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  • WPF Blurry Images - Bitmap Class

    - by Luke
    I am using the following sample at http://blogs.msdn.com/dwayneneed/archive/2007/10/05/blurry-bitmaps.aspx within VB.NET. The code is shown below. I am having a problem when my application loads the CPU is pegging 50-70%. I have determined that the problem is with the Bitmap class. The OnLayoutUpdated() method is calling the InvalidateVisual() continously. This is because some points are not returning as equal but rather, Point(0.0,-0.5) Can anyone see any bugs within this code or know a better implmentation for pixel snapping a Bitmap image so it is not blurry? p.s. The sample code was in C#, however I believe that it was converted correctly. Imports System Imports System.Collections.Generic Imports System.Windows Imports System.Windows.Media Imports System.Windows.Media.Imaging Class Bitmap Inherits FrameworkElement ' Use FrameworkElement instead of UIElement so Data Binding works as expected Private _sourceDownloaded As EventHandler Private _sourceFailed As EventHandler(Of ExceptionEventArgs) Private _pixelOffset As Windows.Point Public Sub New() _sourceDownloaded = New EventHandler(AddressOf OnSourceDownloaded) _sourceFailed = New EventHandler(Of ExceptionEventArgs)(AddressOf OnSourceFailed) AddHandler LayoutUpdated, AddressOf OnLayoutUpdated End Sub Public Shared ReadOnly SourceProperty As DependencyProperty = DependencyProperty.Register("Source", GetType(BitmapSource), GetType(Bitmap), New FrameworkPropertyMetadata(Nothing, FrameworkPropertyMetadataOptions.AffectsRender Or FrameworkPropertyMetadataOptions.AffectsMeasure, New PropertyChangedCallback(AddressOf Bitmap.OnSourceChanged))) Public Property Source() As BitmapSource Get Return DirectCast(GetValue(SourceProperty), BitmapSource) End Get Set(ByVal value As BitmapSource) SetValue(SourceProperty, value) End Set End Property Public Shared Function FindParentWindow(ByVal child As DependencyObject) As Window Dim parent As DependencyObject = VisualTreeHelper.GetParent(child) 'Check if this is the end of the tree If parent Is Nothing Then Return Nothing End If Dim parentWindow As Window = TryCast(parent, Window) If parentWindow IsNot Nothing Then Return parentWindow Else ' Use recursion until it reaches a Window Return FindParentWindow(parent) End If End Function Public Event BitmapFailed As EventHandler(Of ExceptionEventArgs) ' Return our measure size to be the size needed to display the bitmap pixels. ' ' Use MeasureOverride instead of MeasureCore so Data Binding works as expected. ' Protected Overloads Overrides Function MeasureCore(ByVal availableSize As Size) As Size Protected Overloads Overrides Function MeasureOverride(ByVal availableSize As Size) As Size Dim measureSize As New Size() Dim bitmapSource As BitmapSource = Source If bitmapSource IsNot Nothing Then Dim ps As PresentationSource = PresentationSource.FromVisual(Me) If Me.VisualParent IsNot Nothing Then Dim window As Window = window.GetWindow(Me.VisualParent) If window IsNot Nothing Then ps = PresentationSource.FromVisual(window.GetWindow(Me.VisualParent)) ElseIf FindParentWindow(Me) IsNot Nothing Then ps = PresentationSource.FromVisual(FindParentWindow(Me)) End If End If ' If ps IsNot Nothing Then Dim fromDevice As Matrix = ps.CompositionTarget.TransformFromDevice Dim pixelSize As New Vector(bitmapSource.PixelWidth, bitmapSource.PixelHeight) Dim measureSizeV As Vector = fromDevice.Transform(pixelSize) measureSize = New Size(measureSizeV.X, measureSizeV.Y) Else measureSize = New Size(bitmapSource.PixelWidth, bitmapSource.PixelHeight) End If End If Return measureSize End Function Protected Overloads Overrides Sub OnRender(ByVal dc As DrawingContext) Dim bitmapSource As BitmapSource = Me.Source If bitmapSource IsNot Nothing Then _pixelOffset = GetPixelOffset() ' Render the bitmap offset by the needed amount to align to pixels. dc.DrawImage(bitmapSource, New Rect(_pixelOffset, DesiredSize)) End If End Sub Private Shared Sub OnSourceChanged(ByVal d As DependencyObject, ByVal e As DependencyPropertyChangedEventArgs) Dim bitmap As Bitmap = DirectCast(d, Bitmap) Dim oldValue As BitmapSource = DirectCast(e.OldValue, BitmapSource) Dim