Search Results

Search found 32961 results on 1319 pages for 'java'.

Page 774/1319 | < Previous Page | 770 771 772 773 774 775 776 777 778 779 780 781  | Next Page >

  • How do I correctly decode unicode parameters passed to a servlet

    - by Grant Wagner
    Suppose I have: <a href="http://www.yahoo.com/" target="_yahoo" title="Yahoo!&#8482;" onclick="return gateway(this);">Yahoo!</a> <script type="text/javascript"> function gateway(lnk) { window.open(SERVLET + '?external_link=' + encodeURIComponent(lnk.href) + '&external_target=' + encodeURIComponent(lnk.target) + '&external_title=' + encodeURIComponent(lnk.title)); return false; } </script> I have confirmed external_title gets encoded as Yahoo!%E2%84%A2 and passed to SERVLET. If in SERVLET I do: Writer writer = response.getWriter(); writer.write(request.getParameter("external_title")); I get Yahoo!â„¢ in the browser. If I manually switch the browser character encoding to UTF-8, it changes to Yahoo!TM (which is what I want). So I figured the encoding I was sending to the browser was wrong (it was Content-type: text/html; charset=ISO-8859-1). I changed SERVLET to: response.setContentType("text/html; charset=utf-8"); Writer writer = response.getWriter(); writer.write(request.getParameter("external_title")); Now the browser character encoding is UTF-8, but it outputs Yahoo!â?¢ and I can't get the browser to render the correct character at all. My question is: is there some combination of Content-type and/or new String(request.getParameter("external_title").getBytes(), "UTF-8"); and/or something else that will result in Yahoo!TM appearing in the SERVLET output?

    Read the article

  • [Java2D] Is this bad practice? Multiple Graphics2D Objects

    - by m00st
    I've created a JPanel canvas that holds all graphics; namely JLabel. To get animated sprites to work you have to over ride the paintComponent of the extended JLabel class. I've successfully implemented animated sprites this way. Is it bad practice to have a Graphics2D canvas and then have multiple 'images' in their own Graphics2D?

    Read the article

  • How to verify if the private key matches with the certificate..?

    - by surendhar_s
    I have the private key stored as .key file.. -----BEGIN RSA PRIVATE KEY----- MIICXAIBAAKBgQD5YBS6V3APdgqaWAkijIUHRK4KQ6eChSaRWaw9L/4u8o3T1s8J rUFHQhcIo5LPaQ4BrIuzHS8yzZf0m3viCTdZAiDn1ZjC2koquJ53rfDzqYxZFrId 7a4QYUCvM0gqx5nQ+lw1KoY/CDAoZN+sO7IJ4WkMg5XbgTWlSLBeBg0gMwIDAQAB AoGASKDKCKdUlLwtRFxldLF2QPKouYaQr7u1ytlSB5QFtIih89N5Avl5rJY7/SEe rdeL48LsAON8DpDAM9Zg0ykZ+/gsYI/C8b5Ch3QVgU9m50j9q8pVT04EOCYmsFi0 DBnwNBRLDESvm1p6NqKEc7zO9zjABgBvwL+loEVa1JFcp5ECQQD9/sekGTzzvKa5 SSVQOZmbwttPBjD44KRKi6LC7rQahM1PDqmCwPFgMVpRZL6dViBzYyWeWxN08Fuv p+sIwwLrAkEA+1f3VnSgIduzF9McMfZoNIkkZongcDAzjQ8sIHXwwTklkZcCqn69 qTVPmhyEDA/dJeAK3GhalcSqOFRFEC812QJAXStgQCmh2iaRYdYbAdqfJivMFqjG vgRpP48JHUhCeJfOV/mg5H2yDP8Nil3SLhSxwqHT4sq10Gd6umx2IrimEQJAFNA1 ACjKNeOOkhN+SzjfajJNHFyghEnJiw3NlqaNmEKWNNcvdlTmecObYuSnnqQVqRRD cfsGPU661c1MpslyCQJBAPqN0VXRMwfU29a3Ve0TF4Aiu1iq88aIPHsT3GKVURpO XNatMFINBW8ywN5euu8oYaeeKdrVSMW415a5+XEzEBY= -----END RSA PRIVATE KEY----- And i extracted public key from ssl certificate file.. Below is the code i tried to verify if private key matches with ssl certificate or not.. I used the modulus[i.e. private key get modulus==public key get modulus] to check if they are matching.. And this seems to hold only for RSAKEYS.. But i want to check for other keys as well.. Is there any other alternative to do the same..?? private static boolean verifySignature(File serverCertificateFile, File serverCertificateKey) { try { byte[] certificateBytes = FileUtils.readFileToByteArray(serverCertificateFile); //byte[] keyBytes = FileUtils.readFileToByteArray(serverCertificateKey); RandomAccessFile raf = new RandomAccessFile(serverCertificateKey, "r"); byte[] buf = new byte[(int) raf.length()]; raf.readFully(buf); raf.close(); PKCS8EncodedKeySpec kspec = new PKCS8EncodedKeySpec(buf); KeyFactory kf; try { kf = KeyFactory.getInstance("RSA"); RSAPrivateKey privKey = (RSAPrivateKey) kf.generatePrivate(kspec); CertificateFactory certFactory = CertificateFactory.getInstance("X.509"); InputStream in = new ByteArrayInputStream(certificateBytes); //Generate Certificate in X509 Format X509Certificate cert = (X509Certificate) certFactory.generateCertificate(in); RSAPublicKey publicKey = (RSAPublicKey) cert.getPublicKey(); in.close(); return privKey.getModulus() == publicKey.getModulus(); } catch (NoSuchAlgorithmException ex) { logger.log(Level.SEVERE, "Such algorithm is not found", ex); } catch (CertificateException ex) { logger.log(Level.SEVERE, "certificate exception", ex); } catch (InvalidKeySpecException ex) { Logger.getLogger(CertificateConversion.class.getName()).log(Level.SEVERE, null, ex); } } catch (IOException ex) { logger.log(Level.SEVERE, "Signature verification failed.. This could be because the file is in use", ex); } return false; } And the code isn't working either.. throws invalidkeyspec exception

