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  • Debian: Firefox or Iceweasel default printer for POS station

    - by Bubnoff
    Context Using Debian 6.04 "Squeeze" as POS station. There are two printers installed: Network printer and a receipt printer It absolutely must be able to print by default to the receipt printer on a certain website though the system default is a network printer. In Debian ...it doesn't. Problem I've set up XP, 7, Ubuntu and even Mac OSX this way, so I'm no stranger to setting Firefox up this way ...same Iceweasel/Firefox settings ...complete fail. Always uses system default no matter what the settings, or, which printer you print from. To get this to work on other systems you do this: Print a page in Firefox using desired printer. Ensure print.save_settings is true. Firefox remembers last printer used Set print.always_print_silent = true The end. This works on every OS I've set up ....except Firefox and Iceweasel in Debian. My only recourse seems to be to set the receipt printer as default or go back to bloaty Ubuntu/Mint ...etc.

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  • Indefinite loops where the first time is different

    - by George T
    This isn't a serious problem or anything someone has asked me to do, just a seemingly simple thing that I came up with as a mental exercise but has stumped me and which I feel that I should know the answer to already. There may be a duplicate but I didn't manage to find one. Suppose that someone asked you to write a piece of code that asks the user to enter a number and, every time the number they entered is not zero, says "Error" and asks again. When they enter zero it stops. In other words, the code keeps asking for a number and repeats until zero is entered. In each iteration except the first one it also prints "Error". The simplest way I can think of to do that would be something like the folloing pseudocode: int number = 0; do { if(number != 0) { print("Error"); } print("Enter number"); number = getInput(); }while(number != 0); While that does what it's supposed to, I personally don't like that there's repeating code (you test number != 0 twice) -something that should generally be avoided. One way to avoid this would be something like this: int number = 0; while(true) { print("Enter number"); number = getInput(); if(number == 0) { break; } else { print("Error"); } } But what I don't like in this one is "while(true)", another thing to avoid. The only other way I can think of includes one more thing to avoid: labels and gotos: int number = 0; goto question; error: print("Error"); question: print("Enter number"); number = getInput(); if(number != 0) { goto error; } Another solution would be to have an extra variable to test whether you should say "Error" or not but this is wasted memory. Is there a way to do this without doing something that's generally thought of as a bad practice (repeating code, a theoretically endless loop or the use of goto)? I understand that something like this would never be complex enough that the first way would be a problem (you'd generally call a function to validate input) but I'm curious to know if there's a way I haven't thought of.

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  • So, BizTalk 2010 Beta is out &hellip; wait, no it&rsquo;s not &hellip; wait

    - by Enrique Lima
    Over the last couple of days we have seen posts and “rumors” of the Beta availability.  There was a link to the bits from the Download Center, but then they were not. Documentation for it is available now at: BizTalk Server 2010 Documentation – Beta Microsoft BizTalk Server 2010 ESB Toolkit Documentation – Beta BizTalk RFID Server 2010 and BizTalk RFID Mobile 2010 Documentation – Beta But what about the bits?!? From the Biztalk Server Team blog: “We will be announcing the public Beta of BizTalk Server 2010 at the Application Infrastructure Virtual Launch tomorrow (Thursday, May 20th, 2010 at 8:30 AM PST) with planned RTM in Q3 of 2010. BizTalk Server 2010 aligns with the latest Microsoft platform releases, including SQL Server 2008 R2, Visual Studio 2010 and SharePoint 2010, and will integrate with Windows Server AppFabric and with .NET 4. At this virtual launch event we will disclose details on new features and capabilities in BizTalk Server 2010 though presentations, whitepapers, videos and recorded demos. Please join us tomorrow for an exciting launch! The BizTalk Team” Keep your eyes and ears at the ready.

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  • Is Ubuntu MAAS free? Will it remain like that?

    - by Bruno Pereira
    Ubuntu MAAS, very cool, awesome in fact, looks like a unique tool for several jobs. It looks free, but part of its documentation starts already with clauses that would scare anyone with interest in it: Documentation is copy righted by Canonical; Documentation must be used only for non-commercial purposes; If documentation is distributed within the non-commercial clause you must retain copyright; It just sounds a lot for a guide on how to install MAAS + Juju + Openstack and that scares me a bit. Under what license is Ubuntu MAAS distributed and what would be the reasoning for being so worried about copyrighting a guide like that so heavily? Is Ubuntu MAAS free? Will it continue like that?

