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  • Visual Studio Question: How to go to a specific file path and line number programmatically?

    - by Jack
    In the Visual Studio output window, you can double click a line that contains a file path and line number and it automatically takes you to that location. In my program, I need to mimic this behavior and be able to click something (a button for example) and do go to a specific file and line number that I tell it to go to. Any help/suggestions would be appreciated. I am working in C#.

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  • Directory.GetFiles returning entire path, I only want the filename?

    - by blerh
    This is the code I have set up to scan a directory of files: Dim fileArray() As String fileArray = Directory.GetFiles(System.AppDomain.CurrentDomain.BaseDirectory & "help\") And it successfully gets all files in the directory, but it gets their absolute paths aswell. For example, one of the entries in fileArray() is: F:\Project\Project\bin\x86\Debug\help\book_troubleshoot.html And I want it to just be: book_troubleshoot.html Is there a way to do this without parsing through all the array entries to trim off the path? Thanks.

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  • How to find out or where to specify path of the JavaEE project?

    - by Milan
    I develop Java EEapplication and I have to create some files in the src folder in the my application. But I dont where or how to specify the path. I want my application to be portable. It means just to say TestProject/src/.... and not C:/bla/bla/TestProject/src/... do we specify this in some app file like web.inf, meta-inf or its just some trick. Thanks!

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  • Problem registering a COM server written for Excel registered on client machine (can't set full path

    - by toytrains
    In this previous question <How to get COM Server for Excel written in VB.NET installed and registered in Automation Servers list? there is an example of how to create the full path to a registry key using VS 2008. Everything in the previous answer works correctly except the full path that I am setting (using the registry editor in VS) for mscoree.dll is not working (meaning it seems to do nothing). The full registry path is: HKEY_CLASSES_ROOT\CLSID{my_GUID}\InprocServer32(default) and the value I am setting is: [SystemFolder]mscoree.dll I can put anything (including hardcoding the full path) but the setting does not seem to matter and the registry always contains mscoree.dll without any path. I have tried adding another value to the registry path via VS and that works correctly including having the full path as specified by [SystemFolder]. The reason I need the full path (as explained in the previous question) is that without the path, Excel generates an error when the automation server is selected as it cannot find mscoree.dll (interestingly even though I receive an error the registration works OK). I am doing the install via a setup project which otherwise works fine. I am installing on a VISTA*64 system but have gotten the same error on other OS's. Does anyone know what I am doing wrong?

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  • boost::filesystem - how to create a boost path from a windows path string on posix plattforms?

    - by VolkA
    I'm reading path names from a database which are stored as relative paths in Windows format, and try to create a boost::filesystem::path from them on a Unix system. What happens is that the constructor call interprets the whole string as the filename. I need the path to be converted to a correct Posix path as it will be used locally. I didn't find any conversion functions in the boost::filesystem reference, nor through google. Am I just blind, is there an obvious solution? If not, how would you do this? Example: std::string win_path("foo\\bar\\asdf.xml"); std::string posix_path("foo/bar/asdf.xml"); // loops just once, as part is the whole win_path interpreted as a filename boost::filesystem::path boost_path(win_path); BOOST_FOREACH(boost::filesystem::path part, boost_path) { std::cout << part << std::endl; } // prints each path component separately boost::filesystem::path boost_path_posix(posix_path); BOOST_FOREACH(boost::filesystem::path part, boost_path_posix) { std::cout << part << std::endl; }

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  • Get filename from path

    - by Eric
    I am trying to parse the filename from paths. I have this: my $filepath = "/Users/Eric/Documents/foldername/filename.pdf"; $filepath =~ m/^.*\\(.*[.].*)$/; print "Linux path:"; print $1 . "\n\n"; print "-------\n"; my $filepath = "c:\\Windows\eric\filename.pdf"; $filepath =~ m/^.*\\(.*[.].*)$/; print "Windows path:"; print $1 . "\n\n"; print "-------\n"; my $filepath = "filename.pdf"; $filepath =~ m/^.*\\(.*[.].*)$/; print "Without path:"; print $1 . "\n\n"; print "-------\n"; But that returns: Linux path: ------- Windows path:Windowsic ilename.pdf ------- Without path:Windowsic ilename.pdf ------- I am expecting this: Linux path: filename.pdf ------- Windows path: filename.pdf ------- Without path: filename.pdf ------- Can somebody please point out what I am doing wrong? Thanks! :)

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  • How To Disconnect Non-Mapped UNC Path “Drives” in Windows

