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  • What is wrong with this null check for data reader

    - by Phil
    c.Open() r = x.ExecuteReader If Not r("filename").IsDbnull Then imagepath = "<img src='images/'" & getimage(r("filename")) & " border='0' align='absmiddle'" End If c.Close() r.Close() I have also tried; If r("filename") Is DBNull.Value Then imagepath = String.Empty Else imagepath = "<img src='images/'" & getimage(r("filename")) & " border='0' align='absmiddle'" End If c.Close() r.Close() The error is: Invalid attempt to read when no data is present. The idea of my code is to build an img src string only when data is available. Help greatly appreciated. Thanks

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  • Rails: Check output of path helper from console

    - by Thor Thurn
    Rails defines a bunch of magic with named routes that make helpers for your routes. Sometimes, especially with nested routes, it can get a little confusing to keep track of what URL you'll get for a given route helper method call. Is it possible to, using the Ruby console, see what link a given helper function will generate? For example, given a named helper like post_path(post) I want to see what URL is generated.

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  • Check whether Excel file is Password protected

    - by Torben Klein
    I am trying to open an Excel (xlsm) file via VBA. It may or may not be protected with a (known) password. I am using this code: On Error Resume Next Workbooks.Open filename, Password:=user_entered_pw opened = (Err.Number=0) On Error Goto 0 Now, this works fine if the workbook has a password. But if it is unprotected, it can NOT be opened. Apparently this is a bug in XL2007 if there is also workbook structure protection active. (http://vbaadventures.blogspot.com/2009/01/possible-error-in-excel-2007.html). On old XL2003, supplying a password would open both unprotected and password protected file. I tried: Workbooks.Open filename, Password:=user_entered_pw If (Err.Number <> 0) Then workbooks.open filename This works for unprotected and protected file. However if the user enters a wrong password it runs into the second line and pops up the "enter password" prompt, which I do not want. How to get around this?

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  • Check user language selection in NSIS MUI2

    - by wls
    I have multiple language packs in my NSIS installer, using the MUI2 interface. Now I try to select the language pack, which is installed by the "Typical" installation type according to the user's chosen setup language. My problem is, that I can't figure out, how to get the user's language selection. I already tried to access the variables $LANGUAGE and $mui.LangDLL.RegistryLanguage, as well as trying to compare a defined language string to a specific translation string, but without success.

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  • XPath: How to check multiple attributes across similar nodes

    - by Justin
    Hi, If I have some xml like: <root> <customers> <customer firstname="Joe" lastname="Bloggs" description="Member of the Bloggs family"/> <customer firstname="Joe" lastname="Soap" description="Member of the Soap family"/> <customer firstname="Fred" lastname="Bloggs" description="Member of the Bloggs family"/> <customer firstname="Jane" lastname="Bloggs" description="Is a member of the Bloggs family"/> </customers> </root> How do I get, in pure XPath - not XSLT - an xpath expression that detects rows where lastname is the same, but has a different description? So it would pull the last node above? Thanks a mill if you can help, been scratching at it for ages, and I can't find it by searching (apologies if it is) Cheers, J

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  • android: Check if a View is bringed to front

    - by user329692
    Hi Guys! I made a custom component which simple extends a WebView This component is used into activities that are loaded from a tabhost. This component creates a timertask too. I'd like to execute the task only if the activity that contains the component is visible. Ex: public class MyWebView extends WebView { public MyWebView(Context context, AttributeSet as) { super(context,as); /** More code **/ TimerTask ttask = new TimerTask() { @Override public void run() { if (iamvisible) doStuff(); } }; timer = new Timer(); timer.schedule(ttask, refreshInterval * 1000, refreshInterval * 1000); } } How can I set the iamvisible variable? I tried overriding onWindowFocusChanged and onWindowVisibilityChanged but with no luck Regards in advance

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  • Ruby BigDecimal sanity check (floating point newb)

    - by Andy
    Hello, Hoping to get some feedback from someone more experienced here. I haven't dealt with the dreaded floating-point calculation before... Is my understanding correct that with Ruby BigDecimal types (even with varying precision and scale lengths) should calculate accurately or should I anticipate floating point shenanigans? All my values within a Rails application are BigDecimal type and I'm seeing some errors (they do have different decimal lengths), hoping it's just my methods and not my object types... Thanks!

