Search Results

Search found 1525 results on 61 pages for 'pair'.

Page 6/61 | < Previous Page | 2 3 4 5 6 7 8 9 10 11 12 13  | Next Page >

  • What's the best way of using a pair (triple, etc) of values as one value in C#?

    - by Yacoder
    That is, I'd like to have a tuple of values. The use case on my mind: Dictionary<Pair<string, int>, object> or Dictionary<Triple<string, int, int>, object> Are there built-in types like Pair or Triple? Or what's the best way of implementing it? Update There are some general-purpose tuples implementations described in the answers, but for tuples used as keys in dictionaries you should additionaly verify correct calculation of the hash code. Some more info on that in another question. Update 2 I guess it is also worth reminding, that when you use some value as a key in dictionary, it should be immutable.

    Read the article

  • How to insert an item into a key/value pair object?

    - by Clay
    Ok...here's a softball question... I just need to be able to insert a key/value pair into an object at a specific position. I'm currently working with a Hashtable which, of course, doesn't allow for this functionality. What would be the best approach? UPDATE: Also, I do need the ability to lookup by the key. For example...oversimplified and pseudocoded but should convey the point // existing Hashtable myHashtable.Add("somekey1", "somevalue1"); myHashtable.Add("somekey2", "somevalue2"); myHashtable.Add("somekey3", "somevalue3"); // Some other object that will allow me to insert a new key/value pair. // Assume that this object has been populated with the above key/value pairs. oSomeObject.Insert("newfirstkey","newfirstvalue"); Thanks in advance.

    Read the article

  • Understanding Security Certificates (and thier pricing)

    - by John Robertson
    I work at a very small company so certificate costs need to be absolutely minimal. However for some applications we do Need to have our customers get that warm fuzzy not-using-a-self-signed certificate feeling. Since creating a "certificate authority" with makecert really just means creating a public/private key pair, it seems pretty clear that creating a public/private key pair FROM such a "certificate authority" really just means generating a second public/private key pair and signing both with the private key that belongs to the "certificate authority". Since the keys are signed anyone can verify they came from the certificate authority I created, or if verisign gave me the pair they sign it with one of their own private keys, and anyone can use verisigns corresponding public key to confirm verisign as the source of the keys. Given this I don't understand when I go to verisign or godaddy why they have rates only for yearly plans, when all I really want from them is a single public/private key pair signed with one of their private keys (so that anyone else can use their public keys to confirm that, yes, they gave me that public/private key pair and they confirmed I was who I said I was so you can trust my public/private key pair as belonging to a legitimate third party). Clearly I am misunderstanding something, what is it? Does verisign retire their public/private key pairs periodically so that my verisign signed key pair "expires" and I need new ones? Edit: I learned that the certificate has an internal expiration date and it also maintains an internal value stating whether it can be used to sign other certificates (i.e. sign other private/public key pairs stored as certificates). Can't I get a few (even one) non-signing certificate signed by someone like verisign that I can use for authentication/encryption without a yearly subscription?

    Read the article

  • What happens to my PriorityQueue if my Comparator throws an exception while it's busy bubbling up or

    - by nieldw
    Hi, I'm trying order pairs of integers ascendantly where a pair is considered less than another pair if both its entries are strictly less than those of the other pair, and larger than the other pair if both its entries are strictly larger than those of the other pair. All other cases are considered incomparable. They way I want to solve this is by defining a Comparator that implements the above, but will throw an exception for incomparable cases, and provide that to a PriorityQueue. Of course, while inserting a pair the priority queue does several comparisons while bubbling the new entry up to its correct position in the heap, and many of these will be comparable. But it may happen during the bubbling process that a pair is encountered with which this new pair is incomparable, and an exception will be thrown. If this happens, what will be the state of the PriorityQueue? Will the pair I was trying to insert sit in the heap at the last position it was in before the exception was thrown? If I use the PriorityQueue's remove(Object o) method, will the PriorityQueue be restored to a consistent state? Thanks

    Read the article

  • Problem with multidimensional arrays in ruby.

