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  • Getting the number of fragments which passed the depth test

    - by Etan
    In "modern" environments, the "NV Occlusion Query" extension provides a method to get the number of fragments which passed the depth test. However, on the iPad / iPhone using OpenGL ES, the extension is not available. What is the most performant approach to implement a similar behaviour in the fragment shader? Some of my ideas: Render the object completely in white, then count all the colors together using a two-pass shader where first a vertical line is rendered and for each fragment the shader computes the sum over the whole row. Then, a single vertex is rendered whose fragment sums all the partial sums of the first pass. Doesn't seem to be very efficient. Render the object completely in white over a black background. Downsample recursively, abusing the hardware linear interpolation between textures until being at a reasonably small resolution. This leads to fragments which have a greyscale level depending on the number of white pixels where in their corresponding region. Is this even accurate enough? Use mipmaps and simply read the pixel on the 1x1 level. Again the question of accuracy and if it is even possible using non-power-of-two textures. The problem wit these approaches is, that the pipeline gets stalled which results in major performance issues. Therefore, I'm looking for a more performant way to accomplish my goal. Using the EXT_OCCLUSION_QUERY_BOOLEAN extension Apple introduced EXT_OCCLUSION_QUERY_BOOLEAN in iOS 5.0 for iPad 2. "4.1.6 Occlusion Queries Occlusion queries use query objects to track the number of fragments or samples that pass the depth test. An occlusion query can be started and finished by calling BeginQueryEXT and EndQueryEXT, respectively, with a target of ANY_SAMPLES_PASSED_EXT or ANY_SAMPLES_PASSED_CONSERVATIVE_EXT. When an occlusion query is started with the target ANY_SAMPLES_PASSED_EXT, the samples-boolean state maintained by the GL is set to FALSE. While that occlusion query is active, the samples-boolean state is set to TRUE if any fragment or sample passes the depth test. When the occlusion query finishes, the samples-boolean state of FALSE or TRUE is written to the corresponding query object as the query result value, and the query result for that object is marked as available. If the target of the query is ANY_SAMPLES_PASSED_CONSERVATIVE_EXT, an implementation may choose to use a less precise version of the test which can additionally set the samples-boolean state to TRUE in some other implementation dependent cases." The first sentence hints on a behavior which is exactly what I'm looking for: getting the number of pixels which passed the depth test in an asynchronous manner without much performance loss. However, the rest of the document describes only how to get boolean results. Is it possible to exploit this extension to get the pixel count? Does the hardware support it so that there may be hidden API to get access to the pixel count? Other extensions which could be exploitable would be debugging features like the number of times the fragment shader was invoked (PSInvocations in DirectX - not sure if something simila is available in OpenGL ES). However, this would also result in a pipeline stall.

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  • Split vector vs matrix notation for transformation

    - by seahorse
    Some rendering engines like Ogre prefer to use a individual vector based notation for transformations like the following Split vector notation: Net Transformation is represented by Scale vector = sx, sy, sz Transformation vector = tx, ty, tz Rotation Quaternion Vector = w,x,y,z Matrix notation: There are other engines which simply use a net combined transformation matrix. What are the advantages of the first notation over the second? Also for animation interpolation does it work in the first notation that we interpolate across the individual components and use the interpolated parts to get the net transformation? Is this another advantage?

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  • How do I generate a level randomly?

    - by Charlton Santana
    I am currently hard coding 10 different instances like the code below, but but I'd like to create many more. Instead of having the same layout for the new level, I was wondering if there is anyway to generate a random X value for each block (this will be how far into the level it is). A level 100,000 pixels wide would be good enough but if anyone knows a system to make the level go on and on, I'd like to know that too. This is basically how I define a block now (with irrelevant code removed): block = new Block(R.drawable.block, 400, platformheight); block2 = new Block(R.drawable.block, 600, platformheight); block3 = new Block(R.drawable.block, 750, platformheight); The 400 is the X position, which I'd like to place randomly through the level, the platformheight variable defines the Y position which I don't want to change.

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  • How do you properly organize a commercial game?

