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  • Automatic DNS population for routable IPV6 addresses

    - by Clint
    In ipv4 I can set my DHCP server to populate DNS with hostnames and IP addresses as clients are found. This works well and clients can resolve these DNS addresses to contact eachother over routed subnets. How can this be done in ipv6 without DHCP? Link Local Multicast Name Resolution can allow clients on the same subnet to discover eachothers hostnames and match them to link-local addresses, but so far I can't find a way for clients to advertise their global or unique local addresses and hostnames to a DNS server to be resolved across subnets.

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  • Tail recursion in Erlang

    - by dagda1
    Hi, I am really struggling to understand tail recursion in Erlang. I have the following eunit test: db_write_many_test() -> Db = db:new(), Db1 = db:write(francesco, london, Db), Db2 = db:write(lelle, stockholm, Db1), ?assertEqual([{lelle, stockholm},{francesco, london}], Db2). And here is my implementation: -module(db) . -include_lib("eunit/include/eunit.hrl"). -export([new/0,write/3]). new() -> []. write(Key, Value, Database) -> Record = {Key, Value}, [Record|append(Database)]. append([H|T]) -> [H|append(T)]; append([]) -> []. Is my implementation tail recursive and if not, how can I make it so? Thanks in advance

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  • Recursion in Unity and Dispose pattern implementation

    - by Budda
    My class is inherited from UnityContainer (from Unity 2.0), here is source code: public class UnityManager : UnityContainer { private UnityManager() { _context = new MyDataClassesDataContext(); // ... } protected override void Dispose(bool disposing) { if ( disposing ) { _context.Dispose(); } base.Dispose(disposing); } private readonly CMCoreDataClassesDataContext _context; } When Dispose method is called for the instance of UnityManager class it drop into recursion... Why? As far as I know base.Dispose should call the Dispose method of base class only... isn't it? Who call back the Dispose(bool) of UnityManager? How to prevent that? Thanks.

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  • Detecting Infinite recursion in Python or dynamic languages

    - by drozzy
    Recently I tried compiling program something like this with GCC: int f(int i){ if(i<0){ return 0;} return f(i-1); and it ran just fine. When I inspected the stack frames the compiler optimized the program to use only one frame, by just jumping back to the beginning of the function and only replacing the arguments to f. And - the compiler wasn't even running in optimized mode. Now, when I try the same thing in Python - I hit maximum recursion wall (or stack overflow). Is there way that a dynamic language like python can take advantage of these nice optimizations? Maybe it's possible to use a compiler instead of an interpreter to make this work? Just curious!

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  • javascript too much recursion?

    - by Ken
    Hi, I'm trying to make a script that automatically starts uploading after the data has been enter in the database(I need the autoId that the database makes to upload the file). When I run the javascript the scripts runs the php file but it fails calling the other php to upload the file. too much recursion setTimeout(testIfToegevoegd(),500); the script that gives the error send("/projects/backend/nieuwDeeltaak.php",'deeltaakNaam='+f.deeltaaknaam.value+'&beschrijving='+ f.beschrijving.value+'&startDatum='+f.startDatum.value+'&eindDatum='+f.eindDatum.value +'&deeltaakLeider='+f.leiderID.value+'&projectID='+f.projectID.value,id); function testIfToegevoegd(){ if(document.getElementById('resultaat').innerHTML == "<b>De deeltaak werd toegevoegd</b>"){ //stop met testen + upload file document.getElementById('nieuwDeeltaak').target = 'upload_target'; document.forms["nieuwDeeltaak"].submit() }else{ setTimeout(testIfToegevoegd(),500); } } testIfToegevoegd(); sorry for the dutch names we have to use them it is a school project. when I click the button that calls all this for a second time (after the error) it works fine.

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  • PHP object parent/child recursion

    - by Damien
    I've got a parent-child OO relationship. Parent obejcts has many child objects and every child object knows about it's parent by reference. The parent can be a child too (basically its a tree). When i do a var_dump() on the root object it says ["parent"]=RECURSION many times and the generated description will be really long. I'm wondering if i do something wrong. If yes, i'm interested in the "best practice". Thanks for the help!