    Read the article

  • Show/hide views with checkbox

    - by DixieFlatline
    Hi! I want to show or hide some elements (textviews and edittexts) with checkbox. I set their visibility to gone in layout file. Showing them when user checks the box works, but the when user unchecks it, they don't hide. (android 1.5 and 1.6) My code: cb=(CheckBox)findViewById(R.id.cek); cb.setOnClickListener(new OnClickListener() { // checkbox listener public void onClick(View v) { // Perform action on clicks, depending on whether it's now checked if (((CheckBox) v).isChecked()) { tv1.setVisibility(0); //visible==0 et3.setVisibility(0); } else if (((CheckBox) v).isChecked() == false) { tv1.setVisibility(2); //gone=2 et3.setVisibility(2); } } });

    Read the article

  • Hibernate query for multiple items in a collection

    - by aarestad
    I have a data model that looks something like this: public class Item { private List<ItemAttribute> attributes; // other stuff } public class ItemAttribute { private String name; private String value; } (this obviously simplifies away a lot of the extraneous stuff) What I want to do is create a query to ask for all Items with one OR MORE particular attributes, ideally joined with arbitrary ANDs and ORs. Right now I'm keeping it simple and just trying to implement the AND case. In pseudo-SQL (or pseudo-HQL if you would), it would be something like: select all items where attributes contains(ItemAttribute(name="foo1", value="bar1")) AND attributes contains(ItemAttribute(name="foo2", value="bar2")) The examples in the Hibernate docs didn't seem to address this particular use case, but it seems like a fairly common one. The disjunction case would also be useful, especially so I could specify a list of possible values, i.e. where attributes contains(ItemAttribute(name="foo", value="bar1")) OR attributes contains(ItemAttribute(name="foo", value="bar2")) -- etc. Here's an example that works OK for a single attribute: return getSession().createCriteria(Item.class) .createAlias("itemAttributes", "ia") .add(Restrictions.conjunction() .add(Restrictions.eq("ia.name", "foo")) .add(Restrictions.eq("ia.attributeValue", "bar"))) .list(); Learning how to do this would go a long ways towards expanding my understanding of Hibernate's potential. :)

