Search Results

Search found 1237 results on 50 pages for 'sam jarman'.

Page 43/50 | < Previous Page | 39 40 41 42 43 44 45 46 47 48 49 50  | Next Page >

  • Open Source Licenses, which one?

    - by sam
    recently I created a java class " Custom Layout Manager ", which I want to make it open-source and distribute it. So it's not really a "product", nor a "complete program". Here's the list of permissions and specifications: You are free to use and modify with some limitations (packages and classes names, should remain the same, if you want another name, extend this class. - The .jar file, project name is ok to change). You don't need to share your modifications. You can't modify and then sell it to others. You can use it as part of your commercial software (For example: It's OK if: you created an instant messaging program, that uses my "Layout", since your "core bussiness" isn't the "Layout", but the msg program. It's NOT OK if: you created another "Layout" by extending it, added some features and sell it.) You can't remove the author's name nor the author's website address. You are free to donate. :D Basically, it's free and it's Ok as you give me credits and don't make money with it. I guess it might be a little bit complex, since you use it "commercially" but cannot sell it separately. I have seeked almost all the licenses, and the closest one was MIT license, but it says that you can sell it, so I don't really want to use this one. Is there any license that fits all these permissions I stated? Thanks.

    Read the article

  • jQuery: How do I insert an html string an arbitrary number of times (i.e. not with an each() function)?

    - by Sam Bivins
    I just need to take a certain html query object and append it to an html element a lot of times. I have this: var box = $("<div class='box'>&nbsp</div>"); $("#firstbox").after(box); and it works fine, but it just adds one 'box' after the #firstbox element. I'd like to do something like this: var box = $("<div class='box'>&nbsp</div>"); $("#firstbox").after(box * 6000); so that it will insert 6000 copies of that 'box' html, but this is not working. This is I'm sure the easiest thing to do, but I can't seem to find how to multiply actions like this without using the each() function, which doesn't apply here because I don't have 6000 of anything on my page. Thanks.

    Read the article

  • Rails: attribute_changed?

    - by Sam
    I have a model that has an amount and I'm tracking to see if this amount is changed with a Model.amount_changed? with a before_save which works fine but when I check to see amount_was and amount_change? it only returns the updated amount not the previous amount. And all this is happening before it is save. It knows when the attribute is changed but it will not return the old value. Ideas?

    Read the article

  • Rails: update_attribut wihout validation - like object.save(false)

    - by Sam
    I trying to update a model on a callback but the validation is causing some havic and I'm controller the material getting saved so I'm looking for way to do update attributes without a validation and I would like to keep it on the update method not on validations for example :conditions = Something like this? easy_address.update_attributes(some_attributes)(false)

    Read the article

  • rails restful select_tag with :on_change

    - by Sam
    So I'm finally starting to use rest in rails. I want to have a select_tag with product categories and when one of the categories is selected I want it to update the products on change. I did this before with <% form_for :category, :url => { :action => "show" } do |f| %> <%= select_tag :id, options_from_collection_for_select(Category.find(:all), :id, :name), { :onchange => "this.form.submit();"} %> <% end %> however now it doesn't work because it tries to do the show action. I have two controllers 1) products 2) product_categories products belongs_to product_categories with a has_many How should I do this. Since the products are listed on the products controller and index action should I use the products controller or should I use the product_categories controller to find the category such as in the show action and then render the product/index page. But the real problem I have is how to get this form or any other option to work with restful routes.

    Read the article

  • Looking for another regex explanation

    - by Sam
    In my regex expression, I was trying to match a password between 8 and 16 character, with at least 2 of each of the following: lowercase letters, capital letters, and digits. In my expression I have: ^((?=.*\d)(?=.*[a-z])(?=.*[A-Z])(?=.*\d)(?=.*[a-z])(?=.*[A-Z]).{8,16})$ But I don't understand why it wouldn't work like this: ^((?=\d)(?=[a-z])(?=[A-Z])(?=\d)(?=[a-z])(?=[A-Z]){8,16})$ Doesnt ".*" just meant "zero or more of any character"? So why would I need that if I'm just checking for specific conditions? And why did I need the period before the curly braces defining the limit of the password? And one more thing, I don't understand what it means to "not consume any of the string" in reference to "?=".

