Search Results

Search found 2375 results on 95 pages for 'triangle man'.

Page 7/95 | < Previous Page | 3 4 5 6 7 8 9 10 11 12 13 14  | Next Page >

  • How to shoot a triangle out of an asteroid which floats all of the way up to the screen?

    - by Holland
    I currently have an asteroid texture loaded as my "test player" for the game I'm writing. What I'm trying to figure out how to do is get a triangle to shoot from the center of the asteroid, and keep going until it hits the top of the screen. What happens in my case (as you'll see from the code I've posted), is that the triangle will show, however it will either be a long line, or it will just be a single triangle which stays in the same location as the asteroid moving around (that disappears when I stop pressing the space bar), or it simply won't appear at all. I've tried many different methods, but I could use a formula here. All I'm trying to do is write a space invaders clone for my final in C#. I know how to code fairly well, my formulas just need work is all. So far, this is what I have: Main Logic Code protected override void Draw(GameTime gameTime) { GraphicsDevice.Clear(ClearOptions.Target, Color.Black, 1, 1); mAsteroid.Draw(mSpriteBatch); if (mIsFired) { mPositions.Add(mAsteroid.LastPosition); mRay.Fire(mPositions); mIsFired = false; mRay.Bullets.Clear(); mPositions.Clear(); } base.Draw(gameTime); } Draw Code public void Draw() { VertexPositionColor[] vertices = new VertexPositionColor[3]; int stopDrawing = mGraphicsDevice.Viewport.Width / mGraphicsDevice.Viewport.Height; for (int i = 0; i < mRayPos.Length(); ++i) { vertices[0].Position = new Vector3(mRayPos.X, mRayPos.Y + 5f, 10); vertices[0].Color = Color.Blue; vertices[1].Position = new Vector3(mRayPos.X - 5f, mRayPos.Y - 5f, 10); vertices[1].Color = Color.White; vertices[2].Position = new Vector3(mRayPos.X + 5f, mRayPos.Y - 5f, 10); vertices[2].Color = Color.Red; mShader.CurrentTechnique.Passes[0].Apply(); mGraphicsDevice.DrawUserPrimitives<VertexPositionColor>(PrimitiveType.TriangleStrip, vertices, 0, 1); mRayPos += new Vector2(0, 1f); mGraphicsDevice.ReferenceStencil = 1; } }

    Read the article

  • What software development process should I learn first for a solo project?

    - by Omar Kohl
    I want to develop a project on my own (if it is sucessful more people might start working on it too). Also I want to apply some proper software engineering from the first until the last day. On one hand just to try it out and compare results with previous projects that were just about writing code quick and dirty, and on the other hand to learn! I know the proper answer to this question is "It depends very much on the project...", "There is no single correct answer...". But I just need someplace to start, somewhere where every step is written down and tells me what to do. If I'm not happy next time I'll try something else. So, how/where should I start? I would love to hear some book suggestions cause I'm all about books :-D.

    Read the article

  • Using an array as parameter to a class.

    - by Gabriel A. Zorrilla
    I have created an array Man: public main blah blah{ man = man[10]; } Man has fields such as Man.name; Man.age; ... In Man class, there is a OnClick method that opens a new window showing its name and age. public Man(){ Onclick(){ InfoWindow showinfo = new InfoWindow(this.getid()) // If this is Man[2] the id would be 2. } And in InfoWindow class: public class InfoWindow extends JFrame{ public InfoWindow(Man selectedMan){ setSize(300, 200); JLabel info = new JLabel(selectedMan.getname()); add(info); info.setVisible(true); } } Basically, that's wanna acomplish (show in pseudocode), pass a Man[i] into a class that when a window is created, shows the info related to that man. This is how i'm actualy trying to implement it but it's not working, i'm pretty sure there is a misconception from me in some part. Any help?

    Read the article

  • Remove key from known_hosts

    - by Adam Matan
    Hi, I have built several virtual machines during the last few weeks. The problem is, the .ssh/known_hosts gives me the Man in the middle warning. This happens because another fingerprint is associated with the virtual machine IP. In the .ssh/known_hosts file, however, I don't seem to find the record related to the IP, only two bizarre, key-like strings and "ssh-rsa". Any ideas how to remove the old key from known_hosts? Thanks, Udi

    Read the article

  • How to jump to a particular flag in a Unix manpage?

    - by dotancohen
    When reading a Unix manpage in the terminal, how can I jump easily to the description of a particular flag? For instance, I need to know the meaning of the -o flag for mount. I run man mount and want to jump to the place where -o is described. Currently, I search /-o however that option is mentioned in several places before the section that actually describes it, so I must jump around quite a bit. Thanks.

    Read the article

  • How do you switch between Linux manual pages?

    - by Sheldon
    I'm new with Linux and have noticed that there are numbers beside certain commands I look up. For example I want to look up accept() in the aspect of network programming, but man accept shows this instead: accept(8) Easy Software Products accept(8) NAME accept/reject - accept/reject jobs sent to a destination So how do you switch between manual pages to other numbers like accept(1) ~ accept(7)?

