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  • Python Loop for mysql statement

    - by user552974
    Hi, I have a project that i need to compile number of cities in each state and make an insert statement for mysql database. I think the easiest way to do it is via python but since i m a complete noob i would like to reach out all the python gurus here. Here is what the input looks like. Example below is for Florida. cities = ['Boca Raton', 'Boynton Beach', 'Bradenton', 'Cape Coral', 'Deltona'] and this what the output should be. INSERT INTO `oc_locations` (`idLocation`, `name`, `idLocationParent`, `friendlyName`) VALUES (1, 'Florida', 0, 'Florida'), (2, 'Boca Raton', 1, 'Boca Raton'), (3, 'Boynton Beach', 1, 'Boynton Beach'), (4, 'Bradenton', 1, 'Bradenton'), (5, 'Cape Coral', 1, 'Cape Coral'), (6, 'Deltona', 1, 'Deltona'), If you look at carefully the "idLocationParent" for "Florida" value is "0" so which means it is a top level value. This will be done for 50 states so ability to plug the state name into the mysql statement would be icing on the cake if there is a easy way to do it. Also alphabetical order and auto increment for the idLocation would be great. Here is an example of what i m trying to achieve concatenation is the part i need to figure out. for city in cities: print (1, 'city', 0, 'city'), city

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  • Retreiving multiple rows from a loop-created form... Stuck.

    - by hangston
    Hi All, Let me start by saying that I'm new to PHP, but I'm here to learn and would really appreciate your help. I use the following code to pull in data and create a form. This creates up to 40 lines for a user to fill out. Each line consists of the same information: Description, Amount, and Frequency. The remainder of the information needed is generated by the database. (See hidden fields) <?php $row = 0; do { $optid = $row_options['option_id']; echo "<tr>\n\t<td>" . htmlentities($row_options['option']) . "</td>\n"; echo "\t<td>" . "<input name='description' type='text' size='40' maxlength='120'/>" . "</td>\n"; echo "\t<td>" . "<input name='option_id' type='hidden' value='$optid' />$<input name='amount' type='text' size='10' maxlength='7'/>" . "</td>\n"; echo "\t<td>" . "<select name='assisted_frequency'> <option value='Monthly'>Monthly</option> <option value='Weekly'>Weekly</option> <option value='Daily'>Daily</option> <option value='Hourly'>Hourly</option> <option value='One-Time'>One-Time</option> </select>" . "</td>\n</tr>\n"; $array[$row] = array( $arraydesc[$row] = $_POST['description'], $arrayamto[$row] = $_POST['amount'], $arrayoptid[$row] = $optid, $arrayfreq[$row] = $_POST['frequency'], ); $row ++; } while ($row_options = mysql_fetch_assoc($options)); $counter = $row - 1; ?> I'm having troubles retrieving the information that the user inputs. My intent is to loop through each row after the user has input their information, then upload the mix of my database information and the user's information into another database. For example, the user would see, albeit prettier: form1 Option 1: description [input box] amount [input box] frequency [option box] Option 2: description [input box] amount [input box] frequency [option box] Option 3: description [input box] amount [input box] frequency [option box] Option 4: description [input box] amount [input box] frequency [option box] submit Upon submitting the form above, I'm using a query similar to the following to input the data into the database: for($row=0; $row<=$counter; $row++){ $insertSQL2 = sprintf("INSERT INTO table (option_id, amount, description, frequency) VALUES (%s, %s, %s, %s)", GetSQLValueString($arrayoptid[$row], "int"), GetSQLValueString($arrayamto[$row], "int"), GetSQLValueString($arraydesc[$row], "text"), GetSQLValueString($arrayfreq[$row], "text")); // code to submit query } I've tried for, foreach, arrays (what feels like the everything I know) to post each row (row by row) into the database. I either get just the last row of data, or no data at all. I also worry that the [$row] technique is adding characters to my data. What is the best way to retrieve each row of the user's inputs, then upload this data (row by row) into the database? Also, I would really appreciate your suggestions for improving my coding technique and the approach I'm taking. Thank you, Hangston

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  • How to get selected category id after 1st page in pagination?

