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  • topic for final year project

    - by Mrinal Shrivastava
    i am a computer science student and have just entered in my final year. i wanna do a project on something new and exciting in the field of networking dbms os or ai. i am proficient in java c, oracle and am improving my linux skills.. please give me some suggestions for hot topics..

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  • NSDateFormatterFullStyle without year (NSDateFormatter)

    - by Brian Halpin
    Using the user's currentLocale from the device, I want to have a date format exactly like the one generated for NSDateFormatterFullStyle minus the year: [dateFormatter setDateStyle:NSDateFormatterFullStyle]; Friday, 21 September (2012) I've noticed the iPhone app, Living Earth does this and works for all locales, so does the iPhone lock screen. A custom formatter such as, [dateFormatter setDateFormat:@"EEEE, MMMM"]; won't change with localisation. Can anyone shed some light on how to accomplish this? None of the options for date style seem to do this. Thanks

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  • PHP/MYSQL Year Month table for news archive

    - by ee12csvt
    Hi all, I am creating a news archive for my site and want to create an overview page from the following DB table id - Unique identifier newsDate - in a format XXXX-XX-XX title - News Item title details - News item photo - News Item Photo caption - News Item Photo caption update - Timestamp for record The news on the site is current but I hope to add some data from years gone by over the next few months and years. What I want to do is create a new line for each year and highlight the month which corresponds to a record in the DB table, similar to that below. 2002 JAN FEB MAR APR MAY JUN JUL AUG SEP OCT NOV DEC 2004 JAN FEB MAR APR MAY JUN JUL AUG SEP OCT NOV DEC 2005 JAN FEB MAR APR MAY JUN JUL AUG SEP OCT NOV DEC 2008 JAN FEB MAR APR MAY JUN JUL AUG SEP OCT NOV DEC Any help or advice would be much appreciated Cheers

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  • Display relative time in hour, day, month and year

    - by JohnJohnGa
    I wrote a function toBeautyString(epoch) : String which given a epoch, return a string which will display the relative time from now in hour and minute For instance: // epoch: 1346140800 -> Tue, 28 Aug 2012 05:00:00 GMT // and now: 1346313600 -> Thu, 30 Aug 2012 08:00:00 GMT toBeautyString(1346140800) -> "2 days and 3 hours ago" I want now to extend this function to month and year, so it will be able to print: 2 years, 1 month, 3 days and 1 hour ago Only with epoch without any external libraries. The purpose of this function is to give to the user a better way to visualize the time in the past. I found this: Calculating relative time but the granularity is not enough.

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  • Finding begin and end of year/month/day/hour

    - by reto
    I'm using the following snipped to find the begin and end of several time periods in Joda. The little devil on my left shoulder says thats the way to go... but I dont believe him. Could anybody with some joda experience take a brief look and tell me that the little guy is right? (It will be only used for UTC datetime objects) Thank you! /* Year */ private static DateTime endOfYear(DateTime dateTime) { return endOfDay(dateTime).withMonthOfYear(12).withDayOfMonth(31); } private static DateTime beginningOfYear(DateTime dateTime) { return beginningOfMonth(dateTime).withMonthOfYear(1); } /* Month */ private static DateTime endOfMonth(DateTime dateTime) { return endOfDay(dateTime).withDayOfMonth(dateTime.dayOfMonth().getMaximumValue()); } private static DateTime beginningOfMonth(DateTime dateTime) { return beginningOfday(dateTime).withDayOfMonth(1); } /* Day */ private static DateTime endOfDay(DateTime dateTime) { return endOfHour(dateTime).withHourOfDay(23); } private static DateTime beginningOfday(DateTime dateTime) { return beginningOfHour(dateTime).withHourOfDay(0); } /* Hour */ private static DateTime beginningOfHour(DateTime dateTime) { return dateTime.withMillisOfSecond(0).withSecondOfMinute(0).withMinuteOfHour(0); } private static DateTime endOfHour(DateTime dateTime) { return dateTime.withMillisOfSecond(999).withSecondOfMinute(59).withMinuteOfHour(59); }

