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  • How to write this Link2Sql select query

    - by RememberME
    I have 3 tables: subcontracts, companies and contacts. Each table has a active_status flags which shows that the item is still active (hasn't been deleted). Each contact has a company_id field which stores the id of the contact's company. Each subcontract has a company_id field which stores the subcontract's company. Each company has a company_id field which holds its guid and a primary_company field, b/c the company could be a subsidiary. If it's a subsidiary, the primary_company field holds the id of the primary company. I have a subcontract form. On the form, I have a drop-down of contacts which are stored in a contact table. Currently the drop-down lists all contacts. I would like to have the drop-down only list contacts which belong to the subcontract's company or any of that company's subsidiaries. I have the following query which I use elsewhere in the program to pass a company_id and get its subsidiaries. public IQueryable<company> GetSubsidiaryCompanies(Guid id) { return from c in db.companies where c.primary_company == id && c.active_status == true select c; } This is my current contact selection public IQueryable<contact> GetContacts() { return from c in db.contacts where c.active_status == true orderby c.contact_name select c; } What I need to do is pass it the subcontract.company_id and then only return the contacts where contact.company_id == subcontract.company_id or contact.company_id == one of the subsidiary ids.

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  • how escape quotes when inserting into database in PHP

    - by Mauro74
    Hi all, I'm quite new to PHP so sorry if sounds such an easy problem... :) I'm having an error message when inserting content which contains quotes into my db. here's what I tried trying to escape the quotes but didn't work: $con = mysql_connect("localhost","xxxx","xxxxx"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("test", $con); $nowdate = date('d-m-Y') $title = sprintf($_POST[title], mysql_real_escape_string($_POST[title])); $body = sprintf($_POST[body], mysql_real_escape_string($_POST[body])); $sql="INSERT INTO articles (title, body, date) VALUES ('$title','$body','$nowdate'),"; if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } header('Location: index.php'); Could you provide any solution please? Thanks in advance. Mauro

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  • LINQ query code for complex merging of data.

    - by Stacey
    I've posted this before, but I worded it poorly. I'm trying again with a more well thought out structure. Re-writing this a bit to make it more clear. I have the following code and I am trying to figure out the shorter linq expression to do it 'inline'. Please examine the "Run()" method near the bottom. I am attempting to understand how to join two dictionaries together based on a matching identifier in one of the objects - so that I can use the query in this sort of syntax. var selected = from a in items.List() // etc. etc. select a; This is my class structure. The Run() method is what I am trying to simplify. I basically need to do this conversion inline in a couple of places, and I wanted to simplify it a great deal so that I can define it more 'cleanly'. class TModel { public Guid Id { get; set; } } class TModels : List<TModel> { } class TValue { } class TStorage { public Dictionary<Guid, TValue> Items { get; set; } } class TArranged { public Dictionary<TModel, TValue> Items { get; set; } } static class Repository { static public TItem Single<TItem, TCollection>(Predicate<TItem> expression) { return default(TItem); // access logic. } } class Sample { public void Run() { TStorage tStorage = new TStorage(); // access tStorage logic here. Dictionary<TModel, TValue> d = new Dictionary<TModel, TValue>(); foreach (KeyValuePair<Guid, TValue> kv in tStorage.Items) { d.Add(Repository.Single<TModel, TModels>(m => m.Id == kv.Key),kv.Value); } } }

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  • WHERE clause confusion with PDO

    - by Greg
    I'm having some trouble understanding how to use prepared statements, when you need to match one value against several columns at once. In other words what instead of doing this: $stmt = $dbh-prepare("SELECT * FROM REGISTRY where name = ?"); $stmt-bindParam(':name', $name); I wanted to do this: $stmt = $dbh-prepare("SELECT * FROM REGISTRY where firstname = ? or lastname = ?"); with both '?' representing the same string.

