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  • Best way to implement mouse-based movement in MMOG

    - by fiftyeight
    I want to design an MMO where players click the destination they want to walk to with their mouse and the character moves there, similar to Runescape in this manner. I think it should be easier than keyboard movement since the client can simply send the server the destination each time the player clicks on a destination. The main thing I'm trying to decide is what to do when there are obstacles in the way. It's no problem to implement a simple path-finding solution on the client, the question is if the server will do path-finding as well, since it'll probably take too much Computation power from the server. What I though is that when there is an obstacle the client will send only the first coordinate it plans to go to and then when he gets there he'll send the next coordinate automatically. For example if there is a rock in the way the character will decide on a route that is made of two destinations so it goes around the rock and when it arrives at the first destination it sends the next coordinate. That way if the player changes destination is the middle he won't send unnecessary information. Is this a good way to implement it and is there a standard way MMOGs usually do it? EDIT: I should also mention that the server will make sure all movements are legal and there aren't any walls in the way etc. In the way I wrote it should be quite easy since all movements will be sent in straight lines so the server will just check there aren't any obstacles along that line.

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  • OpenGL ES rotate texture

    - by 0xSina
    I just got started with OpenGL ES... I have a fragment: const char * sFragment = _STRINGIFY( varying highp vec2 coordinate; precision mediump float; uniform vec4 maskC; uniform float threshold; uniform sampler2D videoframe; uniform sampler2D videosprite; uniform vec4 mask; uniform vec4 maskB; uniform int recording; vec3 normalize(vec3 color, float meanr) { return color*vec3(0.75 + meanr, 1., 1. - meanr); } void main() { float d; float dB; float dC; float meanr; float meanrB; float meanrC; float minD; vec4 pixelColor; vec4 spriteColor; pixelColor = texture2D(videoframe, coordinate); spriteColor = texture2D(videosprite, coordinate); meanr = (pixelColor.r + mask.r)/8.; meanrB = (pixelColor.r + maskB.r)/8.; meanrC = (pixelColor.r + maskC.r)/8.; d = distance(normalize(pixelColor.rgb, meanr), normalize(mask.rgb, meanr)); dB = distance(normalize(pixelColor.rgb, meanrB), normalize(maskB.rgb, meanrB)); dC = distance(normalize(pixelColor.rgb, meanrC), normalize(maskC.rgb, meanrC)); minD = min(d, dB); minD = min(minD, dC); gl_FragColor = spriteColor; if (minD > threshold) { gl_FragColor = pixelColor; } } Now, depending on wether recording is 0 or 1, I want to rotate uniform sampler2D videosprite 180 degrees (reflection in x-axis, flip vertically). How can I do that? I found the function glRotatef(), but how do i specify that I want to rotate video sprite and not videoframe? Thanks

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  • Converting 3 dimension byte array to a single byte array [on hold]

    - by Andrew Simpson
    I have a 3 dimensional byte array. The 3-d array represents a jpeg image. Each channel/array represents part of the RGB spectrum. I am not interested in retaining black pixels. A black pixel is represented by this atypical arrangement: myarray[0,0,0] =0; myarray[0,0,1] =0; myarray[0,0,2] =0; So, I have flattened this 3d array out to a 1d array by doing this byte[] AFlatArray = new byte[width x height x 3] and then assigning values respective to the coordinate. But like I said I do not want black pixels. So this array has to only contain color pixels with the x,y coordinate. The result I want is to re-represent the image from the i dimension byte array that only contains non-black pixels. How do I do that? It looks like I have to store black pixels as well because of the xy coordinate system. I have tried writing to a binary file but the size of that file is greater than the jpeg file as the jpeg file is compressed. I am using c#.

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  • How can I determine the first visible tile in an isometric perspective?

    - by alekop
    I am trying to render the visible portion of a diamond-shaped isometric map. The "world" coordinate system is a 2D Cartesian system, with the coordinates increasing diagonally (in terms of the view coordinate system) along the axes. The "view" coordinates are simply mouse offsets relative to the upper left corner of the view. My rendering algorithm works by drawing diagonal spans, starting from the upper right corner of the view and moving diagonally to the right and down, advancing to the next row when it reaches the right view edge. When the rendering loop reaches the lower left corner, it stops. There are functions to convert a point from view coordinates to world coordinates and then to map coordinates. Everything works when rendering from tile 0,0, but as the view scrolls around the rendering needs to start from a different tile. I can't figure out how to determine which tile is closest to the upper right corner. At the moment I am simply converting the coordinates of the upper right corner to map coordinates. This works as long as the view origin (upper right corner) is inside the world, but when approaching the edges of the map the starting tile coordinate obviously become invalid. I guess this boils down to asking "how can I find the intersection between the world X axis and the view X axis?"