    Read the article

  • Adding User License Agreement in Solaris package

    - by Adil
    I have asked similar question for Linux RPM (http://stackoverflow.com/questions/2132828/adding-license-agreement-in-rpm-package). Now i have same query for Solaris package. I could not get any helpful link / details if it is possible. But I have found a package which does exactly the same thing but how it has been implemented, its not mentioned. $pkgadd -d . SUNWsamfsr SUNWsamfsu Processing package instance from Sun SAM and Sun SAM-QFS software Solaris 10 (root)(i386) 4.6.5,REV=5.10.2007.03.12 Sun SAMFS - Storage & Archiving Management File System Copyright (c) 2007 Sun Microsystems, Inc. All Rights Reserved. ----------------------------------------------------- In order to install SUNWsamfsr, you must accept the terms of the Sun License Agreement. Enter "y" if you do, "n" if you don't, or "v" to view agreement. y -The administrator commands will be executable by root only (group bin). If this is the desired value, enter "y". If you want to change the specified value enter "c". y ... ... Any ideas how to implement such thing for Solaris package?

    Read the article

  • Fast way to get a list of group members in Active Directory with C#

    - by Jeremy
    In a web app, we're looking to display a list of sam accounts for users that are a member of a certain group. Groups could have 500 or more members in many cases and we need the page to be responsive. With a group of about 500 members it takes 7-8 seconds to get a list of sam accounts for all members of the group. Are there faster ways? I know the Active Directory Management Console does it in under a second. I've tried a few methods: 1) PrincipalContext pcRoot = new PrincipalContext(ContextType.Domain) GroupPrincipal grp = GroupPrincipal.FindByIdentity(pcRoot, "MyGroup"); List<string> lst = grp.Members.Select(g => g.SamAccountName).ToList(); 2) PrincipalContext pcRoot = new PrincipalContext(ContextType.Domain) GroupPrincipal grp = GroupPrincipal.FindByIdentity(pcRoot, "MyGroup"); PrincipalSearchResult<Principal> lstMembers = grp.GetMembers(true); List<string> lst = new List<string>(); foreach (Principal member in lstMembers ) { if (member.StructuralObjectClass.Equals("user")) { lst.Add(member .SamAccountName); } } 3) PrincipalContext pcRoot = new PrincipalContext(ContextType.Domain) GroupPrincipal grp = GroupPrincipal.FindByIdentity(pcRoot, "MyGroup"); System.DirectoryServices.DirectoryEntry de = (System.DirectoryServices.DirectoryEntry)grp.GetUnderlyingObject(); List<string> lst = new List<string>(); foreach (string sDN in de.Properties["member"]) { System.DirectoryServices.DirectoryEntry deMember = new System.DirectoryServices.DirectoryEntry("LDAP://" + sDN); lst.Add(deMember.Properties["samAccountName"].Value.ToString()); }

    Read the article

  • Asp.net Login Status Question: It Aint Working

    - by contactmatt
    I'm starting to use Role Management in my website, and I'm current following along on the tutorial from http://www.asp.net/Learn/Security/tutorial-02-vb.aspx . I'm having a problem with the asp:LoginStatus control. It is not telling me that I am currently logged in after a successful login. This can't be true because after successfully logging in, my LoggedInTemplate is shown. The username and passwords are simply stored in a array. Heres the Login.aspx page code. Protected Sub btnLogin_Click(ByVal sender As Object, ByVal e As System.EventArgs) _ Handles btnLogin.Click ' Three valid username/password pairs: Scott/password, Jisun/password, and Sam/password. Dim users() As String = {"Scott", "Jisun", "Sam"} Dim passwords() As String = {"password", "password", "password"} For i As Integer = 0 To users.Length - 1 Dim validUsername As Boolean = (String.Compare(txtUserName.Text, users(i), True) = 0) Dim validPassword As Boolean = (String.Compare(txtPassword.Text, passwords(i), False) = 0) If validUsername AndAlso validPassword Then FormsAuthentication.RedirectFromLoginPage(txtUserName.Text, chkRemember.Checked) End If Next ' If we reach here, the user's credentials were invalid lblInvalid.Visible = True End Sub Here is the content place holder on the master page specifically designed to hold Login Information. On successfull login, the page is redirected to '/Default.aspx', and the LoggedIn Template below is shown...but the status says Log In. <asp:ContentPlaceHolder Id="LoginContent" runat="server"> <asp:LoginView ID="LoginView1" runat="server"> <LoggedInTemplate> Welcome back, <asp:LoginName ID="LoginName1" runat="server" />. </LoggedInTemplate> <AnonymousTemplate> Hello, stranger. </AnonymousTemplate> </asp:LoginView> <br /> <asp:LoginStatus ID="LoginStatus1" runat="server" LogoutAction="Redirect" LogoutPageUrl="~/Logout.aspx" /> </asp:ContentPlaceHolder> Forms authentication is enabled. I'm not sure what to do about this :o.