    - by Reactorcore
    For the past months I've been studying programming and I've finally learned how to code, but one thing that is confusing me is how to properly organize the design of a game project - code wise. The game I'm building is a pretty standard commercial game. It has the basic components of a normal game: A world, characters and items interacting with each other and all of this is run by game manager. Basically you play as a hero in a world and do stuff. Fight, explore and interact. Think of your standard adventure game that starts off with an intro, goes to the menu system, then gets into the game and back to the menu. Pretty much like 99% of any commercial game or otherwise serious game projects. Thats what I'm aiming at. The problem is: How do you properly code a commercial game architecture? How do you organize it? How do you make it not become unmaintainable spaghetti code? What specific things to keep in mind when building this, codewise? How you can help me: a) Please tell how do you code your own game projects. What is your thought-process when designing the architecture? b) Recommend books, blogs, tutorials, videos or anything else on how to organize a commercial video game. c) Give hints and tips on do's/don'ts when building a game, codewise. Please help!

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  • Flickering when accessing texture by offset

    - by TravisG
    I have this simple compute shader that basically just takes the input from one image and writes it to another. Both images are 128/128/128 in size and glDispatchCompute is called with (128/8,128/8,128/8). The source images are cleared to 0 before this compute shader is executed, so no undefined values should be floating around in there. (I have the appropriate memory barrier on the C++ side set before the 3D texture is accessed). This version works fine: #version 430 layout (location = 0, rgba16f) uniform image3D ping; layout (location = 1, rgba16f) uniform image3D pong; layout (local_size_x = 8, local_size_y = 8, local_size_z = 8) in; void main() { ivec3 sampleCoord = gl_GlobalInvocationID.xyz; imageStore(pong, imageLoad(ping,sampleCoord)); } Reading values from pong shows that it's just a copy, as intended. However, when I load data from ping with an offset: #version 430 layout (location = 0, rgba16f) uniform image3D ping; layout (location = 1, rgba16f) uniform image3D pong; layout (local_size_x = 8, local_size_y = 8, local_size_z = 8) in; void main() { ivec3 sampleCoord = gl_GlobalInvocationID.xyz; imageStore(pong, imageLoad(ping,sampleCoord+ivec3(1,0,0))); } The data that is written to pong seems to depend on the order of execution of the threads within the work groups, which makes no sense to me. When reading from the pong texture, visible flickering occurs in some spots on the texture. What am I doing wrong here?

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  • Creating practically solvable 15 puzzle inputs

    - by Ashwin
    I am now developing a 15 puzzle game. I know the method to detect unsolvable puzzles. But unlike 8-puzzle, solution for 15-puzzle takes quite long time for some input states and can be solved within 5 seconds some other set of input states. Now the problem is that I cannot give the user(the player), a problem for which the solution takes more than 10 seconds(if he/she chooses to see the solution). So what I want is that when I initially shuffle the puzzle, I want to only present those puzzles which can be solved within 10 seconds. There must be some way to determine the hardness of the puzzle. I tried searching the net but could not find it. Does anyone know a way of determining the hardness of a puzzle? NOTE : I am using A* algorithm to find out the solution on a computer with 3GB RAM and 2.27GHZ processor.

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  • Sprites, Primitives and logic entity as structs

    - by Jeffrey
    I'm wondering would it be considered acceptable: The window class is responsible for drawing data, so it will have a method: Window::draw(const Sprite&); Window::draw(const Rect&); Window::draw(const Triangle&); Window::draw(const Circle&); and all those primitives + sprites would be just public struct. For example Sprite: struct Sprite { float x, y; // center float origin_x, origin_y; float width, height; float rotation; float scaling; GLuint texture; Sprite(float w, float h); Sprite(float w, float h, float a, float b); void useTexture(std::string file); void setOrigin(float a, float b); void move(float a, float b); // relative move void moveTo(float a, float b); // absolute move void rotate(float a); // relative rotation void rotateTo(float a); // absolute rotation void rotationReset(); void scale(float a); // relative scaling void scaleTo(float a); // absolute scaling void scaleReset(); }; So instead of having each primitive to call their draw() function, which is a little bit off topic for their object, I let the Window class handle all the OpenGL stuff and manipulate them as simple objects that will be drawn later on. Is this pattern used? Does it have any cons against it's primitives-draw-themself pattern? Are there any other related patterns?