newValue As BitmapSource = DirectCast(e.NewValue, BitmapSource) If ((oldValue IsNot Nothing) AndAlso (bitmap._sourceDownloaded IsNot Nothing)) AndAlso (Not oldValue.IsFrozen AndAlso (TypeOf oldValue Is BitmapSource)) Then RemoveHandler DirectCast(oldValue, BitmapSource).DownloadCompleted, bitmap._sourceDownloaded RemoveHandler DirectCast(oldValue, BitmapSource).DownloadFailed, bitmap._sourceFailed ' ((BitmapSource)newValue).DecodeFailed -= bitmap._sourceFailed; // 3.5 End If If ((newValue IsNot Nothing) AndAlso (TypeOf newValue Is BitmapSource)) AndAlso Not newValue.IsFrozen Then AddHandler DirectCast(newValue, BitmapSource).DownloadCompleted, bitmap._sourceDownloaded AddHandler DirectCast(newValue, BitmapSource).DownloadFailed, bitmap._sourceFailed ' ((BitmapSource)newValue).DecodeFailed += bitmap._sourceFailed; // 3.5 End If End Sub Private Sub OnSourceDownloaded(ByVal sender As Object, ByVal e As EventArgs) InvalidateMeasure() InvalidateVisual() End Sub Private Sub OnSourceFailed(ByVal sender As Object, ByVal e As ExceptionEventArgs) Source = Nothing ' setting a local value seems scetchy... RaiseEvent BitmapFailed(Me, e) End Sub Private Sub OnLayoutUpdated(ByVal sender As Object, ByVal e As EventArgs) ' This event just means that layout happened somewhere. However, this is ' what we need since layout anywhere could affect our pixel positioning. Dim pixelOffset As Windows.Point = GetPixelOffset() If Not AreClose(pixelOffset, _pixelOffset) Then InvalidateVisual() End If End Sub ' Gets the matrix that will convert a Windows.Point from "above" the ' coordinate space of a visual into the the coordinate space ' "below" the visual. Private Function GetVisualTransform(ByVal v As Visual) As Matrix If v IsNot Nothing Then Dim m As Matrix = Matrix.Identity Dim transform As Transform = VisualTreeHelper.GetTransform(v) If transform IsNot Nothing Then Dim cm As Matrix = transform.Value m = Matrix.Multiply(m, cm) End If Dim offset As Vector = VisualTreeHelper.GetOffset(v) m.Translate(offset.X, offset.Y) Return m End If Return Matrix.Identity End Function Private Function TryApplyVisualTransform(ByVal Point As Windows.Point, ByVal v As Visual, ByVal inverse As Boolean, ByVal throwOnError As Boolean, ByRef success As Boolean) As Windows.Point success = True If v IsNot Nothing Then Dim visualTransform As Matrix = GetVisualTransform(v) If inverse Then If Not throwOnError AndAlso Not visualTransform.HasInverse Then success = False Return New Windows.Point(0, 0) End If visualTransform.Invert() End If Point = visualTransform.Transform(Point) End If Return Point End Function Private Function ApplyVisualTransform(ByVal Point As Windows.Point, ByVal v As Visual, ByVal inverse As Boolean) As Windows.Point Dim success As Boolean = True Return TryApplyVisualTransform(Point, v, inverse, True, success) End Function Private Function GetPixelOffset() As Windows.Point Dim pixelOffset As New Windows.Point() Dim ps As PresentationSource = PresentationSource.FromVisual(Me) If ps IsNot Nothing Then Dim rootVisual As Visual = ps.RootVisual ' Transform (0,0) from this element up to pixels. pixelOffset = Me.TransformToAncestor(rootVisual).Transform(pixelOffset) pixelOffset = ApplyVisualTransform(pixelOffset, rootVisual, False) pixelOffset = ps.CompositionTarget.TransformToDevice.Transform(pixelOffset) ' Round the origin to the nearest whole pixel. pixelOffset.X = Math.Round(pixelOffset.X) pixelOffset.Y = Math.Round(pixelOffset.Y) ' Transform the whole-pixel back to this element. pixelOffset = ps.CompositionTarget.TransformFromDevice.Transform(pixelOffset) pixelOffset = ApplyVisualTransform(pixelOffset, rootVisual, True) pixelOffset = rootVisual.TransformToDescendant(Me).Transform(pixelOffset) End If Return pixelOffset End Function Private Function AreClose(ByVal Point1 As Windows.Point, ByVal Point2 As Windows.Point) As Boolean Return AreClose(Point1.X, Point2.X) AndAlso AreClose(Point1.Y, Point2.Y) End Function Private Function AreClose(ByVal value1 As Double, ByVal value2 As Double) As Boolean If value1 = value2 Then Return True End If Dim delta As Double = value1 - value2 Return ((delta < 0.00000153) AndAlso (delta > -0.00000153)) End Function End Class

