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  • Incremement Page Hit Count in Django

    - by Andrew C
    I have a table with an IntegerField (hit_count), and when a page is visited (ie. http://site/page/3) I want record id 3 'hit_count' column in the database to increment by 1. The query should be like: update table set hit_count = hit_count + 1 where id=3 Can I do this with the standard Django Model conventions? Or should I just write the query by hand? I'm starting a new project, so I am trying to avoid hacks. We'll see how long this lasts! Thanks!

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  • Declare models elsewhere than in "models.py"

    - by sebpiq
    Hi ! I have an application that splits models into different files. Actually the folder looks like : >myapp __init__.py models.py >hooks ... ... myapp don't care about what's in the hooks, folder, except that there are models, and that they have to be declared somehow. So, I put this in myapp.__init__.py : from django.conf import settings for hook in settings.HOOKS : try : __import__(hook) except ImportError as e : print "Got import err !", e #where HOOKS = ("myapp.hooks.a_super_hook1", ...) The problem is that it doesn't work when I run syncdb(and throws some strange "Got import err !"... strange considering that it's related to another module of my program that I don't even import anywhere :/ ) ! So I tried successively : 1) for hook in settings.HOOKS : try : exec ("from %s import *" % hook) doesn't work either : syncdb doesn't install the models in hooks 2) from myapp.hooks.a_super_hook1 import * This works 3) exec("from myapp.hooks.a_super_hook1 import *") This works to So I checked that in the test 1), the statement executed is the same than in tests 2) and 3), and it is exactly the same ... Any idea ???

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  • some register.inclusion_tag error in my code using django

    - by zjm1126
    my helloworld_tags: from django import template register = template.Library() def show_profile(): return {"eee": '333'} register.inclusion_tag("b.html")(show_profile) my view: def b(request): return render_to_response('b.html') my html: {% load helloworld_tags%} dsad {{ eee }} but only show 'dsad' ,not show 'dsad333' why?? thanks

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  • Will this SQL screw up

    - by Joshua
    I'm sure everyone knows the joys of concurrency when it comes to threading. Imagine the following scenario on every page-load on a noobily set up MySQL db: UPDATE stats SET visits = (visits+1) If a thousand users load the page at same time, will the count screw up? is this that table locking/row locking crap? Which one mysql use.

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  • Is there a functional way to do this?

    - by Ishpeck
    def flattenList(toFlatten): final=[] for el in toFlatten: if isinstance(el, list): final.extend(flattenList(el)) else: final.append(el) return final When I don't know how deeply the lists will nest, this is the only way I can think to do this. 2

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  • Detect if 2 HTML fragments have identical hierarchical structure

