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  • Interpolation of time series data in R

    - by Pierreten
    I'm not sure what i'm missing here, but i'm basically trying to compute interpolated values for a time series; when I directly plot the series, constraining the interpolation points with "interpolation.date.vector", the plot is correct: plot(date.vector,fact.vector,ylab='Quantity') lines(spline(date.vector,fact.vector,xout=interpolation.date.vector)) When I compute the interpolation, store it in an intermediate variable, and then plot the results; I get a radically incorrect result: intepolated.values <- spline(date.vector,fact.vector,xout=interpolation.date.vector) plot(intepolated.values$x,intepolated.values$y) lines(testinterp$x,testinterp$y) Doesn't the lines() function have to execute the spline() function to retrieve the interpolated points in the same way i'm doing it?

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  • How to plot survey results on Excel?

    - by Mulone
    Hi all, I would like to plot the average of these data sample: 1. Contribution to the project 2. Affiliation with project owners 3. Level of expertise 4. Learning Curve Yes No 3 2 No No 3 2 No No 4 3 No No 5 3 No No 3 3 Yes Yes 5 4 No No 4 3 No No 3 2 No Yes 2 4 No No 5 2 No Yes 5 No answer No No 2 2 No No 3 3 ... Basically I know how to do the average of each numeric column, but I have a few questions for you: If the column contains non numeric values (e.g. "no answer") the average doesn't work. Is there a workaround for this? How can I count the yes/no results and plot only a percentage? Thanks for any hints! Mulone

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  • Excel: Plot order total in map coordinates

    - by Phliplip
    I have a set of data that looks like this: -X--Y----Amount- AE 24 $178,00 Y 27 $162,00 AD 34 $680,00 AK 35 $178,00 Y 25 $29,00 U 23 $178,00 X 38 $193,00 AC 30 $226,00 AK 39 $152,00 AJ 34 $217,00 AC 35 $183,00 AA 22 $211,00 Z 19 $172,00 AJ 32 $187,00 AF 26 $272,00 AI 27 $220,00 AJ 34 $320,00 AB 32 $183,00 AB 35 $272,00 AC 32 $207,00 AB 28 $178,00 AC 30 $168,00 AC 28 $178,00 AB 32 $310,00 AD 30 $188,00 AB 35 $188,00 The sample above is only an excerpt of the total dataset of 16K rows Each row represents a single delivery order, where the 2 first columns are the map coordinate and the third the purchase amount. Would it be possible to plot the above data in a chart or coordinate system. Where the each plot should be a summary of all sales in the same map coordinate. Also a similar chart of order count would be nice to have.

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  • How can I use gnuplot to plot data that is in an un-friendly format?

    - by Zack
    I need to graph some data that is not exactly in the most friendly format, most examples or usage puts things in a nice column/table that is very easy to parse and graph. However I have the following format (and am a bit stuck as to how to tackle this): DATE1 label_1 xx yy DATE1 label_2 xx yy DATE1 label_3 xx yy DATE2 label_2 xx yy DATE2 label_3 xx yy DATE3 label_1 xx yy DATE3 label_2 xx yy DATE3 label_3 xx yy DATE4 label_2 xx yy DATE4 label_3 xx yy ...continues *I've added the extra space between the dates for readability. **Note: under DATE2,DATE4 label_1 is missing, i.e. the data file may have labels that come and go and should represent a discontinuity in the graph. I'd like to have the X-axis use the DATEX for the labels, and then create two lines for each label (xx and yy respectively). Does anyone have any suggestions on the best way to tackle this problem?

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  • How can I plot a time series graph with Perl?

    - by Jazz
    I have some data from a database (SQLite), mapping a value (an integer) to a date. A date is a string with this format: YYYY-MM-DD hh:mm. The dates are not uniformly distributed. I want do draw a line graph with the dates on X and the values on Y. What is the easiest way to do this with Perl? I tried DBIx::Chart but I could not make it recognize my dates. I also tried GD::Graph, but as the documentation says: GD::Graph does not support numerical x axis the way it should. Data for X axes should be equally spaced

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  • Can IDL create a contour plot colorbar like this?

    - by Carthage
    At the bottom of this image, you'll see a nice colorbar that matches the colors of the graph correctly: http://stribog.cc.umanitoba.ca/ceos/20100517_00z_prod/ I couldn't find anything that created a color bar with exactly the colors I wanted, it always seemed to involve a spectrum that included colors I didn't use. I have a vector of colors I use for my data. Is there I way I can use that vector to create a color bar with only those colors?

