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matplotlib.pyplot, preserve aspect ratio of the plot

- by Headcrab

Assuming we have a polygon coordinates as polygon = [(x1, y1), (x2, y2), ...], the following code displays the polygon: import matplotlib.pyplot as plt plt.fill(*zip(*polygon)) plt.show() By default it is trying to adjust the aspect ratio so that the polygon (or whatever other diagram) fits inside the window, and automatically changing it so that it fits even after resizing. Which is great in many cases, except when you are trying to estimate visually if the image is distorted. How to fix the aspect ratio to be strictly 1:1? (Not sure if "aspect ratio" is the right term here, so in case it is not - I need both X and Y axes to have 1:1 scale, so that (0, 1) on both X and Y takes an exact same amount of screen space. And I need to keep it 1:1 no matter how I resize the window.)

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Core-Plot graph in a UIViewController

- by Kenneth

Hi guys, im trying to put a Coreplot graph in a UIView. Some questions, should i do it in XIB? or should i do it programmically ? If so how should i write the codes? etc. I actually have two Classes. one called GraphView which is supposed to hold the Coreplot graph. Another called CorePlotViewController. Thx for looking guys.

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program R- in ggplot restrict y to be >0 in LOESS plot

- by Nate

Here's my code: qplot(data=sites, x, y, main="Site 349") (p <- qplot(data = sites, x, y, xlab = "", ylab = "")) (p1 <- p + geom_smooth(method = "loess",span=0.5, size = 1.5)) p1 + theme_bw() + opts(title = "Site 349") Some of the LOESS lines and confidence intervals go below zero, but I would like to restrict the graphics to 0 and positive numbers (because negative do not make sense). How can I do this?

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Difference between chart, plot and graph

- by Pradyumna

I'm thinking of what would be the right terms to use in the UI of my new program, when referring to graphical data representations - i.e., whether to call them "charts", "plots" or "graphs". I was wondering how these terms are different, and when is it appropriate to use each of them? Thanks, Pradyumna

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MATLAB: Need to make a 4D plot (3D + Colour/Color)

- by user1305624

I need to make a 3D surface where colour will represent the fourth variable. I know "surf" is SIMILAR to what I need, but that's not quite it. Basically, I have the following variables: t = [1:m] y = [1:n] a = [1:o] These should be the three Cartesian corodinate axes. I also have a variable S that is of dimensions m x n x o, and is basically the amplitude, a function of the previous three variables (i.e. S = f(t,y,a)). I want this to be represented by colour. So to summarize, I need a graph of the form (t,y,a,S), where the first three variables are vectors of unequal sizes and the final variable is a multidimensional array whose dimensions are determined by the first three. Thanks in advance.

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plot a line graph in vb.net

- by Husna5207

this is my function for plotting a graph in vb.net how I'm going to replace the ("Jon", 10),("Jordan", 30) with a value that i search from database ? Private Sub chart_btn_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles chart_btn.Click Chart1.Series("Student").Points.AddXY("Jon", 10) Chart1.Series("Student").Points.AddXY("Jon", 10) Chart1.Series("Student").ChartType = System.Windows.Forms.DataVisualization.Charting.SeriesChartType.Bar End Sub

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Plot multiple files

- by LucaB

Hi I'd like to make an animation that illustrates the positions of some agents I'm simulating under Linux. Basically, I have some files named file00001.dat, file00002.dat and so on. I have to generate "something" that get files in order, and output an animated gif, a dynamic graph or whatever, that simulates the moving reading data from file. I have control on the files, meaning that I can put identifiers or everything I want. How would you achieve that? What programs would you use?

