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• Yum lock file problem

  - by David Reynolds

  When there are more than 1 copies of yum running, I get this error: Another app is currently holding the yum lock; waiting for it to exit Is there a way to make yum just exit the first time it can't get the lock rather than stay open waiting for it?

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• I've been a big fan of Revo Uninstaller for years now, but just upgraded to Windows 7 and saw that i

  - by NoCatharsis

  Can I still use Revo Uninstaller with Windows 7 64-bit? I saw on the Revo site that this is not necessarily supported, so I don't want to have it messing with my registry without getting some advice first. If not Revo, what is the best way to uninstall in Windows 7?

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• Untrusted Location

  - by Scott Jackson

  Hi, I've recently switched to roaming profiles in an XP and Windows 7 environment and also changed the login script. Can anyone tell me where I would find the info regarding messages that appear when people are launching various in-house apps : This program is from an untrusted location, Click Run or Cancel. The programs run but users need to click 'Run' first. Thanks Scott

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• Acrobat Reader 9 Crashes Every Time

  - by Jess Sightler

  I have an XP machine on which Adobe Acrobat Reader crashes every time as soon as it starts. I've tried reinstalling 9 and it doesn't help at all. If I use it to open a PDF, it displays the first page, and can be scrolled for about 3 seconds before it crashes. Is there some way to debug this?

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• Linux: shortname stuck as "localhost" even though full hostname is correct

  - by DrStalker

  I have a linux (CentOS 5.2) server with the name myserver.mycompnay.com, which is correctly returned when I run 'hostname'. When I run 'hostname -s' however it returns "localhost" which is causing some backup scripts to put stuff in a "localhost" directory instead of a "myserver" directory. All of our other CentOS boxes correctly return the first part of their hostname when 'hostname -s', where do I go on this server to make it behave the same? Other than having "HOSTNAME=myserver.mycompnay.com" in /etc/sysconfig/network what should I be looking at?

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• Ping to IP address returned Destination Unreachable for a different IP address... huh?

  - by Hafthor

  This was totally an isolated incident, but I performed this command: ping 192.168.1.134 and got this result [image]: Pinging 192.168.1.134 with 32 bytes of data: Reply from 192.168.1.133: Destination host unreachable. Reply from 192.168.1.134: bytes=32 time=75ms TTL=128 Reply from 192.168.1.134: bytes=32 time=83ms TTL=128 Reply from 192.168.1.134: bytes=32 time=96ms TTL=128 note the .133 in the first 'unreachable' reply. I guess I don't understand how this is possible - even given a totally crazy coincidence.

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• How to get predecessor and successors from an adjacency matrix

  - by NickTFried

  Hi I am am trying to complete an assignment, where it is ok to consult the online community. I have to create a graph class that ultimately can do Breadth First Search and Depth First Search. I have been able to implement those algorithms successfully however another requirement is to be able to get the successors and predecessors and detect if two vertices are either predecessors or successors for each other. I'm having trouble thinking of a way to do this. I will post my code below, if anyone has any suggestions it would be greatly appreciated. import java.util.ArrayList; import java.util.Iterator; import java.util.LinkedList; import java.util.Queue; import java.util.Stack; public class Graph<T> { public Vertex<T> root; public ArrayList<Vertex<T>> vertices=new ArrayList<Vertex<T>>(); public int[][] adjMatrix; int size; private ArrayList<Vertex<T>> dfsArrList; private ArrayList<Vertex<T>> bfsArrList; public void setRootVertex(Vertex<T> n) { this.root=n; } public Vertex<T> getRootVertex() { return this.root; } public void addVertex(Vertex<T> n) { vertices.add(n); } public void removeVertex(int loc){ vertices.remove(loc); } public void addEdge(Vertex<T> start,Vertex<T> end) { if(adjMatrix==null) { size=vertices.size(); adjMatrix=new int[size][size]; } int startIndex=vertices.indexOf(start); int endIndex=vertices.indexOf(end); adjMatrix[startIndex][endIndex]=1; adjMatrix[endIndex][startIndex]=1; } public void removeEdge(Vertex<T> v1, Vertex<T> v2){ int startIndex=vertices.indexOf(v1); int endIndex=vertices.indexOf(v2); adjMatrix[startIndex][endIndex]=1; adjMatrix[endIndex][startIndex]=1; } public int countVertices(){ int ver = vertices.size(); return ver; } /* public boolean isPredecessor( Vertex<T> a, Vertex<T> b){ for() return true; }*/ /* public boolean isSuccessor( Vertex<T> a, Vertex<T> b){ for() return true; }*/ public void getSuccessors(Vertex<T> v1){ } public void getPredessors(Vertex<T> v1){ } private Vertex<T> getUnvisitedChildNode(Vertex<T> n) { int index=vertices.indexOf(n); int j=0; while(j<size) { if(adjMatrix[index][j]==1 && vertices.get(j).visited==false) { return vertices.get(j); } j++; } return null; } public Iterator<Vertex<T>> bfs() { Queue<Vertex<T>> q=new LinkedList<Vertex<T>>(); q.add(this.root); printVertex(this.root); root.visited=true; while(!q.isEmpty()) { Vertex<T> n=q.remove(); Vertex<T> child=null; while((child=getUnvisitedChildNode(n))!=null) { child.visited=true; bfsArrList.add(child); q.add(child); } } clearVertices(); return bfsArrList.iterator(); } public Iterator<Vertex<T>> dfs() { Stack<Vertex<T>> s=new Stack<Vertex<T>>(); s.push(this.root); root.visited=true; printVertex(root); while(!s.isEmpty()) { Vertex<T> n=s.peek(); Vertex<T> child=getUnvisitedChildNode(n); if(child!=null) { child.visited=true; dfsArrList.add(child); s.push(child); } else { s.pop(); } } clearVertices(); return dfsArrList.iterator(); } private void clearVertices() { int i=0; while(i<size) { Vertex<T> n=vertices.get(i); n.visited=false; i++; } } private void printVertex(Vertex<T> n) { System.out.print(n.label+" "); } }

