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• Government Mandates and Programming Languages

  A recent SEC proposal (which, at over 600 pages, I havent read in any detail) includes the following: We are proposing to require the filing of a computer program (the waterfall computer program, as defined in the proposed rule) of the contractual cash flow provisions of the securities in the form of downloadable source code in Python, a commonly used computer programming language that is open source and interpretive. The computer program would be tagged in XML and required to be filed with the Commission as an exhibit. Under our proposal, the filed source code for the computer program, when downloaded and run (by loading it into an open Python session on the investors computer), would be required to allow the user to programmatically input information from the asset data file that we are proposing to require as described above. We believe that, with the waterfall computer program and the asset data file, investors would be better able to conduct their own evaluations of ABS and may be less likely to be dependent on the opinions of credit rating agencies. With respect to any registration statement on Form SF-1 (Section 239.44) or Form SF-3 (Section 239.45) relating to an offering of an asset-backed security that is required to comply with Item 1113(h) of Regulation AB, the Waterfall Computer Program (as defined in Item 1113(h)(1) of Regulation AB) must be written in the Python programming language and able to be downloaded and run on a local computer properly configured with a Python interpreter. The Waterfall Computer Program should be filed in the manner specified in the EDGAR Filer Manual. I dont see how it can be in investors best interests that the SEC demand a particular programming language be used for software related to investment data.  I have a feeling that investors who use computers at all already have software with which they are familiar, and that the vast majority of them are not running an open source scripting language on their machines to do their financial analysis.  In fact, I would wager that most of them are using tools like Excel, and if they really need to script anything, its being done with VBA in Excel. Now, Im not proposing that the SEC should require that the data be provided in Excel format with VBA scripts included so everyone can easily access the data (despite the fact that this would actually be pretty useful generally).  Rather, I think it is ill-advised for a government agency to make recommendations of this nature, period.  If the goal of the recommendation is to ensure that the way things work is codified in a transparent manner, than I can certainly respect that.  It seems to me that this could be accomplished without dictating the technology to use.  To wit: An Excel document could contain all of the data as well as the formulae necessary, and most likely would not require the end-user to install anything on their machine The SEC could simply create a calculator in the cloud such that any/all investors could use a single canonical web-based (or web service based) tool Millions of Java and .NET developers could write their own implementations You can read more about this issue, including the favorable position on it, on Jayanth Varmas blog. Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

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• iptables 1.4 and passive FTP on custom port

  - by Cracky

  after the upgrade from debian squeeze to wheezy I've got a problem with passive FTP connection. I could narrow it to be iptables related, as I could connect via FTP w/o problems after adding my IP to the iptables ACCEPT rule. Before the upgrade I was able just to do modprobe nf_conntract_ftp ports=21332 and adding iptables -A THRU -p tcp --dport 21332 -m state --state NEW,ESTABLISHED,RELATED -j ACCEPT now..it doesn't help anymore. The INPUT rule is being triggered as I can see in the counter, but the directory listing is the last thing it does. Setting up a passive-port range is the last thing I want to do, I dislike open ports. I also tried the trick with helper mod by adding following rule before the actual rule for 21332 iptables -A THRU -p tcp -i eth0 --dport 21332 -m state --state NEW -m helper --helper ftp-21332 -j ACCEPT but it doesn't help and is even not being triggered according to counter. The rule in the next line (w/o helper) is being triggered.. here some info: # iptables --version iptables v1.4.14 # lsmod |grep nf_ nf_nat_ftp 12460 0 nf_nat 18242 1 nf_nat_ftp nf_conntrack_ftp 12605 1 nf_nat_ftp nf_conntrack_ipv4 14078 32 nf_nat nf_defrag_ipv4 12483 1 nf_conntrack_ipv4 nf_conntrack 52720 7 xt_state,nf_conntrack_ipv4,xt_conntrack,nf_conntrack_ftp,nf_nat,nf_nat_ftp,xt_helper # uname -a Linux loki 3.2.0-4-amd64 #1 SMP Debian 3.2.46-1 x86_64 GNU/Linux # iptables-save # Generated by iptables-save v1.4.14 on Sun Jun 30 03:54:28 2013 *filter :INPUT ACCEPT [0:0] :FORWARD ACCEPT [0:0] :OUTPUT ACCEPT [0:0] :BLACKLIST - [0:0] :LOGDROP - [0:0] :SPAM - [0:0] :THRU - [0:0] :WEB - [0:0] :fail2ban-dovecot-pop3imap - [0:0] :fail2ban-pureftpd - [0:0] :fail2ban-ssh - [0:0] -A INPUT -p tcp -m multiport --dports 110,995,143,993 -j fail2ban-dovecot-pop3imap -A INPUT -p tcp -m multiport --dports 21,21332 -j fail2ban-pureftpd -A INPUT -p tcp -m multiport --dports 22 -j fail2ban-ssh -A INPUT -p tcp -m multiport --dports 110,995,143,993 -j fail2ban-dovecot-pop3imap -A INPUT -i lo -j ACCEPT -A INPUT -i eth0 -p tcp -m tcp --tcp-flags FIN,SYN,RST,PSH,ACK,URG NONE -j DROP -A INPUT -i eth0 -p tcp -m tcp --tcp-flags FIN,SYN FIN,SYN -j DROP -A INPUT -i eth0 -p tcp -m tcp --tcp-flags SYN,RST SYN,RST -j DROP -A INPUT -i eth0 -p tcp -m tcp --tcp-flags FIN,RST FIN,RST -j DROP -A INPUT -i eth0 -p tcp -m tcp --tcp-flags FIN,ACK FIN -j DROP -A INPUT -i eth0 -p tcp -m tcp --tcp-flags ACK,URG URG -j DROP -A INPUT -m conntrack --ctstate RELATED,ESTABLISHED -j ACCEPT -A INPUT -j BLACKLIST -A INPUT -j THRU -A INPUT -j LOGDROP -A OUTPUT -j ACCEPT -A OUTPUT -s 93.223.38.223/32 -j ACCEPT -A BLACKLIST -s 38.113.165.0/24 -j LOGDROP -A BLACKLIST -s 202.177.216.0/24 -j LOGDROP -A BLACKLIST -s 130.117.190.0/24 -j LOGDROP -A BLACKLIST -s 117.79.92.0/24 -j LOGDROP -A BLACKLIST -s 72.47.228.0/24 -j LOGDROP -A BLACKLIST -s 195.200.70.0/24 -j LOGDROP -A BLACKLIST -s 195.200.71.0/24 -j LOGDROP -A LOGDROP -m limit --limit 5/sec -j LOG --log-prefix drop_packet_ --log-level 7 -A LOGDROP -p tcp -m tcp --dport 25 -m limit --limit 2/sec -j LOG --log-prefix spam_blacklist --log-level 7 -A LOGDROP -p tcp -m tcp --dport 80 -m limit --limit 2/sec -j LOG --log-prefix web_blacklist --log-level 7 -A LOGDROP -p tcp -m tcp --dport 22 -m limit --limit 2/sec -j LOG --log-prefix ssh_blacklist --log-level 7 -A LOGDROP -j REJECT --reject-with icmp-host-prohibited -A THRU -p icmp -m limit --limit 1/sec -m icmp --icmp-type 8 -j ACCEPT -A THRU -i eth0 -p tcp -m tcp --dport 25 -j ACCEPT -A THRU -i eth0 -p udp -m udp --dport 53 -j ACCEPT -A THRU -i eth0 -p tcp -m tcp --dport 80 -j ACCEPT -A THRU -i eth0 -p tcp -m tcp --dport 110 -j ACCEPT -A THRU -i eth0 -p tcp -m tcp --dport 143 -j ACCEPT -A THRU -i eth0 -p tcp -m tcp --dport 465 -j ACCEPT -A THRU -i eth0 -p tcp -m tcp --dport 585 -j ACCEPT -A THRU -i eth0 -p tcp -m tcp --dport 993 -j ACCEPT -A THRU -i eth0 -p tcp -m tcp --dport 995 -j ACCEPT -A THRU -i eth0 -p tcp -m tcp --dport 2008 -m state --state NEW,RELATED,ESTABLISHED -j ACCEPT -A THRU -i eth0 -p tcp -m tcp --dport 10011 -m state --state NEW,RELATED,ESTABLISHED -j ACCEPT -A THRU -i eth0 -p tcp -m tcp --dport 21332 -m state --state NEW,RELATED,ESTABLISHED -j ACCEPT -A THRU -i eth0 -p tcp -m tcp --dport 30033 -m state --state NEW,RELATED,ESTABLISHED -j ACCEPT -A fail2ban-dovecot-pop3imap -j RETURN -A fail2ban-dovecot-pop3imap -j RETURN -A fail2ban-pureftpd -j RETURN -A fail2ban-pureftpd -j RETURN -A fail2ban-ssh -j RETURN -A fail2ban-ssh -j RETURN COMMIT # Completed on Sun Jun 30 03:54:28 2013 So, as I said, I have no problems with connecting when adding my IP to go through..but that's not a solution as noone except me can connect anymore~ If someone got an idea what the problem is, please help me! Thanks Cracky