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  • PDF export printing in Internet Explorer [closed]

    - by user619804
    protected static byte[] exportReportToPdf(JasperPrint jasperPrint) throws JRException { JRPdfExporter exporter = new JRPdfExporter(); ByteArrayOutputStream baos = new ByteArrayOutputStream(); exporter.setParameter(JRExporterParameter.JASPER_PRINT, jasperPrint); exporter.setParameter(JRExporterParameter.OUTPUT_STREAM, baos); exporter.setParameter(JRPdfExporterParameter.PDF_JAVASCRIPT, "this.print({bUI: true,bSilent: false,bShrinkToFit: true});"); exporter.exportReport(); return baos.toByteArray(); } We are using code like this to export a PDF document from a Jasper application. The line exporter.setParameter(JRPdfExporterParameter.PDF_JAVASCRIPT, "this.print({bUI: true,bSilent: false,bShrinkToFit: true});"); adds JavaScript to send the PDF document directly to the printer. The expected behavior is that a print dialog will come up with a preview of the PDF document. This works fine most of the time - except I am having problems about one out of every 5-6 times in Internet Explorer 8 and Firefox. What happens is - the print preview dialog with the PDF document does not appear or it appears with a blank document in the preview window. -I've tried a number of different JavaScripts (different params to this.print() via exporter.setParameter -I've tried setting different response headers such as response.setContentType("application/pdf"); response.setHeader("Content-disposition","inline; filename=\"" + reportName + "\""); response.setContentLength(baos.size()); these did not seem to help This seems to be an IE and FF issue. Has anyone ever dealt with this problem? I need to get it to work across all browsers 100% of the time. Perhaps a different approach to accomplish the goal of sending the PDF document export directly to the printer? or a third party library that will work across browsers?

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  • My Brother printer doesn't accept quality settings anymore - what can I do?

    - by rearlight
    I have a Brother MFC-465CN network printer. It uses the brother-cups-wrapper-bh7 and brother-lpr-drivers-bh7drivers. Now, when I print (which works perfectly fine) I try to print in "fast normal" settings to save some ink. I use LibreOffice and Ubuntus default PDF-viewer to print and set the settings in the print dialog manually. "Fast normal" is the default printing setting (in the Ubuntu GUI printing config). But the printer always prints in "normal" or even "fine" quality settings which takes forever and uses much more ink. So, what can I do about that? Thanks for your help in advance!

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  • Network printer problem with 12.04

    - by G. He
    I had an HP LaserJet 3030 printer connected to an Ubuntu box. It worked fine with 11.10. I was able to print from Ubuntu as well as from Windows and Mac from the home network. About a month or so ago, I upgraded 11.10 to 12.04, then things started to falling apart. My Windows 7 laptop couldn't print to the printer any more. Today, I installed many updates on 12.04, hoping that would fix the printing problem. Unfortunately, it made the situation much worse. Now not only my Windows 7 laptop won't print, my XP desktop won't print either. Every time I print something from the Windows computer, the Ubuntu box logs an error message in /var/log/samba/log.'machineName' as: _spoolss_OpenPrinterEx: Cannot open a printer handle for printer \\server. It is interesting that it uses the server name as the printer, not the \\server\xyzprinter as the printer name. Anyone had a similar problem? Anyway to work around the problem?

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  • Very basic beginner Ruby question to do with elsif and ranges [migrated]

    - by MattKneale
    I've been trying to get to grasps with Ruby (for all of an hour) and this is my first language. I've got the following code: var_comparison = 5 print "Please enter a number: " my_num = Integer(gets.chomp) if my_num > var_comparison print "You picked a number greater than 5!" elsif my_num < var_comparison print "You picked a number less than 5!" elsif my_num > 99 print "Your number is too large, man." else print "You picked the number 5!" end Clearly the interpreter has no way of distinguishing between accepting the rule 5 or 99. How do I make it so that any number between 6-99 returns "You picked a number greater than 5!", but a number 100 or greater returns "Your number is too large, man!"? Do I need to specifically state a range somehow? How would I best do that? Would it by the normal range methods e.g. if my_num 6..99 or if my_num.between(6..99) ?

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  • Is there a standard for machine-readable descriptions of RESTful services?