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  • How to control a spaceship near a planet in Unity3D?

    - by tyjkenn
    Right now I have spaceship orbiting a small planet. I'm trying to make an effective control system for that spaceship, but it always end up spinning out of control. After spinning the ship to change direction, the thrusters thrust the wrong way. Normal airplane controls don't work, since the ship is able to leave the atmosphere and go to other planets, in the journey going "upside-down". Could someone please enlighten me on how to get thrusters to work the way they are supposed to?

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  • In a 2D platform game, how to ensure the player moves smoothly over sloping ground?

    - by Kovsa
    See image: http://i41.tinypic.com/huis13.jpg I'm developing a physics engine for a 2D platform game. I'm using the separating axis theorem for collision detection. The ground surface is constructed from oriented bounding boxes, with the player as an axis aligned bounding box. (Specifically, I'm using the algorithm from the book "Realtime Collision Detection" which performs swept collision detection for OBBs using SAT). I'm using a fairly small (close to zero) restitution coefficient in the collision response, to ensure that the dynamic objects don't penetrate the environment. The engine mostly works fine, it's just that I'm concerned about some edge cases that could possibly occur. For example, in the diagram, A, B and C are the ground surface. The player is heading left along B towards A. It seems to me that due to inaccuracy, the player box could be slightly below the box B as it continues up and left. When it reaches A, therefore, the bottom left corner of the player might then collide with the right side of A, which would be undesirable (as the intention is for the player to move smoothly over the top of A). It seems like a similar problem could happen when the player is on top of box C, moving left towards B - the most extreme point of B could collide with the left side of the player, instead of the player's bottom left corner sliding up and left above B. Box2D seems to handle this problem by storing connectivity information for its edge shapes, but I'm not really sure how it uses this information to solve the problem, and after looking at the code I don't really grasp what it's doing. Any suggestions would be greatly appreciated.

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  • Android Live Testing

    - by Matthew Dockerty
    I am making a game for android and in it I am using sensors which are not available in the emulator. At the moment I am connecting my device and transferring the apk, then installing to test but that is a pain to do, and I have gotten to the stage where I need to start logging values for debugging. I have gone into the run configs of my app and set it to prompt me to pick a device, but my device is never in the list when it is connected to my PC and I try to run it. How am I supposed to set it up to work properly? Thanks for the help.

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  • Repeat a part of spritesheet as background

    - by Moiblpadde
    So I'm trying to repeat a part of my spritesheet as a background (js, canvas). My code so far: var canvas = $("#board")[0], ctx = canvas.getContext("2d"), sprite = new Image(); sprite.src = "spritesheet.png"; sprite.onload = function(){ ctx.fillStyle = ctx.createPattern(spriteBg, "repeat"); ctx.fillRect(0, 25, 500, 500); } This is fine, but as you can see, it repeat the whole sprite, not just a part of it, and I just can't figure out how to do it D:

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  • Unity Occlusion Portals: What and How?

    - by Nick Wiggill
    (Here I eat my words on Meta about posting Unity questions on Unity Answers... since that site is less responsive than this one.) Unity provides cell-based Occlusion Culling (via Umbra, I believe). However, a newer feature that it supports is Occlusion Portals. The question is, if BSP-based occlusion culling is already a feature of Unity, what do portals add, and how? PS. This question is not "What are portals?" -- I'm aware of the original Quake BSP-style portals -- which is partly why I find the explicit portal concept in Unity odd, since it uses BSP anyway.

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  • How can I save state from script in a multithreaded engine?

