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  • How to change the coordinate of a point that is inside a GraphicsPath?

    - by Ben
    Is there anyway to change the coordinates of some of the points within a GraphicsPath object while leaving the other points where they are? The GraphicsPath object that gets passed into my method will contain a mixture of polygons and lines. My method would want to look something like: void UpdateGraphicsPath(GraphicsPath gPath, RectangleF regionToBeChanged, PointF delta) { // Find the points in gPath that are inside regionToBeChanged // and move them by delta. // gPath.PathPoints[i].X += delta.X; // Compiles but doesn't work } GraphicsPath.PathPoints seems to be readonly, so does GraphicsPath.PathData.Points. So I am wondering if this is even possible. Perhaps generating a new GraphicsPath object with an updated set of points? How can I know if a point is part of a line or a polygon? If anyone has any suggestions then I would be grateful.

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  • How can I plot an iteration coordinate(x,y) data with only label in GNUplot?

    - by Mojiiz Alamode
    I have the set of data like this 0 268 195 1 353 199 2 318 209 3 268 232 4 370 238 5 326 253 6 246 265 7 372 284 8 313 290 9 258 297 0 268 196 1 353 199 2 318 209 3 268 233 4 370 238 5 325 253 6 246 265 7 372 284 8 313 290 9 258 297 I would like to use first column for label and second and third for (x,y) plot, however, I would like to plot only one time label without iteration. How should I do? Thank you for help.

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  • Google maps spatial reference system

    - by JavaRocky
    What is Google map's spatial reference system using when you enter a lat, long into the maps search bar? I've found hints that it might be WGS84 but after converting to that coordinate system, nothing shows up when i paste the coordinates into the google maps search box. I am converting from GDA MGA 56. Sample: Input MGA56 coords: 336301, 6253363 Expected WGS86 coords: -33.8473340793201, 151.230631835944 I get: 16834916.928327594 -4008321.1020318186 Spatial coord systems: EPSG:28356 for MGA56 EPSG:900913 for WGS86 (google maps) I am using geotools to do the transform: CoordinateReferenceSystem crsMga56 = CRS.parseWKT(mga56); CoordinateReferenceSystem crsGmaps = CRS.parseWKT(gmaps); Coordinate coordinate = new Coordinate(336301, 6253363); Point point = new GeometryFactory().createPoint(coordinate); MathTransform transform = CRS.findMathTransform(crsMga56, crsGmaps); Geometry geometry = JTS.transform(point, transform); I know the transform is not correct, as when i use an online tool it gives me the correct coords. http://www.environment.gov.au/cgi-bin/transform/mga2geo%5Fgda.pl?east=336301&north=6253363&zone=56

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  • How to reproject a shapefile from WGS 84 to Spherical/Web Mercator projection.