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  • how to check an ANTLR token is only used once or less in the parser

    - by Simon Kenyon Shepard
    In Antlr, if I have a rule for example: someRule : TOKENA TOKENB; it would accept : "tokena tokenb" if I would like TOKENA to be optional, I can say, someRule : TOKENA* TOKENB; then I can have : "tokena tokenb" or "tokenb" or "tokena tokena tokenb" but this also means it can be repeated more that once. Is there anyway I can say this token can be there 1 or less times but not more than one? so it would accept: "tokena tokenb" or "tokenb" BUT NOT "tokena tokena tokenb"? Many thanks

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  • Check whether server is up in AppleScript

    - by Mark Szymanski
    I have an intranet server running on a Windows XP computer and the internet connection on it has been known to be pretty unreliable (surprise, surprise) so I was wondering if there was a way to use an AppleScript to poll it every hour or so to see if it is up and running and if it isn't, execute something, like send myself an email. Thanks in advance!

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  • How to check for case sensitive in hibernate criteria

    - by dhiraj
    0 vote down star I have used hibernate to fetch the login information from the mysql database. But the problem is that say for example the user name is 'dhiraj' in the database, now the login is successful by entering the user name, but it is also allowing to enter by taking the user name in uppercase also, e.g., 'DHIRAJ'. I want to restrict it to as it in the database. Can you tell me how to achieve that in hibernate?

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  • anyone know of a custom membership provider implementation that check password strength against in-b

    - by ronaldwidha
    I've got an Asp.net MVC app and before being able to go live, the IT have requested for us to comply with their password policy. The flexibility of AspnetSqlMembershipProvider doesn’t quite satisfy the requirement. The password strength and length rules are as follows: one lowercase one Uppercase one number and or special character 8 characters in length so far, aspnetsqlmembershipprovider is good... Not allowed to use: Dictionary words Names, real or fictional Plain language phrases Dates Telephone numbers Car registration numbers User IDs Postal codes Organization name Only the first 4 criteria are satisfied by the aspnetsqlmembershipprovider. Do you know of any third party products that offers this functionality (preferably in the form of a custom membership provider)?

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  • How can I check if Zend_Form_Elements has no decorators set

    - by jiewmeng
    I find that even if I just declare an element like $this->addElement('textarea', 'txt1'); I find that it already has decorators set Zend_Debug::dump($this->getElement('txt1')->getDecorators()); http://pastebin.com/7Y24g62w I want to test that I didn't set decorators using setDecorators() or using something like $this->addElement('textarea', 'txt1', array( 'decorators' => array(...) )); If I didn't set any decorators then apply default decorators, how can I do that. I want to apply default decorators per element basis, not using Zend_Form#setDisableLoadDefaultDecoraotrs()

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  • I have to select the checkbox two times to check/uncheck in jTable

    - by 117526709403775781607
    I have a jTable code i intend to use, but the problem with it is that when i click on the checkbox once it doesn't select/deselect it, instead i have to click twice. But if i select any other cell in the row except the one containing the checkbox the purpose is solved. HERE IS MY CODE : public class TableSelectionTest extends JFrame implements ListSelectionListener { private final int COLUMN_COUNT = 5; private TblModel model; public TableSelectionTest() { initialize(); setDefaultCloseOperation(EXIT_ON_CLOSE); pack(); } private void initialize() { List data = new ArrayList(); for (int i = 0; i < 10; i++) { Object record[] = new Object[COLUMN_COUNT]; record[0] = Boolean.FALSE; for (int j = 1; j < COLUMN_COUNT; j++) { record[j] = new Integer(j); } data.add(record); } model = new TblModel(data); JTable table = new JTable(model); table.getSelectionModel().setSelectionMode(ListSelectionModel.SINGLE_SELECTION); table.getSelectionModel().addListSelectionListener (this); JScrollPane scroll = new JScrollPane(table); getContentPane().add(scroll, BorderLayout.CENTER); } public static void main(String[] args) { TableSelectionTest f = new TableSelectionTest(); f.show(); } class TblModel extends AbstractTableModel { private List data; public TblModel(List data) { this.data = data; } public int getColumnCount() { return COLUMN_COUNT; } public int getRowCount() { return data == null ? 0 : data.size(); } public void setValueAt(Object value, int rowIndex, int columnIndex) { getRecord(rowIndex)[columnIndex] = value; super.fireTableCellUpdated(rowIndex, columnIndex); } public Object getValueAt(int rowIndex, int columnIndex) { return getRecord(rowIndex)[columnIndex]; } public boolean isCellEditable(int rowIndex, int columnIndex) { if(columnIndex == 0) return true; else return false; } public Class getColumnClass(int columnIndex) { if (data == null || data.size() == 0) { return Object.class; } Object o = getValueAt(0, columnIndex); return o == null ? Object.class : o.getClass(); } private Object[] getRecord(int rowIndex) { return (Object[]) data.get(rowIndex); } } public void valueChanged(ListSelectionEvent e) { if (!e.getValueIsAdjusting()) { ListSelectionModel lsm = (ListSelectionModel) e.getSource(); int index = lsm.getMinSelectionIndex(); if(model.getRecord(index)[0] == Boolean.FALSE) model.setValueAt(Boolean.TRUE, index, 0); else if(model.getRecord(index)[0] == Boolean.TRUE) model.setValueAt(Boolean.FALSE, index, 0); } } } Please reply soon as it is bugging me a lot Thank you in advance :)