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  • C# slowdown while creating a bitmap - calculating distances from a large List of places for each pixel

    - by user576849
    I'm creating a graphic of the glow of lights above a geographic location based upon Walkers Law: Skyglow=0.01*Population*DistanceFromCenter^-2.5 I have a CSV file of places with 66,000 records using 5 fields (id,name,population,latitude,longitude), parsed on the FormLoad event and stored it in: List<string[]> placeDataList Then I set up nested loops to fill in a bitmap using SetPixel. For each pixel on the bitmap, which represents a coordinate on a map (latitude and longitude), the program loops through placeDataList – calculating the distance from that coordinate (pixel) to each place record. The distance (along with population) is used in a calculation to find how much cumulative sky glow is contributed to the coordinate from each place record. So, for every pixel, 66,000 distance calculations must be made. The problem is, this is predictably EXTREMELY slow – on the order of one line of pixels per 30 seconds or so on a 320 pixel wide image. This is unrelated to SetPixel, which I know is also slow, because the speed is similarly slow when adding the distance calculation results to an array. I don’t actually need to test all 66,000 records for every pixel, only the records within 150 miles (i.e. no skyglow is contributed to a coordinate from a small town 3000 miles away). But to find which records are within 150 miles of my coordinate I would still need to loop through all the records for each pixel. I can't use a smaller number of records because all 66,000 places contribute to skyglow for SOME coordinate in my map as it loops. This seems like a Catch-22, so I know there must be a better method out there. Like I mentioned, the slowdown is related to how many calculations I’m making per pixel, not anything to do with the bitmap. Any suggestions? private void fillPixels(int width) { Color pixelColor; int pixel_w = width; int pixel_h = (int)Math.Floor((width * 0.424088664)); Bitmap bmp = new Bitmap(pixel_w, pixel_h); for (int i = 0; i < pixel_h; i++) for (int j = 0; j < pixel_w; j++) { pixelColor = getPixelColor(i, j); bmp.SetPixel(j, i, pixelColor); } bmp.Save("Nightfall", System.Drawing.Imaging.ImageFormat.Jpeg); pictureBox1.Image = bmp; MessageBox.Show("Done"); } private Color getPixelColor(int height, int width) { int c; double glow,d,cityLat,cityLon,cityPop; double testLat, testLon; int size_h = (int)Math.Floor((size_w * 0.424088664)); ; testLat = (height * (24.443136 / size_h)) + 24.548874; testLon = (width * (57.636853 / size_w)) -124.640767; glow = 0; for (int i = 0; i < placeDataList.Count; i++) { cityPop=Convert.ToDouble(placeDataList[i][2]); cityLat=Convert.ToDouble(placeDataList[i][3]); cityLon=Convert.ToDouble(placeDataList[i][4]); d = distance(testLat, testLon, cityLat, cityLon,"M"); if(d<150) glow = glow+(0.01 * cityPop * Math.Pow(d, -2.5)); } if (glow >= 1) glow=1; c = (int)Math.Ceiling(glow * 255); return Color.FromArgb(c, c, c); }

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  • emo-framework in android move on collision of sprites with physics