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  • Graphing perpendicular offsets in a least squares regression plot in R

    - by D W
    I'm interested in making a plot with a least squares regression line and line segments connecting the datapoints to the regression line as illustrated here in the graphic called perpendicular offsets: http://mathworld.wolfram.com/LeastSquaresFitting.html I have the plot and regression line done here: ## Dataset from http://www.apsnet.org/education/advancedplantpath/topics/RModules/doc1/04_Linear_regression.html ## Disease severity as a function of temperature # Response variable, disease severity diseasesev<-c(1.9,3.1,3.3,4.8,5.3,6.1,6.4,7.6,9.8,12.4) # Predictor variable, (Centigrade) temperature<-c(2,1,5,5,20,20,23,10,30,25) ## Fit a linear model for the data and summarize the output from function lm() severity.lm <- lm(diseasesev~temperature,data=severity) # Take a look at the data plot( diseasesev~temperature, data=severity, xlab="Temperature", ylab="% Disease Severity", pch=16 ) abline(severity.lm,lty=1) title(main="Graph of % Disease Severity vs Temperature") Should I use some kind of for loop and segments http://www.iiap.res.in/astrostat/School07/R/html/graphics/html/segments.html to do the perpendicular offsets? Is there a more efficient way? Please provide an example if possible.

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  • Error when trying to create a faceted plot in ggplot2

    - by John Horton
    I am trying to make a faceted plot in ggplot2 of the coefficients on the regressors from two linear models with the same predictors. The data frame I constructed is this: r.together> reg coef se y 1 (Intercept) 5.068608671 0.6990873 Labels 2 goodTRUE 0.310575129 0.5228815 Labels 3 indiaTRUE -1.196868662 0.5192330 Labels 4 moneyTRUE -0.586451273 0.6011257 Labels 5 maleTRUE -0.157618168 0.5332040 Labels 6 (Intercept) 4.225580743 0.6010509 Bonus 7 goodTRUE 1.272760149 0.4524954 Bonus 8 indiaTRUE -0.829588862 0.4492838 Bonus 9 moneyTRUE -0.003571476 0.5175601 Bonus 10 maleTRUE 0.977011737 0.4602726 Bonus The "y" column is a label for the model, reg are the regressors and coef and se are what you would think. I want to plot: g <- qplot(reg, coef, facets=.~y, data = r.together) + coord_flip() But when I try to display the plot, I get: > print(g) Error in names(df) <- output : 'names' attribute [2] must be the same length as the vector [1] What's strange is that qplot(reg, coef, colour=y, data = r.together) + coord_flip() plots as you would expect.

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  • Add title to meta analysis forest plot

    - by Timothy Alston
    I am meta-analysing some studies and drawing a forest plot for my results. However I can`t seem to get the forest plot to display the title. An example of my code is: require(meta) parameter1<-metaprop(sm="PLOGIT", event=c(4,16,3,2,10,1,0,2), n=c(90,402,89,29,153,86,21,48), level = 0.95, studlab=c("study 1", "study 2", "study 3", "study 4", "study 5", "study 6", "study 7", "study 8"), title="meta analysis 1") forest(parameter1) When it produces the forest plot, the title "meta analysis 1" is missing. How can I add this in? Thanks in advance, Timothy

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  • Pixel plot method errors out without error message.

