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  • problem with logout script in php

    - by user225269
    I'm a beginner in php, and I am trying to create a login and logout. But I am having problems in logging out. My logout just calls for the login form which is this: <? session_start(); session_destroy(); ?> <table width="300" border="0" align="center" cellpadding="0" cellspacing="1" bgcolor="#CCCCCC"> <tr> <form name="form1" method="post" action="checklogin.php"> <td> <table width="100%" border="0" cellpadding="3" cellspacing="1" bgcolor="#FFFFFF"> <tr> <td colspan="3"><strong>Member Login </strong></td> </tr> <tr> <td width="78">Username</td> <td width="6">:</td> <td width="294"><input name="myusername" type="text" id="myusername"></td> </tr> <tr> <td>Password</td> <td>:</td> <td><input name="mypassword" type="text" id="mypassword"></td> </tr> <tr> <td>&nbsp;</td> <td>&nbsp;</td> <td><input type="submit" name="Submit" value="Login"></td> </tr> </table> </td> </form> </tr> </table> My problem is, when I try to press the back button in the browser. Whoever user is using it can still access what is not supposed to be accessed when a user hasn't logged in. Do I need to add a code on the user page? I have this code on the user page: <? session_start(); if(!session_is_registered(myusername)){ header("location:main_login.php"); } ?> What can you recommend that I would do so that a script will prompt to enter the username and password again when a user clicks on the back button.

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  • A logical problem with two tables

    - by Luke
    Hey guys, I created a list for fixtures. $result = mysql_query("SELECT date FROM ".TBL_FIXTURES." WHERE compname = '$comp_name' GROUP BY date"); $i = 1; $d = "Start"; while ($row = mysql_fetch_assoc($result)) { $odate = $row['date']; $date=date("F j Y", $row['date']); echo "<p>Fixture $i - $d to $date</p>"; } As you can see from the query, the date is displayed from the fixtures table. The way my system works is that when a fixture is "played", it is removed from this table. Therefore when the entire round of fixtures are complete, there wont be any dates for that round in this table. They will be in another table. Is there anyway I can run an other query for dates at the same time, and display only dates from the fixtures table if there isnt a date in the results table? "SELECT * FROM ".TBL_CONF_RESULTS." WHERE compid = '$_GET[id]' && type2 = '2' ORDER BY date" That would be the second query!

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  • Beginner having difficulty with SQL query

    - by Vulcanizer
    Hi, I've been studying SQL for 2 weeks now and I'm preparing for an SQL test. Anyway I'm trying to do this question: For the table: 1 create table data { 2 id int, 3 n1 int not null, 4 n2 int not null, 5 n3 int not null, 6 n4 int not null, 7 primary key (id) 8 } I need to return the relation with tuples (n1, n2, n3) where all the corresponding values for n4 are 0. The problem asks me to solve it WITHOUT using subqueries(nested selects/views) It also gives me an example table and the expected output from my query: 01 insert into data (id, n1, n2, n3, n4) 02 values (1, 2,4,7,0), 03 (2, 2,4,7,0), 04 (3, 3,6,9,8), 05 (4, 1,1,2,1), 06 (5, 1,1,2,0), 07 (6, 1,1,2,0), 08 (7, 5,3,8,0), 09 (8, 5,3,8,0), 10 (9, 5,3,8,0); expects (2,4,7) (5,3,8) and not (1,1,2) since that has a 1 in n4 in one of the cases. The best I could come up with was: 1 SELECT DISTINCT n1, n2, n3 2 FROM data a, data b 3 WHERE a.ID <> b.ID 4 AND a.n1 = b.n1 5 AND a.n2 = b.n2 6 AND a.n3 = b.n3 7 AND a.n4 = b.n4 8 AND a.n4 = 0 but I found out that also prints (1,1,2) since in the example (1,1,2,0) happens twice from IDs 5 and 6. Any suggestions would be really appreciated.

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  • Why does this properly escaped SQL query fail?

    - by Jason Rhodes
    Here's the query: INSERT INTO jobemails (jobid, to, subject, message, headers, datesent) VALUES ('340', '[email protected]', 'We\'ve received your request for a photo shoot called \'another\'.', 'message', 'headers', '2010-04-22 15:55:06') The datatypes are all correct, it always fails at the subject, so it must be how I'm escaping the values, I assume. I'm sure one of you will see my idiot mistake right away. A little help?