    - by KaHeL
    I'm developing my first ever game for Android where I'm still learning about using of framework. To begin I made two sprites of ball where one ball is movable by dragging and another one is just standing on it's place on load. Now I've already added the collision listener for both sprites and as tested it's working properly. Now what I need to learn is on how can I add physics on both sprites where when they collide the standing sprite will move based on the physics and bounce around the screen. It would be best if you teach it to me step by step since I'm a little slow on this. Here's my nut so far: local stage = emo.Stage(); class Okay_1 { sprite = null; spriteok = null; dragStart = false; angle = 0; // Called when the stage is loaded function onLoad() { print("Level_1 is loaded!"); // Create new sprite and load 'f1.png' sprite = emo.Sprite("f1.png"); sprite.moveCenter(stage.getWindowWidth() * 0.5, stage.getWindowHeight() * 0.5); sprite.load(); spriteok = emo.Sprite("okay.png") spriteok.setWidth(100); spriteok.setHeight(100); spriteok.load(); // Check if the coordinate (X=100, Y=100) is inside the sprite if (spriteok.contains(100, 100)) { print("contains!"); } // Does the sprite collides with the other sprite? if (spriteok.collidesWith(sprite)) { print("collides!"); } } function onMotionEvent(ev) { if (ev.getAction() == MOTION_EVENT_ACTION_DOWN) { // Moves the sprite at the position of motion event angle = sprite.getAngle(); sprite.remove(); sprite = emo.Sprite("f2.png"); sprite.load(); sprite.rotate(angle); sprite.moveCenter(ev.getX(), ev.getY()); sprite.rotate(sprite.getAngle()+10); // Check if the coordinate (X=100, Y=100) is inside the sprite if (sprite.contains(sprite.getWidth(), sprite.getHeight())) { print("contains!"); } // Does the sprite collides with the other sprite? if (sprite.collidesWith(spriteok)) { print("collides!"); } dragStart = true; }else if (ev.getAction() == MOTION_EVENT_ACTION_MOVE) { if (dragStart) { // Moves the sprite at the position of motion event sprite.moveCenter(ev.getX(), ev.getY()); sprite.rotate(sprite.getAngle()+10); // Check if the coordinate (X=100, Y=100) is inside the sprite if (sprite.contains(sprite.getWidth(), sprite.getHeight())) { print("contains!"); } // Does the sprite collides with the other sprite? if (sprite.collidesWith(spriteok)) { print("collides!"); } } }else if (ev.getAction() == MOTION_EVENT_ACTION_UP || ev.getAction() == MOTION_EVENT_ACTION_CANCEL) { if (dragStart) { // change block color to red dragStart = false; angle = sprite.getAngle(); sprite.remove(); sprite = emo.Sprite("f1.png"); sprite.load(); sprite.moveCenter(ev.getX(), ev.getY()); sprite.rotate(angle); // Check if the coordinate (X=100, Y=100) is inside the sprite if (sprite.contains(sprite.getWidth(), sprite.getHeight())) { print("contains!"); } // Does the sprite collides with the other sprite? if (sprite.collidesWith(spriteok)) { print("collides!"); } } } } // Called when the stage is disposed function onDispose() { sprite.remove(); // Remove the sprite print("Level_1 is disposed!"); } } function emo::onLoad() { emo.Stage().load(Okay_1()); }

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  • How can I draw an arrow at the edge of the screen pointing to an object that is off screen?

    - by Adam Henderson
    I am wishing to do what is described in this topic: http://www.allegro.cc/forums/print-thread/283220 I have attempted a variety of the methods mentioned here. First I tried to use the method described by Carrus85: Just take the ratio of the two triangle hypontenuses (doesn't matter which triagle you use for the other, I suggest point 1 and point 2 as the distance you calculate). This will give you the aspect ratio percentage of the triangle in the corner from the larger triangle. Then you simply multiply deltax by that value to get the x-coordinate offset, and deltay by that value to get the y-coordinate offset. But I could not find a way to calculate how far the object is away from the edge of the screen. I then tried using ray casting (which I have never done before) suggested by 23yrold3yrold: Fire a ray from the center of the screen to the offscreen object. Calculate where on the rectangle the ray intersects. There's your coordinates. I first calculated the hypotenuse of the triangle formed by the difference in x and y positions of the two points. I used this to create a unit vector along that line. I looped through that vector until either the x coordinate or the y coordinate was off the screen. The two current x and y values then form the x and y of the arrow. Here is the code for my ray casting method (written in C++ and Allegro 5) void renderArrows(Object* i) { float x1 = i->getX() + (i->getWidth() / 2); float y1 = i->getY() + (i->getHeight() / 2); float x2 = screenCentreX; float y2 = ScreenCentreY; float dx = x2 - x1; float dy = y2 - y1; float hypotSquared = (dx * dx) + (dy * dy); float hypot = sqrt(hypotSquared); float unitX = dx / hypot; float unitY = dy / hypot; float rayX = x2 - view->getViewportX(); float rayY = y2 - view->getViewportY(); float arrowX = 0; float arrowY = 0; bool posFound = false; while(posFound == false) { rayX += unitX; rayY += unitY; if(rayX <= 0 || rayX >= screenWidth || rayY <= 0 || rayY >= screenHeight) { arrowX = rayX; arrowY = rayY; posFound = true; } } al_draw_bitmap(sprite, arrowX - spriteWidth, arrowY - spriteHeight, 0); } This was relatively successful. Arrows are displayed in the bottom right section of the screen when objects are located above and left of the screen as if the locations of the where the arrows are drawn have been rotated 180 degrees around the center of the screen. I assumed this was due to the fact that when I was calculating the hypotenuse of the triangle, it would always be positive regardless of whether or not the difference in x or difference in y is negative. Thinking about it, ray casting does not seem like a good way of solving the problem (due to the fact that it involves using sqrt() and a large for loop). Any help finding a suitable solution would be greatly appreciated, Thanks Adam