    - by samkea
    Definitions: You will need to know the meaning of these terms below. I have given a small description to the acronyms but you can google and know more about them. #1:WGS-84- World Geodetic Systems (1984)- is a standard reference coordinate system used for Cartography, Geodesy and Navigation. #2: EPGS-European Petroleum Survey Group-was a scientific organization with ties to the European petroleum industry consisting of specialists working in applied geodesy, surveying, and cartography related to oil exploration. EPSG::4326 is a common coordinate reference system that refers to WGS84 as (latitude, longitude) pair coordinates in degrees with Greenwich as the central meridian. Any degree representation (e.g., decimal or DMSH: degrees minutes seconds hemisphere) may be used. Which degree representation is used must be declared for the user by the supplier of data. So, the Spherical/Web Mercator projection is referred to as EPGS::3785 which is renamed to EPSG:900913 by google for use in googlemaps. The associated CRS(Coordinate Reference System) for this is the "Popular Visualisation CRS / Mercator ". This is the kind of projection that is used by GoogleMaps, BingMaps,OSM,Virtual Earth, Deep Earth excetra...to show interactive maps over the web with thier nearly precise coordinates.  Reprojection: After reading alot about reprojecting my coordinates from the deepearth project on Codeplex, i still could not do it. After some help from a colleague, i got my ball rolling.This is how i did it. #1 You need to download and open your shapefile using Q-GIS; its the one with the biggest number of coordinate reference systems/ projections. #2 Use the plugins menu, and enable ftools and the WFS plugin. #3 Use the Vector menu--> Data Management Tools and choose define current projection. Enable, use predefined reference system and choose WGS 84 coodinate system. I am personally in zone 36, so i chose WGS84-UTM Zone 36N under ( Projected Coordinate Systems--> Universal Transverse Mercator) and click ok. #4 Now use the Vector menu--> Data Management Tools and choose export to new projection. The same dialog will pop-up. Now choose WGS 84 EPGS::4326 under Geodetic Coordinate Systems. My Input user Defined Spatial Reference System should looks like this: +proj=tmerc +lat_0=0 +lon_0=33 +k=0.9996 +x_0=500000 +y_0=200000 +ellps=WGS84 +datum=WGS84 +units=m +no_defs Your Output user Defined Spatial Reference System should look like this: +proj=longlat +ellps=WGS84 +datum=WGS84 +no_defs Browse for the place where the shapefile is going to be and give the shapefile a name(like origna_reprojected). If it prompts you to add the projected layer to the TOC, accept. There, you have your re-projected map with latitude and longitude pair of coordinates. #5 Now, this is not the actual Spherical/Web Mercator projection, but dont worry, this is where you have to stop. All the other custom web-mapping portals will pick this projection and transform it into EPGS::3785 or EPSG:900913 but the coordinates will still remain as the LatLon pair of the projected shapefile. If you want to test, a particular know point, Q-GIS has a lot of room for that. Go ahead and test it.

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  • Can get coordinates from iPhone simulator, but can't get coordinates from iPhone device

    - by iPhoneARguy
    Hi everyone, I've run into something of a mysterious bug (to me). I have some code to pick out the user's current location on the iPhone SDK. It works fine on the iPhone simulator, but when I try to run it on the actual device, I get a weird error. Here is the code (I am using ASIFormDataRequest to create a POST request): ASIFormDataRequest * request = [ASIFormDataRequest requestWithURL:url]; [request setPostValue:@"testauthor" forKey:@"author"]; [request setPostValue:[[NSNumber numberWithDouble:datum.location.coordinate.latitude] stringValue] forKey:@"latitude"]; NSLog(@"%f", datum.location.coordinate.latitude); NSLog(@"%f", datum.location.coordinate.longitude); [request setPostValue:[[NSNumber numberWithDouble:datum.location.coordinate.longitude] stringValue] forKey:@"longitude"]; [request setPostValue:datum.comment forKey:@"comment"]; On the simulator, NSLog does log both the latitude and longitude, but on the iPhone, it does not. Even stranger, when I go through with the debugger on the device, I try "po datum.location", I get <+###, -###> +/- 223.10m (speed 0.00 mps / course -1.00) @ 2010-05-02 22:18:37 -0400 (### replaced by my location) but when I do "(gdb) po datum.location.coordinate" I get: There is no member named coordinate. Do you guys have any idea why this might happen? Thanks in advance for your help!

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  • Setting corelocation results to NSNumber object parameters

    - by Dan Ray
    This is a weird one, y'all. - (void)locationManager:(CLLocationManager *)manager didUpdateToLocation:(CLLocation *)newLocation fromLocation:(CLLocation *)oldLocation { CLLocationCoordinate2D coordinate = newLocation.coordinate; self.mark.longitude = [NSNumber numberWithDouble:coordinate.longitude]; self.mark.latitude = [NSNumber numberWithDouble:coordinate.latitude]; NSLog(@"Got %f %f, set %f %f", coordinate.latitude, coordinate.longitude, self.mark.latitude, self.mark.longitude); [manager stopUpdatingLocation]; manager.delegate = nil; if (self.waitingForLocation) { [self completeUpload]; } } The latitude and longitude in that "mark" object are synthesized parameters referring to NSNumber iVars. In the simulator, my NSLog output for that line in the middle there reads: 2010-05-28 15:08:46.938 EverWondr[8375:207] Got 37.331689 -122.030731, set 0.000000 -44213283338325225829852024986561881455984640.000000 That's a WHOLE lot further East than 1 Infinite Loop! The numbers are different on the device, but similar--lat is still zero and long is a very unlikely high negative number. Elsewhere in the controller I'm accepting a button press and uploading a file (an image I just took with the camera) with its geocoding info associated, and I need that self.waitingForLocation to inform the CLLocationManager delegate that I already hit that button and once its done its deal, it should go ahead and fire off the upload. Thing is, up in the button-click-receiving method, I test see if CL is finished by testing self.mark.latitude, which seems to be getting set zero...