    - by sonny5
    // The following method blows up (big red x on screen) without generating error info. Any // ideas why? // MyPlot.PlotPixel(x, y, Color.BlueViolet, Grf); // runs if commented out // My goal is to draw a pixel on a form. Is there a way to increase the pixel size also? using System; using System.Drawing; using System.Drawing.Drawing2D; using System.Collections; using System.ComponentModel; using System.Windows.Forms; using System.Data; public class Plot : System.Windows.Forms.Form { private Size _ClientArea; //keeps the pixels info private double _Xspan; private double _Yspan; public Plot() { InitializeComponent(); } public Size ClientArea { set { _ClientArea = value; } } private void InitializeComponent() { this.AutoScaleBaseSize = new System.Drawing.Size(5, 13); this.ClientSize = new System.Drawing.Size(400, 300); this.Text="World Plot (world_plot.cs)"; this.Resize += new System.EventHandler(this.Form1_Resize); this.Paint += new System.Windows.Forms.PaintEventHandler(this.doLine); this.Paint += new System.Windows.Forms.PaintEventHandler(this.TransformPoints); // new this.Paint += new System.Windows.Forms.PaintEventHandler(this.DrawRectangleFloat); this.Paint += new System.Windows.Forms.PaintEventHandler(this.DrawWindow_Paint); } private void DrawWindow_Paint(object sender, PaintEventArgs e) { Graphics Grf = e.Graphics; pixPlot(Grf); } static void Main() { Application.Run(new Plot()); } private void doLine(object sender, System.Windows.Forms.PaintEventArgs e) { // no transforms done yet!!! Graphics g = e.Graphics; g.FillRectangle(Brushes.White, this.ClientRectangle); Pen p = new Pen(Color.Black); g.DrawLine(p, 0, 0, 100, 100); // draw DOWN in y, which is positive since no matrix called p.Dispose(); } public void PlotPixel(double X, double Y, Color C, Graphics G) { Bitmap bm = new Bitmap(1, 1); bm.SetPixel(0, 0, C); G.DrawImageUnscaled(bm, TX(X), TY(Y)); } private int TX(double X) //transform real coordinates to pixels for the X-axis { double w; w = _ClientArea.Width / _Xspan * X + _ClientArea.Width / 2; return Convert.ToInt32(w); } private int TY(double Y) //transform real coordinates to pixels for the Y-axis { double w; w = _ClientArea.Height / _Yspan * Y + _ClientArea.Height / 2; return Convert.ToInt32(w); } private void pixPlot(Graphics Grf) { Plot MyPlot = new Plot(); double x = 12.0; double y = 10.0; MyPlot.ClientArea = this.ClientSize; Console.WriteLine("x = {0}", x); Console.WriteLine("y = {0}", y); //MyPlot.PlotPixel(x, y, Color.BlueViolet, Grf); // blows up } private void DrawRectangleFloat(object sender, PaintEventArgs e) { // Create pen. Pen penBlu = new Pen(Color.Blue, 2); // Create location and size of rectangle. float x = 0.0F; float y = 0.0F; float width = 200.0F; float height = 200.0F; // translate DOWN by 200 pixels // Draw rectangle to screen. e.Graphics.DrawRectangle(penBlu, x, y, width, height); } private void TransformPoints(object sender, System.Windows.Forms.PaintEventArgs e) { // after transforms Graphics g = this.CreateGraphics(); Pen penGrn = new Pen(Color.Green, 3); Matrix myMatrix2 = new Matrix(1, 0, 0, -1, 0, 0); // flip Y axis with -1 g.Transform = myMatrix2; g.TranslateTransform(0, 200, MatrixOrder.Append); // translate DOWN the same distance as the rectangle... // ...so this will put it at lower left corner g.DrawLine(penGrn, 0, 0, 100, 90); // notice that y 90 is going UP } private void Form1_Resize(object sender, System.EventArgs e) { Invalidate(); } }

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  • Mixing Matplotlib patches with polar plot?

    - by Roger
    I'm trying to plot some data in polar coordinates, but I don't want the standard ticks, labels, axes, etc. that you get with the Matplotlib polar() function. All I want is the raw plot and nothing else, as I'm handling everything with manually drawn patches and lines. Here are the options I've considered: 1) Drawing the data with polar(), hiding the superfluous stuff (with ax.axes.get_xaxis().set_visible(False), etc.) and then drawing my own axes (with Line2D, Circle, etc.). The problem is when I call polar() and subsequently add a Circle patch, it's drawn in polar coordinates and ends up looking like an infinity symbol. Also zooming doesn't seem to work with the polar() function. 2) Skip the polar() function and somehow make my own polar plot manually using Line2D. The problem is I don't know how to make Line2D draw in polar coordinates and haven't figured out how to use a transform to do that. Any idea how I should proceed?

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  • How do i plot a vertical axis with variable intervals (Flex Charts or any other)

    - by satish
    How do i plot a vertical axis with variable intervals? on a Flex Chart. I want to plot a data set that has values from 0.1 to 800. When I use a standard Numerical Axis, I have to define a interval. I tried using Log-Axis, but I am not sure how to plot the point values. Looks like something in lines of semi-log axis would be better. A axis with initial values in Numerical, but later shifting gears to a Log-Axis. Any ideas or pointers to implement this in Flex?

