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  • Magic Quadrant for x86 Server Virtualization Infrastructure

    - by Cinzia Mascanzoni
    The 2012 Gartner MQ for x86 Server Virtualization has just published.  KEY TAKEAWAYS - Oracle is in the “Challengers” quadrant. - This is a significant “jump” above the x-axis (from the “Niche” quadrant) during previous years - The move into the “Challengers” quadrant was possible for 3 primary reasons - 1) strength of the Oracle VM 3.0 release - 2) integrated management capabilities - 3) solid customer momentum during past year - Gartner even specifically states that Oracle VM use is growing amongst VMware customers Read the full report here.

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  • [MATH]Project an axis to a plane

    - by Robert
    how do i project the X axis to a plane if the plane is defined by three points? see pic here: http://129.25.16.135:2080/v6.5/books/usb/graphics/iconventions-local-surfaces.png The default local 1-direction is the projection of the global x-axis onto the surface. If the global x-axis is within 0.1° of being normal to the surface, the local 1-direction is the projection of the global z-axis onto the surface. let's suppose that these points are: t1 = [-0.362879991531372, 0.357021987438202, -0.373737007379532] t2 = [-0.383525013923645, 0.371621012687683, -0.383549988269806] t3 = [-0.383534014225006, 0.34629300236702, -0.38544899225235] is the vector [0.78280971952246, -0.0307519963686645, 0.411184845614438] correct answer in this case? i've calculated the angle between the surf and x (1,0,0) is ~28°. and can you give the entire procedure for the calculation, because i'm just puzzled.

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  • Better way to load level content in XNA?

    - by user2002495
    Currently I loaded all my assets in XNA in the main Game class. What I want to achieve later is that I only load specific assets for specific levels (the game will consist of many levels). Here is how I load my main assets into the main class: protected override void LoadContent() { spriteBatch = new SpriteBatch(GraphicsDevice); plane = new Player(Content.Load<Texture2D>(@"Player/playerSprite"), 6, 8); plane.animation = "down"; plane.pos = new Vector2(400, 500); plane.fps = 15; Global.currentPos = plane.pos; lvl1 = new Level1(Content.Load<Texture2D>(@"Levels/bgLvl1"), Content.Load<Texture2D>(@"Levels/bgLvl1-other"), new Vector2(0, 0), new Vector2(0, -600)); CommonBullet.LoadContent(Content); CommonEnemyBullet.LoadContent(Content); } protected override void UnloadContent() { } protected override void Update(GameTime gameTime) { if (GamePad.GetState(PlayerIndex.One).Buttons.Back == ButtonState.Pressed) this.Exit(); plane.Update(gameTime); lvl1.Update(gameTime); foreach (CommonEnemy ce in cel) { if (ce.CollidesWith(plane)) { ce.hasSpawn = false; } foreach (CommonBullet b in plane.commonBulletList) { if (b.CollidesWith(ce)) { ce.hasSpawn = false; } } ce.Update(gameTime); } LoadCommonEnemy(); base.Update(gameTime); } private void LoadCommonEnemy() { int randY = rand.Next(-600, -10); int randX = rand.Next(0, 750); if (cel.Count < 3) { cel.Add(new CommonEnemy(Content.Load<Texture2D>(@"Enemy/Common/commonEnemySprite"), 7, 2, "left", randX, randY)); } for (int i = 0; i < cel.Count; i++) { if (!cel[i].hasSpawn) { cel.RemoveAt(i); i--; } } } protected override void Draw(GameTime gameTime) { GraphicsDevice.Clear(Color.Black); spriteBatch.Begin(); lvl1.Draw(spriteBatch); plane.Draw(spriteBatch); foreach (CommonEnemy ce in cel) { ce.Draw(spriteBatch); } spriteBatch.End(); base.Draw(gameTime); } I wish to load my players, enemies, all in Level1 class. However, when I move my player & enemy code into the Level1 class, the gameTime returns null. Here is my Level1 class: using System; using System.Collections.Generic; using System.Linq; using System.Text; using Microsoft.Xna.Framework; using Microsoft.Xna.Framework.Audio; using Microsoft.Xna.Framework.Content; using Microsoft.Xna.Framework.Graphics; using Microsoft.Xna.Framework.Media; using Microsoft.Xna.Framework.Input; using SpaceShooter_Beta.Animation.PlayerCollection; using SpaceShooter_Beta.Animation.EnemyCollection.Common; namespace SpaceShooter_Beta.Levels { public class Level1 { public Texture2D bgTexture1, bgTexture2; public Vector2 bgPos1, bgPos2; public float speed = 5f; Player plane; public Level1(Texture2D texture1, Texture2D texture2, Vector2 pos1, Vector2 pos2) { this.bgTexture1 = texture1; this.bgTexture2 = texture2; this.bgPos1 = pos1; this.bgPos2 = pos2; } public void LoadContent(ContentManager cm) { plane = new Player(cm.Load<Texture2D>(@"Player/playerSprite"), 6, 8); plane.animation = "down"; plane.pos = new Vector2(400, 500); plane.fps = 15; Global.currentPos = plane.pos; } public void Draw(SpriteBatch sb) { sb.Draw(bgTexture1, bgPos1, Color.White); sb.Draw(bgTexture2, bgPos2, Color.White); plane.Draw(sb); } public void Update(GameTime gt) { bgPos1.Y += speed; bgPos2.Y += speed; if (bgPos1.Y >= 600) { bgPos1.Y = -600; } if (bgPos2.Y >= 600) { bgPos2.Y = -600; } plane.Update(gt); } } } Of course when I did this, I delete all my player's code in the main Game class. All of that works fine (no errors) except that the game cannot start. The debugger says that plane.Update(gt); in Level 1 class has null GameTime, same thing with the Draw method in the Level class. Please help, I appreciate for the time. [EDIT] I know that using switch in the main class can be a solution. But I prefer a cleaner solution than that, since using switch still means I need to load all the assets through the main class, the code will be A LOT later on for each levels

