so far from pyparsing import * data = ''' john 25 bob 30 john bob 35 ''' name = Word(alphas + Optional(' ') + alphas) rowData = Group(name + Suppress(White(" ")) + Word(nums)) table = ZeroOrMore(rowData) print table.parseString(data) the output I am expecting is [['john', 25], ['bob', 30], ['john bob', 35]] Here is the stacktrace Traceback (most recent call last): File "C:\Users\mccauley\Desktop\client.py", line 11, in <module> eventType = Word(alphas + Optional(' ') + alphas) File "C:\Python27\lib\site-packages\pyparsing.py", line 1657, in __init__ self.name = _ustr(self) File "C:\Python27\lib\site-packages\pyparsing.py", line 122, in _ustr return str(obj) File "C:\Python27\lib\site-packages\pyparsing.py", line 1743, in __str__ self.strRepr = "W:(%s)" % charsAsStr(self.initCharsOrig) File "C:\Python27\lib\site-packages\pyparsing.py", line 1735, in charsAsStr if len(s)>4: TypeError: object of type 'And' has no len()

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  • Import boto from local library

    - by ensnare
    I'm trying to use boto as a downloaded library, rather than installing it globally on my machine. I'm able to import boto, but when I run boto.connect_dynamodb() I get an error: ImportError: No module named dynamodb.layer2 Here's my file structure: project/ project/ __init__.py libraries/ __init__.py flask/ boto/ views/ .... modules/ __init__.py db.py .... templates/ .... static/ .... runserver.py And the contents of the relevant files as follows: project/project/modules/db.py from project.libraries import boto conn = boto.connect_dynamodb( aws_access_key_id='<YOUR_AWS_KEY_ID>', aws_secret_access_key='<YOUR_AWS_SECRET_KEY>') What am I doing wrong? Thanks in advance.

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  • How to accept localized date format (e.g dd/mm/yy) in a DateField on an admin form ?

    - by tomjerry
    Is it possible to customize a django application to have accept localized date format (e.g dd/mm/yy) in a DateField on an admin form ? I have a model class : class MyModel(models.Model): date = models.DateField("Date") And associated admin class class MyModelAdmin(admin.ModelAdmin): pass On django administration interface, I would like to be able to input a date in following format : dd/mm/yyyy. However, the date field in the admin form expects yyyy-mm-dd. How can I customize things ? Nota bene : I have already specified my custom language code (fr-FR) in settings.py, but it seems to have no effect on this date input matter. Thanks in advance for your answer

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  • Simple way to create possible case

    - by bugbug
    I have lists of data such as a = [1,2,3,4] b = ["a","b","c","d","e"] c = ["001","002","003"] And I want to create new another list that was mixed from all possible case of a,b,c like this d = ["1a001","1a002","1a003",...,"4e003"] Is there any module or method to generate d without write many for loop?

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  • uWSGI with Cherokee: first steps

    - by Steve
    Has anyone tried using uWSGI with Cherokee? Can you share your experiences and what documents you relied upon the most? I am trying to get started from the documentation on both (uWSGI and Cherokee) websites. Nothing works yet. I am using Ubuntu 10.04.

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  • I am trying to move a rectangle in Pygame using coordinates but won't work

    - by user1821449
    this is my code import pygame from pygame.locals import * import sys pygame.init() pygame.display.set_caption("*no current mission*") size = (1280, 750) screen = pygame.display.set_mode(size) clock = pygame.time.Clock() bg = pygame.image.load("bg1.png") guy = pygame.image.load("hero_stand.png") rect = guy.get_rect() x = 10 y = 10 while True: for event in pygame.event.get(): if event.type == pygame.QUIT: sys.exit() if event.type == KEYDOWN: _if event.key == K_RIGHT: x += 5 rect.move(x,y)_ rect.move(x,y) screen.blit(bg,(0,0)) screen.blit(guy, rect) pygame.display.flip() it is just a simple test to see if i can get a rectangle to move. Everything seems to work except the code I put in italic.

