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  • PhpMyAdmin; Should I disable root login?

    - by Camran
    I have this setup in Phpmyadmin: USER HOST PASSW PRIVILEGES GRANT debian-sys-maint localhost Yes ALL PRIVILEGES YES phpmyadmin localhost Yes USAGE NO root 127.0.0.1 Yes ALL PRIVILEGES YES root localhost Yes ALL PRIVILEGES YES root my_hostname Yes ALL PRIVILEGES YES username localhost Yes ALL PRIVILEGES YES Where "username" is my username and "my_hostname" is my hostname. I am currently only logging in as the last one (username, localhost). Also, I have php which also uses the last ones login details. Should I disable the other ones? And, what other security measures should I take? BTW: My server is Linux and I have root access. Thanks

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  • Group by clause return latest row information

    - by I Like PHP
    below is my table structure table_movie_info i_movie_id |movie_actor_id |movie_actress_id |movie_director_id | movie_producer_id 48 | 5 | 9 | 66 | 21 48 | 6 | 15 | 88 | 22 48 | 7 | 12 | 77 | 23 one more table is table_movie movie_id | movie_year | movie_genre_id |movie_rating 1 | 2009 | 6 | 8 2 | 2001 | 5 | 7.5 48 | 2007 | 3 | 6.8 now i need total movie information using both table,i write below query SELECT * FROM table_movie_info LEFT JOIN table_movie ON movie_id = i_movie_id WHERE i_movie_id=48 GROUP BY i_movie_id above query return only one row , but i need such type of information movie_id=48, actors_id list=5,6,7 acttress_id list=9,15,12 etc.. please tell me the optimized query which h return complete information i need. thanks for helping me always.

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  • Good article about File- and Folder Permissions on production server?

    - by Camran
    I have a classifieds website, and users may post classifieds, add images, remove classifieds etc etc... I have no idea what to set the permissions to on folders. For instance, a php script which I have uploads a file to a directory. What would you have set the directory permissions to? Nobody need access to the directory, only the php script... Just wonder if anybody has a good (brief) article about setting the "right" permissions? Thanks

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  • Problem with joining to an empty table

    - by Imran Omar Bukhsh
    I use the following query: select * from A LEFT JOIN B on ( A.t_id != B.t_id) to get all the records in A that are not in B. The results are fine except when table B is completely empty, but then I do not get any records, even from table A. Later It wont work yet! CREATE TABLE IF NOT EXISTS T1 ( id int(11) unsigned NOT NULL AUTO_INCREMENT, title varchar(50) CHARACTER SET utf8 COLLATE utf8_unicode_ci NOT NULL, t_id int(11) NOT NULL, PRIMARY KEY (id) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=3 ; -- -- Dumping data for table T1 INSERT INTO T1 (id, title, t_id) VALUES (1, 'apple', 1), (2, 'orange', 2); -- -- Table structure for table T2 CREATE TABLE IF NOT EXISTS T2 ( id int(11) NOT NULL AUTO_INCREMENT, title varchar(50) CHARACTER SET utf8 COLLATE utf8_unicode_ci NOT NULL, t_id int(11) NOT NULL, PRIMARY KEY (id) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=2 ; -- -- Dumping data for table T2 INSERT INTO T2 (id, title, t_id) VALUES (1, 'dad', 2); Now I want to get all records in T1 that do not have a corresponding records in T2 I try SELECT * FROM T1 LEFT OUTER JOIN T2 ON T1.t_id != T2.t_id and it won't work

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  • How do I return the numeric value from a database query in PHP?

    - by Luke
    Hello, I am looking to retreive a numerical value from the database function adminLevel() { $q = "SELECT userlevel FROM ".TBL_USERS." WHERE id = '$_SESSION[id]'"; return mysql_query($q, $this->connection); } This is the SQL. I then wrote the following php/html: <?php $q = $database->adminLevel(); if ($q > 7) { ?> <a href="newleague.php">Create a new league</a> <? } ?> The problem I have is that the userlevel returned isn't affecting the if statement. It is always displayed. How do i get it to test the value of userlevel is greater than 7? Thanks

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  • Pass PHP variables without being seen when working with a database generated list