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  • How to create a magic square in PHP?

    - by TerranRich
    I'd like to try my hand at creating a Magic Square in PHP (i.e. a grid of numbers that all add up to the same value), but I really don't know where to start. I know of the many methods that create magic square, such as starting "1" at a fixed position, then moving in a specific direction with each iteration. But that doesn't create a truly randomized Magic Square, which is what I'm aiming for. I want to be able to generate an N-by-N Magic Square of N² numbers where each row and column adds up to N(N²+1)/2 (e.g. a 5x5 square where all rows/columns add up to 65 — the diagonals don't matter). Can anybody provide a starting point? I don't want anybody to do the work for me, I just need to know how to start such a project? I know of one generator, written in Java (http://www.dr-mikes-math-games-for-kids.com/how-to-make-a-magic-square.html) but the last Java experience I had was over 10 years ago before I quickly abandoned it. Therefore, I don't really understand what the code is actually doing. I did notice, however, that when you generate a new square, it shows the numbers 1-25 (for a 5x5 square), in order, before quickly generating a fresh randomized square.

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  • How does the momentum/inertial scroll work with the Magic Mouse on NSScrollView?

    - by jbrennan
    When you scroll with the newer Apple Magic Mouse (at least on 10.6, I can't confirm any previous Mac OS) you get inertial scroll like scrolling on iPhone (that is, after a flick of the finger to scroll, it doesn't abruptly stop, but instead gradually slows down). This behaviour is "for free" with all NSScrollViews, it would appear. There are exceptional cases, such as Tweetie for Mac (I've heard Tweetie was written with a custom Table View class that works akin to how UITableView works on iPhone). My question is, how do the scroll views know how to do this inertial scrolling? My guess is the mouse [driver] repeatedly sends scroll events with a dampening scroll magnitude (or something like that) over the scroll period. But I'm not really sure how it works. I am having some scrolling problems in my scrollview class and I'm trying to figure out why (obviously we don't have the source code to Tweetie to see why it doesn't get the proper scrolling), but just trying to better understand how it works in order to fix my own problems.

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  • What is the magic behind perl read() function and buffer which is not a ref ?

    - by alex8657
    I do not get to understand how the Perl read($buf) function is able to modify the content of the $buf variable. $buf is not a reference, so the parameter is given by copy (from my c/c++ knowledge). So how come the $buf variable is modified in the caller ? Is it a tie variable or something ? The C documentation about setbuf is also quite elusive and unclear to me # Example 1 $buf=''; # It is a scalar, not a ref $bytes = $fh->read($buf); print $buf; # $buf was modified, what is the magic ? # Example 2 sub read_it { my $buf = shift; return $fh->read($buf); } my $buf; $bytes = read_it($buf); print $buf; # As expected, this scope $buf was not modified

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  • Apple wireless mouse and keyboard doens't work