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  • Duplicate django query set?

    - by Piotr Czapla
    I have a simple django's query set like: qs = AModel.objects.exclude(state="F").order_by("order") I'd like to use it as follows: qs[0:3].update(state='F') expected = qs[3] # throws error here But last statement throws: "Cannot update a query once a slice has been taken." How can I duplicate the query set?

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  • etree.findall: 'OR'-lookup?

    - by piquadrat
    I want to find all stylesheet definitions in a XHTML file with lxml.etree.findall. This could be as simple as elems = tree.findall('link[@rel="stylesheet"]') + tree.findall('style') But the problem with CSS style definitions is that the order matters, e.g. <link rel="stylesheet" type="text/css" href="/media/css/first.css" /> <style>body:{font-size: 10px;}</style> <link rel="stylesheet" type="text/css" href="/media/css/second.css" /> if the contents of the style tag is applied after the rules in the two link tags, the result may be completely different from the one where the rules are applied in order of definition. So, how would I do a lookup that inlcudes both link[@rel="stylesheet"] and style?

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  • SQLAlchemy - SQLite for testing and Postgresql for devlopment - How to port?

    - by StackUnderflow
    I want to use sqlite memory database for all my testing and Postgresql for my development/production server. But the SQL syntax is not same in both dbs. for ex: SQLite has autoincrement, and Postgresql has serial Is it easy to port the SQL script from sqlite to postgresql... what are your solutions? If you want me to use standard SQL, how should I go about generating primary key in both the databases?

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  • SQLAlchemy - select for update example

    - by Mark
    I'm looking for a complete example of using select for update in SQLAlchemy, but haven't found one googling. I need to lock a single row and update a column, the following code doesn't work (blocks forever): s = table.select(table.c.user=="test",for_update=True) u = table.update().where(table.c.user=="test") u.execute(email="foo") Do I need a commit? How do I do that? As far as I know you need to: begin transaction select ... for update update commit

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  • Getting a specific bit value in a byte string

    - by ignoramus
    There is a byte at a specific index in a byte string which represents eight flags; one flag per bit in the byte. If a flag is set, its corresponding bit is 1, otherwise its 0. For example, if I've got b'\x21' the flags would be 0001 0101 # Three flags are set at indexes 3, 5 and 7 # and the others are not set What would be the best way to get each bit value in that byte, so I know whether a particular flag is set or not? (Preferably using bitwise operations)

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  • Splitting a person's name into forename and surname

    - by Nick
    ok so basically I am asking the question of their name I want this to be one input rather than Forename and Surname. Now is there any way of splitting this name? and taking just the last word from the "Sentence" e.g. name = "Thomas Winter" print name.split() and what would be output is just "Winter"

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  • Project design / FS layout for large django projects

    - by rcreswick
    What is the best way to layout a large django project? The tutuorials provide simple instructions for setting up apps, models, and views, but there is less information about how apps and projects should be broken down, how much sharing is allowable/necessary between apps in a typical project (obviously that is largely dependent on the project) and how/where general templates should be kept. Does anyone have examples, suggestions, and explanations as to why a certain project layout is better than another? I am particularly interested in the incorporation of large numbers of unit tests (2-5x the size of the actual code base) and string externalization / templates.

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  • Scraping paginated items from a website using scrapy

    - by Mridang Agarwalla
    I'm using scrapy to scrape items from a site. I'm not being able to implement this scraping pattern. The site I'm trying to scrape is a forum and I scrape the site once a day. Each page has a table containing posts. New posts are added to the top of the table and as more and more posts are posted to the site, the older posts go further into the pages due to pagination. This is a very simple scenario and we will assume that the order of the posts never change. I would like to scrape this site and scrape all the "new" records until the last scraped post from yesterday is encountered. I have configured my spider to paginate endlessly and when it encounters yesterday's last scraped post, it should stop. How can implement this? (My Scrapy installation works with my Django installation using django-dynamic-scraper )

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