    - by sergzach
    An example of fragments that have identical hierarchical structure: (1) <div> <span>It's a message</span> </div> (2) <div> <span class='bold'>This is a new text</span> </div> An example of fragments that have different structure: (1) <div> <span><b>It's a message</b></span> </div> (2) <div> <span>This is a new text</span> </div> So, fragments with a similar structure correspond to one hierarchical tree (the same tag names, the same hierarchical structure). How can I detect if 2 elements (html fragments) have the same structure simply with lxml? I have a function that does not work properly for some more difficult case (than the example): def _is_equal( el1, el2 ): # input: 2 elements with possible equal structure and tag names # e.g. root = lxml.html.fromstring( buf ) # el1 = root[ 0 ] # el2 = root[ 1 ] # move from top to bottom, compare elements result = False if el1.tag == el2.tag: # has no children if len( el1 ) == len( el2 ): if len( el1 ) == 0: return True else: # iterate one of them, for example el1 i = 0 for child1 in el1: child2 = el2[ i ] is_equal2 = _is_equal( child1, child2 ) if not is_equal2: return False return True else: return False else: return False The code fails to detect that 2 divs with class='tovar2' have an identical structure: <body> <div class="tovar2"> <h2 class="new"> <a href="http://modnyedeti-krsk.ru/magazin/product/333193003"> ?????? ?/? </a> </h2> <ul class="art"> <li> ???????: <span>1759</span> </li> </ul> <div> <div class="wrap" style="width:180px;"> <div class="new"> <img src="shop_files/new-t.png" alt=""> </div> <a class="highslide" href="http://modnyedeti-krsk.ru/d/459730/d/820.jpg" onclick="return hs.expand(this)"> <img src="shop_files/fr_5.gif" style="background:url(/d/459730/d/548470803_5.jpg) 50% 50% no-repeat scroll;" alt="?????? ?/?" height="160" width="180"> </a> </div> </div> <form action="" onsubmit="return addProductForm(17094601,333193003,3150.00,this,false);"> <ul class="bott "> <li class="price">????:<br> <span> <b> 3 150 </b> ???. </span> </li> <li class="amount">???-??:<br><input class="number" onclick="this.select()" value="1" name="product_amount" type="text"> </li> <li class="buy"><input value="" type="submit"> </li> </ul> </form> </div> <div class="tovar2"> <h2 class="new"> <a href="http://modnyedeti-krsk.ru/magazin/product/333124803">?????? ?/?</a> </h2> <ul class="art"> <li> ???????: <span>1759</span> </li> </ul> <div> <div class="wrap" style="width:180px;"> <div class="new"> <img src="shop_files/new-t.png" alt=""> </div> <a class="highslide" href="http://modnyedeti-krsk.ru/d/459730/d/820.jpg" onclick="return hs.expand(this)"> <img src="shop_files/fr_5.gif" style="background:url(/d/459730/d/548470803_5.jpg) 50% 50% no-repeat scroll;" alt="?????? ?/?" height="160" width="180"> </a> </div> </div> <form action="" onsubmit="return addProductForm(17094601,333124803,3150.00,this,false);"> <ul class="bott "> <li class="price">????:<br> <span> <b>3 150</b> ???. </span> </li> <li class="amount">???-??:<br><input class="number" onclick="this.select()" value="1" name="product_amount" type="text"> </li> <li class="buy"> <input value="" type="submit"> </li> </ul> </form> </div> </body>

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  • Simple numpy question

    - by dassouki
    I can't get this snippet to work: #base code A = array([ [ 1, 2, 10 ], [ 1, 3, 20 ], [ 1, 4, 30 ], [ 2, 1, 15 ], [ 2, 3, 25 ], [ 2, 4, 35 ], [ 3, 1, 17 ], [ 3, 2, 27 ], [ 3, 4, 37 ], [ 4, 1, 13 ], [ 4, 2, 23 ], [ 4, 3, 33 ] ]) # Number of zones zones = unique1d(A[:,0]) for origin in zones: for destination in zones: if origin != destination: A_ik = A[(A[:,0] == origin & A[:,1] == destination), 2]

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  • def constrainedMatchPair(firstMatch,secondMatch,length):

    - by smart
    matches of a key string in a target string, where one of the elements of the key string is replaced by a different element. For example, if we want to match ATGC against ATGACATGCACAAGTATGCAT, we know there is an exact match starting at 5 and a second one starting at 15. However, there is another match starting at 0, in which the element A is substituted for C in the key, that is we match ATGC against the target. Similarly, the key ATTA matches this target starting at 0, if we allow a substitution of G for the second T in the key string. consider the following steps. First, break the key string into two parts (where one of the parts could be an empty string). Let's call them key1 and key2. For each part, use your function from Problem 2 to find the starting points of possible matches, that is, invoke starts1 = subStringMatchExact(target,key1) and starts2 = subStringMatchExact(target,key2) The result of these two invocations should be two tuples, each indicating the starting points of matches of the two parts (key1 and key2) of the key string in the target. For example, if we consider the key ATGC, we could consider matching A and GC against a target, like ATGACATGCA (in which case we would get as locations of matches for A the tuple (0, 3, 5, 9) and as locations of matches for GC the tuple (7,). Of course, we would want to search over all possible choices of substrings with a missing element: the empty string and TGC; A and GC; AT and C; and ATG and the empty string. Note that we can use your solution for Problem 2 to find these values. Once we have the locations of starting points for matches of the two substrings, we need to decide which combinations of a match from the first substring and a match of the second substring are correct. There is an easy test for this. Suppose that the index for the starting point of the match of the first substring is n (which would be an element of starts1), and that the length of the first substring is m. Then if k is an element of starts2, denoting the index of the starting point of a match of the second substring, there is a valid match with one substitution starting at n, if n+m+1 = k, since this means that the second substring match starts one element beyond the end of the first substring. finally the question is Write a function, called constrainedMatchPair which takes three arguments: a tuple representing starting points for the first substring, a tuple representing starting points for the second substring, and the length of the first substring. The function should return a tuple of all members (call it n) of the first tuple for which there is an element in the second tuple (call it k) such that n+m+1 = k, where m is the length of the first substring.

