Search Results

Search found 10421 results on 417 pages for 'twitter username'.

Page 92/417 | < Previous Page | 88 89 90 91 92 93 94 95 96 97 98 99  | Next Page >

  • Is sending a hashed password over the wire a security hole?

    - by Ubiquitous Che
    I've come across a system that is in use by a company that we are considering partnering with on a medium-sized (for us, not them) project. They have a web service that we will need to integrate with. My current understanding of proper username/password management is that the username may be stored as plaintext in the database. Every user should have a unique pseudo-random salt, which may also be stored in plaintext. The text of their password must be concatenated with the salt and then this combined string may be hashed and stored in the database in an nvarchar field. So long as passwords are submitted to the website (or web service) over plaintext, everything should be just lovely. Feel free to rip into my understanding as summarized above if I'm wrong. Anyway, back to the subject at hand. The WebService run by this potential partner doesn't accept username and password, which I had anticipated. Instead, it accepts two string fields named 'Username' and 'PasswordHash'. The 'PasswordHash' value that I have been given does indeed look like a hash, and not just a value for a mis-named password field. This is raising a red flag for me. I'm not sure why, but I feel uncomfortable sending a hashed password over the wire for some reason. Off the top of my head I can't think of a reason why this would be a bad thing... Technically, the hash is available on the database anyway. But it's making me nervous, and I'm not sure if there's a reason for this or if I'm just being paranoid.

    Read the article

  • Do entity collections and object sets implement IQueryable<T>?

    - by Chevex
    I am using Entity Framework for the first time and noticed that the entities object returns entity collections. DBEntities db = new DBEntities(); db.Users; //Users is an ObjectSet<User> User user = db.Users.Where(x => x.Username == "test").First(); //Is this getting executed in the SQL or in memory? user.Posts; //Posts is an EntityCollection<Post> Post post = user.Posts.Where(x => x.PostID == "123").First(); //Is this getting executed in the SQL or in memory? Do both ObjectSet and EntityCollection implement IQueryable? I am hoping they do so that I know the queries are getting executed at the data source and not in memory. EDIT: So apparently EntityCollection does not while ObjectSet does. Does that mean I would be better off using this code? DBEntities db = new DBEntities(); User user = db.Users.Where(x => x.Username == "test").First(); //Is this getting executed in the SQL or in memory? Post post = db.Posts.Where(x => (x.PostID == "123")&&(x.Username == user.Username)).First(); // Querying the object set instead of the entity collection. Also, what is the difference between ObjectSet and EntityCollection? Shouldn't they be the same? Thanks in advance!

    Read the article

  • authorise user from mysql database

    - by Jacksta
    I suck at php, and cant find the error here. The script gets 2 variables "username" and "password" from a html from then check them against a MySQL databse. When I run this I get the follow error "Query was empty" <? if ((!$_POST[username]) || (!$_POST[password])) { header("Location: show_login.html"); exit; } $db_name = "testDB"; $table_name = "auth_users"; $connection = @mysql_connect("localhost", "admin", "pass") or die(mysql_error()); $db = @mysql_select_db($db_name, $connection) or die(mysql_error()); $slq = "SELECT * FROM $table_name WHERE username ='$_POST[username]' AND password = password('$_POST[password]')"; $result = @mysql_query($sql, $connection) or die(mysql_error()); $num = mysql_num_rows($result); if ($num != 0) { $msg = "<p>Congratulations, you're authorised!</p>"; } else { header("Location: show_login.html"); exit; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Secret Area</title> </head> <body> <? echo "$msg"; ?> </body> </html>

    Read the article

  • Android Dev: The constructor Intent(new View.OnClickListener(){}, Class<DrinksTwitter>) is undefined

    - by Malcolm Woods Spark
    package com.android.drinksonme; import android.app.Activity; import android.content.Intent; import android.os.Bundle; import android.view.View; import android.view.View.OnClickListener; import android.widget.Button; import android.widget.EditText; import android.widget.TextView; public class Screen2 extends Activity { // Declare our Views, so we can access them later private EditText etUsername; private EditText etPassword; private Button btnLogin; private Button btnSignUp; private TextView lblResult; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); // Get the EditText and Button References etUsername = (EditText)findViewById(R.id.username); etPassword = (EditText)findViewById(R.id.password); btnLogin = (Button)findViewById(R.id.login_button); btnSignUp = (Button)findViewById(R.id.signup_button); lblResult = (TextView)findViewById(R.id.result); // Set Click Listener btnLogin.setOnClickListener(new OnClickListener() { @Override public void onClick(View v) { // Check Login String username = etUsername.getText().toString(); String password = etPassword.getText().toString(); if(username.equals("test") && password.equals("test")){ final Intent i = new Intent(this, DrinksTwitter.class); //error on this line startActivity(i); // lblResult.setText("Login successful."); } else { lblResult.setText("Invalid username or password."); } } }); final Intent k = new Intent(Screen2.this, SignUp.class); btnSignUp.setOnClickListener(new OnClickListener() { public void onClick(View v) { startActivity(k); } }); } }