    - by ecmendenhall
    I've interacted with a few RESTful APIs that provided excellent documentation for humans and descriptive URIs, but none of them seem to return machine-readable descriptions of themselves. It's not too tough to write methods of my own that assemble the right paths, and many language-specific API libraries are already just wrappers around RESTful requests. But the next level of abstraction seems really useful: a library that could read in an API's own machine readable documentation and generate the wrappers automatically, perhaps with a call to some standard URI like base_url + '/documentation' Are there any standards for machine-readable API documentation? Am I doing REST wrong? I am a relatively new programmer, but this seems like a good idea.

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  • More about E-Business Suite Certifications

    - by Sadia2
    E-Business Suite certifications contained in My Oracle Support are modeled at the suite-level only. All products packaged within the Rapid Install release bundle follow the certification for that E-Business Suite release. Platform-specific certification exceptions are documented in the Installation and Upgrade Notes for each platform, available as links from the following Oracle Applications Documentation Resources notes: Oracle Applications Documentation Resources, Release 12 (Doc ID 394692.1) Oracle Applications Documentation Resources, Release 12.1 (Doc ID 790942.1)

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  • Map rendering Libgdx Java

    - by user3165683
    Ok, so I am trying to create a 2D non-movable random tiled map. This is what I have so far: private void generateTile(){ System.out.print("tiletry1"); while(loadedTiles != 8100){ System.out.print("tiletry"); Texture currentTile = null; int tileX = 0; int tileY = 0; if (tileX == 120); tileY = 16; tileX = 0; game.batch.begin(); switch(MathUtils.random(2)){ case 0: //game.batch.draw(tile1, tileX, tileY); System.out.print("tile1"); currentTile = tile1; break; case 1: //game.batch.draw(tile2, tileX, tileY); System.out.print("tile2"); currentTile = tile2; break; case 2: //game.batch.draw(tile3, tileX, tileY); System.out.print("tile3"); currentTile = tile3; break; } tileX+=16; loadedTiles ++; game.batch.draw(currentTile, tileX, tileY); game.batch.end(); } } However, I can't see any of the tiles and the screen just looks green. This method is above my render method which I have: camera.update(); batch.setProjectionMatrix(camera.combined); Gdx.gl.glClear(GL20.GL_COLOR_BUFFER_BIT); game.batch.begin(); //other render stuff Why am I not able to see the tiles?

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  • Generate random number histogram using java

    - by Chewart
    Histogram -------------------------------------------------------- 1 ****(4) 2 ******(6) 3 ***********(11) 4 *****************(17) 5 **************************(26) 6 *************************(25) 7 *******(7) 8 ***(3) 9 (0) 10 *(1) -------------------------------------------------------- basically above is what my prgram needs to do.. im missing something somewhere any help would be great :) import java.util.Random; public class Histogram { /*This is a program to generate random number histogram between 1 and 100 and generate a table */ public static void main(String args[]) { int [] randarray = new int [80]; Random random = new Random(); System.out.println("Histogram"); System.out.println("---------"); int i ; for ( i = 0; i<randarray.length;i++) { int temp = random.nextInt(100); //random numbers up to number value 100 randarray[i] = temp; } int [] histo = new int [10]; for ( i = 0; i<10; i++) { /* %03d\t, this generates the random numbers to three decimal places so the numbers are generated with a full number or number with 00's or one 0*/ if (randarray[i] <= 10) { histo[i] = histo[i] + 1; //System.out.println("*"); } else if ( randarray[i] <= 20){ histo[i] = histo[i] + 1; } else if (randarray[i] <= 30){ histo[i] = histo[i] + 1; } else if ( randarray[i] <= 40){ histo[i] = histo[i] + 1; } else if (randarray[i] <= 50){ histo[i] = histo[i] + 1; } else if ( randarray[i] <=60){ histo[i] = histo[i] + 1; } else if ( randarray[i] <=70){ histo[i] = histo[i] + 1; } else if ( randarray[i] <=80){ histo[i] = histo[i] + 1; } else if ( randarray[i] <=90){ histo[i] = histo[i] + 1; } else if ( randarray[i] <=100){ histo[i] = histo[i] + 1; } switch (randarray[i]) { case 1: System.out.print("0-10 | "); break; case 2: System.out.print("11-20 | "); break; case 3: System.out.print("21-30 | "); break; case 4: System.out.print("31-40 | "); break; case 5: System.out.print("41-50 | "); break; case 6: System.out.print("51-60 | "); break; case 7: System.out.print("61-70 | "); break; case 8: System.out.print("71-80 | "); break; case 9: System.out.print("81-90 | "); break; case 10: System.out.print("91-100 | "); } for (int i = 0; i < 80; i++) { randomNumber = random.nextInt(100) index = (randomNumber - 1) / 2; histo[index]++; } } } }