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  • Import Error: No module named testrunner

    - by JiL
    I followed this to add zc.recipe.testrunner to my buildout. I can run buildout successfully but when I run bin/test, I get: ImportError: No module named testrunner I have zope.testrunner-4.0.4-py2.4.egg in /usr/local/lib/python2.4/site-packages I also pinned zope.testrunner = 4.0.4 zc.recipe.testruner = 1.4.0 zc.recipe.egg = 1.3.2 When I ran buildout, I used -vvv and I got: ... Installing 'zc.recipe.testrunner'. We have the distribution that satisfies 'zc.recipe.testrunner==1.4.0'. Egg from site-packages: z3c.recipe.scripts 1.0.1 Egg from site-packages: zope.testrunner 4.0.4 Egg from site-packages: zope.interface 3.8.0 Egg from site-packages: zope.exceptions 3.7.1 ... We have the distribution that satisfies 'zope.testrunner==4.0.4'. Egg from site-packages: zope.testrunner 4.0.4 Adding required 'zope.interface' required by zope.testrunner 4.0.4. We have a develop egg: zope.interface 0.0 Adding required 'zope.exceptions' required by zope.testrunner 4.0.4. We have a develop egg: zope.exceptions 0.0 ... Why is it I get an ImportError? Is zope.testrunner not installed correctly?

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  • How to get the related_name of a many-to-many-field?

    - by amann
    I am trying to get the related_name of a many-to-many-field. The m2m-field is located betweeen the models "Group" and "Lection" and is declared in the group-model as following: lections = models.ManyToManyField(Lection, blank=True) The field looks like this: <django.db.models.fields.related.ManyToManyField object at 0x012AD690> The print of field.__dict__ is: {'_choices': [], '_m2m_column_cache': 'group_id', '_m2m_name_cache': 'group', '_m2m_reverse_column_cache': 'lection_id', '_m2m_reverse_name_cache': 'lection', '_unique': False, 'attname': 'lections', 'auto_created': False, 'blank': True, 'column': 'lections', 'creation_counter': 71, 'db_column': None, 'db_index': False, 'db_table': None, 'db_tablespace': '', 'default': <class django.db.models.fields.NOT_PROVIDED at 0x00FC8780>, 'editable': True, 'error_messages': {'blank': <django.utils.functional.__proxy__ object at 0x00FC 7B50>, 'invalid_choice': <django.utils.functional.__proxy__ object at 0x00FC7A50>, 'null': <django.utils.functional.__proxy__ object at 0x00FC7 A70>}, 'help_text': <django.utils.functional.__proxy__ object at 0x012AD6F0>, 'm2m_column_name': <function _curried at 0x012A88F0>, 'm2m_db_table': <function _curried at 0x012A8AF0>, 'm2m_field_name': <function _curried at 0x012A8970>, 'm2m_reverse_field_name': <function _curried at 0x012A89B0>, 'm2m_reverse_name': <function _curried at 0x012A8930>, 'max_length': None, 'name': 'lections', 'null': False, 'primary_key': False, 'rel': <django.db.models.fields.related.ManyToManyRel object at 0x012AD6B0>, 'related': <RelatedObject: mymodel:group related to lections>, 'related_query_name': <function _curried at 0x012A8670>, 'serialize': True, 'unique_for_date': None, 'unique_for_month': None, 'unique_for_year': None, 'validators': [], 'verbose_name': 'lections'} Now the field should be accessed via a lection-instance. So this is done by lection.group_set But i need to access it dynamically, so there is the need to get the related_name attribute from somewhere. Here in the documentation, there is a note that it is possible to access ManyToManyField.related_name, but this doesn't work for my somehow.. Help would be a lot appreciated. Thanks in advance.