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  • Hibernate Mapping Annotation Question?

    - by paddydub
    I've just started using hibernate and I'm trying to map walking distance between two coordinates into a hashmap, There can be many connections from one "FromCoordinate" to another "ToCoordinate". I'm not sure if i've implemented this correctly, What annotations do i need to map this MashMap? Thanks @Entity @Table(name = "COORDCONNECTIONS") public class CoordinateConnection implements Serializable{ private static final long serialVersionUID = -1624745319005591573L; /** auto increasing id number */ @GeneratedValue(strategy = GenerationType.IDENTITY) @Column(name = "ID") @id private int id; @Embedded public FromCoordinate fromCoord; @Embedded public ToCoordinate toCoord; HashMap<Coordinate, ArrayList<Coordinate>> coordWalkingConnections = new HashMap<Coordinate, ArrayList<Coordinate>>(); } public class FromCoordinate implements ICoordinate { @Column(name = "FROM_LAT") private double latitude; @Column(name = "FROM_LNG") private double longitude; } public class ToCoordinate implements ICoordinate { @Column(name = "TO_LAT") private double latitude; @Column(name = "TO_LNG") private double longitude; @Column(name = "DISTANCE") private double distance; } DATABASE STRUCTURE id FROM_LAT FROM_LNG TO_LAT TO_LNG Dist 1 43.352669 -6.264341 43.350012 -6.260653 0.38 2 43.352669 -6.264341 43.352669 -6.264341 0.00 3 46.352669 -6.264341 43.353373 -6.262013 0.17 4 47.352465 -6.265865 43.351290 -6.261200 0.25 5 45.452578 -6.265768 43.352788 -6.264396 0.01 6 45.452578 -6.265768 45.782788 -6.234523 0.01 ..... ... . Example HashMap for HashMap<Coordinate, ArrayList<Coordinate>> <KEY{43.352669 -6.264341}, Arraylist VALUES{(43.350012,-6.260653,0.383657), (43.352669, -6.264341, 0.000095), (43.353373, -6.262013, 0.173201)}> <KEY{47.352465 -6.265865}, Arraylist VALUES{(43.351290,-6.261200,0.258781)}> <KEY{45.452578 -6.265768}, Arraylist VALUES{(43.352788,-6.264396,0.013726),(45.782788,-6.234523,0.017726)}>

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  • Reverse geocode coordinates to street address and setting as subtitle in annotation?

    - by Krismutt
    Hey everybody! Basically I wanna reverse geocode my coordinates for my annotation and show the address as the subtitle for the annotation. I just cant figure out how to do it... savePosition.h #import <Foundation/Foundation.h> #import <MapKit/MapKit.h> #import <MapKit/MKReverseGeocoder.h> #import <AddressBook/AddressBook.h> @interface savePosition : NSObject <MKAnnotation, MKReverseGeocoderDelegate> { CLLocationCoordinate2D coordinate; } @property (nonatomic, readonly) CLLocationCoordinate2D coordinate; -(id)initWithCoordinate:(CLLocationCoordinate2D) coordinate; - (NSString *)subtitle; - (NSString *)title; @end savePosition.m @synthesize coordinate; -(NSString *)subtitle{ return [NSString stringWithFormat:@"%f", streetAddress]; } -(NSString *)title{ return @"Saved position"; } -(id)initWithCoordinate:(CLLocationCoordinate2D) coor{ coordinate=coor; NSLog(@"%f,%f",coor.latitude,coor.longitude); return self; MKReverseGeocoder *geocoder = [[MKReverseGeocoder alloc] initWithCoordinate:coordinate]; geocoder.delegate = self; [geocoder start]; } - (void)reverseGeocoder:(MKReverseGeocoder *)geocoder didFailWithError:(NSError *)error { } - (void)reverseGeocoder:(MKReverseGeocoder *)geocoder didFindPlacemark:(MKPlacemark *)placemark{ NSString *streetAddress = [NSString stringWithFormat:@"%@", [placemark.addressDictionary objectForKey:kABPersonAddressStreetKey]]; } @end any ideas?? Thanks in advance!

