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• Why doesn't this loop terminate?

  - by David

  Here's the sample code: public static void col (int n) { if (n % 2 == 0) n = n/2 ; if (n % 2 != 0) n = ((n*3)+1) ; System.out.println (n) ; if (n != 1) col (n) ; } this works just fine until it gets down to 2. then it outputs 2 4 2 4 2 4 2 4 2 4 infinitely. it seems to me that if 2 is entered as n then (n % 2 == 0) is true 2 will be divided by 2 to yeild 1. then 1 will be printed and since (n != 1) is false the loop will terminate. Why doesn't this happen?

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• Java: conditional initialization?

  - by HH

  Ruby has conditional initialization. Apparently, Java does not or does it? I try to write more succintly, to limit the range as small as possible. import java.io.*; import java.util.*; public class InitFor{ public static void main(String[] args){ for(int i=7,k=999;i+((String h="hello").size())<10;i++){} System.out.println("It should be: hello = "+h); } } Errors Press ENTER or type command to continue InitFor.java:8: ')' expected for(int i=7,k=999;i+((String h="hello").size())<10;i++){} ^

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• How to sort Map in Java

  - by kalpesh

  hi i want to sort map according to its key value plz see code below public static void main(String[] args) { SortedMap map = new TreeMap(); // Add some elements: map.put("2", "Two"); map.put("1", "One"); map.put("5", "Five"); map.put("4", "Four"); map.put("3", "Three"); map.put("10", "Ten"); map.put("12", "Twelve"); map.put("7", "Seven"); map.put("9", "Nine"); Iterator iterator = map.keySet().iterator(); while (iterator.hasNext()) { Object key = iterator.next(); System.out.println("key : " + key + " value :" + map.get(key)); } } Result Should come below key : 1 value :One key : 2 value :Two key : 3 value :Three key : 4 value :Four key : 5 value :Five key : 7 value :Seven key : 9 value :Nine key : 10 value :Ten key : 12 value :Twelve

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• sending binary data via POST on android

  - by wo_shi_ni_ba_ba

  Android supports a limited version of apache's http client(v4). typically if I want to send binary data using content type= application/octet-stream via POST, I do the following: HttpClient client = getHttpClient(); HttpPost method=new HttpPost("http://192.168.0.1:8080/xxx"); System.err.println("send to server "+s); if(compression){ byte[]compressed =compress(s); RequestEntity entity = new ByteArrayRequestEntity(compressed); method.setEntity(entity); } HttpResponse resp=client.execute(method); however ByteArrayRequestEntity is not supported on android. what can I do?

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• When is a scala partial function not a partial function?

  - by Fred Haslam

  While creating a map of String to partial functions I ran into unexpected behavior. When I create a partial function as a map element it works fine. When I allocate to a val it invokes instead. Trying to invoke the check generates an error. Is this expected? Am I doing something dumb? Comment out the check() to see the invocation. I am using scala 2.7.7 def PartialFunctionProblem() = { def dream()() = { println("~Dream~"); new Exception().printStackTrace() } val map = scala.collection.mutable.HashMap[String,()=>Unit]() map("dream") = dream() // partial function map("dream")() // invokes as expected val check = dream() // unexpected invocation check() // error: check of type Unit does not take parameters }

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• Java: opening and reading from a file without locking it.

  - by rogue780

  I need to be able to mimic 'tail -f' with Java. I'm trying to read a log file as it's being written by another process, but when I open the file to read it, it locks the file and the other process can't write to it anymore. Any help would be greatly appreciated! Here is the code that I'm using currently: public void read(){ Scanner fp = null; try{ fp = new Scanner(new FileReader(this.filename)); fp.useDelimiter("\n"); }catch(java.io.FileNotFoundException e){ System.out.println("java.io.FileNotFoundException e"); } while(true){ if(fp.hasNext()){ this.parse(fp.next()); } } }

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• Object can not be resolved.

