Search Results

Search found 40581 results on 1624 pages for 'mysql select db'.

Page 437/1624 | < Previous Page | 433 434 435 436 437 438 439 440 441 442 443 444  | Next Page >

  • Stop invalid data in a attribute with foreign key constraint using triggers?

    - by Eternal Learner
    How to specify a trigger which checks if the data inserted into a tables foreign key attribute, actually exists in the references table. If it exist no action should be performed , else the trigger should delete the inserted tuple. Eg: Consider have 2 tables R(A int Primary Key) and S(B int Primary Key , A int Foreign Key References R(A) ) . I have written a trigger like this : Create Trigger DelS BEFORE INSERT ON S FOR EACH ROW BEGIN Delete FROM S where New.A <> ( Select * from R;) ); End; I am sure I am making a mistake while specifying the inner sub query within the Begin and end Blocks of the trigger. My question is how do I make such a trigger ?

    Read the article

  • Pagination links do not work after first page

    - by TheStack
    Hello, I am trying to fix this pagination script. It seems when I click on the pagination links [1][2][3][4]or[5] , it doesn't work. It just shows the first page and when clicking on the next numbers nothing happens. I hoping someone can see something in the script that I can not see. The main page looks like this (pagination.php): <?php include_once('generate_pagination.php'); ?> <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.1/jquery.min.js"></script> <script type="text/javascript" src="jquery_pagination.js"></script> <div id="loading" ></div> <div id="content" data-page="1"></div> <ul id="pagination"> <?php generate_pagination() ?> </ul> <br /> <br /> <a href="#" class="category" id="marketing">Marketing</a> <a href="#" class="category" id="automotive">Automotive</a> <a href="#" class="category" id="sports">Sports</a> Then, generate_pagination.php: <?php function generate_pagination($sql) { include_once('config.php'); $per_page = 3; //Calculating no of pages $result = mysql_query($sql); $count = mysql_fetch_row($result); $pages = ceil($count[0]/$per_page); //Pagination Numbers for($i=1; $i<=$pages; $i++) { echo '<li class="page_numbers" id="'.$i.'">'.$i.'</li>'; } } $ids=$_GET['ids']; generate_pagination("SELECT COUNT(*) FROM explore WHERE category='$ids'"); ?> Here is the jquery file (jquery_pagination.js): $(document).ready(function(){ //Display Loading Image function Display_Load() { $("#loading").fadeIn(900,0); $("#loading").html("<img src='bigLoader.gif' />"); } //Hide Loading Image function Hide_Load() { $("#loading").fadeOut('slow'); }; //Default Starting Page Results $("#pagination li:first").css({'color' : '#FF0084'}).css({'border' : 'none'}); Display_Load(); $("#content").load("pagination_data.php?page=1", Hide_Load()); //Pagination Click $("#pagination li").click(function(){ Display_Load(); //CSS Styles $("#pagination li") .css({'border' : 'solid #dddddd 1px'}) .css({'color' : '#0063DC'}); $(this) .css({'color' : '#FF0084'}) .css({'border' : 'none'}); //Loading Data var pageNum = this.id; $("#content").load("pagination_data.php?page=" + pageNum, function(){ Hide_Load(); $(this).attr('data-page', pageNum); }); }); // Editing below. // Sort content Marketing $("a.category").click(function() { Display_Load(); var this_id = $(this).attr('id'); $.get("pagination.php", { category: this.id }, function(data){ //Load your results into the page var pageNum = $('#content').attr('data-page'); $("#pagination").load('generate_pagination.php?category=' + pageNum +'&ids='+ this_id ); $("#content").load("filter_marketing.php?page=" + pageNum +'&id='+ this_id, Hide_Load()); }); }); }); Lastly, filter_marketing.php (when a user clicks the filter link buttons): <?php include('config.php'); $per_page = 3; if(count($_GET)>0) { if($_GET['page']!=''){ $page=$_GET['page']; } if($_GET['id']!=''){ $id=$_GET['id']; } } $page= ($_GET['page']!='') ? $_GET['page']: false; $id= ($_GET['id']!='') ? $_GET['id']: false; $start = ($page-1)*$per_page; if($page && $id){ $sql = "SELECT * FROM explore WHERE category='$id' ORDER BY category LIMIT $start,$per_page"; } else { die('Error: missing parameters. Id= '.$id.' and page= '.$page); } $result = mysql_query($sql); ?> <table width="800px"> <?php while($row = mysql_fetch_array($result)) { $msg_id=$row['id']; $message=$row['site_description']; $site_price=$row['site_price']; ?> <tr> <td><?php echo $msg_id; ?></td> <td><?php echo $message; ?></td> <td><?php echo $site_price; ?></td> </tr> <?php } ?> </table> So, if anyone sees where the problem is occurring and can help rid of the problem, that would be great, Thank you.

