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  • help configuring a mail server for use with mail.jar and activation.jar

    - by bobbyblue
    im trying to work with the below code: import javax.servlet.*; import javax.servlet.http.*; import java.io.*; import javax.mail.*; import javax.mail.internet.*; // important import javax.mail.event.*; // important import java.net.*; import java.util.*; public class servletmail extends HttpServlet { public void doPost(HttpServletRequest request,HttpServletResponse response) throws ServletException, IOException { PrintWriter out=response.getWriter(); response.setContentType("text/html"); try { Properties props=new Properties(); props.put("mail.smtp.host","localhost"); // 'localhost' for testing Session session1 = Session.getDefaultInstance(props,null); String s1 = request.getParameter("text1"); //sender (from) String s2 = request.getParameter("text2"); String s3 = request.getParameter("text3"); String s4 = request.getParameter("area1"); Message message =new MimeMessage(session1); message.setFrom(new InternetAddress(s1)); message.setRecipients (Message.RecipientType.TO,InternetAddress.parse(s2,false)); message.setSubject(s3); message.setText(s4); Transport.send(message); out.println("mail has been sent"); } catch(Exception ex) { System.out.println("ERROR....."+ex); } } } im using mail.jar and activation.jar but i cant understand how shouls i configure it with a mail server which mail server should i use will i be able to send an email using above what are the requirements a mail server? how should i configure it

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  • How do I assign a rotating category to database entries in the order the records come in?

    - by Stomped
    I have a table which gets entries from a website, and as those entries go into the database, they need to be assigned the next category on a list of categories that may be changed at any time. Because of this reason I can't do something simple like for mapping the first category of 5 to IDs 1, 6, 11, 16. I've considered reading in the list of currently possibly categories, and checking the value of the last one inserted, and then giving the new record the next category, but I imagine if two requests come in at the same moment, I could potentially assign them both the same category rather then in sequence. So, my current round of thinking is the following: lock the tables ( categories and records ) insert the newest row into records get the newest row's ID select the row previous to the insertl ( by using order by auto_inc_name desc 0, 1 ) take the previous row's category, and grab the next one from the cat list update the new inserted row unlock the table I'm not 100% sure this will work right, and there's possibly a much easier way to do it, so I'm asking: A. Will this work as I described in the original problem? B. Do you have a better/easier way to do this? Thanks ~

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  • Checking if user owns file before deleting it

    - by Martin Hoe
    I'm building an API for my site that allows users to delete the files they upload. Obviously, I want to check if the user owns that file before they delete it through the API. I have a files table and a users table, here's the schema: f_id, s_id, u_id, name, size, uploaded u_id, username, password, email, activated, activation_code u_id is a foreign key. The u_id field in the files table points to the u_id in the users table. Given the users username, I want to find the users u_id, and then check if they own the file through the file ID (f_id). I wrote this SQL: $sql = 'SELECT u.username FROM `users` u JOIN `files` f ON u.u_id = f.u_id WHERE f_id = ? AND u.u_id = ? LIMIT 1'; I'm assuming that'd work if I was given the users u_id in the API request, but alas I'm given only their username. How can I modify that SQL to find their user ID and use that? Thanks. Edit: Alright I've got this query but it's always returning an empty result set even though both the file ID and username exist. SELECT u.username FROM `users` u JOIN `files` f ON u.u_id = f.u_id WHERE f.f_id = ? AND u.username = ? LIMIT 1

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  • running a stored procedure inside a sql trigger

    - by Ying
    Hi all, the business logic in my application requires me to insert a row in table X when a row is inserted in table Y. Furthermore, it should only do it between specific times(which I have to query another table for). I have considered running a script every 5 minutes or so to check this, but I stumbled upon triggers and figured this might be a better way to do it. But I find the syntax for procedures a little bewildering and I keep getting an error I have no idea how to fix. Here is where I start: CREATE TRIGGER reservation_auto_reply AFTER INSERT ON reservation FOR EACH ROW BEGIN IF NEW.sent_type = 1 /* In-App */ THEN INSERT INTO `messagehistory` (`trip`, `fk`, `sent_time`, `status`, `message_type`, `message`) VALUES (NEW.trip, NEW.psk, 'NOW()', 'submitted', 4, 'This is an automated reply to reservation'); END; I get an error in the VALUES part of the statmenet but im not sure where. I still have to query the other table for the information I need, but I can't even get past this part. Any help is appreciated, including links to many examples..Thanks

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  • Inventory count in CakePHP

