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  • Writing my first bash script (line 2: testscript: No such file or directory)

    - by skyeagle
    I am attempting to write my first shell script (I'm running Ubuntu 10.x) This is what my 'script' looks like cd /path/to/directory/cronscripts . testscript I put the following debug statements (after the cd), in the script above to make sure everything was ok: pwd echo `ls -lhrt` and it displayed all the files in the directory. So I dont understand the error message I am getting. I have the following two questions Why am I getting the above error message and how do I fix it? My script seems to run fine without a shebang in the first line - infact when I try either of the following: #!/usr/bin/bash #!/usr/bin/bash env I get the following error message: /usr/bin/bash: bad interpreter: No such file or directory What is the purpose of the shebang statement and why do I get the above error when I try to include it in my script/ how do I fix it, so I can add the shebang (is it necessary? - it seems most script examples have the shebang - but I'm not sure if it is a must, as the script runs without it).

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  • Empty /var/log after running cron bash script

    - by Ortix92
    I wrote a little bash script and all of a sudden my /var/log folder is completely empty except for the log I created for the bash script. This is the script I'm running every hour with cron: #!/bin/bash STL_DIR=/path/to/some/folder/i/hid LOGFILE=/var/log/stl_upload.log now=`date` echo "----------Start of Transmission----------" 2>&1 | tee -a $LOGFILE echo "Starting transfer at $now" 2>&1 | tee -a $LOGFILE rsync -av -e ssh $STL_DIR [email protected]:/users/path/folder 2>&1 | tee -a $LOGFILE echo "----------End of transmission----------" 2>&1 | tee -a $LOGFILE printf "\n" 2>&1 | tee -a $LOGFILE I want to be clear that I'm not 100% certain this is related to the empty logs folder. So if anyone could give me a pointer as to what could be going on about the reason why my log folder is empty, that'd be great.

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  • bash disable line wrap without truncation

    - by Eric Huang
    I am using a template heavy library in c++ and need to understand the template errors. Reading line wrapped template errors is a serious pain. Is there a way to disable line wrapping in bash without also truncating the output. Additionally, is there a way to do horizontal scrolling on the output. I have seen this answer, how to make bash not to wrap output?, but the output is truncated. The solution doesn't have to be bash targeted, if there is method for this using another shell, tmux, piping make output to another program, compiling from within vim, etc, I'll use it. (Except for copy-pasting into gedit)

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  • how to souce a csh script in bash to set the enviroment

    - by Daniel
    We have oracle running on Solaris, and the shell is by default CSH. So the login script set the oracle_home,oracle_sid in csh also. But I don't like csh and want to use bash to do my work. So how to source the csh login script in bash? e.g, the following is what in the .cshrc file. And when use bash, I'd like use these variables. One way is to copy the variables again and use bash command, such as export ORACLE_SID=TEST. But doing so will let us to maintain two copy of the files. And when we change the database name, or upgrade the database, I need to maintian the bash login file seperately. It's nice to just use something like source .cshr in bash, but it doesn't work. setenv ORACLE_SID TEST setenv ORACLE_HOME /oracle/TEST/home/products/10204 setenv EPC_DISABLED TRUE setenv MANPATH /usr/local/man:/usr/share/man setenv EDITOR vi setenv LD_LIBRARY_PATH $ORACLE_HOME/lib:/usr/sfw/lib/64 setenv NLS_LANG AMERICAN_AMERICA.UTF8 setenv NLS_DATE_FORMAT "DD-MON-RR"

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  • SQL SERVER – Function: Is Function – SQL in Sixty Seconds #004 – Video

    - by pinaldave
    Today is February 29th. An unique date which we only get to observe once every four year. Year 2012 is leap year and SQL Server 2012 is also releasing this year. Yesterday I wrote an article where we have seen observed how using four different function we can create another function which can accurately validate if any year is leap year or not. We will use three functions newly introduced in SQL Server 2012 and demonstrate how we can find if any year is leap year or not. This function uses three of the SQL Server 2012 functions - IIF, EOMONTH and CONCAT. When I wrote this function, this is the sortest function I ever wrote to find out leap year. Please watch the video and let me know if any shorter function can be written to find leap year. More on Leap Yer: Detecting Leap Year in T-SQL using SQL Server 2012 – IIF, EOMONTH and CONCAT Function Date and Time Functions – EOMONTH() – A Quick Introduction Script/Function to Find Last Day of Month  I encourage you to submit your ideas for SQL in Sixty Seconds. We will try to accommodate as many as we can. Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: Database, Pinal Dave, PostADay, SQL, SQL Authority, SQL in Sixty Seconds, SQL Query, SQL Scripts, SQL Server, SQL Tips and Tricks, SQLServer, T SQL, Video