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  • How to draw an UIImageView in -drawRect:?

    - by mystify
    I'm trying since 5 hours now: - (void)drawRect:(CGRect)rect { // flip the wrong coordinate system CGContextTranslateCTM(context, 0.0f, rect.size.height); //shift the origin up CGContextScaleCTM(context, 1.0f, -1.0f); //flip the y-axis CGContextDrawImage(context, myImgView.frame, myImageView.image.CGImage); } The problem: While the image draws correctly, the coordinates specified by the UIImageView frame are completely useless. The image appears placed completely wrong on screen. I guess I must also flip the CGRect of the UIImageView? But how?

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  • How to calculate an angle from three points?

    - by HelloMoon
    Lets say you have this: P1 = (x=2, y=50) P2 = (x=9, y=40) P3 = (x=5, y=20) Assume that P1 is the center point of a circle. It is always the same. I want the angle that is made up by P2 and P3, or in other words the angle that is next to P1. The inner angle to be precise. It will be always a sharp angle, so less than -90 degrees. I thought: Man, that's simplest geometry maths. But I looked for a formula for like 6 hours now and people talk about most complicated NASA stuff like arcos and vector scalar product stuff. My head feels like in a fridge. Some math gurus here that think this is a simple problem? I think the programing language doesn't matter here but for those who think it does: java and objective-c. need that for both. haven't tagged it for these, though.

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  • How to follow user location with MapKit

    - by Bloudermilk
    I'm using MapKit to display the user's location relative to pins around them. I'd like to be able to mimic the functionality that Maps provides via the crosshair button in the lower left-hand corner of the screen. I'm already aware that MapKit provides a CLLocation object with the user's location via MKUserLocation, I just wanted to seek advice on how I should keep focus on that location. My initial inclination was to use an NSTimer to center the map on that coordinate every 500ms or so. Is there a better way to do this? Is there something built in to MapKit that I'm missing that will accomplish this? Thanks so much, Brendan

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  • How to Get Current Weather via Web Services

    - by Brandon
    I am attempting to get the current weather given a zip code or a set of latitude/longitude coordinates. It appears that best practice to do this (and how NOAA does it) is to get the XML feed for a weather station. Example: http://www.weather.gov/xml/current_obs/KEDW.xml The only problem is that NOAA doesn't provide a good way to find the closest weather station given a zip code or coordinates and I did not see any hosted web services out there that will provide this mapping. Does anyone know of any web services to get the nearest weather station given a zip code or coordinate input? If not, does anyone have any great solutions to look into that provide similar information as NOAA does but takes in a zip code or coordinates?

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  • MKMapView doesn't want to call didAddAnnotationViews method

    - by TheLearner
    I am writing a little map kit app but it doesn't want to call the delegate method didaddannotationviews: (void)mapView:(MKMapView *)mv didAddAnnotationViews:(NSArray *)views { //Get the first MKAnnotationView from the views returned MKAnnotationView *annotationView = [views objectAtIndex:0]; //Get the annotation from the first annotation view and save it in a variable which can hold any object as long as it implements mkannotation id <MKAnnotation> mp = [annotationView annotation]; //Create a region MKCoordinateRegion region = MKCoordinateRegionMakeWithDistance([mp coordinate], 250, 250); //As the mapview to animate i.e. display the region [mv setRegion:region animated:YES]; } @interface WhereAmIAppDelegate : NSObject { UIWindow *window; CLLocationManager *locationManager; IBOutlet MKMapView *mapView; IBOutlet UIActivityIndicatorView *activityIndicator; IBOutlet UITextField *locationTitleField; }