    - by Wilcoholic
    Looking for any help regarding the problem. Here's the deal: I have a database that has a teams table and it contains team_id. On one of my pages, I generate a list of links that contain the team_id of the creator in their get URL. I need the team_id on the next page but can't figure out how to pass it through any other way. Using a form and POST isn't an option because this method would only pass through the last links data on the list. Storing in a session isn't an option either because there is no way to discretely pass the the variables I need to a function to set the session variables. I have tried and it can pretty easily be viewed from viewing the source code. So here's some sample code to see exactly what I'm dealing with. <? if(mysql_num_rows($result2)>0){ ?> <a class="fltrt btn btn-danger btn-small" onclick="test()" href="acceptmatch-exec.php?match_id=<?php echo $match_id; ?>&team_id=<?php echo $team_id;?>&action=cancel">Cancel Match</a> <?}else{?> <a class="fltrt btn btn-success btn-small" href="acceptmatch-exec.php?match_id=<?php echo $match_id; ?>&team_id=<?php echo $team_id;?>&action=accept">Accept Match</a> <?} ?> The code above is generated multiple times on a page via a while loop that was excluded. I want to pass the match_id and team_id variables without being seen anywhere. If I made this a form, it wouldn't pass the correct variables unless there is only one result at the time (not likely). I'm sure there has to be an easy method that is eluding me, so please share thoughts on how to solve this. I feel as though I am not explaining it well enough, but it's not really easy to explain. I basically want something that works like GET but acts like POST and can be hidden from people viewing source code or link locations. Thanks

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  • Get the sum by comparing between two tables

    - by Ismail Gunes
    I have to tables ProdBiscuit As tb and StockData As sd , I have to get the sum of the quantity in StockData (quantite) with the condition of if (sd.status0 AND sd.prodid = tb.id AND sd.matcuisine = 3) Here is my sql query SELECT tb.id, tb.nom, tb.proddate, tb.qty, tb.stockrecno FROM ProdBiscuit AS tb JOIN (SELECT id, prodid, matcuisine, status, SUM(quantite) AS rq FROM StockData) AS sd ON (tb.id = sd.prodid AND sd.status > 0 AND sd.matcuisine = 3) LIMIT 25 OFFSET @Myid This gives me no rows at all ? There is only 3 rows in ProdBiscuit and 11 rows in Stockdata and there is only 2 rows in StockData good with the condition. And as shown in the picture there is only two rows which give the condition. What is wrong in my query ? PS: The green lines on the image shows the condition in my query.

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  • php query cant figure out the problem

    - by Eat
    I dont get an error but it does not return me the row values as well. How can I address the problem? <?php //DATABASE $dbConn = mysql_connect($host,$username,$password); mysql_select_db($database,$dbConn); $SQL = mysql_query("SELECT N.*, C.CatID FROM News N INNER JOIN Categories C ON N.CatID = C.CatID WHERE N.Active = 1 ORDER BY DateEntered DESC"); while ( $Result = mysql_fetch_array($SQL) or die(mysql_error())) { $CatID[] = $Result[CatID]; $NewsName[] = $Result[NewsName]; $NewsShortDesc[] = $Result[NewsShortDesc]; } // mysql_free_result($Result); ?> <div class="toparticle"> <span class="section"><?=$CatID[0] ?> </span> <span class="headline"><?=$NewsName[0] ?></span> <p><?=$NewsShortDesc[0] ?></p> </div>

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  • Zip multiple database PDF blob files

    - by Michael
    I have a database table that contains numerous PDF blob files. I am attempting to combine all of the files into a single ZIP file that I can download and then print. Please help! <?php include '../config.php'; include '../connect.php'; $session = $_GET['session']; $query = "SELECT $tbl_uploads.username, $tbl_uploads.description, $tbl_uploads.type, $tbl_uploads.size, $tbl_uploads.content, $tbl_members.session FROM $tbl_uploads LEFT JOIN $tbl_members ON $tbl_uploads.username = $tbl_members.username WHERE $tbl_members.session = '$session'"; $result = mysql_query($query) or die('Error, query failed'); $files = array(); while(list($username, $description, $type, $size, $content) = mysql_fetch_array($result)) { $files[] = "$username-$description.pdf"; } $zip = new ZipArchive; $zip->open('file.zip', ZipArchive::CREATE); foreach ($files as $file) { $zip->addFile($file); } $zip->close(); header('Content-Type: application/zip'); header('Content-disposition: attachment; filename=filename.zip'); header('Content-Length: ' . filesize($zipfilename)); readfile($zipname); exit(); ?>

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  • SELECT GROUP BY latest entry in INBOX msg sent by user

    - by Mohatir S
    i am building a simple PM for my personal website where a user can join and send message to the registered users on my website, i am stuck in grouping and selecting latest user (by latest msg time) in INBOX page my table : id msg_from msg_to msg date in_del out_del i want to show latest user's id each in a group here is my SQL query : SELECT ttalk.id, ttalk.msg_from, users.first_name, users.last_name FROM ttalk INNER JOIN users ON ttalk.msg_from = users.id WHERE ttalk.msg_to = '$_SESSION[user_id]' AND ttalk.in_del='0' GROUP BY ttalk.msg_from DESC LIMIT 500 Thanks in advance :-)

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  • How do I choose what and when to cache data with ob_start rather than query the database?