    Read the article

  • Element to string in HTMLDocument

    - by kalpesh
    i have a Element object its a HTMLDocument object and i want to string value of this element. i want this result Christina Toth, Pharm. D. ======================= plz see below code. public static void main(String args[]) throws Exception { InputStream is = Nullsoft.getInputStream(); InputStreamReader isr = new InputStreamReader(is); BufferedReader br = new BufferedReader(isr); HTMLEditorKit htmlKit = new HTMLEditorKit(); HTMLDocument htmlDoc = (HTMLDocument) htmlKit.createDefaultDocument(); HTMLEditorKit.Parser parser = new ParserDelegator(); HTMLEditorKit.ParserCallback callback = htmlDoc.getReader(0); parser.parse(br, callback, true); // Parse ElementIterator iterator = new ElementIterator(htmlDoc); Element element; while ((element = iterator.next()) != null) { AttributeSet attributes = element.getAttributes(); Object name = attributes.getAttribute(StyleConstants.NameAttribute); if ((name instanceof HTML.Tag) && ((name == HTML.Tag.DIV) || (name == HTML.Tag.H2) || (name == HTML.Tag.H3))) { StringBuffer text = new StringBuffer(); int count = element.getElementCount(); for (int i = 0; i < count; i++) { Element child = element.getElement(i); AttributeSet childAttributes = child.getAttributes(); // if (childAttributes.getAttribute(StyleConstants.NameAttribute) == HTML.Tag.CONTENT) { int startOffset = child.getStartOffset(); int endOffset = child.getEndOffset(); int length = endOffset - startOffset; text.append(htmlDoc.getText(startOffset, length)); } } System.out.println(name + ": " + text.toString()); } } System.exit(0); } public static InputStream getInputStream() { String text = "<html>\n" + "<head>\n" + "<title>pg_0001</title>\n" + "\n" + "<style type=\"text/css\">\n" + ".ft3{font-style:normal;font-weight:bold;font-size:11px;font-family:Helvetica;color:#000000;}\n" + "</style>\n" + "</head>\n" + "<body vlink=\"#FFFFFF\" link=\"#FFFFFF\" bgcolor=\"#ffffff\">\n" + "\n" + "\n" + "<div style=\"position:absolute;top:597;left:252\"><nobr><span class=\"ft3\">Christina Toth, Pharm. D.</span></nobr></div>\n" + "\n" + "\n" + "</body>\n" + "</html>"; InputStream is = null; try { is = new ByteArrayInputStream(text.getBytes("UTF-8")); } catch (UnsupportedEncodingException e) { e.printStackTrace(); } return is; }

    Read the article

  • jsp get ip address

    - by Alan
    Hello, whats the best way of preventing someone from voting twice? How do i get the users ip address? What if they are on a large network? will everyone on that network show the same ip? thanks UPDATE: request.getRemoteAddr() and request.getRemoteHost() return the Server names, not the client's host name and ip. Anyone else got any bright ideas? Ok, so lets forget about the voting twice thing. Im just trying to get the users ip address? i tried request.getRemoteAddr() and request.getRemoteHost() and think im getting the servers address. I have access to two separate networks and am getting the same IP address :(

    Read the article

  • Is it better to use List or Collection?

    - by Vivin Paliath
    I have an object that stores some data in a list. The implementation could change later, and I don't want to expose the internal implementation to the end user. However, the user must have the ability to modify and access this collection of data. Currently I have something like this: public List<SomeDataType> getData() { return this.data; } public void setData(List<SomeDataType> data) { this.data = data; } Does this mean that I have allowed the internal implementation details to leak out? Should I be doing this instead? public Collection<SomeDataType> getData() { return this.data; } public void setData(Collection<SomeDataType> data) { this.data = new ArrayList<SomeDataType>(data); }