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LAbeling with Percentage in R plot

- by Libo Cannici

Hi I have made this function that takes a table and prepare the label for a barplot prepare_labels <- function(ft){ labs <- ft labs <- paste(labs, "\n", sep="") labs <- paste(labs, round(prop.table(ft)*100,2), sep="") labs <- paste(labs, "%", sep="") return(labs) } It actually works fine, but is there any better way to write that function, the above code looks ugly and I want to write beautiful code :-) ex: ft <- table(mydata$phone_partner_products) prepare_labels(ft) [1] "3752\n34.09%" "226\n2.05%" "2907\n26.41%" "1404\n12.76%" "1653\n15.02%" [6] "1065\n9.68%"

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Matlab multiple graph types inside one graph

- by mirekys

Hi, I have a task to draw electrostatic field between two electrodes( at given sizes and shape ), what i have now is that i draw the electrodes with area plot (area(elect_x,elect_y)) the graph looks like this: ------------------.--- |.. .---. |.. |...| |.. .----....| |.. |........| |.. ---------------------- and now i would need to draw inside this probably a mesh, showing the field. Is there any way to do it, or i´m on a wrong way? Thank you very much for every guide

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Toottip data issue in jquery flot

- by Muhammad

I am using Jquery plot.Every thing is working except tooltip data. Total data shown on a line is 190 which is equal to total published PLUS total unpublished.Total Published is 51 which is shown in tooltip.Now the other portion of tooltip shows 190 instead of 190-51 = 139 here is my code var options1 = { series: {stack: stack, lines: { show: lines, fill: false, steps: steps }, bars: { show: bars, barWidth: 0.4 }, points: { show: true} }, grid: { hoverable: true //IMPORTANT! this is needed for tooltip to work }, tooltip: true, tooltipOpts: { content: "%s : %y", shifts: { x: -60, y: 25 } }, legend:{'position':'ne','show':true,'margin':[-3, -20],'backgroundOpacity':0.1, 'noColumns': 4, 'container': null}, xaxis: {ticks: dest4 ,}, }; what i should do with this line to show exact data content: "%s : %y",

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subplot matplotlib wrong syntax

- by madptr

I am using matplotlib to subplot in a loop. For instance, i would like to subplot 49 data sets, and from the doc, i implemented it this way; import numpy as np import matplotlib.pyplot as plt X1=list(range(0,10000,1)) X1 = [ x/float(10) for x in X1 ] nb_mix = 2 parameters = [] for i in range(49): param = [] Y = [0] * len(X1) for j in range(nb_mix): mean = 5* (1 + (np.random.rand() * 2 - 1 ) * 0.5 ) var = 10* (1 + np.random.rand() * 2 - 1 ) scale = 5* ( 1 + (np.random.rand() * 2 - 1) * 0.5 ) Y = [ Y[k] + scale * np.exp(-((X1[k] - mean)/float(var))**2) for k in range(len(X1)) ] param = param + [[mean, var, scale]] ax = plt.subplot(7, 7, i + 1) ax.plot(X1, Y) parameters = parameters + [param] ax.show() However, i have an index out of range error from i=0 onwards. Where can i do better to have it works ? Thanks

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Reading Matrices in MATLAB and assigning coordinates to the entries

- by Michael Schofield

Hi, I'm a bit new to MATLAB. Basically, I have a 25x25 Matrix, complete with various random entries ranging from 0 to 3. I need to write a program that reads this matrix, and assigns x-y coordinates to the entries, so that when I ask for an input of a particular x-y coordinate which has, say an entry of 3, then it will result in an error. I'm a bit overwhelmed - but I understand the general concept of what I'm supposed to be finding. I'm wondering if I should use a plot instead to help me.

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Matlab Error- fplot();

- by udsha

>> fplot(fh,[-2 4]) ??? Undefined function or variable "e". Error in ==> myfun at 3 Y(:,2) = e(:).^x; Error in ==> fplot at 102 x = xmin; y = feval(fun,x,args{4:end}); I tried to plot two function using this m file. function Y = myfun(x) Y(:,1) = 3*x; Y(:,2) = e(:).^x;

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App crashes only after second execution only in Release configuration