    - by antiarchitect
    From script/console: >> pairs = Array.new(2).map!{Array.new(2).map!{Array.new(2, Array.new)}} => [[[[], []], [[], []]], [[[], []], [[], []]]] >> pair = Pair.first => #<Pair id: 39, charge_card_id: 1, classroom_id: 1, timeslot_id: 1, created_at: "2010-04-01 00:45:37", updated_at: "2010-04-01 00:45:47"> >> pairs[0][0][0] << pair => [#<Pair id: 39, charge_card_id: 1, classroom_id: 1, timeslot_id: 1, created_at: "2010-04-01 00:45:37", updated_at: "2010-04-01 00:45:47">] >> pairs[0][0] => [[#<Pair id: 39, charge_card_id: 1, classroom_id: 1, timeslot_id: 1, created_at: "2010-04-01 00:45:37", updated_at: "2010-04-01 00:45:47">], [#<Pair id: 39, charge_card_id: 1, classroom_id: 1, timeslot_id: 1, created_at: "2010-04-01 00:45:37", updated_at: "2010-04-01 00:45:47">]] >> So the question is why the pair object appears in pairs[0][0][0] AND in pairs[0][0][1] inspite of I did'n ask it to appear there. Notice I don't nedd to pairs[0][0][0] = pair - I want it as a first array member, so I need to use << or .push.

    Read the article

  • Another developer revoked and re-created my client's iOS Distribution Certificate - does this mean I can never update my client's existing app?

    - by Schnapple
    Here is the story so far: A client hired us to do an iPhone app for them. This client had never done an iPhone app before and as part of the arrangement we handled all aspects for them, including app store submission, and we handle some level of future development (new features, bug/security fixes, etc.) We created a Distribution certificate and key pair on the client's behalf We developed the app, published it to the App Store without incident Some time later the client hired a second developer to do a different app for them This second developer, it appears, has revoked the existing Distribution certificate and created a new one with a new key pair on their system This second developer shared the new Distribution certificate and key pair with us for future reference. Due to user error, this new certificate and key pair has now been imported onto the Macintosh where the original certificate and key pair for the original app we developed were created and the originals were not backed up. So we have App #1 on the App Store with Distribution certificate/key pair #1 App #2 either on the App Store or soon to be using Distribution certificate/key pair #2 Distribution certificate/key pair #1 appears to be lost now So my question is: if we ever need to update App #1, will we be able to, using Distribution certificate/key pair #2? Or will we have to upload it as a new app?

    Read the article

  • C++ 'using': Should I use it or should I avoid it?

    - by Mehrdad
    I realize there are subtly different semantics for some of these, because of ADL. In general, though: Which one should I prefer (if any), and why? (Or does it depend on the situation (e.g. inline header vs. implementation?) Also: should I prefer ::std:: over std::? using namespace std; pair<string::const_iterator, string::const_iterator> f(const string &s) { return make_pair(s.begin(), s.end()); } or std::pair<std::string::const_iterator, std::string::const_iterator> f(const std::string &s) { return std::make_pair(s.begin(), s.end()); } or using std::pair; using std::string; pair<string::const_iterator, string::const_iterator> f(const string &s) { return make_pair(s.begin(), s.end()); } or std::pair<std::string::const_iterator, std::string::const_iterator> f(const std::string &s) { using std::make_pair; return make_pair(s.begin(), s.end()); } or std::pair<std::string::const_iterator, std::string::const_iterator> f(const std::string &s) { using namespace std; return make_pair(s.begin(), s.end()); } or something else? (This is assuming I don't have C++11 and auto.)

    Read the article

  • Is there a Pair-Wise PostHoc Comparisons for the Chi-Square Test in R?

    - by Tal Galili
    Hi all, I am wondering if there exists in R a package/function to perform the: "Post Hoc Pair-Wise Comparisons for the Chi-Square Test of Homogeneity of Proportions" (or an equivalent of it) Which is described here: http://epm.sagepub.com/cgi/content/abstract/53/4/951 My situation is of just making a chi test, on a 2 by X matrix. I found a difference, but I want to know which of the columns is "responsible" for the difference. Thanks, Tal

    Read the article

  • Easiest way to get Enum in to Key Value pair.

    - by vijay.shad
    Hi, I have defined my Enums like this. public enum UserType { RESELLER("Reseller"), SERVICE_MANAGER("Manager"), HOST("Host"); private String name; private UserType(String name) { this.name = name; } public String getName() { return name; } } What should be the easiest way to get a key-value pair form the enum values?