    Read the article

  • How to determine character's foot contact point on a uniform triangle mesh terrain?

    - by xenon
    For a terrain that is modelled by a heightmap with a uniform triangle mesh, what are some techniques I could use to determine the contact point of the foot of a character standing on the terrain? Since the terrain's Y values are altered by the heightmap, they won't be flat any more. As the character moves on the terrain, it has to know at which values of Y-value its foot should be. Conceptually, what are some methods and techniques to determine the contact point of the character's foot standing on the terrain?

    Read the article

  • How to remove strict RSA key checking in SSH and what's the problem here?

    - by setatakahashi
    I have a Linux server that whenever I connect it shows me the message that changed the SSH host key: $ ssh root@host1 @@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@ @ WARNING: REMOTE HOST IDENTIFICATION HAS CHANGED! @ @@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@ IT IS POSSIBLE THAT SOMEONE IS DOING SOMETHING NASTY! Someone could be eavesdropping on you right now (man-in-the-middle attack)! It is also possible that the RSA host key has just been changed. The fingerprint for the RSA key sent by the remote host is 93:a2:1b:1c:5f:3e:68:47:bf:79:56:52:f0:ec:03:6b. Please contact your system administrator. Add correct host key in /home/emerson/.ssh/known_hosts to get rid of this message. Offending key in /home/emerson/.ssh/known_hosts:377 RSA host key for host1 has changed and you have requested strict checking. Host key verification failed. It keeps me for a very few seconds logged in and then it closes the connection. host1:~/.ssh # Read from remote host host1: Connection reset by peer Connection to host1 closed. Does anyone know what's happening and what I could do to solve this problem?

    Read the article

  • Squid refresh_pattern won't cache "Expires: ..."