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  • table column accepting "0" as a member Id

    - by user682417
    I have two tables one is members table with columns member id , member first name, member last name. I have another table guest passes with columns guest pass id and member id and issue date . I have a list view that will displays guest passes details (I.e) like member name and issue date and I have two text boxes those are for entering member name and issue date . member name text box is auto complete text box that working fine.... but the problem is when I am entering the name that is not in member table at this time it will accept and displays a blank field in list view in member name column and member id is stored as "0" in guest pass table ...... I don't want to display the member name empty blank and I don t want to store "0" in guest pass table and this is the insert statement sql2 = @"INSERT INTO guestpasses(member_Id,guestPass_IssueDate)"; sql2 += " VALUES("; sql2 += "'" + tbCGuestPassesMemberId.Text + "'"; sql2 += ",'" + tbIssueDate.Text + "'"; guestpassmemberId = memberid is there any validation that need to be done can any one suggestions on this pls... and this is the auto complete text box statement sql = @"SELECT member_Id FROM members WHERE concat(member_Firstname,'',member_Lastname) ='" + tbMemberName.Text+"'"; if (dt != null) { if (dt.Rows.Count > 0) { tbCGuestPassesMemberId.Text = Convert.ToInt32(dt.Rows[0] ["member_Id"]).ToString(); } } can any one help me on this ... is there any type of validation with sql query pls help me .....

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  • Lock innoDB table temporarily

    - by Industrial
    Hi everyone, I make bigger inserts consisting of a couple of thousand rows in my current web app and I would like to make sure that no one can do anything but read the table, until the inserts have been done. What is the best way to do this while keeping the read availability open for normal, non-admin users? Thanks!

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  • Is this SQL is valid?

    - by Beck
    UPDATE polls_options SET `votes`=`votes`+1, `percent`=ROUND((`votes`+1) / (SELECT voters FROM polls WHERE poll_id=? LIMIT 1) * 100,1) WHERE option_id=? AND poll_id=? Don't have table data yet, to test it properly. :) And by the way, in what type % integers should be stored in database? Thanks for the help!

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  • Cross vertion line matching.

    - by BCS
    I'm considering how to do automatic bug tracking and as part of that I'm wondering what is available to match source code line numbers (or more accurate numbers mapped from instruction pointers via something like addr2line) in one version of a program to the same line in another. (Assume everything is in some kind of source control and is available to my code) The simplest approach would be to use a diff tool/lib on the files and do some math on the line number spans, however this has some limitations: It doesn't handle cross file motion. It might not play well with lines that get changed It doesn't look at the information available in the intermediate versions. It provides no way to manually patch up lines when the diff tool gets things wrong. It's kinda clunky Before I start diving into developing something better: What already exists to do this? What features do similar system have that I've not thought of?

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  • How can an SQL query return data from multiple tables

    - by Fluffeh
    I would like to know how to get data from multiple tables in my database, what types of methods are there to do this, what are joins and unions and how are they different from one another? When should I use each one compared to the others? I am planning to use this in my (for example - PHP) application, but don't want to run multiple queries against the database, what options do I have to get data from multiple tables in a single query? Note: I am writing this as I would like to be able to link to a well written guide on the numerous questions that I constantly come across in the PHP queue, so I can link to this for further detail when I post an answer. The answers cover off the following: Part 1 - Joins and Unions Part 2 - Subqueries Part 3 - Tricks and Efficient Code

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  • problem during data fetch

    - by nectar
    here is my code $sql="SELECT * FROM $tbl_name WHERE ownerId='$UserId'"; $result=mysql_query($sql,$link)or die(mysql_error()); $row = mysql_fetch_array($result, MYSQL_ASSOC); <?php while($row = mysql_fetch_array($result, MYSQL_ASSOC)) { echo "<tr>"; echo "<td>".$row['pinId']."</td>"; echo "<td>".$row['usedby']."</td>"; echo "<td>".$row['status']."</td>"; echo "</tr>"; } ?> it is ignoring the first record means if 4 rows are in $row its ignoring the 1st one rest three are coming on page. ownerId is not primary key.

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  • SQL query construction - separate data in a column into two columns

    - by Tommy
    I have a column that contains links. The problem is that the titles of the links are in the same column, so it looks like this: linktitle|-|linkurl I want link title and linkurl in separate columns. I've created a new column for the urls, so I'm looking for a way to extract them and update the linkurl column with them. Is there any clever way to construct a query that does this?

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  • Allow users to pull temporary data then delete table?