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  • Year split in Quarters using basic jQuery

    - by Alexander Corotchi
    Hi, I have a interesting question: I want to split the year into 4 quarters. What is the idea, A quarter can be different: The HTML Code: <div class="quarterBody"> <span>04-29-2010</span> <span>06-29-2010</span> <span>08-29-2010</span> </div> jQuery (javascript) is total wrong, I hope that w: $(document).ready(function(){ var quarter1 = to make interval (01-01-2010 to 03-31-2010); var quarter2 = to make interval (03-01-2010 to 06-31-2010); var quarter3 = to make interval (06-01-2010 to 09-31-2010); var quarter4 = to make interval (09-01-2010 to 12-31-2010); ... $(".quarterBody span").each(function(){ var date = Date.parse($(this).text()); //to apply some magic code $(this).addClass(quarterNumber); }); }); OUTPUT: <div class="quarterBody"> <span class="Quarter1">02-29-2010</span> <span class="Quarter2">04-29-2010</span> <span class="Quarter3">08-29-2010</span> ... </div> I know right now it is a stupid way, but I hope that somebody can help me, or suggest an idea how to do that in a better way!! Thanks!

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  • Oracle Date Format Convert Hour-Minute to Interval and Disregard Year-Month-Day

    - by dlite922
    I need to compare an event's half-way midpoint between a start and stop time of day. Right now i'm converting the dates you see on the right, to HH:MM and the comparison works until midnight. the query says: WHERE half BETWEEN pStart and pStop. As you can see below, pStart and pStap have January 1st 2000 dates, this is because the year month day are not important to me... Valid Data: +-------+--------+-------+---------------------+---------------------+---------------------+ | half | pStart | pStop | half2 | pStart2 | pStop2 | +-------+--------+-------+---------------------+---------------------+---------------------+ | 19:00 | 19:00 | 23:00 | 2012-11-04 19:00:00 | 2000-01-01 19:00:00 | 2000-01-01 23:00:00 | | 20:00 | 19:00 | 23:00 | 2012-11-04 20:00:00 | 2000-01-01 19:00:00 | 2000-01-01 23:00:00 | | 21:00 | 19:00 | 23:00 | 2012-11-04 21:00:00 | 2000-01-01 19:00:00 | 2000-01-01 23:00:00 | | 23:00 | 20:00 | 23:00 | 2012-11-05 23:00:00 | 2000-01-01 20:00:00 | 2000-01-01 23:00:00 | +-------+--------+-------+---------------------+---------------------+---------------------+ Now observe what happens when pStop is midnight or later... Valid Data that breaks it: +-------+--------+-------+---------------------+---------------------+---------------------+ | half | pStart | pStop | half2 | pStart2 | pStop2 | +-------+--------+-------+---------------------+---------------------+---------------------+ | 23:00 | 22:00 | 00:00 | 2012-11-04 23:00:00 | 2000-01-01 22:00:00 | 2000-01-01 00:00:00 | | 23:30 | 23:00 | 02:00 | 2012-11-05 23:30:00 | 2000-01-01 23:00:00 | 2000-01-01 02:00:00 | +-------+--------+-------+---------------------+---------------------+---------------------+ Thus my where clause translates to: WHERE 19:00 BETWEEN 22:00 AND 00:00 ...which returns false and I miss those two correct rows above. Question: Is there a way to show those dates as integer interval so that saying half BETWEEN pStart and pStop are correct? I thought about adding 24 when pStop is less than pStart to make 00:00 into 24:00 but don't know an easy way to do that without long string concatenations and number conversions. This would solve the problem because pStart pStop difference will never be longer than 6 hours. Note: (The Query is much more complex. It has other irrelevant date calculations, but the result are show above. DATE_FORMAT(%H:%i) is applied to the first three columns and no formatting to the last three) Thanks for your help:

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  • Java giving incorrect year values