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  • .NET Performance: Deep Recursion vs Queue

    - by JeffN825
    I'm writing a component that needs to walk large object graphs, sometimes 20-30 levels deep. What is the most performant way of walking the graph? A. Enqueueing "steps" so as to avoid deep recursion or B. A DFS (depth first search) which may step many levels deep and have a "deep" stack trace at times. I guess the question I'm asking is: Is there a performance hit in .NET for doing a DFS that causes a "deep" stack trace? If so, what is the hit? And would I better better off with some BFS by means of queueing up steps that would have been handled recursively in a DFS? Sorry if I'm being unclear. Thanks.

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  • Infinite recursion trying to check all elements of a TreeCtrl

    - by mavnn
    I have a TreeCtrl in which more than one Item can be assigned the same object as PyData. When the object is updated, I want to update all of the items in the tree which have that object as their PyData. I thought the following code would solve the problem quite neatly, but for some reason the logical test (current != self.GetFirstVisibleItem()) always returns true leading to infinite recursion. Can anyone explain why? def RefreshNodes(self, obj, current=None): print "Entered refresh" current = current or self.GetFirstVisibleItem() if current.IsOk(): print self.GetPyData(current).name if self.GetPyData(current) == obj: self.RefreshNode(current) current = self.GetNextVisible(current) if current != self.GetFirstVisibleItem(): self.RefreshNodes(obj, current) Edit: the above is obviously part of a class based on wx.TreeCtrl

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  • Tree + Recursion..

    - by RBA
    Hi.. I came across an article on Binary Trees Search . It uses intensive Recursive Algorithms.. I am just so confused with these stuff.. Please guide my path so as I understand these problems at ease, or any good website to read about recursion first and then solving these problems.. Please share your experience on it.. Its very urgent, and I want to learn these concepts as soon as possible.. Thankss... Regards.

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  • How to solve recursion relations in mathematica efficiently?

    - by Qiang Li
    I have a recursion to solve for. f(m,n)=Sum[f[m - 1, n - 1 - i] + f[m - 3, n - 5 - i], {i, 2, n - 2*m + 2}] + f[m - 1, n - 3] + f[m - 3, n - 7] f(0,n)=1, f(1,n)=n However, the following mma code is very inefficient f[m_, n_] := Module[{}, If[m < 0, Return[0];]; If[m == 0, Return[1];]; If[m == 1, Return[n];]; Return[Sum[f[m - 1, n - 1 - i] + f[m - 3, n - 5 - i], {i, 2, n - 2*m + 2}] + f[m - 1, n - 3] + f[m - 3, n - 7]];] It takes unbearably long to compute f[40,20]. Could anyone please suggest an efficient way of doing this? Many thanks!

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  • Limited recursion in C?

    - by function
    I ran this program and it output ... 65088 65089 65090 and then it stopped. Windows 7 said a.exe stopped working. Here is the code: #include <stdio.h> void go(void); main() { go(); } void go(void) { static int i = 0; printf("%d\n", i++); go(); } I think this program should keep on printing numbers indefinitely due to recursion, but it stops at 65090! The C code is compiled with gcc. Any ideas?

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  • Unable to do forwarding in BIND DNS?

    - by preethika
    I have BIND working on Windows Server 2003. i want to forward my queries to another server. Recursion is working but forwarding is not working. can u guide me to set it. i've given the following in the options: options { directory "c:\named\zones"; allow-transfer { none; }; forward only; forwarders { 8.8.8.8 ; }; recursion no; }; is the format for forwarding correct in the above. if not what is the format. Am i to give any port number in the forwarders line? Does forwarding have any particular port number? Thank You in advance....