    - by drigoSkalWalker
    I paired the mouse and keyboard on ubuntu, but it seems not work. I got this error in /var/log/syslog kernel: [ 1875.935712] input: Apple Magic Mouse as /devices/pci0000:00/0000:00:12.0/usb4/4-3/4-3:1.0/bluetooth/hci0/hci0:2/input34 kernel: [ 1875.935885] evdev: no more free evdev devices kernel: [ 1875.935893] input: failed to attach handler evdev to device input34, error: -23 kernel: [ 1875.936049] magicmouse 0005:05AC:030D.0003: input,hidraw0: BLUETOOTH HID v3.06 Mouse [Apple Magic Mouse] on 00:19:5D:0F:4A:F6 kernel: [ 2334.787710] input: Apple Wireless Keyboard as /devices/pci0000:00/0000:00:12.0/usb4/4-3/4-3:1.0/bluetooth/hci0/hci0:4/input36 kernel: [ 2334.787729] evdev: no more free evdev devices kernel: [ 2334.787737] input: failed to attach handler evdev to device input36, error: -23 kernel: [ 2334.787999] generic-bluetooth 0005:05AC:0255.0005: input,hidraw1: BLUETOOTH HID v0.50 Keyboard [Apple Wireless Keyboard] on 00:19:5D:0F:4A:F6 Nothing appears in xinput --list, only the wired mouse and keyboard. How to fix that?

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  • rotate a plane around a diagonal

    - by compie
    I would like to rotate a plane, not around a single (X or Y) axis, but around the diagonal (45 degrees between X and Y). How do I calculate the Rx and Ry given the Rdiagonal? (Rdiagonal is the amount of rotation I would like to achieve around the diagonal axis).

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  • What is the intention behind asking weight of plane?

    - by AKS
    I was asked this question "How would you find weight of Aeroplane" in an interview and I am not sure why this question was one of the two question asked in the interview. I tried to answer it using all possible ways but could not give the correct answer.(found the correct answer after google search) How much such questions decide your selection in the interview? Here was my approach: 1. If measurement of plane is given then i will calculate volume and multiply by density, will consider fuel weight plus other dead weight. 2. Using water displacement method if i can put plane in water and somehow measure how much water is displaced. But found using google search that right approach was to put place on a ship and mark the level of water on the hull, then remove plane and then ship will go up. And start putting weight on the ship till marked hull reaches the water level.

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  • Major Analyst Report Chooses Oracle As An ECM Leader

    - by brian.dirking(at)oracle.com
    Oracle announced that Gartner, Inc. has named Oracle as a Leader in its latest "Magic Quadrant for Enterprise Content Management" in a press release issued this morning. Gartner's Magic Quadrant reports position vendors within a particular quadrant based on their completeness of vision and ability to execute. According to Gartner, "Leaders have the highest combined scores for Ability to Execute and Completeness of Vision. They are doing well and are prepared for the future with a clearly articulated vision. In the context of ECM, they have strong channel partners, presence in multiple regions, consistent financial performance, broad platform support and good customer support. In addition, they dominate in one or more technology or vertical market. Leaders deliver a suite that addresses market demand for direct delivery of the majority of core components, though these are not necessarily owned by them, tightly integrated, unique or best-of-breed in each area. We place more emphasis this year on demonstrated enterprise deployments; integration with other business applications and content repositories; incorporation of Web 2.0 and XML capabilities; and vertical-process and horizontal-solution focus. Leaders should drive market transformation." "To extend content governance and best practices across the enterprise, organizations need an enterprise content management solution that delivers a broad set of functionality and is tightly integrated with business processes," said Andy MacMillan, vice president, Product Management, Oracle. "We believe that Oracle's position as a Leader in this report is recognition of the industry-leading performance, integration and scalability delivered in Oracle Enterprise Content Management Suite 11g." With Oracle Enterprise Content Management Suite 11g, Oracle offers a comprehensive, integrated and high-performance content management solution that helps organizations increase efficiency, reduce costs and improve content security. In the report, Oracle is grouped among the top three vendors for execution, and is the furthest to the right, placing Oracle as the most visionary vendor. This vision stems from Oracle's integration of content management right into key business processes, delivering content in context as people need it. Using a PeopleSoft Accounts Payable user as an example, as an employee processes an invoice, Oracle ECM Suite brings that invoice up on the screen so the processor can verify the content right in the process, improving speed and accuracy. Oracle integrates content into business processes such as Human Resources, Travel and Expense, and others, in the major enterprise applications such as PeopleSoft, JD Edwards, Siebel, and E-Business Suite. As part of Oracle's Enterprise Application Documents strategy, you can see an example of these integrations in this webinar: Managing Customer Documents and Marketing Assets in Siebel. You can also get a white paper of the ROI Embry Riddle achieved using Oracle Content Management integrated with enterprise applications. Embry Riddle moved from a point solution for content management on accounts payable to an infrastructure investment - they are now using Oracle Content Management for accounts payable with Oracle E-Business Suite, and for student on-boarding with PeopleSoft e-Campus. They continue to expand their use of Oracle Content Management to address further use cases from a core infrastructure. Oracle also shows its vision in the ability to deliver content optimized for online channels. Marketers can use Oracle ECM Suite to deliver digital assets and offers as part of an integrated campaign that understands website visitors and ensures that they are given the most pertinent information and offers. Oracle also provides full lifecycle management through its built-in records management. Companies are able to manage the lifecycle of content (both records and non-records) through built-in retention management. And with the integration of Oracle ECM Suite and Sun Storage Archive Manager, content can be routed to the appropriate storage media based upon content type, usage data or other business rules. This ensures that the most accessed content is instantly available, and archived content is stored on a more appropriate medium like tape. You can learn more in this webinar - Oracle Content Management and Sun Tiered Storage. If you are interested in reading more about why Oracle was chosen as a Leader, view the Gartner Magic Quadrant for Enterprise Content Management.

