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  • Bitmap as button?

    - by Hwang
    How to set a bitmap as a button so that i can apply button mode and mouse-event stuff on it, without adding the bitmap to a Movie Clip? var bmpFull=new Bitmap(event.currentTarget.content.bitmapData); bmpFull.smoothing=true; bmpFull.name="photo"; bmpFull.alpha=0; //fullMC.buttonMode=true; fullMC.addChild(bmpFull);

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  • Configuring a html page from an original demo page

    - by Wold
    I forked into rainyday.js through github, an awesome javascript program made by maroslaw at this link: https://github.com/maroslaw/rainyday.js. Basically I tried taking his demo page and my own photo city.jpg and changed the applicable fields so that I could run it on my own site, but only the picture loads and the script itself doesn't start to run. I'm pretty new to html and javascript so I'm probably omitting something very simple, but here is the script for the demo code: <script src="rainyday.js"></script> <script> function getURLParameter(name) { return decodeURIComponent((new RegExp('[?|&]' + name + '=' + '([^&;]+?)(&|#|;|$)').exec(location.search)||[,''])[1].replace(/\+/g, '%20'))||null; } function demo() { var image = document.getElementById('background'); image.onload = function () { var engine = null; var preset = getURLParameter('preset') || '1'; if (preset === '1') { engine = new RainyDay({ element: 'background', blur: 10, opacity: 1, fps: 30, speed: 30 }); engine.rain([ [1, 2, 8000] ]); engine.rain([ [3, 3, 0.88], [5, 5, 0.9], [6, 2, 1] ], 100); } else if (preset === '2') { engine = new RainyDay({ element: 'background', blur: 10, opacity: 1, fps: 30, speed: 30 }); engine.VARIABLE_GRAVITY_ANGLE = Math.PI / 8; engine.rain([ [0, 2, 0.5], [4, 4, 1] ], 50); } else if (preset === '3') { engine = new RainyDay({ element: 'background', blur: 10, opacity: 1, fps: 30, speed: 30 }); engine.trail = engine.TRAIL_SMUDGE; engine.rain([ [0, 2, 0.5], [4, 4, 1] ], 100); } }; image.crossOrigin = 'anonymous'; if (getURLParameter('imgur')) { image.src = 'http://i.imgur.com/' + getURLParameter('imgur') + '.jpg'; } else if (getURLParameter('img')) { image.src = getURLParameter('img') + '.jpg'; } var youtube = getURLParameter('youtube'); if (youtube) { var div = document.getElementById('sound'); var player = document.createElement('iframe'); player.frameborder = '0'; player.height = '1'; player.width = '1'; player.src = 'https://youtube.com/embed/' + youtube + '?autoplay=1&controls=0&showinfo=0&autohide=1&loop=1'; div.appendChild(player); } } </script> This is where I am naming my background and specifying the photo from within the directory. <body onload="demo();"> <div id="sound" style="z-index: -1;"></div> <div id="parent"> <img id='background' alt="background" src="city.jpg" /> </div> </body> The actual code for the whole entire rainyday.js script can be found here: https://github.com/maroslaw/rainyday.js/blob/master/rainyday.js Thanks in advance for any help and advice!

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  • opening and viewing a file in php

    - by Christian Burgos
    how do i open/view for editing an uploaded file in php? i have tried this but it doesn't open the file. $my_file = 'file.txt'; $handle = fopen($my_file, 'r'); $data = fread($handle,filesize($my_file)); i've also tried this but it wont work. $my_file = 'file.txt'; $handle = fopen($my_file, 'w') or die('Cannot open file: '.$my_file); $data = 'This is the data'; fwrite($handle, $data); what i have in mind is like when you want to view an uploaded resume,documents or any other ms office files like .docx,.xls,.pptx and be able to edit them, save and close the said file. edit: latest tried code... <?php // Connects to your Database include "configdb.php"; //Retrieves data from MySQL $data = mysql_query("SELECT * FROM employees") or die(mysql_error()); //Puts it into an array while($info = mysql_fetch_array( $data )) { //Outputs the image and other data //Echo "<img src=localhost/uploadfile/images".$info['photo'] ."> <br>"; Echo "<b>Name:</b> ".$info['name'] . "<br> "; Echo "<b>Email:</b> ".$info['email'] . " <br>"; Echo "<b>Phone:</b> ".$info['phone'] . " <hr>"; //$file=fopen("uploadfile/images/".$info['photo'],"r+"); $file=fopen("Applications/XAMPP/xamppfiles/htdocs/uploadfile/images/file.odt","r") or exit("unable to open file");; } ?> i am getting the error: Warning: fopen(Applications/XAMPP/xamppfiles/htdocs/uploadfile/images/file.odt): failed to open stream: No such file or directory in /Applications/XAMPP/xamppfiles/htdocs/uploadfile/view.php on line 17 unable to open file the file is in that folder, i don't know it wont find it.

