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  • Copy object into another

    - by EugeneP
    Is there an easy way how to achieve this: MyObj : (id, name); MyObj myObj_1 = new MyObj(1, "Name 1"); MyObj myObj_2 = new MyObj(2, "Name 2"); instead of myObj_2.setName(myObj_1.getName()) etc do something as following: myObj_2.copyFrom(myObj_1) so that they are different instances, but have equal properties.

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  • Cursor while loop returning every value but the last

    - by LordSnoutimus
    Hello, I am using a while loop to iterate through a cursor and then outputing the longitude and latitude values of every point within the database. For some reason it is not returning the last (or first depending on if I use Cursor.MoveToLast) set of longitude and latitude values in the cursor. Here is my code: public void loadTrack() { SQLiteDatabase db1 = waypoints.getWritableDatabase(); Cursor trackCursor = db1.query(TABLE_NAME, FROM, "trackidfk=1", null, null, null,ORDER_BY); trackCursor.moveToFirst(); while (trackCursor.moveToNext()) { Double lat = trackCursor.getDouble(2); Double lon = trackCursor.getDouble(1); //overlay.addGeoPoint( new GeoPoint( (int)(lat*1E6), (int)(lon*1E6))); System.out.println(lon); System.out.println(lat); } } From this I am getting: 04-02 15:39:07.416: INFO/System.out(10551): 3.0 04-02 15:39:07.416: INFO/System.out(10551): 5.0 04-02 15:39:07.416: INFO/System.out(10551): 4.0 04-02 15:39:07.416: INFO/System.out(10551): 5.0 04-02 15:39:07.416: INFO/System.out(10551): 5.0 04-02 15:39:07.416: INFO/System.out(10551): 5.0 04-02 15:39:07.416: INFO/System.out(10551): 4.0 04-02 15:39:07.416: INFO/System.out(10551): 4.0 04-02 15:39:07.416: INFO/System.out(10551): 3.0 04-02 15:39:07.416: INFO/System.out(10551): 3.0 04-02 15:39:07.416: INFO/System.out(10551): 2.0 04-02 15:39:07.416: INFO/System.out(10551): 2.0 04-02 15:39:07.493: INFO/System.out(10551): 1.0 04-02 15:39:07.493: INFO/System.out(10551): 1.0 7 Sets of values, where I should be getting 8 sets. Thanks.

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  • null != null - any ideas on how to re-arrange the code or prevent this?

    - by Alex
    Currently debugging, and found an if-statement which for no (I thought...) reason gave me an NPE, obviously for a reason. Which seemed to be that the statement turned out to be if(false && (null != null || null != Color)). if(destination != null && (destination.getPiece() != null || destination.getPiece().getColour() != pieceColour)) - the if-statement Both destination can be null and piece can be. The getColour() method returns an attribute of type Color from piece, which must be null if the piece is null. The piece at destination has a different pieceColour attribute then the one in the if-statement. Specifically, how do I re-arrange (destination.getPiece() != null) ?

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  • Hibernate criteria DB2 composite keys in IN clause

    - by nkr1pt
    Hibernate criteria, using DB2 dialect, generates the following sql with composite keys in the IN clause, but DB2 answers that the query is incorrect: select * from tableA where (x, y) IN ( ( 'x1', y1) ) but, DB2 throws this: SQL0104N An unexpected token "," was found following ", y) in ( ('x1'". Expected tokens may include: "+". SQLSTATE=42601

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  • Set Icon Image problem in Jar file

    - by Mr CooL
    The following code works when running the NetBeans IDE. this.getFrame().setIconImage(Toolkit.getDefaultToolkit().getImage("PlagiaLyzerIcon.png")); However, once it was built into Jar file, the icon was gone. Anyone has idea what's the problem? I realized I've to put the icon image on the root directory, however, after compiling into JAR, the icon gone. Thanks for any help..