    Read the article

  • passing value of index number to different php file.

    - by tooepic
    hi, i am a php beginner and have a question for you please. i have a text file with list of first and last names like this: john,smith sam,lewis david,davidson mike,anderson in my sort.php file, it sorts that name list by first name in ascending order with index number, which will display like this: 1. david,davidson 2. john,smith 3. mike,anderson 4. sam,lewis also, in that sort.php file, there's a form for input type=text where you can type index number and a button to delete that index number entered in that text field: <form action="deletename.php" method="post"> <table> <tr valign="top"> <td>Delete: <input type="text" size="2" name="indexnumber" /> </td> <td> <div align="left"> <input type="submit" name="delete" value="Delete" /> </div> </td> </tr> </table> </form> now the question...is there anything i can do in that form to send the value of that index number i entered in the text field? in other word...if i enter 3, what can i do to that form to send the value "mike,anderson" to deletename.php? thanks in advance.

    Read the article

  • How to build a GridView like DataBound Templated Custom ASP.NET Server Control

    - by Deyan
    I am trying to develop a very simple templated custom server control that resembles GridView. Basically, I want the control to be added in the .aspx page like this: <cc:SimpleGrid ID="SimpleGrid1" runat="server"> <TemplatedColumn>ID: <%# Eval("ID") %></ TemplatedColumn> <TemplatedColumn>Name: <%# Eval("Name") %></ TemplatedColumn> <TemplatedColumn>Age: <%# Eval("Age") %></ TemplatedColumn> </cc:SimpleGrid> and when providing the following datasource: DataTable table = new DataTable(); table.Columns.Add("ID", typeof(int)); table.Columns.Add("Name", typeof(string)); table.Columns.Add("Age", typeof(int)); table.Rows.Add(1, "Bob", 35); table.Rows.Add(2, "Sam", 44); table.Rows.Add(3, "Ann", 26); SimpleGrid1.DataSource = table; SimpleGrid1.DataBind(); the result should be a HTML table like this one. ------------------------------- | ID: 1 | Name: Bob | Age: 35 | ------------------------------- | ID: 2 | Name: Sam | Age: 44 | ------------------------------- | ID: 3 | Name: Ann | Age: 26 | ------------------------------- The main problem is that I cannot define the TemplatedColumn. When I tried to do it like this ... private ITemplate _TemplatedColumn; [PersistenceMode(PersistenceMode.InnerProperty)] [TemplateContainer(typeof(TemplatedColumnItem))] [TemplateInstance(TemplateInstance.Multiple)] public ITemplate TemplatedColumn { get { return _TemplatedColumn; } set { _TemplatedColumn = value; } } .. and subsequently instantiate the template in the CreateChildControls I got the following result which is not what I want: ----------- | Age: 35 | ----------- | Age: 44 | ----------- | Age: 26 | ----------- I know that what I want to achieve is pointless and that I can use DataGrid to achieve it, but I am giving this very simple example because if I know how to do this I would be able to develop the control that I need. Thank you.

    Read the article

  • how to join tables sql server

    - by Rick
    Im having some trouble with joining two tables. This is what my two tables look like: Table 1 Customer_ID CustomerName Add. 1000 John Smith 1001 Mike Coles 1002 Sam Carter Table 2 Sensor_ID Location Temp CustIDFK 1000 NY 70 1002 NY 70 1000 ... ... 1001 1001 1002 Desired: Sensor_ID Location Temp CustIDFK 1000 NY 70 John Smith 1002 NY 70 Sam Carter 1000 ... ... John Smith 1001 Mike Coles 1001 1002 I have made Customer_ID from table 1 my primary key, created custIDFK in table 2 and set that as my foreign key. I am really new to sql server so I am still having trouble with the whole relationship piece of it. My goal is to match one customer_ID with one Sensor_ID. The problem is that the table 2 does not have "unique IDs" since they repeat so I cant set that to my foreign key. I know I will have to do either an inner join or outer join, I just dont know how to link the sensor id with customer one. I was thinking of giving my sensor_ID a unique ID but the data that is being inserted into table 2 is coming from another program. Any suggestions?