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  • plot only x and y axis (no box) in ggplot2

    - by Tyler Rinker
    The convention of some journals is to show only the x and y axis in a plot not a box around the entire plot area. How can I achieve this in ggplot2? I tried theme_minimal_cb_L from HERE but it seems to erase the entire box around the plot (does not leave the x and y axis) as seen here: Here's the code I'm using: dat <- structure(list(x = c(0.7, 0.75, 0.8, 0.85, 0.9, 0.95, 1, 1.05, 1.1, 1.15, 1.2, 1.25, 1.3), y1 = c(34, 30, 26, 23, 21, 19, 17, 16, 15, 13, 12, 12, 11), y2 = c(45, 39, 34, 31, 28, 25, 23, 21, 19, 17, 16, 15, 14)), .Names = c("x", "y1", "y2"), row.names = c(NA, -13L), class = "data.frame") library(reshape2); library(ggplot2) dat2 <- melt(dat, id='x') theme_minimal_cb_L <- function (base_size = 12, base_family = "", ...){ modifyList (theme_minimal (base_size = base_size, base_family = base_family), list (axis.line = element_line (colour = "black"))) } ggplot(data=dat2, aes(x=x, y=value, color=variable)) + geom_point(size=3) + geom_line(size=.5) + theme_minimal_cb_L()

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  • matplotlib 3D plot with PyQt4 in Qtabwidget (mplwidget)

    - by artdijk
    I am working on my first Python app using PythonXY (2.6 and Qt4). I have a window with some buttons and a QtabWidget. When I press a button I want to plot a 3D image on a specific tab. I managed to get a 2D plot but I can't get the axes to 3D. Via Qt desiger I use the mplwidget. In many examples I see the use of figure(), but I can't get that to work with the mplwidget. (I am not sure if that is even possible) Can you please show me an example of code defining the 3D axes (in a QtabWidget) with a simple plot ? Thanks very much

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  • Howto plot two cumulative frequency graph together

    - by neversaint
    I have data that looks like this: #val Freq1 Freq2 0.000 178 202 0.001 4611 5300 0.002 99 112 0.003 26 30 0.004 17 20 0.005 15 20 0.006 11 14 0.007 11 13 0.008 13 13 ...many more lines.. Full data can be found here: http://dpaste.com/173536/plain/ What I intend to do is to have a cumulative graph with "val" as x-axis with "Freq1" & "Freq2" as y-axis, plot together in 1 graph. I have this code. But it creates two plots instead of 1. dat <- read.table("stat.txt",header=F); val<-dat$V1 freq1<-dat$V2 freq2<-dat$V3 valf1<-rep(val,freq1) valf2<-rep(val,freq2) valfreq1table<- table(valf1) valfreq2table<- table(valf2) cumfreq1=c(0,cumsum(valfreq1table)) cumfreq2=c(0,cumsum(valfreq2table)) plot(cumfreq1, ylab="CumFreq",xlab="Loglik Ratio") lines(cumfreq1) plot(cumfreq2, ylab="CumFreq",xlab="Loglik Ratio") lines(cumfreq2) What's the right way to approach this?

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  • matplotlib.pyplot/pylab not updating figure while isinteractive(), using ipython -pylab

    - by NumberOverZero
    There are a lot of questions about matplotlib, pylab, pyplot, ipython, so I'm sorry if you're sick of seeing this asked. I'll try to be as specific as I can, because I've been looking through people's questions and looking at documentation for pyplot and pylab, and I still am not sure what I'm doing wrong. On with the code: Goal: plot a figure every .5 seconds, and update the figure as soon as the plot command is called. My attempt at coding this follows (running on ipython -pylab): import time ion() x=linspace(-1,1,51) plot(sin(x)) for i in range(10): plot([sin(i+j) for j in x]) #see ** print i time.sleep(1) print 'Done' It correctly plots each line, but not until it has exited the for loop. I have tried forcing a redraw by putting draw() where ** is, but that doesn't seem to work either. Ideally, I'd like to have it simply add each line, instead of doing a full redraw. If redrawing is required however, that's fine. Additional attempts at solving: just after ion(), tried adding hold(True) to no avail. for kicks tried show() for ** The closest answer I've found to what I'm trying to do was at http://stackoverflow.com/questions/2310851/plotting-lines-without-blocking-execution, but show() isn't doing anything. I apologize if this is a straightforward request, and I'm looking past something so obvious. For what it's worth, this came up while I was trying to convert matlab code from class to some python for my own use. The original matlab (initializations removed) which I have been trying to convert follows: for i=1:time plot(u) hold on pause(.01) for j=2:n-1 v(j)=u(j)-2*u(j-1) end v(1)= pi u=v end Any help, even if it's just "look up this_method" would be excellent, so I can at least narrow my efforts to figuring out how to use that method. If there's any more information that would be useful, let me know.

