Search Results

Search found 34110 results on 1365 pages for 'gdata python client'.

Page 490/1365 | < Previous Page | 486 487 488 489 490 491 492 493 494 495 496 497  | Next Page >

• How can I fix the scroll bug when using Windows rich edit controls in wxpython?

  - by ChrisD

  When using wx.TextCtl with the wx.TE_RICH2 option in windows, I get this strange bug with the auto-scroll when using the AppendText function. It scrolls so that all the text is above the visible area, which isn't very useful behaviour. I tried just adding a call to ScrollLines(-1) after appending the text - which does scroll it to the correct position - but this can lead to the window flashing when it auto-scrolls. So I'm looking for another way to automatically scroll to the bottom. So far, my solution is to bypass the AppendText functions auto-scroll and implement my own, like this: def append_text(textctrl, text): before_number_of_lines = textctrl.GetNumberOfLines() textctrl.SetInsertionPointEnd() textctrl.WriteText(text) after_number_of_lines = textctrl.GetNumberOfLines() textctrl.ScrollLines(before_number_of_lines - after_number_of_lines + 1) Is there a better way?

  Read the article

• How come my South migrations doesn't work for Django?

  - by TIMEX

  First, I create my database. create database mydb; I add "south" to installed Apps. Then, I go to this tutorial: http://south.aeracode.org/docs/tutorial/part1.html The tutorial tells me to do this: $ py manage.py schemamigration wall --initial >>> Created 0001_initial.py. You can now apply this migration with: ./manage.py migrate wall Great, now I migrate. $ py manage.py migrate wall But it gives me this error... django.db.utils.DatabaseError: (1146, "Table 'fable.south_migrationhistory' doesn't exist") So I use Google (which never works. hence my 870 questions asked on Stackoverflow), and I get this page: http://groups.google.com/group/south-users/browse_thread/thread/d4c83f821dd2ca1c Alright, so I follow that instructions >> Drop database mydb; >> Create database mydb; $ rm -rf ./wall/migrations $ py manage.py syncdb But when I run syncdb, Django creates a bunch of tables. Yes, it creates the south_migrationhistory table, but it also creates my app's tables. Synced: > django.contrib.admin > django.contrib.auth > django.contrib.contenttypes > django.contrib.sessions > django.contrib.sites > django.contrib.messages > south > fable.notification > pagination > timezones > fable.wall > mediasync > staticfiles > debug_toolbar Not synced (use migrations): - (use ./manage.py migrate to migrate these) Cool....now it tells me to migrate these. So, I do this: $ py manage.py migrate wall The app 'wall' does not appear to use migrations. Alright, so fine. I'll add wall to initial migrations. $ py manage.py schemamigration wall --initial Then I migrate: $ py manage.py migrate wall You know what? It gives me this BS: _mysql_exceptions.OperationalError: (1050, "Table 'wall_content' already exists") Sorry, this is really pissing me off. Can someone help ? thanks. How do I get South to work and sync correctly with everything?

  Read the article

• Avoiding nesting two for loops

  - by chavanak

  Hi, Please have a look at the code below: import string from collections import defaultdict first_complex=open( "residue_a_chain_a_b_backup.txt", "r" ) first_complex_lines=first_complex.readlines() first_complex_lines=map( string.strip, first_complex_lines ) first_complex.close() second_complex=open( "residue_a_chain_a_c_backup.txt", "r" ) second_complex_lines=second_complex.readlines() second_complex_lines=map( string.strip, second_complex_lines ) second_complex.close() list_1=[] list_2=[] for x in first_complex_lines: if x[0]!="d": list_1.append( x ) for y in second_complex_lines: if y[0]!="d": list_2.append( y ) j=0 list_3=[] list_4=[] for a in list_1: pass for b in list_2: pass if a==b: list_3.append( a ) kvmap=defaultdict( int ) for k in list_3: kvmap[k]+=1 print kvmap Normally I use izip or izip_longest to club two for loops, but this time the length of the files are different. I don't want a None entry. If I use the above method, the run time becomes incremental and useless. How am I supposed to get the two for loops going? Cheers, Chavanak