    Read the article

  • Eclipse won't believe I have Maven 2.2.1

    - by Andrew Clegg
    I have a project (built from an AppFuse template) that requires Maven 2.2.1. So I upgraded to this (from 2.1.0) and set my path and my M2_HOME and MAVEN_HOME env variables. Then I ran mvn eclipse:eclipse and imported the project into Eclipse (Galileo). However, in the problems list for the project (and at the top of the pom.xml GUI editor) it says: Unable to build project '/export/people/clegg/data/GanymedeWorkspace/funcserve/pom.xml; it requires Maven version 2.2.1 (Please ignore 'GanymedeWorkspace', I really am using Galileo!) This persists whether I set Eclipse to use its Embedded Maven implementation, or the external 2.2.1 installation, in the Preferences - Maven - Installations dialog. I've tried closing and reopening the project, reindexing the repository, cleaning the project, restarting the IDE, logging out and back in again, everything I can think of! But Eclipse still won't believe I have Maven 2.2.1. I just did a plugin update so I have the latest version of Maven Integration for Eclipse -- 0.9.8.200905041414. Does anyone know how to convince Eclipse I really do have the right version of Maven? It's like it's recorded the previous version somewhere else and won't pay any attention to my changes :-( Many thanks! Andrew.

    Read the article

  • PHP Programmer wanting to learn Spring

    - by grokker
    I'm a PHP programmer and I want to try creating a webapp using the Spring framework. The problem is I'm clueless and I don't know where to start. What tutorials/books/websites do you guys suggest that I should learn from? What's IoC? Do I use it alongside MVC? What components of the Spring framework should I use? How do I know what to use? Are there webapps created with Spring that I could study from? Thank you so much in advance! P.S. I've used Struts (1) about a year ago.

    Read the article

  • Custom Classes Passed from Service to a UI threads via AIDL

    - by Honza Pokorny
    I have a service that regularly queries a web server for new messages. The service stores the new messages in an arrayList. These messages are implemented using a custom class, storing all kinds of metadata (strings and longs). An activity then connects to this service to retrieve those messages and display them to the user. I have an .aidl file that describes the interface that the service exposes. package com.example.package; interface MyInterface { List<Message> getMessages(); } The Message class extends the Parcelable class which should allow for the IPC transfer. The problem is this: Eclipse gives me an error saying that the type of List<Message> is unknown. Any imports are marked as invalid. Ideas? Thanks

    Read the article

  • I have a problem with a4j:commandButton and a reredering ...

    - by ollie314
    The code below show whiche thing that is failing in my appliaction. It is a quick add information form, fill out the form and submit it add a new entry into a database and synchronize my a databasle.. This is all done with ajax. The first form submission happens correctly but the second one fails to run the desired ActionListener. The second form is posting to the server though but the saveAction isn't invoke. As you will see, I'm a real beginner with this technologies ... If someone see the problem, it will be very helpfull !! <rich:simpleTogglePanel id="quickaddActivitySimpleToogle" switchType="client" opened="false" label="#{lang.activityModule_quickAdd_panelTitle}"> <p><a4j:form id="quickAddForm"> <h:outputLabel for="activityNameInput" value="#{lang.activity_name_dp}" /> <h:inputText id="activityNameInput" value="#{activityController.quickActivityAdd.name}"> </h:inputText> <rich:spacer width="20px" /> <h:inputHidden id="activityInternalNameInput" value="#{activityController.quickActivityAdd.internalName}" /> <rich:spacer width="20px" /> <a4j:commandButton id="activityQuickAddFormSubmitBtn" reRender="activityListTable,quickAddForm" actionListener="#{activityController.saveActivity}" value="#{lang.saveBtn_header}" /> </a4j:form></p></rich:simpleTogglePanel> Thanks in advanced. ollie314

    Read the article

  • SWT Filedialog Open into home folder

    - by Ivan
    I want to open a FileDialog window into the user home folder (i.e. /home/user or /Users/unsername) I read the user home folder, using System.getProperty: String homefolder = System.getProperty(user.home); And the variable containts the correct home folder. But when i set the filterpath in FileDialog, it opens (in linux) only the /home level not entering into the user home dir. This is the source code: FileDialog dialog = new FileDialog(shell); dialog.setText("Choose a certificate"); String platform = SWT.getPlatform(); String homefolder = System.getProperty("user.home"); dialog.setFilterPath(homefolder); Any idea? Here a screenshot:

    Read the article

  • Using UNINSTALL_SHORTCUT Intent

    - by Lucas S.
    I am trying to use the following intent action, but i get an ActivityNotFoundException in the fisrt case. And nothing at all in the second case. "com.android.launcher.action.UNINSTALL_SHORTCUT" I try to use it with the following code: Intent i = new Intent ("com.android.launcher.action.UNINSTALL_SHORTCUT"); startActivity(i); Also with the following: Intent i = new Intent ("com.android.launcher.action.UNINSTALL_SHORTCUT"); sendBroadCast(i);

    Read the article

  • Putting Select Statement on Hibernate Transaction

    - by Mark Estrada
    Hi All, I have been reading the net for a while regarding Hibernate but I can seem to understand one concept regarding Transaction. On some site that I have visit, Select statements are in transaction mode like this. public List<Book> readAll() { Session session = HibernateUtil.getSessionFactory() .getCurrentSession(); session.beginTransaction(); List<Book> booksList = session.createQuery("from Book").list(); session.getTransaction().commit(); return booksList; } While on some site, it does not advocate the use of transaction on Select statements public List<Book> readAll() { Session session = HibernateUtil.getSessionFactory() .getCurrentSession(); List<Book> booksList = session.createQuery("from Book").list(); return booksList; } I am thinking which one should I follow. Any thoughts please? Are transactions needed on Select Statements or not? Thanks

    Read the article

  • Why does Hibernate 2nd level cache only cache within a session?

    - by Synesso
    Using a named query in our application and with ehcache as the provider, it seems that the query results are tied to the session. Any attempt to access the value from the cache for a second time results in a LazyInitializationException We have set lazy=true for the following mapping because this object is also used by another part of the system which does not require the reference... and we want to keep it lean. <class name="domain.ReferenceAdPoint" table="ad_point" mutable="false" lazy="false"> <cache usage="read-only"/> <id name="code" type="long" column="ad_point_id"> <generator class="assigned" /> </id> <property name="name" column="ad_point_description" type="string"/> <set name="synonyms" table="ad_point_synonym" cascade="all-delete-orphan" lazy="true"> <cache usage="read-only"/> <key column="ad_point_id" /> <element type="string" column="synonym_description" /> </set> </class> <query name="find.adpoints.by.heading">from ReferenceAdPoint adpoint left outer join fetch adpoint.synonyms where adpoint.adPointField.headingCode = ?</query> Here's a snippet from our hibernate.cfg.xml <property name="hibernate.cache.provider_class">net.sf.ehcache.hibernate.SingletonEhCacheProvider</property> <property name="hibernate.cache.use_query_cache">true</property> It doesn't seem to make sense that the cache would be constrained to the session. Why are the cached queries not usable outside of the (relatively short-lived) sessions?

    Read the article

  • Axis webservice calls fail sometimes, access.log shows content!

    - by epischel
    Hi, our app is a webservice client (axis 1) to a third party webservice (also axis 1). We use it for some years now. Since a few weeks, we (as a client) get sometimes HTTP status 400 (bad request) or read timeouts when calling the webservice. Strangely, the access.log of the service shows part of the request or the response instead of the URL. It looks like this (looks like the end of the request string) x.x.x.x -> y.y.y.y:8080 - - [timestamp] "POST /webservice HTTP/1.0" 200 16127 0 x.x.x.x -> y.y.y.y:8080 - - [timestamp] "POST /webservice HTTP/1.0" 200 22511 1 x.x.x.x -> y.y.y.y:8080 - - [timestamp] "il=\"true\"/><nsl:text xsi:type=\"xsd:string\" xsi:nil=\"true\"/></SOAPSomeOperation></soapenv:Body></soapenv:Envelope> Axis/1.4" 400 299 0 or (some string out of the what looks like the request) x.x.x.x -> y.y.y.y:8080 - - [timestamp] ":string\">some text</sometag><othertag>moretext" 400 299 0 or in some other cases it looks like two requests thrown together (... means xml string left out): x.x.x.x -> y.y.y.y:8080 - - [timestamp] "...</someop></soapenv:Body></soapenv:Envelope>:xsd=\"http://www.w3.org/2001/XMLSchema\"...</soapenv:Body></soapenv:Envelope>" 400 299 0 Application log does not give any hints. Frequency of such call is 1% of all calls to that service. The only discriminator I know of so far is that it happens since operations informed us that the service url changed because of "server migration". Has anyone experienced such phenomenon yet? Has somebody got an idea whats wrong and how to fix? Thanks,

    Read the article

  • Grails Deployment - Fastest way to get deployed?