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  • OpenGL - Frustum not culling polygons beyond far plane

    - by Pladnius Brooks
    I have implemented frustum culling and am checking the bounding box for its intersection with the frustum planes. I added the ability to pause frustum updates which lets me see if the frustum culling has been working correctly. When I turn around after I have paused it, nothing renders behind me and to the left and right side, they taper off as well just as you would expect. Beyond the clip distance (far plane), they still render and I am not sure whether it is a problem with my frustum updating or bounding box checking code or I am using the wrong matrix or what. As I put the distance in the projection matrix at 3000.0f, it still says that bounding boxes well past that are still in the frustum, which isn't the case. Here is where I create my modelview matrix: projectionMatrix = glm::perspective(newFOV, 4.0f / 3.0f, 0.1f, 3000.0f); viewMatrix = glm::mat4(1.0); viewMatrix = glm::scale(viewMatrix, glm::vec3(1.0, 1.0, -1.0)); viewMatrix = glm::rotate(viewMatrix, anglePitch, glm::vec3(1.0, 0.0, 0.0)); viewMatrix = glm::rotate(viewMatrix, angleYaw, glm::vec3(0.0, 1.0, 0.0)); viewMatrix = glm::translate(viewMatrix, glm::vec3(-x, -y, -z)); modelViewProjectiomMatrix = projectionMatrix * viewMatrix; The reason I scale it by -1 in the Z direction is because the levels were designed to be rendered with DirectX so I reverse the Z direction. Here is where I update my frustum: void CFrustum::calculateFrustum() { glm::mat4 mat = camera.getModelViewProjectionMatrix(); // Calculate the LEFT side m_Frustum[LEFT][A] = (mat[0][3]) + (mat[0][0]); m_Frustum[LEFT][B] = (mat[1][3]) + (mat[1][0]); m_Frustum[LEFT][C] = (mat[2][3]) + (mat[2][0]); m_Frustum[LEFT][D] = (mat[3][3]) + (mat[3][0]); // Calculate the RIGHT side m_Frustum[RIGHT][A] = (mat[0][3]) - (mat[0][0]); m_Frustum[RIGHT][B] = (mat[1][3]) - (mat[1][0]); m_Frustum[RIGHT][C] = (mat[2][3]) - (mat[2][0]); m_Frustum[RIGHT][D] = (mat[3][3]) - (mat[3][0]); // Calculate the TOP side m_Frustum[TOP][A] = (mat[0][3]) - (mat[0][1]); m_Frustum[TOP][B] = (mat[1][3]) - (mat[1][1]); m_Frustum[TOP][C] = (mat[2][3]) - (mat[2][1]); m_Frustum[TOP][D] = (mat[3][3]) - (mat[3][1]); // Calculate the BOTTOM side m_Frustum[BOTTOM][A] = (mat[0][3]) + (mat[0][1]); m_Frustum[BOTTOM][B] = (mat[1][3]) + (mat[1][1]); m_Frustum[BOTTOM][C] = (mat[2][3]) + (mat[2][1]); m_Frustum[BOTTOM][D] = (mat[3][3]) + (mat[3][1]); // Calculate the FRONT side m_Frustum[FRONT][A] = (mat[0][3]) + (mat[0][2]); m_Frustum[FRONT][B] = (mat[1][3]) + (mat[1][2]); m_Frustum[FRONT][C] = (mat[2][3]) + (mat[2][2]); m_Frustum[FRONT][D] = (mat[3][3]) + (mat[3][2]); // Calculate the BACK side m_Frustum[BACK][A] = (mat[0][3]) - (mat[0][2]); m_Frustum[BACK][B] = (mat[1][3]) - (mat[1][2]); m_Frustum[BACK][C] = (mat[2][3]) - (mat[2][2]); m_Frustum[BACK][D] = (mat[3][3]) - (mat[3][2]); // Normalize all the sides NormalizePlane(m_Frustum, LEFT); NormalizePlane(m_Frustum, RIGHT); NormalizePlane(m_Frustum, TOP); NormalizePlane(m_Frustum, BOTTOM); NormalizePlane(m_Frustum, FRONT); NormalizePlane(m_Frustum, BACK); } And finally, where I check the bounding box: bool CFrustum::BoxInFrustum( float x, float y, float z, float x2, float y2, float z2) { // Go through all of the corners of the box and check then again each plane // in the frustum. If all of them are behind one of the planes, then it most // like is not in the frustum. for(int i = 0; i < 6; i++ ) { if(m_Frustum[i][A] * x + m_Frustum[i][B] * y + m_Frustum[i][C] * z + m_Frustum[i][D] > 0) continue; if(m_Frustum[i][A] * x2 + m_Frustum[i][B] * y + m_Frustum[i][C] * z + m_Frustum[i][D] > 0) continue; if(m_Frustum[i][A] * x + m_Frustum[i][B] * y2 + m_Frustum[i][C] * z + m_Frustum[i][D] > 0) continue; if(m_Frustum[i][A] * x2 + m_Frustum[i][B] * y2 + m_Frustum[i][C] * z + m_Frustum[i][D] > 0) continue; if(m_Frustum[i][A] * x + m_Frustum[i][B] * y + m_Frustum[i][C] * z2 + m_Frustum[i][D] > 0) continue; if(m_Frustum[i][A] * x2 + m_Frustum[i][B] * y + m_Frustum[i][C] * z2 + m_Frustum[i][D] > 0) continue; if(m_Frustum[i][A] * x + m_Frustum[i][B] * y2 + m_Frustum[i][C] * z2 + m_Frustum[i][D] > 0) continue; if(m_Frustum[i][A] * x2 + m_Frustum[i][B] * y2 + m_Frustum[i][C] * z2 + m_Frustum[i][D] > 0) continue; // If we get here, it isn't in the frustum return false; } // Return a true for the box being inside of the frustum return true; }