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  • Covering Earth with Hexagonal Map Tiles

    - by carrier
    Many strategy games use hexagonal tiles. One of the main advantages is that the distance between the center of any tile and all its neighboring tiles is the same. I was wondering if anyone has any thoughts on marrying a hexagonal tile system with the traditional geographic system (longitude/latitude). I think it would be interesting to cover a globe with hexagonal tiles and be able to map a geographic coordinate to a tile. Has anyone seen anything remotely close to this before? UPDATE I'm looking for a way to subdivide the surface of a sphere so that each division has the same surface area. Ideally, the centers of adjacent sub-divisions would be equidistant.

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  • Creating line graph/chart in vb.net (VS2008)

    - by typoknig
    I am reluctant to ask this question because a lot of similar questions have been asked, but after reading through them I am not getting the info I need. I am trying to follow this tutorial and I think it is going to work ok, but I have a lot of data to put in and the tutorial has the reader create the chart data points manually. I want the data points to be generated from an integer which can change while the program is running (thus the chart size needs to change) and the y coordinate of the data points needs to come from an array. I have attempted to "bind" the data but I am messing it up somehow and I don't even think that is the best way to do what I want. Also, I do not have to use the methods suggested in the tutorial, I am looking for the highest quality most efficient way to generate a line graph in vb.net (VS2008) based on the criteria I previously mentioned.

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  • How to simulate a mouse click on a UIWebView in Cocoa for the iPhone?

    - by eagle
    I'm trying to setup automated unit tests for an iPhone application. I'm using a UIWebView and need to simulate clicks on different links. I've tried doing this with JavaScript, but it doesn't produce the same result as when I manually click on the links. The main problem is with links that have their target property set. I believe the only way for this automated unit test to work correctly is to simulate a mouse click at a specific x/y coordinate (i.e. where the link is located). Since the unit testing will only be used internally, private API calls are fine. It seems like this should be possible since the iPhone app isimulate seems to do something similar. Is there any way to do this in the framework?

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  • iPhone MKMapView : the map can’t load completely.

    - by Tattat
    I don't know what's make wrong, my map can load, but the image on the map is not completely load. plx help. thz a lot. Here is the simulate map from the iPhone: (Added more example image.) http://img689.imageshack.us/img689/8476/screenshot20100309at841.jpg Here is the code: MKCoordinateRegion theRegion; MKCoordinateSpan theSpan; theSpan.latitudeDelta = 0.005; theSpan.longitudeDelta = 0.005; theRegion.center =  manager.location.coordinate; theRegion.span = theSpan; myMap.scrollEnabled = YES; myMap.zoomEnabled = YES; [myMap setRegion:theRegion]; [myMap regionThatFits:theRegion];

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  • How to change Matlab program for solving equation with finite element method?

