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  • Why does Hibernate 2nd level cache only cache within a session?

    - by Synesso
    Using a named query in our application and with ehcache as the provider, it seems that the query results are tied to the session. Any attempt to access the value from the cache for a second time results in a LazyInitializationException We have set lazy=true for the following mapping because this object is also used by another part of the system which does not require the reference... and we want to keep it lean. <class name="domain.ReferenceAdPoint" table="ad_point" mutable="false" lazy="false"> <cache usage="read-only"/> <id name="code" type="long" column="ad_point_id"> <generator class="assigned" /> </id> <property name="name" column="ad_point_description" type="string"/> <set name="synonyms" table="ad_point_synonym" cascade="all-delete-orphan" lazy="true"> <cache usage="read-only"/> <key column="ad_point_id" /> <element type="string" column="synonym_description" /> </set> </class> <query name="find.adpoints.by.heading">from ReferenceAdPoint adpoint left outer join fetch adpoint.synonyms where adpoint.adPointField.headingCode = ?</query> Here's a snippet from our hibernate.cfg.xml <property name="hibernate.cache.provider_class">net.sf.ehcache.hibernate.SingletonEhCacheProvider</property> <property name="hibernate.cache.use_query_cache">true</property> It doesn't seem to make sense that the cache would be constrained to the session. Why are the cached queries not usable outside of the (relatively short-lived) sessions?

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  • How to initiate chatting between two clients and two clients only, using applets and servlets?

    - by mithun1538
    Hello everyone, I first need to apologize for my earlier questions. (You can check my profile for them)They seemed to ask more questions than give answers. Hence, I am laying down the actual question that started all them absurd questions. I am trying to design a chat applet. Till now, I have coded the applet, servlet and communication between the applet and the servlet. The code in the servlet side is such that I was able to establish chatting between clients using the applets, but the code was more like a broadcast all feature, i.e. all clients would be chatting with each other. That was my first objective when I started designing the chat applet. The second step is chatting between only two specific users, much like any other chat application we have. So this was my idea for it: I create an instance of the servlet that has the 'broadcast-all' code. I then pass the address of this instance to the respective clients. 2 client applets use the address to then chat. Technically the code is 'broadcast-all', but since only 2 clients are connected to it, it gives the chatting between two clients feature. Thus, groups of 2 clients have different instances of the same servlet, and each instance handles chatting between two clients at a max. However, as predicted, the idea didn't materialize! I tried to create an instance of the servlet but the only solution for that was using sessions on the servlet side, and I don't know how to use this session for later communications. I then tried to modify my broadcast-all code. In that code, I was using classes that implemented Observer and Observable interfaces. So the next idea that I got was: Create a new object of the Observable class(say class_1). This object be common to 2 clients. 2 clients that wish to chat will use same object of the class_1. 2 other clients will use a different object of class_1. But the problem here lies with the class that implements the Observer interface(say class_2). Since this has observers monitoring the same type of class, namely class_1, how do I establish an observer monitoring one object of class_1 and another observer monitoring another object of the same class class_1 (Because notifyObservers() would notify all the observers and I can't assign a particular observer to a particular object)? I first decided to ask individual problems, like how to create instances of servlets, using objects of observable and observer and so on in stackoverflow... but I got confused even more. Can anyone give me an idea how to establish chatting between two clients only?(I am using Http and not sockets or RMI). Regards, Mithun. P.S. Thanks to all who replied to my previous (absurd) queries. I should have stated the purpose earlier so that you guys could help me better.

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  • Can I use android.os.* libraries in a standalone project?

    - by medicdave
    I'm trying to develop an external library (not sure if that's the right term) to provide prepackaged functionality in Android projects. Working in Eclipse, I've added the appropriate android.jar file to the build path, and everything is happy both while editing and upon compilation. However, when I use Android's Handler and Message classes (android.os.Handler, android.os.Message) for inter-thread communication, I get exceptions unless I'm running within an Android app, on the emulator or a device. I can no longer test my library in a "standalone" way without having to go through a running Android target. Is there any way for me to include these two Android classes and still be able to test my library standalone? Do I need to have the Android source available? Or would it require some sort of conditional compilation hand-waving?