    Read the article

  • Custom Header in ASIHTTPREQUEST

    - by Sharon Nathaniel
    Here is my problem. I am using ASIHTTPREQUEST to send request and get response. Now my need of the time is to upload a image,audio , video or docs via PUT method with a custom header . The header takes filename , filesize,sha256sum,username,mediatype,resume as parameters. Here is the code how I am doing that . -(void)uploadFile { NSString *resume =@"0"; NSUserDefaults *userCredentials =[NSUserDefaults standardUserDefaults]; NSString *userName =[userCredentials objectForKey:@"userName"]; NSArray *objects =[NSArray arrayWithObjects:selectedMediaType,delegate.fileName,userName,fileSize,fileSHA256Sum,resume, nil]; NSArray *keys =[NSArray arrayWithObjects:@"mediatype",@"file_name",@"usrname",@"filesize",@"sha256sum",@"resume", nil]; discSentValue =[NSDictionary dictionaryWithObjects:objects forKeys:keys]; NSURL *url = [NSURL URLWithString:@"http://briareos.code20.com/putmedia.php"]; uploadMedia = [ASIFormDataRequest requestWithURL:url]; [uploadMedia addRequestHeader:@"MEDIA_UPLOAD_CUSTOM_HEADER" value:[discSentValue JSONRepresentation]]; [uploadMedia setData:dataToUpload forKey:@"File"]; [uploadMedia setDelegate:self]; [uploadMedia setRequestMethod:@"PUT"]; [uploadMedia startAsynchronous]; } But the server is unable to recognize the header , it always returns "invalid header"

    Read the article

  • URL-Encoded post parameters don't Bind to model

    - by Steven Klein
    I have the following Model namespace ClientAPI.Models { public class Internal { public class ReportRequest { public DateTime StartTime; public DateTime EndTime; public string FileName; public string UserName; public string Password; } } } with the following method: [HttpPost] public HttpResponseMessage GetQuickbooksOFXService(Internal.ReportRequest Request){ return GetQuickbooksOFXService(Request.UserName, Request.Password, Request.StartTime, Request.EndTime, Request.FileName); } My webform looks like this: <form method="POST" action="http://localhost:56772/Internal/GetQuickbooksOFXService" target="_blank"> <input type="text" name="StartTime" value="2013-04-03T00:00:00"> <input type="text" name="EndTime" value="2013-05-04T00:00:00"> <input type="text" name="FileName" value="Export_2013-04-03_to_2013-05-03.qbo"> <input type="text" name="UserName" value="UserName"> <input type="text" name="Password" value="*****"> <input type="submit" value="Submit"></form> My question is: I get into the GetQuickbooksOFXService function but my model has all nulls in it instead something useful. Am I doing something wrong?

    Read the article

  • Leaks in passing the request using URL at NSString, Objective-C.

