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  • Cannot running next process when a variable save no value

    - by bruine
    First, I wanna compare between 2 tables tb_wrapper and tb_summary to get the data in the tb_wrapper that doesn't exist in the tb_summary then save in $link. If I don't get the same data, I want to print the result $link. When I don't get the not same data, I want it to go to another process. Here's the code : $q2 = mysql_query(" SELECT a.doc_url FROM tb_wrapper a LEFT JOIN tb_summary b ON a.doc_name = b.doc_summ WHERE b.doc_summ IS NULL"); while ($row = mysql_fetch_array($q2)){ $link = $row['doc_url']; if (!$link){ include 'next_process.php'; } else { print_r($link); } } it doesn't work. When I don't get the not same data or $link not save a value. table : CREATE TABLE tb1 (`id` int, `doc_name` varchar(100), `doc_url` varchar(50)) } CREATE TABLE tb2 (`id` int, `doc_summ` varchar(100)) }

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  • User's Post count from specific category [Wordpress]

    - by morningglory
    Hello, I want to show user's post count from specific category. Currently, I can only be able to query all posts. My code is like this <?php $userpost_count = $wpdb->get_var("SELECT COUNT(*) FROM $wpdb->posts WHERE post_status = 'publish' AND post_type ='post' AND post_author = '".$curauth->ID."'");?> <?php echo "<span>Total post: </b></span>".$userpost_count.""?> I know that, I need to join two table which is post table and term_relationships, but i don't know how to get it. Please kindly help me with that. Thank you.

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  • Copying a database into a new database including structure and data

    - by Jason
    In phpMyAdmin under operations I can "Copy database to:" and select Structure and data CREATE DATABASE before copying Add AUTO_INCREMENT value I need to be able to do that without using phpMyAdmin. I know how to create the database and user. I have a source database that's a shell that I can work from so all I really need is the how to copy all the table structure and data part. (I know, the harder part) system() & exec() are not options for me which rules out mysqldump. (I think) How can I loop through each table and recreate it's structure and data? Is it just looping through the results of SHOW TABLES then for each table looping through DESCRIBE tablename Then, is there an easy way for getting the data copied?

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  • I cant get a field on report from a view

    - by felipedz
    When I get a field, this work good. But, when get a field from a 'VIEW', is a problem because the code of a VIEW is: CREATE OR REPLACE VIEW tabla_clientes AS SELECT id_cliente,nombre, CONCAT('$ ',FORMAT(monto_a_favor,0), '???'), CONCAT('$ ',FORMAT(calcular_monto_por_cobrar_cliente(id_cliente),0)) FROM cliente; When I compile this. Appears errors from the name of fields. Description | Object ---------------------------------------------------------------------------- Syntax error, insert ";" to complete BlockStatements | ${CONCAT('$ ',FORMAT(monto_a_favor,0)} Syntax error on tokens, delete these tokens | ${CONCAT('$ ',FORMAT(monto_a_favor,0)} Syntax error on token ",", delete this token | ${CONCAT('$ ',FORMAT(monto_a_favor,0)} If I change the name at this field appears other error.

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  • where id = multiple artists

    - by pixel
    Any time there is an update within my music community (song comment, artist update, new song added, yadda yadda yadda), a new row is inserted in my "updates" table. The row houses the artist id involved along with other information (what type of change, time and date, etc). My users have a "favorite artists" section where they can do just that -- mark artists as their favorites. As such, I'd like to create a new feature that shows the user the changes made to their various favorite artists. How should I be doing this efficiently? SELECT * FROM table_updates WHERE artist_id = 1 and artist_id = 500 and artist_id = 60032 Keep in mind, a user could have 43,000 of our artists marked as a favorite. Thoughts?

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  • How do I return the numeric value from a database query in PHP?

    - by Luke
    Hello, I am looking to retreive a numerical value from the database function adminLevel() { $q = "SELECT userlevel FROM ".TBL_USERS." WHERE id = '$_SESSION[id]'"; return mysql_query($q, $this->connection); } This is the SQL. I then wrote the following php/html: <?php $q = $database->adminLevel(); if ($q > 7) { ?> <a href="newleague.php">Create a new league</a> <? } ?> The problem I have is that the userlevel returned isn't affecting the if statement. It is always displayed. How do i get it to test the value of userlevel is greater than 7? Thanks

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  • PHP - How to display other values, when a query is limited by 3?