    Read the article

  • check if a tree is a binary search tree

    - by TimeToCodeTheRoad
    I have written the following code to check if a tree is a Binary search tree. Please help me check the code: Pair p{ boolean isTrue; int min; int max; } public boo lean isBst(BNode v){ return isBST1(v).isTrue; } public Pair isBST1(BNode v){ if(v==null) return new Pair(true, INTEGER.MIN,INTEGER.MAX); if(v.left==null && v.right==null) return new Pair(true, v.data, v.data); Pair pLeft=isBST1(v.left); Pair pRight=isBST1(v.right); boolean check=pLeft.max<v.data && v.data<= pRight.min; Pair p=new Pair(); p.isTrue=check&&pLeft.isTrue&&pRight.isTrue; p.min=pLeft.min; p.max=pRight.max; return p; } Note: This function checks if a tree is a binary search tree

    Read the article

  • Understanding Security Certificates (and thier pricing)

    - by John Robertson
    I work at a very small company so certificate costs need to be absolutely minimal. However for some applications we do Need to have our customers get that warm fuzzy not-using-a-self-signed certificate feeling. Since creating a "certificate authority" with makecert really just means creating a public/private key pair, it seems pretty clear that creating a public/private key pair FROM such a "certificate authority" really just means generating a second public/private key pair and signing both with the private key that belongs to the "certificate authority". Since the keys are signed anyone can verify they came from the certificate authority I created, or if verisign gave me the pair they sign it with one of their own private keys, and anyone can use verisigns corresponding public key to confirm verisign as the source of the keys. Given this I don't understand when I go to verisign or godaddy why they have rates only for yearly plans, when all I really want from them is a single public/private key pair signed with one of their private keys (so that anyone else can use their public keys to confirm that, yes, they gave me that public/private key pair and they confirmed I was who I said I was so you can trust my public/private key pair as belonging to a legitimate third party). Clearly I am misunderstanding something, what is it? Does verisign retire their public/private key pairs periodically so that my verisign signed key pair "expires" and I need new ones?

    Read the article

  • In SICP exercise 2.26 using DrScheme, why does cons return a list, instead of a pair of lists?

    - by limist
    In SICP exercise 2.26, this Scheme code is given: (define x (list 1 2 3)) (define y (list 4 5 6)) Then this cons call is given: (cons x y) I expected a pair of lists would result, ((1 2 3) (4 5 6)) but the interpreter gives, ((1 2 3) 4 5 6) ...a list with 4 elements, the first being a list. Why is y treated differently? I've tried looking up other SICP answers for an explanation, but couldn't find something satisfactory. So could any Scheme/Lisp experts please shed some light on this aspect of cons? Thanks in advance for any insight.

    Read the article

  • How do I prevent a pair of XMLEvent[Reader|Writer] from splitting empty tags into start+end tags?

    - by java.is.for.desktop
    Hello, everyone! I have an understanding problem of how the following code works: XMLInputFactory xif = XMLInputFactory.newFactory(); XMLOutputFactory xof = XMLOutputFactory.newFactory(); XMLEventReader reader = xif.createXMLEventReader(/* ... */); XMLEventWriter writer = xof.createXMLEventWriter(/* ... */); writer.add(reader); The method writer.add([some reader]) reads all events from reader and writes them consequently. Sadly, following happens: The input <root><c/></root> gets transformed to <root><c><c/></root> I know, from XML point of view, these are equal trees, but not for a human ;) What can I do to get the same output? FYI: I need a XMLEvent[Reader|Writer] pair later to filter "XML events".

    Read the article

  • How to test if an array contains a pair of numbers whose product is odd?

    - by John
    How can I write a function that takes an array of integers and returns true if their exists a pair of numbers whose product is odd? What are the properties of odd integers? And of course, how do you write this function in Java? Also, maybe a short explanation of how you went about formulating an algorithm for the actual implementation. Yes, this is a function out of a textbook. No, this is not homework—I'm just trying to learn, so please no "do your own homework comments."

    Read the article

  • Which function pair in QString to use for converting to/from std::string?

    - by Noah Roberts
    I'm working on a project that we want to use Unicode and could end up in countries like Japan, etc... We want to use std::string for the underlying type that holds string data in the data layer (see Qt, MSVC, and /Zc:wchar_t- == I want to blow up the world as to why). The problem is that I'm not completely sure which function pair (to/from) to use for this and be sure we're 100% compatible with anything the user might enter in the Qt layer. A look at to/fromStdString indicates that I'd have to use setCodecForCStrings. The documentation for that function though indicates that I wouldn't want to do this for things like Japanese. This is the set that I'd LIKE to use though. Does someone know enough to explain how I'd set this up if it's possible? The other option that looks like I could be pretty sure of it working is the to/fromUTF8 functions. Those would require a two step approach though so I'd prefer the other if possible. Is there anything I've missed?

    Read the article

  • If Key Value pair exists in multidimensional array.. How to?