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  • Why do I get "ignoring out-of-zone data" when restarting BIND

    - by 6bytes
    I've been using my own DNS server but then I moved to a third part DNS provider. Yesterday I wanted to go back to using my own DNS's and cancel this third party service. I've lowered TTL in current DNS conf, changed DNS info in GoDaddy for my domain and that's when problems started. My domain seems to be working only for some people but not for others so clearly something is wrong. When restarting bind service named restart everything seems to be OK but later in email from Logwatch I'm getting errors like this: mydomain.com:30: ignoring out-of-zone data (ns1.mydns.com): 3 Time(s) mydomain.info:16: ignoring out-of-zone data (ns1.mydns.com): 5 Time(s) Can anyone point me in the right direction? My BIND configuration for those two domains below: File: /var/named/chroot/etc/zones.external zone "mydomain.com" IN { type master; file "mydomain.com"; allow-transfer { 213.251.188.140; }; allow-update { none; }; notify yes; also-notify { 213.251.188.140; }; }; zone "mydomain.info" IN { type master; file "mydomain.info"; allow-transfer { 213.251.188.140; }; allow-update { none; }; notify yes; also-notify { 213.251.188.140; }; }; File /var/named/chroot/var/named/mydomain.com being my main domain $TTL 3600 $ORIGIN mydomain.com. @ IN SOA ns1.mydns.com. ns2.mydns.com. ( 2010032101 ; Serial 10800 ; Refresh 3600 ; Retry 2419200 ; Expire 3600 ) ; NXDOMAIN TTL IN NS ns1.mydns.com. IN NS ns2.mydns.com. IN MX 10 ASPMX.L.GOOGLE.COM. IN MX 20 ALT1.ASPMX.L.GOOGLE.COM. IN MX 20 ALT2.ASPMX.L.GOOGLE.COM. IN MX 30 ASPMX2.GOOGLEMAIL.COM. IN MX 30 ASPMX3.GOOGLEMAIL.COM. IN MX 30 ASPMX4.GOOGLEMAIL.COM. IN MX 30 ASPMX5.GOOGLEMAIL.COM. IN A 111.111.111.111 * IN A 111.111.111.111 edu IN A 111.111.111.111 googleXXXXXXXXXXXXXXXX IN CNAME google.com. ns1.mydns.com. IN A 111.111.111.111 File /var/named/chroot/var/named/mydomain.info just an alias in apache for mydomain.com $TTL 86400 $ORIGIN mydomain.info. @ IN SOA ns1.mydns.com. ns2.mydns.com. ( 2009042901 ; Serial 10800 ; Refresh 3600 ; Retry 2419200 ; Expire 3600 ) ; NXDOMAIN TTL IN NS ns1.mydns.com. IN NS ns2.mydns.com. IN A 111.111.111.111 * IN A 111.111.111.111 ns1.mydns.com. IN A 111.111.111.111

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  • Prevent recursive CTE visiting nodes multiple times

    - by bacar
    Consider the following simple DAG: 1->2->3->4 And a table, #bar, describing this (I'm using SQL Server 2005): parent_id child_id 1 2 2 3 3 4 //... other edges, not connected to the subgraph above Now imagine that I have some other arbitrary criteria that select the first and last edges, i.e. 1-2 and 3-4. I want to use these to find the rest of my graph. I can write a recursive CTE as follows (I'm using terminology from MSDN): with foo(parent_id,child_id) as ( // anchor member that happens to select first and last edges: select parent_id,child_id from #bar where parent_id in (1,3) union all // recursive member: select #bar.* from #bar join foo on #bar.parent_id = foo.child_id ) select parent_id,child_id from foo However, this results in edge 3-4 being selected twice: parent_id child_id 1 2 3 4 2 3 3 4 // 2nd appearance! How can I prevent the query from recursing into subgraphs that have already been described? I could achieve this if, in my "recursive member" part of the query, I could reference all data that has been retrieved by the recursive CTE so far (and supply a predicate indicating in the recursive member excluding nodes already visited). However, I think I can access data that was returned by the last iteration of the recursive member only. This will not scale well when there is a lot of such repetition. Is there a way of preventing this unnecessary additional recursion? Note that I could use "select distinct" in the last line of my statement to achieve the desired results, but this seems to be applied after all the (repeated) recursion is done, so I don't think this is an ideal solution. Edit - hainstech suggests stopping recursion by adding a predicate to exclude recursing down paths that were explicitly in the starting set, i.e. recurse only where foo.child_id not in (1,3). That works for the case above only because it simple - all the repeated sections begin within the anchor set of nodes. It doesn't solve the general case where they may not be. e.g., consider adding edges 1-4 and 4-5 to the above set. Edge 4-5 will be captured twice, even with the suggested predicate. :(