    - by Dodi300
    Hello. Can anyone tell me how to display the other values, when a query is limited my 3. In this question I asked how to order and limit values, but now I want to show the others in another query. How would I go about doing this? Here's the code I used before: $query = "SELECT gmd FROM account ORDER BY gmd DESC LIMIT 3"; $result = mysql_query($query); while($row = mysql_fetch_array($result, MYSQL_ASSOC)) { } Thanks!

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  • differentiating results of sql right join

    - by Sourabh
    Hi I have a below SQL query SELECT `User`.`username` , Permalink.perma_link_id, Permalink.locale, Permalink.title, DATEDIFF( CURDATE( ) , Permalink.created ) AS dtdiff, `TargetSegment`.segment_text, TargetSegment.source_segment_id ,TargetSegment.perma_link_id ,TargetSegment.created ,TargetSegment.updated, DATEDIFF( CURDATE( ) , TargetSegment.updated ) AS datediff FROM `users` AS `User` RIGHT JOIN perma_links AS `PermaLink` ON ( `PermaLink`.`username` = `User`.`username` ) RIGHT JOIN target_segments AS `TargetSegment` ON ( `TargetSegment`.`username` = `User`.`username` ) RIGHT JOIN source_segments AS `SourceSegment` ON ( `SourceSegment`.`source_detail_id` = `PermaLink`.`source_detail_id` ) LEFT JOIN source_details AS `SourceDetail` ON ( `SourceSegment`.`source_detail_id` = `SourceDetail`.`id` ) WHERE `TargetSegment`.`username` = "xxxx" AND `TargetSegment`.`segment_text` <> "" AND `Permalink`.`perma_link_id` = `TargetSegment`.`perma_link_id` AND `TargetSegment`.`source_segment_id` = `SourceSegment`.`id` AND `Permalink`.`source_detail_id` = `SourceDetail`.`id` ORDER BY `TargetSegment`.`updated` DESC LIMIT 0 , 10 This SQL is fetching correct results for me.I want to identify from which table each row if from , to be specific which result is due to PermaLink table and which is from TargetSegment table. is this achievable ?

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  • Storing database records into array

    - by zerey
    I would want to create an array that will hold records retrieved from a database using a query of SELECT statement. The records to be retrieved have multiple fields such as lastname, firstname, mi and 20 more fields. What would be the best approach on coding this function? alright i have followed what prisoner have given below.. the next question is how do i search through this kind of array using queries? for example i want to search for a username..

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  • How can I fake sql data while preserving statements without commenting my server-side code?

    - by Fedor
    I have to use hardcoded values for certain fields because at this moment we don't have access to the real data. When we do get access, I don't want to go through a lot of work uncommenting. Is it possible to keep this statement the way it is, except use '25' as the alias for ratecode? IF(special.ratecode IS NULL, br.ratecode, special.ratecode) AS ratecode, I have about 8 or so IF statements similar to this and I'm just too lazy ( even with vim ) to re-append while commenting out each if statement line by line. I would have to do this: $sql = 'SELECT u.*,'; // IF ( special.ratecode IS NULL, br.ratecode, special.ratecode) AS ratecode $sql.= '25 AS ratecode';

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  • Securing database keys for client-side processing

    - by danp
    I have a tree of information which is sent to the client in a JSON object. In that object, I don't want to have raw IDs which are coming from the database. I thought of making a hash of the id and a field in the object (title, for example) or a salt, but I'm worried that this might have a serious effect on processing overhead. SELECT * FROM `things` where md5(concat(id,'some salt')) = md5('1some salt'); Is there a standard practice for obscuring IDs in this kind of situation?