    - by whistler
    Something very, very strange is occurring in my program, and I'm wondering if anyone out there has seen this occur before. And, if so, how to fix it. Basically, I am parsing an csv file...no problem there. One column contains a date and I am taking it in as a String and changing to a Date object. Again, no problem there. The code is as follows: SimpleDateFormat dateFormat = new SimpleDateFormat("MM/dd/yy hh:mm"); Date initialDate = new Date(); try { initialDate = dateFormat.parse(rows.get(0)[8]); System.out.println(initialDate); } catch (ParseException e) { // TODO Auto-generated catch block e.printStackTrace(); } Of course, I'm parsing other columns as well (and those are working fine). So, when I run my program for a small csv file (2.8 MB), the dates come out (i.e. are parsed) perfectly. However, when I run the program for a large csv file (25 MB), the dates are a hot mess. For example, take a look at the year values I am getting (the following is just a tiny portion of the println output from the code above): 1000264 at Sun Nov 05 15:30:00 EST 2186 1000320 at Sat Mar 04 17:30:00 EST 2169 1000347 at Sat Apr 01 09:45:00 EDT 2169 1000413 at Tue Jul 09 13:00:00 EDT 2182 1000638 at Fri Dec 11 13:45:00 EST 2167 1000667 at Wed Dec 10 10:00:00 EST 2188 1000690 at Mon Jan 02 13:00:00 EST 2169 1000843 at Thu Feb 11 13:30:00 EST 2196 In actuality, the years are in the realm of 1990-2006 or so. Again, this does not happen with the small csv file. Does anyone know what's going on here and how I can fix it? I need to process the large csv file (the small one was just for testing purposes). By request, here are the actual dates in the csv file and after that the value given by the code above: 5/20/03 15:30 5/20/03 15:30 8/30/04 9:00 8/30/04 9:00 12/20/04 10:30 12/20/04 10:30 Sun Nov 05 15:30:00 EST 2186 Sun Nov 05 15:30:00 EST 2186 Sun Nov 05 15:30:00 EST 2186 Thu Dec 08 09:00:00 EST 2196 Tue Dec 12 10:30:00 EST 2186 Tue Dec 12 10:30:00 EST 2186

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  • Is it smart to take a year off from school to get experience?

    - by user134147
    firstly I apologize if this question is not appropriate for the site, but I've seen other similar (though slightly deviant) questions on this sight before and I know the people here are the most qualified to answer my question. Anyways, I'm currently between my sophomore and junior years at a 4 year university, and after a bit of deliberation I've decided on computer science as a major (BA, by the way, as a BS would require me to stay at least an extra year the way our program is set up). I've been interested now in programming for a few months and I've developed a passion for it in a very short time. I began learning C++, migrating to Java recently when I learned my school focuses on this language. Now, I should mention that the concept of higher education has never sat well with me, so part of my motivation for wanting to take time off is to truly challenge myself and see what I can accomplish when I actually try at something. The autodidact in me finds it difficult to focus on my passions while trying to keep a high GPA in unrelated classes. However, I understand the times we live in and therefore would plan to complete my degree after this year. So my question is whether or not the skills I learn in a year off from college could justify the time off from school. Unfortunately, I don't believe I know enough yet to gain any professional experience (internship, etc.) so I would mostly focus my time on learning Java and another language, possibly Wordpress (to gain an understanding of web programming concepts as I have not yet decided what field I want to get into, and to make some money to fund my off-year), and to delve into security concepts, which also interest me. I'm hoping I could work on projects, such as simple applications or contributions to open source software during this time to enhance my resume once I do finish school, so I can find a job out of college easier. I do not want to be the new hire who knows nothing beyond the concepts of his Java textbooks. Does anyone have any input about these thoughts of mine, or any ideas for where I should focus my studies or how high I might set the bar for my work? Thanks a lot everyone!