  Read the article

• foreignkey problem

  - by realshadow

  Hey, Imagine you have this model: class Category(models.Model): node_id = models.IntegerField(primary_key = True) type_id = models.IntegerField(max_length = 20) parent_id = models.IntegerField(max_length = 20) sort_order = models.IntegerField(max_length = 20) name = models.CharField(max_length = 45) lft = models.IntegerField(max_length = 20) rgt = models.IntegerField(max_length = 20) depth = models.IntegerField(max_length = 20) added_on = models.DateTimeField(auto_now = True) updated_on = models.DateTimeField(auto_now = True) status = models.IntegerField(max_length = 20) node = models.ForeignKey(Category_info, verbose_name = 'Category_info', to_field = 'node_id' The important part is the foreignkey. When I try: Category.objects.filter(type_id = 15, parent_id = offset, status = 1) I get an error that get returned more than category, which is fine, because it is supposed to return more than one. But I want to filter the results trough another field, which would be type id (from the second Model) Here it is: class Category_info(models.Model): objtree_label_id = models.AutoField(primary_key = True) node_id = models.IntegerField(unique = True) language_id = models.IntegerField() label = models.CharField(max_length = 255) type_id = models.IntegerField() The type_id can be any number from 1 - 5. I am desparately trying to get only one result where the type_id would be number 1. Here is what I want in sql: SELECT c.*, ci.* FROM category c JOIN category_info ci ON (c.node_id = ci.node_id) WHERE c.type_id = 15 AND c.parent_id = 50 AND ci.type_id = 1 Any help is GREATLY appreciated. Regards

  Read the article

• Duplicate django query set?

  - by Piotr Czapla

  I have a simple django's query set like: qs = AModel.objects.exclude(state="F").order_by("order") I'd like to use it as follows: qs[0:3].update(state='F') expected = qs[3] # throws error here But last statement throws: "Cannot update a query once a slice has been taken." How can I duplicate the query set?

  Read the article

• Which parts of the client certificate to use when uniquely identifying users?

  - by miha

  I'm designing a system where users will be able to register and afterward authenticate with client certificates in addition to username/password authentication. The client certificates will have to be valid certificates issued by a configured list of certificate authorities and will be checked (validated) when presented. In the registration phase, I need to store part(s) of the client certificate in a user repository (DB, LDAP, whatever) so that I can map the user who authenticates with client certificate to an internal "user". One fairly obvious choice would be to use certificate fingerprint; But fingerprint itself is not enough, since collisions may occur (even though they're not probable), so we need to store additional information from the certificate. This SO question is also informative in this regard. RFC 2459 defines (4.1.2.2) that certificate serial number must be unique within a given CA. With all of this combined, I'm thinking of storing certificate serial number and certificate issuer for each registered user. Given that client certificates will be verified and valid, this should uniquely identify each client certificate. That way, even when client certificate is renewed, it would still be valid (serial number stays the same, and so does the issuer). Did I miss something?

  Read the article

• PAM authentication problem

  - by mdipierro

  I am using this module to authenticate using pam: http://code.google.com/p/web2py/source/browse/gluon/contrib/pam.py I can call authenticate('username','password') and it returns True/ False. It works for any 'username' but 'root'. My guess is that there is a security restriction in PAM that does not allow to check for the root password. I need to be able to check the root password. Is there anything I can change in the pam.conf or somewhere else to remove this restriction?

  Read the article

• Send a "304 Not Modified" for images stored in the datastore

  - by Emilien

  I store user-uploaded images in the Google App Engine datastore as db.Blob, as proposed in the docs. I then serve those images on /images/<id>.jpg. The server always sends a 200 OK response, which means that the browser has to download the same image multiple time (== slower) and that the server has to send the same image multiple times (== more expensive). As most of those images will likely never change, I'd like to be able to send a 304 Not Modified response. I am thinking about calculating some kind of hash of the picture when the user uploads it, and then use this to know if the user already has this image (maybe send the hash as an Etag?) I have found this answer and this answer that explain the logic pretty well, but I have 2 questions: Is it possible to send an Etag in Google App Engine? Has anyone implemented such logic, and/or is there any code snippet available?