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• question about InnoDB deadlock in MySQL?

  - by WilliamLou

  I found this kind of interesting problem in MySQL InnoDB engine, could anyone explain why the engine always claim it's a deadlock. First, I created a table with a single row, single column: CREATE TABLE `SeqNum` (`current_seq_num` bigint(30) NOT NULL default '0', PRIMARY KEY (`current_seq_num`) ) ENGINE=InnoDB DEFAULT CHARSET=utf8 | Now, I have two MySQL connector threads, In thread1: mysql> begin; Query OK, 0 rows affected (0.00 sec) mysql> select `current_seq_num` into @curr_seq FROM SeqNum FOR UPDATE; Query OK, 1 row affected (0.00 sec) Now, in thread2, I did the exactly same: mysql> begin; Query OK, 0 rows affected (0.00 sec) mysql> select `current_seq_num` into @curr_seq FROM SeqNum FOR UPDATE; before the default innodb_lock_wait_timeout, the thread2 just wait for thread1 to release its exclusive lock on the table, and it's normal. However, in thread1, if I input the following update query: mysql> update SeqNum set `current_seq_num` = 8; ERROR 1213 (40001): Deadlock found when trying to get lock; try restarting transaction Now, thread2 get the select query finished because thread1 quits. In addition, in thread1, if I input the update query with a where clause, it can be executed very well: mysql> update SeqNum set `current_seq_num` = 8 where `current_seq_num` =5 Query OK, 1 row affected (0.00 sec) Could anyone explain this?

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• MySQL MyISAM table performance... painfully, painfully slow

  - by Salman A

  I've got a table structure that can be summarized as follows: pagegroup * pagegroupid * name has 3600 rows page * pageid * pagegroupid * data references pagegroup; has 10000 rows; can have anything between 1-700 rows per pagegroup; the data column is of type mediumtext and the column contains 100k - 200kbytes data per row userdata * userdataid * pageid * column1 * column2 * column9 references page; has about 300,000 rows; can have about 1-50 rows per page The above structure is pretty straight forwad, the problem is that that a join from userdata to page group is terribly, terribly slow even though I have indexed all columns that should be indexed. The time needed to run a query for such a join (userdata inner_join page inner_join pagegroup) exceeds 3 minutes. This is terribly slow considering the fact that I am not selecting the data column at all. Example of the query that takes too long: SELECT userdata.column1, pagegroup.name FROM userdata INNER JOIN page USING( pageid ) INNER JOIN pagegroup USING( pagegroupid ) Please help by explaining why does it take so long and what can i do to make it faster. Edit #1 Explain returns following gibberish: id select_type table type possible_keys key key_len ref rows Extra 1 SIMPLE userdata ALL pageid 372420 1 SIMPLE page eq_ref PRIMARY,pagegroupid PRIMARY 4 topsecret.userdata.pageid 1 1 SIMPLE pagegroup eq_ref PRIMARY PRIMARY 4 topsecret.page.pagegroupid 1 Edit #2 SELECT u.field2, p.pageid FROM userdata u INNER JOIN page p ON u.pageid = p.pageid; /* 0.07 sec execution, 6.05 sec fecth */ id select_type table type possible_keys key key_len ref rows Extra 1 SIMPLE u ALL pageid 372420 1 SIMPLE p eq_ref PRIMARY PRIMARY 4 topsecret.u.pageid 1 Using index SELECT p.pageid, g.pagegroupid FROM page p INNER JOIN pagegroup g ON p.pagegroupid = g.pagegroupid; /* 9.37 sec execution, 60.0 sec fetch */ id select_type table type possible_keys key key_len ref rows Extra 1 SIMPLE g index PRIMARY PRIMARY 4 3646 Using index 1 SIMPLE p ref pagegroupid pagegroupid 5 topsecret.g.pagegroupid 3 Using where Moral of the story Keep medium/long text columns in a separate table if you run into performance problems such as this one.