    - by JM4
    I don't know the best way to title this question but am trying to accomplish the following goal: When a client logs into their profile, they are presented with a link to download data from an existing database in CSV format. The process works, however, I would like for this data to be 'fresh' each time they click the link so my plan was - once a user has clicked the link and downloaded the CSV file, the database table would 'erase' all of its data and start fresh (be empty) until the next set of data populated it. My EXISTING CSV creation code: <?php $host = 'localhost'; $user = 'username'; $pass = 'password'; $db = 'database'; $table = 'tablename'; $file = 'export'; $link = mysql_connect($host, $user, $pass) or die("Can not connect." . mysql_error()); mysql_select_db($db) or die("Can not connect."); $result = mysql_query("SHOW COLUMNS FROM ".$table.""); $i = 0; if (mysql_num_rows($result) > 0) { while ($row = mysql_fetch_assoc($result)) { $csv_output .= $row['Field'].", "; $i++; } } $csv_output .= "\n"; $values = mysql_query("SELECT * FROM ".$table.""); while ($rowr = mysql_fetch_row($values)) { for ($j=0;$j<$i;$j++) { $csv_output .= '"'.$rowr[$j].'",'; } $csv_output .= "\n"; } $filename = $file."_".date("Y-m-d",time()); header("Content-type: application/vnd.ms-excel"); header("Content-disposition: csv" . date("Y-m-d") . ".csv"); header( "Content-disposition: filename=".$filename.".csv"); print $csv_output; exit; ?> any ideas?

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  • Insert into select and update in single query

    - by Ossi
    I have 4 tables: tempTBL, linksTBL and categoryTBL, extra on my tempTBL I have: ID, name, url, cat, isinserted columns on my linksTBL I have: ID, name, alias columns on my categoryTBL I have: cl_id, link_id,cat_id on my extraTBL I have: id, link_id, value How do I do a single query to select from tempTBL all items where isinsrted = 0 then insert them to linksTBL and for each record inserted, pickup ID (which is primary) and then insert that ID to categoryTBL with cat_id = 88. after that insert extraTBL ID for link_id and url for value. I know this is so confusing, put I'll post this anyhow... This is what I have so far: INSERT IGNORE INTO linksTBL (link_id,link_name,alias) VALUES(NULL,'tex2','hello'); # generate ID by inserting NULL INSERT INTO categoryTBL (link_id,cat_id) VALUES(LAST_INSERT_ID(),'88'); # use ID in second table I would like to add here somewhere that it only selects items where isinserted = 0 and iserts those records, and onse inserted, will change isinserted to 1, so when next time it runs, it will not add them again.

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  • Looking for WebAii Framework free edition online - before the Telerik merge

    - by jdk
    Art of Test produced a nice UI testing tool for free -- WebAii Framework-- that I've been using to add client-side DOM unit tests to my projects. Recently they merged with Telerik and it's now a commercial product. From free to $1500 is suddenly very expensive. Does anybody know if the community edition is still available, or even the last free version is available for download? At least I can finish off with that.

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  • Django database - how to add this column in raw SQL.

    - by alex
    Suppose I have my models set up already. class books(models.Model): title = models.CharField... ISBN = models.Integer... What if I want to add this column to my table? user = models.ForeignKey(User, unique=True) How would I write the raw SQL in my database so that this column works?

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  • Wordpress SQL_CALC fix causes PHP error

    - by ok1ha
    I'm looking for some followup on an older topic for Wordpress where SQL_CALC was found to slow things down when you have a large DB in Wordpress. I have been using the code, at the bottom of this post, to get around it but it does generate an error in my error log. How would I prevent this error? PHP Warning: Division by zero in /var/www/vhosts/domain.com/httpdocs/wp-content/themes/greatTheme/functions.php on line 19 The original thread: http://wordpress.org/support/topic/slow-queries-sql_calc_found_rows-bringing-down-site?replies=25 The code in my functions.php: add_filter('pre_get_posts', 'optimized_get_posts', 100); function optimized_get_posts() { global $wp_query, $wpdb; $wp_query->query_vars['no_found_rows'] = 1; $wp_query->found_posts = $wpdb->get_var( "SELECT COUNT(*) FROM wp_posts WHERE 1=1 AND wp_posts.post_type = 'post' AND (wp_posts.post_status = 'publish' OR wp_posts.post_status = 'private')" ); $wp_query->found_posts = apply_filters_ref_array( 'found_posts', array( $wp_query->found_posts, &$wp_query ) ); $wp_query->max_num_pages = ceil($wp_query->found_posts / $wp_query->query_vars['posts_per_page']); return $wp_query; }

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  • problems with inserting data in database