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  • Marshalling C# com items when using recursion

    - by Kevin
    I am using the SourceSafe COM object (SourceSafeTypeLib) from C# to automate a SourceSafe recursive get (part of a larger build process). The recursive function is shown below. How do I ensure that all the COM objects created in the foreach loop get released correctly? /// <summary> /// Recursively gets files/projects from SourceSafe (this is a recursive function). /// </summary> /// <param name="vssItem">The VSSItem to get</param> private void GetChangedFiles(VSSItem vssItem) { // 'If the object is a file perform the diff, // 'If not, it is a project, so use recursion to go through it if(vssItem.Type == (int)VSSItemType.VSSITEM_FILE) { bool bDifferent = false; //file is different bool bNew = false; //file is new //Surround the diff in a try-catch block. If a file is new(doesn't exist on //the local filesystem) an error will be thrown. Catch this error and record it //as a new file. try { bDifferent = vssItem.get_IsDifferent(vssItem.LocalSpec); } catch { //File doesn't exist bDifferent = true; bNew = true; } //If the File is different(or new), get it and log the message if(bDifferent) { if(bNew) { clsLog.WriteLine("Getting " + vssItem.Spec); } else { clsLog.WriteLine("Replacing " + vssItem.Spec); } string strGetPath = vssItem.LocalSpec; vssItem.Get(ref strGetPath, (int)VSSFlags.VSSFLAG_REPREPLACE); } } else //Item is a project, recurse through its sub items { foreach(VSSItem fileItem in vssItem.get_Items(false)) { GetChangedFiles(fileItem); } } }

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  • Knight's tour / recursion

    - by Layne
    Hey, I'm trying to learn a little bit more about recursion but somehow I can't solve the knight's tour and I'm hoping someone can point out my logic error. public class main { static int fsize = 5; static int board[][] = new int[fsize][fsize]; static int[] sprung_x = {1,2,2,1,-1,-2,-2,-1}; static int[] sprung_y = {-2,-1,1,2,2,1,-1,-2}; static void SucheWeg(int schrittnummer, int x, int y) { board[x][y] = schrittnummer; if( schrittnummer == ((fsize*fsize)-1)) { for(int i = 0; i<fsize; i++) { for(int c=0; c<fsize; c++) { System.out.printf("%3d", board[i][c]); } System.out.println("\n"); } } else { for(int i = 0; i<8; i++) { for(int c = 0; c<8; c++) { if( (x+sprung_x[i]) >= 0 && (x+sprung_x[i]) < fsize && (y+sprung_y[c]) >= 0 && (y+sprung_y[c]) < fsize ) { if(board[x+sprung_x[i]][y+sprung_y[c]] == -1) { System.out.println("Move: "+schrittnummer + "\n"); SucheWeg(schrittnummer+1, (x+sprung_x[i]), (y+sprung_y[c])); } } } } board[x][y] = -1; } } public static void main(String[] args) { System.out.println("Begin: \n"); for(int i = 0; i<fsize; i++) { for(int c = 0; c<fsize; c++) { board[i][c] = -1; } } SucheWeg(0, 0, 0); System.out.println("\nEnd"); } }

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  • I need to stop execution during recursive algorithm

    - by Shaza
    Hey, I have a problem in choosing the right method to accomplish my goal. I'm working on Algorithms teaching system, I'm using C#. I need to divide my algorithm into steps, each step will contain a recursion. I have to stop execution after each step, user can then move to the next step(next recursion) using a button in my GUI. After searching, threads was the right choice, but I found several methods: (Thread.sleep/interrupt): didn't work, my GUI freezed !! (Suspend/Resume): I've read that it's a bad idea to use. (Waithandles): still reading about them. (Monitor wait/resume). I don't have much time to try and read all previous methods, please help me in choosing the best method that fits my system.Any suggestions are extremal welcomed.