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• MySQL: order by and limit gives wrong result

  - by Larry K

  MySQL ver 5.1.26 I'm getting the wrong result with a select that has where, order by and limit clauses. It's only a problem when the order by uses the id column. I saw the MySQL manual for LIMIT Optimization My guess from reading the manual is that there is some problem with the index on the primary key, id. But I don't know where I should go from here... Question: what should I do to best solve the problem? Works correctly: mysql> SELECT id, created_at FROM billing_invoices WHERE (billing_invoices.account_id = 5) ORDER BY id DESC ; +------+---------------------+ | id | created_at | +------+---------------------+ | 1336 | 2010-05-14 08:05:25 | | 1334 | 2010-05-06 08:05:25 | | 1331 | 2010-05-05 23:18:11 | +------+---------------------+ 3 rows in set (0.00 sec) WRONG result when limit added! Should be the first row, id - 1336 mysql> SELECT id, created_at FROM billing_invoices WHERE (billing_invoices.account_id = 5) ORDER BY id DESC limit 1; +------+---------------------+ | id | created_at | +------+---------------------+ | 1331 | 2010-05-05 23:18:11 | +------+---------------------+ 1 row in set (0.00 sec) Works correctly: mysql> SELECT id, created_at FROM billing_invoices WHERE (billing_invoices.account_id = 5) ORDER BY created_at DESC ; +------+---------------------+ | id | created_at | +------+---------------------+ | 1336 | 2010-05-14 08:05:25 | | 1334 | 2010-05-06 08:05:25 | | 1331 | 2010-05-05 23:18:11 | +------+---------------------+ 3 rows in set (0.01 sec) Works correctly with limit: mysql> SELECT id, created_at FROM billing_invoices WHERE (billing_invoices.account_id = 5) ORDER BY created_at DESC limit 1; +------+---------------------+ | id | created_at | +------+---------------------+ | 1336 | 2010-05-14 08:05:25 | +------+---------------------+ 1 row in set (0.01 sec) Additional info: explain SELECT id, created_at FROM billing_invoices WHERE (billing_invoices.account_id = 5) ORDER BY id DESC limit 1; +----+-------------+------------------+-------+--------------------------------------+--------------------------------------+---------+------+------+-------------+ | id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra | +----+-------------+------------------+-------+--------------------------------------+--------------------------------------+---------+------+------+-------------+ | 1 | SIMPLE | billing_invoices | range | index_billing_invoices_on_account_id | index_billing_invoices_on_account_id | 4 | NULL | 3 | Using where | +----+-------------+------------------+-------+--------------------------------------+--------------------------------------+---------+------+------+-------------+

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• Javascript timezone solution needed(taking into account the actual difference in UTC timestamps)

  - by user198729

  I have unix timestamps from time zone X which is not known, the current timestamp(now()) in TZ X is known 1275143019, how to approach a javascript function so that it can generate the datetime in the users current TZ in the format 2010-05-29 15:32:35 ? UPDATE I'm not a unix timestamp expert,if unix timestamp is always the same in different TZ, then I have to change the question a little,so that the current datetime in TZ X is known(like 2010-05-29 22:32:28),and the other datetime is also in this format,how to convert them to the user's TZ based on the difference between now() ? UPDATE Something strange from MySQL: On server: mysql> select now(); +---------------------+ | now() | +---------------------+ | 2010-05-29 18:34:30 | +---------------------+ 1 row in set (0.00 sec) mysql> select UNIX_TIMESTAMP(); +------------------+ | UNIX_TIMESTAMP() | +------------------+ | 1275143674 | +------------------+ 1 row in set (0.00 sec) On local: mysql> select now(); +---------------------+ | now() | +---------------------+ | 2010-05-29 22:41:30 | +---------------------+ 1 row in set (0.00 sec) mysql> select UNIX_TIMESTAMP(); +------------------+ | UNIX_TIMESTAMP() | +------------------+ | 1275144091 | +------------------+ 1 row in set (0.00 sec) Why the difference between now() (2010-05-29 22:41:30-2010-05-29 18:34:30=6hours) and UNIX_TIMESTAMP() (1275144091 - 1275143674 = 417seconds) is not the same ?

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• Esper generating episodes

  - by Jasonojh

  I would like to use Esper to generate episodes of events. I am trying to detect the changes in robot movement during each time period and was wondering what would be the best way of implementation. The rules for generation of episodes from the events would be If the new event time(eg. 7sec, robot A) of a robot is more than 3 sec than the latest event(eg. 3 sec, robot A) of the same robot, the new event belongs to a new episode. Each episode should represent only one robot (eg. 2sec, robotA and 3sec, robotB should output 2 episodes) Input data: Event Time Robot Position 1 1 A 0 2 2 A 1 3 6 A 2 Output data should be: Array[0]={Event 1,Event 2} Array[1]={Event 3} //more than 3 sec Input data: Event Time Robot Position 1 1 A 0 2 2 A 1 3 4 B 0 4 6 A 2 Output data should be: Array[0]={Event 1,Event 2} Array[1]={Event 3} //different robot Array[2]={Event 4} Please help provide suggestions. I have tried using mulitple listeners, one for each robot, to create episodes and it works but I am trying to use a single EPL statement to do it. I have tried win:time_accum(3sec) group by robot but the second example output: Array[0]={Event 1,Event 2, Event 4} Array[1]={Event 3} as the time window is shifted everytime an event comes in, the system still thinks that event 4 is less than 3 sec due to event 3. how do I create a unique time window for each robot? Thank you for your suggestions and any help is greatly appreciated.

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• pointer to a pointer in a linked list

  - by user1596497

  I'm trying to set a linked list head through pointer to a pointer. I can see inside the function that the address of the head pointer is changing but as i return to the main progran it becomes NULL again. can someone tell me what I'm doing wrong ?? #include <stdio.h> #include <stdlib.h> typedef void(*fun_t)(int); typedef struct timer_t { int time; fun_t func; struct timer_t *next; }TIMER_T; void add_timer(int sec, fun_t func, TIMER_T *head); void run_timers(TIMER_T **head); void timer_func(int); int main(void) { TIMER_T *head = NULL; int time = 1; fun_t func = timer_func; while (time < 1000) { printf("\nCalling add_timer(time=%d, func=0x%x, head=0x%x)\n", time, func, &head); add_timer(time, func, head); time *= 2; } run_timers(&head); return 0; } void add_timer(int sec, fun_t func, TIMER_T *head) { TIMER_T ** ppScan=&head; TIMER_T *new_timer = NULL; new_timer = (TIMER_T*)malloc(sizeof(TIMER_T)); new_timer->time = sec; new_timer->func = func; new_timer->next = NULL; while((*ppScan != NULL) && (((**ppScan).time)<sec)) ppScan = &(*ppScan)->next; new_timer->next = *ppScan; *ppScan = new_timer; }