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  • MATLAB fill area between lines

    - by dustynrobots
    I'm trying to do something similar to what's outlined in this post: MATLAB, Filling in the area between two sets of data, lines in one figure but running into a roadblock. I'm trying to shade the area of a graph that represents the mean +/- standard deviation. The variable definitions are a bit complicated but it boils down to this code, and when plotted without shading, I get the screenshot below: x = linspace(0, 100, 101)'; mean = torqueRnormMean(:,1); meanPlusSTD = torqueRnormMean(:,1) + torqueRnormStd(:,1); meanMinusSTD = torqueRnormMean(:,1) - torqueRnormStd(:,1); plot(x, mean, 'k', 'LineWidth', 2) plot(x, meanPlusSTD, 'k--') plot(x, meanMinusSTD, 'k--') But when I try to implement shading just on the lower half of the graph (between mean and meanMinusSTD) by adding the code below, I get a plot that looks like this: fill( [x fliplr(x)], [mean fliplr(meanMinusSTD)], 'y', 'LineStyle','--'); It's obviously not shading the correct area of the graph, and new near-horizontal lines are being created close to 0 that are messing with the shading. Any thoughts? I'm stumped.

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  • Strange Matlab error: "??? Subscript indices must either be real positive integers or logicals"

    - by Roee Adler
    I have a function func that returns a vector a. I usually plot a and then perform further analysis on it. I have a certain scenario when once I try to plot a, I get a "??? Subscript indices must either be real positive integers or logicals" error. Take a look at the following piece of code to see the vector's behavior: K>> a a = 5.7047 6.3529 6.4826 5.5750 4.1488 5.8343 5.3157 5.4454 K>> plot(a) ??? Subscript indices must either be real positive integers or logicals. K>> for i=1:length(a); b(i) = a(i); end; K>> b b = 5.7047 6.3529 6.4826 5.5750 4.1488 5.8343 5.3157 5.4454 K>> plot(b) ??? Subscript indices must either be real positive integers or logicals. The scenario where this happens is when I call function func from within another function (call it outer_func), and return the result directly as outer_func's result. When debugging inside outer_func, I can plot a properly, but outside the scope of outer_func, its result has the above behavior. What can cause this? Where do I start from?

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  • Calculate area under FFT graph in Matlab

    - by lytheone
    Hiya, Currently I did a FFT of a set of data which gives me a plot with frequency at x axis and amplitude at y axis. I would like to calculate out the area under graph to give me energy. I am not sure how to determinate the area because i am without the equation and also i only want a certain area of the plot rather than whole area under the plot. Is there a way i can do it?

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  • Plotting a grouped 2 dimensional vector in MATLAB

    - by Hossein
    I am trying to make a plot of a 2-dimensional vector (2D Plot). But I don't want all the datapoints to have the same color on the plot. Each datapoint corresponds to a group. I want to have different colors for each group of datapoints. class=[1 3 2 5 2 5 1 3 3 4 2 2 2] says each datapoint belongs to which group X=[x1,y1;x2,y2;x3,y3;.....] the number of these datapoints are the same as the number of elements in the class vector. Now I want to plot these based on colors.

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  • Plotting a grouped 2 dimensional vevtor in MATLAB

    - by Hossein
    Hi, I am trying to make a plot of a 2-Dimensional vector(2D Plot).But I don't want all the datapoints to have the same color on the plot.Each datapoint corresponds to a group.I want to have different colors for each group of datapoints. class=[1 3 2 5 2 5 1 3 3 4 2 2 2] says each datapoint belongs to which group X=[x1,y1;x2,y2;x3,y3;.....] the number of thes datapoints are the same as the number of elements in th class vector. Now I want to plot these based on colors. Can someone help me? Thanks

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  • Plot numpy datetime64 with matplotlib

    - by enedene
    I have two numpy arrays 1D, one is time of measurement in datetime64 format, for example: array([2011-11-15 01:08:11, 2011-11-16 02:08:04, ..., 2012-07-07 11:08:00], dtype=datetime64[us]) and other array of same length and dimension with integer data. I'd like to make a plot in matplotlib time vs data. If I put the data directly, this is what I get: plot(timeSeries, data) Is there a way to get time in more natural units? For example in this case months/year would be fine.

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  • R: How to plot data grouped by a factor, but not as a boxplot

    - by amarillion
    In R, given a vector casp6 <- c(0.9478638, 0.7477657, 0.9742675, 0.9008372, 0.4873001, 0.5097587, 0.6476510, 0.4552577, 0.5578296, 0.5728478, 0.1927945, 0.2624068, 0.2732615) and a factor: trans.factor <- factor (rep (c("t0", "t12", "t24", "t72"), c(4,3,3,3))) I want to create a plot where the data points are grouped as defined by the factor. So the categories should be on the x-axis, values in the same category should have the same x coordinate. Simply doing plot(trans.factor, casp6) does almost what I want, it produces a boxplot, but I want to see the individual data points.

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