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  • my MKAnnotationVIew is not showing the title

    - by hydev
    Hi, I am new to iPhone programming and I can't understand why the MKAnnotationView is not showing the title's of my annotation's. Below is the code that is used to display it on the map. - (void)mapView:(MKMapView *)mv didAddAnnotationViews:(NSArray *)views { NSLog(@"Entered didAddAnnotationViews"); MKAnnotationView *annotationView = [views objectAtIndex:0]; id <MKAnnotation> mp = [annotationView annotation]; MKCoordinateRegion region = MKCoordinateRegionMakeWithDistance([mp coordinate], 250, 250); [mv setRegion:region animated:YES]; } Here is where I am defining my annotations: MapPoint *mp = [[MapPoint alloc] initWithCoordinate:[newLocation coordinate] title:[locationTitleField text]]; [mapView addAnnotation:mp]; [mp release]; mp is a class I have created to keep track of all the map points: #import "MapPoint.h" @implementation MapPoint @synthesize coordinate, title; - (id)initWithCoordinate:(CLLocationCoordinate2D)c title:(NSString *)t { [super init]; coordinate = c; [self setTitle:t]; return self; } - (void)dealloc { [title release]; [super dealloc]; } @end I am beginner so go easy, and all help greatly appreciated. Mike

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  • Calculating bounding grid coordinates to a user click on google maps/google earth

    - by user170304
    Hello, I have a requirement to calculate the centroid or geodesic midpoint of when a user clicks in between the lat/long grid crossing. The crossing forms a square in most parts of GE and sometimes elongated rectangles. This is due to the shape of the earth of course. I'm looking for a valid mathematical formula that would allow a user to click anywhere in between this grid and then an accurate function (in Javascript or server side code) that would take an assumed grid resolution (say 1km intervals for this discussion) and the input coordinates that should return a centroid coordinate within that graticule grid. To clarify please take a look at the attached image to my google group post: http://google-earth-api.googlegroups.com/web/Picture+5.png?gda=h5oFPz8AAAD315KpovipQeBwdfGpmW3ZhBc9PTADwYa-n193hZ6AItFmHuno63c7phcEXYVuRA6ccyFKn-rNKC-d1pM%5FIdV0&gsc=sz6bbAsAAABBKF7YXWYyc4GmXg-QruHj What I need to be able to do is if a user clicks anywhere in this grid square, I need to find the centroid or center point of that grid intersection/square or at least the bounding grid coordinates (that make the square). If we assume that the grid is UTM standard and has a max resolution of 1km (or make this a parameter), I need to detect the four other points nearby and then calculating the centroid is not as difficult. I welcome any feedback you all may have and appreciate it. I don't have a simple way of letting a user click anywhere on the grid and finding the grid bounding coordinates (making a square of 4 coordinates) or the centroid / midpoint of the graticule grid square necessary. One thought is to use assumptions as much as possible using a reference such as UTM coordinate reference. If I assume that the grid is X degrees wide, can we have a pure javascript function take any input coordinate and return for me the bounding graticule coordinates in Decimal Degrees? Another thought I had was to create the grid in a geo-spatial layer to take any input coordinate and return the nearest centroid of the graticule? Does this make sense? Thanks! Omar

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  • How to get the title and subtitle for a pin when we are implementing the MKAnnotation?