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• A basic load test question

  - by user236131

  I have a very basic load test question. I am running a load test using VSTS 2008 and I have test rig with controller + 10 agents. This load test is against a SharePoint farm I have. My goal of the load test is to find out the resource utilization on web+app+db tiers of my farm for any given load scenario. An example of a load scenario is Usage profile: Average collaboration (as defined by SCCP) User Load: 500 (using step load pattern=a step of 50 every 2 mins and a warm up time of 2mins for every step) Think time: 0 Load duration: 8hrs Now, the question is: Is it fair to expect that metrics like Requests/sec, %processor time on web front end / App / DB, Test/sec, and etc become flat or enter a steady state at one point in time during the load test. Like I said, the goal is not to create a bottleneck but to only measure the utilization of resources by the above load profile. I am asking this question because I see something different. At one point in the load test, requests/sec becomes more or less flat. But processor utilization on the web/DB servers keeps increasing. After digging through the data a bit, I see that "tests running" counter also steadily increased over time. So, if I run the load test for more than 8hrs, %processor may go up further. This way, I don't know what to consider as the load excreted by the load profile. What does this "tests running" counter really signify? How is this different from tests/sec? Another question is: how can I find out why "tests running" counter shows an increase overtime? Thanks for your time

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• Help Me Make My Pascal Program Display Multiple Names Which Were Entered Plz.

  - by Sketchie

  Hey,Guys I'm having trouble displaying names using arrays in my Pascal program. But first heres the question I'm writing the program to answer : Develop pseudocode that accepts as input the name of an unspecified number of masqueraders who each have paid the full cost of their costume and the amount each has paid. A masquerader may have paid for a costume in any of the five sections in the band. The algorithm should determine the section in which the masquerader plays, based on the amount he/she has paid for the costume. The algorithm should also determine the number of masqueraders who have paid for costumes in each section. The names of persons and the section for which they have paid should be printed. A listing of the sections and the total number of persons registered to play in each section should also be printed, along with the total amount paid in each section. And here's what I've done so far(It's a bit messy): program Maqueprgrm; uses wincrt; type names=array [1..30]of string; var name:string; s1_nms:names; s2_nms:names; s3_nms:names; s4_nms:names; s5_nms:names; amt_paid:integer; stop,x,full,ins,ttl1,ttl2,ttl3,ttl4,ttl5,sec_1,sec_2,sec_3,sec_4,sec_5,sec:integer; begin stop := 0; writeln ('To Begin Data Collecting Section Press 1, To End Press 0'); readln(stop); while stop <0 do begin for x:= 1 to 30 do x:= x+1; writeln ('Please Enter The Name of Masquerader.'); readln (name); writeln ('Please Enter The Amount Paid For Costume.'); readln (amt_paid); IF amt_paid = 144 THEN Begin full:=full+1; {people who paid in full + 1} sec_1:=sec_1+1; {people in this section + 1} ttl1:= ttl1+amt_paid; {total money earned in this section + amount person paid} s1_nms[x]:= name; {People's names in this section plus current entry's name} End else IF amt_paid = 184 then Begin ins:=ins+1; sec_1:=sec_1+1; ttl1:=ttl1+amt_paid; s1_nms[x]:= name; end else IF amt_paid = 198 then Begin full:=full+1; sec_2:=sec_2+1; ttl2:=ttl2+amt_paid; s2_nms[x]:= 'name'; end else IF amt_paid = 153 then Begin ins:=ins+1; sec_2:=sec_2+1; ttl2:=ttl2+amt_paid; s2_nms[x]:= 'name'; end else IF amt_paid = 264 then Begin full:=full+1; sec_3:=sec_3+1; ttl3:=ttl3+amt_paid; s3_nms[x]:= 'name'; end else IF amt_paid = 322 then Begin ins:=ins+1; sec_3:=sec_3+1; ttl3:=ttl3+amt_paid; s3_nms[x]:= 'name'; end else IF amt_paid = 315 then Begin full:=full+1; sec_4:=sec_4+1; ttl4:=ttl4+amt_paid; s4_nms[x]:= 'name'; end else IF amt_paid = 402 then Begin ins:=ins+1; sec_4:=sec_4+1; ttl4:=ttl4+amt_paid; s4_nms[x]:= 'name'; end else IF amt_paid = 382. then Begin ins:=ins+1; sec_4:=sec_4+1; ttl4:=ttl4+amt_paid; s4_nms[x]:= 'name'; end else IF amt_paid = 488 then Begin ins:=ins+1; sec_5:=sec_5+1; ttl5:=ttl5+amt_paid; s5_nms[x]:= 'name'; end else begin Writeln ('Invalid Entry'); For x:= 1 to 30 do end; writeln (' To Enter More Data Press 1, To Print Data and Calculations Press 0'); Readln (stop); End; writeln ('For Information on Sections Press 1, 2, 3, 4, or 5 Respectively'); Readln (sec); IF Sec= 1 THEN Begin for x:= 1 to 30 do; begin writeln ('The Number of Revelers in This Section is ',Sec_1,'.'); Writeln ('The Number of Revelers in the Band Who Paid in Full Is ', Full,'.'); Writeln ('The Number of Revelers in the Band Who Paid in Installments is ', Ins ,'.'); Writeln ('The Names of Revelers in This Section is ', S1_Nms[x], '.'); Writeln ('The Total Amount Collected By This Section Is ', Ttl1, '.'); End; end else IF Sec= 2 THEN Begin For x:= 1 to 30 do begin Writeln ('The Number of Revelers in This Section is ', Sec_2,'.'); Writeln ('The Number of Revelers in the Band Who Paid in Full Is ', Full,'.'); Writeln ('The Number of Revelers in the Band Who Paid in Installments is ', Ins ,'.'); Writeln ('The Names of Revelers in This Section is ', S2_Nms[x] ,'.'); Writeln ('The Total Amount Collected By This Section Is ', Ttl2, '.'); End; End else IF Sec= 3 THEN Begin For x:= 1 to 30 do begin writeln ('The Number of Revelers in This Section is ', Sec_3,'.'); Writeln ('The Number of Revelers in the Band Who Paid in Full Is ', Full,'.'); Writeln ('The Number of Revelers in the Band Who Paid in Installments is ', Ins ,'.'); Writeln ('The Names of Revelers in This Section is ', S3_Nms[x] ,'.'); Writeln ('The Total Amount Collected By This Section Is ', Ttl3, '.'); End; End else IF Sec= 4 THEN Begin For x:= 1 to 30 do begin writeln ('The Number of Revelers in This Section is ', Sec_4,'.'); Writeln ('The Number of Revelers in the Band Who Paid in Full Is ', Full,'.'); Writeln ('The Number of Revelers in the Band Who Paid in Installments is ', Ins, '.'); Writeln ('The Names of Revelers in This Section is ', S4_Nms [x],'.'); Writeln ('The Total Amount Collected By This Section Is ', Ttl4 ,'.'); End; End else IF Sec= 5 THEN Begin For x:= 1 to 30 do begin writeln ('The Number of Revelers in This Section is ', Sec_5,'.'); Writeln ('The Number of Revelers in the Band Who Paid in Full Is ', Full,'.'); Writeln ('The Number of Revelers in the Band Who Paid in Installments is ', Ins, '.'); Writeln ('The Names of Revelers in This Section is ', S5_Nms[x], '.'); Writeln ('The Total Amount Collected By This Section Is ', Ttl5 ,'.'); End; End else BEGIN Writeln ('Invalid Entry. For Information on Sections Press 1, 2, 3, 4, or 5 Respectively. '); End; end. The result I keep getting is that for the names in the section it is only the name of the last person entered that is displayed. For example it would display: The number of revelers in this section is 2 The number of revelers in the band who paid in full is 2 {Band is the whole thing divided into 5 section} The number of revelers in the band who paid in installments is 0 The names of revelers in this section is Amy Total amount collected by this section is 288 So yea, the program only displays "Amy" even though I entered more than 1 name. Do you guys know how to fix it also if it's not asking too much could you help me to make a while loop for the last portion of the program so that after the user sees the info for a section he can see another section. It sucks that I've been working on it for a while but if it doesn't run properly tomorrow I'll fail. Help would be greatly appreciated and responses are welcome anytime cause i'll be up anyway. P.S. Sorry for the long post.