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  • Find node level in a tree

    - by Álvaro G. Vicario
    I have a tree (nested categories) stored as follows: CREATE TABLE `category` ( `category_id` int(10) unsigned NOT NULL AUTO_INCREMENT, `category_name` varchar(100) NOT NULL, `parent_id` int(10) unsigned DEFAULT NULL, PRIMARY KEY (`category_id`), UNIQUE KEY `category_name_UNIQUE` (`category_name`,`parent_id`), KEY `fk_category_category1` (`parent_id`,`category_id`), CONSTRAINT `fk_category_category1` FOREIGN KEY (`parent_id`) REFERENCES `category` (`category_id`) ON DELETE SET NULL ON UPDATE CASCADE ) ENGINE=InnoDB DEFAULT CHARSET=utf8 COLLATE=utf8_spanish_ci I need to feed my client-side language (PHP) with node information (child+parent) so it can build the tree in memory. I can tweak my PHP code but I think the operation would be way simpler if I could just retrieve the rows in such an order that all parents come before their children. I could do that if I knew the level for each node: SELECT category_id, category_name, parent_id FROM category ORDER BY level -- No `level` column so far :( Can you think of a way (view, stored routine or whatever...) to calculate the node level? I guess it's okay if it's not real-time and I need to recalculate it on node modification.

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  • Can I do this in only one query ?

    - by Paté
    Merry christmas everyone, I Know my way around SQL but I'm having a hard time figuring this one out. First here are my tables (examples) User id name friend from //userid to //userid If user 1 is friend with user 10 then you a row with 1,10. User 1 cannot be friend with user 10 if user 10 is not friend with user 1 so you have 1,10 10,1 It may look weird but I need those two rows per relations. Now I'm trying to make a query to select the users that have the most mutual friend with a given user. For example User 1 is friend with user 10,9 and 7 and user 8 is friend with 10,9 and 7 too ,I want to suggest user 1 to invite him (like facebook). I want to get like the 10 first people with the most mutual friend. The output would be like User,NumOfMutualFriends I dont know if that can be done in a single query ? Thanks in advance for any help.

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  • Turning user ID into name (seperate tables) in PHP

    - by mobile
    I am currently trying to display the username of people who i am following, the problem is that during the following process, only the ID of me and the person i'm following is stored. I've got it to the point where the ID's are displayed but i'd like to show the names hyperlinked. $p_id is the profile ID. Here's what I've got: $following = mysql_query("SELECT `follower`, `followed` FROM user_follow WHERE follower=$p_id"); I am following: <?php while($apple = mysql_fetch_array($following)){ echo '<a href="'.$apple['followed'].'">+'.$apple['followed'].'</a> '; }?> The usernames are in a different table "users" under the field "username" - I need them to match up with the ID's that are currently displayed, and be displayed. Any help appreciated, thanks guys

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  • Stopping users posting more than once

    - by user342391
    Before posting my form I am checking the database to see if there are any previous posts from the user. If there are previous posts then the script will kick back a message saying you have already posted. The problem is that what I am trying to achieve isn't working it all goes wrong after my else statement. It is also probable that there is an sql injection vulnerability too. Can you help??4 <?php include '../login/dbc.php'; page_protect(); $customerid = $_SESSION['user_id']; $checkid = "SELECT customerid FROM content WHERE customerid = $customerid"; if ($checkid = $customerid) {echo 'You cannot post any more entries, you have already created one';} else $sql="INSERT INTO content (customerid, weburl, title, description) VALUES ('$_POST[customerid]','$_POST[webaddress]','$_POST[pagetitle]','$_POST[pagedescription]')"; if (!mysql_query($sql)) { die('Error: ' . mysql_error()); } echo "1 record added"; ?>

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  • How to limit results by SUM

