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  • Grouping a query with php

    - by Tom Hoad
    Basic question! I have 2 tables FRUIT id | fruit_name ------------------- 1 | Apple 2 | Banana 3 | Carrot VARIETIES id | fk_fruit_id | variety_name --------------------------------------- 1 1 Cox 2 1 Braeburn 3 2 Chester 4 3 Kotaka 5 3 Imperial 6 3 Oneal I'd like to output a list of varieties per fruit e.g. APPLE - Cox, Braeburn BANANA - Chester CARROT - Kotaka, Imperial, Oneal My current code is $query = "SELECT * FROM produce, varieties WHERE produce.id = varieties.fk_fruit_id"; $result = mysql_query($query) or die('Error : ' . mysql_error()); while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) { $produce_fruit_code = $row['fruit_code']; $variety_name = $row['variety_name']; echo $produce_fruit_code.' - '.$variety_name.'<br/>'; } which outputs: Apple - Cox Apple - Braeburn Banana - Chester Carrot - Kotaka Carrot - Imperial Carrot - Oneal Not a million miles away, but still not there. Any help is much appreciated, thanks!

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  • PHP submit problem

    - by TaG
    I'm trying to check if the username is available and display it for the user to see when they check there account settings, which I have done. BUT when the user tries to fill out another field I get the Your username is unavailable! which should not pop up because its the users username already. I want to know how can I fix this problem using PHP so that the users name is displayed every time the user views their account settings and it wont cause problems when a user submits additional info? Here is the PHP code. if (isset($_POST['submitted'])) { require_once '../htmlpurifier/library/HTMLPurifier.auto.php'; $config = HTMLPurifier_Config::createDefault(); $config->set('Core.Encoding', 'UTF-8'); $config->set('HTML.Doctype', 'XHTML 1.0 Strict'); $config->set('HTML.TidyLevel', 'heavy'); $config->set('HTML.SafeObject', true); $config->set('HTML.SafeEmbed', true); $purifier = new HTMLPurifier($config); $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT users.* FROM users WHERE user_id=3"); $first_name = mysqli_real_escape_string($mysqli, $purifier->purify(htmlentities(strip_tags($_POST['first_name'])))); $username = mysqli_real_escape_string($mysqli, $purifier->purify(htmlentities(strip_tags($_POST['username'])))); if($_POST['username']) { $u = "SELECT user_id FROM users WHERE username = '$username'"; $r = mysqli_query ($mysqli, $u) or trigger_error("Query: $q\n<br />MySQL Error: " . mysqli_error($mysqli)); if (mysqli_num_rows($r) == TRUE) { $username = NULL; echo '<p class="error">Your username is unavailable!</p>'; } else if(mysqli_num_rows($r) == 0) { $username = mysqli_real_escape_string($mysqli, $purifier->purify(htmlentities(strip_tags($_POST['username'])))); if ($_POST['password1'] == $_POST['password2']) { $sha512 = hash('sha512', $_POST['password1']); $password = mysqli_real_escape_string($mysqli, $purifier->purify(strip_tags($sha512))); } else { $password = NULL; } if($password == NULL) { echo '<p class="error">Your password did not match the confirmed password!</p>'; } else { if (mysqli_num_rows($dbc) == 0) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"INSERT INTO users (user_id, first_name, username, password) VALUES ('$user_id', '$first_name', '$username', '$password')"); } if ($dbc == TRUE) { $dbc = mysqli_query($mysqli,"UPDATE users SET first_name = '$first_name', username = '$username', password = '$password' WHERE user_id = '$user_id'"); echo '<p class="changes-saved">Your changes have been saved!</p>'; } if (!$dbc) { print mysqli_error($mysqli); return; } } } } } Here is the html form. <form method="post" action="index.php"> <fieldset> <ul> <li><label for="first_name">First Name: </label><input type="text" name="first_name" id="first_name" size="25" class="input-size" value="<?php if (isset($_POST['first_name'])) { echo stripslashes(htmlentities(strip_tags($_POST['first_name']))); } else if(!empty($first_name)) { echo stripslashes(htmlentities(strip_tags($first_name))); } ?>" /></li> <li><label for="username">UserName: </label><input type="text" name="username" id="username" size="25" class="input-size" value="<?php if (isset($_POST['username'])) { echo stripslashes(htmlentities(strip_tags($_POST['username']))); } else if(!empty($username)) { echo stripslashes(htmlentities(strip_tags($username))); } ?>" /><br /><span>(ex: CSSKing, butterball)</span></li> <li><label for="password1">Password: </label><input type="password" name="password1" id="password1" size="25" class="input-size" value="<?php if (isset($_POST['password1'])) { echo stripslashes(htmlentities(strip_tags($_POST['password1']))); } ?>" /></li> <li><label for="password2">Confirm Password: </label><input type="password" name="password2" id="password2" size="25" class="input-size" value="<?php if (isset($_POST['password2'])) { echo stripslashes(htmlentities(strip_tags($_POST['password2']))); } ?>" /></li> <li><input type="submit" name="submit" value="Save Changes" class="save-button" /> <input type="hidden" name="submitted" value="true" /> <input type="submit" name="submit" value="Preview Changes" class="preview-changes-button" /></li> </ul> </fieldset> </form>