    - by Peter Ren
    We are building a multithreaded game engine and we've encountered some problems as described below. The engine have 3 threads in total: script, render, and audio. Each frame, we update these 3 threads simultaneously. As these threads updating themselves, they produce some tasks and put them into a public storage area. As all the threads finish their update, each thread go and copy the tasks for themselves one by one. After all the threads finish their task copying, we make the threads process those tasks and update these threads simultaneously as described before. So this is the general idea of the task schedule part of our engine. Ok, well, all the task schedule part work well, but here's the problem: For the simplest, I'll take Camera as an example: local oldPos = camera:getPosition() -- ( 0, 0, 0 ) camera:setPosition( 1, 1, 1 ) -- Won't work now, cuz the render thread will process the task at the beginning of the next frame local newPos = camera:getPosition() -- Still ( 0, 0, 0 ) So that's the problem: If you intend to change a property of an object in another thread, you have to wait until that thread process this property-changing message. As a result, what you get from the object is still the information in the last frame. So, is there a way to solve this problem? Or are we build the task schedule part in a wrong way? Thanks for your answers :)

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  • Slick2d Spritesheet showing whole image

    - by BotskoNet
    I'm trying to show a single subimage from a sprite sheet. Using slick2d SpriteSheet class, all it's doing is showing me the entire image, but scaled down to fit the cell dimensions. The image is 96x192 and should have cells of 32x32. The code: SpriteSheet spriteSheet = new SpriteSheet("images/"+file, 32, 32 ); System.out.println("Horiz Count: " + spriteSheet.getHorizontalCount()); System.out.println("Vert Count: " + spriteSheet.getVerticalCount()); System.out.println("Height: " + spriteSheet.getHeight()); System.out.println("Width: " + spriteSheet.getWidth()); System.out.println("Texture Width: " + spriteSheet.getTextureWidth()); System.out.println("Texture Height: " + spriteSheet.getTextureHeight()); Prints: Horiz Count: 3 Vert Count: 6 Height: 192 Width: 96 Texture Width: 0.75 Texture Height: 0.75 Not sure what the texture dimensions refer to, but the rest is entirely accurate. However, when I draw the icon, the entire sprite image shows scaled down to 32x32: Image image = spriteSheet.getSprite(1, 0); // a test image.bind(); GL11.glEnable(GL11.GL_BLEND); GL11.glBlendFunc(GL11.GL_SRC_ALPHA, GL11.GL_ONE_MINUS_SRC_ALPHA); GL11.glBegin(GL11.GL_QUADS); GL11.glTexCoord2f(0,0); GL11.glVertex2f(x,y); GL11.glTexCoord2f(1,0); GL11.glVertex2f(x+image.getWidth(),y); GL11.glTexCoord2f(1,1); GL11.glVertex2f(x+image.getWidth(),y+image.getHeight()); GL11.glTexCoord2f(0,1); GL11.glVertex2f(x,y+image.getHeight()); GL11.glEnd(); GL11.glDisable(GL11.GL_BLEND);

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  • what making a good soundtrack for social game

    - by Maged
    there are many successful social games in Facebook and other social sites like brain buddies, who has the biggest brain and word challenge.both of them have a great soundtrack while playing and in the beginning of the game . my question is how to find a good soundtrack or what's i should look for to find a good soundtrack like this that's help to attract the user specially for games that need concentration ?

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  • How do I draw anti-aliased holes in a bitmap

    - by gyozo kudor
    I have an artillery game (hobby-learning project) and when the projectile hits it leaves a hole in the ground. I want this hole to have antialiased edges. I'm using System.Drawing for this. I've tried with clipping paths, and drawing with a transparent color using gfx.CompositingMode = CompositingMode.SourceCopy, but it gives me the same result. If I draw a circle with a solid color it works fine, but I need a hole, a circle with 0 alpha values. I have enabled these but they work only with solid colors: gfx.CompositingQuality = CompositingQuality.HighQuality; gfx.InterpolationMode = InterpolationMode.HighQualityBicubic; gfx.SmoothingMode = SmoothingMode.AntiAlias; In the two pictures consider black as being transparent. This is what I have (zoomed in): And what I need is something like this (made with photoshop): This will be just a visual effect, in code for collision detection I still treat everything with alpha 128 as solid. Edit: I'm usink OpenTK for this game. But for this question I think it doesn't really matter probably it is gdi+ related.