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• Apache2 benchmarks - very poor performance

  - by andrzejp

  I have two servers on which I test the configuration of apache2. The first server: 4GB of RAM, AMD Athlon (tm) 64 X2 Dual Core Processor 5600 + Apache 2.2.3, mod_php, mpm prefork: Settings: Timeout 100 KeepAlive On MaxKeepAliveRequests 150 KeepAliveTimeout 4 <IfModule Mpm_prefork_module> StartServers 7 MinSpareServers 15 MaxSpareServers 30 MaxClients 250 MaxRequestsPerChild 2000 </ IfModule> Compiled in modules: core.c mod_log_config.c mod_logio.c prefork.c http_core.c mod_so.c Second server: 8GB of RAM, Intel (R) Core (TM) i7 CPU [email protected] Apache 2.2.9, **fcgid, mpm worker, suexec** PHP scripts are running via fcgi-wrapper Settings: Timeout 100 KeepAlive On MaxKeepAliveRequests 100 KeepAliveTimeout 4 <IfModule Mpm_worker_module> StartServers 10 MaxClients 200 MinSpareThreads 25 MaxSpareThreads 75 ThreadsPerChild 25 MaxRequestsPerChild 1000 </ IfModule> Compiled in modules: core.c mod_log_config.c mod_logio.c worker.c http_core.c mod_so.c The following test results, which are very strange! New server (dynamic content - php via fcgid+suexec): Server Software: Apache/2.2.9 Server Hostname: XXXXXXXX Server Port: 80 Document Path: XXXXXXX Document Length: 179512 bytes Concurrency Level: 10 Time taken for tests: 0.26276 seconds Complete requests: 1000 Failed requests: 0 Total transferred: 179935000 bytes HTML transferred: 179512000 bytes Requests per second: 38.06 Transfer rate: 6847.88 kb/s received Connnection Times (ms) min avg max Connect: 2 4 54 Processing: 161 257 449 Total: 163 261 503 Old server (dynamic content - mod_php): Server Software: Apache/2.2.3 Server Hostname: XXXXXX Server Port: 80 Document Path: XXXXXX Document Length: 187537 bytes Concurrency Level: 10 Time taken for tests: 173.073 seconds Complete requests: 1000 Failed requests: 22 (Connect: 0, Length: 22, Exceptions: 0) Total transferred: 188003372 bytes HTML transferred: 187546372 bytes Requests per second: 5777.91 Transfer rate: 1086267.40 kb/s received Connnection Times (ms) min avg max Connect: 3 3 28 Processing: 298 1724 26615 Total: 301 1727 26643 Old server: Static content (jpg file) Server Software: Apache/2.2.3 Server Hostname: xxxxxxxxx Server Port: 80 Document Path: /images/top2.gif Document Length: 40486 bytes Concurrency Level: 100 Time taken for tests: 3.558 seconds Complete requests: 1000 Failed requests: 0 Write errors: 0 Total transferred: 40864400 bytes HTML transferred: 40557482 bytes Requests per second: 281.09 [#/sec] (mean) Time per request: 355.753 [ms] (mean) Time per request: 3.558 [ms] (mean, across all concurrent requests) Transfer rate: 11217.51 [Kbytes/sec] received Connection Times (ms) min mean[+/-sd] median max Connect: 3 11 4.5 12 23 Processing: 40 329 61.4 339 1009 Waiting: 6 282 55.2 293 737 Total: 43 340 63.0 351 1020 New server - static content (jpg file) Server Software: Apache/2.2.9 Server Hostname: XXXXX Server Port: 80 Document Path: /images/top2.gif Document Length: 40486 bytes Concurrency Level: 100 Time taken for tests: 3.571531 seconds Complete requests: 1000 Failed requests: 0 Write errors: 0 Total transferred: 41282792 bytes HTML transferred: 41030080 bytes Requests per second: 279.99 [#/sec] (mean) Time per request: 357.153 [ms] (mean) Time per request: 3.572 [ms] (mean, across all concurrent requests) Transfer rate: 11287.88 [Kbytes/sec] received Connection Times (ms) min mean[+/-sd] median max Connect: 2 63 24.8 66 119 Processing: 124 278 31.8 282 391 Waiting: 3 70 28.5 66 164 Total: 126 341 35.9 350 443 I noticed that in the apache error.log is a lot of entries: [notice] mod_fcgid: call /www/XXXXX/public_html/forum/index.php with wrapper /www/php-fcgi-scripts/XXXXXX/php-fcgi-starter What I have omitted, or do not understand? Such a difference in requests per second? Is it possible? What could be the cause?