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  • Validation for Alert dialog

    - by Hossam
    Hi Everyone, Im working in a game and when the player finished the level , Im asking the Player to enter his name on EditText in Alert Dialog : AlertDialog.Builder builder = new Builder(this); LayoutInflater inflater = getLayoutInflater(); // Inflate and set the layout for the dialog // Pass null as the parent view because its going in the dialog layout builder.setView(inflater.inflate(R.layout.dialog_name, null)) // Add action buttons .setPositiveButton(R.string.alertName, new DialogInterface.OnClickListener() { @Override public void onClick(DialogInterface dialog, int id) { playerText = (EditText) ((AlertDialog)dialog).findViewById(R.id.username); if(playerText.getText() != null && playerText.getText().length() != 0) Helper.currentPlayer.setName(playerText.getText().toString()); //calculate the score // save in data base PlayerDataSource playerDS = new PlayerDataSource(getApplicationContext()); playerDS.open(); Helper.currentPlayer = playerDS.createPlayer(Helper.currentPlayer.getName(), Helper.currentPlayer.getScore(), Helper.currentPlayer.levels, Helper.currentPlayer.times, LanguageHelper.div); playerDS.close(); saveStmc(); mainScene.setChildScene(choicesMenu, false, true, true); } }) .setTitle("Please Enter Your name") .setNegativeButton(R.string.cancel, new DialogInterface.OnClickListener() { public void onClick(DialogInterface dialog, int id) { } }); alert = builder.create(); When the Player enters his name and press OK (Positive button) I will check in database if the name exists or not, if the name is exist : show Toast and not dismiss the alert to write another name. How to do that?

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  • Audit Table using Triggers

    - by Jose
    DROP TABLE IF EXISTS `actividades`.`act_actividad_audit`; CREATE TABLE `actividades`.`act_actividad_audit` ( `fe_creacion` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP ON UPDATE CURRENT_TIMESTAMP, `usr_digitador` char(10) NOT NULL, `ip_digitador` char(15) NOT NULL, `id_act_actividad` int(10) unsigned NOT NULL, `titulo` char(64) NOT NULL, `act_prioridad_id` int(10) unsigned NOT NULL, `act_motivo_id` int(10) unsigned NOT NULL, `detalle` text, `detalle_tecnico` text, `hostname_id` int(10) unsigned NOT NULL, `hostname_nombre` char(50) NOT NULL, `es_SMOP` tinyint(1) NOT NULL, `url_SMOP` text, `es_tecnico` tinyint(1) NOT NULL ) ENGINE=InnoDB DEFAULT CHARSET=latin1 COMMENT='Auditoria Actividad General'; I want to populate that audit table with a trigger but how can i send or fill the values for usr_digitador or ip_digitador if that values are on client side.? please help

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  • ERRNO: 2 Division by zero error

    - by chupinette
    I am getting this error : ERRNO: 2 TEXT: Division by zero I have the following function in my class Customer public static function GetQuotationDetails($string) { $sql = 'SELECT I.name, I.discounted_price, I.other_name FROM item I WHERE ( I.name LIKE CONCAT( '%', :string, '%' )) AND T.item_name=:string'; $parameters = array(':string' => $string); DB::GetAll($sql,$parameters); } Then, $this->results = Customer::GetQuotationDetails('grinder'); and i echo the results by echo $obj_quotations->results; Can anyone help me?

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  • Creation time of Innodb tables

    - by shantanuo
    CRETAE_TIME column of "TABLES" table from INFORMATION_SCHEMA shows the same CREATE_TIME for all my innodb tables. It means all these tables were created between 2010-03-26 06:52:00 and 2010-03-26 06:53:00 while actually they were created a few months ago. Does the CREATE_TABLE field change automatically for Innodb tables?

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  • Replacing characters with specified one

    - by mahesh
    Hello All, I have a string as follows - MFMFMF now i want to change this string to FMFMFM how to do this , help needed pls i had tried select replace(replace('mfmfmf','M','F'),'F','M') this gives me result - MMMMMM which i donot what i want the output to be FMFMFM Need your help D.Mahesh

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  • SQL, PHP: want to get the collums of a table INFORMATION_SCHEMA gives acces denied --> alternative?

    - by matthy
    hi what i am trying to do is get all the collums of a table (the table can be empty) example of what i did before: SELECT COLUMN_NAME FROM INFORMATION_SCHEMA.COLUMNS WHERE table_name = 'aTable' AND table_schema = 'theDatabase' it works perfectly on localhost however on my provider it gives: #1142 - SELECT command denied to user 'username'@'localhost' for table 'COLUMNS' is there an alternative that doesn't use the INFORMATION_SCHEMA??

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  • Select a random row from table, but with odds?

    - by Don
    I have a table that describes a variety of objects in my system (ie. umbrella, boots, satchel, whatever). Each one of these objects needs to have a distinct prevalence or incidence. For example, the umbrella is rarer than the boots. Based on those factors, I need to randomly select a single object (including a blank or 'no object found') based on that incidence value. Yikes. Make sense?