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  • Html 5 ping pong game side collision problem

    - by Gurjit
    I am making a simple ping pong game where I am facing a side collision problem means when the ball collides with the either side of the paddle . Although I have written code for making it works but something is failing....I want plz someone to give suggestions and tell how to avoid it. Means while trying to hit the ball with side face of the paddle poses a problem.!! Here is the main part of the code causing problem function checkCollision(){ ///// This is collision detection for the upper part ///// if( cy + radius >= paddleTop && cx + radius > paddleLeft && cy + radius >= paddleTop + 5 && cx - radius <= paddleLeft + paddleWidth ) { dy = -dy; ++hits; /// On collision we are increasing the Score playSound(); } else if( cy + radius >= paddleTop && cy + radius <= paddleTop + paddleHeight && cx + radius >= paddleLeft && cy - radius <= paddleLeft - (radius + 1) ) { dx = -dx; } } here is working fiddle for it :- http://jsfiddle.net/gurjitmehta/orzpzf69/

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  • Rotate canvas along its center based on user touch - Android

    - by Ganapathy
    I want to rotate the canvas circularly on its center axis based on user touch. i want to rotate based on center but its rotating based on top left corner . so i am able to see only 1/4 for rotation of image. any idea.. Like a old phone dialer . I have tried like as follows onDraw(Canvas canvas){ canvas.save(); // do my rotation canvas.rotate(rotation,0,0); canvas.drawBitmap( ((BitmapDrawable)d).getBitmap(),0,0,p ); canvas.restore(); } @Override public boolean onTouchEvent(MotionEvent e) { float x = e.getX(); float y = e.getY(); updateRotation(x,y); mPreviousX = x; mPreviousY = y; invalidate(); } private void updateRotation(float x, float y) { double r = Math.atan2(x - centerX, centerY - y); rotation = (int) Math.toDegrees(r); }

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  • XNA 4.0 SpriteFont not displaying all Characters

    - by Iain Brown
    Am looking for a little help and trying to use SpriteFont in my XNA 4.0 game but the problem is am displaying to string "This is a test" but all that's displayed on the screen is "This is st" so the "a te" are missing from the screen. The space is there for the characters but the letters are not. The code am using is: spriteBatch.Begin(SpriteSortMode.BackToFront, BlendState.AlphaBlend); spriteBatch.DrawString(font,"this is a test",new Vector2(692,372),Color.White); spriteBatch.Draw(texture,new Rectangle(0,0,100,100),Color.White); spriteBatch.End(); Any help with this would be great!

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  • Bouncing off a circular Boundary with multiple balls?