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  • find substring and indices in mips

    - by ccc
    im trying find out substring and first occurrence indices. but something wrong. im comparing each element of pattern array and each element of string array until pointer reach to '\0'. and if any characater found it keep in temp array. and increasing pointers +1. whats the problem. algorithm is totaly wrong ? #Note: $v0 is a symbolic name used by the assember for $2. # $a0 is a symbolic name used by the assember for $4. .data prompt_str: .asciiz "Please type a text string: " prompt_ptr: .asciiz "Please type a pattern string: " print_yes: .asciiz "Yes, there is a match." print_no: .asciiz "No, there is no match." text_str: .asciiz "Text string : " pattern_str: .asciiz "Pattern string : " print_out: .asciiz "Output to be produced :" print_dash: .asciiz "----------------------" print_index: .asciiz "Starting index :" print_msg : .asciiz "Length of longest partial match = " nl: .asciiz "\n" str : .space 81 ptr : .space 81 tmp : .space 81 .text main: la $a0, prompt_str li $v0, 4 #print_string command. syscall la $a0,str #read string li $a1,81 li $v0,8 syscall la $t0,str #move string to $t0 la $a0,prompt_ptr li $v0,4 #print pattern command syscall la $a0,ptr #read pattern li $a1,81 li $v0,8 syscall la $t1,ptr #move pattern to $t1 la $t5,tmp #move temp to $t5 lb $t2,0($t0) #pointer first element array of string lb $t3,0($t1) #pointer first element array of pattern lb $t6,0($t5) #pointer first element array of temp loop : beq $t3,$0,end_loop beq $t2,$t3,match addiu $t0,$t0,1 j loop match : move $t6,$t2 addiu $t5,$t5,1 addiu $t0,$t0,1 addiu $t1,$t1,1 j print_match print_match : la $a0,text_str #print string li $v0,4 syscall move $a0,$t0 li $v0,4 syscall la $a0,nl #print newline character li $v0,4 syscall la $a0,pattern_str #print pattern string li $v0,4 syscall move $a0,$t1 li $v0,4 syscall la $a0,nl #print newline character li $v0,4 syscall la $a0,print_out #print output line and newline character li $v0,4 syscall la $a0,nl li $v0,4 syscall la $a0,print_dash li $v0,4 syscall la $a0,print_yes li $v0,4 syscall la $a0,print_index #print starting index li $v0,4 syscall li $v0,10 syscall end_loop : li $v0,10 syscall

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  • Make Python Socket Server More Efficient

    - by BenMills
    I have very little experience working with sockets and multithreaded programming so to learn more I decided to see if I could hack together a little python socket server to power a chat room. I ended up getting it working pretty well but then I noticed my server's CPU usage spiked up over 100% when I had it running in the background. Here is my code in full: http://gist.github.com/332132 I know this is a pretty open ended question so besides just helping with my code are there any good articles I could read that could help me learn more about this? My full code: import select import socket import sys import threading from daemon import Daemon class Server: def __init__(self): self.host = '' self.port = 9998 self.backlog = 5 self.size = 1024 self.server = None self.threads = [] self.send_count = 0 def open_socket(self): try: self.server = socket.socket(socket.AF_INET6, socket.SOCK_STREAM) self.server.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1) self.server.bind((self.host,self.port)) self.server.listen(5) print "Server Started..." except socket.error, (value,message): if self.server: self.server.close() print "Could not open socket: " + message sys.exit(1) def remove_thread(self, t): t.join() def send_to_children(self, msg): self.send_count = 0 for t in self.threads: t.send_msg(msg) print 'Sent to '+str(self.send_count)+" of "+str(len(self.threads)) def run(self): self.open_socket() input = [self.server,sys.stdin] running = 1 while running: inputready,outputready,exceptready = select.select(input,[],[]) for s in inputready: if s == self.server: # handle the server socket c = Client(self.server.accept(), self) c.start() self.threads.append(c) print "Num of clients: "+str(len(self.threads)) self.server.close() for c in self.threads: c.join() class Client(threading.Thread): def __init__(self,(client,address), server): threading.Thread.__init__(self) self.client = client self.address = address self.size = 1024 self.server = server self.running = True def send_msg(self, msg): if self.running: self.client.send(msg) self.server.send_count += 1 def run(self): while self.running: data = self.client.recv(self.size) if data: print data self.server.send_to_children(data) else: self.running = False self.server.threads.remove(self) self.client.close() """ Run Server """ class DaemonServer(Daemon): def run(self): s = Server() s.run() if __name__ == "__main__": d = DaemonServer('/var/servers/fserver.pid') if len(sys.argv) == 2: if 'start' == sys.argv[1]: d.start() elif 'stop' == sys.argv[1]: d.stop() elif 'restart' == sys.argv[1]: d.restart() else: print "Unknown command" sys.exit(2) sys.exit(0) else: print "usage: %s start|stop|restart" % sys.argv[0] sys.exit(2)