  - by Gabriel A. Zorrilla

  I have this code: public class Window extends JFrame { public Window(){ ... JButton button = new JButton("OK"); getContentPane().add(button); ButtonHandler handler = new ButtonHandler(); button.addActionListener(handler); ... } private class ButtonHandler implements ActionListener { public void actionPerformed(ActionEvent event){ if (event.getSource() == button){ // <--- "button can not be resolved" System.out.println("Hello"); } } } I'm getting that error in Eclipse. I just made a (simplified) example found in a book, dont know what can be wrong. Knowledge eye required! :)

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• Casting a primitive int to a Number

  - by Tamer

  Let's say that I have the following: int a = 2; Number b = (Number) a; System.out.println(b); // Prints 2 http://java.sun.com/docs/books/jls/first_edition/html/15.doc.html#238146 says that a primitive value may not be cast to a reference type. Does Java know to create an Integer from the primitive int and then cast to the superclass? How exactly does Java handle this behind the scenes? Thanks!

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• Java HTTP Client Request with defined timeout

  - by Maxim Veksler

  Hello, I would like to make BIT (Built in tests) to a number of server in my cloud. I need the request to fail on large timeout. How should I do this with java? Trying something like the below does not seem to work. public class TestNodeAliveness { public static NodeStatus nodeBIT(String elasticIP) throws ClientProtocolException, IOException { HttpClient client = new DefaultHttpClient(); client.getParams().setIntParameter("http.connection.timeout", 1); HttpUriRequest request = new HttpGet("http://192.168.20.43"); HttpResponse response = client.execute(request); System.out.println(response.toString()); return null; } public static void main(String[] args) throws ClientProtocolException, IOException { nodeBIT(""); } } -- EDIT: Clarify what library is being used -- I'm using httpclient from apache, here is the relevant pom.xml section org.apache.httpcomponents httpclient 4.0.1 jar

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• Understanding the workings of equals and hashCode in a HashMap

  - by andandandand

  I have this test code: import java.util.*; class MapEQ { public static void main(String[] args) { Map<ToDos, String> m = new HashMap<ToDos, String>(); ToDos t1 = new ToDos("Monday"); ToDos t2 = new ToDos("Monday"); ToDos t3 = new ToDos("Tuesday"); m.put(t1, "doLaundry"); m.put(t2, "payBills"); m.put(t3, "cleanAttic"); System.out.println(m.size()); } } class ToDos{ String day; ToDos(String d) { day = d; } public boolean equals(Object o) { return ((ToDos)o).day == this.day; } // public int hashCode() { return 9; } } When // public int hashCode() { return 9; } is uncommented m.size() returns 2, when it's left commented it returns three. Why?

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• How to make Requests HttpOnly in strus1.1 [on hold]

  - by WSDL

  I am using struts1.2 with jboss4 sever.I have to make my requests HttpOnly.How do I make this with jobss4 and struts1.2.Please Help me .It is urgent private void validateToken(HttpServletRequest request, HttpServletResponse response) { HttpSession session = request.getSession(true); String token = (String)session.getAttribute(TOKEN_KEY); if (token == null) { token = getRandomString(); session.setAttribute(TOKEN_KEY, token); // System.out.println("Executing the Filter............XSS1"); response.addHeader("Set-Cookie", "httpOnly"); } } private String getRandomString() { return String.valueOf(System.currentTimeMillis()); }

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• Java.util.scanner error handeling

  - by Hussain

  I'm helping a friend with a java problem. However, we've hit a snag. We're using Java.Util.Scanner.nextInt() to get a number from the user, asking continiously if the user gives anything else. Only problem is, we can't figure out how to do the error handeling. What we've tried: do { int reloop = 0; try { number = nextInt(); } catch (Exception e) { System.out.println ("Please enter a number!"); reloop ++; } } while(reloop != 0); Only problem is, this loops indefinatly if you enter in something not a number. Any help?

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• Is there a simpler way to convert a byte array to a 2-byte-size hexadecimal string?