    - by DSblizzard
    I don't know is this question more related to mathematics or programming and I'm absolute newbie in Matlab. Program FEM_50 applies the finite element method to Laplace's equation -Uxx(x, y) - Uyy(x, y) = F(x, y) in Omega. How to change it to apply FEM to equation -Uxx(x, y) - Uyy(x, y) + U(x, y) = F(x, y)? At this page: http://sc.fsu.edu/~burkardt/m_src/fem_50/fem_50.html additional code files in case you need them. function fem_50 ( ) %% FEM_50 applies the finite element method to Laplace's equation. % % Discussion: % % FEM_50 is a set of MATLAB routines to apply the finite % element method to solving Laplace's equation in an arbitrary % region, using about 50 lines of MATLAB code. % % FEM_50 is partly a demonstration, to show how little it % takes to implement the finite element method (at least using % every possible MATLAB shortcut.) The user supplies datafiles % that specify the geometry of the region and its arrangement % into triangular and quadrilateral elements, and the location % and type of the boundary conditions, which can be any mixture % of Neumann and Dirichlet. % % The unknown state variable U(x,y) is assumed to satisfy % Laplace's equation: % -Uxx(x,y) - Uyy(x,y) = F(x,y) in Omega % with Dirichlet boundary conditions % U(x,y) = U_D(x,y) on Gamma_D % and Neumann boundary conditions on the outward normal derivative: % Un(x,y) = G(x,y) on Gamma_N % If Gamma designates the boundary of the region Omega, % then we presume that % Gamma = Gamma_D + Gamma_N % but the user is free to determine which boundary conditions to % apply. Note, however, that the problem will generally be singular % unless at least one Dirichlet boundary condition is specified. % % The code uses piecewise linear basis functions for triangular elements, % and piecewise isoparametric bilinear basis functions for quadrilateral % elements. % % The user is required to supply a number of data files and MATLAB % functions that specify the location of nodes, the grouping of nodes % into elements, the location and value of boundary conditions, and % the right hand side function in Laplace's equation. Note that the % fact that the geometry is completely up to the user means that % just about any two dimensional region can be handled, with arbitrary % shape, including holes and islands. % clear % % Read the nodal coordinate data file. % load coordinates.dat; % % Read the triangular element data file. % load elements3.dat; % % Read the quadrilateral element data file. % load elements4.dat; % % Read the Neumann boundary condition data file. % I THINK the purpose of the EVAL command is to create an empty NEUMANN array % if no Neumann file is found. % eval ( 'load neumann.dat;', 'neumann=[];' ); % % Read the Dirichlet boundary condition data file. % load dirichlet.dat; A = sparse ( size(coordinates,1), size(coordinates,1) ); b = sparse ( size(coordinates,1), 1 ); % % Assembly. % for j = 1 : size(elements3,1) A(elements3(j,:),elements3(j,:)) = A(elements3(j,:),elements3(j,:)) ... + stima3(coordinates(elements3(j,:),:)); end for j = 1 : size(elements4,1) A(elements4(j,:),elements4(j,:)) = A(elements4(j,:),elements4(j,:)) ... + stima4(coordinates(elements4(j,:),:)); end % % Volume Forces. % for j = 1 : size(elements3,1) b(elements3(j,:)) = b(elements3(j,:)) ... + det( [1,1,1; coordinates(elements3(j,:),:)'] ) * ... f(sum(coordinates(elements3(j,:),:))/3)/6; end for j = 1 : size(elements4,1) b(elements4(j,:)) = b(elements4(j,:)) ... + det([1,1,1; coordinates(elements4(j,1:3),:)'] ) * ... f(sum(coordinates(elements4(j,:),:))/4)/4; end % % Neumann conditions. % if ( ~isempty(neumann) ) for j = 1 : size(neumann,1) b(neumann(j,:)) = b(neumann(j,:)) + ... norm(coordinates(neumann(j,1),:) - coordinates(neumann(j,2),:)) * ... g(sum(coordinates(neumann(j,:),:))/2)/2; end end % % Determine which nodes are associated with Dirichlet conditions. % Assign the corresponding entries of U, and adjust the right hand side. % u = sparse ( size(coordinates,1), 1 ); BoundNodes = unique ( dirichlet ); u(BoundNodes) = u_d ( coordinates(BoundNodes,:) ); b = b - A * u; % % Compute the solution by solving A * U = B for the remaining unknown values of U. % FreeNodes = setdiff ( 1:size(coordinates,1), BoundNodes ); u(FreeNodes) = A(FreeNodes,FreeNodes) \ b(FreeNodes); % % Graphic representation. % show ( elements3, elements4, coordinates, full ( u ) ); return end

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  • How can I make a custom layout / change header background color … with Tex, Latex, ConTeXt ?

    - by harobed
    Hi, currently I produce dynamically this document http://download.stephane-klein.info/exemple_document.png with Python Report Labs… to produce pdf documents. Now, I would like try to produce this document with Tex / Latex / ConTeXt… I've some questions : how can I make the layout ? how can I make header background color ? how can I define my custom title (with blue box) ? what is the better choice for my project : Latex or ConTeXt ? What package I need to use ? geometry ? fancyhdr ? Have you some example ? some resource ? Yesterday, I've read many many documentation… and I don't found a solution / example for my questions. Thanks for your help, Stephane

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  • Using Graphics2D to overlay text on a BufferedImage and return a BufferedImage

    - by Andrew Bolster
    I have checked similarly named questions, but they don't answer this use case. Basically, I was to overlay some text (text) at a given coordinate (x,y) I have the below function in a package; protected BufferedImage Process2(BufferedImage image){ Graphics2D gO = image.createGraphics(); gO.setColor(Color.red); gO.setFont(new Font( "SansSerif", Font.BOLD, 12 )); gO.drawString(this.text, this.x, this.y); System.err.println(this.text+this.x+this.y); return image; } I feel like im missing something patently obvious; every reference to Graphics2D I can find is dealing with either games or writing directly to a file but I just want a BufferedImage returned. with the overlay 'rendered' In the current code, the image appears out the end unchanged. Thanks!