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  • Looking for android Facebook SDK examples...

    - by brybam
    I've looked all over the internet and can't seem to find what i'm looking for... I'm just trying to find a site with some examples on how to use the OFFICIAL facebook android SDK http://github.com/facebook/facebook-android-sdk To be specific i'd like to see some examples on notification use and simple photo upload. But i'll take anything to help get a feel for using the SDK. If anyone knows of any examples please share thank you so much!

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  • Parsing EXIF's "ExposureTime" using PHP

    - by MarkL
    Re, One photo with exposure being 1/640 has the EXIF field of "ExposureTime" eq. "15625/10000000". I am not sure why some photos display this value in a readable format (e.g., "1/100"), but I need to convert this "15625" back to "1/640". How? :) Thanks.

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  • SQL 2008 HierarchyID - Select X descendants down

    - by NTulip
    How can I query a table which has a column of data type HIERARCHYID and get a list of descendants X levels deep under an employee? Here is the current structure: CREATE TABLE [dbo].[Employees]( [NodeId] [hierarchyid] NOT NULL, [EmployeeId] [int] IDENTITY(1,1) NOT NULL, [FirstName] [varchar](120) NULL, [MiddleInitial] [varchar](1) NULL, [LastName] [varchar](120) NULL, [DepartmentId] [int] NULL, [Title] [varchar](120) NULL, [PhoneNumber] [varchar](20) NULL, [IM] [varchar](120) NULL, [Photo] [varbinary](max) NULL, [Bio] [varchar](400) NULL, [Active] [bit] NULL, [ManagerId] [int] NULL )

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  • How do I write object classes effectively when dealing with table joins?

    - by Chris
    I should start by saying I'm not now, nor do I have any delusions I'll ever be a professional programmer so most of my skills have been learned from experience very much as a hobby. I learned PHP as it seemed a good simple introduction in certain areas and it allowed me to design simple web applications. When I learned about objects, classes etc the tutor's basic examnples covered the idea that as a rule of thumb each database table should have its own class. While that worked well for the photo gallery project we wrote, as it had very simple mysql queries, it's not working so well now my projects are getting more complex. If I require data from two separate tables which require a table join I've instead been ignoring the class altogether and handling it on a case by case basis, OR, even worse been combining some of the data into the class and the rest as a separate entity and doing two queries, which to me seems inefficient. As an example, when viewing content on a forum I wrote, if you view a thread, I retrieve data from the threads table, the posts table and the user table. The queries from the user and posts table are retrieved via a join and not instantiated as an object, whereas the thread data is called using my Threads class. So how do I get from my current state of affairs to something a little less 'stupid', for want of a better word. Right now I have a DB class that deals with connection and escaping values etc, a parent db query class that deals with the common queries and methods, and all of the other classes (Thread, Upload, Session, Photo and ones thats aren't used Post, User etc ) are children of that. Do I make a big posts class that has the relevant extra attributes that I retrieve from the users (and potentially threads) table? Do I have separate classes that populate each of their relevant attributes with a single query? If so how do I do that? Because of the way my classes are written, based on what I was taught, my db update row method, or insert method both just take the attributes as an array and update all of that, if I have extra attributes from other db tables in each class then how do I rewrite those methods as obbiously updating automatically like that would result in errors? In short I think my understanding is limited right now and I'd like some pointers when it comes to the fundamentals of how to write more complex classes.

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  • Free server solution for strict content photos with geotags

    - by Max Gontar
    Hi! I would like to create some kind of open free "group" posting of photos with geotags First I thought about Panoramio, but seems there is no API for photos upload. By now I can see only two ways: Flickr - there are groups but you have to approve group membership anyway, or use tags for grouping which is bad for maintenance Custom server solution which will cost efforts and hosting Can you suggest other free photo services with geotags functionality, or opensource solutions? Thank you!