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  • C++ : integer constant is too large for its type

    - by user38586
    I need to bruteforce a year for an exercise. The compiler keep throwing this error: bruteforceJS12.cpp:8:28: warning: integer constant is too large for its type [enabled by default] My code is: #include <iostream> using namespace std; int main(){ unsigned long long year(0); unsigned long long result(318338237039211050000); unsigned long long pass(1337); while (pass != result) { for (unsigned long long i = 1; i<= year; i++) { pass += year * i * year; } cout << "pass not cracked with year = " << year << endl; ++year; } cout << "pass cracked with year = " << year << endl; } Note that I already tried with unsigned long long result(318338237039211050000ULL); I'm using gcc version 4.8.1 EDIT: Here is the corrected version using InfInt library http://code.google.com/p/infint/ #include <iostream> #include "InfInt.h" using namespace std; int main(){ InfInt year = "113"; InfInt result = "318338237039211050000"; InfInt pass= "1337"; while (pass != result) { for (InfInt i = 1; i<= year; i++) { pass += year * i * year; } cout << "year = " << year << " pass = " << pass << endl; ++year; } cout << "pass cracked with year = " << year << endl; }

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  • JQuery datePicker: start/end date should be within one year

    - by Abu Hamzah
    So if my start date is : 04/22/2010 then my end date selection can be up to 04/22/2011 and after 04/22/2011 are dates all disabled. Here is what I have for both selection start and end date: $(document).ready(function () { $('#endDate').datepicker({ showOn: 'button', buttonImage: '../images/Calendar.png', buttonImageOnly: true, onSelect: function () { }, onClose: function () { $(this).focus(); } }); $('#startDate').datepicker({ showOn: 'button', buttonImage: '../images/Calendar.png', buttonImageOnly: true, onSelect: function (dateText, inst) { $('#endDate').datepicker("option", 'minDate', new Date(dateText)); } , onClose: function () { $(this).focus(); } }); });

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  • interview questions for a 7 year Exp Guy?

    - by harigm
    What kind of approach I(5 Years Exp In Java J2ee Platform) need to follow to interview 8 years exp Guy in Java and J2ee technology. I am asking all the basic questions, where he is able to answer, if he is atleast the bookish knowledge. I want to ask some thing different where we can check his actual skills in technical. Can any one help me with some thoughts where i can use to get some good and technical challenging questions to ask?

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  • How to install Eclipse + PHP Development Tools (PDT) + Debugger on Mac in The Year 2010

    - by aphex5
    I had a lot of trouble installing Eclipse and PDT on my system. It took two days, largely because all the tutorials I could find were out of date (written in 2008, it's 2010 now) and various steps they included were no longer necessary, broken, or irrelevant. I wanted to write my process here so it could be improved upon (via wiki) as time goes on. Install Eclipse without PHP plugin ("Eclipse Classic"). This will give you a complete Eclipse, which I find preferable, as the UI is more fleshed out (e.g. you get a default list of Perspectives, which helps you understand what Perspectives are.) Install PDT SDK with the Help Install New Software menu item. You'd think you'd be done here, but if you try to run something, it'll fail complaining of not having a debugger. Install the Zend Debugger. It'll fail if you try to use the Install New Software option, as many tutorials suggest ("No repository found containing osgi.bundle.org.zend.php.debug.debugger.5.3.7.v20091116".) Instead, download it from http://www.zend.com/en/community/pdt, and manually copy the features/ and plugins/ directory into your Eclipse install (these instructions are not written anywhere). Restart Eclipse Monkey with preferences for a while -- if you followed a previous tutorial and tried to manually add your php executable to Eclipse prefs (/usr/bin/php), remove it (PHP PHP Executables). Set one of the Zend Debugger executables to the default. If you've already tried to execute a .php file, remove the existing "Run" profile you (maybe weren't aware that you) created (Run Debug Configurations...). Eclipse works! You should be able to run a .php file as a script just fine.