    - by jannes braet
    $message=$_POST['answer']; $message=nl2br($message); $message=strip_tags($message, '<p><a><b><i><strong><em><code><sub><sup><img><ul><ol><li>'); $message = mysql_real_escape_string($message); $user=$_SESSION['SESS_MEMBER_ID']; $qry="INSERT INTO forum_rules (message,author,date) VALUES ($message,$user,'".date("Y-m-d H:i:s")."')"; $result=mysql_query($qry) or die(mysql_error()); if (!$result) { echo "error inserting data into database"; } else { ... } this codes always outputs error inserting data into database and i don't see what i'm doing wrong. i hav also tried to do it without the date part but that didn't work tho. can someone please tell me what i'm doing wrong here

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  • Separating Variables Inside an Array

    - by Jake Avila Talledo
    Hey i have an array an I need to separate each value so it would be something like this $arry = array(a,b,c,d,e,f) $point1 = (SELECT distance FROM Table WHERE Origin = a AND Destination = b); $point2 = (SELECT distance FROM Table WHERE Origin = b AND Destination = c); $point3 = (SELECT distance FROM Table WHERE Origin = c AND Destination = d); $point4 = (SELECT distance FROM Table WHERE Origin = d AND Destination = e); $point5 = (SELECT distance FROM Table WHERE Origin = e AND Destination = f); $point6 = (SELECT distance FROM Table WHERE Origin = f AND Destination = g); $point7 = (SELECT distance FROM Table WHERE Origin = g AND Destination = f); $total_trav = $point1+$point2+$point3+$point4+$point5+$point6+$point7

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  • Confused as to why my PHP include isn't working

    - by Sam
    I had a prototype of my website working correctly, meaning it connected to the database correctly. This was done with just one file called "connect.php" which had mysql_connect() and such inside it. I then separated the connect information into to separate files, one containing the account information (account.php) and one containing the connect function (connect.php), with correct information (I triple checked) and it isn't connecting properly. All I can think of is that I'm not including it the right way. This is what I have in a file: <?php include('account.php'); include('connect.php'); include('functions.php'); ..... ?>

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  • How to skip an empty LIKE operator in a multiple LIKE query?

    - by alex
    I notice my query doesn't behave correctly if one of the like variables is empty: SELECT name FROM employee WHERE name LIKE '%a%' AND color LIKE '%A%' AND city LIKE '%b%' AND country LIKE '%B%' AND sport LIKE '%c%' AND hobby LIKE '%C%' Now when a and A are not empty it works but when a, A and c are not empty the c part is not excuted so it seems? How can I fix this?

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  • The best way to structure this database?

    - by James P
    At the moment I'm doing this: gems(id, name, colour, level, effects, source) id is the primary key and is not auto-increment. A typical row of data would look like this: id => 40153 name => Veiled Ametrine colour => Orange level => 80 effects => +12 sp, +10 hit source => Ametrine (Some of you gamers might see what I'm doing here :) ) But I realise this could be sorted a lot better. I have studied database relationships and secondary keys in my A-Level computing class but never got as far as to set one up properly. I just need help with how this database should be organised, like what tables should have what data with what secondary and foreign keys? I was thinking maybe 3 tables: gem, effects, source. Which then have relationships to each other? Can anyone shed some light on this? Is a complex way like I'm proposing really the way to go or should I just carry on with what I'm doing? Cheers.

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  • PHP PDO Parameters from a function returned array

    - by noko
    I've got a function written that runs a query based on parameters passed to the function. I can't seem to figure out why doing the following returns a result: function test($function_returned_array) { $variable = 'Hello World'; $sql = 'SELECT `name`, `pid` FROM `products` WHERE `name` IN (?)'; $found = $this->db->get_array($sql, $variable); } While this doesn't return any results: function test2($function_returned_array) { $sql = 'SELECT `name`, `pid` FROM `products` WHERE `name` IN (?)'; $found = $this->db->get_array($sql, $function_returned_array[0]); } $function_returned_array[0] is also equal to 'Hello World'. Shouldn't they both return the same results? When I echo the values of $variable and $function_returned_array[0], they are both 'Hello World' Here's the relevant parts of my PDO wrapper: public function query(&$query, $params) { $sth = $this->_db->prepare($query); if(is_null($params)) { $sth->execute(); } else if(is_array($params)) { $sth->execute($params); } else { $sth->execute(array($params)); } $this->_rows = $sth->rowCount(); $this->_counter++; return $sth; } public function get_array(&$query, $params, $style = PDO::FETCH_ASSOC) { $q = $this->query($query, $params); return $q->fetchAll($style); } I'm using PHP 5.3.5. Any help would be appreciated.

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