    Read the article

  • CakePHP HABTM Filtering

    - by James Haigh
    Hi, I've got two tables - users and servers, and for the HABTM relationship, users_servers. Users HABTM servers and vice versa. I'm trying to find a way for Cake to select the servers that a user is assigned to. I'm trying things like $this->User->Server->find('all'); which just returns all the servers, regardless of whether they belong to the user. $this->User->Server->find('all', array('conditions' => array('Server.user_id' => 1))) just gives an unknown column SQL error. I'm sure I'm missing something obvious but just need someone to point me in the right direction. Thanks!

    Read the article

  • Many Associations Leading to Slow Query

    - by Joey Cadle
    I currently have a database that has a lot of many to many associations. I have services which have many variations which have many staff who can perform the variation who then have details on themselves like name, role, etc... At 10 services with 3 variations each and up to 4 out of 20 staff attached to each service even doing something as getting all variations and the staff associated with them takes 4s. Is there a way I can reduce these queries that take a while to process? I've cut down the queries by doing eager loading in my DBM to reduce the problems that arise from 1+N issues, but still 4s is a long query for just a testing stage. Is there a structure out there that would help make such nested many to many associations much quicker to select? Maybe combining everything past the service level into a single table with a 'TYPE' column ?? I'm just not knowledgable enough to know the solution that turns this 4s query into a 300MS query... Any suggestions would be helpful.

    Read the article

  • Getting highest results in a JOIN

    - by Keithamus
    I've got three tables; Auctions, Auction Bids and Users. The table structure looks something like this: Auctions: id title -- ----- 1 Auction 1 2 Auction 2 Auction Bids: id user_id auction_id bid_amt -- ------- ---------- ------- 1 1 1 200.00 2 2 1 202.00 3 1 2 100.00 Users is just a standard table, with id and user name. My aim is to join these tables so I can get the highest values of these bids, as well as get the usernames related to those bids; so I have a result set like so: auction_id auction_title auctionbid_amt user_username ---------- ------------- -------------- ------------- 1 Auction 1 202.00 Bidder2 2 Auction 2 100.00 Bidder1 So far my query is as follows: SELECT a.id, a.title, ab.bid_points, u.display_name FROM auction a LEFT JOIN auctionbid ab ON a.id = ab.auction_id LEFT JOIN users u ON u.id = ab.user_id GROUP BY a.id This gets the single rows I am after, but it seems to display the lowest bid_amt, not the highest.

    Read the article

  • sql boolean truth test: zero OR null

    - by AK
    Is there way to test for both 0 and NULL with one equality operator? I realize I could do this: WHERE field = 0 OR field IS NULL But my life would be a hundred times easier if this would work: WHERE field IN (0, NULL) (btw, why doesn't that work?) I've also read about converting NULL to 0 in the SELECT statement (with COALESCE). The framework I'm using would also make this unpleasant. Realize this is oddly specific, but is there any way to test for 0 and NULL with one WHERE predicate?

    Read the article

  • group by, order by, with join

    - by Scarface
    Hey guys, quick question, I have this query, and I am trying to get the latest comment for each topic and then sort those results in descending order (therefore one comment per topic). I have what I think should work, but my join always messes my results up. Somehow, it seems to have sorted the end results properly, but has not taken the latest comment from each topic instead it seems to have just taken a random comment. If anyone has any ideas, would really appreciate any advice SELECT * FROM comments JOIN topic ON topic.topic_id=comments.topic_id WHERE topic.creator='admin' GROUP BY comments.topic_id ORDER BY comments.time DESC table comments is structured like id time user message topic_id table topic is structured like topic_id subject_id topic_title creator timestamp description

    Read the article

  • SQL where clasue to work with Group by clasue after performing a count()

    - by Matt
    Tried my usual references at w3schools and google. No luck I'm trying to produce the following results. QTY is a derived column | Position | QTY -------------------- 1 Clerk 2 2 Mgr 2 Here's what I'm not having luck with: SELECT Position, Count(position) AS 'QTY' FROM tblemployee Where ('QTY' != 1) GROUP BY Position I know that my Position is set up as varchar(255) Count produces a integer data and my where clasue is accurate so that leads me to believe that that Count() is jamming me up. Please throw up an example so I can reference later. Thanks for the help!