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  • PDO prepared statement not working for login system

    - by Cortopasta
    Anybody no what I'm doing wrong here? I have a username and password hashed in my database, but i can't seem to get it to match the one I submit through the script. $res = $dbcon->prepare('SELECT id FROM users WHERE name = :name AND password = MD5(:password)'); $res->bindParam(':name', $user); $res->bindParam(':password', $password); $res->execute(); $row = $res->fetch(); for ($i=0; $i<7; $i++) { $row[$i]; }

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  • SQL where clause to work with Group by clause after performing a count()

    - by Matt
    Tried my usual references at w3schools and google. No luck I'm trying to produce the following results. QTY is a derived column | Position | QTY -------------------- 1 Clerk 2 2 Mgr 2 Here's what I'm not having luck with: SELECT Position, Count(position) AS 'QTY' FROM tblemployee Where ('QTY' != 1) GROUP BY Position I know that my Position is set up as varchar(255) Count produces a integer data and my where clasue is accurate so that leads me to believe that that Count() is jamming me up. Please throw up an example so I can reference later. Thanks for the help!

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  • Cast integer to real

    - by Dave Jarvis
    Question How do you cast an INTEGER value as a REAL value? Attempts CAST( Y.YEAR AS REAL), but that failed (the documentation indicates you cannot CAST or CONVERT values to REALs. Y.YEAR + 0.0, but that failed, too. Error Message Using udf_slope fails due to: Can't initialize function 'slope'; slope() requires a real as parameter 2 Code SELECT D.AMOUNT, Y.YEAR, slope(D.AMOUNT, Y.YEAR + 0.0) as SLOPE, intercept(D.AMOUNT, Y.YEAR + 0.0) as INTERCEPT FROM YEAR_REF Y, DAILY D Here, D.AMOUNT is a FLOAT and Y.YEAR is an INTEGER. Thank you!

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  • Fetch posts with attachments in a certain category?

    - by TiuTalk
    I need to retreive a list of posts that have (at least) one attachment that belongs to a category in WordPress. The relation between attachments and categories I made by myself using the WordPress default method. Here's the query that i'm running right now: SELECT p.* FROM `wp_posts` AS p # The post INNER JOIN `wp_posts` AS a # The attachment ON p.`ID` = a.`post_parent` AND a.`post_type` = 'attachment' INNER JOIN `wp_term_relationships` AS ra ON a.`ID` = ra.`object_id` AND ra.`term_taxonomy_id` IN (3) # The category ID list WHERE p.`post_type` = 'post' ORDER BY p.`post_date` DESC LIMIT 15 The problem here is that the query only use the first found attachment, and if it doesn't belongs to the category, the result isn't returned.

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  • Is there any way to simplify a verbose SQL INSERT INTO(..) query?

    - by Soundar Rajan
    I have a table with one id (autonumber) field and 50 other fields. The table is normalized, these are 50 material properties etc. I want to copy a record from this table into the same table - only the autoincrement id will be different. The query I am using now is INSERT INTO tableName (field1,field2,....field50) SELECT field1,field2,....field50 from tableName WHERE autoid=1234; Note that I have to type in ALL the 50 field names, twice! Is there any way to shorten this query so I don't have to type all of them? Thanks.