    - by Marcelo Cantos
    Background I frequent the OpenGL ES documentation site at http://www.khronos.org/opengles/sdk/1.1/docs/man/. Even though the content is completely static, it seems to force a reload on every single page I visit, which is very annoying. I have a squid 3.0 proxy set up (apt-get install squid3 on Ubuntu 10.04), and I added a refresh_pattern to force the pages to cache: refresh_pattern ^http://www.khronos.org/opengles/sdk/1\.1/docs/man/ … 1440 20% 10080 … override-expire ignore-reload ignore-no-cache ignore-private ignore-no-store This is all on one line, of course. While this appears to work for the XHTML documents (e.g., glBindTexture), it fails to cache the linked content, such as the DTD, some .ent files (?) and some XSL files. The delay in fetching these extra files delays rendering of the main document, so my principal annoyance isn't fixed. The only difference I can glean with these ancillary files is that they come with an Expires: header set to the current time, whereas the XHTML document has none. But I would have expected the override-expire option to fix this. I have confirmed that documents have the same base URL. I have also truncated the pattern to varying degrees, with no effect. My questions Why does the override-expire option not seem to work? Is there a simple way to tell squid to unconditionally cache a document, no matter what it finds in the response headers? (Hopefully) relevant output cache.log Jan 01 10:33:30 1970/06/25 21:18:27| Processing Configuration File: /etc/squid3/squid.conf (depth 0) Jan 01 10:33:30 1970/06/25 21:18:27| WARNING: use of 'override-expire' in 'refresh_pattern' violates HTTP Jan 01 10:33:30 1970/06/25 21:18:27| WARNING: use of 'ignore-reload' in 'refresh_pattern' violates HTTP Jan 01 10:33:30 1970/06/25 21:18:27| WARNING: use of 'ignore-no-cache' in 'refresh_pattern' violates HTTP Jan 01 10:33:30 1970/06/25 21:18:27| WARNING: use of 'ignore-no-store' in 'refresh_pattern' violates HTTP Jan 01 10:33:30 1970/06/25 21:18:27| WARNING: use of 'ignore-private' in 'refresh_pattern' violates HTTP Jan 01 10:33:30 1970/06/25 21:18:27| DNS Socket created at 0.0.0.0, port 37082, FD 10 Jan 01 10:33:30 1970/06/25 21:18:27| Adding nameserver 192.168.1.1 from /etc/resolv.conf Jan 01 10:33:30 1970/06/25 21:18:27| Accepting HTTP connections at 0.0.0.0, port 3128, FD 11. Jan 01 10:33:30 1970/06/25 21:18:27| Accepting ICP messages at 0.0.0.0, port 3130, FD 13. Jan 01 10:33:30 1970/06/25 21:18:27| HTCP Disabled. Jan 01 10:33:30 1970/06/25 21:18:27| Loaded Icons. Jan 01 10:33:30 1970/06/25 21:18:27| Ready to serve requests. access.log Jun 25 21:19:35 2010.710 0 192.168.1.50 TCP_MEM_HIT/200 2452 GET http://www.khronos.org/opengles/sdk/1.1/docs/man/glBindTexture.xml - NONE/- text/xml Jun 25 21:19:36 2010.263 543 192.168.1.50 TCP_MISS/304 322 GET http://www.khronos.org/opengles/sdk/1.1/docs/man/xhtml1-transitional.dtd - DIRECT/74.54.224.215 - Jun 25 21:19:36 2010.276 556 192.168.1.50 TCP_MISS/304 370 GET http://www.khronos.org/opengles/sdk/1.1/docs/man/mathml.xsl - DIRECT/74.54.224.215 - Jun 25 21:19:36 2010.666 278 192.168.1.50 TCP_MISS/304 322 GET http://www.khronos.org/opengles/sdk/1.1/docs/man/xhtml-lat1.ent - DIRECT/74.54.224.215 - Jun 25 21:19:36 2010.958 279 192.168.1.50 TCP_MISS/304 322 GET http://www.khronos.org/opengles/sdk/1.1/docs/man/xhtml-symbol.ent - DIRECT/74.54.224.215 - Jun 25 21:19:37 2010.251 276 192.168.1.50 TCP_MISS/304 322 GET http://www.khronos.org/opengles/sdk/1.1/docs/man/xhtml-special.ent - DIRECT/74.54.224.215 - Jun 25 21:19:37 2010.332 0 192.168.1.50 TCP_IMS_HIT/304 316 GET http://www.khronos.org/opengles/sdk/1.1/docs/man/ctop.xsl - NONE/- text/xml Jun 25 21:19:37 2010.332 0 192.168.1.50 TCP_IMS_HIT/304 316 GET http://www.khronos.org/opengles/sdk/1.1/docs/man/pmathml.xsl - NONE/- text/xml store.log Jun 25 21:19:36 2010.263 RELEASE -1 FFFFFFFF D3056C09B42659631A65A08F97794E45 304 1277464776 -1 1277464776 unknown -1/0 GET http://www.khronos.org/opengles/sdk/1.1/docs/man/xhtml1-transitional.dtd Jun 25 21:19:36 2010.276 RELEASE -1 FFFFFFFF 9BF7F37442FD84DD0AC0479E38329E3C 304 1277464776 -1 1277464776 unknown -1/0 GET http://www.khronos.org/opengles/sdk/1.1/docs/man/mathml.xsl Jun 25 21:19:36 2010.666 RELEASE -1 FFFFFFFF 7BCFCE88EC91578C8E2589CB6310B3A1 304 1277464776 -1 1277464776 unknown -1/0 GET http://www.khronos.org/opengles/sdk/1.1/docs/man/xhtml-lat1.ent Jun 25 21:19:36 2010.958 RELEASE -1 FFFFFFFF ECF1B24E437CFAA08A2785AA31A042A0 304 1277464777 -1 1277464777 unknown -1/0 GET http://www.khronos.org/opengles/sdk/1.1/docs/man/xhtml-symbol.ent Jun 25 21:19:37 2010.251 RELEASE -1 FFFFFFFF 36FE3D76C80F0106E6E9F3B7DCE924FA 304 1277464777 -1 1277464777 unknown -1/0 GET http://www.khronos.org/opengles/sdk/1.1/docs/man/xhtml-special.ent Jun 25 21:19:37 2010.332 RELEASE -1 FFFFFFFF A33E5A5CCA2BFA059C0FA25163485192 304 1277462871 1221139523 1277462871 text/xml -1/0 GET http://www.khronos.org/opengles/sdk/1.1/docs/man/ctop.xsl Jun 25 21:19:37 2010.332 RELEASE -1 FFFFFFFF E2CF8854443275755915346052ACE14E 304 1277462872 1221139523 1277462872 text/xml -1/0 GET http://www.khronos.org/opengles/sdk/1.1/docs/man/pmathml.xsl

    Read the article

  • Speaking at Triangle SQL Server User Group 16 Mar 2010!

    - by andyleonard
    I'm excited to present Applied SSIS Design Patterns to the Triangle SQL Server User Group 16 Mar 2010! This is a reprise of my PASS Summit 2009 spotlight session. If you read this blog and make the meeting, introduce yourself! :{> Andy Share this post: email it! | bookmark it! | digg it! | reddit! | kick it! | live it!...(read more)

    Read the article

  • pascal triangle in php (anything wrong with this solution?) [migrated]

    - by zhenka
    I saw that one of the interview questions could be building a pascal triangle. Is there anything wrong with this particular solution I came up with? function pascal_r($r){ $local = array(); if($r == 1){ return array(array(1)); } else { $previous = pascal_r($r - 1); array_push($local, 1); for($i = 0; $i < $r - 2 && $r > 2; $i++){ array_push($local, $previous[$r-2][$i] + $previous[$r-2][$i + 1]); } array_push($local, 1); } array_push($previous, $local); return $previous; } print_r(pascal_r(100));

    Read the article

  • Is there a Pac-Man-like character in ASCII or Unicode?