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  • Simple way to decrease values without making a new attribute?

    - by Jam
    I'm making a program where you're firing a 'blaster', and I have 5 ammo. I'm blasting an alien who has 5 health. At the end I instantiate the player and make him blast 6 times to check that the program works correctly. But the way I've done it makes it so that the amount won't decrease. Is there an easy fix to this, or do I just have to make a new attribute for ammo and health? Here's what I have: class Player(object): """ A player in a shooter game. """ def blast(self, enemy, ammo=5): if ammo>=1: ammo-=1 print "You have blasted the alien." print "You have", ammo, "ammunition left." enemy.die(5) else: print "You are out of ammunition!" class Alien(object): """ An alien in a shooter game. """ def die(self, health=5): if health>=1: health-=1 print "The alien is wounded. He now has", health, "health left." elif health==0: health-=1 print "The alien gasps and says, 'Oh, this is it. This is the big one. \n" \ "Yes, it's getting dark now. Tell my 1.6 million larvae that I loved them... \n" \ "Good-bye, cruel universe.'" else: print "The alien's corpse sits up momentarily and says, 'No need to blast me, I'm dead already!" # main print "\t\tDeath of an Alien\n" hero = Player() invader = Alien() hero.blast(invader) hero.blast(invader) hero.blast(invader) hero.blast(invader) hero.blast(invader) hero.blast(invader) raw_input("\n\nPress the enter key to exit.")

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  • Problem running a Python program, error: Name 's' is not defined.

    - by Sergio Tapia
    Here's my code: #This is a game to guess a random number. import random guessTaken = 0 print("Hello! What's your name kid") myName = input() number = random.randint(1,20) print("Well, " + myName + ", I'm thinking of a number between 1 and 20.") while guessTaken < 6: print("Take a guess.") guess = input() guess = int(guess) guessTaken = guessTaken + 1 if guess < number: print("You guessed a little bit too low.") if guess > number: print("You guessed a little too high.") if guess == number: break if guess == number: guessTaken = str(guessTaken) print("Well done " + myName + "! You guessed the number in " + guessTaken + " guesses!") if guess != number: number = str(number) print("No dice kid. I was thinking of this number: " + number) This is the error I get: Name error: Name 's' is not defined. I think the problem may be that I have Python 3 installed, but the program is being interpreted by Python 2.6. I'm using Linux Mint if that can help you guys help me. Using Geany as the IDE and pressing F5 to test it. It may be loading 2.6 by default, but I don't really know. :( Edit: Error 1 is: File "GuessingGame.py", line 8, in <Module> myName = input() Error 2 is: File <string>, line 1, in <Module>

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  • Python Twisted Client Connection Lost