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• Ubuntu server has slow performance

  - by Rich

  I have a custom built Ubuntu 11.04 server with a 6 disk software RAID 10 primary drive. On it I'm primarily running a PostgreSQL and a few other utilities that stream data from the web. I often find after a few hours of uptime the server starts to lag with all kinds of processes. For example, it may take 10-15 seconds after log-in to get a shell prompt. It might take 5-10 seconds for top to come up. An ls might take a second or two. When I look at top there is almost no CPU usage. There's a fair amount of memory used by the PostgreSQL server but not enough to bleed into swap. I have no idea where to go from here, other than to suspect the RAID10 (I've only ever had software RAID 1's before). Edit: Output from top: top - 11:56:03 up 1:46, 3 users, load average: 0.89, 0.73, 0.72 Tasks: 119 total, 1 running, 118 sleeping, 0 stopped, 0 zombie Cpu(s): 0.2%us, 0.0%sy, 0.0%ni, 93.5%id, 6.2%wa, 0.0%hi, 0.0%si, 0.0%st Mem: 16325596k total, 3478248k used, 12847348k free, 20880k buffers Swap: 19534176k total, 0k used, 19534176k free, 3041992k cached PID USER PR NI VIRT RES SHR S %CPU %MEM TIME+ COMMAND 1747 woodsp 20 0 109m 10m 4888 S 1 0.1 0:42.70 python 357 root 20 0 0 0 0 S 0 0.0 0:00.40 jbd2/sda3-8 1 root 20 0 24324 2284 1344 S 0 0.0 0:00.84 init 2 root 20 0 0 0 0 S 0 0.0 0:00.00 kthreadd 3 root 20 0 0 0 0 S 0 0.0 0:00.24 ksoftirqd/0 6 root RT 0 0 0 0 S 0 0.0 0:00.00 migration/0 7 root RT 0 0 0 0 S 0 0.0 0:00.01 watchdog/0 8 root RT 0 0 0 0 S 0 0.0 0:00.00 migration/1 10 root 20 0 0 0 0 S 0 0.0 0:00.02 ksoftirqd/1 12 root RT 0 0 0 0 S 0 0.0 0:00.01 watchdog/1 13 root RT 0 0 0 0 S 0 0.0 0:00.00 migration/2 14 root 20 0 0 0 0 S 0 0.0 0:00.00 kworker/2:0 15 root 20 0 0 0 0 S 0 0.0 0:00.00 ksoftirqd/2 16 root RT 0 0 0 0 S 0 0.0 0:00.01 watchdog/2 17 root RT 0 0 0 0 S 0 0.0 0:00.00 migration/3 18 root 20 0 0 0 0 S 0 0.0 0:00.00 kworker/3:0 19 root 20 0 0 0 0 S 0 0.0 0:00.02 ksoftirqd/3 20 root RT 0 0 0 0 S 0 0.0 0:00.01 watchdog/3 21 root 0 -20 0 0 0 S 0 0.0 0:00.00 cpuset 22 root 0 -20 0 0 0 S 0 0.0 0:00.00 khelper 23 root 20 0 0 0 0 S 0 0.0 0:00.00 kdevtmpfs 24 root 0 -20 0 0 0 S 0 0.0 0:00.00 netns 26 root 20 0 0 0 0 S 0 0.0 0:00.00 sync_supers df -h rpsharp@ncp-skookum:~$ df -h Filesystem Size Used Avail Use% Mounted on /dev/sda3 1.8T 549G 1.2T 32% / udev 7.8G 4.0K 7.8G 1% /dev tmpfs 3.2G 492K 3.2G 1% /run none 5.0M 0 5.0M 0% /run/lock none 7.8G 0 7.8G 0% /run/shm /dev/sda2 952M 128K 952M 1% /boot/efi /dev/md0 5.5T 562G 4.7T 11% /usr/local free -m psharp@ncp-skookum:~$ free -m total used free shared buffers cached Mem: 15942 3409 12533 0 20 2983 -/+ buffers/cache: 405 15537 Swap: 19076 0 19076 tail -50 /var/log/syslog Jul 3 06:31:32 ncp-skookum rsyslogd: [origin software="rsyslogd" swVersion="5.8.6" x-pid="1070" x-info="http://www.rsyslog.com"] rsyslogd was HUPed Jul 3 06:39:01 ncp-skookum CRON[14211]: (root) CMD ( [ -x /usr/lib/php5/maxlifetime ] && [ -d /var/lib/php5 ] && find /var/lib/php5/ -depth -mindepth 1 -maxdepth 1 -type f -cmin +$(/usr/lib/php5/maxlifetime) ! -execdir fuser -s {} 2>/dev/null \; -delete) Jul 3 06:40:01 ncp-skookum CRON[14223]: (smmsp) CMD (test -x /etc/init.d/sendmail && /usr/share/sendmail/sendmail cron-msp) Jul 3 07:00:01 ncp-skookum CRON[14328]: (woodsp) CMD (/home/woodsp/bin/mail_tweetupdate # email an update) Jul 3 07:00:01 ncp-skookum CRON[14327]: (smmsp) CMD (test -x /etc/init.d/sendmail && /usr/share/sendmail/sendmail cron-msp) Jul 3 07:00:28 ncp-skookum sendmail[14356]: q63E0SoZ014356: from=woodsp, size=2328, class=0, nrcpts=2, msgid=<[email protected]>, relay=woodsp@localhost Jul 3 07:00:29 ncp-skookum sm-mta[14357]: q63E0Si6014357: from=<[email protected]>, size=2569, class=0, nrcpts=2, msgid=<[email protected]>, proto=ESMTP, daemon=MTA-v4, relay=localhost [127.0.0.1] Jul 3 07:00:29 ncp-skookum sendmail[14356]: q63E0SoZ014356: to=Spencer Wood <[email protected]>,Martin Lacayo <[email protected]>, ctladdr=woodsp (1004/1005), delay=00:00:01, xdelay=00:00:01, mailer=relay, pri=62328, relay=[127.0.0.1] [127.0.0.1], dsn=2.0.0, stat=Sent (q63E0Si6014357 Message accepted for delivery) Jul 3 07:00:29 ncp-skookum sm-mta[14359]: STARTTLS=client, relay=mx3.stanford.edu., version=TLSv1/SSLv3, verify=FAIL, cipher=DHE-RSA-AES256-SHA, bits=256/256 Jul 3 07:00:29 ncp-skookum sm-mta[14359]: q63E0Si6014357: to=<[email protected]>,<[email protected]>, ctladdr=<[email protected]> (1004/1005), delay=00:00:01, xdelay=00:00:00, mailer=esmtp, pri=152569, relay=mx3.stanford.edu. [171.67.219.73], dsn=2.0.0, stat=Sent (Ok: queued as 8F3505802AC) Jul 3 07:09:08 ncp-skookum CRON[14396]: (root) CMD ( [ -x /usr/lib/php5/maxlifetime ] && [ -d /var/lib/php5 ] && find /var/lib/php5/ -depth -mindepth 1 -maxdepth 1 -type f -cmin +$(/usr/lib/php5/maxlifetime) ! -execdir fuser -s {} 2>/dev/null \; -delete) Jul 3 07:17:01 ncp-skookum CRON[14438]: (root) CMD ( cd / && run-parts --report /etc/cron.hourly) Jul 3 07:20:01 ncp-skookum CRON[14453]: (smmsp) CMD (test -x /etc/init.d/sendmail && /usr/share/sendmail/sendmail cron-msp) Jul 3 07:39:01 ncp-skookum CRON[14551]: (root) CMD ( [ -x /usr/lib/php5/maxlifetime ] && [ -d /var/lib/php5 ] && find /var/lib/php5/ -depth -mindepth 1 -maxdepth 1 -type f -cmin +$(/usr/lib/php5/maxlifetime) ! -execdir fuser -s {} 2>/dev/null \; -delete) Jul 3 07:40:01 ncp-skookum CRON[14562]: (smmsp) CMD (test -x /etc/init.d/sendmail && /usr/share/sendmail/sendmail cron-msp) Jul 3 08:00:01 ncp-skookum CRON[14668]: (smmsp) CMD (test -x /etc/init.d/sendmail && /usr/share/sendmail/sendmail cron-msp) Jul 3 08:09:01 ncp-skookum CRON[14724]: (root) CMD ( [ -x /usr/lib/php5/maxlifetime ] && [ -d /var/lib/php5 ] && find /var/lib/php5/ -depth -mindepth 1 -maxdepth 1 -type f -cmin +$(/usr/lib/php5/maxlifetime) ! -execdir fuser -s {} 2>/dev/null \; -delete) Jul 3 08:17:01 ncp-skookum CRON[14766]: (root) CMD ( cd / && run-parts --report /etc/cron.hourly) Jul 3 08:20:01 ncp-skookum CRON[14781]: (smmsp) CMD (test -x /etc/init.d/sendmail && /usr/share/sendmail/sendmail cron-msp) Jul 3 08:39:01 ncp-skookum CRON[14881]: (root) CMD ( [ -x /usr/lib/php5/maxlifetime ] && [ -d /var/lib/php5 ] && find /var/lib/php5/ -depth -mindepth 1 -maxdepth 1 -type f -cmin +$(/usr/lib/php5/maxlifetime) ! -execdir fuser -s {} 2>/dev/null \; -delete) Jul 3 08:40:01 ncp-skookum CRON[14892]: (smmsp) CMD (test -x /etc/init.d/sendmail && /usr/share/sendmail/sendmail cron-msp) Output of hdparm -t /dev/sd{a,b,c,d,e,f} This looks suspicious? /dev/sda: Timing buffered disk reads: 2 MB in 4.84 seconds = 423.39 kB/sec /dev/sdb: Timing buffered disk reads: 420 MB in 3.01 seconds = 139.74 MB/sec /dev/sdc: Timing buffered disk reads: 390 MB in 3.00 seconds = 129.87 MB/sec /dev/sdd: Timing buffered disk reads: 416 MB in 3.00 seconds = 138.51 MB/sec /dev/sde: Timing buffered disk reads: 422 MB in 3.00 seconds = 140.50 MB/sec /dev/sdf: Timing buffered disk reads: 416 MB in 3.01 seconds = 138.26 MB/sec