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  • SQL Server Date Comparison Functions

    - by HighAltitudeCoder
    A few months ago, I found myself working with a repetitive cursor that looped until the data had been manipulated enough times that it was finally correct.  The cursor was heavily dependent upon dates, every time requiring the earlier of two (or several) dates in one stored procedure, while requiring the later of two dates in another stored procedure. In short what I needed was a function that would allow me to perform the following evaluation: WHERE MAX(Date1, Date2) < @SomeDate The problem is, the MAX() function in SQL Server does not perform this functionality.  So, I set out to put these functions together.  They are titled: EarlierOf() and LaterOf(). /**********************************************************                               EarlierOf.sql   **********************************************************/ /**********************************************************   Return the later of two DATETIME variables.   Parameter 1: DATETIME1 Parameter 2: DATETIME2   Works for a variety of DATETIME or NULL values. Even though comparisons with NULL are actually indeterminate, we know conceptually that NULL is not earlier or later than any other date provided.   SYNTAX: SELECT dbo.EarlierOf('1/1/2000','12/1/2009') SELECT dbo.EarlierOf('2009-12-01 00:00:00.000','2009-12-01 00:00:00.521') SELECT dbo.EarlierOf('11/15/2000',NULL) SELECT dbo.EarlierOf(NULL,'1/15/2004') SELECT dbo.EarlierOf(NULL,NULL)   **********************************************************/ USE AdventureWorks GO   IF EXISTS       (SELECT *       FROM sysobjects       WHERE name = 'EarlierOf'       AND xtype = 'FN'       ) BEGIN             DROP FUNCTION EarlierOf END GO   CREATE FUNCTION EarlierOf (       @Date1                              DATETIME,       @Date2                              DATETIME )   RETURNS DATETIME   AS BEGIN       DECLARE @ReturnDate     DATETIME         IF (@Date1 IS NULL AND @Date2 IS NULL)       BEGIN             SET @ReturnDate = NULL             GOTO EndOfFunction       END         ELSE IF (@Date1 IS NULL AND @Date2 IS NOT NULL)       BEGIN             SET @ReturnDate = @Date2             GOTO EndOfFunction       END         ELSE IF (@Date1 IS NOT NULL AND @Date2 IS NULL)       BEGIN             SET @ReturnDate = @Date1             GOTO EndOfFunction       END         ELSE       BEGIN             SET @ReturnDate = @Date1             IF @Date2 < @Date1                   SET @ReturnDate = @Date2             GOTO EndOfFunction       END         EndOfFunction:       RETURN @ReturnDate   END -- End Function GO   ---- Set Permissions --GRANT SELECT ON EarlierOf TO UserRole1 --GRANT SELECT ON EarlierOf TO UserRole2 --GO                                                                                             The inverse of this function is only slightly different. /**********************************************************                               LaterOf.sql   **********************************************************/ /**********************************************************   Return the later of two DATETIME variables.   Parameter 1: DATETIME1 Parameter 2: DATETIME2   Works for a variety of DATETIME or NULL values. Even though comparisons with NULL are actually indeterminate, we know conceptually that NULL is not earlier or later than any other date provided.   SYNTAX: SELECT dbo.LaterOf('1/1/2000','12/1/2009') SELECT dbo.LaterOf('2009-12-01 00:00:00.000','2009-12-01 00:00:00.521') SELECT dbo.LaterOf('11/15/2000',NULL) SELECT dbo.LaterOf(NULL,'1/15/2004') SELECT dbo.LaterOf(NULL,NULL)   **********************************************************/ USE AdventureWorks GO   IF EXISTS       (SELECT *       FROM sysobjects       WHERE name = 'LaterOf'       AND xtype = 'FN'       ) BEGIN             DROP FUNCTION LaterOf END GO   CREATE FUNCTION LaterOf (       @Date1                              DATETIME,       @Date2                              DATETIME )   RETURNS DATETIME   AS BEGIN       DECLARE @ReturnDate     DATETIME         IF (@Date1 IS NULL AND @Date2 IS NULL)       BEGIN             SET @ReturnDate = NULL             GOTO EndOfFunction       END         ELSE IF (@Date1 IS NULL AND @Date2 IS NOT NULL)       BEGIN             SET @ReturnDate = @Date2             GOTO EndOfFunction       END         ELSE IF (@Date1 IS NOT NULL AND @Date2 IS NULL)       BEGIN             SET @ReturnDate = @Date1             GOTO EndOfFunction       END         ELSE       BEGIN             SET @ReturnDate = @Date1             IF @Date2 > @Date1                   SET @ReturnDate = @Date2             GOTO EndOfFunction       END         EndOfFunction:       RETURN @ReturnDate   END -- End Function GO   ---- Set Permissions --GRANT SELECT ON LaterOf TO UserRole1 --GRANT SELECT ON LaterOf TO UserRole2 --GO                                                                                             The interesting thing about this function is its simplicity and the built-in NULL handling functionality.  Its interesting, because it seems like something should already exist in SQL Server that does this.  From a different vantage point, if you create this functionality and it is easy to use (ideally, intuitively self-explanatory), you have made a successful contribution. Interesting is good.  Self-explanatory, or intuitive is FAR better.  Happy coding! Graeme