    - by MovieYoda
    I have this twisted client, which connects with a twisted server having an index. I ran this client from command-line. It worked fine. Now I modified it to run in loop (see main()) so that I can keep querying. But the client runs only once. Next time it simply says connection lost \n Connection lost - goodbye!. What am i doing wrong? In the loop I am reconnecting to the server, it that wrong? from twisted.internet import reactor from twisted.internet import protocol from settings import AS_SERVER_HOST, AS_SERVER_PORT # a client protocol class Spell_client(protocol.Protocol): """Once connected, send a message, then print the result.""" def connectionMade(self): self.transport.write(self.factory.query) def dataReceived(self, data): "As soon as any data is received, write it back." if data == '!': self.factory.results = '' else: self.factory.results = data self.transport.loseConnection() def connectionLost(self, reason): print "\tconnection lost" class Spell_Factory(protocol.ClientFactory): protocol = Spell_client def __init__(self, query): self.query = query self.results = '' def clientConnectionFailed(self, connector, reason): print "\tConnection failed - goodbye!" reactor.stop() def clientConnectionLost(self, connector, reason): print "\tConnection lost - goodbye!" reactor.stop() # this connects the protocol to a server runing on port 8090 def main(): print 'Connecting to %s:%d' % (AS_SERVER_HOST, AS_SERVER_PORT) while True: print query = raw_input("Query:") if query == '': return f = Spell_Factory(query) reactor.connectTCP(AS_SERVER_HOST, AS_SERVER_PORT, f) reactor.run() print f.results return if __name__ == '__main__': main()

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  • Slow Python HTTP server on localhost

    - by Abiel
    I am experiencing some performance problems when creating a very simple Python HTTP server. The key issue is that performance is varying depending on which client I use to access it, where the server and all clients are being run on the local machine. For instance, a GET request issued from a Python script (urllib2.urlopen('http://localhost/').read()) takes just over a second to complete, which seems slow considering that the server is under no load. Running the GET request from Excel using MSXML2.ServerXMLHTTP also feels slow. However, requesting the data Google Chrome or from RCurl, the curl add-in for R, yields an essentially instantaneous response, which is what I would expect. Adding further to my confusion is that I do not experience any performance problems for any client when I am on my computer at work (the performance problems are on my home computer). Both systems run Python 2.6, although the work computer runs Windows XP instead of 7. Below is my very simple server example, which simply returns 'Hello world' for any get request. from BaseHTTPServer import BaseHTTPRequestHandler, HTTPServer class MyHandler(BaseHTTPRequestHandler): def do_GET(self): print("Just received a GET request") self.send_response(200) self.send_header("Content-type", "text/html") self.end_headers() self.wfile.write('Hello world') return def log_request(self, code=None, size=None): print('Request') def log_message(self, format, *args): print('Message') if __name__ == "__main__": try: server = HTTPServer(('localhost', 80), MyHandler) print('Started http server') server.serve_forever() except KeyboardInterrupt: print('^C received, shutting down server') server.socket.close() Note that in MyHandler I override the log_request() and log_message() functions. The reason is that I read that a fully-qualified domain name lookup performed by one of these functions might be a reason for a slow server. Unfortunately setting them to just print a static message did not solve my problem. Also, notice that I have put in a print() statement as the first line of the do_GET() routine in MyHandler. The slowness occurs prior to this message being printed, meaning that none of the stuff that comes after it is causing a delay.

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  • c++ function scope

    - by Myx
    I have a main function in A.cpp which has the following relevant two lines of code: B definition(input_file); definition.Print(); In B.h I have the following relevant lines of code: class B { public: // Constructors B(void); B(const char *filename); ~B(void); // File input int ParseLSFile(const char *filename); // Debugging void Print(void); // Data int var1; double var2; vector<char* > var3; map<char*, vector<char* > > var4; } In B.cpp, I have the following function signatures (sorry for being redundant): B::B(void) : var1(-1), var2(numeric_limits<double>::infinity()) { } B::B(const char *filename) { B *def = new B(); def->ParseLSFile(filename); } B::~B(void) { // Free memory for var3 and var 4 } int B::ParseLSFile(const char *filename) { // assign var1, var2, var3, and var4 values } void B::Print(void) { // print contents of var1, var2, var3, and var4 to stdout } So when I call Print() from within B::ParseLSFile(...), then the contents of my structures print correctly to stdout. However, when I call definition.Print() from A.cpp, my structures are empty or contain garbage. Can anyone recommend the correct way to initialize/pass my structures so that I can access them outside of the scope of my function definition? Thanks.