  Read the article

• Create a color generator in matplotlib

  - by Brendan

  I have a series of lines that each need to be plotted with a separate colour. Each line is actually made up of several data sets (positive, negative regions etc.) and so I'd like to be able to create a generator that will feed one colour at a time across a spectrum, for example the gist_rainbow map shown here. I have found the following works but it seems very complicated and more importantly difficult to remember, from pylab import * NUM_COLORS = 22 mp = cm.datad['gist_rainbow'] get_color = matplotlib.colors.LinearSegmentedColormap.from_list(mp, colors=['r', 'b'], N=NUM_COLORS) ... # Then in a for loop this_color = get_color(float(i)/NUM_COLORS) Moreover, it does not cover the range of colours in the gist_rainbow map, I have to redefine a map. Maybe a generator is not the best way to do this, if so what is the accepted way?

  Read the article

• How do I set up my own proxy server?

  - by NJTechGuy

  This website (abc.com) slowed access from our original IP address. How do I implement my own proxy server to hide my IP while browsing abc.com? Do I need special hardware/software combo to achieve this? If I can generate about 5 proxies and alternate amongst those 5 while browsing abc.com would be awesome. Please suggest. Thanks guys!

  Read the article

• Debugging Actionmailer

  - by Trip

  I have actionmailer set up. Emails are not being sent, and no errors. Where can I start my search to debug this? class Notifier < ActionMailer::Base default_url_options[:host] = APP_DOMAIN def email_blast(user, subject, message) subject subject from NOTIFIER_EMAIL recipients user.email sent_on Time.zone.now body :user => user.first_name + ' ' + user.last_name, :message => message end I do get a return in my log that the email was sent, just no actual email goes through. Also the reason, that this is not working is because I switched form a cluster to a solo box and some server settings were overwritten. I suspect that is probably the reason why this is not working. Anyone know what specific server settings I would have to look at ? UPDATE: ActionMailer::Base.delivery_method = :sendmail config.action_mailer.default_url_options = { :host => "75.101.153.93" } I found this in my production.rb . This code was originally here when it worked. Again, I believe that there must be something missing on my server..I did a 'which sendmail' and it returned /usr/bin/sendmail , so I added this : config.action_mailer.raise_delivery_errors = false config.action_mailer.perform_deliveries = true config.action_mailer.sendmail_settings = { :location => '/usr/bin/sendmail', :arguments => '-i -t' } Redeployed, restarted the server, and tested it. No emails were sent. The production.log said something was sent : Processing MediaController#create_a_video (for 173.161.167.41 at 2010-06-03 11:58:13) [GET] Parameters: {"action"=>"create_a_video", "controller"=>"media", "organization_id"=>"470", "_"=>"1275591493194"} Sent mail to [email protected] Rendering media/create_a_video Completed in 128ms (View: 51, DB: 1) | 200 OK [http://invent.hqchannel.com/organizations/470/media/create_a_video?_=1275591493194]

  Read the article

• Import boto from local library

  - by ensnare

  I'm trying to use boto as a downloaded library, rather than installing it globally on my machine. I'm able to import boto, but when I run boto.connect_dynamodb() I get an error: ImportError: No module named dynamodb.layer2 Here's my file structure: project/ project/ __init__.py libraries/ __init__.py flask/ boto/ views/ .... modules/ __init__.py db.py .... templates/ .... static/ .... runserver.py And the contents of the relevant files as follows: project/project/modules/db.py from project.libraries import boto conn = boto.connect_dynamodb( aws_access_key_id='<YOUR_AWS_KEY_ID>', aws_secret_access_key='<YOUR_AWS_SECRET_KEY>') What am I doing wrong? Thanks in advance.

  Read the article

• matplotlib - zebra-stripe a figure's background color?

  - by jawonlee

  I'm building a simple line chart with matplotlib, and I'd like to zebra-stripe the background of the chart, so that each alternating row is colored differently. Is there a way to do this? My chart already has gridding, and has major ticks only.

  Read the article

• SQLAlchemy - select for update example

  - by Mark

  I'm looking for a complete example of using select for update in SQLAlchemy, but haven't found one googling. I need to lock a single row and update a column, the following code doesn't work (blocks forever): s = table.select(table.c.user=="test",for_update=True) u = table.update().where(table.c.user=="test") u.execute(email="foo") Do I need a commit? How do I do that? As far as I know you need to: begin transaction select ... for update update commit

  Read the article

• Project design / FS layout for large django projects

  - by rcreswick

  What is the best way to layout a large django project? The tutuorials provide simple instructions for setting up apps, models, and views, but there is less information about how apps and projects should be broken down, how much sharing is allowable/necessary between apps in a typical project (obviously that is largely dependent on the project) and how/where general templates should be kept. Does anyone have examples, suggestions, and explanations as to why a certain project layout is better than another? I am particularly interested in the incorporation of large numbers of unit tests (2-5x the size of the actual code base) and string externalization / templates.