    - by Surjay
    //$id=$_REQUEST['category']; //$catid=mysql_escape_string($id); $catid = isset($_GET['category']) ? (int)$_GET['category'] : 0; $recordsPerPage =4; 0 // //default startup page $pageNum = 1; if(isset($_GET['p'])) { $pageNum = $_GET['p']; settype($pageNum, 'integer'); } $offset = ($pageNum - 1) * $recordsPerPage; //set the number of columns $columns = 1; //set the number of columns $columns = 1; $query = "SELECT temp_id, temp_img, temp_header, temp_resize, temp_small, temp_name, temp_type, cat_id, col_id, artist_id FROM templates where cat_id = '{$catid}' ORDER BY temp_id DESC LIMIT $offset, $recordsPerPage"; $result = mysql_query($query); //we add this line because we need to know the number of rows $num_rows = mysql_num_rows($result); echo ""; //changed this to a for loop so we can use the number of rows for($i = 0; $i < $num_rows; $i++) { while($row = mysql_fetch_array($result)){ if($i % $columns == 0) { //if there is no remainder, we want to start a new row echo ""; } echo ...........my data(s). if(($i % $columns) == ($columns - 1) || ($i + 1) == $num_rows) { echo ""; } } } echo ""; //} ? <div class="pagination"> <? $query = "SELECT COUNT( temp_id ) AS `temp_date` FROM `templates` where cat_id ='{$catid}'"; $result = mysql_query($query) or die('Mysql Err. 2'); $row = mysql_fetch_assoc($result); $numrows = $row['temp_date']; //$numrows = mysql_num_rows($result); $self = $_SERVER['PHP_SELF']; $maxPage = ceil($numrows/$recordsPerPage); $nav = ''; for($page = 1; $page <= $maxPage; $page++) { if ($page == $pageNum) { $nav .= "$page"; } else { $nav .= "$page"; } } if ($pageNum 1) { $page = $pageNum - 1; $prev = ""; $first = ""; } else { $prev = ' '; $first = ' '; } if ($pageNum < $maxPage) { $page = $pageNum + 1; $next = " "; $last = " "; } else { $next = ' '; $last = ' '; } echo " $first $prev $nav $next $last "; ? Here my ajax code: function GetXmlHttpObject(handler) { var objXMLHttp=null if (window.XMLHttpRequest) { objXMLHttp=new XMLHttpRequest() } else if (window.ActiveXObject) { objXMLHttp=new ActiveXObject("Microsoft.XMLHTTP") } return objXMLHttp } function stateChanged() { if (xmlHttp.readyState==4 || xmlHttp.readyState=="complete") { document.getElementById("txtResult").innerHTML=xmlHttp.responseText } else { //alert(xmlHttp.status); } } function htmlData(url, qStr) { if (url.length==0) { document.getElementById("txtResult").innerHTML=""; return; } xmlHttp=GetXmlHttpObject() if (xmlHttp==null) { alert ("Browser does not support HTTP Request"); return; } url=url+"?"+qStr; url=url+"&sid="+Math.random(); xmlHttp.onreadystatechange=stateChanged; xmlHttp.open("GET",url,true) ; xmlHttp.send(null); }

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  • Loop results executing twice

    - by ozzysmith
    I creating a simple site with PHP where the users can submit blogs and other users (who are logged in) can post comments on them. I have made a link called "comments" below each blog that when clicked will show / hide all the comments relevant to the specific blog (also if the user is logged in, it will show a form field in which they can submit new comments). So basically each blog will have multiple comments. I have done two different codes for this but they both have the same problem that each comment appears twice (everything else works fine). Could anyone point out why? mysql_select_db ("ooze"); $result = mysql_query ("select * from blog") or die(mysql_error()); $i = 1; while($row = mysql_fetch_array($result)) { echo "<h1>$row[title]</h1>"; echo "<p class ='second'>$row[blog_content]</p> "; echo "<p class='meta'>Posted by .... &nbsp;&bull;&nbsp; $row[date] &nbsp;&bull;&nbsp; <a href='#' onclick=\"toggle_visibility('something$i'); return false\">Comments</a><div id='something$i' style='display: none;'>"; $i++; $a = $row["ID"]; $result2 = mysql_query ("select * from blog, blogcomment where $a=blogID") or die(mysql_error()); while($sub = mysql_fetch_array($result2)) { echo "<p class='third' >$sub[commentdate] &nbsp;&bull;&nbsp; $sub[username]</p><p>said:</p> <p>$sub[comment]</p>"; } if ( isset ($_SESSION["gatekeeper"])) { echo '<form method="post" name="result_'.$row["ID"].'" action="postcomment.php"><input name="ID" type = "hidden" value = "'.$row["ID"].'" /><input name="comment" id="comment" type="text" style="margin-left:20px;"/><input type="submit" value="Add comment" /></form>'; } else { echo '<p class="third"><a href="register.html">Signup </a>to post a comment</p>'; } echo "</div>"; } mysql_close($conn); //second version of inner loop:// if ( isset ($_SESSION["gatekeeper"])) { while($sub = mysql_fetch_array($result2)) { echo "<p class='third' >$sub[commentdate] &nbsp;&bull;&nbsp; $sub[username] said:</p> <p>$sub[comment]</p>"; } echo '<form method="post" name="result_'.$row["ID"].'" action="postcomment.php"><input name="ID" type = "hidden" value = "'.$row["ID"].'" /><input name="comment" id="comment" type="text" style="margin-left:20px;"/><input type="submit" value="Add comment" /></form>'; } else { while($sub = mysql_fetch_array($result2)) { echo "<p class='third' >$sub[commentdate] &nbsp;&bull;&nbsp; $sub[username] said:</p> <p>$sub[comment]</p>"; } echo '<p class="third"><a href="register.html">Signup </a>to post a comment</p>'; } echo "</div>"; } mysql_close($conn);

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  • Retrieving multiple rows from a loop-created form... Stuck.