    Read the article

  • Encrypting XML Element

    - by Kanta
    I have created XML file called users.xml Looks like this: <Users> <user> <uin>"0012345"</uin> <name>black</name> <email>"[email protected]"</email> <created>"3/02/2010"</created> </user> <user> <uin>"123456780"</uin> <name>sam</name> <email>"[email protected]"</email> <created>"3/02/2010"</created> </user> <user> <uin>"123456799"</uin> <name>kblack</name> <email>"[email protected]"</email> <created>"3/02/2010"</created> </user> </Users> I want to encrypt the element. Using code like XmlElement uinelement = (XmlElement)xmldoc.SelectSingleNode("Users/user/uin"); ...encrypts only first UIN from the user.xml file. How can I Encrypt all UIN elements? Thank you Kanta

    Read the article

  • How do I strip multiple (optional) parts of a SQL string using .NET Regular Expressions?

    - by Luc
    I've been working on this for a few hours now and can't find any help on it. Basically, I'm trying to strip a SQL string into various parts (fields, from, where, having, groupBy, orderBy). I refuse to believe that I'm the first person to ever try to do this, so I'd like to ask for some advise from the StackOverflow community. :) To understand what I need, assume the following SQL string: select * from table1 inner join table2 on table1.id = table2.id where field1 = 'sam' having table1.field3 > 0 group by table1.field4 order by table1.field5 I created a regular expression to group the parts accordingly: select\s+(?<fields>.+)\s+from\s+(?<from>.+)\s+where\s+(?<where>.+)\s+having\s+(?<having>.+)\s+group\sby\s+(?<groupby>.+)\s+order\sby\s+(?<orderby>.+) This gives me the following results: fields => * from => table1 inner join table2 on table1.id = table2.id where => field1 = 'sam' having => table1.field3 > 0 groupby => table1.field4 orderby => table1.field5 The problem that I'm faced with is that if any part of the SQL string is missing after the 'from' clause, the regular expression doesn't match. To fix that, I've tried putting each optional part in it's own (...)? group but that doesn't work. It simply put all the optional parts (where, having, groupBy, and orderBy) into the 'from' group. Any ideas?

    Read the article

  • WP7 - listbox Binding

    - by Jeff V
    I have an ObservableCollection that I want to bind to my listbox... lbRosterList.ItemsSource = App.ViewModel.rosterItemsCollection; However, in that collection I have another collection within it: [DataMember] public ObservableCollection<PersonDetail> ContactInfo { get { return _ContactInfo; } set { if (value != _ContactInfo) { _ContactInfo = value; NotifyPropertyChanged("ContactInfo"); } } } PersonDetail contains 2 properties: name and e-mail I would like the listbox to have those values for each item in rosterItemsCollection RosterId = 0; RosterName = "test"; ContactInfo.name = "Art"; ContactInfo.email = "[email protected]"; RosterId = 0; RosterName = "test" ContactInfo.name = "bob"; ContactInfo.email = "[email protected]"; RosterId = 1; RosterName = "test1" ContactInfo.name = "chris"; ContactInfo.email = "[email protected]"; RosterId = 1; RosterName = "test1" ContactInfo.name = "Sam"; ContactInfo.email = "[email protected]"; I would like that listboxes to display the ContactInfo information. I hope this makes sense... My XAML that I've tried with little success: <listbox x:Name="lbRosterList" ItemsSource="rosterItemCollection"> <textblock x:name="itemText" text="{Binding Path=name}"/> What am I doing incorrectly?

    Read the article

  • Apache server immediately shuts down

    - by winarm
    I just installed MySql 5.1.49, Apache 2.2.16 and PHP 5.3.3 on my Vista Home Basic. I followed the instructions in the "Sam's Teach Yourself", adding: LoadModule php5_module C:/php/php5apache2_2.dll PHPIniDir "C:/php/" and AddType application/x-httpd-php .php .html I changed the Listening port to 8080 and the domain is localhost. When I start the server it pops open the window for less than a second and then closes. What am I missing? Thanks.

    Read the article

  • How do I teach my linux command line manners?

    - by Sam152
    Whenever I complete something in the command line while using Ubuntu and my computer does something of value to me, I enjoy saying thank you, just because it's the polite thing to do. A typical conversation might look something like this: mtp-sendfile HamishAndyPodcast.mp3 /Music/podcasts Sending file... Progress: 17769768 of 17769768 (100%) New file ID: 76098 sam@sams-laptop:~$ thanks thanks: command not found What's the best way to teach my PC a few manners and respond with something like "No problemo".