    - by wolverine
    I have implemented the MKAnnotation as below. I will put a lot of pins and the information for each of those pins are stored in an array. Each member of this array is an object whose properties will give the values for the title and subtitle of the pin. Each object corresponds to a pin. But how can I display these values for the pin when I click a pin?? @interface UserAnnotation : NSObject <MKAnnotation> { CLLocationCoordinate2D coordinate; NSString *title; NSString *subtitle; NSString *city; NSString *province; } @property (nonatomic, assign) CLLocationCoordinate2D coordinate; @property (nonatomic, retain) NSString *title; @property (nonatomic, retain) NSString *subtitle; @property (nonatomic, retain) NSString *city; @property (nonatomic, retain) NSString *province; -(id)initWithCoordinate:(CLLocationCoordinate2D)c; And .m is @implementation UserAnnotation @synthesize coordinate, title, subtitle, city, province; - (NSString *)title { return title; } - (NSString *)subtitle { return subtitle; } - (NSString *)city { return city; } - (NSString *)province { return province; } -(id)initWithCoordinate:(CLLocationCoordinate2D)c { coordinate=c; NSLog(@"%f,%f",c.latitude,c.longitude); return self; } @end

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  • CLLocationManagerDelegate method not calling in iPodTouch

    - by Siddharth
    HI all, I was using a sample code which uses CLLocationManager class to determine the current location of user. when i run this app on iPad i am getting the correct location but when i run the same app on iPod Touch i am getting a blank label i.e nothing is displayed on the label .although wi-fi signal strength is good in both iPod and iPad.The code looks like... - (void)locationManager:(CLLocationManager *)manager didUpdateToLocation:(CLLocation *)newLocation fromLocation:(CLLocation *)oldLocation{ int degrees = newLocation.coordinate.latitude; double decimal = fabs(newLocation.coordinate.latitude - degrees); int minutes = decimal * 60; double seconds = decimal * 3600 - minutes * 60; NSString *lat = [NSString stringWithFormat:@"%d° %d' %1.4f\"", degrees, minutes, seconds]; latLabel.text = lat; [latLocationArray addObject:lat]; degrees = newLocation.coordinate.longitude; decimal = fabs(newLocation.coordinate.longitude - degrees); minutes = decimal * 60; seconds = decimal * 3600 - minutes * 60; NSString *longt = [NSString stringWithFormat:@"%d° %d' %1.4f\"", degrees, minutes, seconds]; longLabel.text = longt; [longLocationArray addObject:longt]; }

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  • How do you pass a BitmapImage from a background thread to the UI thread in WPF?

    - by DanM
    I have a background thread that generates a series of BitmapImage objects. Each time the background thread finishes generating a bitmap, I would like to show this bitmap to the user. The problem is figuring out how to pass the BitmapImage from the background thread to the UI thread. This is an MVVM project, so my view has an Image element: <Image Source="{Binding GeneratedImage}" /> My view-model has a property GeneratedImage: private BitmapImage _generatedImage; public BitmapImage GeneratedImage { get { return _generatedImage; } set { if (value == _generatedImage) return; _generatedImage= value; RaisePropertyChanged("GeneratedImage"); } } My view-model also has the code that creates the background thread: public void InitiateGenerateImages(List<Coordinate> coordinates) { ThreadStart generatorThreadStarter = delegate { GenerateImages(coordinates); }; var generatorThread = new Thread(generatorThreadStarter); generatorThread.ApartmentState = ApartmentState.STA; generatorThread.IsBackground = true; generatorThread.Start(); } private void GenerateImages(List<Coordinate> coordinates) { foreach (var coordinate in coordinates) { var backgroundThreadImage = GenerateImage(coordinate); // I'm stuck here...how do I pass this to the UI thread? } } I'd like to somehow pass backgroundThreadImage to the UI thread, where it will become uiThreadImage, then set GeneratedImage = uiThreadImage so the view can update. I've looked at some examples dealing with the WPF Dispatcher, but I can't seem to come up with an example that addresses this issue. Please advise.

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  • CLLocationManager class method not calling in iPodTouch

    - by Siddharth
    HI all, I was using a sample code which uses CLLocationManager class to determine the current location of user. when i run this app on iPad i am getting the correct location but when i run the same app on iPod Touch i am getting a blank label i.e nothing is displayed on the label .although wi-fi signal strength is good in both iPod and iPad.The code looks like... - (void)locationManager:(CLLocationManager *)manager didUpdateToLocation:(CLLocation *)newLocation fromLocation:(CLLocation *)oldLocation{ int degrees = newLocation.coordinate.latitude; double decimal = fabs(newLocation.coordinate.latitude - degrees); int minutes = decimal * 60; double seconds = decimal * 3600 - minutes * 60; NSString *lat = [NSString stringWithFormat:@"%d° %d' %1.4f\"", degrees, minutes, seconds]; latLabel.text = lat; [latLocationArray addObject:lat]; degrees = newLocation.coordinate.longitude; decimal = fabs(newLocation.coordinate.longitude - degrees); minutes = decimal * 60; seconds = decimal * 3600 - minutes * 60; NSString *longt = [NSString stringWithFormat:@"%d° %d' %1.4f\"", degrees, minutes, seconds]; longLabel.text = longt; [longLocationArray addObject:longt]; }

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  • In Powerpoint 2007, how can I position a Callout's Tail programatically?