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  • two threads acting on the same runnable

    - by Eslam
    Given: public class Thread1 { int x = 0; public class Runner implements Runnable { public void run() { int current = 0; for (int i = 0; i < 4; i++) { current = x; System.out.print(current + " "); x = current + 2; } } } public void go() { Runnable r1 = new Runner(); new Thread(r1).start(); new Thread(r1).start(); } public static void main(String[] args) { new Thread1().go(); } } Which two are possible results? (Choose two) A. 0, 2, 4, 4, 6, 8, 10, 6, B. 0, 2, 4, 6, 8, 10, 2, 4, C. 0, 2, 4, 6, 8, 10, 12, 14, D. 0, 0, 2, 2, 4, 4, 6, 6, 8, 8, 10, 10, 12, 12, 14, 14, E. 0, 2, 4, 6, 8, 10, 12, 14, 0, 2, 4, 6, 8, 10, 12, 14, i chosed A,B but i'm not certain is those is the true or not.

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  • Printing is not working in tomcat, when i start server with services.msc(From client side we could not print )

    - by maya
    I am using JasperReports 1.3.1 to print the report. I am sing eclipse and tomcat for development purpose. In eclipse, when i run the application, the below code will show the listed printer devices and print button. If i click the print button, the report is printing by selected device. PrintRequestAttributeSet printRequestAttributeSet = new HashPrintRequestAttributeSet(); printRequestAttributeSet.add(MediaSizeName.ISO_A5); PrintServiceAttributeSet printServiceAttributeSet = new HashPrintServiceAttributeSet(); JRPrintServiceExporter exporter = new JRPrintServiceExporter(); exporter.setParameter(JRExporterParameter.JASPER_PRINT, jasperPrint); exporter.setParameter(JRPrintServiceExporterParameter.PRINT_REQUEST_ATTRIBUTE_SET, printRequestAttributeSet); exporter.setParameter(JRPrintServiceExporterParameter.PRINT_SERVICE_ATTRIBUTE_SET, printServiceAttributeSet); exporter.setParameter(JRPrintServiceExporterParameter.DISPLAY_PAGE_DIALOG, Boolean.FALSE); exporter.setParameter(JRPrintServiceExporterParameter.DISPLAY_PRINT_DIALOG, Boolean.TRUE); exporter.exportReport(); Here I am passing jasperPrint as a parameter which i manually construted.Its working good My problem is: I created war file and pasted in tomcat Apache Software Foundation\Tomcat 6.0\webapps directory and started the tomcat by using services.msc. At this point, its not displaying the listed printer details and also not printing. I put some logger, I found that, the code is hanging with exporter.exportReport(); after this line code is not executing . Please suggest me for how to print from client side using jasper

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  • How can I get the size?

    - by Sanju
    I got a class. Lets say its named Class1 Here I create another class, Class2 Class2 has an arrya[] No my question is. When I create Class2 I cant have any size of the array with me in. How can I then know how big I want the array to be??? Out in Class1 I know how big it is. Thanks in Advance.

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  • Paypal - DoExpressCheckoutPayment null pointer

    - by user969894
    String nvpstr = "&TOKEN=" + token + "&PAYERID=" + payerID + "&PAYMENTREQUEST_0_PAYMENTACTION=" + paymentType + "&PAYMENTREQUEST_0_AMT=" + finalPaymentAmount + "&PAYMENTREQUEST_0_CURRENCYCODE=" + currencyCodeType + "&IPADDRESS=" + serverName; Having done an earlier call to SetExpressCheckout, I had to change a few parameter names because Paypal had changed it in the documentation but not in the code from the integration wizard. Now for DoExpressCheckoutPayment I've modified a few but I get a null pointer at strAck: HashMap nvp = httpcall("DoExpressCheckoutPayment", nvpstr); String strAck = nvp.get("ACK").toString(); if (strAck.equalsIgnoreCase("Success")) { return nvp; } Not sure what is wrong, any suggestions for debugging this or possible solutions?

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  • How to replace a regexp group with a post proceed value?

    - by Pentium10
    I have this code to public static String ProcessTemplateInput(String input, int count) { Pattern pattern = Pattern.compile("\\{([^\\}]+)\\}"); Matcher matcher = pattern.matcher(input); while (matcher.find()) { String newelem=SelectRandomFromTemplate(matcher.group(1), count); } return input; } Input is: String s1 = "planets {Sun|Mercury|Venus|Earth|Mars|Jupiter|Saturn|Uranus|Neptune}{?|!|.} Is this ok? "; Output example: String s2="planets Sun, Mercury. Is this ok? "; I would like to replace the {} set of templates with the picked value returned by the method. How do I do that in Java1.5?