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  • Debug irrelevant Wordpress search results

    - by konzepz
    On Wordpress, I keep getting irrelevant search results. Some search strings that do not exist on the DB yield All Posts as results. Some search strings that DO exist, works great. What could be the cause of that behavior? I've uninstalled all related plugins. Is there a way to debug the search? Thanks!

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  • Thoughts/Input about Database Design for a CMS

    - by dallasclark
    I'm just about to expand the functionality of our own CMS but was thinking of restructuring the database to make it simpler to add/edit data types and values. Currently, the CMS is quite flat - the CMS requires a field in the database for every type of stored value (manually created). The first option that comes to mind is simply a table which keeps the data types (ie: Address 1, Suburb, Email Address etc) and another table which holds values for each of these data types. Just like how Wordpress keeps values in the 'options' table, PHP serialize would be used to store an array of values. The second option is how Drupal works, the CMS creates tables for every data type. Unlike Wordpress, this can be a bit of an overkill but really useful for SQL queries when ordering and grouping by a particular value. What's everyone's thoughts?

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  • Cast integer to real

    - by Dave Jarvis
    Question How do you cast an INTEGER value as a REAL value? Attempts CAST( Y.YEAR AS REAL), but that failed (the documentation indicates you cannot CAST or CONVERT values to REALs. Y.YEAR + 0.0, but that failed, too. Error Message Using udf_slope fails due to: Can't initialize function 'slope'; slope() requires a real as parameter 2 Code SELECT D.AMOUNT, Y.YEAR, slope(D.AMOUNT, Y.YEAR + 0.0) as SLOPE, intercept(D.AMOUNT, Y.YEAR + 0.0) as INTERCEPT FROM YEAR_REF Y, DAILY D Here, D.AMOUNT is a FLOAT and Y.YEAR is an INTEGER. Thank you!

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  • Drupal Views pulling Data Fields

    - by askon
    I'm a little new to drupal but have been using things like devel module and theme developer to speed up the learning process. My question, is it possible to theme an entire views BLOCK from a single views tpl.php page OR even a preprocess? When I'm grabbing the $view object I can see results $node-result, it has all of the results, but it doesn't have all my views fields. I'm missing things like, node path, taxonomy titles and paths, etc. From my understanding, Drupal wants you to individually theme EACH output field. It seems rather superfluous to create so many extra templates when I've already got over HALF of my results coming through the $view object Would outputting node over field make this easier? Or am going in the wrong direction with $view-result? Thanks!

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  • SQL - How can I apply a "semi-unique" constraint?

    - by Erin Drummond
    Hi, I have a (simplified) table consisting of three columns: id INT PRIMARY KEY NOT NULL AUTO_INCREMENT, foreignID INT NOT NULL, name VARCHAR NOT NULL Basically, I would like to add a constraint (at the database level rather than at the application level) where it only possible for one unique 'name' to exist per foreignID. For example, given the data (id, foreignid, name): 1,1,Name1 2,1,Name2 3,1,Name3 4,2,Name1 5,2,Name2 I want the constraint to fail if the user tries to insert another 'Name3' under foreignId 1, but succeed if the user tries to insert 'Name3' under foreignId 2. For this reason I cannot simply make the whole column UNIQUE. I am having difficulty coming up with a SQL expression to achieve this, can anybody help me? Thanks

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  • How to design tag database structure?

    - by liuxingruo
    I have a subjects database, and I want to create a new tag database to tag the subjects, but I have no idea how to design the new tag database structure. I'm assuming the new database looks like this: tag_id tag_name tagged_subject_ids 1 tag1 1, 2, 3, 5, 10 2 tag2 2, 4, 5, 6, 10, 12 so, if I want to select the tags belong to subject 1: SELECT tag_name FROM tag_database WHERE tagged_subject_ids LIKE '1'; I think the way that I select tag may be very slow, so please help me. Thanks!