    Read the article

  • How to display how many times each records in a table used by other table

    - by Fredy
    I have a problem with my query, below are two tables that tbl_tag and tbl_tag_usedby. I want to show how much of each record in tbl_tag used by record in tbl_tag_usedby. Here is a query that I use: SELECT t.*, COUNT(u.tagid) AS totale FROM tbl_tag t LEFT JOIN tbl_tag_usedby u ON u.tagid = t.id AND t.status =1 GROUP BY u.tagid and the results are as below: In this case the record id from 2 to 6 do not appear in the query results, I want record id from 2 to 6 are also shown and on the field "totale" its value is 0. Can anyone help me?

    Read the article

  • How can I sqldump a huge database?

    - by meder
    SELECT count(*) from table gives me 3296869 rows. The table only contains 4 columns, storing dropped domains. I tried to dump the sql through: $backupFile = $dbname . date("Y-m-d-H-i-s") . '.gz'; $command = "mysqldump --opt -h $dbhost -u $dbuser -p $dbpass $dbname | gzip > $backupFile"; However, this just dumps an empty 20 KB gzipped file. My client is using shared hosting so the server specs and resource usage aren't top of the line. I'm not even given ssh access or access directly to the database so I have to make queries through PHP scripts I upload via FTP ( SFTP isn't an option, again ). Is there some way I can perhaps sequentially download portions of it, or pass an argument to mysqldump that will optimize it? I came across http://jeremy.zawodny.com/blog/archives/000690.html which mentions the -q flag and tried that but it didn't seem to do anything differently.

    Read the article

  • How to refresh site if $_SESSION variable has changed

    - by 4ndro1d
    I'm writing in my $_SESSION variable from a database, when i clicked a link. public function getProjectById($id){ $query="SELECT * FROM projects WHERE id=\"$id\""; $result=mysql_query($query); $num=mysql_numrows($result); while ($row = mysql_fetch_object($result)) { $_SESSION['projectid'] = $row->id; $_SESSION['projecttitle'] = $row->title; $_SESSION['projectinfo'] = $row->info; $_SESSION['projecttext'] = $row->text; $_SESSION['projectcategory'] = $row->category; } } Now my variable is overwritten and I want to show these variables in my index.php like this: <div id="textContent"> <?php if(isset($_SESSION['projecttext']) && !empty($_SESSION['projecttext'])) { echo $_SESSION['projecttext']; }else { echo 'No text'; } ?></div> But of course, my page will not refresh automatically. How can I do that?

    Read the article

  • How can I use cURL to open multiple URLs simultaneously with PHP?

    - by Rob
    Here is my current code: $SQL = mysql_query("SELECT url FROM urls") or die(mysql_error()); //Query the urls table while($resultSet = mysql_fetch_array($SQL)){ //Put all the urls into one variable // Now for some cURL to run it. $ch = curl_init($resultSet['url']); //load the urls curl_setopt($ch, CURLOPT_TIMEOUT, 2); //No need to wait for it to load. Execute it and go. curl_exec($ch); //Execute curl_close($ch); //Close it off } //While loop I'm relatively new to cURL. By relatively new, I mean this is my first time using cURL. Currently it loads one for two seconds, then loads the next one for 2 seconds, then the next. however, I want to make it load ALL of them at the same time. I'm sure its possible, I'm just unsure as to how. If someone could point me in the right direction, I'd appreciate it.