    - by Tim Santeford
    I have a home page that has several independent dynamic parts. The parts consist of a list of recent news from the company, a site statistics panel, and the online status of certain employees. The recent news changes monthly, site statistics change daily, and online statuses change on a per minute bases. I would like to cache these panels so that the db is not hit on every page load. Is using ob_start() then ob_get_contents() to cache these parts to a file the correct way to do this or is there a better method in PHP5 for doing this? In asking this question I'm trying to answer these additional questions: How can I determine the correct approach for caching this data without doing extensive benchmarking? Does it make sense to cache these parts in different files and then join them together per requests or should I re-query the data and cache once per minute? I'm looking for a rule of thumb for planning pages and for situations where doing testing is not cost effective (The client is not paying enough for it I mean). Thanks!

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  • Compare text of two methods

    - by The Talking Walnut
    Is there a tool that can do a diff of two methods? I'm working on some legacy code that has several 100-200 line methods that contain a lot of duplication and I would like to abstract the duplication out. Being able to diff the two methods would be a huge help. In case it matters, I'm working with .NET and Visual Studio 2008.

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  • Open Source PHP search engine

    - by Ravi Gupta
    I am looking for an open source search engine plugin written in php for my website(eCommerce). Before anybody answer that I have a doubt regarding the search engine. Usually search engine crawl web pages, create indexes and then use them while looking for contents. But will the same model work for eCommerce websites? Yeah, it can crawl products pages, index them but don't you think it would be better if it crawls the database directly and index the products stored in the database? And when a user search for any product, it will simply give us the rows of the table which matches the user query? May be what I am asking is a stupid question but I am new to web development, so kindly help me to understand the concept. I have looked at a search engine called Sphider but didn't get what all I have to do to make it work with an eCommerce website.

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  • Help creating a SQL Query

    - by Wes
    Somewhat new to SQL queries and I need a little help with my join. I am supplied with gid For each of these I need to grab name from table wp_ngg_gallery then join in table wp_ngg_pictures and grab field filename limit 1 order DESC by field imagedate Anyone able to help?

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  • How to translate this query:

    - by xRobot
    How can I translate this 2 queries in postgresql ? : . CREATE TABLE example ( id int(10) unsigned NOT NULL auto_increment, from varchar(255) NOT NULL default '0', message text NOT NULL, lastactivity timestamp NULL default '0000-00-00 00:00:00', read int(10) unsigned NOT NULL, PRIMARY KEY (id), KEY from (from) ) DEFAULT CHARSET=utf8; . SELECT * FROM table_1 LEFT OUTER JOIN table_2 ON ( table_1.id = table_2.id ) WHERE (table_1.lastactivity > NOW()-100);

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  • Archiving rows dynamically

    - by Serge
    I was wondering what would be the best solution to dynamically archive rows. For instance when a user marks a task as completed, that task needs to be archived yet still accessible. What would be the best practices for achieving this? Should I just leave it all in the same table and leave out completed tasks from the queries? I'm afraid that over time the table will become huge (1,000,000 rows in a year or less). Or should I create another table ie task_archive and query that row whenever data is needed from it? I know similar questions have been asked before but most of them where about archiving thousands of rows simultaneously, I just need to know what would be the best method (and why) to archive 1 row at a time once it's been marked completed

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  • "slash before every quote" problem

    - by Camran
    I have a php page which contains a form. Sometimes this page is submitted to itself (like when pics are uploaded). I wouldn't want users to have to fill in every field again and again, so I use this as a value of a text-input inside the form: value="<?php echo htmlentities(@$_POST['annonsera_headline'],ENT_COMPAT,'UTF-8');?>"> This works, except it adds a "\" sign before every double-quote... For instance writing 19" wheels gives after page is submitted to itself: 19\" wheels And if I don't even use htmlentities then everything after the quotes dissappears. What is the problem here?

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  • Broken count(*) after adding LEFT JOIN

    - by Iain Urquhart
    Since adding the LEFT JOIN to the query below, the count(*) has been returning some strange values, it seems to have added the total rows returned in the query to the 'level': SELECT `n`.*, exp_channel_titles.*, round((`n`.`rgt` - `n`.`lft` - 1) / 2, 0) AS childs, count(*) - 1 + (`n`.`lft` > 1) + 1 AS level, ((min(`p`.`rgt`) - `n`.`rgt` - (`n`.`lft` > 1)) / 2) > 0 AS lower, (((`n`.`lft` - max(`p`.`lft`) > 1))) AS upper FROM `exp_node_tree_6` `n` LEFT JOIN `exp_channel_titles` ON (`n`.`entry_id`=`exp_channel_titles`.`entry_id`), `exp_node_tree_6` `p`, `exp_node_tree_6` WHERE `n`.`lft` BETWEEN `p`.`lft` AND `p`.`rgt` AND ( `p`.`node_id` != `n`.`node_id` OR `n`.`lft` = 1 ) GROUP BY `n`.`node_id` ORDER BY `n`.`lft` I'm totally stumped... Thank you!