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  • Python Ephem / Datetime calculation

    - by dassouki
    the output should process the first date as "day" and second as "night". I've been playing with this for a few hours now and can't figure out what I'm doing wrong. Any ideas? Edit I assume that the problem is due to my date comparison implementation Output: $ python time_of_day.py * should be day: event date: 2010/4/6 16:00:59 prev rising: 2010/4/6 09:24:24 prev setting: 2010/4/5 23:33:03 next rise: 2010/4/7 09:22:27 next set: 2010/4/6 23:34:27 day * should be night: event date: 2010/4/6 00:01:00 prev rising: 2010/4/5 09:26:22 prev setting: 2010/4/5 23:33:03 next rise: 2010/4/6 09:24:24 next set: 2010/4/6 23:34:27 day time_of_day.py import datetime import ephem # install from http://pypi.python.org/pypi/pyephem/ #event_time is just a date time corresponding to an sql timestamp def type_of_light(latitude, longitude, event_time, utc_time, horizon): o = ephem.Observer() o.lat, o.long, o.date, o.horizon = latitude, longitude, event_time, horizon print "event date ", o.date print "prev rising: ", o.previous_rising(ephem.Sun()) print "prev setting: ", o.previous_setting(ephem.Sun()) print "next rise: ", o.next_rising(ephem.Sun()) print "next set: ", o.next_setting(ephem.Sun()) if o.previous_rising(ephem.Sun()) <= o.date <= o.next_setting(ephem.Sun()): return "day" elif o.previous_setting(ephem.Sun()) <= o.date <= o.next_rising(ephem.Sun()): return "night" else: return "error" print "should be day: ", type_of_light('45.959','-66.6405','2010/4/6 16:01','-4', '-6') print "should be night: ", type_of_light('45.959','-66.6405','2010/4/6 00:01','-4', '-6')

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  • Python optimization problem?

    - by user342079
    Alright, i had this homework recently (don't worry, i've already done it, but in c++) but I got curious how i could do it in python. The problem is about 2 light sources that emit light. I won't get into details tho. Here's the code (that I've managed to optimize a bit in the latter part): import math, array import numpy as np from PIL import Image size = (800,800) width, height = size s1x = width * 1./8 s1y = height * 1./8 s2x = width * 7./8 s2y = height * 7./8 r,g,b = (255,255,255) arr = np.zeros((width,height,3)) hy = math.hypot print 'computing distances (%s by %s)'%size, for i in xrange(width): if i%(width/10)==0: print i, if i%20==0: print '.', for j in xrange(height): d1 = hy(i-s1x,j-s1y) d2 = hy(i-s2x,j-s2y) arr[i][j] = abs(d1-d2) print '' arr2 = np.zeros((width,height,3),dtype="uint8") for ld in [200,116,100,84,68,52,36,20,8,4,2]: print 'now computing image for ld = '+str(ld) arr2 *= 0 arr2 += abs(arr%ld-ld/2)*(r,g,b)/(ld/2) print 'saving image...' ar2img = Image.fromarray(arr2) ar2img.save('ld'+str(ld).rjust(4,'0')+'.png') print 'saved as ld'+str(ld).rjust(4,'0')+'.png' I have managed to optimize most of it, but there's still a huge performance gap in the part with the 2 for-s, and I can't seem to think of a way to bypass that using common array operations... I'm open to suggestions :D

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  • Python opening a file and putting list of names on separate lines

    - by Jeremy Borton
    I am trying to write a python program using Python 3 I have to open a text file and read a list of names, print the list, sort the list in alphabetical order and then finally re-print the list. There's a little more to it than that BUT the problem I am having is that I'm supposed to print the list of names with each name on a separate line Instead of printing each name on a separate line, it prints the list all on one line. How can I fix this? def main(): #create control loop keep_going = 'y' #Open name file name_file = open('names.txt', 'r') names = name_file.readlines() name_file.close() #Open outfile outfile = open('sorted_names.txt', 'w') index = 0 while index < len(names): names[index] = names[index].rstrip('\n') index += 1 #sort names print('original order:', names) names.sort() print('sorted order:', names) #write names to outfile for item in names: outfile.write(item + '\n') #close outfile outfile.close() #search names while keep_going == 'y' or keep_going == 'Y': search = input('Enter a name to search: ') if search in names: print(search, 'was found in the list.') keep_going = input('Would you like to do another search Y for yes: ') else: print(search, 'was not found.') keep_going = input('Would you like to do another search Y for yes: ') main()

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