    - by The Geek
    Have you ever browsed over to another PC on your network using “network neighborhood”, and then connected to one of the file shares? Without a drive letter, how do you disconnect yourself once you’ve done so? Really confused as to what I’m talking about? Let’s walk through the process. First, imagine that you browse through and connect to a share, entering your username and password to gain access. The problem is that you stay connected, and there’s no visible way to disconnect yourself. If you try and shut down the other PC, you’ll receive a message that users are still connected. So let’s disconnect! Open up a command prompt, and then type in the following: net use This will give you a list of the connected drives, including the ones that aren’t actually mapped to a drive letter. To disconnect one of the connections, you can use the following command: net use /delete \\server\sharename For example, in this instance we’d disconnect like so: net use /delete \\192.168.1.205\root$ Now when you run the “net use” command again, you’ll see that you’ve been properly disconnected. If you wanted to actually connect to a share without mapping a drive letter, you can do the following: net use /user:Username \\server\sharename Password You could then just pop \\server\sharename into a Windows Explorer window and browse the files that way. Note that this technique should work exactly the same in any version of windows. Similar Articles Productive Geek Tips Remove "Map Network Drive" Menu Item from Windows Vista or XPDisable the Annoying "This page has an unspecified potential security risk" When Using Files on a Network ShareCopy Path of a File to the Clipboard in Windows 7 or VistaMap a Network Drive from XP to Windows 7Defrag Multiple Hard Drives At Once In Windows TouchFreeze Alternative in AutoHotkey The Icy Undertow Desktop Windows Home Server – Backup to LAN The Clear & Clean Desktop Use This Bookmarklet to Easily Get Albums Use AutoHotkey to Assign a Hotkey to a Specific Window Latest Software Reviews Tinyhacker Random Tips DVDFab 6 Revo Uninstaller Pro Registry Mechanic 9 for Windows PC Tools Internet Security Suite 2010 Enable DreamScene in Windows 7 Microsoft’s “How Do I ?” Videos Home Networks – How do they look like & the problems they cause Check Your IMAP Mail Offline In Thunderbird Follow Finder Finds You Twitter Users To Follow Combine MP3 Files Easily

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  • Spotlight on a career path: Paul, Business Development Consultant

    - by Maria Sandu
    I came to work for Oracle in November 2012 as a Customer Intelligence Representative and since then I was promoted to a Business Development Consultant, for Commercial Industries in the UK, based in Dublin. My background was primarily in Logistics, working for such companies as Indaver Ireland, Wincanton and P&O. I spent 10 years working in this industry and gained experience in negotiating with customers and suppliers in order to meet the needs of both, monitoring the quality and quantity of goods as well as the efficiency and organisation of the movement and storage of products. I decided to move from my logistics career in 2009 to study Information Technology in D.I.T. This was a challenge for me to move my career path; however the lectures at the college helped me significantly with the ability to understand how IT can have an effect on how businesses operate. Following on from college I came to work for Oracle. This also presented challenges but the training I received and the encouragement from management helped me understand that the same business rules apply no matter what background you come from. I have also learnt that using my past experience in working with customers and suppliers in Logistics has helped me understand how to meet customer’s needs. Oracle has offered me excellent training such as Sandler Sales Techniques and John Costigan. I continue to get all the training that I need to develop my career. If you’re interested in joining the Business Development Group visit http://bit.ly/oracledirectcareers or follow our CareersatOracle Facebook Community! /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0in 5.4pt 0in 5.4pt; mso-para-margin-top:0in; mso-para-margin-right:0in; mso-para-margin-bottom:10.0pt; mso-para-margin-left:0in; line-height:115%; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Calibri","sans-serif"; mso-ascii-font-family:Calibri; mso-ascii-theme-font:minor-latin; mso-fareast-font-family:"Times New Roman"; mso-fareast-theme-font:minor-fareast; mso-hansi-font-family:Calibri; mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;}

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  • Inkscape: what are "line" objects?