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• Does mailx send mail using an SMTP relay or does it directly connect to the target SMTP server?

  - by iamrohitbanga

  Suppose i send a mail using the following the following command: mailx [email protected] then does mailx first try to find out the SMTP server of my ISP for relaying the mail or does it connect directly. Does it depend on whether my PC has a public IP address or it is behind a NAT. How do I check the settings of mailx on my PC? How can I verify this using tcpdump?

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• Xubuntu 9.10 LiveCD on USB fails with error can't open /dev/sr0: no medium found

  - by EricJLN

  Using Ubuntu's USB Startup Disk Creator (usb-creator-gtk), I created a LiveUSB from the Xubuntu 9.10 LiveCD. When booting, it stalls up with the Xubuntu mouse splash screen displayed. In attempting to troubleshoot, I used Ctrl-Alt-F1 to check out the first virtual terminal. On that screen, I see over and over again the lines: stdin: I/O error stdin: error 0 /init: line 1: can't open /dev/sr0: No medium found

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• Hooking up my power switch/reset switch/LEDs

  - by David Oneill

  I'm working on building a computer (first time for me). There are several plugs that I need to connect to the motherboard (Power LED, reset switch, etc). Of the two wires, they are either: Color and white (reset switch, power LED, HDD LED) red and black (speaker, power switch) The manual for the motherboard has a nice diagram of where to plug them in, but has them labeled + or -. Which colors are positive, and which are negative?

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• How do I make mailto: links open gmail in Ubuntu?

  - by Matthew

  I've tried using this How-To Geek guide, but it doesn't work. Running the script from the terminal works (although I had to change its permissions first), but clicking on a mailto: link does nothing. Note: I am using the Chromium Daily Builds for my browser. I would mailto: links in all applications to point to gmail, not just the ones that I click on in my browser.

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• Telnet disconnected on login failure

  - by LinuxPenseur

  Hi, I have two servers running Linux 2.6.9 kernel. When i telnet to server1 , the telnet will be disconnected only after 3 login failures. While, when i telnet to server2, telnet will be disconnected after the first login failure. I expect server2 to behave the same way as server1 when telnet is executed. Kindly tell me where i should tweak my servers so that i could achieve what i expect. Thanks, LinuxPenseur

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• Is it advisable to use multiple ReadyBoost flash drives?

  - by ymasood

  I am a fan of ReadyBoost and have seen good results using it with my work laptop. I tried something today and connected a second flash drive (2GB) and configured it for use with ReadyBoost. The first is an 8GB configured with 4GB for ReadyBoost. I'm using Windows 7 RC 7100 and was wondering if using more than one ReadyBoost drive helps?

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• git clone is blank from a Gitosis Served Repository

  - by mykeus

  Everything is working fine with my public keys and repository activity but when one of my team members tries to clone a repository, the clone is blank, example output: bry4n@~/tests$ git clone [email protected]:tg/base.git bry4n@~/tests$ At first, It was giving the typical no read access error. Then i stripped out alot of the junk out of the configuration then he started only getting the output above.