    - by hangston
    Let me start by saying that I'm new to PHP, but I'm here to learn and would really appreciate your help. I use the following code to pull in data and create a form. This creates up to 40 lines for a user to fill out. Each line consists of the same information: Description, Amount, and Frequency. The remainder of the information needed is generated by the database. (See hidden fields) <?php $row = 0; do { $optid = $row_options['option_id']; echo "<tr>\n\t<td>" . htmlentities($row_options['option']) . "</td>\n"; echo "\t<td>" . "<input name='description' type='text' size='40' maxlength='120'/>" . "</td>\n"; echo "\t<td>" . "<input name='option_id' type='hidden' value='$optid' />$<input name='amount' type='text' size='10' maxlength='7'/>" . "</td>\n"; echo "\t<td>" . "<select name='assisted_frequency'> <option value='Monthly'>Monthly</option> <option value='Weekly'>Weekly</option> <option value='Daily'>Daily</option> <option value='Hourly'>Hourly</option> <option value='One-Time'>One-Time</option> </select>" . "</td>\n</tr>\n"; $array[$row] = array( $arraydesc[$row] = $_POST['description'], $arrayamto[$row] = $_POST['amount'], $arrayoptid[$row] = $optid, $arrayfreq[$row] = $_POST['frequency'], ); $row ++; } while ($row_options = mysql_fetch_assoc($options)); $counter = $row - 1; ?> I'm having troubles retrieving the information that the user inputs. My intent is to loop through each row after the user has input their information, then upload the mix of my database information and the user's information into another database. For example, the user would see, albeit prettier: form1 Option 1: description [input box] amount [input box] frequency [option box] Option 2: description [input box] amount [input box] frequency [option box] Option 3: description [input box] amount [input box] frequency [option box] Option 4: description [input box] amount [input box] frequency [option box] submit Upon submitting the form above, I'm using a query similar to the following to input the data into the database: for($row=0; $row<=$counter; $row++){ $insertSQL2 = sprintf("INSERT INTO table (option_id, amount, description, frequency) VALUES (%s, %s, %s, %s)", GetSQLValueString($arrayoptid[$row], "int"), GetSQLValueString($arrayamto[$row], "int"), GetSQLValueString($arraydesc[$row], "text"), GetSQLValueString($arrayfreq[$row], "text")); // code to submit query } I've tried for, foreach, arrays (what feels like the everything I know) to post each row (row by row) into the database. I either get just the last row of data, or no data at all. I also worry that the [$row] technique is adding characters to my data. What is the best way to retrieve each row of the user's inputs, then upload this data (row by row) into the database? Also, I would really appreciate your suggestions for improving my coding technique and the approach I'm taking.

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  • How can I remove this query from within a loop?

    - by Chris
    I am currently designing a forum as a personal project. One of the recurring issues I've come across is database queries in loops. I've managed to avoid doing that so far by using table joins or caching of data in arrays for later use. Right now though I've come across a situation where I'm not sure how I can write the code in such a way that I can use either of those methods easily. However I'd still prefer to do at most 2 queries for this operation rather than 1 + 1 per group of forums, which so far has resulted in 5 per page. So while 5 isn't a huge number (though it will increase for each forum group I add) it's the principle that's important to me here, I do NOT want to write queries in loops What I'm doing is displaying forum index groupings (eg admin forums, user forums etc) and then each forum within that group on a single page index, it's the combination of both in one page that's causing me issue. If it had just been a single group per page, I'd use a table join and problem solved. But if I use a table join here, although I can potentially get all the data I need it'll be in one mass of results and it needs displaying properly. Here's the code (I've removed some of the html for clarity) <?php $sql= "select * from forum_groups"; //query 1 $result1 = $database->query($sql); while($group = mysql_fetch_assoc($result1)) //first loop {?> <table class="threads"> <tr> <td class="forumgroupheader"> <?php echo $group['group_name']; ?> </td> </tr> <tr> <td class="forumgroupheader2"> <?php echo $group['group_desc']; ?> </td> </tr> </table> <table> <tr> <th class="thforum"> Forum Name</th> <th class="thforum"> Forum Decsription</th> <th class="thforum"> Last Post </th> <tr> <?php $group_id = $group['id']; $sql = "SELECT forums.id, forums.forum_group_id, forums.forum_name, forums.forum_desc, forums.visible_rank, forums.locked, forums.lock_rank, forums.topics, forums.posts, forums.last_post, forums.last_post_id, users.username FROM forums LEFT JOIN users on forums.last_post_id=users.id WHERE forum_group_id='{$group_id}'"; //query 2 $result2 = $database->query($sql); while($forum = mysql_fetch_assoc($result2)) //second loop {?> So how can I either a) write the SQL in such a way as to remove the second query from inside the loop or b) combine the results in an array either way I need to be able to access the data as an when so I can format it properly for the page output, ie within the loops still.