  - by Tom Brito

  Is there a simpler way of implement this? Or a implemented method in JDK or other lib? /** * Convert a byte array to 2-byte-size hexadecimal String. */ public static String to2DigitsHex(byte[] bytes) { String hexData = ""; for (int i = 0; i < bytes.length; i++) { int intV = bytes[i] & 0xFF; // positive int String hexV = Integer.toHexString(intV); if (hexV.length() < 2) { hexV = "0" + hexV; } hexData += hexV; } return hexData; } public static void main(String[] args) { System.out.println(to2DigitsHex(new byte[] {8, 10, 12})); } the output is: "08 0A 0C" (without the spaces)

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• delete item from array

  - by davit-datuashvili

  hello can anybody tell me what is wrong here? i want delete item from array but it shows me error ArrayIndexOutBound exception public class delete{ public static void main(String[]args){ int i; //delete item from array int k[]=new int[]{77,99,44,11,00,55,66,33,10}; //delete 55 int searchkey=55; int nums=k.length; for ( i=0;i<nums;i++) if (k[i]==searchkey) break; for (int t=i;t<nums;t++) k[t]=k[t+1]; nums--; for (int m=0;m<nums;m++){ System.out.println(k[m]); } } }

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• ajax parameter to send correctly a variable to a specified url

  - by kawtousse

  I am trying to send data to a servlet from a js file but the servlet never received the parameter. so this is what I have: function showProject(prj) { xmlhttp=GetXmlHttpObject(); if (xmlhttp==null) { alert ("Browser does not support HTTP Request"); return; } var url="ServletxmlGenerator"; idprj = prj.options[prj.selectedIndex].value; //alert(idprj); url=url+"?idprj="+idprj; xmlhttp.onreadystatechange=stateChanged; xmlhttp.open("GET",url,true); xmlhttp.send(null); } and to capture th request it is with: public void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { String projectcode=request.getParameter("idprj"); System.out.println("++++projectCode:=" +projectcode); the output is like: ++++projectCode:=null Can any one explain it to me it seems to be correct but i didnot find the error.Thinks

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• File is not Writing using FileOutputStream in java

  - by Krishna

  I have Java Desktop Swing application in which i am trying to write xml file but its not writing data into file here my code is FileOutputStream fileOutputStream = new FileOutputStream(input_file); SOAPConnectionFactory soapConnectionFactory = SOAPConnectionFactory.newInstance(); SOAPConnection soapConnection = soapConnectionFactory.createConnection(); SOAPMessage soapResponse = soapConnection.call(soapcall, url); String str = WebServiceDAO.soapMessageToString(soapResponse); System.err.println("String*****" + str); fileOutputStream.write(str.getBytes()); fileOutputStream.close(); here i am getting data but its not writing in file what could be the prob?

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• Error with default argument in Source.getLines (Scala 2.8.0 RC1)

  - by Derek

  assuming I running Scala 2.8.0 RC1, the following scala code should print out the content of the file "c:/hello.txt" for ( line<-Source.fromPath( "c:/hello.txt" ).getLines ) println( line ) However, when I run it, I get the following error <console>:10: error: missing arguments for method getLines in class Source; follow this method with `_' if you want to treat it as a partially applied function Error occured in an application involving default arguments. val it = Source.fromPath("c:/hello.scala").getLines From what I understand, Scala should use the default argument "compat.Platform.EOL" for "getLines". I am wondering if I did wrong or is it a bug in scala 2.8 Thanks

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• how to ouput text to java console from servlet

  - by mithun1538

  I have a servlet. But it is not working as desired. Hence for debugging purposes, I want to print statements to the java console(the one that can be opened using the java icon in taskbar). However, if I use System.out.println("message"), it doesnt display in java console. Is there any alternative way where I can display messages to the console from the servlet? Or can anyone suggest me an alternative way to display messages to any other console?

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• Progress bar increment by 1 every 100th of second

  - by Matthew De'Loughry

  I'm trying to get a JProgressBar to increment by 1 every 100th of a second, and at the moment I'm using Thread.sleep(100) inside a while statement like so: try { while (i<=100){ doTime(); } } catch (InterruptedException ex) { Logger.getLogger(SplashScreen.class.getName()).log(Level.SEVERE, null, ex); } public void doTime() throws InterruptedException{ jLabel1.setText("sleeping"); Thread.sleep(100); jLabel1.setText("start"); i++; pb.setValue(i); pb.repaint(); } and If I debug by doing a System.out.println it displays in real time but the swing GUI freezes until it drops out of the while loop can anyone help? thanks matt

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• input file cannot be found

  - by Eric Smith

  I am just messing around with reading input files with java until I got stumped at the most basic of steps... finding the input file! The input.txt file is in the same directory as my class file that is calling it yet eclipse still gives me an error that it cant be found: "Exception in thread "main" java.lang.Error: Unresolved compilation problem: Unhandled exception type FileNotFoundException" My code: package pa; import java.util.Scanner; public class Project { public static void main(String[] args) { java.io.File file = new java.io.File("input.txt"); System.out.println(file.getAbsolutePath()); Scanner input = new Scanner(file); } } input.txt is in the same package, same folder and everything. I'm confused :(

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• lexical analysis gives only one output?