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• edit .avi movie cut

  - by c0mrade

  Hello everybody, how can I edit .avi file .. let say I want first 20 seconds to play and from 120th sec untill 150th sec .. and take that out of the entire movie, with which software I can do that ?

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• Just to not to be ignorant.

  - by atch

  Could anyone explain to me why is it that producers of processors claim that their processor can perform so many thousands (or millions) operations per second and yet typical program (Word, VS etc.) on my machine with 4GB, 3500hz starts with no less than 10 sec. Have to mention that I've just formatted disk and tick any necessary boxes to optimize my machine. So if for example outlook starts in 10 sec I wonder how many millions of operations have to be performed to run such program? Thanks

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• wondering how much data bandwidth can a 3G gsm cell tower can support?

  - by Karim

  i was always wondering how many simaltinues users can a 3G tower supports with its data rates? i mean they advertize 28.8Mb/Sec for the 3G Data but in reallity if a lot of people use it say 10 , it wont give 288Mb/Sec bandwidth. i didnt find anywhere where such information is published so i thought to ask here. dont know why the cell operators keep it such a secret :)

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• How to specify what network interface to use with TTCP or IPERF?

  - by Sammy

  The PC has two Gigabit Ethernet ports. They function as two separate network adapters. I'm trying to do a simple loopback test between the two. I've tried TTCP and IPERF. They're giving me hard time because I'm using the same physical PC. Using pcattcp... On the receiver end: C:\PCATTCP-0114>pcattcp -r PCAUSA Test TCP Utility V2.01.01.14 (IPv4/IPv6) IP Version : IPv4 Started TCP Receive Test 0... TCP Receive Test Local Host : GIGA ************** Listening...: On TCPv4 0.0.0.0:5001 Accept : TCPv4 0.0.0.0:5001 <- 10.1.1.1:33904 Buffer Size : 8192; Alignment: 16384/0 Receive Mode: Sinking (discarding) Data Statistics : TCPv4 0.0.0.0:5001 <- 10.1.1.1:33904 16777216 bytes in 0.076 real seconds = 215578.95 KB/sec +++ numCalls: 2052; msec/call: 0.038; calls/sec: 27000.000 C:\PCATTCP-0114> On the transmitter end: C:\PCATTCP-0114>PCATTCP.exe -t 10.1.1.1 PCAUSA Test TCP Utility V2.01.01.14 (IPv4/IPv6) IP Version : IPv4 Started TCP Transmit Test 0... TCP Transmit Test Transmit : TCPv4 0.0.0.0 -> 10.1.1.1:5001 Buffer Size : 8192; Alignment: 16384/0 TCP_NODELAY : DISABLED (0) Connect : Connected to 10.1.1.1:5001 Send Mode : Send Pattern; Number of Buffers: 2048 Statistics : TCPv4 0.0.0.0 -> 10.1.1.1:5001 16777216 bytes in 0.075 real seconds = 218453.33 KB/sec +++ numCalls: 2048; msec/call: 0.037; calls/sec: 27306.667 C:\PCATTCP-0114> It's responding alright. But why does it say 0.0.0.0? Is it passing through only one of the network adapters? I want 10.1.1.1 to be the server (receiver) and 10.1.1.2 to be the client (transmitter). These are the IP addresses assigned manually to each network adapter. How do I specify these addresses in TTCP? There is also the IPERF tool which has the -B option. Unfortunately I've been only able to use this option to bind the server to the 10.1.1.1 address. I was unable to bind the client to the 10.1.1.2 address. I might be doing it wrong. Can the -B option be used for both the server as well as the client side? What does the syntax look like for the client?