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  • Resultant Vector Algorithm for 2D Collisions

    - by John
    I am making a Pong based game where a puck hits a paddle and bounces off. Both the puck and the paddles are Circles. I came up with an algorithm to calculate the resultant vector of the puck once it meets a paddle. The game seems to function correctly but I'm not entirely sure my algorithm is correct. Here are my variables for the algorithm: Given: velocity = the magnitude of the initial velocity of the puck before the collision x = the x coordinate of the puck y = the y coordinate of the puck moveX = the horizontal speed of the puck moveY = the vertical speed of the puck otherX = the x coordinate of the paddle otherY = the y coordinate of the paddle piece.horizontalMomentum = the horizontal speed of the paddle before it hits the puck piece.verticalMomentum = the vertical speed of the paddle before it hits the puck slope = the direction, in radians, of the puck's velocity distX = the horizontal distance between the center of the puck and the center of the paddle distY = the vertical distance between the center of the puck and the center of the paddle Algorithm solves for: impactAngle = the angle, in radians, of the angle of impact. newSpeedX = the speed of the resultant vector in the X direction newSpeedY = the speed of the resultant vector in the Y direction Here is the code for my algorithm: int otherX = piece.x; int otherY = piece.y; double velocity = Math.sqrt((moveX * moveX) + (moveY * moveY)); double slope = Math.atan(moveX / moveY); int distX = x - otherX; int distY = y - otherY; double impactAngle = Math.atan(distX / distY); double newAngle = impactAngle + slope; int newSpeedX = (int)(velocity * Math.sin(newAngle)) + piece.horizontalMomentum; int newSpeedY = (int)(velocity * Math.cos(newAngle)) + piece.verticalMomentum; for those who are not program savvy here is it simplified: velocity = v(moveX² + moveY²) slope = arctan(moveX / moveY) distX = x - otherX distY = y - otherY impactAngle = arctan(distX / distY) newAngle = impactAngle + slope newSpeedX = velocity * sin(newAngle) + piece.horizontalMomentum newSpeedY = velocity * cos(newAngle) + piece.verticalMomentum My Question: Is this algorithm correct? Is there an easier/simpler way to do what I'm trying to do?

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  • Storing a Hex Grid

    - by Pedro Caetano
    I've been creating a small hex grid framework for Unity3D and have come to the following dilema. This is my coordinate system (taken from here) Link because I'm a new user It all works pretty nicely except for the fact I have no idea how to store it. I originally intended to store this in a 2D array and use images to generate my maps. One problem was that it had negative values (this was easily fixed by offsetting the coordinates a bit). However, due to this coordinate system, such an image or bitmap would have to be diamond shaped - and since these structures are square shaped, this would cause a lot of headaches even if I hack something together. Is there anything I'm missing that could fix this? I recall seeing a forum post regarding this in the unity forums but I can no longer find the link. Is writing a set of coordinate translators the best solution here? If you guys think it would be helpful, I can post code and images of my problem.

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  • Find the new coordinates using a starting point, a distance, and an angle

    - by dqhendricks
    Okay, say I have a point coordinate. var coordinate = { x: 10, y: 20 }; Now I also have a distance and an angle. var distance = 20; var angle = 72; The problem I am trying to solve is, if I want to travel 20 points in the direction of angle from the starting coordinate, how can I find what my new coordinates will be? I know the answer involves things like sin/cosin, because I used to know how to do this, but I have since forgotten the formula. Can anyone help?