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  • inserts 'Array' into mysql table

    - by Noah Smith
    i want to insert an array into a mysql table. The array is produced by script scanning all the links, converting into absolute links and then displaying them in an array. i decided to mysql_query the array into the table but now i am stuck. it only posts 'Array', instead of every row from the array into a different row. Any ideas??! <?php require_once('simplehtmldom_1_5/simple_html_dom.php'); require_once('url_to_absolute/url_to_absolute.php'); $connect = mysql_connect("xxxx", "xxxx", "xxx") or die('Couldn\'t connect to MySQL Server: ' . mysql_error()); mysql_select_db("xxxx", $connect ) or die('Couldn\'t Select the database: ' . mysql_error( $connect )); $links = Array(); $URL = 'http://www.theqlick.com'; // change it for urls to grab // grabs the urls from URL $file = file_get_html($URL); foreach ($file->find('a') as $theelement) { $links[] = url_to_absolute($URL, $theelement->href); } print_r($links); mysql_query("INSERT INTO pages (url) VALUES ('$links[]')"); mysql_close($connect);

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  • How do I simplify this php script

    - by user225269
    Any suggestions on how I can simplify the php script below?This was my previous question: http://stackoverflow.com/questions/2712237/how-to-check-if-a-checkbox-radio-button-is-checked-in-php that is linked to this one, What I'm trying to do here is to output the data depending on the checkbox that is checked. But my code isn't really good, it shows 2 tables if the condition is met by the 2 results. As you can see in the code below, any suggestions on how I can simplify this? <?php $con = mysql_connect("localhost","root","nitoryolai123$%^"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("school", $con); $id = mysql_real_escape_string($_POST['idnum']); if ( $_POST['yr'] == 'year' and $_POST['sec'] == 'section' ){ $result2 = mysql_query("SELECT * FROM student WHERE IDNO='$id'"); echo "<table border='1'> <tr> <th>IDNO</th> <th>YEAR</th> <th>SECTION</th> </tr>"; while($row = mysql_fetch_array($result2)) { echo "<tr>"; echo "<td>" . $row['IDNO'] . "</td>"; echo "<td>" . $row['YEAR'] . "</td>"; echo "<td>" . $row['SECTION'] . "</td>"; echo "</tr>"; } echo "</table>"; } if ( $_POST['yr'] == 'year' and $_POST['sec'] == 'section' and $_POST['lname'] == 'lastname'){ $result3 = mysql_query("SELECT * FROM student WHERE IDNO='$id'"); echo "<table border='1'> <tr> <th>IDNO</th> <th>YEAR</th> <th>SECTION</th> <th>LASTNAME</th> </tr>"; while($row = mysql_fetch_array($result3)) { echo "<tr>"; echo "<td>" . $row['IDNO'] . "</td>"; echo "<td>" . $row['YEAR'] . "</td>"; echo "<td>" . $row['SECTION'] . "</td>"; echo "<td>" . $row['LASTNAME'] . "</td>"; echo "</tr>"; } echo "</table>"; } mysql_close($con); ?>

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  • html-encode output && incorrect string error