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  • Help with query

    - by hdoe123
    Hi, I'm trying make a query that looks at a single table and looks to see if a student is a team called CMHT and in a medic team - if they are I don't want to see the result. I only want see if there only in CMHT or medic not both. Would the right direction be using sub query to filer it out? I've done a search on NOT IN but how could you get to see check if its in more then 2 teams are not? Student Team ref 1 CMHT 1 1 Medic 2 2 Medic 3 this would be in the result 3 CMHT 5 this would be in the result So far I've done the following code would I need use a sub query or do a self join and filter it that way? SELECT Table1.Student, Table1.Team, Table1.refnumber FROM Table1 WHERE (((Table1.Team) In ('Medics','CMHT'))

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  • How would I UPDATE these table entries with SQL and PHP?

    - by CT
    I am working on an Asset Database problem. I enter assets into a database. Every object is an asset and has variables within the asset table. An object is also a type of asset. In this example the type is server. Here is the Query to retrieve all necessary data: SELECT asset.id ,asset.company ,asset.location ,asset.purchaseDate ,asset.purchaseOrder ,asset.value ,asset.type ,asset.notes ,server.manufacturer ,server.model ,server.serialNumber ,server.esc ,server.warranty ,server.user ,server.prevUser ,server.cpu ,server.memory ,server.hardDrive FROM asset LEFT JOIN server ON server.id = asset.id WHERE asset.id = '$id' I then assign all results into single php variables. How would I write a query/script to update an asset?

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  • Syntax error, unexpected T_CONSTANT_ENCAPSED_STRING in PHP

    - by pmms
    mysql_connect("localhost","root",""); mysql_select_db("hitnrunf_db"); $result=mysql_query("select * from jos_users INTO OUTFILE 'users.csv' FIELDS ESCAPED BY '""' TERMINATED BY ',' ENCLOSED BY '"' LINES TERMINATED BY '\n' "); header("Content-type: text/plain"); header("Content-Disposition: attachment; filename=your_desired_name.xls"); header("Content-Transfer-Encoding: binary"); header("Pragma: no-cache"); header("Expires: 0"); print "$header\n$data"; in the above code in query string i.e string in side mysql_quey we are getting following error Parse error: syntax error, unexpected T_CONSTANT_ENCAPSED_STRING in C:\wamp\www\samples\mysql_excel\exel_outfile.php on line 8 in query string '\n' charter is not identifying as string thats why above error getting

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  • Make A HTML/PHP Link

    - by Will Evans
    I have the code below: $result = mysql_query("SELECT link, notes FROM links WHERE username='will';"); $html .= "<ul>"; while ($row = mysql_fetch_array($result)) { //loop extract($row); $html .= "<li>{$link} - {$notes}</li>"; } I need the bit where it says {$link} to become a clickable link which opens a new window. How would I do this? When I put tags around it you get this error: The error is: Parse error: syntax error, unexpected '{' in /data/www/vhosts/themacsplash.com/httpdocs/ClipBoy/will.php on line 18 Line 18 is $html .= "{$link} - {$notes}";

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  • How would I UPDATE these table entries with SQL?

    - by CT
    I am working on an Asset Database problem. I enter assets into a database. Every object is an asset and has variables within the asset table. An object is also a type of asset. In this example the type is server. Here is the Query to retrieve all necessary data: SELECT asset.id ,asset.company ,asset.location ,asset.purchaseDate ,asset.purchaseOrder ,asset.value ,asset.type ,asset.notes ,server.manufacturer ,server.model ,server.serialNumber ,server.esc ,server.warranty ,server.user ,server.prevUser ,server.cpu ,server.memory ,server.hardDrive FROM asset LEFT JOIN server ON server.id = asset.id WHERE asset.id = '$id' How would I write a query to update an asset?