- by denbec

Hey all, i know this is probably not an easy question to answer, as it's hard to describe on my hand. I have an app that runs without problems on the device in Debug Configuration (also multiple times). Once I put it into Release Configuration (which I need before publishing?), the app starts without problems and I can proceed to the next page, where I show an core-plot graph. BUT only if I run it from xcode. As soon as I end the App and start it again, it opens without problems, but on the next page, it crashes. Now I don't have anything to debug other than the crash report: Exception Type: EXC_BAD_ACCESS (SIGSEGV) Exception Codes: KERN_INVALID_ADDRESS at 0xcf10000a Crashed Thread: 0 Thread 0 Crashed: 0 libobjc.A.dylib 0x000026f2 objc_msgSend + 14 1 StandbyCheck 0x0001fbea -[CPXYTheme newGraph] (CPXYTheme.m:36) 2 StandbyCheck 0x00007c06 -[SCGraphCell initWithStyle:reuseIdentifier:] (SCGraphCell.m:28) 3 StandbyCheck 0x00076b4a -[TTTableViewDataSource tableView:cellForRowAtIndexPath:] (TTTableViewDataSource.m:128) 4 UIKit 0x0007797a -[UITableView(UITableViewInternal) _createPreparedCellForGlobalRow:withIndexPath:] + 514 5 UIKit 0x000776b0 -[UITableView(UITableViewInternal) _createPreparedCellForGlobalRow:] + 28 6 UIKit 0x00037e78 -[UITableView(_UITableViewPrivate) _updateVisibleCellsNow] + 940 7 UIKit 0x000367d4 -[UITableView layoutSubviews] + 176 8 StandbyCheck 0x000734b8 -[TTTableView layoutSubviews] (TTTableView.m:226) [...] Now, can someone point in any direction? What are the differences in Debug/Release Modes? How could I possibly debug this failure? I've been searching for hours now, please help me :( Thanks, Dennis

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Cannot change font size /type in plots

- by Sameet Nabar

I recently had to re-install my operating system (Ubuntu). The only thing I did differently is that I installed Matlab on a separate partition, not the main Ubuntu partition. After re-installing, the fonts in my plots are no longer configurable. For example, if I ask the title font to be bold, it doesn't happen. I ran the sample code below on my computer and then on my colleague's computer and the 2 results are attached. This cannot be a problem with the code; rather in the settings of Matlab. Could somebody please tell me what settings I need to change? Thanks in advance for your help. Regards, Sameet. x1=-pi:.1:pi; x2=-pi:pi/10:pi; y1=sin(x1); y2=tan(sin(x2)) - sin(tan(x2)); [AX,H1,H2]=plotyy(x1,y1,x2,y2); xlabel ('Time (hh:mm)'); ylabel (AX(1), 'Plot1'); ylabel (AX(2), 'Plot2'); axes(AX(2)) set(H1,'linestyle','none','marker','.'); set(H2,'linestyle','none','marker','.'); title('Plot Title','FontWeight','bold'); set(gcf, 'Visible', 'off'); [legh, objh] = legend([H1 H2],'Plot1', 'Plot2','location','Best'); set(legend,'FontSize',8); print -dpng Trial.png; Bad image: http://imageshack.us/photo/my-images/708/trial1u.png/ Good image: http://imageshack.us/photo/my-images/87/trial2.png/

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How to find "y" values of the already estimated monotone function of the non-monotone regression curve corresponding to the original "x" points?