    - by Ricket
    Simple question: is there a character that looks either like Pac-Man, or like the ghost in Pac-Man? With Google's recent Pac-Man logo, everyone should know what these look like, but in case you don't here are some sample images: If you answer "no" please provide a little more proof that you actually searched all unicode characters...

    Read the article

  • 2D polygon triangulation

    - by logank9
    The code below is my attempt at triangulation. It outputs the wrong angles (it read a square's angles as 90, 90. 90, 176) and draws the wrong shapes. What am I doing wrong? //use earclipping to generate a list of triangles to draw std::vector<vec> calcTriDraw(std::vector<vec> poly) { std::vector<double> polyAngles; //get angles for(unsigned int i = 0;i < poly.size();i++) { int p1 = i - 1; int p2 = i; int p3 = i + 1; if(p3 > int(poly.size())) p3 -= poly.size(); if(p1 < 0) p1 += poly.size(); //get the angle from 3 points double dx, dy; dx = poly[p2].x - poly[p1].x; dy = poly[p2].y - poly[p1].y; double a = atan2(dy,dx); dx = poly[p3].x - poly[p2].x; dy = poly[p3].y - poly[p2].y; double b = atan2(dy,dx); polyAngles.push_back((a-b)*180/PI); } std::vector<vec> triList; for(unsigned int i = 0;i < poly.size() && poly.size() > 2;i++) { int p1 = i - 1; int p2 = i; int p3 = i + 1; if(p3 > int(poly.size())) p3 -= poly.size(); if(p1 < 0) p1 += poly.size(); if(polyAngles[p2] >= 180) { continue; } else { triList.push_back(poly[p1]); triList.push_back(poly[p2]); triList.push_back(poly[p3]); poly.erase(poly.begin()+p2); std::vector<vec> add = calcTriDraw(poly); triList.insert(triList.end(), add.begin(), add.end()); break; } } return triList; }

    Read the article

  • Find all cycles in graph, redux

    - by Shadow
    Hi, I know there are a quite some answers existing on this question. However, I found none of them really bringing it to the point. Some argue that a cycle is (almost) the same as a strongly connected components (s. http://stackoverflow.com/questions/546655/finding-all-cycles-in-graph/549402#549402) , so one could use algorithms designed for that goal. Some argue that finding a cycle can be done via DFS and checking for back-edges (s. boost graph documentation on file dependencies). I now would like to have some suggestions on whether all cycles in a graph can be detected via DFS and checking for back-edges? My opinion is that it indeed could work that way as DFS-VISIT (s. pseudocode of DFS) freshly enters each node that was not yet visited. In that sense, each vertex exhibits a potential start of a cycle. Additionally, as DFS visits each edge once, each edge leading to the starting point of a cycle is also covered. Thus, by using DFS and back-edge checking it should indeed be possible to detect all cycles in a graph. Note that, if cycles with different numbers of participant nodes exist (e.g. triangles, rectangles etc.), additional work has to be done to discriminate the acutal "shape" of each cycle.

    Read the article

  • What most efficient method to find a that triangle which contains the given point?

    - by Christo
    Given the triangle with vertices (a,b,c): c / \ / \ / \ a - - - b Which is then subdivided into four triangles by halving each of the edges: c / \ / \ ca / \ bc /\ - - - /\ / \ / \ / \ / \ a- - - - ab - - - -b Wich results in four triangles (a, ab, ca), (b, bc, ab), (c, ca, bc), (ab, bc, ca). Now given a point p. How do I determine in which triangle p lies, given that p is within the outer triangle (a, b, c)? Currently I intend to use ab as the origin. Check whether it is to the left of right of the line "ca - ab" using the perp of "ca - ab" and checking the sign against the dot product of "ab - a" and the perp vector and the vector "p - ab". If it is the same or the dot product is zero then it must be in (a, ab, ca)... Continue with this procedure with the other outer triangles (b, ba, ab) & (c, ca, ba). In the end if it didn't match with these it must be contained within the inner triangle (ab, bc, ca). Is there a better way to do it?