  Read the article

• Django: How do I access the request object or any other variable in a form's clean() method?

  - by nubela

  I am trying to request.user for a form's clean method, but how can I access the request object? Can I modify the clean method to allow variables input? Thanks.

  Read the article

• Problem bounding name to a class in Django

  - by martinthenext

  Hello! I've got a view function that has to decide which form to use depending on some conditions. The two forms look like that: class OpenExtraForm(forms.ModelForm): class Meta: model = Extra def __init__(self, *args, **kwargs): super(OpenExtraForm, self).__init__(*args, **kwargs) self.fields['opening_challenge'].label = "lame translation" def clean_opening_challenge(self): challenge = self.cleaned_data['opening_challenge'] if challenge is None: raise forms.ValidationError('??????? ???, ??????????? ?????? ???. ???????????') return challenge class HiddenExtraForm(forms.ModelForm): class Meta: model = Extra exclude = ('opening_challenge') def __init__(self, *args, **kwargs): super(HiddenExtraForm, self).__init__(*args, **kwargs) The view code goes like that: @login_required def manage_extra(request, extra_id=None, hidden=False): if not_admin(request.user): raise Http404 if extra_id is None: # Adding a new extra extra = Extra() if hidden: FormClass = HiddenExtraForm else: FormClass = OpenExtraForm else: # Editing an extra extra = get_object_or_404(Extra, pk=extra_id) if extra.is_hidden(): FromClass = HiddenExtraForm else: FormClass = OpenExtraForm if request.POST: form = FormClass(request.POST, instance=extra) if form.is_valid(): form.save() return HttpResponseRedirect(reverse(view_extra, args=[extra.id])) else: form = FormClass(instance=extra) return render_to_response('form.html', { 'form' : form, }, context_instance=RequestContext(request) ) The problem is somehow if extra.is_hidden() returns True, the statement FromClass = HiddenExtraForm doesn't work. I mean, in all other conditions that are used in the code it works fine: the correct Form classes are intantiated and it all works. But if extra.is_hidden(), the debugger shows that the condition is passed and it goes to the next line and does nothing! As a result I get a UnboundLocalVar error which says FormClass hasn't been asssigned at all. Any ideas on what's happening?

  Read the article

• Process Name with inotify tool

  - by Priyanka

  Hi ALl Is there a way to find out which process is causing a particular event to occur? In the inotify-tool version 3.13, in struct_kernel , pid,uid and gid are used but it is not handled in the source code. Is there any latest patch available for the same. Please let me know.

  Read the article

• Django does not load internal .css files

  - by Rubén Jiménez

  I have created a Django project in local which runs without any kind of problem. But, after an annoying and difficult Cherokee + uWSGI installation on Amazon AWS, my project does not show Django .css internal files. http://f.cl.ly/items/2Q2W3I3R0X1n2X3v0q2P/django_error.jpg <-- /Admin/ looks like The image is a screen of my /admin/, which should have a different style, but .css files are not loaded. [pid: 23206|app: 0|req: 19/19] 83.49.10.217 () {56 vars in 1121 bytes} [Sun Apr 15 05:50:24 2012] GET /static/admin/css/base.css = generated 2896 bytes in 6 msecs (HTTP/1.1 404) 1 headers in 51 bytes (1 switches on core 0) [pid: 23206|app: 0|req: 20/20] 83.49.10.217 () {56 vars in 1125 bytes} [Sun Apr 15 05:50:24 2012] GET /static/admin/css/login.css = generated 2899 bytes in 5 msecs (HTTP/1.1 404) 1 headers in 51 bytes (1 switches on core 0) This is a log from Cherokee. I don't understand why it is looking for the .css files in that path. Cherokee should be searching the files in Django original directory so i didn't change .css files in my project. Any advice? Thanks a lot.