    - by Madan Mohan
    Hi Guys, I getting the leak in this method even the allocated nsstring is released. -(BOOL)getTicket:(NSString*)userName passWord:(NSString*)aPassword isLogin:(BOOL)isLogin { login =[self getloginList]; username = login.name; password = login.password; NSString* str=@""; if (isLogin == YES) { str = @"https://accounts.=true&LOGIN_ID="; str = [str stringByAppendingString:[self _encodeString:username]]; str = [str stringByAppendingString:@"&PASSWORD="]; str = [str stringByAppendingString:[self _encodeString:password]]; } else if (isLogin == NO) { str = @"https://accounts.=true&LOGIN_ID="; str = [str stringByAppendingString:[self _encodeString:userName]]; str = [str stringByAppendingString:@"&PASSWORD="]; str = [str stringByAppendingString: [self _encodeString:aPassword]]; } NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:[NSURL URLWithString:str] cachePolicy:NSURLRequestReloadIgnoringCacheData timeoutInterval:25.0]; [request setHTTPMethod: @"POST"]; NSData *returnData = [NSURLConnection sendSynchronousRequest:request returningResponse:nil error:nil];//****************** i am getting leak here showing as nsstring is leaking NSString *returnString = [[NSString alloc] initWithData:returnData encoding:NSUTF8StringEncoding]; printf("\n returnString in getticket:%s",[returnString UTF8String]); NSRange textRange; textRange =[returnString rangeOfString:@"TICKET"]; if(textRange.location != NSNotFound) { printf("\n **********************"); NSArray* splitValues = [returnString componentsSeparatedByString:@"TICKET="]; NSString* str1 = [splitValues objectAtIndex:1]; NSArray* splitValues1 = [str1 componentsSeparatedByString:@"RESULT"]; NSString* ticket1 = [splitValues1 objectAtIndex:0]; self.ticket = ticket1; self.isCorrectLogin = YES; [returnString release]; return YES; } else { self.isCorrectLogin = NO; [returnString release]; return NO; } return NO; } Please help me out of this problem.

    Read the article

  • Getting the number of posts a user has by the number of rows returned?

    - by transparent
    So I have a question. I have chatting/IM website that I am working on and I was making a user profile page. I wanted to show how many posts that user had. Another issue I had earlier was that when I called a certain value it would return a 'Resource #1' type string. But I got that working by using $totalposts=mysql_query("SELECT * FROM `posts` WHERE Username='" . $username . "'"); $totalposts = mysql_fetch_row($totalposts); $totalposts = $totalposts[0]; But that just returns the last postID of the most recent post. I thought that mysql_num_rows would work. But this code returns an error (example with numbers): 29: $totalposts=mysql_query("SELECT * FROM `posts` WHERE Username='" . $username . "'"); 30: $totalposts = mysql_num_rows($totalposts); 31: $totalposts =mysql_fetch_row($totalposts); 32: $totalposts = $totalposts[0]; That returns this error: Warning: mysql_fetch_row(): supplied argument is not a valid MySQL result resource in /home/a9091503/public_html/im/user.php on line 31 Thanks guys. :) I hope you can figure this out. :D

    Read the article

  • Select rows from table1 and all the children from table2 into an object

    - by Patrick
    I want to pull data from table "Province_Notifiers" and also fetch all corresponding items from table "Province_Notifier_Datas". The table "Province_Notifier" has a guid to identify it (PK), table "Province_Notifier_Datas" has a column called BelongsToProvinceID witch is a foreign key to the "Province_Notifier" tables guid. I tried something like this: var records = from data in ctx.Province_Notifiers where DateTime.Now >= data.SendTime && data.Sent == false join data2 in ctx.Province_Notifier_Datas on data.Province_ID equals data2.BelongsToProvince_ID select new Province_Notifier { Email = data.Email, Province_ID = data.Province_ID, ProvinceName = data.ProvinceName, Sent = data.Sent, UserName = data.UserName, User_ID = data.User_ID, Province_Notifier_Datas = (new List<Province_Notifier_Data>().AddRange(data2)) }; This line is not working and i am trying to figure out how topull the data from table2 into that Province_Notifier_Datas variable. Province_Notifier_Datas = (new List<Province_Notifier_Data>().AddRange(data2)) I can add a record easily by adding the second table row into the Province_Notifier_Datas but i can't fetch it back. Province_Notifier dbNotifier = new Province_Notifier(); // set some values for dbNotifier dbNotifier.Province_Notifier_Datas.Add( new Province_Notifier_Data { BelongsToProvince_ID = userInput.Value.ProvinceId, EventText = GenerateNotificationDetail(notifierDetail) }); This works and inserts the data correctly into both tables. Edit: These error messages is thrown: Cannot convert from 'Province_Notifier_Data' to 'System.Collections.Generic.IEnumerable' If i look in Visual Studio, the variable "Province_Notifier_Datas" is of type System.Data.Linq.EntitySet The best overloaded method match for 'System.Collections.Generic.List.AddRange(System.Collections.Generic.IEnumerable)' has some invalid arguments Edit: var records = from data in ctx.Province_Notifiers where DateTime.Now >= data.SendTime && data.Sent == false join data2 in ctx.Province_Notifier_Datas on data.Province_ID equals data2.BelongsToProvince_ID into data2list select new Province_Notifier { Email = data.Email, Province_ID = data.Province_ID, ProvinceName = data.ProvinceName, Sent = data.Sent, UserName = data.UserName, User_ID = data.User_ID, Province_Notifier_Datas = new EntitySet<Province_Notifier_Data>().AddRange(data2List) }; Error 3 The name 'data2List' does not exist in the current context.