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  • current location from CoreLocation

    - by Christian
    I have an App which launches the google Map App. The code is: UIApplication *app = [UIApplication sharedApplication]; [app openURL:[[NSURL alloc] initWithString: @"http://maps.google.com/maps?daddr=Obere+Laube,+Konstanz,+Germany&saddr="]]; The saddr= should be the current location. I get the current location with -(void)locationManager:(CLLocationManager *)manager didUpdateToLocation:(CLLocation *)newLocation fromLocation:(CLLocation *)oldLocation { NSLog(@"%f,%f", [newLocation coordinate]); The Log displays the correct coordinates like 2010-04-05 15:33:25.436 deBordeaux[60657:207] 37.331689,-122.030731 I didn't find the right way to transmit the coordinates to the url-string. Does someone can give me a hint how-to?

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  • CGContext rotation

    - by kasperjj
    I have a 100x100 pixel image that I want to draw at various angles rotated around the center of the image. The following code works, but rotates around the original origo of the coordinate system (upper left hand corner) and not the translated location. Thus the image is not rotated around itself but around the upper left corner of the screen. CGContextRef context = UIGraphicsGetCurrentContext(); CGContextTranslateCTM(context, -50, -50); CGContextRotateCTM (context, 0.3); CGContextTranslateCTM(context,768/2,1024/2); [image drawAtPoint:CGPointMake(0,0)]; I tried doing the same using CGAffineTransform, but got the same results.

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  • Should I Make These Vectors Classes or Structs in C#

    - by dewald
    I am creating a geometry library in C# and I will need the following immutable types: Vector2f (2 floats - 8 bytes) Vector2d (2 doubles - 16 bytes) Vector3f (3 floats - 12 bytes) Vector3d (3 doubles - 24 bytes) Vector4f (4 floats - 16 bytes) Vector4d (4 doubles - 32 bytes) I am trying to determine whether to make them structs or classes. MSDN suggests only using a struct if the size if going to be no greater than 16 bytes. That reference seems to be from 2005. Is 16 bytes still the max suggested size? I am sure that using structs for the float vectors would be more efficient than using a class, but what should I do about the double vectors? Should I make them structs also to be consistent, or should I make them classes?

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  • OCmock and MKReverseGeocoder

    - by user315374
    Hi, I would like to test a method that uses reverse Geocoding. What i would like to do is : set the geocoder as a property of my controller create the geocoder in the init method call the geocoder in the method i want to test replace the geocoder with a mock in my test The problem is that the MKReverseGeocoder coordinate property is read only, i can only set it in the constructor method : [[MKReverseGeocoder alloc] initWithCoordinate:coord] And of course the coordinates are only available in the method i want to test.. Does anyone knows how i could mock the MKReverseGeocoder class ? Thanks in advance, Vincent.

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  • google maps, cellid to location

    - by Dels
    According to this sample: http://www.codeproject.com/KB/mobile/DeepCast.aspx It's possible to request a gps coordinate (longitude & latitude) including range when sending cellid information (MCC, MNC, towerid, etc) Can someone tell me the actual parameter to request/post to this address? http://www.google.com/glm/mmap It could be something like this http://www.google.com/glm/mmap?mcc=xxx&mnc=xxx&towerid=xxx And i would like to know what response we would get. I have observe OpenCellid website and they provide some nice API to begin with, but i want to know about that in google map too (since they have more completed database). OpenCellID API

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  • Retrieving FBO data in GLSL

    - by Tom Savage
    I'm trying to get MRT working in OpenGL to try out deferred rendering. Here's the situation as I understand it. Create 3 render buffers (for example). Two RGBA8 and one Depth32. Create an FBO. Attach render buffers to FBO. ColorAttachment0/1 for color buffers, DepthAttachment for depth buffer. Bind the FBO. Draw geometry. Send data to different attachments using gl_FragData[] in the frag shader. At this point I would want to take the data in another pass using GLSL, how can a) retrieve data from the framebuffer color attachments, b) get data from the depth component.