    Read the article

  • Final Man vs. Machine Round of Jeopardy Unfolds; Watson Dominates

    - by ETC
    The final round of IBM’s Watson against Ken Jenning and Brad Rutter ended last night with Watson coming out in a strong lead against its two human opponents. Read on to catch a video of the match and see just how quick Watson is on the draw. Watson tore through many of the answers, the little probability bar at the bottom of the screen denoting it was often 95%+ confident in its answers. Some of the more interesting stumbles were, like in the last matches, based on nuance. By far the biggest “What?” moment of the night, however, was when it answered the Daily Double question of “The New Yorker’s 1959 review of this said in its brevity and clarity, it is ‘unlike most such manuals, a book as well as a tool’”. Watson, inexplicably, answered “Dorothy Parker”. You can win them all, eh? Check out the video below to see Watson in action on its final day. Latest Features How-To Geek ETC How to Enable User-Specific Wireless Networks in Windows 7 How to Use Google Chrome as Your Default PDF Reader (the Easy Way) How To Remove People and Objects From Photographs In Photoshop Ask How-To Geek: How Can I Monitor My Bandwidth Usage? Internet Explorer 9 RC Now Available: Here’s the Most Interesting New Stuff Here’s a Super Simple Trick to Defeating Fake Anti-Virus Malware The Citroen GT – An Awesome Video Game Car Brought to Life [Video] Final Man vs. Machine Round of Jeopardy Unfolds; Watson Dominates Give Chromium-Based Browser Desktop Notifications a Native System Look in Ubuntu Chrome Time Track Is a Simple Task Time Tracker Google Sky Map Turns Your Android Phone into a Digital Telescope Walking Through a Seaside Village Wallpaper

    Read the article

  • What's the best project management software for internal dev. 5 man shop

    - by P.Brian.Mackey
    I work for a large corporation, but we do small intranet web application development. Our project management tracking sucks. Its custom software built by a jr. intern. For what its worth, our development style is akin to agile, but there's nothing set in stone...very customer oriented approach. I need project tracking that meets the criteria: Intranet, internal products. Mostly maintenance, some new development. 5 developers 12 products 1 hands-off manager. He really just wants to know estimated man hours, due date for dev, QA and release. Along with a short description of the project. Free or super cheap. Bonus Simple pretty UI. Think pretty charts. Hope I covered everything. Please ask for any clarification. If you read dreaming in code, the company uses some project tracking software that sounds pretty sweet. Note, we do have Team Foundation Server. I already tried pushing its use as PM tracking, but its too complicated. I can't get people to sit and train. So this software has to be easy.

    Read the article

  • How does a one-man developer do its games' sounds?

    - by Gustavo Maciel
    Before anything, that's not a "oh, where can I find resources?" question. Well, I've been curious about one thing in the indie games industry. For the development of the game, such tasks like game design, art, sketches, code programming and etc can be easily done by just one person. You can just take up a paper and pencil and you're a game designer. You can just take software like Photoshop or Paint and you're an artist, a scanner and you're a sketcher, a compiler and you're a programmer. For sound it's different. You may tell me: Well, follow the line, take a lot of instruments and record it. But all we know that things don't work this way. I can list up some changes for us: External noises are a big problem, sound effects can't be made with instruments, it can't sound like a recorded and clipped sound. Well I can imagine how they do this in large companies, with such big studios and etc. But to summarise, my question is: What's the best way for a one-man indie to do all its sound? Does he have to synthesize everything? Record and buy some crazy program for editing sounds?

    Read the article

  • Museum of Modern Art Starts Video Game Collection; Acquires Myst, Pac-Man, and More

    - by Jason Fitzpatrick
    The Museum of Modern Art is weighing in on the video-games-as-art debate by starting a collection of iconic video games and putting them up for public display. Read on to see what games are included in the initial batch and the MoMA’s reasons behind starting a video game collection. Although the MoMA is slated to grow to over 40 titles, the seed batch is 14 titles including: Pac-Man, Tetris, Sim City 2000, Myst, Portal, and Dwarf Fortress. In the announcement they explain the motivation for building a video game collection: Are video games art? They sure are, but they are also design, and a design approach is what we chose for this new foray into this universe. The games are selected as outstanding examples of interaction design—a field that MoMA has already explored and collected extensively, and one of the most important and oft-discussed expressions of contemporary design creativity. Our criteria, therefore, emphasize not only the visual quality and aesthetic experience of each game, but also the many other aspects—from the elegance of the code to the design of the player’s behavior—that pertain to interaction design. In order to develop an even stronger curatorial stance, over the past year and a half we have sought the advice of scholars, digital conservation and legal experts, historians, and critics, all of whom helped us refine not only the criteria and the wish list, but also the issues of acquisition, display, and conservation of digital artifacts that are made even more complex by the games’ interactive nature. This acquisition allows the Museum to study, preserve, and exhibit video games as part of its Architecture and Design collection. The above quote is only a small snippet of a much lengthier look at the benefits of examining and preserving video games, hit up the link below to check out the full post including future titles the MoMA would like to include in their archive. Video Games: 14 in the Collection, for Starters [Inside/Out] How To Boot Your Android Phone or Tablet Into Safe Mode HTG Explains: Does Your Android Phone Need an Antivirus? How To Use USB Drives With the Nexus 7 and Other Android Devices