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  • Best way to check for NULL value in MySql query

    - by PHP-Prabhu
    Can any one please let me know the best way to use IF statement in mysql query to show if the "email" field is NULL then it should show as "no email"... Postcode Telephone Email ---------------------------------------------------------- BS20 0QN 1275373088 no email BS20 0QN 1275373088 no email PO9 4HG 023 92474208 [email protected] SO43 7DS 07801 715200 [email protected] ----------------------------------------------------------

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  • Android - overlay small check icon over specific image in gridview or change border

    - by oscar
    I've just asked a question about an hour ago, while waiting for replies, I've thought maybe I can achieve what I want differently. I was thinking of changing the image but it would be better if I could perhaps overlay something over the top of complete levels in the gridview i.e a small tick icon At the moment, when a level has been completed I am storing that with sharedpreferences So I have a gridView layout to display images that represent levels. Let's just say for this example I have 20 levels. When one level is complete is it possible to overlay the tick icon or somehow highlight the level image. Maybe change the border of the image?? Here are the image arrays I use int[] imageIDs = { R.drawable.one, R.drawable.two, R.drawable.three, R.drawable.four, R.drawable.five, R.drawable.six etc....... and then I have my code to set the images in gridView. Obviously there is more code in between. public View getView(int position, View convertView, ViewGroup parent) { ImageView imageView; if (convertView == null) { imageView = new ImageView(context); imageView.setLayoutParams(new GridView.LayoutParams(140, 140)); imageView.setScaleType(ImageView.ScaleType.CENTER_CROP); imageView.setPadding(5, 5, 5, 5); } else { imageView = (ImageView) convertView; } imageView.setImageResource(imageIDs[position]); return imageView; would it be possible to do any of the above, even the border method would be fine. Thanks for any help

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  • How to get a template tag to auto-check a checkbox in Django

    - by Daniel Quinn
    I'm using a ModelForm class to generate a bunch of checkboxes for a ManyToManyField but I've run into one problem: while the default behaviour automatically checks the appropriate boxes (when I'm editing an object), I can't figure out how to get that information in my own custom templatetag. Here's what I've got in my model: ... from django.forms import CheckboxSelectMultiple, ModelMultipleChoiceField interests = ModelMultipleChoiceField(widget=CheckboxSelectMultiple(), queryset=Interest.objects.all(), required=False) ... And here's my templatetag: @register.filter def alignboxes(boxes, cls): """ Details on how this works can be found here: http://docs.djangoproject.com/en/1.1/howto/custom-template-tags/ """ r = "" i = 0 for box in boxes.field.choices.queryset: r += "<label for=\"id_%s_%d\" class=\"%s\"><input type=\"checkbox\" name=\"%s\" value=\"%s\" id=\"id_%s_%d\" /> %s</label>\n" % ( boxes.name, i, cls, boxes.name, box.id, boxes.name, i, box.name ) i = i + 1 return mark_safe(r) The thing is, I'm only doing this so I can wrap some simpler markup around these boxes, so if someone knows how to make that happen in an easier way, I'm all ears. I'd be happy with knowing a way to access whether or not a box should be checked though.

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  • jquery validate check at least one checkbox

    - by Omu
    I have something like this: <form> <input id='roles' name='roles' type='checkbox' value='1' /> <input id='roles' name='roles' type='checkbox' value='2' /> <input id='roles' name='roles' type='checkbox' value='3' /> <input id='roles' name='roles' type='checkbox' value='4' /> <input id='roles' name='roles' type='checkbox' value='5' /> <input type='submit' value='submit' /> <form> I would like to validate that at least one checkbox (roles) should be checked, is it possible with jquery.validate ?

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  • Check wether Excel file is Password protected

    - by Torben Klein
    I am trying to open an Excel (xlsm) file via VBA. It may or may not be protected with a (known) password. I am using this code: On Error Resume Next Workbooks.Open filename, Password:=user_entered_pw opened = (Err.Number=0) On Error Goto 0 Now, this works fine if the workbook has a password. But if it is unprotected, it can NOT be opened. Apparently this is a bug in XL2007 if there is also workbook structure protection active. (http://vbaadventures.blogspot.com/2009/01/possible-error-in-excel-2007.html). On old XL2003, supplying a password would open both unprotected and password protected file. I tried: Workbooks.Open filename, Password:=user_entered_pw If (Err.Number <> 0) Then workbooks.open filename This works for unprotected and protected file. However if the user enters a wrong password it runs into the second line and pops up the "enter password" prompt, which I do not want. How to get around this?