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  • SQL SERVER – Curious Case of Disappearing Rows – ON UPDATE CASCADE and ON DELETE CASCADE – T-SQL Example – Part 2 of 2

    - by pinaldave
    Yesterday I wrote a real world story of how a friend who thought they have an issue with intrusion or virus whereas the issue was really in the code. I strongly suggest you read my earlier blog post Curious Case of Disappearing Rows – ON UPDATE CASCADE and ON DELETE CASCADE – Part 1 of 2 before continuing this blog post as this is second part of the first blog post. Let me reproduce the simple scenario in T-SQL. Building Sample Data USE [TestDB] GO -- Creating Table Products CREATE TABLE [dbo].[Products]( [ProductID] [int] NOT NULL, [ProductDesc] [varchar](50) NOT NULL, CONSTRAINT [PK_Products] PRIMARY KEY CLUSTERED ( [ProductID] ASC )) ON [PRIMARY] GO -- Creating Table ProductDetails CREATE TABLE [dbo].[ProductDetails]( [ProductDetailID] [int] NOT NULL, [ProductID] [int] NOT NULL, [Total] [int] NOT NULL, CONSTRAINT [PK_ProductDetails] PRIMARY KEY CLUSTERED ( [ProductDetailID] ASC )) ON [PRIMARY] GO ALTER TABLE [dbo].[ProductDetails] WITH CHECK ADD CONSTRAINT [FK_ProductDetails_Products] FOREIGN KEY([ProductID]) REFERENCES [dbo].[Products] ([ProductID]) ON UPDATE CASCADE ON DELETE CASCADE GO -- Insert Data into Table USE TestDB GO INSERT INTO Products (ProductID, ProductDesc) SELECT 1, 'Bike' UNION ALL SELECT 2, 'Car' UNION ALL SELECT 3, 'Books' GO INSERT INTO ProductDetails ([ProductDetailID],[ProductID],[Total]) SELECT 1, 1, 200 UNION ALL SELECT 2, 1, 100 UNION ALL SELECT 3, 1, 111 UNION ALL SELECT 4, 2, 200 UNION ALL SELECT 5, 3, 100 UNION ALL SELECT 6, 3, 100 UNION ALL SELECT 7, 3, 200 GO Select Data from Tables -- Selecting Data SELECT * FROM Products SELECT * FROM ProductDetails GO Delete Data from Products Table -- Deleting Data DELETE FROM Products WHERE ProductID = 1 GO Select Data from Tables Again -- Selecting Data SELECT * FROM Products SELECT * FROM ProductDetails GO Clean up Data -- Clean up DROP TABLE ProductDetails DROP TABLE Products GO My friend was confused as there was no delete was firing over ProductsDetails Table still there was a delete happening. The reason was because there is a foreign key created between Products and ProductsDetails Table with the keywords ON DELETE CASCADE. Due to ON DELETE CASCADE whenever is specified when the data from Table A is deleted and if it is referenced in another table using foreign key it will be deleted as well. Workaround 1: Design Changes – 3 Tables Change the design to have more than two tables. Create One Product Mater Table with all the products. It should historically store all the products list in it. No products should be ever removed from it. Add another table called Current Product and it should contain only the table which should be visible in the product catalogue. Another table should be called as ProductHistory table. There should be no use of CASCADE keyword among them. Workaround 2: Design Changes - Column IsVisible You can keep the same two tables. 1) Products and 2) ProductsDetails. Add a column with BIT datatype to it and name it as a IsVisible. Now change your application code to display the catalogue based on this column. There should be no need to delete anything. Workaround 3: Bad Advices (Bad advises begins here) The reason I have said bad advices because these are going to be bad advices for sure. You should make necessary design changes and not use poor workarounds which can damage the system and database integrity further. Here are the examples 1) Do not delete the data – well, this is not a real solution but can give time to implement design changes. 2) Do not have ON CASCADE DELETE – in this case, you will have entry in productsdetails which will have no corresponding product id and later on there will be lots of confusion. 3) Duplicate Data – you can have all the data of the product table move to the product details table and repeat them at each row. Now remove CASCADE code. This will let you delete the product table rows without any issue. There are so many things wrong this suggestion, that I will not even start here. (Bad advises ends here)  Well, did I miss anything? Please help me with your suggestions. Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: PostADay, SQL, SQL Authority, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology

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  • Complex Join - involving date ranges and sum...