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  • how to access camera.java in on cick event?

    - by Srikanth Naidu
    hi , i am making a app which takes photo on button click i have camera.java which operates camera and takes photo how to i call it on the below event? public void onClick(DialogInterface arg0, int arg1) { setContentView(R.layout.startcamera); } Camera .java package neuro.com; import java.io.FileNotFoundException; import java.io.FileOutputStream; import java.io.IOException; import android.app.Activity; import android.hardware.Camera; import android.hardware.Camera.PictureCallback; import android.hardware.Camera.ShutterCallback; import android.os.Bundle; import android.util.Log; import android.view.View; import android.view.View.OnClickListener; import android.widget.Button; import android.widget.FrameLayout; public class CameraDemo extends Activity { private static final String TAG = "CameraDemo"; Camera camera; Preview preview; Button buttonClick; /** Called when the activity is first created. */ @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.startcamera); preview = new Preview(this); ((FrameLayout) findViewById(R.id.preview)).addView(preview); buttonClick = (Button) findViewById(R.id.buttonClick); buttonClick.setOnClickListener( new OnClickListener() { public void onClick(View v) { preview.camera.takePicture(shutterCallback, rawCallback, jpegCallback); } }); Log.d(TAG, "onCreate'd"); } ShutterCallback shutterCallback = new ShutterCallback() { public void onShutter() { Log.d(TAG, "onShutter'd"); } }; /** Handles data for raw picture */ PictureCallback rawCallback = new PictureCallback() { public void onPictureTaken(byte[] data, Camera camera) { Log.d(TAG, "onPictureTaken - raw"); } }; /** Handles data for jpeg picture */ PictureCallback jpegCallback = new PictureCallback() { public void onPictureTaken(byte[] data, Camera camera) { FileOutputStream outStream = null; try { // write to local sandbox file system // outStream = CameraDemo.this.openFileOutput(String.format("%d.jpg", System.currentTimeMillis()), 0); // Or write to sdcard outStream = new FileOutputStream(String.format("/sdcard/%d.jpg", System.currentTimeMillis())); outStream.write(data); outStream.close(); Log.d(TAG, "onPictureTaken - wrote bytes: " + data.length); } catch (FileNotFoundException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } finally { } Log.d(TAG, "onPictureTaken - jpeg"); } }; }

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  • What is the default resolution of the image saved by iPhone UIImagePicker? is it 1500 x 2000?

    - by zerlphr
    Hi, i have problem trying to find out the default resolution of the images taken and saved by UIImagePicker. I'm trying to merge the photo taken and another image from my library and without knowing what's the size of the image, i'm not able to merge the 2 images correctly. Another question is that: are there different resolutions for the different iphones such as 2g, 3g or 3gs?

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  • In Asp.net i'm not able to catch any exception properly?

    - by Anand
    In Asp.net (c#),i'm not able to catch exception(FileNotFoundException) properly... i don't know the reason..Actually File s not there..But catch statement fails to catch the exception.. here is the code.. try { System.Drawing.Image imgg1 = System.Drawing.Image.FromFile(Server.MapPath("").ToString() + "\\images\\img1.jpg"); } catch (FileNotFoundException) { Response.Write("<script>alert('Please Select and upload Student's Photo');</script>"); }

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  • Android , Read in binary data and write it to file

    - by Shpongle
    Hi all , Im trying to read in image file from a server , with the code below . It keeps going into the exception. I know the correct number of bytes are being sent as I print them out when received. Im sending the image file from python like so #open the image file and read it into an object imgfile = open (marked_image, 'rb') obj = imgfile.read() #get the no of bytes in the image and convert it to a string bytes = str(len(obj)) #send the number of bytes self.conn.send( bytes + '\n') if self.conn.sendall(obj) == None: imgfile.flush() imgfile.close() print 'Image Sent' else: print 'Error' Here is the android part , this is where I'm having the problem. Any suggestions on the best way to go about receiving the image and writing it to a file ? //read the number of bytes in the image String noOfBytes = in.readLine(); Toast.makeText(this, noOfBytes, 5).show(); byte bytes [] = new byte [Integer.parseInt(noOfBytes)]; //create a file to store the retrieved image File photo = new File(Environment.getExternalStorageDirectory(), "PostKey.jpg"); DataInputStream dis = new DataInputStream(link.getInputStream()); try{ os =new FileOutputStream(photo); byte buf[]=new byte[1024]; int len; while((len=dis.read(buf))>0) os.write(buf,0,len); Toast.makeText(this, "File recieved", 5).show(); os.close(); dis.close(); }catch(IOException e){ Toast.makeText(this, "An IO Error Occured", 5).show(); } EDIT: I still cant seem to get it working. I have been at it since and the result of all my efforts have either resulted in a file that is not the full size or else the app crashing. I know the file is not corrupt before sending server side. As far as I can tell its definitely sending too as the send all method in python sends all or throws an exception in the event of an error and so far it has never thrown an exception. So the client side is messed up . I have to send the file from the server so I cant use the suggestion suggested by Brian .