    - by metrobalderas
    We are developing an inventory tracking system. Basically we've got an order table in which orders are placed. When an order is payed, the status changes from 0 to 1. This table has multiple children in another table order_items. This is the main structure. CREATE TABLE order( id INT UNSIGNED AUTO_INCREMENT PRIMARY KEY, user_id INT UNSIGNED, status INT(1), total INT UNSIGNED ); CREATE TABLE order_items( id INT UNSIGNED AUTO_INCREMENT PRIMARY KEY, order_id INT UNSIGNED, article_id INT UNSIGNED, size enum('s', 'm', 'l', 'xl'), quantity INT UNSIGNED ); Now, we've got a stocks table with similar architecture for the acquisitions. This is the structure. CREATE TABLE stock( id INT UNSIGNED AUTO_INCREMENT PRIMARY KEY, article_id INT UNSIGNED ); CREATE TABLE stock_items( id INT UNSIGNED AUTO_INCREMENT PRIMARY KEY, stock_id INT UNSIGNED, size enum('s', 'm', 'l', 'xl'), quantity INT(2) ); The main difference is that stocks has no status field. What we are looking for is a way to sum each article size from stock_items, then sum each article size from order_items where Order.status = 1 and substract both these items to find our current inventory. This is the table we want to get from a single query: Size | Stocks | Sales | Available s | 10 | 3 | 7 m | 15 | 13 | 2 l | 7 | 4 | 3 Initially we thought abouth using complex find conditions, but perhaps that's the wrong approach. Also, since it's not a direct join, it turns out to be quite hard. This is the code we have to retrieve the stock's total for each item. function stocks_total($id){ $find = $this->StockItem->find('all', array( 'conditions' => array( 'StockItem.stock_id' => $this->find('list', array('conditions' => array('Stock.article_id' => $id))) ), 'fields' => array_merge( array( 'SUM(StockItem.cantidad) as total' ), array_keys($this->StockItem->_schema) ), 'group' => 'StockItem.size', 'order' => 'FIELD(StockItem.size, \'s\', \'m\' ,\'l\' ,\'xl\') ASC' )); return $find; } Thanks.

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  • in what way wordpress rewrite pages

    - by Mac Taylor
    Hey Recently I'm interested in post's structure of worpress . They use a table named (wp_posts) and in this table they saved 3 related fields such as : post_title post_name guid It's clear that they save title of each story in post_title field , and slugs in post_name , and full url of a post in guild filed . But where the hell, they rewrite these urls in way it appears in browsers : http://localhost/wordpress/about/ There is no htaccess rules for this ! I checked rewrite.php and didn't understand an inch ?! If you were me , and u need to create such pages , what steps you would take !?

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  • Zend Framework Multiple Table Query

    - by Jeff
    I am looking to execute this statement via Zend Framework. As I understand it, I can use Zend_Db_Select. Is it possible to use Zend_Db_Table? Three tables: classes, students, and class_students select classes.name, students.student_id, students.fname, students.lname from students, classes, class_students where class_students.student_id=students.student_id AND class_students.class_id=classes.class_id;

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  • How to exclude result from 2 different table and show the result?

    - by Lucy Amalia Lusiana
    I have 2 tables: T1 (Total User) T2 (User_id_that_have_done_something_for_today) the mysql_query result from T1 are (Total User) ----- ID ----- | 1 | | 2 | | 3 | | 4 | | 5 | | 6 | | 7 | | 8 | the mysql_query from T2 are (logged) ----- user_id_log ----- | 1 | | 3 | | 4 | | 7 | How to compare T1 and T2 And only show the user that not approved? The end result that i wanted is (result) ----- ID ----- | 2 | | 5 | | 6 | | 8 | I spent 2 days to make this work but i cannot do it I have try LEFT JOIN and NOT IT but the result is not what i wanted Please help me, thank you

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  • inserting facebook app users details to database

    - by fusion
    i'm trying to insert user details, who authorize the app, into the database, but nothing seems to be happening. the data is null and no record is being inserted. is there something wrong with the code? function insertUser($user_id,$sk,$conn) { //$info = $facebook->api_client->users_getInfo($user_id, 'first_name, last_name', 'name', 'sex'); $info = $facebook->api_client->fql_query("SELECT uid, first_name, last_name, name, sex FROM user WHERE uid = $user_id"); for ($i=0; $i < count($info); $i++) { $record = $info[$i]; $first_name=$record['first_name']; $last_name=$record['last_name']; $full_name=$record['name']; $gender=$record['sex']; } $data= mysql_query("select uid from users where uid='{$user_id}'",$conn); if(mysql_num_rows($data)==0) { $sql = "INSERT INTO users (uid,sessionkey, active, fname, lname, full_name, gender) VALUES('{$user_id}','{$sk}','1', '{$first_name}', '{$last_name}', '{$full_name}', '{$gender}')"; mysql_query($sql,$conn); return true; } return false; }