    Read the article

  • How can I preserve share paths when moving a share to a new server?

    - by realitnzsam
    Hi guys, I have 2 servers and I just moved most of the shares from server1 (SBS 2003 server) to server2 (Server 2003 Standard). However, in sharepoint there are a lot of links that refer to the old server by name, ie, \\server1\accounts. How can I have the shares physically on the new (larger) server, while preserving these links and having them still work. Cheers, Sam

    Read the article

  • How do I teach my command line manners?

    - by Sam152
    Whenever I complete something in the command line while using Ubuntu and my computer does something of value to me, I enjoy saying thank you, just because it's the polite thing to do. A typical conversation might look something like this: mtp-sendfile HamishAndyPodcast.mp3 /Music/podcasts Sending file... Progress: 17769768 of 17769768 (100%) New file ID: 76098 sam@sams-laptop:~$ thanks thanks: command not found What's the best way to teach my PC a few manners and respond with something like "No problemo".

    Read the article

  • How do I update the BIOS on my motherboard. Asus P8Z77-V LX

    - by neilh
    I recently built this new PC but I notice most games are not running as well as I had hopped, Tribes, Skyrim, Saints Row the Third and Serious Sam 3 for example. Some have really bad FPS like 60-30, dipping frequently. I notice my Motherboard has a lot of updates, I'm hoping this will help. CPU: Intel Core i5 3570K 3.4GHz | GPU: Radeon HD 6950 | Mobo: Asus P8Z77-V LX | RAM: Corsair 8GB (2x4GB) DDR3 1600MHz

    Read the article

  • DIY Coffee Table Arcade Hides Retro Gaming Inside

    - by Jason Fitzpatrick
    Last week we showed you a nifty man-cave arcade-in-coffee-table build that was a bit, shall we say, exposed. If you’re looking for a sleek build that conceals its arcade-heart until it’s game time, this clean and concealed build is for you. Courtesy of IKEAHacker reader Sam Wang, the beauty of this build is that other than the rectangle of black glass in the center of the table–which could just as well be a design accent–there is no indication that the coffee table is a gaming machine when not in use. Slide out the drawers and boot it up, however, and you’re in business–full MAME arcade emulation at your finger tips. Hit up the link below to check out his full photo build guide. My DIY Arcade Machine Coffee Table [via IKEAHacker] How To Switch Webmail Providers Without Losing All Your Email How To Force Windows Applications to Use a Specific CPU HTG Explains: Is UPnP a Security Risk?

    Read the article

  • 3d transformation of game world keeping gameplay 2d - COCOS2D 2.0

    - by samfisher
    Using: COCOS2D + iOS. I want to rotate the game world, may be loading another .tmx file for another dimensions when user want to switch dimension. the effect what I am looking for is something like this:CLICK HERE What I have thought of till now: rotating CCCamera will be mandatory. Question: How will I have the other part of the level in place while the camera rotates/rotating? I can load a CCSprite and rotate it accordingly to the 3rd dimension. phew..!! Question: When the camera and world is rotated, will the player controls work properly.. I think not...? I think a better option would be to checkout with COCOS3D... there I could implement 3d world... right?? Question: Not sure how well 2d dynamics will work there as I want to user Box2d as physics engine.. could anyone provide suggestions? Regards, Sam

    Read the article

  • How do the environments of a standard Terminal command-line and a bash script differ?

    - by fred.bear
    I know there is something different about the environment of the Terminal command-line and the environment in a bash script, but I don't know what that difference is... Here is the example which finally led me to ask this quesiton; it may flush out some of the differences. I am trying to strip leading '0's from a number, with this command. var="000123"; var="${var##+(0)}" ; echo $var When I run this command from the Terminal's command-line, I get: 123 However, when I run it from within a script, it doesn't work; I get: 000123 I'm using Ubuntu 10.04, and tried all the following with the sam results: GNOME Terminal 2.30.2 Konsole 2.4.5 #!/bin/bash #!/bin/sh What is causing this difference? Even if some upgrade will make it work in scripts... I am trying to find out the what and why, so in future, I'll know what to look out for .

    Read the article

< Previous Page | 39 40 41 42 43 44 45 46 47 48 49 50  | Next Page >