    - by superspace
    I have a table of events called event. For the purpose of this question it only has one field called date. The following query returns me a number of events that are happening on each date for the next 14 days: SELECT DATE_FORMAT( ev.date, '%Y-%m-%d' ) as short_date, count(*) as date_count FROM event ev WHERE ev.date >= NOW() GROUP BY short_date ORDER BY ev.start_date ASC LIMIT 14 The result could be as follows: +------------+------------+ | short_date | date_count | +------------+------------+ | 2010-03-14 | 1 | | 2010-03-15 | 2 | | 2010-03-16 | 9 | | 2010-03-17 | 8 | | 2010-03-18 | 11 | | 2010-03-19 | 14 | | 2010-03-20 | 13 | | 2010-03-21 | 7 | | 2010-03-22 | 2 | | 2010-03-23 | 3 | | 2010-03-24 | 3 | | 2010-03-25 | 6 | | 2010-03-26 | 23 | | 2010-03-27 | 14 | +------------+------------+ 14 rows in set (0.06 sec) Let's say I want to dislay these events by date. At the same time I only want to display a maximum of 10 at a time. How would I do this? Somehow I need to limit this result by the SUM of the date_count field but I do not know how. Anybody run into this problem before? Any help would be appreciated. Thanks

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  • MULTIPLE CRITERIA TABLE JOIN

    - by user1447203
    I have a table listing clothing items (shirt, trousers, etc) named . Each item is identified with a unique CLOTHING.CLOTHING_ID. So a blue shirt is 01, a flowery shirt is 12 and jeans are 07 say. I have a second table identifying outfits with a column for shirts, for trousers, shoes etc. For example Outfit 1: shirt 01, trousers 07 (i.e. blue shirt with jeans) Outfit 2: shirt 12, trousers 07 (so flowery shirt with jeans). This table is named and each outfit is unique with OUTFIT_LIST.OUTFIT_ID. I want to produce a select statement that will list each outfit's contents, i.e. find the clothing specified in Outfit 1. Any help would be very much appreciated, and apologies in advance if I am missing a very simple solution. I have been playing with JOINS of all descriptions and CONCATS and so on with now luck - I am very new to this. Thanks.

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  • You can't specify target table 'b' for update in FROM clause

    - by elo
    I need to know where did i do wrong in this sql statement. I try to find solution in previous threads with similar problem but none can solve my problem. so i think maybe my statement is actually wrong. update table1 b left join table2 m on b.ICNO=m.ICNO set b.SalMoveMth = '01' where m.Status!='6' and (DATE_FORMAT(startDateSand,'%m')='10' or DATE_FORMAT(startDateSand,'%m')='11' or DATE_FORMAT(startDateSand,'%m')='12') and ((select SalMoveMth from table1 where ICNO=table2.ICNO order by SalMoveMthStDt desc limit 1)!='10'). Thank You.

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  • Testing a SQL Query for True or False

    - by KickingLettuce
    $sql = "SELECT # FROM users WHERE onduty = 1 AND loc_id = '{$site}';"; $result = mysql_query($sql); I simply want to test if this is true or false. If it returns 0 rows, I want next line to be something like: if (!$result) { //do this; } However, in my test, I am getting false when I know it should be true. Is this sound logic here? (note, yes I know I should be using mysqli_query, that is not what I am asking here)

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  • Are Triggers Based On Queries Atomic?

    - by David
    I have a table that has a Sequence number. This sequence number will change and referencing the auto number will not work. I fear that the values of the trigger will collide. If two transactions read at the same time. I have ran simulated tests on 3 connections @ ~1 million records each and no collisions. CREATE TABLE `aut` ( `au_id` int(10) NOT NULL AUTO_INCREMENT, `au_control` int(10) DEFAULT NULL, `au_name` varchar(50) DEFAULT NULL, `did` int(10) DEFAULT NULL, PRIMARY KEY (`au_id`), KEY `Did` (`did`) ) ENGINE=InnoDB AUTO_INCREMENT=1 DEFAULT CHARSET=latin1 TRIGGER `binc_control` BEFORE INSERT ON `aut` FOR EACH ROW BEGIN SET NEW.AU_CONTROL = (SELECT COUNT(*)+1 FROM aut WHERE did = NEW.did); END;

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  • Where I get wrong?

    - by Ole Jak
    I have PHP code like this require_once( "includes" . DIRECTORY_SEPARATOR . "constants.php"); $userID = validKey( $key ); $query = "select a.username, b.streamID from user a, streams b where a.id = b.userID;)"; $connection = mysql_connect(DB_SERVER,DB_USER,DB_PASS); if (!$connection) { die("Database connection failed: " . mysql_error()); } $db_select = mysql_select_db(DB_NAME,$connection); if (!$db_select) {die( "Database selection failed: " . mysql_error()); } $generated_table = mysql_fetch_array(mysql_query($query, $connection)); // line (*) print_r($generated_table); But PHP gives me error/worning and does not print anything out Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given on line (*) 1) Why It does not printed me anything out 2) Where am I wrong?