    - by Daniel White
    I have a codeigniter shopping cart going and its "cart" array is the following: Array ( [a87ff679a2f3e71d9181a67b7542122c] => Array ( [rowid] => a87ff679a2f3e71d9181a67b7542122c [id] => 4 [qty] => 1 [price] => 12.95 [name] => Maroon Choir Stole [image] => 2353463627maroon_3.jpg [custprod] => 0 [subtotal] => 12.95 ) [8f14e45fceea167a5a36dedd4bea2543] => Array ( [rowid] => 8f14e45fceea167a5a36dedd4bea2543 [id] => 7 [qty] => 1 [price] => 12.95 [name] => Shiny Red Choir Stole [image] => 2899638984red_vstole_1.jpg [custprod] => 0 [subtotal] => 12.95 ) [eccbc87e4b5ce2fe28308fd9f2a7baf3] => Array ( [rowid] => eccbc87e4b5ce2fe28308fd9f2a7baf3 [id] => 3 [qty] => 1 [price] => 14.95 [name] => Royal Blue Choir Stole [image] => 1270984005royal_vstole.jpg [custprod] => 1 [subtotal] => 14.95 ) ) My goal is to loop through this multidimensional array some how and if ANY product with the key value pair "custprod == 1" exists, then my checkout page will display one thing, and if no custom products are in the cart it displays another thing. Any help is appreciated. Thanks.

    Read the article

  • Most efficient algorithm for merging sorted IEnumerable<T>

    - by franck
    Hello, I have several huge sorted enumerable sequences that I want to merge. Theses lists are manipulated as IEnumerable but are already sorted. Since input lists are sorted, it should be possible to merge them in one trip, without re-sorting anything. I would like to keep the defered execution behavior. I tried to write a naive algorithm which do that (see below). However, it looks pretty ugly and I'm sure it can be optimized. It may exist a more academical algorithm... IEnumerable<T> MergeOrderedLists<T, TOrder>(IEnumerable<IEnumerable<T>> orderedlists, Func<T, TOrder> orderBy) { var enumerators = orderedlists.ToDictionary(l => l.GetEnumerator(), l => default(T)); IEnumerator<T> tag = null; var firstRun = true; while (true) { var toRemove = new List<IEnumerator<T>>(); var toAdd = new List<KeyValuePair<IEnumerator<T>, T>>(); foreach (var pair in enumerators.Where(pair => firstRun || tag == pair.Key)) { if (pair.Key.MoveNext()) toAdd.Add(pair); else toRemove.Add(pair.Key); } foreach (var enumerator in toRemove) enumerators.Remove(enumerator); foreach (var pair in toAdd) enumerators[pair.Key] = pair.Key.Current; if (enumerators.Count == 0) yield break; var min = enumerators.OrderBy(t => orderBy(t.Value)).FirstOrDefault(); tag = min.Key; yield return min.Value; firstRun = false; } } The method can be used like that: // Person lists are already sorted by age MergeOrderedLists(orderedList, p => p.Age); assuming the following Person class exists somewhere: public class Person { public int Age { get; set; } } Duplicates should be conserved, we don't care about their order in the new sequence. Do you see any obvious optimization I could use?

    Read the article

  • Using array as map value: Cant see the error

    - by Tom
    Hi all, Im trying to create a map, where the key is an int, and the value is an array int red[3] = {1,0,0}; int green[3] = {0,1,0}; int blue[3] = {0,0,1}; std::map<int, int[3]> colours; colours.insert(std::pair<int,int[3]>(GLUT_LEFT_BUTTON,red)); //THIS IS LINE 24 ! colours.insert(std::pair<int,int[3]>(GLUT_MIDDLE_BUTTON,blue)); colours.insert(std::pair<int,int[3]>(GLUT_RIGHT_BUTTON,green)); However, when I try to compile this code, I get the following error. g++ (Ubuntu 4.4.1-4ubuntu8) 4.4.1 In file included from /usr/include/c++/4.4/bits/stl_algobase.h:66, from /usr/include/c++/4.4/bits/stl_tree.h:62, from /usr/include/c++/4.4/map:60, from ../src/utils.cpp:9: /usr/include/c++/4.4/bits/stl_pair.h: In constructor ‘std::pair<_T1, _T2>::pair(const _T1&, const _T2&) [with _T1 = int, _T2 = int [3]]’: ../src/utils.cpp:24: instantiated from here /usr/include/c++/4.4/bits/stl_pair.h:84: error: array used as initializer /usr/include/c++/4.4/bits/stl_pair.h: In constructor ‘std::pair<_T1, _T2>::pair(const std::pair<_U1, _U2>&) [with _U1 = int, _U2 = int [3], _T1 = const int, _T2 = int [3]]’: ../src/utils.cpp:24: instantiated from here /usr/include/c++/4.4/bits/stl_pair.h:101: error: array used as initializer In file included from /usr/include/c++/4.4/map:61, from ../src/utils.cpp:9: /usr/include/c++/4.4/bits/stl_map.h: In member function ‘_Tp& std::map<_Key, _Tp, _Compare, _Alloc>::operator[](const _Key&) [with _Key = int, _Tp = int [3], _Compare = std::less<int>, _Alloc = std::allocator<std::pair<const int, int [3]> >]’: ../src/utils.cpp:30: instantiated from here /usr/include/c++/4.4/bits/stl_map.h:450: error: conversion from ‘int’ to non-scalar type ‘int [3]’ requested make: *** [src/utils.o] Error 1 I really cant see where the error is. Or even if there's an error. Any help (please include an explanation to help me avoid this mistake) will be appreciated. Thanks in advance.