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  • Any way of working with Eclipse WTP that does not mean redeploying the _WHOLE_ application when a J

    - by Thorbjørn Ravn Andersen
    I have migrated a Web Application from MyEclipse to Eclipse WTP, and I am now in the middle of the first major upgrade to the code base and web pages after the migration, and it is frankly driving me mad that saving a JSP page causes a redeployment of the WHOLE application, as it takes time and that my backend connection does not survive the serialization-deserialization of the session object (which is non-trivial to fix). In addition to that the JSP-editor is insanely slow so I frequently have to pause to let the editor catch up to be certain where my edits go in a small JSP using JavaServer Faces. Disabling validation did not help. The Eclipse Dynamic Web Project depends on several library eclipse projects so I cannot just tell e.g. Jetty to use the WebRoot folder, as several dependencies are then missing from the classpath. The question is: Is there a way of working - ANY way of working - with the Eclipse WTP system that does NOT imply redeploying everything every time any file is saved? I can use Tomcat 5.5 or Jetty 6 as servers.

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  • Websphere 6.1, Datasource, two apps

    - by asrijaal
    Hi, I've got a webapp running on a Websphere 6.1 Server which JNDI lookups for a datasource. This webapp runs fine, the Websphere server recognizes the datasource ref in the web.xml etc.. Now we added a second webapp which should use this datasource with same configuration but I only getting a NULL Object when I invoke my JNDI lookup and a ClassCastException is thrown (which is correct). Maybe one of you has some suggestions?

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  • Deploy maven generated site on Google Code svn?

    - by xamde
    Using a google code svn as a basic maven repository is easy. However, using mvn site:deploy efficiently on google code seems hard. So far, I found only these solutions: * Deploy to a local file:/// and use a PERL script to delete the old and copy the new * Use wagen-svn to deploy. This is very slow (hours!) and does not delete old files * Plus all mime-types are wrong I am looking for a solution that allows new developers in my projects to check out the current source and just use it, without requiring to install PERL or learn weird steps to perform or wait hours.

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  • How do I prevent JAXB from binding superclass methods of the @XmlRootElement when marshalling?

    - by Matt Fisher
    I have a class that is annotated as the @XmlRootElement with @XmlAccessorType(XmlAccessType.NONE). The problem that I am having is that the superclass's methods are being bound, when I do not want them to be bound, and cannot update the class. I am hoping there is an annotation that I can put on the root element class to prevent this from happening. Example: @XmlRootElement @XmlAccessorType(XmlAccessType.NONE) public class Person extends NamedObject { @XmlElement public String getId() { ... } } I would expect that only the methods annotated @XmlElement on Person would be bound and marshalled, but the superclass's methods are all being bound, as well. The resulting XML then has too much information. How do I prevent the superclass's methods from being bound without having to annotate the superclass, itself?

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  • Modelling a manyToMany relationship with attributes

    - by Javi
    Hello, I have a ManyToMany relationship between two classes, for instance class Customer and class Item. A customer can buy several items and an item can be bought by different customers. I need to store extra information in this relationship, for example the day when the item was bought. I wonder how is this usually modelled in JPA, cause I'm not sure how to express this in code. Do I have to create a new class to model all the attributes of the relationship and make a manyToMany relationship between the other classes or is a better way to do this? Thanks

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  • Possible to split one JAX-WS service across multiple source files?

    - by Rob S.
    Hi everyone, Is it possible to split a web service in to multiple classes and still provide a single path to the web service? I know this isn't possible because of the duplicate url-pattern values. It sort of illustrates where we're wanting to go :) <endpoint name="OneBigService" implementation="SmallImpl1" url-pattern="/OneBigService"/> <endpoint name="OneBigService" implementation="SmallImpl2" url-pattern="/OneBigService"/> Basically, how do avoid having one monolithic @WebService class? Thanks! Rob

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  • Using ControllerClassNameHandlerMapping with @Controller and extending AbstractController