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  • How to check if a checkbox/ radio button is checked in php

    - by user225269
    I have this html code: <tr> <td><label><input type="text" name="id" class="DEPENDS ON info BEING student" id="example">ID</label></td> </tr> <tr> <td> <label> <input type="checkbox" name="yr" class="DEPENDS ON info BEING student"> Year</label> </td> </tr> But I don't have any idea on how do I check this checkboxes if they are checked using php, and then output the corresponding data based on the values that are checked. Please help, I'm thinking of something like this. But of course it won't work, because I don't know how to equate checkboxes in php if they are checked: <?php $con = mysql_connect("localhost","root","nitoryolai123$%^"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("school", $con); $id = mysql_real_escape_string($_POST['idnum']); if($_POST['id'] == checked & $_POST['yr'] ==checked ){ $result2 = mysql_query("SELECT * FROM student WHERE IDNO='$id'"); echo "<table border='1'> <tr> <th>IDNO</th> <th>YEAR</th> </tr>"; while($row = mysql_fetch_array($result2)) { echo "<tr>"; echo "<td>" . $row['IDNO'] . "</td>"; echo "<td>" . $row['YEAR'] . "</td>"; echo "</tr>"; } echo "</table>"; } mysql_close($con); ?>

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  • Moving from dedicated to shared cpanel - any scripts to do all / some of the install tasks ?

    - by mbbcat
    Hi, I have a few hundred phpld sites to move - each has its own cpanel, ( & the target may have shared cpanel) & I can do a full cpanel backup on the original server, but I don't have whm on the current host - the backups are fairly easy to organize but the installs so far means picking through files & setting up db's & mail etc by hand - I am thinking there ought to be an easier ie scripted way to do the installs or at least some parts - can anyone please suggest something ? I would like to migrate the stats at the same time Thanks M

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  • Beginner having difficulty with SQL query

    - by Vulcanizer
    Hi, I've been studying SQL for 2 weeks now and I'm preparing for an SQL test. Anyway I'm trying to do this question: For the table: 1 create table data { 2 id int, 3 n1 int not null, 4 n2 int not null, 5 n3 int not null, 6 n4 int not null, 7 primary key (id) 8 } I need to return the relation with tuples (n1, n2, n3) where all the corresponding values for n4 are 0. The problem asks me to solve it WITHOUT using subqueries(nested selects/views) It also gives me an example table and the expected output from my query: 01 insert into data (id, n1, n2, n3, n4) 02 values (1, 2,4,7,0), 03 (2, 2,4,7,0), 04 (3, 3,6,9,8), 05 (4, 1,1,2,1), 06 (5, 1,1,2,0), 07 (6, 1,1,2,0), 08 (7, 5,3,8,0), 09 (8, 5,3,8,0), 10 (9, 5,3,8,0); expects (2,4,7) (5,3,8) and not (1,1,2) since that has a 1 in n4 in one of the cases. The best I could come up with was: 1 SELECT DISTINCT n1, n2, n3 2 FROM data a, data b 3 WHERE a.ID <> b.ID 4 AND a.n1 = b.n1 5 AND a.n2 = b.n2 6 AND a.n3 = b.n3 7 AND a.n4 = b.n4 8 AND a.n4 = 0 but I found out that also prints (1,1,2) since in the example (1,1,2,0) happens twice from IDs 5 and 6. Any suggestions would be really appreciated.

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  • The best way to structure this database?

    - by James P
    At the moment I'm doing this: gems(id, name, colour, level, effects, source) id is the primary key and is not auto-increment. A typical row of data would look like this: id => 40153 name => Veiled Ametrine colour => Orange level => 80 effects => +12 sp, +10 hit source => Ametrine (Some of you gamers might see what I'm doing here :) ) But I realise this could be sorted a lot better. I have studied database relationships and secondary keys in my A-Level computing class but never got as far as to set one up properly. I just need help with how this database should be organised, like what tables should have what data with what secondary and foreign keys? I was thinking maybe 3 tables: gem, effects, source. Which then have relationships to each other? Can anyone shed some light on this? Is a complex way like I'm proposing really the way to go or should I just carry on with what I'm doing? Cheers.

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