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  • Why do all module run together?

    - by gunbuster363
    I just made a fresh copy of eclipse and installed pydev. In my first trial to use pydev with eclipse, I created 2 module under the src package(the default one) FirstModule.py: ''' Created on 18.06.2009 @author: Lars Vogel ''' def add(a,b): return a+b def addFixedValue(a): y = 5 return y +a print "123" run.py: ''' Created on Jun 20, 2011 @author: Raymond.Yeung ''' from FirstModule import add print add(1,2) print "Helloword" When I pull out the pull down menu of the run button, and click "ProjectName run.py", here is the result: 123 3 Helloword Apparantly both module ran, why? Is this the default setting?

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  • Update Facebook Page's status using pyfacebook

    - by thornomad
    I am attempting to add functionality to my Django app: when a new post is approved, I want to update the corresponding Facebook Page's status with a message and a link to the post automatically. Basic status update. I have downloaded and installed pyfacebook - and I have read through the tutorial from Facebook. I have also seen this suggestion here on SO: import facebook fb = facebook.Facebook('YOUR_API_KEY', 'YOUR_SECRET_KEY') fb.auth.createToken() fb.login() # THIS IS AS FAR AS I CAN GET fb.auth.getSession() fb.set_status('Checking out StackOverFlow.com') When I get to the login() call, however, pyfacebook tries to open lynx so I can login to Facebook 'via the web' -- this is, obviously, not going to work for me because the system is supposed to be automated ... I've been looking, but can't find out how I can keep this all working with the script and not having to login via a web browser. Any ideas?

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  • Why does SQLAlchemy with psycopg2 use_native_unicode have poor performance?

    - by Bob Dover
    I'm having a difficult time figuring out why a simple SELECT query is taking such a long time with sqlalchemy using raw SQL (I'm getting 14600 rows/sec, but when running the same query through psycopg2 without sqlalchemy, I'm getting 38421 rows/sec). After some poking around, I realized that toggling sqlalchemy's use_native_unicode parameter in the create_engine call actually makes a huge difference. This query takes 0.5secs to retrieve 7300 rows: from sqlalchemy import create_engine engine = create_engine("postgresql+psycopg2://localhost...", use_native_unicode=True) r = engine.execute("SELECT * FROM logtable") fetched_results = r.fetchall() This query takes 0.19secs to retrieve the same 7300 rows: engine = create_engine("postgresql+psycopg2://localhost...", use_native_unicode=False) r = engine.execute("SELECT * FROM logtable") fetched_results = r.fetchall() The only difference between the 2 queries is use_native_unicode. But sqlalchemy's own docs state that it is better to keep use_native_unicode=True (http://docs.sqlalchemy.org/en/latest/dialects/postgresql.html). Does anyone know why use_native_unicode is making such a big performance difference? And what are the ramifications of turning off use_native_unicode?

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  • Emptying the datastore in GAE