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  • Learning Haskell maps, folds, loops and recursion

    - by Darknight
    I've only just dipped my toe in the world of Haskell as part of my journey of programming enlightenment (moving on from, procedural to OOP to concurrent to now functional). I've been trying an online Haskell Evaluator. However I'm now stuck on a problem: Create a simple function that gives the total sum of an array of numbers. In a procedural language this for me is easy enough (using recursion) (c#) : private int sum(ArrayList x, int i) { if (!(x.Count < i + 1)) { int t = 0; t = x.Item(i); t = sum(x, i + 1) + t; return t; } } All very fine however my failed attempt at Haskell was thus: let sum x = x+sum in map sum [1..10] this resulted in the following error (from that above mentioned website): Occurs check: cannot construct the infinite type: a = a -> t Please bear in mind I've only used Haskell for the last 30 minutes! I'm not looking simply for an answer but a more explanation of it. Thanks in advanced.

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  • jQuery rotator not rotating properly - too much recursion

    - by Matt Nathanson
    I've built a custom jQuery rotator using just basic animation to rotate the 3 Divs (images). I've built the function and then reinitiate the function using it as a call back. Here's the code: function ImageRotate() { var CurrentFeature = "#container" + featureNumber; $(CurrentFeature).stop(false, true).delay(4500).animate({'top' : '330px'}, 3000); var featureNumber2 = featureNumber-1; if ( featureNumber == 1) {featureNumber2=3} var CurrentFeature2 = "#container" + featureNumber2; $(CurrentFeature2).stop(false, true).delay(4500).animate({'top' : '0px'}, 3000); $('#container2').stop(false, true).delay(4500).animate({'top' : '-330px'}, 25); var featureNumber3 = featureNumber+1; if ( featureNumber == 3){featureNumber3=1} var CurrentFeature3 = "#container" + featureNumber3; $(CurrentFeature3).stop(false, true).delay(7500).animate({'top' : '0px'}, 3000); $(CurrentFeature2).stop(false, true).delay(4500).animate({'top' : '330px'}, 3000); $(CurrentFeature).stop(false, true).delay(4500).animate({'top' : '-330px'}, 25); if (featureNumber ==1) {featureNumber=3} else{featureNumber--}; $(CurrentFeature).stop(false, true).delay(7500).animate({'top' : '0px'}, 3000); $(CurrentFeature3).stop(false, true).delay(4500).animate({'top' : '330px'}, 3000); $(CurrentFeature2).stop(false, false).delay(4500).animate({'top' : '-330px'}, 25,ImageRotate()); }; It's worth noting that when calling the function again I also tried making another function called ImageRotate2(); and it did the same thing. It loops, but i get all sorts of funkiness. Edit: I've also tried some answers in the replies and they both leave me with recursion errors each second.

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  • too much recursion in javascript with jquery mouseover

    - by Stacia
    I am a JS novice. Using some code I found here to help me with mouseover scale/rotate images but now when I try to apply it to more than one object I'm getting errors saying "too much recursion". Before the function didn't take any arguments, it just was on s_1 and it worked fine. I am tempted to just write different code for each object but that isn't very good programming practice. var over = false; $(function(){ $("#s_1").hover(function(){ over = true; swing_left_anim("#s_1"); }, function(){ over = false; }); $("#np_1").hover(function(){ over = true; swing_left_anim("np_1"); }, function(){ over = false; }); }); function swing_left_anim(obj){ $(obj).animate({ rotate: '0deg' }, { duration: 500 }); if (over) { $(obj).animate({ rotate: '25deg' }, 500, swing_right_anim(obj)); } } function swing_right_anim(obj){ $(obj).animate({ rotate: '-25deg' }, 500, swing_left_anim(obj)); }

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  • Nested loops through recursion with usable iterators