- by parenthesis

The title sounds complicated but that is what I am looking for. Focus on the picture. ## data x <- c(1.009648,1.017896,1.021773,1.043659,1.060277,1.074578,1.075495,1.097086,1.106268,1.110550,1.117795,1.143573,1.166305,1.177850,1.188795,1.198032,1.200526,1.223329,1.235814,1.239068,1.243189,1.260003,1.262732,1.266907,1.269932,1.284472,1.307483,1.323714,1.326705,1.328625,1.372419,1.398703,1.404474,1.414360,1.415909,1.418254,1.430865,1.431476,1.437642,1.438682,1.447056,1.456152,1.457934,1.457993,1.465968,1.478041,1.478076,1.485995,1.486357,1.490379,1.490719) y <- c(0.5102649,0.0000000,0.6360097,0.0000000,0.8692671,0.0000000,1.0000000,0.0000000,0.4183691,0.8953987,0.3442624,0.0000000,0.7513169,0.0000000,0.0000000,0.0000000,0.0000000,0.1291901,0.4936121,0.7565551,1.0085108,0.0000000,0.0000000,0.1655482,0.0000000,0.1473168,0.0000000,0.0000000,0.0000000,0.1875293,0.4918018,0.0000000,0.0000000,0.8101771,0.6853480,0.0000000,0.0000000,0.0000000,0.0000000,0.4068802,1.1061434,0.0000000,0.0000000,0.0000000,0.0000000,0.0000000,0.0000000,0.0000000,0.0000000,0.0000000,0.6391678) fit1 <- c(0.5102649100,0.5153380934,0.5177234836,0.5255544980,0.5307668662,0.5068087080,0.5071001179,0.4825657520,0.4832969250,0.4836378194,0.4842147729,0.5004039310,0.4987301366,0.4978800742,0.4978042478,0.4969807064,0.5086987191,0.4989497612,0.4936121200,0.4922210302,0.4904593166,0.4775197108,0.4757040857,0.4729265271,0.4709141776,0.4612406896,0.4459316517,0.4351338346,0.4331439717,0.4318664278,0.3235179189,0.2907908968,0.1665721429,0.1474035158,0.1443999345,0.1398517097,0.1153991839,0.1142140393,0.1022584672,0.1002410843,0.0840033244,0.0663669309,0.0629119398,0.0627979240,0.0473336492,0.0239237481,0.0238556876,0.0084990298,0.0077970954,0.0000000000,-0.0006598571) fit2 <- c(-0.0006598571,0.0153328298,0.0228511733,0.0652889427,0.0975108758,0.1252414661,0.1270195143,0.1922510501,0.2965234797,0.3018551305,0.3108761043,0.3621749370,0.4184150225,0.4359301495,0.4432114081,0.4493565757,0.4510158144,0.4661865431,0.4744926045,0.4766574718,0.4796937554,0.4834718810,0.4836125426,0.4839450098,0.4841092849,0.4877317306,0.4930561638,0.4964939389,0.4970089201,0.4971376528,0.4990394601,0.5005881678,0.5023814257,0.5052125977,0.5056691690,0.5064254338,0.5115481820,0.5117259449,0.5146054557,0.5149729419,0.5184178197,0.5211542908,0.5216215426,0.5216426533,0.5239797875,0.5273573222,0.5273683002,0.5293994824,0.5295130266,0.5306236672,0.5307303109) ## picture plot(x, y) ## red regression curve points(x, fit1, col=2); lines(x, fit1, col=2) ## blue monotonic curve to the regression points(min(x) + cumsum(c(0, rev(diff(x)))), rev(fit2), col="blue"); lines(min(x) + cumsum(c(0, rev(diff(x)))), rev(fit2), col="blue") ## "x" original point matches with the regression estimated point ## but not with the estimated (fit2=estimate) monotonic curve abline(v=1.223329, lty=2, col="grey") Focus on the dashed grey line. The idea is to get y value of the monotonic blue curve corresponding to x original value. The grey line should cross three points (the original one "black", the regression estimate "red", the adjusted regression estimate "blue"). Can we do this? Methodology: The object "fit2" is the output of the function rearrangement(). It is always monotonically increasing. library(Rearrangement) fit2 <- rearrangement(x=as.data.frame(x), y=fit1)

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How to code a time delay between plotting points in JFreeCharts?