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  • implementing a high level function in a script to call a low level function in the game engine

    - by eat_a_lemon
    In my 2d game engine I have a function that does pathfinding, find_shortest_path. It executes for each time step in the game loop and calculates the next coordinate pair in the series of coordinates to reach the destination object. Now I want to call this function in a scripting language and have it only return the last coordinate pair result. I want the game engine to go about the business of rendering the incremental steps but I don't want the high level script to care about the rendering. The high level script is only for ai game logic. Now I know how to bind a method from C to python but how can I signal and coordinate the wait time between the incremental steps without the high level function returning until its time for the last step?

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  • WPF 3D - converting from Point2D to Point3D and back again

    - by DanM
    I'm new to WPF 3D, so I may just be missing something obvious, but how would I go about converting from a 2D coordinate to a 3D coordinate and back again? I'd like the 2D coordinate to be the location measured from the upper-left corner of Viewport3D and the 3D coordinate to be the location relative to the origin (0, 0, 0) of the 3D world. The conversion functions should have these signatures: public Point3D Point2DAndWorldZToPoint3D(Point2D point2D, double worldZ) // usually I want to know where a 2D point will be on the ground plane // so worldZ will usually be zero (but not always) public Point2D Point3DToPoint2D(Point3D point3D) I found this related question, but it only addresses conversion from 3D to 2D (not the reverse), and I'm not sure if the answers are up-to-date. Note, I'm currently using .NET 3.5, but if there are improvements in .NET 4.0 that would help me, please let me know.

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  • database design to speed up hibernate querying of large dataset

    - by paddydub
    I currently have the below tables representing a bus network mapped in hibernate, accessed from a Spring MVC based bus route planner I'm trying to make my route planner application perform faster, I load all the above tables into Lists to perform the route planner logic. I would appreciate if anyone has any ideas of how to speed my performace Or any suggestions of another method to approach this problem of handling a large set of data Coordinate Connections Table (INT,INT,INT)( Containing 50,000 Coordinate Connections) ID, FROMCOORDID, TOCOORDID 1 1 2 2 1 17 3 1 63 4 1 64 5 1 65 6 1 95 Coordinate Table (INT,DECIMAL, DECIMAL) (Containing 4700 Coordinates) ID , LAT, LNG 0 59.352669 -7.264341 1 59.352669 -7.264341 2 59.350012 -7.260653 3 59.337585 -7.189798 4 59.339221 -7.193582 5 59.341408 -7.205888 Bus Stop Table (INT, INT, INT)(Containing 15000 Stops) StopID RouteID COORDINATEID 1000100001 100 17 1000100002 100 18 1000100003 100 19 1000100004 100 20 1000100005 100 21 1000100006 100 22 1000100007 100 23 This is how long it takes to load all the data from each table: stop.findAll = 148ms, stops.size: 15670 Hibernate: select coordinate0_.COORDINATEID as COORDINA1_2_, coordinate0_.LAT as LAT2_, coordinate0_.LNG as LNG2_ from COORDINATES coordinate0_ coord.findAll = 51ms , coordinates.size: 4704 Hibernate: select coordconne0_.COORDCONNECTIONID as COORDCON1_3_, coordconne0_.DISTANCE as DISTANCE3_, coordconne0_.FROMCOORDID as FROMCOOR3_3_, coordconne0_.TOCOORDID as TOCOORDID3_ from COORDCONNECTIONS coordconne0_ coordinateConnectionDao.findAll = 238ms ; coordConnectioninates.size:48132 Hibernate Annotations @Entity @Table(name = "STOPS") public class Stop implements Serializable { @Id @GeneratedValue @Column(name = "COORDINATEID") private Integer CoordinateID; @Column(name = "LAT") private double latitude; @Column(name = "LNG") private double longitude; } @Table(name = "COORDINATES") public class Coordinate { @Id @GeneratedValue @Column(name = "COORDINATEID") private Integer CoordinateID; @Column(name = "LAT") private double latitude; @Column(name = "LNG") private double longitude; } @Entity @Table(name = "COORDCONNECTIONS") public class CoordConnection { @Id @GeneratedValue @Column(name = "COORDCONNECTIONID") private Integer CoordinateID; /** * From Coordinate_id value */ @Column(name = "FROMCOORDID", nullable = false) private int fromCoordID; /** * To Coordinate_id value */ @Column(name = "TOCOORDID", nullable = false) private int toCoordID; //private Coordinate toCoordID; }