    - by Anarkie
    I am making a game like this : Yellow Smiley has to escape from red smileys, when yellow smiley hits the boundary game is over, when red smileys hit the boundary they should bounce back with the same angle they came, like shown below: Every 10 seconds a new red smiley comes in the big circle, when red smiley hits yellow, game is over, speed and starting angle of red smileys should be random. I control the yellow smiley with arrow keys. The biggest problem I have reflecting the red smileys from the boundary with the angle they came. I don't know how I can give a starting angle to a red smiley and bouncing it with the angle it came. I would be glad for any tips! My js source code : var canvas = document.getElementById("mycanvas"); var ctx = canvas.getContext("2d"); // Object containing some global Smiley properties. var SmileyApp = { radius: 15, xspeed: 0, yspeed: 0, xpos:200, // x-position of smiley ypos: 200 // y-position of smiley }; var SmileyRed = { radius: 15, xspeed: 0, yspeed: 0, xpos:350, // x-position of smiley ypos: 65 // y-position of smiley }; var SmileyReds = new Array(); for (var i=0; i<5; i++){ SmileyReds[i] = { radius: 15, xspeed: 0, yspeed: 0, xpos:350, // x-position of smiley ypos: 67 // y-position of smiley }; SmileyReds[i].xspeed = Math.floor((Math.random()*50)+1); SmileyReds[i].yspeed = Math.floor((Math.random()*50)+1); } function drawBigCircle() { var centerX = canvas.width / 2; var centerY = canvas.height / 2; var radiusBig = 300; ctx.beginPath(); ctx.arc(centerX, centerY, radiusBig, 0, 2 * Math.PI, false); // context.fillStyle = 'green'; // context.fill(); ctx.lineWidth = 5; // context.strokeStyle = '#003300'; // green ctx.stroke(); } function lineDistance( positionx, positiony ) { var xs = 0; var ys = 0; xs = positionx - 350; xs = xs * xs; ys = positiony - 350; ys = ys * ys; return Math.sqrt( xs + ys ); } function drawSmiley(x,y,r) { // outer border ctx.lineWidth = 3; ctx.beginPath(); ctx.arc(x,y,r, 0, 2*Math.PI); //red ctx.fillStyle="rgba(255,0,0, 0.5)"; ctx.fillStyle="rgba(255,255,0, 0.5)"; ctx.fill(); ctx.stroke(); // mouth ctx.beginPath(); ctx.moveTo(x+0.7*r, y); ctx.arc(x,y,0.7*r, 0, Math.PI, false); // eyes var reye = r/10; var f = 0.4; ctx.moveTo(x+f*r, y-f*r); ctx.arc(x+f*r-reye, y-f*r, reye, 0, 2*Math.PI); ctx.moveTo(x-f*r, y-f*r); ctx.arc(x-f*r+reye, y-f*r, reye, -Math.PI, Math.PI); // nose ctx.moveTo(x,y); ctx.lineTo(x, y-r/2); ctx.lineWidth = 1; ctx.stroke(); } function drawSmileyRed(x,y,r) { // outer border ctx.lineWidth = 3; ctx.beginPath(); ctx.arc(x,y,r, 0, 2*Math.PI); //red ctx.fillStyle="rgba(255,0,0, 0.5)"; //yellow ctx.fillStyle="rgba(255,255,0, 0.5)"; ctx.fill(); ctx.stroke(); // mouth ctx.beginPath(); ctx.moveTo(x+0.4*r, y+10); ctx.arc(x,y+10,0.4*r, 0, Math.PI, true); // eyes var reye = r/10; var f = 0.4; ctx.moveTo(x+f*r, y-f*r); ctx.arc(x+f*r-reye, y-f*r, reye, 0, 2*Math.PI); ctx.moveTo(x-f*r, y-f*r); ctx.arc(x-f*r+reye, y-f*r, reye, -Math.PI, Math.PI); // nose ctx.moveTo(x,y); ctx.lineTo(x, y-r/2); ctx.lineWidth = 1; ctx.stroke(); } // --- Animation of smiley moving with constant speed and bounce back at edges of canvas --- var tprev = 0; // this is used to calculate the time step between two successive calls of run function run(t) { requestAnimationFrame(run); if (t === undefined) { t=0; } var h = t - tprev; // time step tprev = t; SmileyApp.xpos += SmileyApp.xspeed * h/1000; // update position according to constant speed SmileyApp.ypos += SmileyApp.yspeed * h/1000; // update position according to constant speed for (var i=0; i<SmileyReds.length; i++){ SmileyReds[i].xpos += SmileyReds[i].xspeed * h/1000; // update position according to constant speed SmileyReds[i].ypos += SmileyReds[i].yspeed * h/1000; // update position according to constant speed } // change speed direction if smiley hits canvas edges if (lineDistance(SmileyApp.xpos, SmileyApp.ypos) + SmileyApp.radius > 300) { alert("Game Over"); } // redraw smiley at new position ctx.clearRect(0,0,canvas.height, canvas.width); drawBigCircle(); drawSmiley(SmileyApp.xpos, SmileyApp.ypos, SmileyApp.radius); for (var i=0; i<SmileyReds.length; i++){ drawSmileyRed(SmileyReds[i].xpos, SmileyReds[i].ypos, SmileyReds[i].radius); } } // uncomment these two lines to get every going // SmileyApp.speed = 100; run(); // --- Control smiley motion with left/right arrow keys function arrowkeyCB(event) { event.preventDefault(); if (event.keyCode === 37) { // left arrow SmileyApp.xspeed = -100; SmileyApp.yspeed = 0; } else if (event.keyCode === 39) { // right arrow SmileyApp.xspeed = 100; SmileyApp.yspeed = 0; } else if (event.keyCode === 38) { // up arrow SmileyApp.yspeed = -100; SmileyApp.xspeed = 0; } else if (event.keyCode === 40) { // right arrow SmileyApp.yspeed = 100; SmileyApp.xspeed = 0; } } document.addEventListener('keydown', arrowkeyCB, true); JSFiddle : http://jsfiddle.net/gj4Q7/

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  • How do I properly use multithreading with Nvidia PhysX?