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  • Stuffed Animal In OpenGL

    - by anon
    I have seen metal/plastic/water/fire/... shaders for OpenGL. However, it it possible to render something fur-like, say a stuffed animal / teddy bear in OpenGL (I know this is possible with renderman / ray tracers, but I want to do it in OpenGl). If you have pointers to GLSl shaders for this, please point me in the right direction. Thanks! [I'm guessing the answer is no since fur requires more than just shaders -- it almost requires creating geometry on the fly -- but I'd love to be proven wrong)]

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  • Custom Silverlight button with <Path> content and visual states

    - by Klay
    I would like to create a button control that has a Path element as its content--an IconButton if you will. This button should fulfill two conditions: 1. The Path element's stroke and fill colors should be available for manipulation by the VisualStateManager. 2. The Path element's data string (which defines it's shape) can be set in code or in XAML, so that I can create several such buttons without creating a new custom control for each. The only way I can see to do it would involve no XAML whatsoever. That is, setting all the visual states and animations in the code behind, plus generating the Geometry objects point by point (and not being able to use the convenient Data string property on the Path element). Is there a simpler way to do this?

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  • How to draw a full ellipse in a StreamGeometry in WPF?

    - by romkyns
    The only method in a StreamGeometryContext that seems related to ellipses is the ArcTo method. Unfortunately it is heavily geared to joining lines rather than drawing ellipses. In particular, the position of the arc is determined by a starting and ending point. For a full ellipse the two coincide obviously, and the exact orientation becomes undefined. So far the best way of drawing an ellipse centered on 100,100 of size 10,10 that I found is like this: using (var ctx = geometry.Open()) { ctx.BeginFigure(new Point(100+5, 100), isFilled: true, isClosed: true); ctx.ArcTo( new Point(100 + 5*Math.Cos(0.01), 100 + 5*Math.Sin(0.01)), // need a small angle but large enough that the ellipse is positioned accurately new Size(10/2, 10/2), // docs say it should be 10,10 but in practice it appears that this should be half the desired width/height... 0, true, SweepDirection.Counterclockwise, true, true); } Which is pretty ugly, and also leaves a small "flat" area (although not visible at normal zoom levels). How else might I draw a full ellipse using StreamGeometryContext?

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  • Algorithm to generate radial gradient

    - by user146780
    I have this algorithm here: pc = # the point you are coloring now p0 = # start point p1 = # end point v = p1 - p0 d = Length(v) v = Normalize(v) # or Scale(v, 1/d) v0 = pc - p0 t = Dot(v0, v) t = Clamp(t/d, 0, 1) color = (start_color * t) + (end_color * (1 - t)) to generate point to point linear gradients. It works very well for me. I was wondering if there was a similar algorithm to generate radial gradients. By similar, I mean one that solves for color at point P rather than solve for P at a certain color (where P is the coordinate you are painting). Thanks

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  • Interpolation of scattered data: What could I do?

    - by Simon
    Hi! I need your help. I'm working on a 3D chart in Java using Java 3D. It should be able to display a bunch of measured values. As measured, the data I get is scattered. This means I will have to interpolate the missing points in order to get my surface plotted nicely. I didn't study all that 3D-Geometry stuff yet and I don't know where to start. My idea is to triangulate the points to a surface and then, based on the triangulation, interpolate the missing points. (see this to have a rough idea of what I want to achieve) Does someone have experiences with the interpolation of scattered data? Is my approach the right one? If yes, what kind of data structures and algorithms will I need in order to triangulate my points cloud?

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  • Huge dataset point in polygon in .net (collision detection)

    - by Rickard Liljeberg
    I have a pretty big mesh with polygons, usually triangles but sometimes rectangles. Each point in my mesh has a value (value has nothing to do with coordinates). Now I am creating a second mesh in the same coordinate-space as the old mesh. I now want to interpolate out values for all points (vertices) in the new mesh using the values from the old mesh. Now I could loop each polygon in the new mesh and detect which old vertices are in each polygon by making 2d collision detection (altho even this I don't get to function properly so if anyone has simple and fast code for 2d collision detection (triangle is enough) I would gladly see it). However to my main point again. looping each old vertice for each new polygon seems less than efficient. is there a better way?

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