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  • Multiple file upload with preview

    - by sean717
    Hi, Is there any good control or plug-in for uploading multiple photos with preview? As far as I understand it is impossible to preview photo on local computer using just JavaScript. So it has to use Flash or Java. Thanks, also, I use ASP.NET.

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  • Drawing connected lines with OpenGL

    - by user146780
    I'm drawing convex polygons with OpenGL. I then do the same thing but use GL_LINE_LOOP. The problem I have is the lines are not always connected. How could I ensure that the lines are always connected? In the photo below, Iv highlighted in green, the corners that are connected and in red, those that are not. I would like for them to be all like the green ones. http://img249.imageshack.us/i/notconnected.png/ Thanks

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  • UIImagePNGRepresentation issues?

    - by disorderdev
    I want to load images from UIImagePickerController, then save the selected photo to my app's document directory. UIImage *image = [info objectForKey:UIImagePickerControllerOriginalImage]; NSData *data1 = UIImagePNGRepresentation(image); NSString *fileName = "1.png"; NSString *path = //get Document path, then add fileName BOOL succ = [data1 writeToFile:path atomically:YES]; but after I save the image to my document, I found that, the image was rotated 90 degree, then I change the method UIImagePNGRepresentation to UIImageJPEGRepresentation, this time it's fine, anyone know what's the problem?

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  • run a program under a limited user account

    - by sam
    hi all, i want to develop a program that will process images and show all esxisting images with details like "picasa photo viewer",also i have a windows service that gathering new images,it will run under "Local System Account",but in limited user account my program don't work,how i can run my program from limited user account ? thx for ur time

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  • In Asp.net (c#) i'm not able to catch any exception properly????

    - by Anand
    In Asp.net (c#),i'm not able to catch exception(FileNotFoundException) properly... i don't know the reason..Actually File s not there..But catch statement fails to catch the exception.. here is the code.. try { System.Drawing.Image imgg1 = System.Drawing.Image.FromFile(Server.MapPath("").ToString() + "\\images\\img1.jpg"); } catch (FileNotFoundException) { Response.Write("<script>alert('Please Select and upload Student's Photo');</script>"); }

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  • How to control the text inside DIV tag by not allowing the text to be increased?

    - by SzamDev
    Hi I have this CSS code : #d_image { float: left; width: 320px; margin-top: 20px; margin-left: 25px; } #d_coll { width: 320px; float: left; } #n_div { width: 240px; text-align: right; padding-top: 10px; float: left; padding-right: 10px; padding-left: 0px; } #n_text { text-align: right; float: left; clear: both; } #im { height: 50px; width: 50px; float: right; padding-right: 15px; } #n_col { clear: both; width: 310px; float: right; border-bottom-width: 2px; border-bottom-style: solid; border-bottom-color: #CCC; padding-bottom: 10px; } #n_tittle { text-decoration: none; text-align: right; padding-bottom: 10px; padding-right: 15px; } #n_tittle a { text-decoration: none; text-align: right; color: #1C60B3; } #n_tittle a:hover { text-decoration: underline; text-align: right; color: #FF0000; } I have this HTML code : <div id="d_coll"> <div id="d_image">sample text</div> <div id="n_text">Here will be photo</div> </div> <div id="n_col"> <div id="n_tittle">sample text</div> <div id="im">small photo will be here</div> <div id="n_div">long text</div> </div> I have proplem in n_div, if I put in it a very long text it will be under im div and I want the text inside it to go to new line when it reach the end because the image should be to the right of the text in im div . How I can do that? Thanks in Advance.

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