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  • Search 2 Columns with 1 Input Field

    - by Norbert
    I have a db with two columns: first name and last name. The first name can have multiple words. Last name can contain hyphenated words. Is there a way to search both columns with only one input box? Database ID `First Name` `Last Name` 1 John Peter Doe 2 John Fubar 3 Michael Doe Search john peter returns id 1 john returns id 1,2 doe returns id 1,3 john doe returns id 1 peter john returns id 1 peter doe returns id 1 doe john returns id 1 I previously tried the following. Searching for John Doe: SELECT * FROM names WHERE ( `first` LIKE '%john%' OR `first` LIKE '%doe%' OR `last` LIKE '%john%' OR `last` LIKE '%doe%' ) which returns both 1 and 3

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  • Auto deployment of PHP applications

    - by Christopher McCann
    My team currently has a development web/database server and a live deployment web server and a live database server. We use SVN with the repository stored on the development server but the problem is our deployment process. Currently when we need to deploy an update to the live application we simply use SFTP to transfer from the repository to the live web server and then amend the database on the live server to reflect the development database. This is a really slow process as we also minify all javascript and CSS files. I have used Capistrano for Ruby and Cruise Control for java but I have never used anything for PHP. I'd rather not have to build our own if something already existed. Does anyone know of anything?

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  • IF expression in SQL

    - by chupinette
    INSERT INTO item_quotation (item_id, quotation_id,name_searched,item_name,other_name,selling_price,discounted_price) SELECT DISTINCT I.item_id," . $quotation_id . ",T.item_name, I.name,I.other_name, INV.selling_price, I.discounted_price FROM temp_quotations T, item I, inventory INV<br/> WHERE ( I.name LIKE CONCAT( '%', T.item_name, '%' ) OR I.other_name LIKE CONCAT( '%', T.item_name, '%' )) AND INV.item_id = I.item_id; I have a table called temp_quotations(temp_item_id,item_name)having values (1,grinder), (2,drill), (3,kit) I have another table called item(item_id,name,other_name,discounted_price) having values (1,grinder A,100),(2,kit A,200) When I execute this sql, it insert values in table item_quotation(item_id, quotation_id,name_searched,item_name,other_name,selling_price,discounted_price) for example in this case it will insert (1,1,grinder,grinder A,150,100) (2,1,kit,kit A, 250,200) Since the item drill is not found in table item, it wont display it in table item_quotations. I want to write an if statement within that sql so that when the item_name from temp_quotation does not match the name from item, it displays not found in the place of item_name. This is what i tried but it does not display "not found": INSERT INTO item_quotation (item_id, quotation_id,name_searched,item_name,other_name,selling_price,discounted_price) SELECT DISTINCT I.item_id," . $quotation_id . ",T.item_name, IF(I.name LIKE CONCAT( '%', T.item_name, '%' ),I.name,'not found'),I.other_name, INV.selling_price, I.discounted_price FROM temp_quotations T, item I, inventory INV WHERE ( I.name LIKE CONCAT( '%', T.item_name, '%' ) OR I.other_name LIKE CONCAT( '%', T.item_name, '%' )) AND INV.item_id = I.item_id;

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  • Altering constraint delete action

    - by Hobhouse
    I did this: ALTER TABLE `db`.`my_table` ADD CONSTRAINT FOREIGN KEY (`my_second_table_id`) REFERENCES `my_second_table` (`id`); I should have done this: ALTER TABLE `db`.`my_table` ADD CONSTRAINT FOREIGN KEY (`my_second_table_id`) REFERENCES `my_second_table` (`id`) ON DELETE SET NULL; Is it possible to ALTER this, or do I have to drop the constraint and add again?

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  • Validate Canadian Postal Code Regex

    - by Alex Block
    I have a script written in JavaScript to Validate Canadian Postal Codes using Regex, however it does not seem to be working. Here is the script: If statement: if (myform.zip.value == "" || myform.zip.value == null || myform.zip.value == "Postal Code" || myform.zip.value.length < 12 ) { alert("Please fill in field Postal Code. You should only enter 7 characters"); myform.zip.focus(); return false; } Function: function okNumber(myform) { var regex = /^[ABCEGHJKLMNPRSTVXY]{1}\d{1}[A-Z]{1} *\d{1}[A-Z]{1}\d{1}$/; if (regex.test(myform.zip.value) == false) { alert("Input Valid Postal Code"); myform.zip.focus(); return false; } return true; }

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  • SQL select statement

    - by kwokwai
    Hi all, I got a Table which has two fields: Point, and Level, with some sample data as follows: ----------------------- Point | Level ----------------------- 10 | Level 1 20 | Level 2 30 | Level 3 40 | Level 4 Suppose that there is a user who has 25 points, to find the Level in which this user is in, the Select statement I used was: Select Level from Table where Point < 30 AND Point > 20; But the Select SQL ststament is a hard-copy one where you can see the ponts 30 and 20 are fixed. I want to alter the Select statement so that the new SQL Select statement can be applied to all users with different points, but I don't know how to do it.

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