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  • Call a void* as a function without declaring a function pointer

    - by ToxIk
    I've searched but couldn't find any results (my terminology may be off) so forgive me if this has been asked before. I was wondering if there is an easy way to call a void* as a function in C without first declaring a function pointer and then assigning the function pointer the address; ie. assuming the function to be called is type void(void) void *ptr; ptr = <some address>; ((void*())ptr)(); /* call ptr as function here */ with the above code, I get error C2066: cast to function type is illegal in VC2008 If this is possible, how would the syntax differ for functions with return types and multiple parameters?

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  • JS function returning another function

    - by Michael
    I want to understand about variables, that has been used in returning function. This is example code Prototype = {} Prototype.F = { bind: function() { var args = arguments, __method = args.shift(), object = args.shift(); return function() { return __method.apply(object, args.concat(arguments)); } } } function ObjectA() { ... this.addListener = Prototype.F.bind(this.eventSource.addListener, this.eventSource); ... } var a = ObjectA(); a.addListener(this); // assuming 'this' here will point to some window object As I understand the returning function in F() is not evaluated until it's called in the last line. It's ok to accept. So addListener will hold a function body containing 'apply'. But what I don't understand, when addListener is called, what kind of parameters it is going to have? particularly _method and args will always be uninitialized?

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  • how to pass arguments into function within a function in r

    - by jon
    I am writing function that involve other function from base R with alot of arguments. For example (real function is much longer): myfunction <- function (dataframe, Colv = NA) { matrix <- as.matrix (dataframe) out <- heatmap(matrix, Colv = Colv) return(out) } data(mtcars) myfunction (mtcars, Colv = NA) The heatmap has many arguments that can be passed to: heatmap(x, Rowv=NULL, Colv=if(symm)"Rowv" else NULL, distfun = dist, hclustfun = hclust, reorderfun = function(d,w) reorder(d,w), add.expr, symm = FALSE, revC = identical(Colv, "Rowv"), scale=c("row", "column", "none"), na.rm = TRUE, margins = c(5, 5), ColSideColors, RowSideColors, cexRow = 0.2 + 1/log10(nr), cexCol = 0.2 + 1/log10(nc), labRow = NULL, labCol = NULL, main = NULL, xlab = NULL, ylab = NULL, keep.dendro = FALSE, verbose = getOption("verbose"), ...) I want to use these arguments without listing them inside myfun. myfunction (mtcars, Colv = NA, col = topo.colors(16)) Error in myfunction(mtcars, Colv = NA, col = topo.colors(16)) : unused argument(s) (col = topo.colors(16)) I tried the following but do not work: myfunction <- function (dataframe, Colv = NA) { matrix <- as.matrix (dataframe) out <- heatmap(matrix, Colv = Colv, ....) return(out) } data(mtcars) myfunction (mtcars, Colv = NA, col = topo.colors(16))

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  • Getting more helpful tab completion prompts in bash?

    - by Rory McCann
    Let's say I have a directory with a few files in it like this: $ ls file1 file2 file3 And I want to do some tab completion in bash: $ cat file<tab> file1 file2 file3 I remember seeing someone doing tab completion and the shell bolded the next parts, so in this case, it would bold the 1, 2 and 3 of the filename so it'll look like this: file**1** file**2** file**3** which will tell you what you should type in next. I think this was a feature of zsh, but is there any way to get it in bash?

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  • bash vs sh | What is the difference

    - by Saif Bechan
    In using i see 2 types of code #!/usr/bin/sh and #!/user/bin/bash I have Googled this and the opinions vary a lot. The explanation I have seen on most websites is that sh is older than bash, and that there is no real difference. Does someone know the difference between these and can give a practical example when to use either one of them. I highly doubt that there is no real difference, because then having to things that do the exact same thing would be just

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  • Bash Script To Repair Directory and File Ownership

    - by ServerChecker
    My client had me deploy some folders out to a bunch of home directories for his customer websites. I did this with a Bash script, but it ended up using the root account permissions. How do I make a Bash script that takes each folder under /home/user (not hidden files or folders), gets the user and group ownership of that folder, and then does a chown -R {user}.{group} /home/user? The servers are running CentOS Linux.