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• adding many points to a personalized google map

  - by Tal Galili

  Hi all, I wish to create a personalized google map (as is shown here), I see it is possible to import a geo file (KML, KMZ or GeoRSS) with many points. I would love to use that but don't know how to create such a geo file in the first place. Which one should I use? What is the best way to create them? Thanks.

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• Exchange 2003 Offline Defrag

  - by Tom

  Looking to do my first offline defrag this weekend on Exchange 2003. Our Exchange DB is on E drive and server1 is the temporary location where there is sufficient space. Dismount the store and change to c:\program files\exchsrvr\bin Does this look like the correct command to run? eseutil /d "e:\exchdata\priv1.edb /t"\\server1\exchtemp\tempdfg.edb" Is there anything I should be aware of such as backups running at the same time etc?

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• XP Suddenly asking for password

  - by ProfKaos

  Is there any sane explanation for a client's Acer Aspire 1 netbook, running XP Home SP 2, suddenly starting to ask for a login password at boot? He has a strict policy of not using passwords, and I removed his login password weeks ago. The story is that suddenly this morning, for the first time, it is asking for a login password.

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• XP Suddenly asking for password

  - by ProfKaos

  Is there any sane explanation for a client's Acer Aspire 1 netbook, running XP Home SP 2, suddenly starting to ask for a login password at boot? He has a strict policy of not using passwords, and I removed his login password weeks ago. The story is that suddenly this morning, for the first time, it is asking for a login password.

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• How can I quickly access the Microsoft Word zoom setting?

  - by nevan

  I get a lot of Word documents to work on, and the first thing I always do is access the zoom setting (View- Zoom) and change the zoom to "Page Width". There's no keyboard shortcut for the zoom settings, and I do it enough times that I'd like a quicker way. In Pages, there's a little pop-up that lets you choose the zoom you want. Is there a way to quickly change the zoom settings in Word? Thanks.

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• Using a pre-existing function for a new row

  - by Jonathan Kushner

  I have an Excel document that contains X columns and N number of rows. The very last column of a row performs a SUM of the first X-1 columns. The problem I have is, the user of this Excel document progressively adds rows to the document, and because of this, the function does not exist yet in the last column for new rows. I need a way to have this function exist in new rows dynamically (the user is not Excel-savvy and doesn't have the ability to just drag the function down a row).

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• Google Chrome on Mac OS X, full screen option is greyed out, why?

  - by Chris Kimpton

  When I first installed Chrome the menu option for "full screen" was enabled and worked, but for the last few months is been greyed out/disabled. Is it just me or perhaps there is a bug which is why its disabled? I tried deleting the installed version and downloading a new copy, to no avail - but perhaps there is a setting in my local preferences that could be disabling it. Thanks in advance, Chris

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• Problem with building tree bottom up