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  • Essence of BiMap in Google collections

    - by littleEinstein
    I am still quite puzzled at the BiMap in Google collections/Guava. It was claimed that The two bimaps are backed by the same data; any changes to one will appear in the other. I browsed through the source code, and I found the use of delegate in ForwardingMap. But in any actually subclass of StandardBiMap, I do see the data are put into both the forward and reverse map. So what is the essence, and why it claims to have saved space by keeping only one copy of the data? Is it just the actual objects are one set, but two distinct sets of references to these objects are still needed, one set maintained in forward map, and the other in reverse map? private V putInBothMaps(K key, V value, boolean force) { boolean containedKey = containsKey(key); if (containedKey && Objects.equal(value, get(key))) { return value; } if (force) { inverse().remove(value); } else if (containsValue(value)) { throw new IllegalArgumentException( "value already present: " + value); } V oldValue = super.put(key, value); updateInverseMap(key, containedKey, oldValue, value); return oldValue; }

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  • Confused about Huffman Trees

    - by ShrimpCrackers
    A quick tutorial on generating a huffman tree Confused about Huffman Trees. Near the end of that link above, it shows the tree with 2 elements left, and then the completed tree. I'm confused about the way that it is branched. Is there a specific way a huffman tree needs to be branched? For example, 57:* with its right child 35:* is branched off to the right. Could it have been 35 branched to the left with 22 branched to the right? Also, why wasn't 22:* paired up with 15:4 - it just paired with 20:5 to create a new tree. From initial obersvations it seems the tree does not need to be balanced or have any specific order other than that the frequencies of a leaf add up to the value of the parent node. Could two people creating a huffman tree with the same data end up with different encoding values?

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  • Iceface: reset old values while update

    - by J L A
    Hello all, I have information of user in bean, and I want to update this user. but my problem is: when the value of inputtext changed I want to put validation on it. and if the new value is wrong I want to reset the old value. please can any one help me

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  • May the FileInputStream.available foolish me?

    - by Tom Brito
    This FileInputStream.available() javadoc says: Returns an estimate of the number of remaining bytes that can be read (or skipped over) from this input stream without blocking by the next invocation of a method for this input stream. The next invocation might be the same thread or another thread. A single read or skip of this many bytes will not block, but may read or skip fewer bytes. In some cases, a non-blocking read (or skip) may appear to be blocked when it is merely slow, for example when reading large files over slow networks. I'm not sure if in this check: if (new FileInputStream(xmlFile).available() == 0) can I rely that empty files will always return zero?

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  • Code refactoring homework?

    - by Hira
    This is the code that I have to refactor for my homework: if (state == TEXAS) { rate = TX_RATE; amt = base * TX_RATE; calc = 2 * basis(amt) + extra(amt) * 1.05; } else if ((state == OHIO) || (state == MAINE)) { rate = (state == OHIO) ? OH_RATE : MN_RATE; amt = base * rate; calc = 2 * basis(amt) + extra(amt) * 1.05; if (state == OHIO) points = 2; } else { rate = 1; amt = base; calc = 2 * basis(amt) + extra(amt) * 1.05; } I have done something like this if (state == TEXAS) { rate = TX_RATE; calculation(rate); } else if ((state == OHIO) || (state == MAINE)) { rate = (state == OHIO) ? OH_RATE : MN_RATE; calculation(rate); if (state == OHIO) points = 2; } else { rate = 1; calculation(rate); } function calculation(rate) { amt = base * rate; calc = 2 * basis(amt) + extra(amt) * 1.05; } How could I have done better? Edit i have done code edit amt = base * rate;

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  • How do I get a JPanel with an empty JLabel to take up space in a GridBagLayout