    - by fusion
    my data includes arabic characters which looks like garbage in mysql but displays correctly when run on browser. my questions: how do i html-encode the output? if i add this to all my files: <meta http-equiv="Content-Type" content="text/html; charset=utf-8"> i get this error: Error: Incorrect string value: '\xE4\xEE\xC3\xD8\xEF\xE6...' for column 'cQuotes' at row 1 i'm working on php/mysql platform. insertion form in html: <!doctype html> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8"> <title>Your Favorite Quotes</title> <link rel="stylesheet" type="text/css" href="style.css" /> <link rel="stylesheet" href="css/validationEngine.jquery.css" type="text/css" media="screen" charset="utf-8" /> <script type="text/javascript" src="scripts/jquery-1.4.2.js"></script> <script src="scripts/jquery.validationEngine-en.js" type="text/javascript"></script> <script src="scripts/jquery.validationEngine.js" type="text/javascript"></script> <script type="text/javascript"> $(document).ready(function() { $("#submitForm").validationEngine() }) </script> </head> <body> <div class="container"> <div class="center_div"> <h2>Submit Your Quote</h2> <fieldset> <form id="submitForm" action="qinsert.php" method="post"> <div class="field"> <label>Author: </label> <input id="author" name="author" type="text" class="validate[required,custom[onlyLetter],length[0,100]]"> </div><br /> <div class="field"> <label>Quote: </label> <textarea id="quote" name="quote" class="validate[required, length[0,1000]]"></textarea> <br /> </div> <input id="button1" type="submit" value="Submit" class="submit" /><br /> <input id="button2" type="reset" value="Reset" /> </form> </fieldset> </div> </div> </body> </html> ////////////////////// query in php: //<?php //header('Content-Type: text/html; charset=UTF-8'); //?> <!doctype html> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8"> <link rel="stylesheet" type="text/css" href="style2.css" /> <title>Your Quote Databank</title> </head> <body> <?php include 'config.php'; echo "Connected <br />"; //check for quotes and apostrophes $author = ''; $quote = ''; $author = $_POST['author']; $quote = $_POST['quote']; $author = mysql_real_escape_string(trim($author)); $quote = mysql_real_escape_string(trim($quote)); //************************** //validating data $query = "SELECT * FROM Quotes where cQuotes = '$quote' limit 1;"; $result = mysql_query($query, $conn); //now check that the number of rows is 0 if (mysql_num_rows($result) > 0 ) { header("Location: /error.html"); exit; } //inserting data //mysql_query("SET NAMES 'utf8'"); //mysql_query("SET CHARACTER SET utf8"); $sql="INSERT INTO Quotes (vauthor, cquotes) VALUES ('$author', '$quote')"; if (!mysql_query($sql,$conn)) { die('Error: ' . mysql_error()); } echo "<div class='container'><p><label class='lbl_record'> Record Added Successfully!</label>"; echo "<a href='qform.html'> Submit a New Quote!</a></p>"; //************************** //selecting data $result = mysql_query("SELECT * FROM Quotes ORDER BY idQuotes DESC"); echo "<div class='center_div'>"; echo "<table> <thead> <tr> <th>Author</th> <th>Quotes</th> </tr> </thead>"; while($row = mysql_fetch_array($result)) { echo "<tbody><tr>"; echo "<td width='150px'>" . $row['vAuthor'] . "</td>"; echo "<td>" . $row['cQuotes'] . "</td>"; echo "</tr>"; } echo "</tbody></table>"; echo "</div></div>"; //************************** include 'close_config.php'; ?> </body> </html>

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  • Session is working in Localhost Properly but not Online (Cpanel)