  - by Esmond

  Hi, I have problems building a binary tree from the bottom up. THe input of the tree would be internal nodes of the trees with the children of this node being the leaves of the eventual tree. So initially if the tree is empty the root would be the first internal node. Afterwards, The next internal node to be added would be the new root(NR), with the old root(OR) being one of the child of NR. And so on. The problem i have is that whenever i add a NR, the children of the OR seems to be lost when i do a inOrder traversal. This is proven to be the case when i do a getSize() call which returns the same number of nodes before and after addNode(Tree,Node) Any help with resolving this problem is appreciated edited with the inclusion of node class code. both tree and node classes have the addChild methods because i'm not very sure where to put them for it to be appropriated. any comments on this would be appreciated too. The code is as follows: import java.util.*; public class Tree { Node root; int size; public Tree() { root = null; } public Tree(Node root) { this.root = root; } public static void setChild(Node parent, Node child, double weight) throws ItemNotFoundException { if (parent.child1 != null && parent.child2 != null) { throw new ItemNotFoundException("This Node already has 2 children"); } else if (parent.child1 != null) { parent.child2 = child; child.parent = parent; parent.c2Weight = weight; } else { parent.child1 = child; child.parent = parent; parent.c1Weight = weight; } } public static void setChild1(Node parent, Node child) { parent.child1 = child; child.parent = parent; } public static void setChild2(Node parent, Node child) { parent.child2 = child; child.parent = parent; } public static Tree addNode(Tree tree, Node node) throws ItemNotFoundException { Tree tree1; if (tree.root == null) { tree.root = node; } else if (tree.root.getSeq().equals(node.getChild1().getSeq()) || tree.root.getSeq().equals(node.getChild2().getSeq())) { Node oldRoot = tree.root; oldRoot.setParent(node); tree.root = node; } else { //form a disjoint tree and merge the 2 trees tree1 = new Tree(node); tree = mergeTree(tree, tree1); } System.out.print("addNode2 = "); if(tree.root != null ) { Tree.inOrder(tree.root); } System.out.println(); return tree; } public static Tree mergeTree(Tree tree, Tree tree1) { String root = "root"; Node node = new Node(root); tree.root.setParent(node); tree1.root.setParent(node); tree.root = node; return tree; } public static int getSize(Node root) { if (root != null) { return 1 + getSize(root.child1) + getSize(root.child2); } else { return 0; } } public static boolean isEmpty(Tree Tree) { return Tree.root == null; } public static void inOrder(Node root) { if (root != null) { inOrder(root.child1); System.out.print(root.sequence + " "); inOrder(root.child2); } } } public class Node { Node child1; Node child2; Node parent; double c1Weight; double c2Weight; String sequence; boolean isInternal; public Node(String seq) { sequence = seq; child1 = null; c1Weight = 0; child2 = null; c2Weight = 0; parent = null; isInternal = false; } public boolean hasChild() { if (this.child1 == null && this.child2 == null) { this.isInternal = false; return isInternal; } else { this.isInternal = true; return isInternal; } } public String getSeq() throws ItemNotFoundException { if (this.sequence == null) { throw new ItemNotFoundException("No such node"); } else { return this.sequence; } } public void setChild(Node child, double weight) throws ItemNotFoundException { if (this.child1 != null && this.child2 != null) { throw new ItemNotFoundException("This Node already has 2 children"); } else if (this.child1 != null) { this.child2 = child; this.c2Weight = weight; } else { this.child1 = child; this.c1Weight = weight; } } public static void setChild1(Node parent, Node child) { parent.child1 = child; child.parent = parent; } public static void setChild2(Node parent, Node child) { parent.child2 = child; child.parent = parent; } public void setParent(Node parent){ this.parent = parent; } public Node getParent() throws ItemNotFoundException { if (this.parent == null) { throw new ItemNotFoundException("This Node has no parent"); } else { return this.parent; } } public Node getChild1() throws ItemNotFoundException { if (this.child1 == null) { throw new ItemNotFoundException("There is no child1"); } else { return this.child1; } } public Node getChild2() throws ItemNotFoundException { if (this.child2 == null) { throw new ItemNotFoundException("There is no child2"); } else { return this.child2; } } }

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• How can I mount an AES-128 encrypted DMG file using the NTFS file system under Windows XP?

  - by flarn2006

  I found HFSExplorer, which can handle encrypted DMG files, but it only supports HFS, and the DMG I want to open is NTFS. I can't just use any image mounter since the DMG file is encrypted, and I don't want to need to copy it over to my main hard drive first. (The DMG is on an external hard drive.) If copying it is the only way, however, I'd be willing to settle for that, but I'd rather just leave it on the external hard drive in an encrypted form.

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• Show multiple calendars in overlay view by default

  - by Kyle Strand

  In MS Outlook 2007/2010, it's possible to show multiple calendars overlayed on each other (a la Google Calendar; see http://office.microsoft.com/en-us/help/view-calendars-side-by-side-or-overlaid-HA001230157.aspx#BM4). However, it appears that in order to do this, you must first open the calendars side-by-side and then press the little left-arrow button to "combine" them into an overlaid view. Is there a way to make "overlaid" the default view for multiple calendars (again, a la Google Calendar)?

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• What is stopping data flow with .NET 3.5 asynchronous System.Net.Sockets.Socket?