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  • MacRuby - CLLocation Properties Not Accessible

    - by Craig Williams
    Anyone know why this works in Objective-C but not in MacRuby? Objective-C Version: CLLocation *loc = [[CLLocation alloc] initWithLatitude:38.0 longitude:-122.0]; NSLog(@"Lat: %.2f", loc.coordinate.latitude); NSLog(@"Long: %.2f", loc.coordinate.longitude); [loc release]; // Results: // 2010-04-30 16:48:55.568 OCCoreLocationTest[70030:a0f] Lat: 38.00 // 2010-04-30 16:48:55.570 OCCoreLocationTest[70030:a0f] Long: -122.00 Here is the MacRuby version with results: loc = CLLocation.alloc.initWithLatitude(38.0, longitude:-122.0) puts loc.class # => CLLocation puts loc.description # => <+38.00000000, -122.00000000> +/- 0.00m (speed -1.00 mps / course -1.00) @ 2010-04-30 16:37:47 -0600 puts loc.respond_to?(:coordinate) # => true puts loc.coordinate.latitude # => Error: unrecognized runtime type `{?=dd}' (TypeError)

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  • How do faces in .obj work?

    - by Adl
    Hi When parsing an .obj-file, with vertices and vertex-faces, it is easy to pass the vertices to the shader and the use glDrawElements using the vertex-faces. When parsing an .obj-file, with vertices and texture-coordinates, another type of face occur: texture-coordinate faces. When displaying textures, apart from loading images, binding them and passing texture coordinates into the parser, how to use the texture-coordinate faces? They differ from the vertex-faces and I suppose that the texture-coordinate faces have a purpose when displaying textures? Regards Niclas

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  • pass array by reference in c

    - by Yassir
    How can I pass an array of struct by reference ? example : struct Coordinate { int X; int Y; }; SomeMethod(Coordinate *Coordinates[]){ //Do Something with the array } int main(){ Coordinate Coordinates[10]; SomeMethod(&Coordinates); }

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  • View results of affine transform

    - by stckjp
    I am trying to find out the reason why when I apply affine transformations on an image in OpenCV, the result of it is not visible in the preview window, but the entire window is black.How can I find workaround for this problem so that I can always view my transformed image (the result of the affine transform) in the window no matter the applied transformation? Update: I think that this happens because all the transformations are calculated with respect to the origin of the coordinate system (top left corner of the image). While for rotation I can specify the center of the rotation, and I am able to view the result, when I perform scaling I am not able to control where the transformed image goes. Is it possible to somehow move the coordinate system to make the image fit in the window? Update2: I have an image which contains only ROI at some position in it (the rest of the image is black), and I need to apply a set of affine transforms on it. To make things simpler and to see the effect of each individual transform, I applied each transform one by one. What I noticed is that, whenever I move (translate) the image such that the center of the ROI is in the center of the coordinate system (top left corner of the view window), all the affine transforms perform correctly without moving. However, by translating the center of ROI at the center of the coordinate system, the upper and the left part of the ROI remain cut out of the current view window. If I move ROI's central point to another point in the view window (for example the window center), an affine transform of type: A=[a 0 0; 0 b 0] (A is 2x3 matrix, parameter of the warpAffine function) moves the image (ROI), outside of the view window (which doesn't happen if the ROI's center is in the top-left corner). How can I modify the affine transform so the image doesn't move out of its place (behaves the same way as when the ROI center is in the center of the coordinate system)?

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  • matlab: how to transform screen pixels into specific coordinates

    - by user3137385
    I have to draw a curve captured on a image using screen pixels (mouse clicks) into a coordinate system. E.g.: Pixels on the screen, from left to right (130 px to 970 px) correspond to the x-axis of my coordinate system (1000 to 6000). Pixels from bottom to top (670 to 99) correspond to the y-axis of coordinate system (0 to 1.2). How can this be done? Maybe there's a function in matlab doing something like that? Some more explanation: I have a jpg image of a curve on a coordinate system. I've got pixel positions (x,y) of several points on that curve. Now I want to plot same curve into a matlab figure with same x and y axis as on the jpg image.