    - by nando pandi
    Hello guys Sorry for my stupid question regarding to my yesterday question its not solved yet even the advice you have given but still not working. i have removed all of spaces but still showing the problem for me. it's working perfect in localhost but not in CPANEL. Here is the errors which give: Warning: session_start() [function.session-start]: Cannot send session cookie - headers already sent by (output started at /home/scalepro/public_html/Admin Panel/Remote Employee/main.php:1) in /home/scalepro/public_html/Admin Panel/Remote Employee/main.php on line 1 Warning: session_start() [function.session-start]: Cannot send session cache limiter - headers already sent (output started at /home/scalepro/public_html/Admin Panel/Remote Employee/main.php:1) in /home/scalepro/public_html/Admin Panel/Remote Employee/main.php on line 1 Warning: Cannot modify header information - headers already sent by (output started at /home/scalepro/public_html/Admin Panel/Remote Employee/main.php:1) in /home/scalepro/public_html/Admin Panel/Remote Employee/main.php on line 13 Warning: Unknown: Your script possibly relies on a session side-effect which existed until PHP 4.2.3. Please be advised that the session extension does not consider global variables as a source of data, unless register_globals is enabled. You can disable this functionality and this warning by setting session.bug_compat_42 or session.bug_compat_warn to off, respectively in Unknown on line 0 ANY ONE PLEASE ??? Here is my code: <?php session_start(); require_once('../../Admin Panel/db.php'); if(isset($_POST['email']) && !empty($_POST['email']) && isset($_POST['password']) && !empty($_POST['password'])) { $email = $_POST['email']; $password = $_POST['password']; $query="SELECT RemoteEmployeeFullName, RemoteEmployeeEmail, RemoteEmployeePassword FROM remoteemployees WHERE RemoteEmployeeEmail='".$email."' AND RemoteEmployeePassword='".$password."'"; $queryrun=$connection->query($query); if($queryrun->num_rows > 0) { $_SESSION['email']=$RemoteEmployeeFullName; header("Location: /home/scalepro/public_html/Admin Panel/Remote Employee/REPLists.php"); } else { echo 'Email: <b>'.$email. '</b> or Password <b>'. $password.'</b> Is Not Typed Correctly Try Again Please!.'; header( "refresh:5;url= /home/scalepro/public_html/spd/myaccount.php" ); } } else { header( "refresh:5;url= /home/scalepro/public_html/spd/myaccount.php" ); } ?> if the condition gets true this will be redirected to a page by the name of REPLists.php here is the page. <?php session_start(); require_once('../../Admin Panel/db.php'); ?> <html> <head> <style> .wrapper { width:1250px; height:auto; border:solid 1px #000; margin:0 auto; padding:5px; border-radius:5px; -webkit-border-radius:5px; -moz-border-radius:5px; -ms-border-radius:5px; } .wrapper .header { width:1250px; height:20px; border-bottom:solid 1px #f0eeee; margin:auto 0; margin-bottom:12px; } .wrapper .header div { text-decoration:none; color:#F60; } .wrapper .header div a { text-decoration:none; color:#F60; } .wrapper .Labelcon { width:1250px; height:29px; border-bottom:solid 1px #ccc; } .wrapper .Labelcon .Label { width:125px; height:20px; float:left; text-align:center; border-left:1px solid #f0eeee; font:Verdana, Geneva, sans-serif; font-size:14.3px; font-weight:bold; } .wrapper .Valuecon { width:1250px; height:29px; border-bottom:solid 1px #ccc; color:#F60; text-decoration:none; } .wrapper .Valuecon .Value { width:125px; height:20px; float:left; text-align:center; border-left:1px solid #f0eeee; font-size:14px; } </style> </head> <body> <div class="wrapper"> <div class="header"> <div style="float:left;"><font color="#000000">Email: </font> <?php if(isset($_SESSION['email'])) { echo $_SESSION['email']; } ?> </div> <div style="float:right;"> <a href="#">My Profile</a> | <a href="logout.php">Logout</a></div> </div> <div class="Labelcon"> <div class="Label">Property ID</div> <div class="Label">Property Type</div> <div class="Label">Property Deal Type</div> <div class="Label">Property Owner</div> <div class="Label">Proposted Price</div> </div> <?php if(!isset($_SESSION['email'])) { header('Location:../../spd/myaccount.php'); } else { $query = "SELECT properties.PropertyID, properties.PropertyType, properties.PropertyDealType, properties.Status, properties.PropostedPrice, remoteemployees.RemoteEmployeeFullName, propertyowners.PropertyOwnerName, propertydealers.PropertyDealerName FROM remoteemployees, propertyowners, propertydealers, properties WHERE properties.PropertyOwnerID=propertyowners.PropertyOwnerID AND properties.PropertyDealerID=propertydealers.PropertyDealerID AND remoteemployees.RemoteEmployeeID=properties.RemoteEmployeeID ORDER BY properties.PropertyID "; $query_run = $connection->query($query); if( $connection->error ) exit( $connection->error ); while($row=$query_run->fetch_assoc()) { ?> <div class="Valuecon"> <div class="Value"><?php echo $row['PropertyID'] ?></div> <div class="Value"><?php echo $row['PropertyType'] ?></div> <div class="Value"><?php echo $row['PropertyDealType']?></div> <div class="Value"><?php echo $row['PropertyOwnerName'] ?></div> <div class="Value"><?php echo $row['PropostedPrice'];?></div> </div> <?php } }?> </div> </body> </html>

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  • How to convert this query to a "django model query" ?

    - by fabriciols
    Hello ! What i want is simple : models : class userLastTrophy(models.Model): user = models.ForeignKey(userInfo) platinum = models.IntegerField() gold = models.IntegerField() silver = models.IntegerField() bronze = models.IntegerField() level = models.IntegerField() rank = models.IntegerField() perc_level = models.IntegerField() date_update = models.DateTimeField(default=datetime.now, blank=True) total = models.IntegerField() points = models.IntegerField() class userTrophy(models.Model): user = models.ForeignKey(userInfo) platinum = models.IntegerField() gold = models.IntegerField() silver = models.IntegerField() bronze = models.IntegerField() total = models.IntegerField() level = models.IntegerField() perc_level = models.IntegerField() date_update = models.DateTimeField(default=datetime.now, blank=True) rank = models.IntegerField(default=0) total = models.IntegerField(default=0) points = models.IntegerField(default=0) last_trophy = models.ForeignKey(userLastTrophy, default=0) I have this query : select t2.user_id as id, t2.platinum - t1.platinum as plat, t2.gold - t1.gold as gold, t2.silver - t1.silver as silver, t2.bronze - t1.bronze as bronze, t2.points - t1.points as points from myps3t_usertrophy t2, myps3t_userlasttrophy t1 where t1.id = t2.last_trophy_id order by points; how to do this with django models ?

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  • Counting and joining two tables

    - by Eikern
    Eventhosts – containing the three regular hosts and an "other" field (if someone is replacing them) eventid | host (SET[Steve,Tim,Brian,other]) ------------------------------------------- 1 | Steve 2 | Tim 3 | Brian 4 | other 5 | other Event id | other | name etc. ---------------------- 1 | | … 2 | | … 3 | | … 4 | Billy | … 5 | Irwin | … This query: SELECT h.host, COUNT(*) AS hostcount FROM host AS h LEFT OUTER JOIN event AS e ON h.eventid = e.id GROUP BY h.host Returns Steve | 1 Tim | 1 Brian | 1 other | 2 I want it to return Steve | 1 Tim | 1 Brian | 1 Billy | 1 Irwin | 1 OR Steve | | 1 Tim | | 1 Brian | | 1 other | Billy | 1 other | Irwin | 1 Can someone tell me how I can achieve this or point me in a direction?