    Read the article

  • Broken count(*) after adding LEFT JOIN

    - by Iain Urquhart
    Since adding the LEFT JOIN to the query below, the count(*) has been returning some strange values, it seems to have added the total rows returned in the query to the 'level': SELECT `n`.*, exp_channel_titles.*, round((`n`.`rgt` - `n`.`lft` - 1) / 2, 0) AS childs, count(*) - 1 + (`n`.`lft` > 1) + 1 AS level, ((min(`p`.`rgt`) - `n`.`rgt` - (`n`.`lft` > 1)) / 2) > 0 AS lower, (((`n`.`lft` - max(`p`.`lft`) > 1))) AS upper FROM `exp_node_tree_6` `n` LEFT JOIN `exp_channel_titles` ON (`n`.`entry_id`=`exp_channel_titles`.`entry_id`), `exp_node_tree_6` `p`, `exp_node_tree_6` WHERE `n`.`lft` BETWEEN `p`.`lft` AND `p`.`rgt` AND ( `p`.`node_id` != `n`.`node_id` OR `n`.`lft` = 1 ) GROUP BY `n`.`node_id` ORDER BY `n`.`lft` I'm totally stumped... Thank you!

    Read the article

  • SQL Query That Should Return Least two days record

    - by Aryans
    I have a table "abc" where i store timestamp having multiple records let suppose 1334034000 Date:10-April-2012 1334126289 Date:11-April-2012 1334291399 Date:13-April-2012 I want to build a sql query where I can find at first attempt the records having last two day values and so second time the next two days . . . Example: Select *,dayofmonth(FROM_UNIXTIME(i_created)) from notes where dayofmonth(FROM_UNIXTIME(i_created)) > dayofmonth(FROM_UNIXTIME(i_created)) -2 order by dayofmonth(FROM_UNIXTIME(i_created)) this query returns all the records date wise but we need very most two days record. Please suggest accordingly. Thanks in advance

    Read the article

  • Yes another ON DUPLICATE KEY UPDATE query

    - by Andy Gee
    I've been reading all the questions on here but I still don't get it I have two identical tables of considerable size. I would like to update table packages_sorted with data from packages_sorted_temp without destroying the existing data on packages_sorted Table packages_sorted_temp contains data on only 2 columns db_id and quality_rank Table packages_sorted contains data on all 35 columns but quality_rank is 0 The primary key on each table is db_id and this is what I want to trigger the ON DUPLICATE KEY UPDATE with. In essence how do I merge these two tables by and change packages_sorted.quality_rank of 0 to the quality_rank stored in packages_sorted_temp under the same primary key Here's what's not working INSERT INTO `packages_sorted` ( `db_id` , `quality_rank` ) SELECT `db_id` , `quality_rank` FROM `packages_sorted_temp` ON DUPLICATE KEY UPDATE `packages_sorted`.`db_id` = `packages_sorted`.`db_id`

    Read the article

  • mysql_fetch_array() not displaying all results

    - by user1666995
    I have a database with a calendar table (each row represents one day) with 4 years of rows (2012, 2013, 2014, 2015). I use the column name calyear for the year. I use the following code to find values for distinct years then display it: $year = mysql_query("SELECT DISTINCT calyear FROM calendar"); while($yeararray = mysql_fetch_array($year)) { echo($yeararray['calyear']."<br />"); } The problem is it only displays the years 2013, 2014, 2015 even though when I use echo(mysql_num_rows($year); it displays the value 4 which I take to mean all 4 years are there. I'm not quite sure where I'm going wrong with this.

    Read the article

  • PHP - How to retrieve session in php

    - by Klaus Jasper
    I created a table that contains id - names - jobs and page that shows the names only and beside each name there is button Job and session that contains the id. this is my code $query = mysql_query("SELECT * FROM table"); while($fetch = mysql_fetch_array("$query")){ $name = $fetch['names']; $id = $fetch['id']; echo '</br>'; echo $name; $_SESSION['name'] = $id; echo "<button>Job</button>"; } I want when the user click on button Job redirect to a page that contains the job of that session. so how can I do it?

    Read the article

  • LIMIT amount of rows fetched by JOIN

    - by user892134
    How do i LIMIT the child rows fetched to only 5? Here is the SQLfiddle http://sqlfiddle.com/#!2/bd96a/2. Right now it fetches all rows with parentid='4' and parentid='14'. It should only fetch 5 of each parentid. Assuming i have hundreds of rows, it should only fetch a max of 5 for each parentid. "SELECT child.* FROM mytable as parent LEFT JOIN mytable as child on child.parentid=parent.id WHERE parent.pageid IN ( 1, 2) AND parent.submittype='1' ORDER BY child.id ASC"; How do i solve this?