    - by colwilson
    I know what you're thinking, 'O not that again!', but here we are since Google have not yet provided a simpler method. I have been using a queue based solution which worked fine: import datetime from models import * DELETABLE_MODELS = [Alpha, Beta, AlphaBeta] def initiate_purge(): for e in config.DELETABLE_MODELS: deferred.defer(delete_entities, e, 'purging', _queue = 'purging') class NotEmptyException(Exception): pass def delete_entities(e, queue): try: q = e.all(keys_only=True) db.delete(q.fetch(200)) ct = q.count(1) if ct > 0: raise NotEmptyException('there are still entities to be deleted') else: logging.info('processing %s completed' % queue) except Exception, err: deferred.defer(delete_entities, e, then, queue, _queue = queue) logging.info('processing %s deferred: %s' % (queue, err)) All this does is queue a request to delete some data (once for each class) and then if the queued process either fails or knows there is still some stuff to delete, it re-queues itself. This beats the heck out of hitting the refresh on a browser for 10 minutes. However, I'm having trouble deleting AlphaBeta entities, there are always a few left at the end. I think because it contains Reference Properties: class AlphaBeta(db.Model): alpha = db.ReferenceProperty(Alpha, required=True, collection_name='betas') beta = db.ReferenceProperty(Beta, required=True, collection_name='alphas') I have tried deleting the indexes relating to these entity types, but that did not make any difference. Any advice would be appreciated please.

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  • Django dictionary in templates: Grab key from another objects attribute

    - by Jordan Messina
    I have a dictionary called number_devices I'm passing to a template, the dictionary keys are the ids of a list of objects I'm also passing to the template (called implementations). I'm iterating over the list of objects and then trying to use the object.id to get a value out of the dict like so: {% for implementation in implementations %} {{ number_devices.implementation.id }} {% endfor %} Unfortunately number_devices.implementation is evaluated first, then the result.id is evaluated obviously returning and displaying nothing. I can't use parentheses like: {{ number_devices.(implementation.id) }} because I get a parse error. How do I get around this annoyance in Django templates? Thanks for any help!

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  • Find next lower item in a sorted list

    - by Sebastian
    Hey guys, let's say I have a sorted list of Floats. Now I'd like to get the index of the next lower item of a given value. The usual for-loop aprroach has a complexity of O(n). Since the list is sorted there must be a way to get the index with O(log n). My O(n) approach: index=0 for i,value in enumerate(mylist): if value>compareValue: index=i-1 Is there a datatype for solving that problem in O(log n)? best regards Sebastian

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  • How to give points for each indices of list

    - by Eric Jung
    def voting_borda(rank_ballots): '''(list of list of str) -> tuple of (str, list of int) The parameter is a list of 4-element lists that represent rank ballots for a single riding. The Borda Count is determined by assigning points according to ranking. A party gets 3 points for each first-choice ranking, 2 points for each second-choice ranking and 1 point for each third-choice ranking. (No points are awarded for being ranked fourth.) For example, the rank ballot shown above would contribute 3 points to the Liberal count, 2 points to the Green count and 1 point to the CPC count. The party that receives the most points wins the seat. Return a tuple where the first element is the name of the winning party according to Borda Count and the second element is a four-element list that contains the total number of points for each party. The order of the list elements corresponds to the order of the parties in PARTY_INDICES.''' #>>> voting_borda([['GREEN','NDP', 'LIBERAL', 'CPC'], ['GREEN','CPC','LIBERAL','NDP'], ['LIBERAL','NDP', 'CPC', 'GREEN']]) #('GREEN',[4, 6, 5, 3]) list_of_party_order = [] for sublist in rank_ballots: for party in sublist[0]: if party == 'GREEN': GREEN_COUNT += 3 elif party == 'NDP': NDP_COUNT += 3 elif party == 'LIBERAL': LIBERAL_COUNT += 3 elif party == 'CPC': CPC_COUNT += 3 for party in sublist[1]: if party == 'GREEN': GREEN_COUNT += 2 elif party == 'NDP': NDP_COUNT += 2 elif party == 'LIBERAL': LIBERAL_COUNT += 2 elif party == 'CPC': CPC_COUNT += 2 for party in sublist[2]: if party == 'GREEN': GREEN_COUNT += 1 elif party == 'NDP': NDP_COUNT += 1 elif party == 'LIBERAL': LIBERAL_COUNT += 1 elif party == 'CPC': CPC_COUNT += 1 I don't know how I would give points for each indices of the list MORE SIMPLY. Can someone please help me? Without being too complicated. Thank you!

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