- by Javajava

Is there a way to animate the plotting process of an xy-line chart using JFreeCharts? I want to be able to watch the program draw each line segment and connect them. For example, if I paste this into the TextArea, "gtgtaaacaatatatggcg," I want to watch it graph each line segment one by one. Thanks in advance! :) My code is below: import java.util.Scanner; import java.applet.Applet; import java.awt.; import java.awt.event.ActionListener; import java.awt.event.ActionEvent; import org.jfree.chart.; import org.jfree.chart.plot.PlotOrientation; import org.jfree.data.xy.*; public class RandomWalkComplete extends Applet implements ActionListener { Panel panel; TextArea textarea, outputArea; Button move,exit; String thetext; Scanner reader = new Scanner(System.in); String thetext2; Label instructions; int x,y; public void init() { setSize(500,250); //set size of applet instructions=new Label("Paste the gene sequences in the " + "text field and press the graph button."); add(instructions); panel = new Panel(); add(panel); setVisible(true); textarea= new TextArea(10,20); add(textarea); move=new Button("Graph"); move.addActionListener(this); add(move); exit=new Button("Exit"); exit.addActionListener(this); add(exit); } public void actionPerformed(ActionEvent e) { XYSeries series = new XYSeries("DNA Walk",false,true); x= 0; y = 0; series.add(x,y); if(e.getSource() == move) { thetext=textarea.getText(); //the text is the DNA bases pasted thetext=thetext.replaceAll(" ",""); //removes spaces thetext2 = ""; for(int i=0; i<thetext.length(); i++) { char a = thetext.charAt(i); switch (a) { case 'A': case 'a'://moves right x+=1; y+=0; series.add(x,y); break; case 'C': case 'c': //moves up x+=0; y+=1; series.add(x,y); break; case 'G': case 'g': //move left x-=1; y+=0; series.add(x,y); break; case 'T': case 't'://move down x+=0; y-=1; series.add(x,y); break; default: // series.add(0,0); break; } } XYDataset xyDataset = new XYSeriesCollection(series); JFreeChart chart = ChartFactory.createXYLineChart ("DNA Random Walk", "", "", xyDataset, PlotOrientation.VERTICAL, true, true, false); ChartFrame frame1=new ChartFrame("DNA Random Walk",chart); frame1.setVisible(true); frame1.setSize(300,300); } if(e.getSource()==exit) {System.exit(0);} } public void stop(){} }

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How to plot 3D graphs in Excel from CSV data?

- by Primx

I have data formatted like this in a csv file: a, 1, 4, 6.0 a, 2, 42, 16.0 a, 5, 14, 69.3 a, 11, 4, 7.0 b, 1, 45, 6.0 b, 2, 45, 1.9 b, 9, 2, 4.4 b, 11, 4, 7.9 lines with first parameter a is one set of data, and first parameter b represents another set. My aim is to plot two lines on the same graph, one with points (1, 4, 6.0), (2, 42, 16.0), (5, 14, 69.3), (11, 4, 7.0) and the other with points (1, 45, 6.0), (2, 45, 1.9), (9, 2, 4.4), (11, 4, 7.9) I am able to import the data directly in MS Excel, but am not sure how to plot them. How can I plot this data?

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How to plot 3d surface in R on Windows x64?

- by Thomas Bratt

How to plot 3d surface in R on Windows x64? Related questions: Plotting a 3d surface plot with contour map overlay, using R

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How can the crosshair of ginput be restricted to one plot?

- by Lucas

I wrote a small MATLAB program with a gui. Inside the gui I have, among other things, a plot in which the user should be able to select two points. For this I use the function ginput, which creates a crosshair for selection. Unfortunatley the crosshair extends the whole window and is not restricted to the plot, which doesn't look nice and is confusing for the user. How can the crosshair be restricted only to the area of the plot?

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Google Visualization API - Line and Scatter on one Chart.

- by ealgestorm

Does any one know if it is possible to use the Default Google Scatter Chart in the Google Visualizations Gallery to draw a scatter chart that has both a series with points only, a series with a line of best fit and on top of this a set of lines across the chart indicating limits. i.e. at +/- 20% etc. The chart we need is actually a Control Chart with multiple series and individual formatting of each series displayed on the chart. i.e some series with only points other series with a line of best fit. Does any one know of a Control Chart that has already been done using the Google Visualization API?

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How to get scrolling plot in Linux (using command-line tools)?