  Read the article

• Inexpensive ways to add seek to a filetype object

  - by becomingGuru

  PdfFileReader reads the content from a pdf file to create an object. I am querying the pdf from a cdn via urllib.urlopen(), this provides me a file like object, which has no seek. PdfFileReader, however uses seek. What is the simple way to create a PdfFileReader object from a pdf downloaded via url. Now, what can I do to avoid writing to disk and reading it again via file(). Thanks in advance.

  Read the article

• Datastore query outputting for Django form instance

  - by Jelle

  Hello! I'm using google appengine and Django. I'm using de djangoforms module and wanted to specify the form instance with the information that comes from the query below. userquery = db.GqlQuery("SELECT * FROM User WHERE googleaccount = :1", users.get_current_user()) form = forms.AccountForm(data=request.POST or None,instance=?????) I've found a snippet in a sample app that does this trick, but I can't modify it to work with the query I need. gift = User.get(db.Key.from_path(User.kind(), int(gift_id))) if gift is None: return http.HttpResponseNotFound('No gift exists with that key (%r)' % gift_id) form = RegisterForm(data=request.POST or None, instance=gift) Could anyone help me?

  Read the article

• Find subset with K elements that are closest to eachother

  - by Nima

  Given an array of integers size N, how can you efficiently find a subset of size K with elements that are closest to each other? Let the closeness for a subset (x1,x2,x3,..xk) be defined as: 2 <= N <= 10^5 2 <= K <= N constraints: Array may contain duplicates and is not guaranteed to be sorted. My brute force solution is very slow for large N, and it doesn't check if there's more than 1 solution: N = input() K = input() assert 2 <= N <= 10**5 assert 2 <= K <= N a = [] for i in xrange(0, N): a.append(input()) a.sort() minimum = sys.maxint startindex = 0 for i in xrange(0,N-K+1): last = i + K tmp = 0 for j in xrange(i, last): for l in xrange(j+1, last): tmp += abs(a[j]-a[l]) if(tmp > minimum): break if(tmp < minimum): minimum = tmp startindex = i #end index = startindex + K? Examples: N = 7 K = 3 array = [10,100,300,200,1000,20,30] result = [10,20,30] N = 10 K = 4 array = [1,2,3,4,10,20,30,40,100,200] result = [1,2,3,4]

  Read the article

• how to pass in dynamic data to decorators

  - by steve

  Hi, I am trying to write a base crud controller class that does the following: class BaseCrudController: model = "" field_validation = {} template_dir = "" @expose(self.template_dir) def new(self, *args, **kwargs) .... @validate(self.field_validation, error_handler=new) @expose() def post(self, *args, **kwargs): ... My intent is to have my controllers extend this base class, set the model, field_validation, and template locations, and am ready to go. Unfortunately, decorators (to my understanding), are interpreted when the function is defined. Hence it won't have access to instance's value. Is there a way to pass in dynamic data or values from the sub class? If not, I guess I could use override_template as a workaround to expose and set the template within the controller action. How would I go about validating the form within the controller action? Thanks, Steve

  Read the article

• Which software for intranet CMS - Django or Joomla?

  - by zalun

  In my company we are thinking of moving from wiki style intranet to a more bespoke CMS solution. Natural choice would be Joomla, but we have a specific architecture. There is a few hundred people who will use the system. System should be self explainable (easier than wiki). We use a lot of tools web, applications and integrated within 3rd party software. The superior element which is a glue for all of them is API. In example for the intranet tools we do use Django, but it's used without ORM, kind of limited to templates and url - every application has an adequate methods within our API. We do not use the Django admin interface, because it is hardly dependent on ORM. Because of that Joomla may be hard to integrate. Every employee should be able to edit most of the pages, authentication and privileges have to be managed by our API. How hard is it to plug Joomla to use a different authentication process? (extension only - no hacks) If one knows Django better than Joomla, should Django be used?

  Read the article

• GUI IDE with PyDev Eclipse

  - by gizgok

  I have 2 weeks to finish my final year project.I need a GUI IDE or a GUI framework compatible with PyDev and Eclipse. I cannot spend time learning something cause the functionality is yet to be completed.I'm looking for very simple GUI for a simulation game.

  Read the article

< Previous Page | 486 487 488 489 490 491 492 493 494 495 496 497  | Next Page >