    Read the article

  • Why Backbone.js isn't binding my event

    - by Saif Bechan
    I have a router like this, as main entry point: window.AppRouter = Backbone.Router.extend({ routes: { '': 'login' }, login: function(){ userLoginView = new UserLoginView(); } }); var appRouter = new AppRouter; Backbone.history.start({pushState: true}); I have a model/collection/view like this: window.User = Backbone.Model.extend({}); window.Users = Backbone.Collection.extend({ model: User }); window.UserLoginView = Backbone.View.extend({ events: { 'click #login-button': 'loginAction' }, initialize: function(){ _.bindAll(this, 'render', 'loginAction'); }, loginAction: function(){ var uid = $("#login-username").val(); var pwd = $("#login-password").val(); var user = new User({uid:uid, pwd:pwd}); } }); And body of my HTML looks like this: <form action="#" method="POST" id="login-form"> <p> <label for="login-username">username</label> <input type="text" id="login-username" autofocus /> </p> <p> <label for="login-password">password</label> <input type="password" id="login-password" /> </p> <a id="login-button" href="#">Inloggen</a> </form> Note: The HTML comes from Node.js using express.js, should I maybe wait for a document ready event somewhere? Edit: I have tried this, create the view when ready, did not solve the problem. $(function(){ userLoginView = new UserLoginView(); });

    Read the article

  • WCF newbie - how to install and use a SSL certificate?

    - by Shaul
    This should be a snap for anyone who's done it before... I'm trying to set up a self-hosted WCF service using NetTcpBinding. I got a trial SSL certificate from Thawte and successfully installed that in my IIS store, and I think I've got it correctly set up in the service - at least it doesn't exception out on me! Now, I'm trying to connect the client (this is still all on my dev machine), and it's giving me an error, "Message = "The X.509 certificate CN=ssl.mydomain.com, OU=For Test Purposes Only. No assurances., OU=IT, O=My Company, L=My Town, S=None, C=IL chain building failed. The certificate that was used has a trust chain that cannot be verified. Replace the certificate or change the certificateValidationMode. A certificate chain processed, but terminated in a root certificate which is not trusted by the trust provider." Ooookeeeey... now what? Client code (I want to do this in code, not app.config): var baseAddress = "localhost"; var factory = new DuplexChannelFactory<IMyWCFService>(new InstanceContext(SiteServer.Instance)); factory.Endpoint.Address = new EndpointAddress("net.tcp://{0}:8000/".Fmt(baseAddress)); var binding = new NetTcpBinding(SecurityMode.Message); binding.Security.Message.ClientCredentialType = MessageCredentialType.UserName; factory.Endpoint.Binding = binding; var u = factory.Credentials.UserName; u.UserName = userName; u.Password = password; return factory.CreateChannel()