    - by gav
    Hi All, If anyone has or is running a Grails application on their server I would appreciate some details on where to go after creating the WAR. Background I chose grails because with Google App Engine and the App Engine Plugin deployment should have been trivial. This issue is that there is a bug which makes any application pretty much unusable, I wish this had been more prominent so I didn't have to get to the point of seeing the error myself before I was aware of it. The next option was EC2 and the Cloud Tools plugin, it seems Cloud Tools worked with grails 1.0 but doesn't work with the current 1.2.1 due to issues getting the JAR dependencies. It also seems that Cloud Tools has been succeeded by Cloud Foundry which is in beta, will cost extra money and has limited places (I signed up but haven't got an e-mail). Question My application is painfully trivial, it has a small load, small data requirements and doesn't need to scale past 5 users. How can I deploy my grails app as quickly and painlessly as possible? Specifically: Are there any hosting companies that have tomcat installed on their servers out of the box that I can sign up to and use that will just work? Do you know of any simple tutorials for getting a grails application deployed to EC2 without Cloud Tools? Thanks in advance, Gav Side-note: I picked grails because of good advice from SO, it should have been a very short time from development to deployed product except the tools for auto-deployment aren't that mature and I've never configured a server before.

    Read the article

  • String Manipulation: Splitting Delimitted Data

    - by Milli Szabo
    I need to split some info from a asterisk delimitted data. Data Format: NAME*ADRESS LINE1*ADDRESS LINE2 Rules: 1. Name should be always present 2. Address Line 1 and 2 might not be 3. There should be always three asterisks. Samples: MR JONES A ORTEGA*ADDRESS 1*ADDRESS2* Name: MR JONES A ORTEGA Address Line1: ADDRESS 1 Address Line2: ADDRESS 2 A PAUL*ADDR1** Name: A PAUL Address Line1: ADDR1 Address Line2: Not Given My algo is: 1. Iterate through the characters in the line 2. Store all chars in a temp variables until first * is found. Reject the data if no char is found before first occurence of asterisk. If some chars found, use it as the name. 3. Same as step 2 for finding address line 1 and 2 except that this won't reject the data if no char is found My algo looks ugly. The code looks uglier. Spliting using //* doesn't work either since name can be replaced with address line 1 if the data was *Address 1*Address2. Any suggestion?

    Read the article

  • Iterables.find and Iterators.find - instead of throwing exception, get null

    - by mjlee
    I'm using google-collections and trying to find the first element that satisfies Predicate if not, return me 'null'. Unfortunately, Iterables.find and Iterators.find throws NoSuchElementException when no element is found. Now, I am forced to do Object found = null; if ( Iterators.any( newIterator(...) , my_predicate ) { found = Iterators.find( newIterator(...), my_predicate ) } I can surround by 'try/catch' and do the same thing but for my use-cases, I am going to encounter many cases where no-element is found. Is there a simpler way of doing this?

    Read the article

  • JUnit Rule TemporaryFolder

    - by Jeff Storey
    I'm creating a TemporaryFolder using the @Rule annotation in JUnit 4.7. I've tried to create a new folder that is a child of the temp folder using tempFolder.newFolder("someFolder") in the @Before (setup) method of my test. It seems as though the temporary folder gets initialized after the setup method runs, meaning I can't use the temporary folder in the setup method. Is this correct (and predictable) behavior? thanks, Jeff

    Read the article

  • Why does my JButton look differently of different computers?

    - by Roman
    I use JButtons in my application. They need to have different colors. First I used that btn.setBackground(col);. It works on my computer and on another computer my button just gray (not red, as it's supposed to be). Trying to solve this problem I decided to use images. I do it in the following way: tmp = new JButton(newIcon); Again, it works fine on my computer and on another computer I see just gray buttons. Does anybody have any ideas what can be the reason of the problem and how it can be solved? I heard it can be related to "look-and-feel of the native system". But I do not know what it means and what should I do if it is the case? Can anybody pleas, help me with that?

    Read the article

< Previous Page | 770 771 772 773 774 775 776 777 778 779 780 781  | Next Page >