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  • form not showing for empty records

    - by Chris Hodges
    I have a relatively simple PHP page called editcustomers with 3 columns. The problem I'm having is that the form will show when there is a record in the database and the fields will be populated with that info. When no such records exists, the form is not even shown, eliminating the possibility to insert a record. My page layout is as follows: Column 1 shows a form containing customer information, allowing it to be edited. Column 2 allows ordering of products and showing how many products were ordered Column 3 shows the total paid so far, and the total owing. The code for the page I have at present: <html> <?php $id = $_GET['id']; require_once('connect.php'); $sth = $dbh->query("SELECT * FROM users where id = '$id';"); $sth->setFetchMode(PDO::FETCH_ASSOC); $eth = $dbh->query("SELECT * FROM purchases where id = '$id';"); $eth->setFetchMode(PDO::FETCH_ASSOC); ?> <div id="main"> <div id="left"> <form name="custInfo" action ="process.php" method ="post" > <input type = "hidden" name ="formType" value="custInfo"/> <?php while($row = $sth->fetch()){ ?> <p><input type = "hidden" name ="id" value="<?php echo $row["id"] ?>"/> <p><input type = "text" name ="firstName" size ="30" value=" <?php echo $row["firstName"]?>"/> <p><input type = "text" name ="lastName" size ="30" value="<?php echo $row["lastName"]?>"/> <p><input type = "text" name ="country" size ="30" value="<?php echo $row["country"]?>"/> <p></p> <input type="submit" value="Update" /> <?php }?> </div> <div id="mid"> <form name="custCosts" action ="process.php" method ="post" > <input type = "hidden" name ="formType" value="custCosts"/> <?php while($row = $eth->fetch()){ ?> <p><input type = "hidden" name ="id" value="<?php echo $row["id"] ?>"/> <p><input type = "text" name ="amountOwed" size ="30" value=" <?php echo $row["amountOwed"]?>"/> <p><input type = "text" name ="numAaa" size ="30" value="<?php echo $row["numAaa"]?>"/> <p><input type = "text" name ="numBbb" size ="30" value="<?php echo $row["numBbb"]?>"/> <p></p> <input type="submit" value="Update" /> <?php }?> </div> <div id="right"> <b>Total Balance</b> <p> Money owed: </p> <p> aaa total: </p> <p> bbb total: </p> <p> Total: </p> <input type = "text" name ="pay" size ="20" /></p> <input type="submit" value="Make Payment" /> </div> <?php $dbh =null; ?> </body> </html> And the code for all the database trickery: <?php require_once 'connect.php'; $formType = $_POST['formType']; $id = $_POST['id']; $firstName = $_POST['firstName']; $lastName = $_POST['lastName']; $country = $_POST['country']; $amountOwed = $_POST['amountOwed ']; $numAaa = $_POST['numAaa']; $numBbb = $_POST['numBbb']; if(empty($_POST['id'])) { $sth = $dbh->prepare("INSERT INTO customers (firstName, lastName, country) VALUES ('$firstName', '$lastName', '$country')"); $sth->execute(); } elseif(!empty($_POST['id']) && !isset($_POST['stayCost']) && $_POST['formType'] == 'guestInfo'){ $sth = $dbh->prepare("UPDATE customers SET firstName = '$firstName', lastName = '$lastName', country = '$country' WHERE id = '$id'"); $sth->execute(); }elseif(!empty($_POST['id']) && isset($_POST['stayCost']) && $_POST['formType'] == 'guestInfo'){ $sth = $dbh->prepare("INSERT INTO purchases (id, amountOwed, numAaa, numBbb) VALUES ('$id', '$amountOwed', '$numAaa', '$numBbb'"); $sth->execute(); }elseif(!empty($_POST['id']) && $_POST['formType'] == 'guestCosts'){ $sth = $dbh->prepare("UPDATE purchases SET amountOwed= '$amountOwed', numAaa = '$numAaa', numBbb= '$numBbb' WHERE id = '$id'"); $sth->execute(); } $dbh =null; ?> Why does the form not even display if there is no record? An error or something I might understand....but the form is still in the HTML and should still be being output, from what I can see. Why is this not the case?

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  • Is it possible for a Grails Domain to have no 'id'?