    Read the article

  • Setting up a transparent SSL proxy

    - by badunk
    I've got a linux box set up with 2 network cards to inspect traffic going through port 80. One card is used to go out to the internet, the other one is hooked up to a networking switch. The point is to be able to inspect all HTTP and HTTPS traffic on devices hooked up to that switch for debugging purposes. I've written the following rules for iptables: nat -A PREROUTING -i eth1 -p tcp -m tcp --dport 80 -j DNAT --to-destination 192.168.2.1:1337 -A PREROUTING -i eth1 -p tcp -m tcp --dport 80 -j REDIRECT --to-ports 1337 -A POSTROUTING -s 192.168.2.0/24 -o eth0 -j MASQUERADE On 192.168.2.1:1337, I've got a transparent http proxy using Charles (http://www.charlesproxy.com/) for recording. Everything's fine for port 80, but when I add similar rules for port 443 (SSL) pointing to port 1337, I get an error about invalid message through Charles. I've used SSL proxying on the same computer before with Charles (http://www.charlesproxy.com/documentation/proxying/ssl-proxying/), but have been unsuccessful with doing it transparently for some reason. Some resources I've googled say its not possible - I'm willing to accept that as an answer if someone can explain why. As a note, I have full access to the described set up including all the clients hooked up to the subnet - so I can accept self-signed certs by Charles. The solution doesn't have to be Charles-specific since in theory, any transparent proxy will do. Thanks! Edit: After playing with it a little, I was able to get it working for a specific host. When I modify my iptables to the following (and open 1338 in charles for reverse proxy): nat -A PREROUTING -i eth1 -p tcp -m tcp --dport 80 -j DNAT --to-destination 192.168.2.1:1337 -A PREROUTING -i eth1 -p tcp -m tcp --dport 80 -j REDIRECT --to-ports 1337 -A PREROUTING -i eth1 -p tcp -m tcp --dport 443 -j DNAT --to-destination 192.168.2.1:1338 -A PREROUTING -i eth1 -p tcp -m tcp --dport 443 -j REDIRECT --to-ports 1338 -A POSTROUTING -s 192.168.2.0/24 -o eth0 -j MASQUERADE I am able to get a response, but with no destination host. In the reverse proxy, if I just specify that everything from 1338 goes to a specific host that I wanted to hit, it performs the hand shake properly and I can turn on SSL proxying to inspect the communication. The setup is less than ideal because I don't want to assume everything from 1338 goes to that host - any idea why the destination host is being stripped? Thanks again

    Read the article

  • What program should I use for SSL stripping and re-encrypting

    - by Sparksis
    I'm trying to strip a HTTP over SSL connection down to SSL and then re-encrypt the channel (with a signed certificate(s) I can provide). Of course I want to be able to store captures of all the un-encrypted data. The purpose of this is to reverse engineer a HTTP handshake that is used by a SIP program on my machine. I've tried SSLstrip but it doesn't support what I need it too. Edit: I want something to this effect https://github.com/applidium/Cracking-Siri/blob/master/tcpProxy.rb only more generic and able to write to a pcap stream that wireshark will understand (I'm not sure if this does that). Edit2: upon further inspection this does not create pcap streams. I guess if need be I can write a compatible version but that is not the desired choice.

    Read the article

  • Open Source project that does SSL Inspection

    - by specs
    I've been assigned to research out and spec replacing our old and decrepit http content filtering system. There are several open source filtering packages available but I've not come across one that does SSL inspection. The new system will scale to many branches of different sizes, from say 10 users to a few hundred, so purchasing an appliance for each branch isn't desirable. When we're further along, we will do custom programming as we have a few unique needs in other aspects of filtering, so if the suggestion takes a bit of customization, it won't be a problem.

    Read the article

  • Using gluLookAt to move camera in 2D iPhone game ?

    - by Mr.Gando
    Hey guys, I'm trying to use gluLookAt to move the camera in my iPhone game, but every time I've tried to use gluLookAt my screen just goes "blank" ( grey in this case ) I'm trying to render a simple triangle and to move the camera, this is my code: to setup my scene I do: glViewport(0, 0, backingWidth, backingHeight); glMatrixMode(GL_PROJECTION); glLoadIdentity(); glRotatef(-90.0, 0.0, 0.0, 1.0); //using iPhone in horizontal mode glOrthof(-240, 240, -160, 160, -1, 1); glMatrixMode(GL_MODELVIEW); then my "triangle rendering" code looks like: GLfloat triangle[] = {0, 100, 100, 0, -100, 0,}; glClearColor(0.7, 0.7, 0.7, 1.0); glClear(GL_COLOR_BUFFER_BIT | GL_DEPTH_BUFFER_BIT); glEnableClientState(GL_VERTEX_ARRAY); glColor4f(1.0, 0.0, 0.0, 1.0); glVertexPointer(2, GL_FLOAT, 0, &triangle); glDrawArrays(GL_TRIANGLES, 0, 6); glDisableClientState(GL_VERTEX_ARRAY); This draws a red triangle in the middle of the screen, when I try to apply gluLookAt ( I got the implementation of the function from Cocos2D so I asume it's correct ), i do: glMatrixMode(GL_MODELVIEW); glLoadIdentity(); gluLookAt(0,0,1,0,0,0,0,0,1); // try to move the camera a bit ? GLfloat triangle[] = {0, 100, 100, 0, -100, 0,}; glClearColor(0.7, 0.7, 0.7, 1.0); glClear(GL_COLOR_BUFFER_BIT | GL_DEPTH_BUFFER_BIT); glEnableClientState(GL_VERTEX_ARRAY); glColor4f(1.0, 0.0, 0.0, 1.0); glVertexPointer(2, GL_FLOAT, 0, &triangle); glDrawArrays(GL_TRIANGLES, 0, 6); glDisableClientState(GL_VERTEX_ARRAY); This leads me to grey screen (glClearColor is grey), I've tried all sort of things and read what I've found about gluLookAt on the net, but no luck :(, if someone could explain me or show me how to move to move the camera in a top-down fashion ( zelda, etc ), I would really appreciate it. Thanks!