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  • ASP.NET Webforms site using HTTPCookie with 100 year timeout times out after 20 minutes

    - by Rob
    I have a site that is using Forms Auth. The client does not want the site session to expire at all for users. In the login page codebehind, the following code is used: // user passed validation FormsAuthentication.Initialize(); // grab the user's roles out of the database String strRole = AssignRoles(UserName.Text); // creates forms auth ticket with expiration date of 100 years from now and make it persistent FormsAuthenticationTicket fat = new FormsAuthenticationTicket(1, UserName.Text, DateTime.Now, DateTime.Now.AddYears(100), true, strRole, FormsAuthentication.FormsCookiePath); // create a cookie and throw the ticket in there, set expiration date to 100 years from now HttpCookie cookie = new HttpCookie(FormsAuthentication.FormsCookieName, FormsAuthentication.Encrypt(fat)) { Expires = DateTime.Now.AddYears(100) }; // add the cookie to the response queue Response.Cookies.Add(cookie); Response.Redirect(FormsAuthentication.GetRedirectUrl(UserName.Text, false)); The web.config file auth section looks like this: <authentication mode="Forms"> <forms name="APLOnlineCompliance" loginUrl="~/Login.aspx" defaultUrl="~/Course/CourseViewer.aspx" /> </authentication> When I log into the site I do see the cookie correctly being sent to the browser and passed back up: However, when I walk away for 20 minutes or so, come back and try to do anything on the site, the login window reappears. This solution was working for a while on our servers - now it's back. The problem doesn't occur on my local dev box running Cassini in VS2008. Any ideas on how to fix this?

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  • Java - How to get current year?

    - by Yatendra Goel
    I want to know the current Date and Time. The code Calendar.getInstance(); represents a date and time of the system on which the program is running and the system date can be wrong. So Is there any way by which I can get correct current date and time irrespective of the date and time of the system on which program is running?

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  • Django: Sum on an date attribute grouped by month/year

    - by Sébastien Piquemal
    Hello, I'd like to put this query from SQL to Django: "select date_format(date, '%Y-%m') as month, sum(quantity) as hours from hourentries group by date_format(date, '%Y-%m') order by date;" The part that causes problem is to group by month when aggregating. I tried this (which seemed logical), but it didn't work : HourEntries.objects.order_by("date").values("date__month").aggregate(Sum("quantity"))

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  • Big-O for Eight Year Olds?

    - by Jason Baker
    I'm asking more about what this means to my code. I understand the concepts mathematically, I just have a hard time wrapping my head around what they mean conceptually. For example, if one were to perform an O(1) operation on a data structure, I understand that the amount of operations it has to perform won't grow because there are more items. And an O(n) operation would mean that you would perform a set of operations on each element. Could somebody fill in the blanks here? Like what exactly would an O(n^2) operation do? And what the heck does it mean if an operation is O(n log(n))? And does somebody have to smoke crack to write an O(x!)?

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  • Is it possible to create a DateFormatter which converts a two-digit year into a four-digit year?

    - by DR
    In my Java application I use a DateFormat instance to parse date inputs. DateFormat fmt; fmt = DateFormat.getDateInstance(DateFormat.DEFAULT) // dd.MM.yyyy for de_DE The problem is that the user insists to enter dates in the form 31.12.11. Unfortunately this is parsed to 31.12.11. (0011-12-31 in ISO format) Instead I want the parsed date to become 31.12.2011 (2011-12-31 in ISO format). Can I modify the date format to somehow parse inputs that way?

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  • How To Create a lookup Table with an NSDate for weekly range (over 5 year period)

    - by EarlyMan
    Unsure how to best achieve this. NSDate *date = [NSDate date]; I need to do a lookup on the date and return a string value. 12/17/2011 < date < 12/23/2011 return "20120101" 12/24/2011 < date < 12/30/2012 return "20120102" 12/31/2011 < date < 01/06/2012 return "20120201" ... 10/20/2012 < date < 10/26/2012 return "20122301" ... 11/02/2013 < date < 11/08/2013 return "20132301" .. for 5 years... for each week date can be any date until Dec. 2017. I do not know the logic behind the return strings so I can't simply calculate the string based on the date. The return string (converted to NSDate in the model) is used successfully as my section for my fetchedresultscontroller. I am not sure how to create a lookup table based on an NSDate or if I need some monster if/case statement.

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