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  • Show number of results in each "filter item"

    - by Roberto
    Hi ! How can i get the number of each filter item in a seach? Example... im doing a job/resumes portal... i seach a job title and i have some filters items like City, State , area and etc... How can i show the number of each filter in the select box example Contry: Brazil(22 results), USA(61 results) Here a url with a sample: http://www.manager.com.br/resumes/resumes_result.php?&search_table=resumes&tipo_local=0&keyword=program& Tkz Roberto

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  • Zend_Table_Db and Zend_Paginator and Zend_Paginator_Adapter_DbSelect

    - by Uffo
    I have the following query: $this->select() ->where("`name` LIKE ?",'%'.mysql_escape_string($name).'%') Now I have the Zend_Paginator code: $paginator = new Zend_Paginator( // $d is an instance of Zend_Db_Select new Zend_Paginator_Adapter_DbSelect($d) ); $paginator->getAdapter()->setRowCount(200); $paginator->setItemCountPerPage(15) ->setPageRange(10) ->setCurrentPageNumber($pag); $this->view->data = $paginator; As you see I'm passing the data to the view using $this->view->data = $paginator Before I didn't had $paginator->getAdapter()->setRowCount(200);I could determinate If I have any data or not, what I mean with data, if the query has some results, so If the query has some results I show the to the user, if not, I need to show them a message(No results!) But in this moment I don't know how can I determinate this, since count($paginator) doesn't work anymore because of $paginator->getAdapter()->setRowCount(200);and I'm using this because it taks about 7 sec for Zend_Paginator to count the page numbers. So how can I find If my query has any results?

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  • How do I show a user's credit based on their session

    - by Jamie
    Hi all - I'm developing a simple LAMP app where users can credit their account using Paypal. I suspect this is a simple issue, but have spent quite a while experimenting to no avail and would appreciate any thoughts: System has a user management system working fine using sessions, but I can't get it to display the current user's credit. But I've been trying things along the lines of: $result = mysql_query(" SELECT * FROM users INNER JOIN account ON account.UserID=account.UserID ORDER BY account.accountID"); while($_SESSION['Username'] = $row['Username'] ) { echo $row['Username']; echo $row['Credit']; } I suspect the while statement is invalid, but I want it to echo username and credit where the current session username = the username stored in the database. Thanks so much for taking a look - very much appreciated.

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  • Query results taking too long on 200K database, speed up tips?

    - by colorfulgrayscale
    I have a sql statement where I'm joining about 4 tables, each with 200K rows. The query runs, but keeps freezing. When I do a join on 3 tables instead, it returns the rows (takes about 10secs). Any suggestion why? suggestions to speed up? Thanks! Code SELECT * FROM equipment, tiremap, workreference, tirework WHERE equipment.tiremap = tiremap.`TireID` AND tiremap.`WorkMap` = workreference.`aMap` AND workreference.`bMap` = tirework.workmap LIMIT 5 p.s and if it helps any, I'm using sql alchemy to generate this code, the sqlalchemy code for this is query = session.query(equipment, tiremap, workreference, tirework) query = query.filter(equipment.c.tiremap == tiremap.c.TireID) query = query.filter(tiremap.c.WorkMap==workreference.c.aMap) query = query.filter(workreference.c.bMap == tirework.c.workmap) query = query.limit(5) query.all()

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  • DataMapper is only returning the last part of this query

    - by Josh K
    So I'm using the following: $r = new Record(); $r->select('ip, count(*) as ipcount'); $r->group_by('ip'); $r->order_by('ipcount', 'desc'); $r->limit(5); $r->get(); foreach($r->all as $record) { echo($record->ip." "); echo($record->ipcount." <br />"); } And I only get the last (fifth) record echo'ed out and no ipcount echoed. Is there a different way to go around this? I'm working on learning DataMapper (hence the questions) and need to figure some of this out. I haven't quite wrapped my head around the whole ORM thing.