    - by firnnauriel
    Is it possible to create a table that has no 'id'? For example, this is my domain: class SnbrActVector { int nid String term double weight static mapping = { version false id generator: 'identity' } static constraints = { } } When I run this SQL statement, it fails: insert into snbr_act_vector values (5, 'term', 0.5) I checked the table and 'id' is already set to autoincrement. I'm thinking that another option is to remove the 'id' itself. Or is there another workaround for this? Please assume that it is not an option to change the givent SQL statement.

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  • Generating SQL for website

    - by Ethan
    I am working on a webapplication How can i create SQL for the following Database Information User information Username - String Password - String Admin or Client - boolean Last login – Date/Time LogItem typeLogItem – String (Page name?) hitCount – int View PageURL UserID Transaction User – String DateTimeStamp SKU – int Purchase-boolean TransactionID-int Inventory information Sku number - int Item description - String Price to customer - double Count - in

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  • % confuses python raw sql query

    - by Jonathan
    Following this SO question, I'm trying to "truncate" all tables related to a certain django application using the following raw sql commands in python: cursor.execute("set foreign_key_checks = 0") cursor.execute("select concat('truncate table ',table_schema,'.',table_name,';') as sql_stmt from information_schema.tables where table_schema = 'my_db' and table_type = 'base table' AND table_name LIKE 'some_prefix%'") for sql in [sql[0] for sql in cursor.fetchall()]: cursor.execute(sql) cursor.execute("set foreign_key_checks = 1") Alas I receive the following error: C:\dev\my_project>my_script.py Traceback (most recent call last): File "C:\dev\my_project\my_script.py", line 295, in <module> cursor.execute(r"select concat('truncate table ',table_schema,'.',table_name,';') as sql_stmt from information_schema.tables where table_schema = 'my_db' and table_type = 'base table' AND table_name LIKE 'some_prefix%'") File "C:\Python26\lib\site-packages\django\db\backends\util.py", line 18, in execute sql = self.db.ops.last_executed_query(self.cursor, sql, params) File "C:\Python26\lib\site-packages\django\db\backends\__init__.py", line 216, in last_executed_query return smart_unicode(sql) % u_params TypeError: not enough arguments for format string Is the % in the LIKE making trouble? How can I workaround it?

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  • Group by clause return latest row information

    - by I Like PHP
    below is my table structure table_movie_info i_movie_id |movie_actor_id |movie_actress_id |movie_director_id | movie_producer_id 48 | 5 | 9 | 66 | 21 48 | 6 | 15 | 88 | 22 48 | 7 | 12 | 77 | 23 one more table is table_movie movie_id | movie_year | movie_genre_id |movie_rating 1 | 2009 | 6 | 8 2 | 2001 | 5 | 7.5 48 | 2007 | 3 | 6.8 now i need total movie information using both table,i write below query SELECT * FROM table_movie_info LEFT JOIN table_movie ON movie_id = i_movie_id WHERE i_movie_id=48 GROUP BY i_movie_id above query return only one row , but i need such type of information movie_id=48, actors_id list=5,6,7 acttress_id list=9,15,12 etc.. please tell me the optimized query which h return complete information i need. thanks for helping me always.

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  • PHP reporting error. DB verify how to?

    - by iamfab
    Error reporting Notice: Undefined variable: random_chars in wamp\www\php_sandbox\idgen.php on line 21 Call Stack: # Time Memory Function Location 1 0.0045 678928 {main}( ) ..\idgen.php:0 GPB7446 How do I fix this error? Using this code like an automatic unique id generator. How do I connect to DB to verify code is truly unique before allowing it to be assigned to a user creating a new account? Thanks <?php $characters = array( "A","B","E","F","G","H","J","K","M","N","P","R","S","T","W","X","Y","Z"); $keys = array(); while(count($keys) < 3) { $x = mt_rand(0, count($characters)-1); if(!in_array($x, $keys)) { $keys[] = $x; } } foreach($keys as $key){ $random_chars .= $characters[$key];} $randNum = rand(2327,9987); $randLet = rand(2327,9987); echo $random_chars . $randNum; ?>

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  • How to find and update the next record in a linking table

    - by someoneinomaha
    I have a classifieds system I'm working on. People are able to add photos to a classified, but I only display one when displaying the list of classifieds. To do that, I have a linking table between classifieds and photos that has a "is_main" boolean field. When someone deletes one of their classified photos, I want to: 1) See if there is more than that photo tied to the classified. 2) If there is, update the next photo and set that "is_main" field to TRUE. Just trying to find out the most efficient way to do this.