    - by calumbrodie
    I have two tables that I need to join... I want to join table1 and table2 on 'id' - however in table two id is not unique. I only want one value returned for table two, and this value represents the sum of a column called 'total_sold' - within a specified date range (say one month).. SELECT ta.id, tb.total_sold as total_sold_this_week FROM table_a as ta LEFT JOIN table_b as tb ON ta.id=tb.id AND tb.date_sold BETWEEN ADDDATE(NOW(),INTERVAL -3 WEEK) AND NOW() this works but does not SUM the rows - only returning one row for each id... how do I get the sum from table b instead of only one row??? Please criticise if format of question could use more work - I can rewrite and provide sample data if required - this is a trivialised version of a much larger problem. -Thanks

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  • please help me in this query

    - by testkhan
    I have three tables (user, friends, posts) and two users (user1 and user2). When user1 adds user2 as friend then user1 can see the posts of user2 just like on Facebook. But only the posts after the date when user1 added user2 as friend. My query is like this: $sql = mysql_query("SELECT * FROM posts p JOIN friends f ON p.currentuserid = f.friendid AND p.time >= f.friend_since OR p.currentuserid='user1id' WHERE f.myid='user1id' ORDER BY p.postid DESC LIMIT 20"); it is working all the way fine but with a little problem.....!! it displays user2, user3 (all the users as friends of user1) posts for single time but shows user1 posts multiple.......i.e user2. hi user1. userssfsfsfsfsdf user1. userssfsfsfsfsdf user3. dddddddd user1. sdfsdsdfsdsfsf user1. sdfsdsdfsdsfsf but i in database it is single entry/post why it is happening........!! How can I fix it?

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  • problem in counting children category

    - by moustafa
    I have this table: fourn_category (id , sub) I am using this code to count: function CountSub($id){ $root = array($id); $query = mysql_query("SELECT id FROM fourn_category WHERE sub = '$id'"); while( $row = mysql_fetch_array( $query, MYSQL_ASSOC ) ){ array_push($root,$row['id']); CountSub($row['id']); } return implode(",",$root); } It returns the category id as 1,2,3,4,5 to using it to count the sub by IN() But the problem is that it counts this: category 1 category 2 category 3 category 4 category 5 Category 1 has 1 child not 4. Why? How can I get all children's trees?

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  • Recursive Function To Create Array

    - by mTuran
    Hi, i use kohana framework and i am trying to code recursive function to create category tree. My Categories Table id int(11) NO PRI NULL auto_increment name varchar(50) NO NULL parent_id int(11) NO NULL projects_count int(11) NO NULL My Example Which Is Not Work public static function category_list($parent_id = 0) { $result = Database::instance()->query(' SELECT name, projects_count FROM project_categories WHERE parent_id = ?', array($parent_id) ); $project_categories = array(); foreach($result as $row) { $project_categories[] = $row; Project_Categories_Model::factory()->category_list($parent_id + 1); } return $project_categories; }

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  • PHP coding a price comparaison tool

    - by Tristan
    Hello, it's the first time I developp such tool you all know (the possibility to compare articles according to price and/or options) Since I never did that i want to tell me what do you think of the way i see that : On the database we would have : offer / price / option 1 / option 2 / option 3 / IDseller / IDoffer best buy / 15$ / full FTP / web hosting / php.ini / 10 / 1 .../..../.... And the request made by the client : "SELECT * FROM offers WHERE price <= 20 AND option1 = fullFTP"; I don't know if it seems OK to you. Plus i was wondering, how to avoid multiples entries for the same seller. Imagine you have multiple offers with a price <= 20 with the option FullFTP for the same seller, i don't want him to be shown 5 times on the comparator. If you have any advices ;) Thanks

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  • how to set a status

    - by ejah85
    hello guys..here i've a problem where i want to set the status whether it is approved or reject.. the condition are if admin select the registration number and driver name, that means the status is approve otherwise, if admin fill up the reason, that means the request is reject.. here is the code to set status if ($reason =='null'){ $query2 = "UPDATE usage SET status ='APPROVED' WHERE '$bookingno'=bookingno"; $result2 = @mysql_query($query2); } elseif (($regno =='null')&&($d_name =='null')) { $query3 = "UPDATE usage SET status ='REJECT' WHERE '$bookingno'=bookingno"; $result3 = @mysql_query($query3); } when i save the data, the status field are not updates..