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  • width of a frustum at a given distance from the near plane

    - by structolite
    I'm using CML to manage the 3D math in an OpenGL-based interface project I'm making for work. I need to know the width of the viewing frustum at a given distance from the eye point, which is kept as a part of a 4x4 matrix that represents the camera. My goal is to position gui objects along the apparent edge of the viewport, but at some distance into the screen from the near clipping plane. CML has a function to extract the planes of the frustum, giving them back in Ax + By + Cz + D = 0 form. This frustum is perpendicular to the camera, which isn't necessarily aligned with the z axis of the perspective projection. I'd like to extract x and z coordinates so as to pin graphical elements to the sides of the screen at different distances from the camera. What is the best way to go about doing it? Thanks!

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  • Magic key in Linux Kernel

    - by Masi
    What is the purpose of the following command? sudo echo t > /proc/sysrq-trigger I run it, but I can see no difference in the magic key and its output at dmesg. Trigger suggests me that the databases of sysrq are involved in the process.

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  • Successful SQL Injection despite PHP Magic Quotes

    - by Crimson
    I have always read that Magic Quotes do not stop SQL Injections at all but I am not able to understand why not! As an example, let's say we have the following query: SELECT * FROM tablename WHERE email='$x'; Now, if the user input makes $x=' OR 1=1 --, the query would be: SELECT * FROM tablename WHERE email='\' OR 1=1 --'; The backslash will be added by Magic Quotes with no damage done whatsoever! Is there a way that I am not seeing where the user can bypass the Magic Quote insertions here?

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  • How do I make PHP's Magic __set work like a natural variable?