    Read the article

  • Eine komplette Virtualisierungslandschaft auf dem eigenen Laptop – So geht’s

    - by Manuel Hossfeld
    Eine komplette Virtualisierungslandschaftauf dem eigenen Laptop – So geht’s Wenn man sich mit dem Virtualisierungsprodukt Oracle VM in der aktuellen Version 3.x näher befassen möchte, bietet es sich natürlich an, eine eigene Umgebung zu Lern- und Testzwecken zu installieren. Doch leichter gesagt als getan: Bei näherer Betrachtung der Architektur wird man schnell feststellen, dass mehrere Rechner benötigt werden, um überhaupt alle Komponenten abbilden zu können: Zum einen gilt es, den oder die OVM Server selbst zu installieren. Das ist recht leicht und schnell erledigt, aber da Oracle VM ein „Typ 1 Hypervisor ist“ - also direkt auf dem Rechner („bare metal“) installiert wird – ist der eigenen Arbeits-PC oder Laptop dafür recht ungeeignet. (Eine Dual-Boot Umgebung wäre zwar denkbar, aber recht unpraktisch.) Zum anderen wird auch ein Rechner benötigt, auf dem der OVM Manager installiert wird. Im Gegensatz zum OVM Server erfolgt dessen Installation nicht „bare metal“, sondern auf einem bestehenden Oracle Linux. Aber was tun, wenn man gerade keinen Linux-Server griffbereit hat und auch keine extra Hardware dafür opfern will? Möchte man alle Funktionen von Oracle VM austesten, so sollte man zusätzlich über einen Shared Storag everüfugen. Dieser kann wahlweise über NFS oder über ein SAN (per iSCSI oder FibreChannel) angebunden werden. Zwar braucht man zum Testen nicht zwingend entsprechende „echte“ Storage-Hardware, aber auch die „Simulation“ entsprechender Komponenten erfordert zusätzliche Hardware mit entsprechendem freien Plattenplatz.(Alternativ können auch fertige „Software Storage Appliances“ wie z.B. OpenFiler oder FreeNAS verwendet werden). Angenommen, es stehen tatsächlich keine „echte“ Server- und Storage Hardware zur Verfügung, so benötigt man für die oben genannten drei Punkte  drei bzw. vier Rechner (PCs, Laptops...) - je nachdem ob man einen oder zwei OVM Server starten möchte. Erfreulicherweise geht es aber auch mit deutlich weniger Aufwand: Wie bereits kurz im Blogpost anlässlich des letzten OVM-Releases 3.1.1 beschrieben, ist die aktuelle Version in der Lage, selbst vollständig innerhalb von VirtualBox als Gast zu laufen. Wer bei dieser „doppelten Virtualisierung“ nun an das Prinzip der russischen Matroschka-Puppen denkt, liegt genau richtig. Oracle VM VirtualBox stellt dabei gewissermaßen die äußere Hülle dar – und da es sich bei VirtualBox im Gegensatz zu Oracle VM Server um einen „Typ 2 Hypervisor“ handelt, funktioniert dieser Ansatz auch auf einem „normalen“ Arbeits-PC bzw. Laptop, ohne dessen eigentliche Betriebsystem komplett zu überschreiben. Doch das beste dabei ist: Die Installation der jeweiligen VirtualBox VMs muss man nicht selber durchführen. Der OVM Manager als auch der OVM Server stehen bereits als vorgefertigte „VirtualBox Appliances“ im Oracle Technology Network zum Download zur Verfügung und müssen im Grunde nur noch importiert und konfiguriert werden. Das folgende Schaubild verdeutlicht das Prinzip: Die dunkelgrünen Bereiche stellen jeweils Instanzen der eben erwähnten VirtualBox Appliances für OVM Server und OVM Manager dar. (Hier im Bild sind zwei OVM Server zu sehen, als Minimum würde natürlich auch einer genügen. Dann können aber viele Features wie z.B. OVM HA nicht ausprobieren werden.) Als cleveren Trick zur Einsparung einer weiteren VM für Storage-Zwecke hat Wim Coekaerts (Senior Vice President of Linux and Virtualization Engineering bei Oracle), der „Erbauer“ der VirtualBox Appliances, die OVM Manager Appliance bereits so vorbereitet, dass diese gleichzeitig als NFS-Share (oder ggf. sogar als iSCSI Target) dienen kann. Dies beschreibt er auch kurz auf seinem Blog. Die hellgrünen Ovale stellen die VMs dar, welche