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  • Fetching a result twice with deferend name

    - by user1799842
    I have 1 table with tasks named opentask:columns: id,title,description,expires,creator_id,creator_name, executer_id, executer_name, priority_id, status_id1 table with users named user: with columns: user_id, username What I want is to create a query where there will be all columns from opentask table where the executer_id will be equal to the user_id of user table AND the creator_id will be equal to the user_id again. This creates a confusion because the first equality excludes the second.So I need somehow to create a query where I will include the usernames for the executer with something like where "opentask.executer_id=user_user_id" and at the same time I will include the username again (as a differend name?) for the creator with something like "where opentask.executer_id=user_user_id"So I try this, which of course I know that is missing something, can you help? SELECT DISTINCT id, title, description, expires, creator_id, executer_id, oc_opentask.priority_id, oc_opentask.status_id, priority_name, status_name, user_id, username, (SELECT username FROM oc_opentask, oc_user WHERE oc_opentask.creator_id=oc_user.user_id) AS username2 FROM oc_opentask, oc_opentask_priority, oc_user, oc_opentask_status WHERE oc_opentask.priority_id=oc_opentask_priority.priority_id AND oc_opentask.executer_id=oc_user.user_id AND oc_opentask.status_id=oc_opentask_status.status_id ORDER BY oc_opentask.expires DESC

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  • my sql insert query not working

    - by Piyush
    I am inserting userId.It is displaying correct but inserting 0 in spite of actual userId. mycode- If(! empty($userIDToCheck) || $userIDToCheck != '' ) { echo $userIDToCheck; $sql = "INSERT INTOpnpdb.ruser(userid) VALUES ('$userIDToCheck');"; mysql_query($sql)or die(mysql_error()); echo "Done"; } Output : pi203713 Done But is database it is inserting "0"???

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  • how do I copy value from one table and inserted to another in the same database??

    - by mathew
    I am having a tough time to do this... I have created two table say table-1 and table-2 in same database.what I want is I need to copy some values from table-1 and insert the same to table-2. I have tried many ways but it does not seems work. below is my code can any one tell me where I am missing?? $db = mysql_connect("localhost", "user", "pass") or die("Could not connect."); mysql_select_db("comdata",$db)or die(mysql_error()); $resultb = mysql_query("SELECT * FROM table-2")or die(mysql_error()); $row = mysql_fetch_array($resultb); $days = (strtotime(date("Y-m-d")) - strtotime($row['regtime'])) / (60 * 60 * 24); if($row > 0 && $days < 1){ $person = $row['person']; $catogr = $row['catog']; $position = $row['position']; $location = $row['location']; $rank = $row['rank']; mysql_close($db); }else{ $db = mysql_connect("localhost", "user", "pass") or die("Could not connect."); mysql_select_db("comdata",$db)or die(mysql_error()); $result = mysql_query("SELECT * FROM table-1 WHERE regtime = DATE(NOW()) ORDER BY rank ASC LIMIT 1;")or die(mysql_error()); $row = mysql_fetch_array($result); $person = $row['person']; $catogr = $row['catog']; $position = $row['position']; $location = $row['location']; $rank = $row['rank']; mysql_query("INSERT INTO table-2 (regtime,person,catog,position,location,rank) VALUES(NOW(),'$person','$catogr','$position','$location','$rank')"); mysql_close($db); }

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  • Worpress WorkFlow Modfications

    - by blgnklc
    Hi All WordPress Lovers, I would like to ask a help about Zensor which is a plugin that you publish a post then a moderator approves the post to be published on the wordpress blog site. When a post is awating for approval, each awaiting post is appearing "waiting moderation". But, I dont want any link appears before moderator approval. Actually I found the joing sentence below; 1- Must be added to the end of JOIN part of any query: LEFT JOIN wp_zensor ON ID = wp_zensor.post_id 2- Must be added to the end of WHERE condition : AND wp_zensor.moderation_status = 'approved' Could you please show me; where should I add these modification on the category link presentation below: <h2>Politics</h2> <?php $recent = new WP_Query("cat=31&showposts=1"); while($recent->have_posts()) : $recent->the_post();?> <b><a href="<?php the_permalink() ?>" rel="bookmark"><?php the_title(); ?></a></b> <?php the_content_limit(140, "devami &raquo;"); ?> <div class="hppostmeta"> <p><?php the_time('j F Y, H:i'); ?> | <?php the_author_posts_link(); ?></p> </div> <?php endwhile; ?> Or any general solutions will be welcomed. Thanks. BK

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