    Read the article

  • workaround for ORA-03113: end-of-file on communication channel

    - by Jefferstone
    The call to TEST_FUNCTION below fails with "ORA-03113: end-of-file on communication channel". A workaround is presented in TEST_FUNCTION2. I boiled down the code as my actual function is far more complex. Tested on Oracle 11G. Anyone have any idea why the first function fails? CREATE OR REPLACE TYPE "EMPLOYEE" AS OBJECT ( employee_id NUMBER(38), hire_date DATE ); CREATE OR REPLACE TYPE "EMPLOYEE_TABLE" AS TABLE OF EMPLOYEE; CREATE OR REPLACE FUNCTION TEST_FUNCTION RETURN EMPLOYEE_TABLE IS table1 EMPLOYEE_TABLE; table2 EMPLOYEE_TABLE; return_table EMPLOYEE_TABLE; BEGIN SELECT CAST(MULTISET ( SELECT user_id, created FROM all_users WHERE LOWER(username) < 'm' ) AS EMPLOYEE_TABLE) INTO table1 FROM dual; SELECT CAST(MULTISET ( SELECT user_id, created FROM all_users WHERE LOWER(username) >= 'm' ) AS EMPLOYEE_TABLE) INTO table2 FROM dual; SELECT CAST(MULTISET ( SELECT employee_id, hire_date FROM TABLE(table1) UNION SELECT employee_id, hire_date FROM TABLE(table2) ) AS EMPLOYEE_TABLE) INTO return_table FROM dual; RETURN return_table; END TEST_FUNCTION; CREATE OR REPLACE FUNCTION TEST_FUNCTION2 RETURN EMPLOYEE_TABLE IS table1 EMPLOYEE_TABLE; table2 EMPLOYEE_TABLE; return_table EMPLOYEE_TABLE; BEGIN SELECT CAST(MULTISET ( SELECT user_id, created FROM all_users WHERE LOWER(username) < 'm' ) AS EMPLOYEE_TABLE) INTO table1 FROM dual; SELECT CAST(MULTISET ( SELECT user_id, created FROM all_users WHERE LOWER(username) >= 'm' ) AS EMPLOYEE_TABLE) INTO table2 FROM dual; WITH combined AS ( SELECT employee_id, hire_date FROM TABLE(table1) UNION SELECT employee_id, hire_date FROM TABLE(table2) ) SELECT CAST(MULTISET ( SELECT * FROM combined ) AS EMPLOYEE_TABLE) INTO return_table FROM dual; RETURN return_table; END TEST_FUNCTION2; SELECT * FROM TABLE (TEST_FUNCTION()); -- Throws exception ORA-03113. SELECT * FROM TABLE (TEST_FUNCTION2()); -- Works

    Read the article

  • Rails 2.x provide meaningful error message with http basic authentication

    - by randombits
    I'm using basic http authentication in my rails app via the following code: class ApplicationController < ActionController::Base helper :all # include all helpers, all the time before_filter :authenticate private def authenticate authenticate_or_request_with_http_basic do |username, password| if username.nil? || password.nil? render :inline => %(xml.instruct! :xml, :version => "1.0", :encoding => "UTF-8" xml.errors do xml.error('Could not authenticate you.') end), :type => :builder, :status => 401 end end end end The problem is, if you do a curl http://127.0.0.1:3000/foo/1.xml without providing the -u username:password flag, you get a dead beat response like this: HTTP/1.1 401 Unauthorized Cache-Control: no-cache WWW-Authenticate: Basic realm="Foo" X-Runtime: 1 Content-Type: text/html; charset=utf-8 Content-Length: 27 Server: WEBrick/1.3.1 (Ruby/1.9.1/2010-01-10) Date: Thu, 03 Jun 2010 03:09:18 GMT Connection: Keep-Alive HTTP Basic: Access denied. Is it possible at all to render the inline XML I have above in the event a username and password is not provided by the user?

    Read the article

  • why does this knockout method receive a form element instead of the object its nested in?

    - by ladookie
    I have this HTML: <ul class="chat_list" data-bind="foreach: chats"> <li> <div class="chat_response" data-bind="visible: CommentList().length == 0"> <form data-bind="submit: $root.addComment"> <input class="comment_field" placeholder="Comment…" data-bind="value: NewCommentText" /> </form> </div> </li> </ul> and this JavaScript: function ChatListViewModel(chats) { // var self = this; self.chats = ko.observableArray(ko.utils.arrayMap(chats, function (chat) { return { CourseItemDescription: chat.CourseItemDescription, CommentList: ko.observableArray(chat.CommentList), CourseItemID: chat.CourseItemID, UserName: chat.UserName, ChatGroupNumber: chat.ChatGroupNumber, ChatCount: chat.ChatCount, NewCommentText: ko.observable("") }; })); self.newChatText = ko.observable(); self.addComment = function (chat) { var newComment = { CourseItemDescription: chat.NewCommentText(), ParentCourseItemID: chat.CourseItemID, CourseID: $.CourseLogic.dataitem.CourseID, AccountID: $.CourseLogic.dataitem.AccountID, SystemObjectID: $.CourseLogic.dataitem.CommentSystemObjectID, SystemObjectName: "Comments", UserName: chat.UserName }; chat.CommentList.push(newComment); chat.NewCommentText(""); }; } ko.applyBindings(new ChatListViewModel(initialData)); When I go into the debugger it shows that the chat parameter of the addComment() function is a form element instead of a chat object. Why is this happening?

    Read the article

  • JPA - Can an @JoinColumn be an @Id as well? SerializationException occurs.