dann innerhalb einer der virtualisierten OVM Server laufen können. Aufgrund der Tatsache, dass durch diese „doppelte Virtualisierung“ die Fähigkeit zur Hardware-Virtualisierung verloren geht, können diese „Nutz-VMs“ demzufolge nur paravirtualisiert sein (PVM). Die hier in blau eingezeichneten Netzwerk-Schnittstellen sind virtuelle Interfaces, welche beliebig innerhalb von VirtualBox eingerichtet werden können. Wer die verschiedenen Netzwerk-Rollen innerhalb von Oracle VM im Detail ausprobieren will, kann hier natürlich auch mehr als zwei dieser Interfaces konfigurieren. Die Vorteile dieser Lösung für Test- und Demozwecke liegen auf der Hand: Mit lediglich einem PC bzw. Laptop auf dem VirtualBox installiert ist, können alle oben genannten Komponenten installiert und genutzt werden – genügend RAM vorausgesetzt. Als Minimum darf hier 8GB gelten. Soll auf der „Host-Umgebung“ (also dem PC auf dem VirtualBox läuft) nebenbei noch gearbeiten werden und/oder mehrere „Nutz-VMs“ in dieser simulierten OVM-Server-Umgebung laufen, empfehlen sich natürlich eher 16GB oder mehr. Da die nötigen Schritte zum Installieren und initialen Konfigurieren der Umgebung ausführlich in einem entsprechenden Paper beschrieben sind, möchte ich im Rest dieses Artikels noch einige zusätzliche Tipps und Details erwähnen, welche einem das Leben etwas leichter machen können: Um möglichst entstpannt und mit zusätzlichen „Sicherheitsnetz“ an die Konfiguration der Umgebung herangehen zu können, empfiehlt es sich, ausgiebigen Gebrauch von der in VirtualBox eingebauten Funktionalität der VM Snapshots zu machen. Dies ermöglicht nicht nur ein Zurücksetzen falls einmal etwas schiefgehen sollte, sondern auch ein beliebiges Wiederholen von bereits absolvierten Teilschritten (z.B. um eine andere Idee oder Variante der Umgebung auszuprobieren). Sowohl bei den gerade erwähnten Snapshots als auch bei den VMs selbst sollte man aussagekräftige Namen verwenden. So ist sichergestellt, dass man nicht durcheinander kommt und auch nach ein paar Wochen noch weiß, welche Umgebung man da eigentlich vor sich hat. Dies beinhaltet auch die genaue Versions- und Buildnr. des jeweiligen OVM-Releases. (Siehe dazu auch folgenden Screenshot.) Weitere Informationen und Details zum aktuellen Zustand sowie Zweck der jeweiligen VMs kann in dem oft übersehenen Beschreibungsfeld hinterlegt werden. Es empfiehlt sich, bereits VOR der Installation einen Notizzettel (oder eine Textdatei) mit den geplanten IP-Adressen und Namen für die VMs zu erstellen. (Nicht vergessen: Auch der Server Pool benötigt eine eigene IP.) Dabei sollte man auch nochmal die tatsächlichen Netzwerke der zu verwendenden Virtualbox-Interfaces prüfen und notieren. Achtung: Es gibt im Rahmen der Installation einige Passworte, die vom Nutzer gesetzt werden können – und solche, die zunächst fest eingestellt sind. Zu letzterem gehört das Passwort für den ovs-agent sowie den root-User auf den OVM Servern, welche beide per Default „ovsroot“ lauten. (Alle weiteren Passwort-Informationen sind in dem „Read me first“ Dokument zu finden, welches auf dem Desktop der OVM Manager VM liegt.) Aufpassen muss man ggf. auch in der initialen „Interview-Phase“ welche die VirtualBox VMs durchlaufen, nachdem sie das erste mal gebootet werden. Zu diesem Zeitpunkt ist nämlich auf jeden Fall noch die amerikanische Tastaturbelegung aktiv, so dass man z.B. besser kein „y“ und „z“ in seinem selbst gewählten Passwort verwendet. Aufgrund der Tatsache, dass wie oben erwähnt der OVM Manager auch gleichzeitig den Shared Storage bereitstellt, sollte darauf geachtet werden, dass dessen VM vor den OVM Server VMs gestartet wird. (Andernfalls „findet“ der dem OVM Server Pool zugrundeliegende Cluster sein sog. „Server Pool File System“ nicht.)

    Read the article

< Previous Page | 3 4 5 6 7 8 9 10 11 12 13 14  | Next Page >