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  • recursive function to get all the child categories

    - by user253530
    Here is what I'm trying to do: - i need a function that when passed as an argument an ID (for a category of things) will provide all the subcategories and the sub-sub categories and sub-sub-sub..etc. - i was thinking to use a recursive function since i don't know the number of subcategories their sub-subcategories and so on so here is what i've tried to do so far function categoryChild($id) { $s = "SELECT * FROM PLD_CATEGORY WHERE PARENT_ID = $id"; $r = mysql_query($s); if(mysql_num_rows($r) > 0) { while($row = mysql_fetch_array($r)) echo $row['ID'].",".categoryChild($row['ID']); } else { $row = mysql_fetch_array($r); return $row['ID']; } } If i use return instead of echo, i won't get the same result. I need some help in order to fix this or rewrite it from scratch

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  • Sql simple query

    - by Josemalive
    Hello, I have the following table Persons_Companies that shows a relation between persons and companies knowns by these persons: PersonID | CompanyID 1 1 2 1 2 2 3 2 4 2 Imaging that company 1="Google" and company 2 is ="Microsoft", i would like to know the query to have the following result: PersonID | Microsoft | Google 1 0 1 2 1 1 3 1 0 4 1 0 Until this moment i have something similar: select PersonID, case when CompanyID=1 then 1 else 0 end as Google, case when EmpresaID=2 then 1 else 0 end as Microsoft from Persons_Companies My problem is with the persons that knows both companies, i cant imagine how could this query be. Could you give me a hand? Thanks in advance. Best Regards. Josema.

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  • executing perl code stored in a database?

    - by TheGNUGuy
    Hey everyone, Is it possible to save some perl code in a database then retrieve it using a select statement and then execute that perl code? I have tried using the eval() function but that doesn't seem to work. Here is what I'm trying right now and it doesn't seem to work: my $temp = $qryResults[0]; print $temp."\n"; eval{"$temp"}; the output is $con->Disconnect();exit; Thanks for the help!

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  • excel import query error

    - by pmms
    mysql_connect("localhost","root",""); mysql_select_db("hitnrunf_db"); $result=mysql_query("select * from jos_users INTO OUTFILE 'users.csv' FIELDS ESCAPED BY '""' TERMINATED BY ',' ENCLOSED BY '"' LINES TERMINATED BY '\n' "); header("Content-type: text/plain"); header("Content-Disposition: attachment; filename=your_desired_name.xls"); header("Content-Transfer-Encoding: binary"); header("Pragma: no-cache"); header("Expires: 0"); print "$header\n$data"; in the above code in query string i.e string in side mysql_quey we are getting following error Parse error: syntax error, unexpected T_CONSTANT_ENCAPSED_STRING in C:\wamp\www\samples\mysql_excel\exel_outfile.php on line 8 in query string '\n' charter is not identifying as string thats why above error getting

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  • Move million records from MEMORY table to MYISAM table.

    - by Prashant
    Hi, I am looking for a fast way to move records from a MEMORY table to MYISAM table. MEMORY table has around 0.5 million records. Both tables have exactly the same structure (same number of columns, data types etc.). But the MYISAM table is indexed (B-TREE) on a few columns. There are around 25 columns most of which are unsigned integers. I have already tried using "INSERT INTO SELECT * FROM " query. But is there any faster way to do this? Appreciate your help. Prashant

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  • Join Query returns empty result, unexpected result

    - by Abs
    Hello all, Can anyone explain why this query returns an empty result. SELECT * FROM (`bookmarks`) JOIN `tags` ON `tags`.`bookmark_id` = `bookmarks`.`id` WHERE `tag` = 'clean' AND `tag` = 'simple' In my bookmarks table, I have a bookmark with an id of 70 and in my tags table i have two tags 'clean' and 'simple' both that have the column bookmark_id as 70. I would of thought a result would have been returned? How can I remedy this so that I have the bookmark returned when it has a tag of 'clean' and 'simple'? Thanks all for any explanation and solution to this.

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  • One table, need multiple values from different rows/tuples

    - by WmasterJ
    I have tables like: 'profile_values' userID | fid | value -------+---------+------- 1 | 3 | [email protected] 1 | 45 | 203-234-2345 3 | 3 | [email protected] 1 | 45 | 123-456-7890 And: 'users' userID | name -------+------- 1 | joe 2 | jane 3 | jake I want to join them and have one row with two of the values like: 'profile_values' userID | name | email | phone -------+-------+----------------+-------------- 1 | joe | [email protected] | 203-234-2345 2 | jane | [email protected] | 123-456-7890 I have solved it but it feels clumsy and I want to know if there is a better way to do it. Meaning solutions that are either more readable or faster(optimized) or simply best-practice. Current solution: multiple tables selected, many conditional statements: SELECT u.userID AS memberid, u.name AS first_name, pv1.value AS fname, pv2.value as lname FROM users AS u, profile_values AS pv1, profile_values AS pv2, WHERE u.userID = pv1.userID AND pv1.fid = 3 AND u.userID = pv2.userID AND pv2.fid = 45; Thanks for the help!

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  • Does a version control database storage engine exist?

    - by Zak
    I was just wondering if a storage engine type existed that allowed you to do version control on row level contents. For instance, if I have a simple table with ID, name, value, and ID is the PK, I could see that row 354 started as (354, "zak", "test")v1 then was updated to be (354, "zak", "this is version 2 of the value")v2 , and could see a change history on the row with something like select history (value) where ID = 354. It's kind of an esoteric thing, but it would beat having to keep writing these separate history tables and functions every time a change is made...

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