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  • Launching an application from Bash

    - by JBoy
    I'm right now busy with moving the first steps into Linux, i'm using a bash shell within a mac osx I see in all tutorials that in order to launch an application from the bash its necessary to cd to its directory and simply type the name of the app. This is exatly what i'm doing and it does not work (i have on my desktop a 'Eclipse' folder with the launcher icon in it): cd Desktop cd Eclipse Eclipse.app Why will this not work? I read everywhere that typing the name of the app its enough

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  • How to load powershell profile from cygwin bash?

    - by Jon Erickson
    So in cygwin bash I am able to type "powershell" to bring me into a powershell prompt but it won't load my powershell profile.ps1 due to not being able to execute scripts, but I can't set the execution policy in this prompt... So I tried running the default powershell prompt (as administrator) and was able to set the execution policy to remote signed, but it doesn't affect the powershell within bash what am I missing?

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  • Bash if statement equal output from last command

    - by mYzk
    I am trying to equal something from last command with bash if statement: #!/bin/bash monit status if [ "status" != "error" ]; then echo -e "hostname\ttest\t0\t0" | /usr/sbin/send_nsca -H hostname -c /etc/send_nsca.cfg exit 1; fi Even if the monit status gives out status = online with all services it runs the echo command. I can not figure out how to make the if statement match the status of monit status output.

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  • Bash command to focus a specific window.

    - by D Connors
    Is there a way, in bash command line, to give focus to a specific window of a running process. Assume I know the process' name, number, and anything else I need. For instance, if I have a single instance of Firefox running, but it's minimized (or there's some other window on top of it). I need a bash command that brings up and gives focus to the Firefox window, by making it the active window. Thanks

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  • (Ubuntu) setuid bash doesn't work

    - by ???
    Here is the code: (root:) # mkdir /test # cp /bin/bash /test/sbash # chmod a+s /test/sbash (user1:) $ cd /test $ ./sbash $ mkdir trycreate mkdir: cannot create directory `trycreate': Permission denied And bash scripts with setuid bit set not work, either. By the way, my setuid perl script works: test.pl: (with setuid bit set, owner=root) #!/usr/bin/perl mkdir('/test/tryperlcreate') or die 'failed'; execute test.pl by user1 will create the directory owned by root.

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  • echo newline character not working in bash

    - by Bashuser
    I have bash script which has lots of echo statements and also I aliased echo to echo -e both in .bash_profile and .bashrc, so that new lines are printed properly for a statement like echo 'Hello\nWorld' the output should be Hello World but the output I am getting is Hello\nWorld I even tried using shopt -s expand_aliases in the script, it doesn't help I am running my script as bash /scripts/scriptnm.sh; if I run it as . /scripts/scriptnm.sh I am getting the desired output...

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  • Error running bash script - No matching processes

    - by Bashity
    I am trying to kill Xcode by running killall Xcode.app, which works normally when I run it through terminal. However, if I put it into a bash script that I keep on my Desktop called re_xcode, the script will output the following error. Please can you tell me where I am going wrong? No matching processes belonging to you were found The file /Users/Max/Desktop/Applications/Xcode.app does not exist. #!/bin/bash killall Xcode.app open ./Applications/Xcode.app

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  • Comments in a multi-line bash command

    - by Nicolas Raoul
    This single-command BASH script file is difficult to understand, so I want to write a comment for each of the actions: grep -R "%" values* \ | sed -e "s/%/\n%/" \ | grep "%" \ | grep -v " % " \ | grep -v " %<" \ | grep -v "%s" \ | grep -v "%d" \ | grep -v "%1$s" I would hate having to duplicate lines, or having each comment far away from the line it applies to. But at the same time BASH does not seem to allow "in-line" comments. Any elegant way to solve this problem?

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  • What is the difference between bash and sh

    - by Saif Bechan
    In using i see 2 types of code #!/usr/bin/sh and #!/user/bin/bash I have Googled this and the opinions vary a lot. The explanation I have seen on most websites is that sh is older than bash, and that there is no real difference. Does someone know the difference between these and can give a practical example when to use either one of them. I highly doubt that there is no real difference, because then having to things that do the exact same thing would be just

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  • Problem with bash scripting

    - by eple
    Hi. I terrible with bash scripting, and need some help with the following: #!/bin/bash if [ -e Pretty* ];then ncftpput -R -DD -v -u xbmc -p xbmc 192.168.1.100 /home/xbmc/TV/Pretty_Little_Liars/ Pretty* else echo "No new folders" fi find -depth -type d -empty -exec rmdir {} \; Problem here is the ncftpput line.. if I just do a simple [ echo "working" ] instead, everything is OK, but when I try the ncftpput-line it just gives me [ line 5: [: too many arguments ] the ncftpput command alone works fine.. Any ideas?

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