    - by Peter Mortensen
    What is a "line" object in Inkscape? Drawing lines in Inkscape is by using the tool "Draw Bezier curves and straight lines (Shift+F6)". This creates objects of another type, "path". Using Inkscape: is there a way to convert an object of type "line" into an object of the more general type "path"? I have imported a drawing (mostly lines, rectangles and text) that has been through Adobe Illustrator: originally made in Inkscape, imported into Illustrator, edited, saved from Illustrator as SVG, imported into Inkscape. Sample from the imported SVG file: <path id="path5855" stroke="#000000" d=" M320.198,275.935" /> <line fill="none" stroke="#000000" x1="348.553" y1="45.097" x2="348.553" y2="185.346" id="line3368" /> Update 1: I have inspected the original XML (SVG) file from 2006 and it does not contain any "line" XML tags. Thus it must be a crime of Adobe Illustrator. When a line is selected in this imported SVG file the bottom panel displays: "Line in root. Click selection to toggle scale/rotation handles.". When a line is selected that was drawn in Inkscape the bottom panel displays: "Path (2 nodes) in Layer 1. Click selection to toggle scale/rotation handles." What is the difference between "line" and "path"? Is "line" some kind of read-only/non-editable object? A generic term like "line" is not easy to use in search, but I have now found the definitions for "line" and "path": SVG line: http://www.w3schools.com/svg/svg_line.asp SVG path: http://www.w3schools.com/svg/svg_path.asp Platform: Inkscape v0.46 (2008-03-10), Windows XP 64 bit, 8 GB RAM.

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  • Finding the shortest path between two points on a grid, using Haskell.

    - by esperantist
    This is a problem that I can easily enough solve in a non-functional manner. But solving it in Haskell is giving me big problems. Me being inexperienced when it comes to functional programming is surely a reason. The problem: I have a 2D field divided into rectangles of equal size. A simple grid. Some rectangles are empty space (and can be passed through) while others are impassable. Given a starting rectangle A and a destination rectangle B, how would I calculate the shortest path between the two? Movement is possible only vertically and horizontally, in steps a single rectangle large. How would I go about accomplishing this in Haskell? Code snippets certainly welcome, but also certainly not neccessary. And links to further resources also very welcome! Thanks!

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  • how to merge multiple url/path into multidimensional array ?

    - by KelNoReem
    I have array like this: $path = array ( [0] => site\projects\terrace_and_balcony\mexico.jpg [1] => site\projects\terrace_and_balcony\new_york.jpg [2] => site\projects\terrace_and_balcony\berlin.jpg [3] => site\projects\terrace_and_balcony\Kentucky.jpg [4] => site\projects\terrace_and_balcony\Utah.jpg [5] => site\projects\terrace_and_balcony\Hawaii.jpg [6] => site\projects\private_gardens\mexico.jpg [7] => site\projects\private_gardens\new_york.jpg [8] => site\projects\private_gardens\berlin.jpg [9] => site\projects\private_gardens\Kentucky.jpg [10] => site\projects\private_gardens\Utah.jpg [11] => site\projects\private_gardens\Hawaii.jpg ) How to convert it to that: $path11 = array ( "site"=>array ( "projects"=>array ( "terrace_and_balcony"=>array ( "mexico.jpg", "new_york.jpg", "berlin.jpg", "Kentucky.jpg", "Utah.jpg", "Hawaii.jpg" ), "private_gardens"=>array ( "mexico.jpg", "new_york.jpg", "berlin.jpg", "Kentucky.jpg", "Utah.jpg", "Hawaii.jpg" ) ) ) );

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  • Clipping different parts of an image with path

    - by huggie
    I've recently asked a question about clipping an image via path at view's drawRect method. http://stackoverflow.com/questions/2570653/iphone-clip-image-with-path Krasnyk's code is copied below. - (void)drawRect:(CGRect)rect { CGContextRef context = UIGraphicsGetCurrentContext(); CGMutablePathRef path = CGPathCreateMutable(); //or for e.g. CGPathAddRect(path, NULL, CGRectInset([self bounds], 10, 20)); CGPathAddEllipseInRect(path, NULL, [self bounds]); CGContextAddPath(context, path); CGContextClip(context); CGPathRelease(path); [[UIImage imageNamed:@"GC.png"] drawInRect:[self bounds]]; } It works very well. However, when my image is larger than the view itself, how do I show different parts of the image? I tried tweaking around with translation on the locations (show as bounds above) of ellipse and/or UIImage drawInRect but some complex effects (Unwanted clipping, weird elipse size) I can't explain happens.

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  • How do find the longest path in a cyclic Graph between two nodes?

    - by Nazgulled
    Hi, I already solved most the questions posted here, all but the longest path one. I've read the Wikipedia article about longest paths and it seems any easy problem if the graph was acyclic, which mine is not. How do I solve the problem then? Brute force, by checking all possible paths? How do I even begin to do that? I know it's going to take A LOT on a Graph with ~18000. But I just want to develop it anyway, cause it's required for the project and I'll just test it and show it to the instructor on a smaller scale graph where the execution time is just a second or two. At least I did all tasks required and I have a running proof of concept that it works but there's no better way on cyclic graphs. But I don't have clue where to start checking all these paths...

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  • shell script fun! how to perform an action on each subdirectory from a given path??