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• MySQL Execution Time Spikes

  - by Brett

  I am having issues with MySQL all of the sudden today. Details: OS: CentOS release 5.7 Server type: Parallels virtuozzo container running on mediatemple DV 4.0 package Average total memory usage: <500mb Total memory usage allowed: 1gb (part of shared pool for emergency only, users are only guaranteed 500mb) Processor: 1ghz Main database sizes with most usage: 275mb & 107mb server stack: nginx 1.0.10, mysql 5.1.54, php 5.3.8 with php-fpm innodb_buffer_pool_size=100M php-fpm max children: 5 Webapps: custom php-based sites, magento & drupal slow query timeout is set to 1 second Steps I completed towards diagnosis: Cannot restart container yet - I will try later tonight when our domestic traffic has dropped Enabled mysql and php-fpm slowlog. Found functions that did DB queries in php-fpm slowlog were taking over 1s to complete at times Found some simple queries in mysql slowlog taking well over 1s to complete that should take less than 1s. Most interesting - execution time seems to spike at times. A query will take .2s a couple times, then one time it will take 8s to run the same query. These results were verified by running raw SQL queries through mysql command line. Top does not reveal anything too interesting Only resource related thing i can see is load averages much higher than normal Up until today, mysql has been fine, there have been no major changes to the db since yesterday. Sometimes things are so bad, I am seeing bad gateway errors after 60s of execution time. Innodb is doing on average 300-1400 reads/sec. Mysql is doing 3-10 queries/sec slow query count in 2 hours uptime is 171 (with slow timeout at 1 second) Tried restarting mysql, nginx, php-fpm multiple times For example: UPDATE `catalogsearch_query` SET `query_text` = 'EW 90', `num_results` = '7532', `popularity` = '99180', `redirect` = NULL, `synonym_for` = NULL, `store_id` = '1', `display_in_terms` = '1', `is_active` = '1', `is_processed` = '1', `updated_at` = '2012-05-08 21:38:31' WHERE (query_id='31'); This query took 17sec to complete one time, rest of the time around .079 sec. But varies, sometimes 1sec, sometimes .004 sec. This is running the same query, over and over with a couple seconds time in between each. Most tables are innodb, and sometimes I noticed the lock time taking 90% of the query execution time, but most of the time lock time is insignificant. Any idea what's going on here?

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• How much data bandwidth can a 3G gsm cell tower can support?

  - by Karim

  I was always wondering how many simultaneous users can a 3G tower supports with its data rates? I mean they advertise 28.8Mb/Sec for the 3G Data but in reality if a lot of people use it say 10 , it wont give 288Mb/Sec bandwidth. I didn't find anywhere where such information is published so I thought to ask here. Don' know why the cell operators keep it such a secret :)

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• How to get higher download rate than upload rate

  - by user23950

  i'm using bandwidthplace.com to measure my internet speed. And here it is: Download Speed: 422 kbps (52.8 KB/sec transfer rate) Upload Speed: 202 kbps (25.3 KB/sec transfer rate) Can you please explain to me how did they get the 52.8 transfer rate. And how do I get to lower the upload speed in order for me to get higher download speed.

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• Why is Hard Disk Access Slow Through a Virtual Machine?

  - by Earl

  Why is throughput to an external hard drive from a virtual machine much slower than through the host? Access is generally 30MB/sec from the host and 4MB/sec frm the client. Is this normal?

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• how to disable these logs on the screen?

  - by user62367

  using Fedora 14: http://pastebin.com/raw.php?i=jUvcfugw i mount an anonym Samba share [checks it in every 5 sec] it's working, ok, great! But: when i shut down my Fedora box, i can see the lines containing this scripts lines! Many times, about ~50x on the screen. How could i disable these lines when shutting down? I [and other people] don't want to see those lines for about ~ 5 sec Thank you!

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• Why is Windows "stuck" on the Welcome screen for so long?

  - by Perdana Putra

  I use Windows 7 with a laptop specifications processor core (Core i3), 2 GB DDR3 RAM, the remaining capacity on the system partition (25 GB). I do not know why the "welcome screen" takes a long time (about 40 sec), but yesterday only took about 10 sec., I tried to defragment the disk and do a virus & spyware scan with antivirus, but still the "Welcome screen" comes along. How do I get the welcome screen to pass by faster when Windows boots up?

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• Can I put a SATA2 HDD into a laptop supporting SATA1?

  - by user22559

  I have a laptop that supports SATA1 (1.5 GB/sec) The HDD for it has bad sectors, and I want to buy another one. It seems that where I live, SATA1 notebook HDDs aren't really available (only if you wait for a few weeks for them to be delivered), and they cost more than SATA2 HDDs. So I was wondering if I buy a SATA2 (3GB/sec) HDD, will it work without problems on my laptop? The laptop is an HP Pavilion DV6000

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• single web app multible webservers

  - by Ramakrishna

  hi guys, Hi have a prob of load balancing we developed a web app using nearly 1500/- users parallely so the number of users increased we are unable to serve the requests that much of faster, its takes around 10 to 20 sec to load a page if page having heavy weight it takes 1min also. we need to solve this situation and we have to serve each request with in 2 to 3 sec App develped in : asp.net hosted in : IIS 7.5 Machine configuration : Windows server 2008 8GB RAM 1MBPS band width

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• MySQL query cache is enabled but not being used

  - by Yoga

  I've checked the query cache is enabled mysql> SHOW VARIABLES LIKE 'have_query_cache'; +------------------+-------+ | Variable_name | Value | +------------------+-------+ | have_query_cache | YES | +------------------+-------+ 1 row in set (0.00 sec) But seems it is not being used mysql> SHOW STATUS LIKE 'Qcache%'; +-------------------------+----------+ | Variable_name | Value | +-------------------------+----------+ | Qcache_free_blocks | 1 | | Qcache_free_memory | 16759648 | | Qcache_hits | 0 | | Qcache_inserts | 0 | | Qcache_lowmem_prunes | 0 | | Qcache_not_cached | 21555882 | | Qcache_queries_in_cache | 0 | | Qcache_total_blocks | 1 | +-------------------------+----------+ 8 rows in set (0.00 sec) Any reason?

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