    - by xcrypt
    I'm having a multithreading problem with Nvidia PhysX. the SDK requires that you call Simulate() (starts computing new physics positions within a new thread) and FetchResults() (waits 'till the physics computations are done). Inbetween Simulate() and FetchResults() you may not "compute new physics". It is proposed (in a sample) that we create a game loop as such: Logic (you may calculate physics here and other stuff) Render + Simulate() at start of Render call and FetchResults at end of Render() call However, this has given me various little errors that stack up: since you actually render the scene that was computed in the previous iteration in the game loop. Does anyone have a solution to this?

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  • How to determine the end of list has been reached?

    - by Sweta Dwivedi
    I'm trying to animate my object according to a set of recorded values from kinect skeleton stream by saving the (x,y,z) stream from the skeletal data into a list and then set my objects x and y position from the x,y of the list. However, once the list end has been reached it starts to animate again from the start. I don't want that - I just want the model position to keep going in the positive X direction. Is there any way I can check if end of the list has been reached and to just update the model position in x direction? Or is there any other way to continue moving my sprite once the points in the list are over... i dont want it to start animating all the way again.. protected override void Update(GameTime gameTime) { //position += spriteSpeed * (float)gameTime.ElapsedGameTime.TotalSeconds; //// TODO: Add your update logic here using (StreamReader r = new StreamReader(f)) { string line; Viewport view = graphics.GraphicsDevice.Viewport; int maxWidth = view.Width; int maxHeight = view.Height; while((line = r.ReadLine()) != null) { string[] temp = line.Split(','); int x = (int) Math.Floor(((float.Parse(temp[0]) * 0.5f) + 0.5f) * maxWidth); int y = (int) Math.Floor(((float.Parse(temp[1]) * -0.5f) + 0.5f) * maxHeight); motion_2.Add(new Point(x, y)); } } position.X = motion_2[i].X; position.Y = motion_2[i].Y; i++; a_butterfly_up.Update(gameTime); a_butterfly_side.Update(gameTime); G_vidPlayer.Play(mossV); base.Update(gameTime); }

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  • How can I implement an Iris Wipe effect?

    - by Vandell
    For those who doesn't know: An iris wipe is a wipe that takes the shape of a growing or shrinking circle. It has been frequently used in animated short subjects, such as those in the Looney Tunes and Merrie Melodies cartoon series, to signify the end of a story. When used in this manner, the iris wipe may be centered around a certain focal point and may be used as a device for a "parting shot" joke, a fourth wall-breaching wink by a character, or other purposes. Example from flasheff.com Your answer may or may not include a coding sample, a language agnostic explanation is considered enough.

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  • Can SpriteBatch be used to fill a polygon with a texture?

    - by can poyrazoglu
    I basically need to fill a texture into a polygon using the SpriteBatch. I've done some research but couldn't find anything useful except polygon triangulation method, which works well only with convex polygons (without diving into super math which is definitely not something I'm pretty good at). Are there any solutions for filling in a polygon in a basic way? I of course need something dynamic (I'll have a map editor that you can define polygons, and the game will render them (and collision detection will also use them but that's off topic), basically I can't accept solutions like "pre-calculated" bitmaps or anything like that. I need to draw a polygon with the segments provided, to the screen, using the SpriteBatch.

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  • Is there any advantage in using DX10/11 for a 2D game?

    - by David Gouveia
    I'm not entirely familiar with the feature set introduced by DX10/11 class hardware. I'm vaguely familiar with the new stages added to the programmable graphics pipeline, such as the geometry shader, the compute shader, and the new tesselation stages. I don't see how any of these make much of a difference for a 2D game though. Is there any compelling reason to make the switch to DX10/11 (or the OpenGL equivalents) for a 2D game, or would it be wiser to stick with DX9 considering that that a significant share of the market still runs on older technologies (e.g. the February 2012 Steam surveys lists around 17% of users as still using Windows XP)?

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