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  • How to check for palindrome using Python logic

    - by DrOnline
    My background is only a 6 month college class in basic C/C++, and I'm trying to convert to Python. I may be talking nonsense, but it seems to me C, at least at my level, is very for-loop intensive. I solve most problems with these loops. And it seems to me the biggest mistake people do when going from C to Python is trying to implement C logic using Python, which makes things run slowly, and it's just not making the most of the language. I see on this website: http://hyperpolyglot.org/scripting (serach for "c-style for", that Python doesn't have C-style for loops. Might be outdated, but I interpret it to mean Python has its own methods for this. I've tried looking around, I can't find much up to date (Python 3) advice for this. How can I solve a palindrome challenge in Python, without using the for loop? I've done this in C in class, but I want to do it in Python, on a personal basis. The problem is from the Euler Project, great site btw. def isPalindrome(n): lst = [int(n) for n in str(n)] l=len(lst) if l==0 || l==1: return True elif len(lst)%2==0: for k in range (l) ##### else: while (k<=((l-1)/2)): if (list[]): ##### for i in range (999, 100, -1): for j in range (999,100, -1): if isPalindrome(i*j): print(i*j) break I'm missing a lot of code here. The five hashes are just reminders for myself. Concrete questions: 1) In C, I would make a for loop comparing index 0 to index max, and then index 0+1 with max-1, until something something. How to best do this in Python? 2) My for loop (in in range (999, 100, -1), is this a bad way to do it in Python? 3) Does anybody have any good advice, or good websites or resources for people in my position? I'm not a programmer, I don't aspire to be one, I just want to learn enough so that when I write my bachelor's degree thesis (electrical engineering), I don't have to simultaneously LEARN an applicable programming language while trying to obtain good results in the project. "How to go from basic C to great application of Python", that sort of thing. 4) Any specific bits of code to make a great solution to this problem would also be appreciated, I need to learn good algorithms.. I am envisioning 3 situations. If the value is zero or single digit, if it is of odd length, and if it is of even length. I was planning to write for loops... PS: The problem is: Find the highest value product of two 3 digit integers that is also a palindrome.

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  • asp classic and javascript to check for session status

    - by StealthRT
    Hey all, i am in need of some help with trying to figure out how to go about checking the users session and seeing if they are still logged in or not. The problem being is because i have a static page that pretty much loads everything into "tabs" using jquery. So when they use navigates the page, it really never leaves that same page they started out on. Hints my problem in trying to determine if they are still logged in or not when they click on update their information on their profile or whatnot. Any suggestions/help would be great! :o) David

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  • quick check on use of map api (android)

    - by Peter vdL
    When you use the Google map api, it is not part of the Android SDK, and you have to mention it in your manifest xml file. Do you have to do anything to access the jar file containing the map api code? Or is that automatically present on the device or emulator, the way the SDK code is? Do you need put the map api jar file in your class path, either when compiling or when executing? Or is it kept somewhere where it is already visible, and the requirement of an XML mention is merely to remind you of the licensing issue? Thanks, Peter

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  • iphone table view check mark accessory problem

    - by Pankaj Kainthla
    I have a table with 50 rows. I want to select particular rows with checkmark accessory but when i select some rows and scroll down the table then i see pre checked rows. I know that table cell are reused but i want to emit this problem what can i do about this? - (NSInteger)numberOfSectionsInTableView:(UITableView *)tableView { return 1; } - (NSInteger)tableView:(UITableView *)tableView numberOfRowsInSection:(NSInteger)section { // return [array count]; return 50; } // Customize the appearance of table view cells. - (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath { static NSString *CellIdentifier = @"Cell"; TableViewCell *cell = (TableViewCell *)[tableView dequeueReusableCellWithIdentifier:CellIdentifier]; if (cell == nil) { cell = [[[TableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:CellIdentifier] autorelease]; } cell.textLabel.text=[NSString stringWithFormat:@"%i",[indexPath row]]; return cell; } // Override to support row selection in the table view. - (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath { UITableViewCell *cell = [tableView cellForRowAtIndexPath:indexPath]; if (cell.accessoryType == UITableViewCellAccessoryNone) { cell.accessoryType = UITableViewCellAccessoryCheckmark; } else { cell.accessoryType = UITableViewCellAccessoryNone; }

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