    - by pocketfullofcheese
    I am writing a shell script (which I suck at) and I need some help. Its a script that is moving things from git to CVS (not important). The thing is, i a file path: controllers/listbuilder/setup/SubmissionRolesListbuilderHandler.inc.php and I need to be able to do: cvs add controllers; cvs add controllers/listbuilder; cvs add controllers/listbuilder/setup; cvs add controllers/listbuilder/setup/SubmissionRolesListbuilderHandler.inc.php Can someone help me out? The best I've come up with so far is to recursively add ALL files in my working tree, but that seems overly inefficient.

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  • shell script fun! performing action on each subdirectory from a given path

    - by pocketfullofcheese
    I am writing a shell script (which I suck at) and I need some help. Its a script that is moving things from git to CVS (not important). The thing is, i a file path: controllers/listbuilder/setup/SubmissionRolesListbuilderHandler.inc.php and I need to be able to do: cvs add controllers; cvs add controllers/listbuilder; cvs add controllers/listbuilder/setup; cvs add controllers/listbuilder/setup/SubmissionRolesListbuilderHandler.inc.php Can someone help me out? The best I've come up with so far is to recursively add ALL files in my working tree, but that seems overly inefficient.

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  • How to set the path to "context path" for uploaded files using Apache Common fileupload?

    - by BugKiller
    Hi, I'm using Apache common fileupload library with Netbeans 6.8 + Glassfish.I'm trying to change the current upload path to be in the current context path of the servlet , something like this: WEB-INF/upload so I wrote : File uploadedFile = new File("WEB-INF/upload/"+fileName); session.setAttribute("path",uploadedFile.getAbsolutePath()); item.write(uploadedFile); but I notice that the library save the uploaded files into glassfish folder , here what I get when I print the absolute path of the uploaded file : C:\Program Files\sges-v3\glassfish\domains\domain1\WEB-INF\upload\xx.rar My Question : How can I force the common fileupload to save the uploaded file in a path relative to the current servlet path , so I don't need to specify the whole path ? is this possible ?

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  • Can't Use Path in ASP MVC Action

    - by user1477388
    I am trying to use Path() but it has a blue line under it and says, "local variable (path) cannot be referred to until it is declared." How can I use Path()? Imports System.Globalization Imports System.IO Public Class MessageController Inherits System.Web.Mvc.Controller <EmployeeAuthorize()> <HttpPost()> Function SendReply(ByVal id As Integer, ByVal message As String, ByVal files As IEnumerable(Of HttpPostedFileBase)) As JsonResult ' upload files For Each i In files If (i.ContentLength > 0) Then Dim fileName = path.GetFileName(i.FileName) Dim path = path.Combine(Server.MapPath("~/App_Data/uploads"), fileName) i.SaveAs(path) End If Next End Function End Class

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  • Python os module path functions

    - by broiyan
    From the documentation: os.path.realpath(path) Return the canonical path of the specified filename, eliminating any symbolic links encountered in the path (if they are supported by the operating system). When I invoke this with an extant file's name, I get the path to it: /home/myhome/myproject. When I invoke this with a 'nonsense.xxx' string argument, I still get a path to /home/myhome/myproject/nonsense.xxx. This is a little inconsistent because it looks like nonsense.xxx is taken to be a directory not a file (though it is neither: it does not exist). When I invoke this with a null string file name, I still get a path to /home/myhome/myproject. How can I account for this behaviour when the documentation says so little about realpath()? (I am using Python 2.5.) Edit: Somebody suggested a way to test if files exist. My concern is not to test if files exist. My concern is to account for behaviour.

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  • comments in svg path

    - by dr jerry
    I'm experimenting with jquery and svg, I make up my path but now I want to change that (based on some user input) I do something like var dpath = $('path').attr("d"); $('path').attr("d",dpath.replace("150 150", "450 450")); which works fine, but this not useful when my path grows, so I wonder is there a possibility to put a label or a comment in the path to serve as a replace hook? searching for svg path comments gives me all. I'm close to write my own "replaceble" pseudo svg path code, but is there an alternative possible in svg? regards, Jeroen.

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  • How to add folder to assembly search path at runtime in .NET?

    - by Valery Tydykov
    My DLLs are loaded by a third-party application, which we can not customize. My assemblies have to be located in their own folder. I can not put them into GAC (my application has a requirement to be deployed using XCOPY). When the root DLL tries to load resource or type from another DLL (in the same folder), the loading fails (FileNotFound). Is it possible to add the folder where my DLLs are located to the assembly search path programmatically (from the root DLL)? I am not allowed to change the configuration files of the application.

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