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  • Matching process , issue with query

    - by Blerta Blerta
    i have this code which helps me match two different tables.. now, each of this tables, has a epos_id and a rbpos_id ! I have another table which has pairs of rbpos_id and epos_id, something like: id | epos_id | rbpos_id 1 a3566 465jd 2 hkiyb rbposi When i join this other table, i need to check this condition, i mean, the matching should be done, only and if, the epos_id and rbpos_id of the join i'm doing, have the same id,i mean, belong to the same row.. Here is my current query... Thanks! SELECT retailer.date, retailer.time, retailer.location, retailer.user_id,imovo.mobile_number ". "FROM retailer LEFT JOIN imovo ". " ON addtime(retailer.time, '0:0:50')>imovo.time AND retailer.time <imovo.time AND retailer.date=imovo.date

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  • Merge overlapping date intervals

    - by leoinfo
    Is there a better way of merging overlapping date intervals? The solution I came up with is so simple that now I wonder if someone else has a better idea of how this could be done. /***** DATA EXAMPLE *****/ DECLARE @T TABLE (d1 DATETIME, d2 DATETIME) INSERT INTO @T (d1, d2) SELECT '2010-01-01','2010-03-31' UNION SELECT '2010-04-01','2010-05-31' UNION SELECT '2010-06-15','2010-06-25' UNION SELECT '2010-06-26','2010-07-10' UNION SELECT '2010-08-01','2010-08-05' UNION SELECT '2010-08-01','2010-08-09' UNION SELECT '2010-08-02','2010-08-07' UNION SELECT '2010-08-08','2010-08-08' UNION SELECT '2010-08-09','2010-08-12' UNION SELECT '2010-07-04','2010-08-16' UNION SELECT '2010-11-01','2010-12-31' UNION SELECT '2010-03-01','2010-06-13' /***** INTERVAL ANALYSIS *****/ WHILE (1=1) BEGIN UPDATE t1 SET t1.d2 = t2.d2 FROM @T AS t1 INNER JOIN @T AS t2 ON DATEADD(day, 1, t1.d2) BETWEEN t2.d1 AND t2.d2 -- AND t1.d2 <= t2.d2 /***** this condition is useless *****/ IF @@ROWCOUNT = 0 BREAK END /***** RESULT *****/ SELECT StartDate = MIN(d1) , EndDate = d2 FROM @T GROUP BY d2 ORDER BY StartDate, EndDate /***** OUTPUT *****/ /***** StartDate EndDate 2010-01-01 2010-06-13 2010-06-15 2010-08-16 2010-11-01 2010-12-31 *****/ EDIT: I realized that the t1.d2 <= t2.d2 condition is not really useful.

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  • php - upload script mkdir saying file already exists when same directory even though different filename

