C++: Template functor cannot deduce reference type
- by maciekp
I've got a functor f, which takes a function func and a parameter t of the same type as func. I cannot pass g to f because of compilation error (no matching function for call to f(int&, void (&)(int&)) ). If g would take non-reference parameter g(int s), compilation finishes. Or if I manually specify template parameter f(i, g), compilation also finishes.
template<typename T>
void f(T t, void (*func)(T)) {}
void g(int& s) {}
int main(int, char*[])
{
int i = 7;
f(i, g); // compilation error here
return 0;
}
How can I get deduction to work?