    - by Rorschach
    I'm looking at the XML and this is what it has for the Callout object's coordinates and geometry: <p:spPr> <a:xfrm> <a:off x="2819400" y="5181600"/> // X,Y Position of Callout Box <a:ext cx="609600" cy="457200"/> // Width,Height of Callout Box </a:xfrm> <a:prstGeom prst="wedgeRectCallout"> <a:avLst> <a:gd name="adj1" fmla="val 257853"/> // X Position Of Tail <a:gd name="adj2" fmla="val -532360"/> // Y Position of Tail </a:avLst> </a:prstGeom> <a:solidFill> <a:schemeClr val="accent1"> <a:alpha val="50000"/> </a:schemeClr> </a:solidFill> </p:spPr> What I'm having trouble with is the formula for telling it to place the tail at a particular coordinate on the slide. I've tried this to calculate it, but it does not work correctly. //This gives me the distance between the Coordinate and the Center of the Callout. DistanceX = Coordinate.X - (Callout.X + Callout.X_Ext)/2 DistanceY = Coordinate.Y - (Callout.Y + Callout.Y_Ext)/2 But, the geometric value is not the distance between the two points. Anybody know what the formula is for calculating this?

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  • Refreshing a MKMapView when the user location is updated or using default values

    - by koichirose
    I'm trying to refresh my map view and load new data from the server when the device acquires the user location. Here's what I'm doing: - (void)viewDidLoad { CGRect bounds = self.view.bounds; mapView = [[MKMapView alloc] initWithFrame:bounds]; mapView.showsUserLocation=YES; mapView.delegate=self; [self.view insertSubview:mapView atIndex:0]; [self refreshMap]; } - (void)mapView:(MKMapView *)theMapView didUpdateUserLocation:(MKUserLocation *)userLocation { //this is to avoid frequent updates, I just need one position and don't need to continuously track the user's location if (userLocation.location.horizontalAccuracy > self.myUserLocation.location.horizontalAccuracy) { self.myUserLocation = userLocation; CLLocationCoordinate2D centerCoord = { userLocation.location.coordinate.latitude, userLocation.location.coordinate.longitude }; [theMapView setCenterCoordinate:centerCoord zoomLevel:10 animated:YES]; [self refreshMap]; } } - (void)refreshMap { [[UIApplication sharedApplication] setNetworkActivityIndicatorVisible:YES]; [self.mapView removeAnnotations:self.mapView.annotations]; //default position NSString *lat = @"45.464161"; NSString *lon = @"9.190336"; if (self.myUserLocation != nil) { lat = [[NSNumber numberWithDouble:myUserLocation.coordinate.latitude] stringValue]; lon = [[NSNumber numberWithDouble:myUserLocation.coordinate.longitude] stringValue]; } NSString *url = [[NSString alloc] initWithFormat:@"http://myserver/geo_search.json?lat=%@&lon=%@", lat, lon]; NSURLRequest *theRequest=[NSURLRequest requestWithURL:[NSURL URLWithString:url] cachePolicy:NSURLRequestUseProtocolCachePolicy timeoutInterval:60.0]; [[NSURLConnection alloc] initWithRequest:theRequest delegate:self]; [url release]; [[UIApplication sharedApplication] setNetworkActivityIndicatorVisible:NO]; } I also have a - (void)connection:(NSURLConnection *)connection didReceiveData:(NSData *)data, to create and add the annotations. Here's what happens: sometimes I get the location after a while, so I already loaded data close to the default location. Then I get the location and it should remove the old annotations and add the new ones, instead I keep seeing the old annotations and the new ones are added anyway (let's say I receive 10 annotations each time, so it means that I have 20 on my map when I should have 10). What am I doing wrong?

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  • Capture screen with fixed region

    - by user62046
    I would like to know if there is a systematical way (software) to capture a fixed region on the screen, under Windows 7 or OS X. It must be accurate about the region. I always want to capture the region with left-top coordinate (300, 300) and right-bottome coordinate (800, 800). So I can't not select the region by mouse myself. A software to do this capture should let me to input the 2 coordinates.