    - by whiskerz
    Hey there, actually I thought I was trying something really simple. ControllerClassNameHandlerMapping sounded great to produce a small spring webapp using a very lean configuration. Just annotate the Controller with @Controller, have it extend AbstractController and the configuration shouldn't need more than this <context:component-scan base-package="test.mypackage.controller" /> <bean id="urlMapping" class="org.springframework.web.servlet.mvc.support.ControllerClassNameHandlerMapping" /> to resolve my requests and map them to my controllers. I've mapped the servlet to "*.spring", and calling <approot>/hello.spring All I ever get is an error stating that no mapping was found. If however I extend the MultiActionController, and do something like <approot>/hello/hello.spring it works. Which somehow irritates me, as I would have thought that if that is working, why didn't my first try? Does anyone have any idea? The two controllers I used looked like this @Controller public class HelloController extends AbstractController { @Override protected ModelAndView handleRequestInternal(HttpServletRequest request, HttpServletResponse response) throws Exception { ModelAndView modelAndView = new ModelAndView("hello"); modelAndView.addObject("message", "Hello World!"); return modelAndView; } } and @Controller public class HelloController extends MultiActionController { public ModelAndView hello(HttpServletRequest request, HttpServletResponse response) throws Exception { ModelAndView modelAndView = new ModelAndView("hello"); modelAndView.addObject("message", "Hello World!"); return modelAndView; } }

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  • Importing hibernate configuration file into Spring applicationContext

    - by Himanshu Yadav
    I am trying to integrate Hibernate 3 with Spring 3.1.0. The problem is that application is not able to find mapping file which declared in hibernate.cfg.xml file. Initially hibernate configuration has datasource configuration, hibernate properties and mapping hbm.xml files. Master hibernate.cfg.xml file exist in src folder. this is how Master file looks: <hibernate-configuration> <session-factory> <!-- Mappings --> <mapping resource="com/test/class1.hbm.xml"/> <mapping resource="/class2.hbm.xml"/> <mapping resource="com/test/class3.hbm.xml"/> <mapping resource="com/test/class4.hbm.xml"/> <mapping resource="com/test/class5.hbm.xml"/> Spring config is: <bean id="sessionFactoryEditSolution" class="org.springframework.orm.hibernate3.LocalSessionFactoryBean"> <property name="dataSource" ref="data1"/> <property name="mappingResources"> <list> <value>/master.hibernate.cfg.xml</value> </list> </property> <property name="hibernateProperties"> <props> <prop key="hibernate.dialect">org.hibernate.dialect.SQLServerDialect</prop> <prop key="hibernate.cache.use_second_level_cache">true</prop> </props> </property> </bean>

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  • Adding exclusive filter for <static initializer> in findbugs

    - by MilanAleksic
    Hi all, I want my findbugs report not show the following error: DM_NUMBER_CTOR: Method invokes inefficient Number constructor; use static valueOf instead The problem is that this happens in groovy-generated code files, so I can't control the source code - that is why I want to exclude it and add it to my exclude filter. I do not want to add explicitly class (since I make API that many tools will use, I want my filter to be generic). I would not like to completely remove this bug from the report by type, I would really like to only exclude this bug from appearing if it happenned in "static initializer" methods. Any idea? I tried the filter below but no luck, maybe somebody has better idea? <Match> <Method name="~.*static initializer.*" /> <Bug pattern="DM_NUMBER_CTOR" /> </Match> Here is the "stacktrace" of FindBugs in that case: In class net.milanaleksic.cuc.tools.sound.SoundPlayerTool In method net.milanaleksic.cuc.tools.sound.SoundPlayerTool.() Called method new Long(long) Should call Long.valueOf(long) instead In SoundPlayerTool.groovy

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  • Exception when indexing text documents with Lucene, using SnowballAnalyzer for cleaning up