    - by Shivago
    Hi everyone, I am trying to use an @JoinColumn as an @Id using JPA and I am getting SerializationExceptions, "Could not serialize." UserRole.java: @Entity @Table(name = "authorities") public class UserRole implements Serializable { @Column(name = "authority") private String role; @Id @ManyToOne @JoinColumn(name = "username") private User owner; ... } User.java: @Entity @Table(name = "users") public class User implements Serializable { @Id @GeneratedValue protected Long id; @Column(name = "username") protected String email; @OneToMany(mappedBy = "owner", fetch = FetchType.LAZY, cascade = CascadeType.ALL) protected Set<UserRole> roles = new HashSet<UserRole>(); .... } "username" is set up as a unique index in my Users table but not as the primary key. Is there any way to make "username" act as the ID for UserRole? I don't want to introduce a numeric key in UserRole. Have I totally lost the plot here? I am using MySQL and Hibernate under the hood.

    Read the article

  • Windows Phone 7, login screen redirect and a case for .exit?

    - by Jarrette
    I know this has been discussed ad nauseum, but I want to present my case.... 1. My start page in my app is login.xaml. The user logs in, the username and password are authenticated through my WCF service, the username is saved in isolated storage, and then the user is redirected to mainpage.xaml. When a user starts my app, and they already have a saved username in isolated storage, they are redirected to mainpage.xaml If the user hit's "back" hard button from mainpage.xaml, they are redirected to the login screen, which in turn redirects them back to the mainpage.xaml since they already have a saved local username. This is causing my app to fail certification currently since the user cannot hit the "back" button to exit the app from mainpage.xaml. My instinct here is to override the BackKeyPress in mainpage.xaml and exit the app somehow. By reading the other posts, I can see that this method is not available. My second idea was to somehow store a property in the app.xaml.cs page that would tell the app to exit when the login page is loaded and that property is set to true, but that seems a bit hacky as well.... Any ideas here?

    Read the article

  • With lots of help, I have gotten this android class activity down to only one error. Eclipse aks for me to add ")" ,"}", and ";" why though?

    - by AndroidNewb
    package com.android.drinksonme; import android.app.Activity; import android.content.Intent; import android.os.Bundle; import android.view.View; import android.view.View.OnClickListener; import android.widget.Button; import android.widget.EditText; import android.widget.TextView; public class Screen2 extends Activity { // Declare our Views, so we can access them later private EditText etUsername; private EditText etPassword; private Button btnLogin; private Button btnSignUp; private TextView lblResult; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); // Get the EditText and Button References etUsername = (EditText)findViewById(R.id.username); etPassword = (EditText)findViewById(R.id.password); btnLogin = (Button)findViewById(R.id.login_button); btnSignUp = (Button)findViewById(R.id.signup_button); lblResult = (TextView)findViewById(R.id.result); btnLogin.setOnClickListener(new OnClickListener () { String username = etUsername.getText().toString(); String password = etPassword.getText().toString(); public void onClick(View v){ if(username.equals("test") && password.equals("test")){ Intent i = new Intent(Screen2.this, DrinksTwitter.class); startActivity(i);} else lblResult.setText("Invalid username or password."); } /* final Intent k = new Intent(Screen2.this, SignUp.class); btnSignUp.setOnClickListener(new OnClickListener() { public void onClick(View v) { startActivity(k); }*/ } ); } }

    Read the article

  • Codeigniter: validation problem

    - by krike
    For some reason a user can login with any password, first I thought I forgot to check for the password but I didn't... and I just cant find the problem here is the model: /*#######################################################*/ function validate() /*#######################################################*/ { $this->db->where('username', $this->input->post('username')); $this->db->where('password', md5($this->input->post('password'))); $q = $this->db->get('user_extra'); if($q->num_rows() == 1): return true; else: return false; endif; }//end of function validate() The controller /*#######################################################*/ function validate_credentials() /*#######################################################*/ { $this->load->model('membership_model'); $this->load->library('form_validation'); $this->form_validation->set_rules('username', 'Name', 'trim|required'); $this->form_validation->set_rules('password', 'password', 'trim|required'); if(!$this->membership_model->validate()): $this->form_validation->set_message('check_login', 'Login not correct, please try again.'); endif; if($this->form_validation->run() == FALSE): $this->index(); else: $this->membership_model->userinfo($this->input->post('username')); //should redirect to last view redirect($this->session->flashdata('redirect_url')); endif; }// end of validate_credentials()

    Read the article

  • Fatal error: Call to a member function escape() on a non-object in .....on line 10