  - by Caffè

  I tested this example(lexe.java), but it gave me only one output. I gave this text as a reader: public class LexeTest{ private int a = 14; } And the nextToken() function is : public Category nextToken () { if (inp.findWithinHorizon (tokenPat, 0) == null) return Category.EOF; else { lastLexeme = inp.match ().group (0); if (inp.match ().start (1) != -1) return nextToken (); else if (inp.match ().start (2) != -1) return Category.IDENT; else if (inp.match ().start (3) != -1) return Category.NUMERAL; Category result = tokenMap.get (lastLexeme); if (result == null) return Category.ERROR; else return result; } } Isdie the main method: System.out.println(lexeObject.nextToken()); output is : IDENT Why? but the textfile contains multiple keywords? Anyone know what's the problem?

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• PIG doesn't read my custom InputFormat

  - by Simon Guo

  I have a custom MyInputFormat that suppose to deal with record boundary problem for multi-lined inputs. But when I put the MyInputFormat into my UDF load function. As follow: public class EccUDFLogLoader extends LoadFunc { @Override public InputFormat getInputFormat() { System.out.println("I am in getInputFormat function"); return new MyInputFormat(); } } public class MyInputFormat extends TextInputFormat { public RecordReader createRecordReader(InputSplit inputSplit, JobConf jobConf) throws IOException { System.out.prinln("I am in createRecordReader"); //MyRecordReader suppose to handle record boundary return new MyRecordReader((FileSplit)inputSplit, jobConf); } } For each mapper, it print out I am in getInputFormat function but not I am in createRecordReader. I am wondering if anyone can provide a hint on how to hoop up my costome MyInputFormat to PIG's UDF loader? Much Thanks. I am using PIG on Amazon EMR.

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• Local variables in java

  - by Mandar

  Hello , I went through local variables and class variables concept. But I had stuck at a doubt " Why is it so that we cannot declare local variables as static " ? For e.g Suppose we have a play( ) function : void play( ) { static int i=5; System.out.println(i); } It gives me error in eclipse : Illegal modifier for parameter i; I had this doubt because of the following concepts I have read : Variables inside method : scope is local i.e within that method. When variable is declared as static , it is present for the entire class i.e not to particular object. Please could anyone help me out to clarify the concept. Thanks.

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• java - POST vs JDBC

  - by Dan

  OK so here's the code: import java.io.BufferedReader; import java.io.InputStreamReader; import java.net.URL; public class Main { public static void main(String[] args) { try { URL my_url = new URL("http://www.viralpatel.net/blogs/"); BufferedReader br = new BufferedReader(new InputStreamReader(my_url.openStream())); String strTemp = ""; while(null != (strTemp = br.readLine())){ System.out.println(strTemp); } } catch (Exception ex) { ex.printStackTrace(); } } } Using this method I can use POST and GET methods using PHP scripts. I can then use the PHP scripts to the MySQL database which in turn outputs back to the java applet. Is this possible? (and safer?) Thanks.

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• how to retrieve data in image uri in sd card to read data in byte convertion

  - by narasimha

  hi sir i am implementing upload image click upload button then select into sdcard images i am getting uri File Img = new File(selectedImage.getPath()); System.out.println("2............."+Img); FileInputStream is = null; try { is = new FileInputStream(Img); is.read(buffer); BufferedInputStream bis = new BufferedInputStream(is); Bitmap bm = BitmapFactory.decodeStream(is); bis.close(); is.close(); i got in image uri how can retrieve data in particular image uri in image path above code Img i am new in android then some suggition give me some reply

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