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  • Howto serialize a List<T> in Silverlight?

    - by Jurgen
    I have a struct called coordinate which is contained in a list in another class called segment. public struct Coordinate { public double Latitude { get; set; } public double Longtitude { get; set; } public double Altitude { get; set; } public DateTime Time { get; set; } } public class Segment { private List<Coordinate> coordinates; ... } I'd like to serialize the Segment class using the XmlSerializer using Silverlight (on Windows Phone 7). I understand from link text that XmlSerializer doesn't support List<T>. What is the advised way of serializing a resizable array coordinates? Thanks, Jurgen

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  • Outputing struct to NSLog for debugging?

    - by fuzzygoat
    I am just curious, is there a way to print via NSLog the contents of a struct? id <MKAnnotation> mp = [annotationView annotation]; MKCoordinateRegion region = MKCoordinateRegionMakeWithDistance([mp coordinate], 350, 350); I am trying to output whats in [mp coordinate] for debugging. . EDIT_001: I cracked it, well unless there is another way. id <MKAnnotation> mp = [annotationView annotation]; CLLocationCoordinate2D location = [mp coordinate]; NSLog(@"LAT: %f LON: %f", location.latitude, location.longitude); many thanks gary

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  • MKReverseGeocoder delegate location?

    - by fuzzygoat
    I have a quick question regarding memory management that I am not quite sure about. I currently have a locationManager delegate that calls locationManager:didUpdateToLocation:fromLocation when it resolves the device location. My question is I am looking at adding ReverseGeoCoding after I have obtained the [newLocation coordinate] but am unsure about doing the alloc here, as each time locationManager:didUpdateToLocation:fromLocation gets called I will be alloc-ing a new MKReverseGeoCoder? // LOCATION -(void)locationManager:(CLLocationManager *)manager didUpdateToLocation:(CLLocation *)newLocation fromLocation:(CLLocation *)oldLocation { // GeoCoding: MKReverseGeocoder *geoCoder = [[MKReverseGeocoder alloc] initWithCoordinate:[newLocation coordinate]]; [geoCoder setDelegate:self]; [geoCoder start]; [self foundLocation]; } Can anyone point me in the right direction with regards to this? I did try doing the alloc in application:didFinishLaunchingWithOptions: but then realised I did not have access to [newLocation coordinate]. many thanks gary

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  • SVG - From Window coordinates to ViewBox coordinates

    - by user353072
    Hi, Basically I have an svg "SecondSVG" into an svg "FirstSVG" into an svg "MainSVG".Every svg has its own ViewBox. This page can be loaded anywhere on the screen by another page. So basically how can i find the screen x for viewBox for"SecondSVG" knowing that this svg can be loaded basically anywhere based on the calling page? event.clientX gives myself the x coordinate for the screen. If I don't know the coordinate for ViewBox of "SecondSVG" then how can I find out the x coordinate inside the ViewBox of "SecondSVG"? I am using Firefox 3.6.3 and I do have an event object from which I can extract clientX, clientY and other coordinates that are relative to the screen. However what I need are the coordinates inside the ViewBox.

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  • How i access the array of CGPoints to draw the graph?

    - by Rajendra Bhole
    Hi, I have the code in which i want to develop the graph.The code is, NSArray *coordinate = [[NSArray alloc] initWithObjects: @"42,213", @"75,173", @"108,153", @"141,133", @"174,113", @"207,73", @"240,33", nil]; CGContextSetRGBFillColor(ctx, 255, 0, 0, 1.0); CGContextSetLineWidth(ctx, 8.0); for(int intIndex = 0; intIndex < [coordinate count]; fltX1+=33, intIndex++) { CGContextMoveToPoint(ctx, fltX1+37, fltY2+18); CGPoint point = [[coordinate objectAtIndex:intIndex] CGPointValue]; CGContextAddLineToPoint(ctx, point); CGContextStrokePath(ctx); } The problem is that the function of CGContextAddLineToPoint(ctx, point); not working properly. How i drawing the line in the graph using above code????????