  - by TonyG

  I have a .NET 3.5 client/server socket interface using the asynchronous methods. The client connects to the server and the connection should remain open until the app terminates. The protocol consists of the following pattern: send stx receive ack send data1 receive ack send data2 (repeat 5-6 while more data) receive ack send etx So a single transaction with two datablocks as above would consist of 4 sends from the client. After sending etx the client simply waits for more data to send out, then begins the next transmission with stx. I do not want to break the connection between individual exchanges or after each stx/data/etx payload. Right now, after connection, the client can send the first stx, and get a single ack, but I can't put more data onto the wire after that. Neither side disconnects, the socket is still intact. The client code is seriously abbreviated as follows - I'm following the pattern commonly available in online code samples. private void SendReceive(string data) { // ... SocketAsyncEventArgs completeArgs; completeArgs.Completed += new EventHandler<SocketAsyncEventArgs>(OnSend); clientSocket.SendAsync(completeArgs); // two AutoResetEvents, one for send, one for receive if ( !AutoResetEvent.WaitAll(autoSendReceiveEvents , -1) ) Log("failed"); else Log("success"); // ... } private void OnSend( object sender , SocketAsyncEventArgs e ) { // ... Socket s = e.UserToken as Socket; byte[] receiveBuffer = new byte[ 4096 ]; e.SetBuffer(receiveBuffer , 0 , receiveBuffer.Length); e.Completed += new EventHandler<SocketAsyncEventArgs>(OnReceive); s.ReceiveAsync(e); // ... } private void OnReceive( object sender , SocketAsyncEventArgs e ) {} // ... if ( e.BytesTransferred > 0 ) { Int32 bytesTransferred = e.BytesTransferred; String received = Encoding.ASCII.GetString(e.Buffer , e.Offset , bytesTransferred); dataReceived += received; } autoSendReceiveEvents[ SendOperation ].Set(); // could be moved elsewhere autoSendReceiveEvents[ ReceiveOperation ].Set(); // releases mutexes } The code on the server is very similar except that it receives first and then sends a response - the server is not doing anything (that I can tell) to modify the connection after it sends a response. The problem is that the second time I hit SendReceive in the client, the connection is already in a weird state. Do I need to do something in the client to preserve the SocketAsyncEventArgs, and re-use the same object for the lifetime of the socket/connection? I'm not sure which eventargs object should hang around during the life of the connection or a given exchange. Do I need to do something, or Not do something in the server to ensure it continues to Receive data? The server setup and response processing looks like this: void Start() { // ... listenSocket.Bind(...); listenSocket.Listen(0); StartAccept(null); // note accept as soon as we start. OK? mutex.WaitOne(); } void StartAccept(SocketAsyncEventArgs acceptEventArg) { if ( acceptEventArg == null ) { acceptEventArg = new SocketAsyncEventArgs(); acceptEventArg.Completed += new EventHandler<SocketAsyncEventArgs>(OnAcceptCompleted); } Boolean willRaiseEvent = this.listenSocket.AcceptAsync(acceptEventArg); if ( !willRaiseEvent ) ProcessAccept(acceptEventArg); // ... } private void OnAcceptCompleted( object sender , SocketAsyncEventArgs e ) { ProcessAccept(e); } private void ProcessAccept( SocketAsyncEventArgs e ) { // ... SocketAsyncEventArgs readEventArgs = new SocketAsyncEventArgs(); readEventArgs.SetBuffer(dataBuffer , 0 , Int16.MaxValue); readEventArgs.Completed += new EventHandler<SocketAsyncEventArgs>(OnIOCompleted); readEventArgs.UserToken = e.AcceptSocket; dataReceived = ""; // note server is degraded for single client/thread use // As soon as the client is connected, post a receive to the connection. Boolean willRaiseEvent = e.AcceptSocket.ReceiveAsync(readEventArgs); if ( !willRaiseEvent ) this.ProcessReceive(readEventArgs); // Accept the next connection request. this.StartAccept(e); } private void OnIOCompleted( object sender , SocketAsyncEventArgs e ) { // switch ( e.LastOperation ) case SocketAsyncOperation.Receive: ProcessReceive(e); // similar to client code // operate on dataReceived here case SocketAsyncOperation.Send: ProcessSend(e); // similar to client code } // execute this when a data has been processed into a response (ack, etc) private SendResponseToClient(string response) { // create buffer with response // currentEventArgs has class scope and is re-used currentEventArgs.SetBuffer(sendBuffer , 0 , sendBuffer.Length); Boolean willRaiseEvent = currentClient.SendAsync(currentEventArgs); if ( !willRaiseEvent ) ProcessSend(currentEventArgs); } A .NET trace shows the following when sending ABC\r\n: Socket#7588182::SendAsync() Socket#7588182::SendAsync(True#1) Data from Socket#7588182::FinishOperation(SendAsync) 00000000 : 41 42 43 0D 0A Socket#7588182::ReceiveAsync() Exiting Socket#7588182::ReceiveAsync() - True#1 And it stops there. It looks just like the first send from the client but the server shows no activity. I think that could be info overload for now but I'll be happy to provide more details as required. Thanks!

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