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  • How to fetch managed objects sorted by calculated value

    - by Marcin Zbijowski
    Hello, I'm working on the app that uses CoreData. There is location entity that holds latitude and longitude values. I'd like to fetch those entities sorted by distance to the user's location. I tried to set sort descriptor to distance formula sqrt ((x1 - x2)^2 + (y1 - y2)^2) but it fails with exception "... keypath ... not found in entity". NSString *distanceFormula = [NSString stringWithFormat:@"sqrt(((latitude - %f) * (latitude - %f)) + ((longitude - %f) * (longitude - %f)))", location.coordinate.latitude, location.coordinate.latitude, location.coordinate.longitude, location.coordinate.longitude]; NSSortDescriptor *sortDescriptor = [[NSSortDescriptor alloc] initWithKey:distanceFormula ascending:YES]; [fetchRequest setSortDescriptors:[NSArray arrayWithObject:sortDescriptor]]; NSError *error; NSArray *result = [[self managedObjectContext] executeFetchRequest:fetchRequest error:&error]; I'd like to fetch already sorted objects rather then fetch them all and then sort in the code. Any tips appreciated.

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  • Sep 10 Week - I'll be on the West Coast Speaking in Irvine and San Fran

    - by RickHeiges
    In my role as a Solutions Architect for Scalability Experts, I often get to present to customers about the work that we performed. Unfortunately, this is often on short notice and I can't coordinate a trip to participate in a User Group Meeting. Next week, I was able to coordinate my west coast trip to be able to present. I am heading to Irvine at the MTC on Sepember 11 and San Francisco at the MSFT offices on Sep 13 to speak to customers who want to learn more about SQL Server 2012.To register for...(read more)

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  • get stick analogue XY position using Jinput in lwjgl

    - by oIrC
    i want to capture the movement of the analogue stick of the gamePad. is there any equivalent function to this public void mouseMoved(MouseEvent mouseEvent) { mouseEvent.getX(); //return the X coordinate of the cursor inside a component mouseEvent.getY();//return the Y coordinate of the cursor inside a component } into lwjgl.input.Controllers, i found controller.getAxisValue() but this one doesn't work as the function above. any help? thanks.

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  • An alternative to a video codec for storing motion changes [on hold]

    - by Andrew Simpson
    I have a 3 dimensional byte array. The 3-d array represents a jpeg image. Each channel/array represents part of the RGB spectrum. I am not interested in retaining black pixels. A black pixel is represented by this atypical arrangement: myarray[0,0,0] =0; myarray[0,0,1] =0; myarray[0,0,2] =0; So, I have flattened this 3d array out to a 1d array by doing this byte[] AFlatArray = new byte[width x height x 3] and then assigning values respective to the coordinate. But like I said I do not want black pixels. So this array has to only contain color pixels with the x,y coordinate. The result I want is to re-represent the image from the i dimension byte array that only contains non-black pixels. How do I do that? It looks like I have to store black pixels as well because of the xy coordinate system. I have tried writing to a binary file but the size of that file is greater than the jpeg file as the jpeg file is compressed. I am using c#.

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  • Excel: Plot order total in map coordinates

    - by Phliplip
    I have a set of data that looks like this: -X--Y----Amount- AE 24 $178,00 Y 27 $162,00 AD 34 $680,00 AK 35 $178,00 Y 25 $29,00 U 23 $178,00 X 38 $193,00 AC 30 $226,00 AK 39 $152,00 AJ 34 $217,00 AC 35 $183,00 AA 22 $211,00 Z 19 $172,00 AJ 32 $187,00 AF 26 $272,00 AI 27 $220,00 AJ 34 $320,00 AB 32 $183,00 AB 35 $272,00 AC 32 $207,00 AB 28 $178,00 AC 30 $168,00 AC 28 $178,00 AB 32 $310,00 AD 30 $188,00 AB 35 $188,00 The sample above is only an excerpt of the total dataset of 16K rows Each row represents a single delivery order, where the 2 first columns are the map coordinate and the third the purchase amount. Would it be possible to plot the above data in a chart or coordinate system. Where the each plot should be a summary of all sales in the same map coordinate. Also a similar chart of order count would be nice to have.

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