    - by Julia
    Hello!!! I am indexing the documents with Lucene and am trying to apply the SnowballAnalyzer for punctuation and stopword removal from text .. I keep getting the following error :( IllegalAccessError: tried to access method org.apache.lucene.analysis.Tokenizer.(Ljava/io/Reader;)V from class org.apache.lucene.analysis.snowball.SnowballAnalyzer Here is the code, I would very much appreciate help!!!! I am new with this.. public class Indexer { private Indexer(){}; private String[] stopWords = {....}; private String indexName; private IndexWriter iWriter; private static String FILES_TO_INDEX = "/Users/ssi/forindexing"; public static void main(String[] args) throws Exception { Indexer m = new Indexer(); m.index("./newindex"); } public void index(String indexName) throws Exception { this.indexName = indexName; final File docDir = new File(FILES_TO_INDEX); if(!docDir.exists() || !docDir.canRead()){ System.err.println("Something wrong... " + docDir.getPath()); System.exit(1); } Date start = new Date(); PerFieldAnalyzerWrapper analyzers = new PerFieldAnalyzerWrapper(new SimpleAnalyzer()); analyzers.addAnalyzer("text", new SnowballAnalyzer("English", stopWords)); Directory directory = FSDirectory.open(new File(this.indexName)); IndexWriter.MaxFieldLength maxLength = IndexWriter.MaxFieldLength.UNLIMITED; iWriter = new IndexWriter(directory, analyzers, true, maxLength); System.out.println("Indexing to dir..........." + indexName); if(docDir.isDirectory()){ File[] files = docDir.listFiles(); if(files != null){ for (int i = 0; i < files.length; i++) { try { indexDocument(files[i]); }catch (FileNotFoundException fnfe){ fnfe.printStackTrace(); } } } } System.out.println("Optimizing...... "); iWriter.optimize(); iWriter.close(); Date end = new Date(); System.out.println("Time to index was" + (end.getTime()-start.getTime()) + "miliseconds"); } private void indexDocument(File someDoc) throws IOException { Document doc = new Document(); Field name = new Field("name", someDoc.getName(), Field.Store.YES, Field.Index.ANALYZED); Field text = new Field("text", new FileReader(someDoc), Field.TermVector.WITH_POSITIONS_OFFSETS); doc.add(name); doc.add(text); iWriter.addDocument(doc); } }

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  • Getting hibernate to log clob parameters

    - by SCdF
    (see here for the problem I'm trying to solve) How do you get hibernate to log clob values it's going to insert. It is logging other value types, such as Integer etc. I have the following in my log4j config: log4j.logger.net.sf.hibernate.SQL=DEBUG log4j.logger.org.hibernate.SQL=DEBUG log4j.logger.net.sf.hibernate.type=DEBUG log4j.logger.org.hibernate.type=DEBUG Which produces output such as: (org.hibernate.SQL) insert into NoteSubstitutions (note, listIndex, substitution) values (?, ?, ?) (org.hibernate.type.LongType) binding '170650' to parameter: 1 (org.hibernate.type.IntegerType) binding '0' to parameter: 2 (org.hibernate.SQL) insert into NoteSubstitutions (note, listIndex, substitution) values (?, ?, ?) (org.hibernate.type.LongType) binding '170650' to parameter: 1 (org.hibernate.type.IntegerType) binding '1' to parameter: 2 However you'll note that it never displays parameter: 3 which is our clob. What I would really want is something like: (org.hibernate.SQL) insert into NoteSubstitutions (note, listIndex, substitution) values (?, ?, ?) (org.hibernate.type.LongType) binding '170650' to parameter: 1 (org.hibernate.type.IntegerType) binding '0' to parameter: 2 (org.hibernate.type.ClobType) binding 'something' to parameter: 3 (org.hibernate.SQL) insert into NoteSubstitutions (note, listIndex, substitution) values (?, ?, ?) (org.hibernate.type.LongType) binding '170650' to parameter: 1 (org.hibernate.type.IntegerType) binding '1' to parameter: 2 (org.hibernate.type.ClobType) binding 'something else' to parameter: 3 How do I get it to show this in the log?

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  • How can you write a function that accepts multiple types?

    - by matthy
    I have a function that should work on int[] and on String[] now i have made the same function with a int parameter and an String parameter however if it has to go this way its a bit copy paste work and doesn't look very organized is there a way to solve this and put these 4 functions in 2? static public void print(String s) { System.out.println(s); } static public void print(int s) { System.out.println(s); } static public void printArray(String[] s) { for (int i=0; i<s.length; i++) print(s[i]); } static public void printArray(int[] s) { for (int i=0; i<s.length; i++) print(s[i]); } Thanks Matthy

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  • How to parse json with fromJson method

    - by Ankit HTech
    I want to parse my json by fromJson class but I am unable to understand what should be the structure of my class if my json is like below: String json = "{"Result":{"Status":"SUCCESS","Message":""},"Response":{"Token":"ca0d7507-3907-4eed-af19-ad256bc71088","ZoneUrl":"https:\/\/qa.tritononline.com\/","CustomerID":1,"UserID":29,"DefaultLanguageID":1,"ZoneID":1,"IsTritonIntegrated":false,"Language":[{"LanguageId":1,"Language":"English","IsSelected":false}]}}" This is what I want to do Response res = new Response(); Gson gson = new Gson(); res = gson.fromJson(json, Response.class); I want to know what all variable should I take in Response class.

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