    - by user2888663
    I am working on a GUI for a project at school. I am using a GridBagLayout in swing. I want to have a label indicating the input(a type of file @ x = 0, y = 0), followed by another label(the actual file name once selected @ x = 1, y = 0), followed by a browse button for a file chooser( @ x = 2, y = 0). The label at (1,0) is initially blank, however I want the area that the text will occupy to take up some space when the label contains no text. I also want the space between the label at (0,0) and the button at (2,0) to remain constant. To achieve this, I'm trying to put the label onto a panel and then play with the layouts. However I can't seam to achieve the desired results. Could anyone offer some suggestions? The next three rows of the GridBagLayout will be laid out exactly the same way. Here is a link to a screen shot of the GUI. calibrationFileSelectionValueLabel = new JLabel("",Label.LEFT); calibrationFileSelectionValueLabel.setName("calibrationFileSelection"); calibrationFileSelectionValueLabel.setMinimumSize(new Dimension(100,0)); calibrationFileSelectionValuePanel = new JPanel(); calibrationFileSelectionValuePanel.setBorder(BorderFactory.createEtchedBorder()); calibrationFileSelectionValuePanel.add(calibrationFileSelectionValueLabel); c.gridx = 0; c.gridy = 0; c.fill = GridBagConstraints.NONE; filesPanel.add(calibrationFileLabel,c); c.gridy = 1; filesPanel.add(frequencyFileLabel,c); c.gridy = 2; filesPanel.add(sampleFileLabel,c); c.gridy = 3; filesPanel.add(outputFileLabel,c); c.gridx = 1; c.gridy = 0; c.fill = GridBagConstraints.BOTH; // filesPanel.add(calibrationFileSelection,c); filesPanel.add(calibrationFileSelectionValuePanel,c); c.gridy = 1; // filesPanel.add(frequencyFileSelection,c); filesPanel.add(frequencyFileSelectionValueLabel,c); c.gridy = 2; // filesPanel.add(sampleFileSelection,c); filesPanel.add(sampleFileSelectionValueLabel,c); c.gridy = 3; // filesPanel.add(outputFileSelection,c); filesPanel.add(outputFileSelectionValueLabel,c); c.gridx = 2; c.gridy = 0; c.fill = GridBagConstraints.NONE; filesPanel.add(calibrationFileSelectionButton,c); c.gridy = 1; filesPanel.add(frequencyFileSelectionButton,c); c.gridy = 2; filesPanel.add(sampleFileSelectionButton,c); c.gridy = 3; filesPanel.add(createOutputFileButton,c); panelForFilesPanelBorder = new JPanel(); panelForFilesPanelBorder.setBorder(BorderFactory.createCompoundBorder(new EmptyBorder(5,10,5,10), BorderFactory.createEtchedBorder())); panelForFilesPanelBorder.add(filesPanel); buttonsPanel = new JPanel(); buttonsPanel.setLayout(new FlowLayout(FlowLayout.CENTER)); buttonsPanel.setBorder(BorderFactory.createCompoundBorder(new EmptyBorder(5,10,10,10), BorderFactory.createEtchedBorder())); buttonsPanel.add(startButton); buttonsPanel.add(stopButton); basePanel.add(panelForFilesPanelBorder); basePanel.add(numericInputPanel); basePanel.add(buttonsPanel);

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  • How to count term frequency for set of documents?

    - by ManBugra
    i have a Lucene-Index with following documents: doc1 := { caldari, jita, shield, planet } doc2 := { gallente, dodixie, armor, planet } doc3 := { amarr, laser, armor, planet } doc4 := { minmatar, rens, space } doc5 := { jove, space, secret, planet } so these 5 documents use 14 different terms: [ caldari, jita, shield, planet, gallente, dodixie, armor, amarr, laser, minmatar, rens, jove, space, secret ] the frequency of each term: [ 1, 1, 1, 4, 1, 1, 2, 1, 1, 1, 1, 1, 2, 1 ] for easy reading: [ caldari:1, jita:1, shield:1, planet:4, gallente:1, dodixie:1, armor:2, amarr:1, laser:1, minmatar:1, rens:1, jove:1, space:2, secret:1 ] What i do want to know now is, how to obtain the term frequency vector for a set of documents? for example: Set<Documents> docs := [ doc2, doc3 ] termFrequencies = magicFunction(docs); System.out.pring( termFrequencies ); would result in the ouput: [ caldari:0, jita:0, shield:0, planet:2, gallente:1, dodixie:1, armor:2, amarr:1, laser:1, minmatar:0, rens:0, jove:0, space:0, secret:0 ] remove all zeros: [ planet:2, gallente:1, dodixie:1, armor:2, amarr:1, laser:1 ] Notice, that the result vetor contains only the term frequencies of the set of documents. NOT the overall frequencies of the whole index! The term 'planet' is present 4 times in the whole index but the source set of documents only contains it 2 times. A naive implementation would be to just iterate over all documents in the docs set, create a map and count each term. But i need a solution that would also work with a document set size of 100.000 or 500.000. Is there a feature in Lucene i can use to obtain this term vector? If there is no such feature, how would a data structure look like someone can create at index time to obtain such a term vector easily and fast? I'm not that Lucene expert so i'am sorry if the solution is obvious or trivial.

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  • Distributed sequence number generation?

    - by Jon
    I've generally implemented sequence number generation using database sequences in the past. e.g. Using Postgres SERIAL type http://neilconway.org/docs/sequences/ I'm curious though as how to generate sequence numbers for large distributed systems where there is no database. Does anybody have any experience or suggestions of a best practice for achieving sequence number generation in a thread safe manner for multiple clients?