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  • NSArray vs. SQLite for Complex Queries on iPhone

    - by GingerBreadMane
    Developing for iPhone, I have a collection of points that I need to make complex queries on. For example: "How many points have a y-coordinate of 10" and "Return all points with an X-coordinate between 3 and 5 and a y-coordinate of 7". Currently, I am just cycling through each element of an NSArray and checking to see if each element matches my query. It's a pain to write the queries though. SQLite would be much nicer. I'm not sure which would be more efficient though since a SQLite database resides on disk and not in memory (to my understanding). Would SQLite be as efficient or more efficient here? Or is there a better way to do it other than these methods that I haven't thought of? I would need to perform the multiple queries with multiple sets of points thousands of times, so the best performance is important.

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  • Is there a transformation matrix that can scale the x and/or y axis logarithmically?

    - by Dave M
    I'm using .net WPF geometry classes to graph waveforms. I've been using the matrix transformations to convert from the screen coordinate space to my coordinate space for the waveform. Everything works great and it's really simple to keep track of my window and scaling, etc. I can even use the inverse transform to calculate the mouse position in terms of the coordinate space. I use the built in Scaling and Translation classes and then a custom matrix to do the y-axis flipping (there's not a prefab matrix for flipping). I want to be able to graph these waveforms on a log scale as well (either x axis or y axis or both), but I'm not sure if this is even possible to do with a matrix transformation. Does anyone know if this is possible, and if it is, what is the matrix?

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  • Sampler referencing in HLSL - Sampler parameter must come from a literal expression

    - by user1423893
    The following method works fine when referencing a sampler in HLSL float3 P = lightScreenPos; sampler ShadowSampler = DPFrontShadowSampler; float depth; if (alpha >= 0.5f) { // Reference the correct sampler ShadowSampler = DPFrontShadowSampler; // Front hemisphere 'P0' P.z = P.z + 1.0; P.x = P.x / P.z; P.y = P.y / P.z; P.z = lightLength / LightAttenuation.z; // Rescale viewport to be [0, 1] (texture coordinate space) P.x = 0.5f * P.x + 0.5f; P.y = -0.5f * P.y + 0.5f; depth = tex2D(ShadowSampler, P.xy).x; depth = 1.0 - depth; } else { // Reference the correct sampler ShadowSampler = DPBackShadowSampler; // Back hemisphere 'P1' P.z = 1.0 - P.z; P.x = P.x / P.z; P.y = P.y / P.z; P.z = lightLength / LightAttenuation.z; // Rescale viewport to be [0, 1] (texture coordinate space) P.x = 0.5f * P.x + 0.5f; P.y = -0.5f * P.y + 0.5f; depth = tex2D(ShadowSampler, P.xy).x; depth = 1.0 - depth; } // [Standard Depth Calculation] float mydepth = P.z; shadow = depth + Bias.x < mydepth ? 0.0f : 1.0f; If I try and do anything with the sampler reference outside the if statement then I get the following error: Sampler parameter must come from a literal expression This code demonstrates that float3 P = lightScreenPos; sampler ShadowSampler = DPFrontShadowSampler; if (alpha >= 0.5f) { // Reference the correct sampler ShadowSampler = DPFrontShadowSampler; // Front hemisphere 'P0' P.z = P.z + 1.0; P.x = P.x / P.z; P.y = P.y / P.z; P.z = lightLength / LightAttenuation.z; } else { // Reference the correct sampler ShadowSampler = DPBackShadowSampler; // Back hemisphere 'P1' P.z = 1.0 - P.z; P.x = P.x / P.z; P.y = P.y / P.z; P.z = lightLength / LightAttenuation.z; } // Rescale viewport to be [0, 1] (texture coordinate space) P.x = 0.5f * P.x + 0.5f; P.y = -0.5f * P.y + 0.5f; // [Standard Depth Calculation] float depth = tex2D(ShadowSampler, P.xy).x; depth = 1.0 - depth; float mydepth = P.z; shadow = depth + Bias.x < mydepth ? 0.0f : 1.0f; How can I reference the sampler in this manner without triggering the error?

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  • OpenGL 2D Depth Perception

    - by Stephen James
    This is the first time i have ever commented on a forum about programming, so sorry if I'm not specific enough. Here's my problem: I have a 2D RPG game written in Java using LWJGL. All works fine, but at the moment I'm having trouble deciding what the best way to do depth perception is. So , for example, if the player goes in front of the tree/enemy (lower than the objects y-coordinate) then show the player in front), if the player goes behind the tree/enemy (higher than the objects specific y-coordinate), then show the player behind the object. I have tried writing a block of code to deal with this, and it works quite well for the trees, but not for the enemies yet. Is there a simpler way of doing this in LWJGL that I'm missing? Thanks :)

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