    Read the article

  • Conditionals in Antlr String Templates

    - by Pat Long - Munkii Yebee
    We are using Antlr StringTemplates to give control over how a Entity's Name is output. The basic Stringtemplate is $FirstName$ $Initial$ $LastName$, $Suffix$, $Degree$ I want to add some smarts to that template so that the commas are only output when necessary i.e. The first comma is only output when there is a Suffix or Degree and the second commas is only output if there is a suffix. I tried the following template string bit it does not work. I guess I have misunderstood $FirstName$ $Initial$ $LastName$ <if(Suffix|Degree)>,<endif>, $Suffix$ <if(Suffix)>,<endif> $Degree$ If it helps we process the templates using this C# StringTemplate stringtemplate = new Antlr.StringTemplate.StringTemplate(template.Data); foreach (Pair<string, string> pair in dictionary) { if (pair.First != null && pair.Second != null) { stringtemplate.SetAttribute(pair.First, pair.Second); } } return stringtemplate.ToString();

    Read the article

  • Using LINQ to remove dupicates in dictionary and the count of those duplicates

    - by Robert
    I have some code that returns unique elements in my dictionary, but I would also like to return the count of the duplicate elements. Basically change dictionary[key, uniqueelement] to dictionary[uniqueelement, count]. Here is my code that just returns the unique elements. var uniqueItems = deviceInstances.Children.GroupBy(pair => pair.Value.Information.UnderlyingDeviceType) .Select(group => group.First()) .ToDictionary(pair => pair.Key, pair => pair.Value.Information.UnderlyingDeviceType.ToString());

    Read the article

  • Is do-notation specific to "base:GHC.Base.Monad"?

    - by yairchu
    The idea that the standard Monad class is flawed and that it should actually extend Functor or Pointed is floating around. I'm not necessarily claiming that it is the right thing to do, but suppose that one was trying to do it: import Prelude hiding (Monad(..)) class Functor m => Monad m where return :: a -> m a join :: m (m a) -> m a join = (>>= id) (>>=) :: m a -> (a -> m b) -> m b a >>= t = join (fmap t a) (>>) :: m a -> m b -> m b a >> b = a >>= const b So far so good, but then when trying to use do-notation: whileM :: Monad m => m Bool -> m () whileM iteration = do done <- iteration if done then return () else whileM iteration The compiler complains: Could not deduce (base:GHC.Base.Monad m) from the context (Monad m) Question: Does do-notation work only for base:GHC.Base.Monad? Is there a way to make it work with an alternative Monad class? Extra context: What I really want to do is replace base:Control.Arrow.Arrow with a "generalized" Arrow class: {-# LANGUAGE TypeFamilies #-} class Category a => Arrow a where type Pair a :: * -> * -> * arr :: (b -> c) -> a b c first :: a b c -> a (Pair a b d) (Pair a c d) second :: a b c -> a (Pair a d b) (Pair a d c) (***) :: a b c -> a b' c' -> a (Pair a b b') (Pair a c c') (&&&) :: a b c -> a b c' -> a b (Pair a c c') And then use the Arrow's proc-notation with my Arrow class, but that fails like in the example above of do-notation and Monad. I'll use mostly Either as my pair type constructor and not the (,) type constructor as with the current Arrow class. This might allow to make the code of my toy RTS game (cabal install DefendTheKind) much prettier.

    Read the article

< Previous Page | 2 3 4 5 6 7 8 9 10 11 12 13  | Next Page >