    - by danyo
    i am making a simple javascript login form for wordpress. i have the form submitting to the following bit of php to handle the login: <?php get_header(); global $user_ID; if (!$user_ID) { if($_POST){ //We shall SQL escape all inputs $username = $wpdb->escape($_REQUEST['username']); $password = $wpdb->escape($_REQUEST['password']); $remember = $wpdb->escape($_REQUEST['rememberme']); if($remember) $remember = "true"; else $remember = "false"; $login_data = array(); $login_data['user_login'] = $username; $login_data['user_password'] = $password; $login_data['remember'] = $remember; $user_verify = wp_signon( $login_data, false ); //wp_signon is a wordpress function which authenticates a user. It accepts user info parameters as an array. if ( is_wp_error($user_verify) ) { echo "<span class='error'>Invalid username or password. Please try again!</span>"; exit(); } else { echo "<script type='text/javascript'>window.location='". get_bloginfo('url') ."'</script>"; exit(); } } else { //get_header(); ?> any ideas on why i am getting the error? Cheers, Dan

    Read the article

  • How can I join 3 tables with mysql & php?

    - by steven
    check out the page [url]http://www.mujak.com/test/test3.php[/url] It pulls the users Post,username,xbc/xlk tags etc which is perfect... BUT since I am pulling information from a MyBB bulletin board system, its quite different. When replying, people are are allowed to change the "Thread Subject" by simplying replying and changing it. I dont want it to SHOW the changed subject title, just the original title of all posts in that thread. By default it repies with "RE:thread title". They can easily edit this and it will show up in the "Subject" cell & people wont know which thread it was posted in because they changed their thread to when replying to the post. So I just want to keep the orginial thread title when they are replying. Make sense~?? Tables:mybb_users Fields:uid,username Tables:mybb_userfields Fields:ufid Tables:mybb_posts Fields:pid,tid,replyto,subject,ufid,username,uid,message Tables:mybb_threads Fields:tid,fid,subject,uid,username,lastpost,lastposter,lastposteruid I haev tried multiple queries with no success: $result = mysql_query(" SELECT * FROM mybb_users LEFT JOIN (mybb_posts, mybb_userfields, mybb_threads) ON ( mybb_userfields.ufid=mybb_posts.uid AND mybb_threads.tid=mybb_posts.tid AND mybb_users.uid=mybb_userfields.ufid ) WHERE mybb_posts.fid=42"); $result = mysql_query(" SELECT * FROM mybb_users LEFT JOIN (mybb_posts, mybb_userfields, mybb_threads) ON ( mybb_userfields.ufid=mybb_posts.uid AND mybb_threads.tid=mybb_posts.tid AND mybb_users.uid=mybb_posts.uid ) WHERE mybb_threads.fid=42"); $result = mysql_query(" SELECT * FROM mybb_posts LEFT JOIN (mybb_userfields, mybb_threads) ON ( mybb_userfields.ufid=mybb_posts.uid AND mybb_threads.tid=mybb_posts.tid ) WHERE mybb_posts.fid=42");

    Read the article

  • JDBC with JSP fails to insert

    - by StrykeR
    I am having some issues right now with JDBC in JSP. I am trying to insert username/pass ext into my MySQL DB. I am not getting any error or exception, however nothing is being inserted into my DB either. Below is my code, any help would be greatly appreciated. <% String uname=request.getParameter("userName"); String pword=request.getParameter("passWord"); String fname=request.getParameter("firstName"); String lname=request.getParameter("lastName"); String email=request.getParameter("emailAddress"); %> <% try{ String dbURL = "jdbc:mysql:localhost:3306/assi1"; String user = "root"; String pwd = "password"; String driver = "com.mysql.jdbc.Driver"; String query = "USE Users"+"INSERT INTO User (UserName, UserPass, FirstName, LastName, EmailAddress) " + "VALUES ('"+uname+"','"+pword+"','"+fname+"','"+lname+"','"+email+"')"; Class.forName(driver); Connection conn = DriverManager.getConnection(dbURL, user, pwd); Statement statement = conn.createStatement(); statement.executeUpdate(query); out.println("Data is successfully inserted!"); } catch(SQLException e){ for (Throwable t : e) t.printStackTrace(); } %> DB script here: CREATE DATABASE Users; use Users; CREATE TABLE User ( UserID INT NOT NULL AUTO_INCREMENT, UserName VARCHAR(20), UserPass VARCHAR(20), FirstName VARCHAR(30), LastName VARCHAR(35), EmailAddress VARCHAR(50), PRIMARY KEY (UserID) );