    - by narandzasto
    Help! I need to generate a query with loops,but there must be undefinitly numbers of loop or much as many a client wants. I know that it can be done with recursion,but don't know exectly how.One more thing. Notice,please,that I need to use those k,i,j iterators later in "if" condition and I don't know how to catch them. Thanks class Class1 { public void ListQuery() { for (int k = 0; k < listbox1.Count; k++) { for (int i = 0; i < listbox2.Count; i++) { for (int j = 0; j < listbox3.Count; j++) { if (k == listbox1.count-1 && i == listbox2.count-1 && j == listbox3.count-1) { if (!checkbox1) Query += resultset.element1 + "=" + listbox1[k]; if (!checkbox2) Query += resultset.element2 + "=" + listbox1[i]; if (!checkbox3) Query += resultset.element3 + "=" + listbox1[j]; } } } } } }

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  • C# Recursion SumOfOnlyNeg Elements

    - by Chris
    Hello, A array gets filled up with random elements (negative and positive). Now i want to calculate the sum of ONLY the postive elements. Iterative there is no problem, but in the recursion version i can only get the sum of both negative and postive. How can i "check" in the recursive version that it only sums up the Postive elements? Best Regards. Iterative version: public int IterSomPosElem(int[] tabel, int n) { n = 0; for (int i = 0; i < tabel.Length; i++) { if (tabel[i] >= 0) { n += tabel[i]; } } return n; } Recursive version atm (sums up all the elements insteed, of only the positive) public int RecuSomPosElem(int[] tabel, int n) { if(n == 1) return tabel[0]; //stopCriterium else { return (tabel[n - 1] + RecuSomPosElem(tabel, n - 1)); // how to check, so it only sums up the postive elements and "ignores" the negative elements. } }

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  • Trie Backtracking in Recursion

    - by Darksky
    I am building a tree for a spell checker with suggestions. Each node contains a key (a letter) and a value (array of letters down that path). So assume the following sub-trie in my big trie: W / \ a e | | k k | | is word--> e e | ... This is just a subpath of a sub-trie. W is a node and a and e are two nodes in its value array etc... At each node, I check if the next letter in the word is a value of the node. I am trying to support mistyped vowels for now. So 'weke' will yield 'wake' as a suggestion. Here's my searchWord function in my trie: def searchWord(self, word, path=""): if len(word) > 0: key = word[0] word = word[1:] if self.values.has_key(key): path = path + key nextNode = self.values[key] return nextNode.searchWord(word, path) else: # check here if key is a vowel. If it is, check for other vowel substitutes else: if self.isWord: return path # this is the word found else: return None Given 'weke', at the end when word is of length zero and path is 'weke', my code will hit the second big else block. weke is not marked as a word and so it will return with None. This will return out of searchWord with None. To avoid this, at each stack unwind or recursion backtrack, I need to check if a letter is a vowel and if it is, do the checking again. I changed the if self.values.has_key(key) loop to the following: if self.values.has_key(key): path = path + key nextNode = self.values[key] ret = nextNode.searchWord(word, path) if ret == None: # check if key == vowel and replace path # return nextNode.searchWord(... return ret What am I doing wrong here? What can I do when backtracking to achieve what I'm trying to do?

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  • How do I make a recursive list that checks company rankings?

    - by Sera
    I have a set of companies in rank order. I want my rule to check if the companies in a specified list are in rank order, and for the rule to recur until all companies in the list have been checked. I currently have the following: isOrder([]). isOrder([COM1,COM2|T]) :- rank(COM1,D), rank(COM2,E), D<E, print("in order"), isOrder([COM2|T]). However, this does not seem to work. Sometimes, the recursion goes on forever without ending, and sometimes the recursion doesn't work at all. This is when I vary the code to try and get the correct answer. Can anybody help me? I have just started Prolog and my understanding of it is severely limited. Any help would be greatly appreciated.

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  • www do not equal no www

    - by marc-andre menard
    I have a website with dns pointing to my own server. the website WITH www.mysite.com lead to the right site, but the address mysite.com lead to a publicity site that I DONT CONTROL I like to make www.mysite.com and the mysite.com lead to the same DNS Can i make it with .htaccess or with google analitic, but since i dont know the resolver that lead me to the bizzare page i dont have control on that As request : http://www.demolition-st-chrysostome.org/ (ok) http://demolition-st-chrysostome.org/ (no)

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