    - by Navarr
    Basically, what I want to do is create a class called Variables that uses sessions to store everything in it, allowing me to quickly get and store data that needs to be used throughout the entire site without working directly with sessions. Right now, my code looks like this: <?php class Variables { public function __construct() { if(session_id() === "") { session_start(); } } public function __set($name,$value) { $_SESSION["Variables"][$name] = $value; } public function __get($name) { return $_SESSION["Variables"][$name]; } public function __isset($name) { return isset($_SESSION["Variables"][$name]); } } However, when I try to use it like a natural variable, for example... $tpl = new Variables; $tpl->test[2] = Moo; echo($tpl->test[2]); I end up getting "o" instead of "Moo" as it sets test to be "Moo," completely ignoring the array. I know I can work around it by doing $tpl->test = array("Test","Test","Moo"); echo($tpl->test[2]); but I would like to be able to use it as if it was a natural variable. Is this possible?

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  • rpmbuild on Cent OS 6: "cpio: bad magic"

    - by djhaskin987
    When I try to run this command : rpmbuild -bb SPECS/software.spec I get an error when the WAR file (as in tomcat java web archive file) is being added to the rpm: error: create archive failed on file /<filepath>/<filename>.war: cpio: Bad magic This didn't use to happen. The only things that have changed since this worked was an upgrade. Further, no problems are happening like it on my CentOS 5 box. I compile and build the exact same code set on both machines, but CentOS 6 won't create an rpm. How do I troubleshoot this? I have already googled it and received few (if any) useful links. This appears nowhere in the user guide for RPM as far as I can see, and Maximum RPM has no section on this.

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  • Drag lock crisis with Windows 7 and Apple Magic Trackpad

    - by rockinthesixstring
    This is driving me insane and I've scowered the web for two days trying to fix this. I just picked up an Apple Magic Trackpad to be used exclusively on a Windows 7 PC (not apple with bootcamp). I found a nice driver that got it working right away, but when I'm moving the cursor around the screen, often it will begin "highlighting" text, or picking up and dragging things I don't want it to. I looked in the "regedit" where people are saying there is binary that can be changed, however the driver I installed doesn't use the binary being suggested. Can anyone suggest a better driver for my situation or a way to disable the drag lock that is driving me so nuts? I don't mind not being able to lift my finger when dragging, it's a far better compromise than having the insane feature.

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  • place and show pixel in the Cartesian plane graph in JavaFX

    - by user3671803
    I have this method to draw the Cartesian plane in JavaFX, using canvas and would like to know if it is possible to place or show the pixel: public class Grafics extends StackPane { private Canvas canvas; public void Grafics(){ GridPane grid = new GridPane(); grid.setPadding(new Insets(5)); grid.setHgap(10); grid.setVgap(10); canvas = new Canvas(); canvas.setHeight(500); canvas.setWidth(700); GridPane.setHalignment(canvas, HPos.CENTER); grid.add(canvas, 0, 2); GraphicsContext gc = canvas.getGraphicsContext2D(); gc.setFill(Color.BLACK); gc.fillRect(0, 0, canvas.getWidth(), canvas.getHeight()); gc.setFill(Color.WHITE); gc.fillRect(1, 1, canvas.getWidth() - 2, canvas.getHeight() - 2); drawAxesXY(gc); //call the method drawAxes getChildren().addAll(grid);// add an gridpane in stackpane } private void drawAxesXY(GraphicsContext gc1) { PixelWriter pixelWriter = canvas.getGraphicsContext2D().getPixelWriter(); gc1.setFill(Color.WHITE); gc1.setStroke(Color.BLACK); gc1.setLineWidth(1.5); gc1.strokeText("Y", 350, 30); gc1.scale(1, 1); gc1.translate((canvas.getHeight() / 50) - (canvas.getWidth() / 10), canvas.getHeight() / 50); gc1.strokeLine(canvas.getWidth() - 300, canvas.getWidth() - 300, canvas.getHeight() - 100, canvas.getHeight() / 30); pixelWriter.setColor(300, 300, Color.RED); gc1.strokeText("X", 620, 220); gc1.translate(canvas.getWidth() - (canvas.getHeight() / 10), -220); gc1.rotate(90.0); gc1.setFill(Color.WHITE); gc1.setStroke(Color.RED); gc1.setLineWidth(1.5); gc1.strokeLine(canvas.getWidth() - 250, canvas.getWidth() - 250, canvas.getHeight() - 50, canvas.getHeight() / 30); pixelWriter.setColor(620, 220, Color.RED); } } I put a line black and the other red http://postimg.org/image/tewjhco4z/ and I wanna know if is possible to place or show the pixel in Figure like this http://postimg.org/image/98k9mvnb3/

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