    Read the article

  • Sessions not sticking linux server

    - by Jacob Windsor
    I have just moved the dev site over to my linux server for production but the sessions don't seem to be sticking for very long. I am guessing it is the server settings and not the php because it does the same thing with the plesk panel. Whenever a script is executed the sessions seems to get unset. I see nothing in the error log so not sure what it is. It all worked fine on wamp. Anyway I uploaded the php.ini file which was in the wamp server as it had all the settings i needed and all was working on localhost. Not sure what the problem is and this is the final thing that I have to sort out before going into production. And just too add the sessions are being started as they last for a little bit just don't stick around long. Here is the relevent part of my login script just in case there is something wrong with the code: // if login is ok then we add a cookie if($flag == 0) { $pass = htmlspecialchars(mysql_real_escape_string($_POST['pass'])); $username = htmlspecialchars(mysql_real_escape_string($_POST['username'])); $_SESSION['username']=$username; $_SESSION['password']=$pass;

    Read the article

  • How to solve this ?

    - by Karthick
    Hi all. I use the following code in java. It works well and it adds events into Google calendar. But in android it gives the Exception “Error connecting with login URI”.Can anyone help me to solve this?? CalendarService myService = new CalendarService("calendarTest"); String userName = "[email protected]"; String userPassword = "xxxxxxx"; // Create the necessary URL objects. try { metafeedUrl = new URL(METAFEED_URL_BASE + userName); eventFeedUrl = new URL(METAFEED_URL_BASE + userName + EVENT_FEED_URL_SUFFIX); } catch (MalformedURLException e) { // Bad URL strbuf.append(e.getMessage()); System.err.println("Uh oh - you've got an invalid URL."); e.printStackTrace(); return; } try { myService.setUserCredentials(userName, userPassword); // Demonstrate creating a single-occurrence event. CalendarEventEntry singleEvent = createSingleEvent(myService,"Event Title", "Event Description "); System.out.println("Successfully created event " +singleEvent.getTitle().getPlainText() ); // Demonstrate creating a quick add event. CalendarEventEntry quickAddEvent = createQuickAddEvent(myService,"Tennis with me June 22 3pm-3:30pm"); System.out.println("Successfully created quick add event " + quickAddEvent.getTitle().getPlainText()); } catch.......

    Read the article

  • What is an efficient way to serve images (PHP)?

    - by Scarface
    Hey guys currently I am thinking of serving images using an image handler script. I have two sources of images. One is from my web images folder where images that are used to construct my site interface are served. The other is in each users images folder where they can store their own images. I was thinking of giving each user image a unique id and then searching that id with the image handler script and serving the image, and changing the file name. The problem is that my site images folder does not have any information in the database and thus has no ids, should I just serve directly? Also this way of serving user images does not seem like the most efficient. If anyone has any suggestions I would really appreciate it. $sql="SELECT username,file_name FROM images WHERE id=?"; $stmt=$conn->prepare($sql); $result=$stmt->execute(array($ID)); while($row = $stmt->fetch(PDO::FETCH_ASSOC)){ $image_name = $row['file_name']; $username = $row['username']; } $path="$username/images/$image_name"; header("Expires: -1"); header("Cache-Control: no-store, no-cache, must-revalidate"); header("Cache-Control: post-check=0, pre-check=0", false); readfile($path);

    Read the article

  • form.has_errors tag not working

    - by John
    Hello, Im using Django 1.2.3. I have login functionality in my site using django.contrib.auth.views.login. The user is able to login after entering correct username and password. But, form.has_errors is not working i.e. if the login credentials entered are incorrect i dont see the error message. My login.html in templates/registration is as follows : <html> <head> <title>Login</title> </head> <body> <h1>User Login</h1> {% if form.has_errors %} <p>Your username and password didn't match. Please try again.</p> {% endif %} <form method="post" action="."> {% csrf_token %} <p><label for="id_username">Username:</label> {{ form.username }}</p> <p><label for="id_password">Password:</label> {{ form.password }}</p> <input type="hidden" name="next" value="/" /> <input type="submit" value="login" /> </form> </body> </html> Any way to fix this problem? Please Help Thank You.

    Read the article

< Previous Page | 88 89 90 91 92 93 94 95 96 97 98 99  | Next Page >