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  • Finding the second highest number in array

    - by Richard Jackson
    I'm having difficulty to understand the logic behind the method to find the second highest number in array. The method used is to find the highest in the array but less than the previous highest (which has already been found). The thing that I still can't figure it out is why || highest_score == second_highest is necessary. For example I input three numbers: 98, 56, 3. Without it, both highest and second highest would be 98. Please explain. int second highest = score[0]; if (score[i] > second_highest && score[i] < highest_score || highest_score == second_highest) second_highest = score[i];

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  • Browser show incomplete JSP data

    - by memoryleaks
    I am using JSP, Struts 1.3 and Apache Tomcat 5.5. For some reason response from JSP is being truncated and complete information is not shown. Class generated from the problem JSP page looks just fine. There are no any errors logged in Catalina's logs. I have no idea how this issue can be fixed.

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  • Disable chaching in JPA (eclipselink)

    - by James
    Hi, I want to use JPA (eclipselink) to get data from my database. The database is changed by a number of other sources and I therefore want to go back to the database for every find I execute. I have read a number of posts on disabling the cache but this does not seem to be working. Any ideas? I am trying to execute the following code: EntityManagerFactory entityManagerFactory = Persistence.createEntityManagerFactory("default"); EntityManager em = entityManagerFactory.createEntityManager(); MyLocation one = em.createNamedQuery("MyLocation.findMyLoc").getResultList().get(0); MyLocation two = em.createNamedQuery("MyLocation.findMyLoc").getResultList().get(0); System.out.println(one==two); one==two is true while I want it to be false. I have tried adding each/all the following to my persistence.xml <property name="eclipselink.cache.shared.default" value="false"/> <property name="eclipselink.cache.size.default" value="0"/> <property name="eclipselink.cache.type.default" value="None"/> I have also tried adding the @Cache annotation to the Entity itself: @Cache( type=CacheType.NONE, // Cache nothing expiry=0, alwaysRefresh=true ) Am I misunderstanding something? Thank you, James

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  • How do Tomcat examples work?

    - by Bialecki
    Alright, this is a very simple question. I just installed Tomcat 6 on my Mac to play around with it, and every tutorial I look at says the first thing to do to create a new web application is to add a line to the server.xml file with defines a new Context. Fair enough. However, my question is, I don't see a line in there for the example web applications, so how do those work?

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  • Jad file download link for my website

    - by Jareim
    Hi sir/madam! I am putting up a small website via webs.com for me and my friends that could also be accessible via wap, i.e. mobile internet, and I want to add links to my site that downloads .jar files. I uploaded the files on my site, and links to the .jar files went fine, but I also need links for .jad files (for some mobile phones that require .jad files FIRST then .jar). I tried doing a regular link for the .jad files, but it simply displayed the content of the .jad file. It wasn't installed or downloaded. What should I do? Or am I at a wrong website? Thanks!

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  • Correct algorith for checking leap year

    - by Debanjan
    What will be the exact definition of leap year ? AFAIK "A year which is divisible by 4 is a leap year.But for century years' the years which are divisible by 400 is a leap year." But that definition makes 100, 200, 300, 400.... upto 1700 NOT LEAP years! But in Gregorian calender all of them are all leap year,check this out. You can also try "call 1700" in Linux to verify. So the correct algorithm foe leap year would be if ( (year % 4 == 0) && ( year <= 1700 || year % 100 != 0 || year % 400 == 0 )) printf("%d is a leap year.\n", year); else printf("%d is not a leap year.\n", year); But is this specific to Gregorian calender ? Even if that is the case why is it not mentioned here ? Regards, PS:The history of Gregorian callender seems interesting check out the September month of 1752.

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  • Why is Collection<String>.class Illegal?

    - by Peter
    I am puzzled by generics. You can declare a field like: Class<Collection<String>> clazz = ... It seems logical that you could assign this field with: Class<Collection<String>> clazz = Collection<String>.class; However, this generates an error: Syntax error on token ">", void expected after this token So it looks like the .class operator does not work with generics. So I tried: class A<S> {} class B extends A<String> {} Class<A<String>> c = B.class; Also does not work, generates: Type mismatch: cannot convert from Class<Test.StringCollection> to Class<Collection<String>> Now, I really fail to see why this should not work. I know generic types are not reified but in both cases it seems to be fully type safe without having access to runtime generic types. Anybody an idea? Peter Kriens

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