    Read the article

  • PHP displaying error for already used Username and empty field

    - by Pixel Reaper
    I want PHP to make sure the username is not already used and also check to see if the field is empty. Sorry I am a huge noob when it comes to php. Here is my code: // Check for an Username: $dup = mysql_query("SELECT user_username FROM users WHERE user_username='".$_POST['user_username']."'"); if(mysql_num_rows($dup) >0){ $errors[] = 'Username already used.'; } else{ $un = mysqli_real_escape_string($dbc, trim($_POST['user_username'])); echo '<b>Congrats, You are now Registered.</b>'; } else { $errors[] = 'You forgot to enter your Username.'; }

    Read the article

  • form not showing for empty records

    - by Chris Hodges
    I have a relatively simple PHP page called editcustomers with 3 columns. The problem I'm having is that the form will show when there is a record in the database and the fields will be populated with that info. When no such records exists, the form is not even shown, eliminating the possibility to insert a record. My page layout is as follows: Column 1 shows a form containing customer information, allowing it to be edited. Column 2 allows ordering of products and showing how many products were ordered Column 3 shows the total paid so far, and the total owing. The code for the page I have at present: <html> <?php $id = $_GET['id']; require_once('connect.php'); $sth = $dbh->query("SELECT * FROM users where id = '$id';"); $sth->setFetchMode(PDO::FETCH_ASSOC); $eth = $dbh->query("SELECT * FROM purchases where id = '$id';"); $eth->setFetchMode(PDO::FETCH_ASSOC); ?> <div id="main"> <div id="left"> <form name="custInfo" action ="process.php" method ="post" > <input type = "hidden" name ="formType" value="custInfo"/> <?php while($row = $sth->fetch()){ ?> <p><input type = "hidden" name ="id" value="<?php echo $row["id"] ?>"/> <p><input type = "text" name ="firstName" size ="30" value=" <?php echo $row["firstName"]?>"/> <p><input type = "text" name ="lastName" size ="30" value="<?php echo $row["lastName"]?>"/> <p><input type = "text" name ="country" size ="30" value="<?php echo $row["country"]?>"/> <p></p> <input type="submit" value="Update" /> <?php }?> </div> <div id="mid"> <form name="custCosts" action ="process.php" method ="post" > <input type = "hidden" name ="formType" value="custCosts"/> <?php while($row = $eth->fetch()){ ?> <p><input type = "hidden" name ="id" value="<?php echo $row["id"] ?>"/> <p><input type = "text" name ="amountOwed" size ="30" value=" <?php echo $row["amountOwed"]?>"/> <p><input type = "text" name ="numAaa" size ="30" value="<?php echo $row["numAaa"]?>"/> <p><input type = "text" name ="numBbb" size ="30" value="<?php echo $row["numBbb"]?>"/> <p></p> <input type="submit" value="Update" /> <?php }?> </div> <div id="right"> <b>Total Balance</b> <p> Money owed: </p> <p> aaa total: </p> <p> bbb total: </p> <p> Total: </p> <input type = "text" name ="pay" size ="20" /></p> <input type="submit" value="Make Payment" /> </div> <?php $dbh =null; ?> </body> </html> And the code for all the database trickery: <?php require_once 'connect.php'; $formType = $_POST['formType']; $id = $_POST['id']; $firstName = $_POST['firstName']; $lastName = $_POST['lastName']; $country = $_POST['country']; $amountOwed = $_POST['amountOwed ']; $numAaa = $_POST['numAaa']; $numBbb = $_POST['numBbb']; if(empty($_POST['id'])) { $sth = $dbh->prepare("INSERT INTO customers (firstName, lastName, country) VALUES ('$firstName', '$lastName', '$country')"); $sth->execute(); } elseif(!empty($_POST['id']) && !isset($_POST['stayCost']) && $_POST['formType'] == 'guestInfo'){ $sth = $dbh->prepare("UPDATE customers SET firstName = '$firstName', lastName = '$lastName', country = '$country' WHERE id = '$id'"); $sth->execute(); }elseif(!empty($_POST['id']) && isset($_POST['stayCost']) && $_POST['formType'] == 'guestInfo'){ $sth = $dbh->prepare("INSERT INTO purchases (id, amountOwed, numAaa, numBbb) VALUES ('$id', '$amountOwed', '$numAaa', '$numBbb'"); $sth->execute(); }elseif(!empty($_POST['id']) && $_POST['formType'] == 'guestCosts'){ $sth = $dbh->prepare("UPDATE purchases SET amountOwed= '$amountOwed', numAaa = '$numAaa', numBbb= '$numBbb' WHERE id = '$id'"); $sth->execute(); } $dbh =null; ?> Why does the form not even display if there is no record? An error or something I might understand....but the form is still in the HTML and should still be being output, from what I can see. Why is this not the case?