- by Vi

Supposing I have a program that prints lines with data periodically, how can I turn then info them into graphical plot that updates itself each time new line available? $ ./prog 10 44 20 66 30 55 40 58 50 59 55 58 60 77 ^C $ ./prog | scrollingplot Window appears and updates on each line printed: 80| | ---- | ---- ______...__/ | / ----- | - 40| ------------------------------- 10 20 30 40 50 60 # Note that ASCII art-style plot is just for example, # I want simple X window like in mplayer. There are enough tools for static data, but I haven't seen ones for updating data (except of ksysguard).

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How can a data ellipse be superimposed on a ggplot2 scatterplot?

- by Radu

Hi, I have an R function which produces 95% confidence ellipses for scatterplots. The output looks like this, having a default of 50 points for each ellipse (50 rows): [,1] [,2] [1,] 0.097733810 0.044957994 [2,] 0.084433494 0.050337990 [3,] 0.069746783 0.054891438 I would like to superimpose a number of such ellipses for each level of a factor called 'site' on a ggplot2 scatterplot, produced from this command: > plat1 <- ggplot(mapping=aes(shape=site, size=geom), shape=factor(site)); plat1 + geom_point(aes(x=PC1.1,y=PC2.1)) This is run on a dataset, called dflat which looks like this: site geom PC1.1 PC2.1 PC3.1 PC1.2 PC2.2 1 Buhlen 1259.5649 -0.0387975838 -0.022889782 0.01355317 0.008705276 0.02441577 2 Buhlen 653.6607 -0.0009398704 -0.013076251 0.02898955 -0.001345149 0.03133990 The result is fine, but when I try to add the ellipse (let's say for this one site, called "Buhlen"): > plat1 + geom_point(aes(x=PC1.1,y=PC2.1)) + geom_path(data=subset(dflat, site="Buhlen"),mapping=aes(x=ELLI(PC1.1,PC2.1)[,1],y=ELLI(PC1.1,PC2.1)[,2])) I get an error message: "Error in data.frame(x = c(0.0977338099339815, 0.0844334944904515, 0.0697467834016782, : arguments imply differing number of rows: 50, 211 I've managed to fix this in the past, but I cannot remember how. It seems that geom_path is relying on the same points rather than plotting new ones. Any help would be appreciated.

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Curve fitting: Find the smoothest function that satisfies a list of constraints.

- by dreeves

Consider the set of non-decreasing surjective (onto) functions from (-inf,inf) to [0,1]. (Typical CDFs satisfy this property.) In other words, for any real number x, 0 <= f(x) <= 1. The logistic function is perhaps the most well-known example. We are now given some constraints in the form of a list of x-values and for each x-value, a pair of y-values that the function must lie between. We can represent that as a list of {x,ymin,ymax} triples such as constraints = {{0, 0, 0}, {1, 0.00311936, 0.00416369}, {2, 0.0847077, 0.109064}, {3, 0.272142, 0.354692}, {4, 0.53198, 0.646113}, {5, 0.623413, 0.743102}, {6, 0.744714, 0.905966}} Graphically that looks like this: We now seek a curve that respects those constraints. For example: Let's first try a simple interpolation through the midpoints of the constraints: mids = ({#1, Mean[{#2,#3}]}&) @@@ constraints f = Interpolation[mids, InterpolationOrder->0] Plotted, f looks like this: That function is not surjective. Also, we'd like it to be smoother. We can increase the interpolation order but now it violates the constraint that its range is [0,1]: The goal, then, is to find the smoothest function that satisfies the constraints: Non-decreasing. Tends to 0 as x approaches negative infinity and tends to 1 as x approaches infinity. Passes through a given list of y-error-bars. The first example I plotted above seems to be a good candidate but I did that with Mathematica's FindFit function assuming a lognormal CDF. That works well in this specific example but in general there need not be a lognormal CDF that satisfies the constraints.

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Basic Matlab question

- by sylvester

I know this is really basic, but I am new to matlab. After opening a .fig file, how do you actually work with the data in the command line? All I see is the picture. Im not sure how to actually get the data.

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