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  • SUM a pair of COUNTs from two tables based on a time variable

    - by Kevin O.
    Been searching for an answer to this for the better part of an hour without much luck. I have two regional tables laid out with the same column names and I can put out a result list for either table based on the following query (swap Table2 for Table1): SELECT Table1.YEAR, FORMAT(COUNT(Table1.id),0) AS Total FROM Table1 WHERE Table1.variable='Y' GROUP BY Table1.YEAR Ideally I'd like to get a result that gives me a total sum of the counts by year, so instead of: | REGION 1 | | REGION 2 | | YEAR | Total | | YEAR | Total | | 2010 | 5 | | 2010 | 1 | | 2009 | 2 | | 2009 | 3 | | | | | 2008 | 4 | I'd have: | MERGED | | YEAR | Total | | 2010 | 6 | | 2009 | 5 | | 2008 | 4 | I've tried a variety of JOINs and other ideas but I think I'm caught up on the SUM and COUNT issue. Any help would be appreciated, thanks!

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  • Where to store users visited pages?

    - by kofto4ka
    Hi there. I have a project, where I have posts for example. The task is next: I must show to user his last posts visit. This is my solution: every time user visits new (for him) topic, I create a new record in table visits. Table visits has next structure: id, user_id, post_id, last_visit. Now my tables visits has ~14,000,000 records and its still growing every day.. May be my solution isnt optimal and exists another way how to store users visits? Its important to save every visit as standalone record, because I also have feature to select and use users visits. And I cant purge this table, because data could be needed later month, year. How I could optimize this situation?

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  • Strange SQL problem selecting multiple values for same column

    - by Nubber
    Hello there, Been at this for a few hours now and I can't make any sense of it. I've used this way of selecting multiple values for same column a few times, but there is something weird with this one. SELECT * FROM employee as s INNER JOIN works AS w1 ON w1.name = s.name INNER JOIN employee AS w2 ON w2.name = s.name INNER JOIN employee AS w3 ON w3.name = s.name WHERE w2.city = 'Washington' Basically what I want to do is find all companies which have people in all the cities. The company name is under 'works'. The problem is however that if I have the WHERE w2.city='Washington' it will make ALL the cities match Washington when it should only touch w2 and leave w3 alone so I could match it with another value. Anyone know why its doing this? Or know a better way to do it. Thank you very much in advance.

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  • Obtaining a timestamp every minute from a database

    - by soumen
    This is my table structure: +------------+-----------+------+-----+---------+-------+ | Field | Type | Null | Key | Default | Extra | +------------+-----------+------+-----+---------+-------+ | uid | char(255) | NO | MUL | NULL | | | cid | char(255) | NO | MUL | NULL | | | ip_address | char(15) | NO | | NULL | | | user_agent | char(255) | YES | | NULL | | | open_date | datetime | NO | MUL | NULL | | | referrer | char(255) | YES | | NULL | | | environ | text | YES | | NULL | | | country | char(255) | NO | MUL | NULL | | +------------+-----------+------+-----+---------+-------+ I want to get a timestamp every minute within a range. select DATE_ADD(open_date,interval 1 minute) as m from open_track.camp_open where open_date between "2009-05-13 00:00:00" and "2009-05-13 23:59:59" limit 10; outputs +---------------------+ | m | +---------------------+ | 2009-05-13 00:01:01 | | 2009-05-13 00:01:02 | | 2009-05-13 00:01:03 | | 2009-05-13 00:01:03 | | 2009-05-13 00:01:04 | | 2009-05-13 00:01:05 | | 2009-05-13 00:01:06 | | 2009-05-13 00:01:08 | | 2009-05-13 00:01:08 | | 2009-05-13 00:01:09 | +---------------------+ Please advise me.

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