    Read the article

  • check for several conditions when a user logs in

    - by paul
    I would like to accomplish the following: If a username or password field is null, notify the user. If user name already exists, do not insert into the database and notify user to create a different name. if the username is unique and password is not null, return the username to the user. As of now it always returns "Please enter a different user name." I believe the issue has to do with the database query but I am not sure. If anyone can have a look and see if I am making an error, I greatly appreciate it, thanks. if ($userName or $userPassword = null) { echo "Please enter a user name and password or return to the homepage."; } elseif (mysql_num_rows(mysql_query("SELECT count(userName) FROM logininfo WHERE userName = '$userName'")) ==1) { echo "Please enter a different user name."; } elseif ($userName and $userPassword != null) { echo "Your login name is: $userName"; }

    Read the article

  • if specific row = null, execute query

    - by fusion
    how do i check if the value of a column is null, and only then execute the query? for example: col1 col2 col3 01 abc i run a query which first checks if the record exists or not; if it exists, it should execute the update query and if it doesn't exist, it executes the insert query. how do i check if col3 is null and if it is null, it should execute the update query. . $sql = "SELECT uid FROM `users` WHERE uid = '" . $user_id . "'"; $result = mysql_query($sql,$conn) or die('Error:' .mysql_error()); $totalrows = mysql_num_rows($result); if($totalrows < 1) { insertUser($user_id,$sk, $conn); } else { updateSessionKey($user_id,$sk,$conn); }

    Read the article

  • Group by clause return latest row information

    - by I Like PHP
    below is my table structure table_movie_info i_movie_id |movie_actor_id |movie_actress_id |movie_director_id | movie_producer_id 48 | 5 | 9 | 66 | 21 48 | 6 | 15 | 88 | 22 48 | 7 | 12 | 77 | 23 one more table is table_movie movie_id | movie_year | movie_genre_id |movie_rating 1 | 2009 | 6 | 8 2 | 2001 | 5 | 7.5 48 | 2007 | 3 | 6.8 now i need total movie information using both table,i write below query SELECT * FROM table_movie_info LEFT JOIN table_movie ON movie_id = i_movie_id WHERE i_movie_id=48 GROUP BY i_movie_id above query return only one row , but i need such type of information movie_id=48, actors_id list=5,6,7 acttress_id list=9,15,12 etc.. please tell me the optimized query which h return complete information i need. thanks for helping me always.

    Read the article

  • php query cant figure out the problem

    - by Eat
    I dont get an error but it does not return me the row values as well. How can I address the problem? <?php //DATABASE $dbConn = mysql_connect($host,$username,$password); mysql_select_db($database,$dbConn); $SQL = mysql_query("SELECT N.*, C.CatID FROM News N INNER JOIN Categories C ON N.CatID = C.CatID WHERE N.Active = 1 ORDER BY DateEntered DESC"); while ( $Result = mysql_fetch_array($SQL) or die(mysql_error())) { $CatID[] = $Result[CatID]; $NewsName[] = $Result[NewsName]; $NewsShortDesc[] = $Result[NewsShortDesc]; } // mysql_free_result($Result); ?> <div class="toparticle"> <span class="section"><?=$CatID[0] ?> </span> <span class="headline"><?=$NewsName[0] ?></span> <p><?=$NewsShortDesc[0] ?></p> </div>

    Read the article

  • help me with the following sql query

    - by rupeshmalviya
    could somebody correct my following query, i am novice to software development realm, i am to a string builder object in comma separated form to my query but it's not producing desired result qyery is as follows and string cmd = "SELECT * FROM [placed_student] WHERE passout_year=@passout AND company_id=@companyId AND course_id=@courseId AND branch_id IN('" + sb + "')"; StringBuilder sb = new StringBuilder(); foreach (ListItem li in branch.Items) { if (li.Selected == true) { sb.Append(Convert.ToInt32(li.Value) +", "); } } li is integer value of my check box list which are getting generated may be differne at different time ...please also suggest me some good source to learn sql..

    Read the article

< Previous Page | 433 434 435 436 437 438 439 440 441 442 443 444  | Next Page >