    - by neeko
    my upload script says my file already exists when i try upload even though different filename <?php // Start a session for error reporting session_start(); ?> <?php // Check, if username session is NOT set then this page will jump to login page if (!isset($_SESSION['username'])) { header('Location: index.html'); } // Call our connection file include('config.php'); // Check to see if the type of file uploaded is a valid image type function is_valid_type($file) { // This is an array that holds all the valid image MIME types $valid_types = array("image/jpg", "image/JPG", "image/jpeg", "image/bmp", "image/gif", "image/png"); if (in_array($file['type'], $valid_types)) return 1; return 0; } // Just a short function that prints out the contents of an array in a manner that's easy to read // I used this function during debugging but it serves no purpose at run time for this example function showContents($array) { echo "<pre>"; print_r($array); echo "</pre>"; } // Set some constants // Grab the User ID we sent from our form $user_id = $_SESSION['username']; $category = $_POST['category']; // This variable is the path to the image folder where all the images are going to be stored // Note that there is a trailing forward slash $TARGET_PATH = "img/users/$category/$user_id/"; mkdir($TARGET_PATH, 0755, true); // Get our POSTed variables $fname = $_POST['fname']; $lname = $_POST['lname']; $contact = $_POST['contact']; $price = $_POST['price']; $image = $_FILES['image']; // Build our target path full string. This is where the file will be moved do // i.e. images/picture.jpg $TARGET_PATH .= $image['name']; // Make sure all the fields from the form have inputs if ( $fname == "" || $lname == "" || $image['name'] == "" ) { $_SESSION['error'] = "All fields are required"; header("Location: error.php"); exit; } // Check to make sure that our file is actually an image // You check the file type instead of the extension because the extension can easily be faked if (!is_valid_type($image)) { $_SESSION['error'] = "You must upload a jpeg, gif, or bmp"; header("Location: error.php"); exit; } // Here we check to see if a file with that name already exists // You could get past filename problems by appending a timestamp to the filename and then continuing if (file_exists($TARGET_PATH)) { $_SESSION['error'] = "A file with that name already exists"; header("Location: error.php"); exit; } // Lets attempt to move the file from its temporary directory to its new home if (move_uploaded_file($image['tmp_name'], $TARGET_PATH)) { // NOTE: This is where a lot of people make mistakes. // We are *not* putting the image into the database; we are putting a reference to the file's location on the server $imagename = $image['name']; $sql = "insert into people (price, contact, category, username, fname, lname, expire, filename) values (:price, :contact, :category, :user_id, :fname, :lname, now() + INTERVAL 1 MONTH, :imagename)"; $q = $conn->prepare($sql) or die("failed!"); $q->bindParam(':price', $price, PDO::PARAM_STR); $q->bindParam(':contact', $contact, PDO::PARAM_STR); $q->bindParam(':category', $category, PDO::PARAM_STR); $q->bindParam(':user_id', $user_id, PDO::PARAM_STR); $q->bindParam(':fname', $fname, PDO::PARAM_STR); $q->bindParam(':lname', $lname, PDO::PARAM_STR); $q->bindParam(':imagename', $imagename, PDO::PARAM_STR); $q->execute(); $sql1 = "UPDATE people SET firstname = (SELECT firstname FROM user WHERE username=:user_id1) WHERE username=:user_id2"; $q = $conn->prepare($sql1) or die("failed!"); $q->bindParam(':user_id1', $user_id, PDO::PARAM_STR); $q->bindParam(':user_id2', $user_id, PDO::PARAM_STR); $q->execute(); $sql2 = "UPDATE people SET surname = (SELECT surname FROM user WHERE username=:user_id1) WHERE username=:user_id2"; $q = $conn->prepare($sql2) or die("failed!"); $q->bindParam(':user_id1', $user_id, PDO::PARAM_STR); $q->bindParam(':user_id2', $user_id, PDO::PARAM_STR); $q->execute(); header("Location: search.php"); exit; } else { // A common cause of file moving failures is because of bad permissions on the directory attempting to be written to // Make sure you chmod the directory to be writeable $_SESSION['error'] = "Could not upload file. Check read/write persmissions on the directory"; header("Location: error.php"); exit; } ?>

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  • getting notice like undefined index

    - by user2533308
    $result = mysql_query("SELECT * FROM customers WHERE loginid='$_POST[login]' AND accpassword='$_POST[password]'"); if(mysql_num_rows($result) == 1) { while($recarr = mysql_fetch_array($result)) { $_SESSION[customerid] = $recarr[customerid]; $_SESSION[ifsccode] = $recarr[ifsccode]; $_SESSION[customername] = $recarr[firstname]. " ". $recarr[lastname]; $_SESSION[loginid] = $recarr[loginid]; $_SESSION[accstatus] = $recarr[accstatus]; $_SESSION[accopendate] = $recarr[accopendate]; $_SESSION[lastlogin] = $recarr[lastlogin]; } $_SESSION["loginid"] =$_POST["login"]; header("Location: accountalerts.php"); } else { $logininfo = "Invalid Username or password entered"; } Notice: Undefined index:login and Notice: Undefined index:password try to help me out getting error message in second line

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  • How to get Joomla users data into a json array

    - by sami
    $sql = "SELECT * FROM `jos_users` LIMIT 0, 30 "; $response = array(); $posts = array(); $result=mysql_query($sql); while($row=mysql_fetch_array($result)) { $id=$row['id']; $id=$row['name']; $posts[] = array('id'=> $title, 'name'=> $name); } $response['jos_users'] = $posts; $fp = fopen('results.json', 'w'); fwrite($fp, json_encode($response)); fclose($fp); I want to fetch the user id and name to the json file.i thought id did wrong code.can anyone correct it ?

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