Search Results

Search found 32961 results on 1319 pages for 'java'.

Page 927/1319 | < Previous Page | 923 924 925 926 927 928 929 930 931 932 933 934  | Next Page >

  • JAR file folder for eclipse projects

    - by Daff
    I'm trying to create a centralized folder (in some kind of a "meta project" in my eclipse workspace) for commonly used JAR files for referenced projects in this workspace. It should work similar to the WEB-INF/lib folder for web projects but also apply to non web projects, and automatically scan and add all jar files in this folder. I tried to create a user library with these jar files and reference them in the project but I still have to add every new jar manually to the user library (and don't know if it is referenced relative of absoulute) and Tomcat (WTP) doesn't seem to take these files (Run As - Run on Server) into its classpath (and I don't want to duplicate the jars and put them into WEB-INF/lib). Any ideas?

    Read the article

  • is it possible to store server returned json data in jqgrid to display columnnames models data dynamically for every request?

    - by user1768246
    is it possible to store server returned json data in jqgrid to display columnnames models data dynamically for every request ? $("#grid").jqGrid({ type: "GET", url: "", var columnNames = $("#grid")[0].p.colNames, var columnModel = $("#grid")[0].p.colNames, var columnData = $("#grid")[0].p.colNames, datatype: 'jsonstring', datastr: columnData, colModel: columnModel, jsonReader: { root: 'innerWrapper.rows', page: "result.gridData.outerWrapper.page", total: "result.gridData.outerWrapper.total", records: "result.gridData.outerWrapper.total", repeatitems: false, }, gridview: true, pager: "pager", height: "auto", rowNum: 10, width:"auto", height:"auto", rowList: [10, 20, 30,40], viewrecords: true, caption:"Graph Data", rownumbers: true, });

    Read the article

  • Adding a MouseOverHandler to an Element?

    - by JP
    I would like to listen for the mouse over event in GWT 1.6. Since GWT 1.6 has introduced handlers and deprecated listeners I'm unsure as to how I can accomplish this with what little information exists. Note: I have an Element object. That's what I need to add the mouse handler to. I apologize for my lack of clarity. Thanks!

    Read the article

  • Beginnerquestion: How to count amount of each number drawn in a Lottery and output it in a list?

    - by elementz
    I am writing this little Lottery application. Now the plan is, to count how often each number has been drawn during each iteration of the Lottery, and store this somewhere. My guess is that I would need to use a HashMap, that has 6 keys and increments the value by one everytime the respective keys number is drawn. But how would I accomplish this? My code so far: public void numberCreator() { // creating and initializing a Random generator Random rand = new Random(); // A HashMap to store the numbers picked. HashMap hashMap = new HashMap(); // A TreeMap to sort the numbers picked. TreeMap treeMap = new TreeMap(); // creating an ArrayList which will store the pool of availbale Numbers List<Integer>numPool = new ArrayList<Integer>(); for (int i=1; i<50; i++){ // add the available Numbers to the pool numPool.add(i); hashMap.put(nums[i], 0); } // array to store the lotto numbers int [] nums = new int [6]; for (int i =0; i < nums.length; i++){ int numPoolIndex = rand.nextInt(numPool.size()); nums[i] = numPool.get(numPoolIndex); // check how often a number has been called and store the new amount in the Map int counter = hashMap.get numPool.remove(numPoolIndex); } System.out.println(Arrays.toString(nums)); } Maybe someone can tell me if I have the right idea, or even how I would implement the map properly?

    Read the article

  • Q about AbstractApplicationContext.getBeansOfType() and getBean()

    - by Paul Reiners
    We have the following legacy 2.0.7 Spring code: final Map<String, MyClass> secondaryFactories = (Map<String, MyClass>) context.getBeansOfType(MyClass.class, false, true); return (MyClass) context.getBean("myClass"); where context is an instance of org.springframework.context.support.AbstractApplicationContext Note that we ignore the return value of getBeansOfType(). This works just fine, but the problem is that the call to getBeansOfType() is time-consuming. However, even though we ignore the return value of this call, if we try to eliminate this call, then the instance of MyClass returned by getBean() is not fully initialized. (So, apparently, the call to getBeansOfType() is having some sort of side-effects that we need.) We suspect that the call to getBeansOfType() is overkill and we could do something more lightweight so that the instance of MyClass obtained by the call to getBean() would be fully initialized (but it's not null and no exception is thrown). So, is there a more efficient way of doing this?

    Read the article

  • Refactoring a nested loop

    - by user3517441
    I have the following code which I use a lot of times in the class. for (int i = 0; i < someList.size(); i++) { for (int j = 0; j < someList.size(); j++) { if (i != j) { someList.get(i).sendMessageTo(someList.get(j))); //variable action } } } The purpose of the loop is to make each element in the List to send a message (or perform another action) to every element in the list except itself. Is there any way I can create a helper method so I don't have to repeat the loop code. I want to be able to state the variable action and call the helper method. Thanks.

    Read the article

  • Rotating A Tile In A BufferedImage

    - by Eddy Freeman
    I have created a a bufferedImage of 6 tiles of 2 rows and 3 columns and i want to rotate the last tile of the second row. This tile serves as a crossing for my animation. My problems are : How can i get access to that specifc tile alone and rotate it alone without affecting others. I have googled for a while but no answer.

    Read the article

  • recursion resulting in extra unwanted data

    - by spacerace
    I'm writing a module to handle dice rolling. Given x die of y sides, I'm trying to come up with a list of all potential roll combinations. This code assumes 3 die, each with 3 sides labeled 1, 2, and 3. (I realize I'm using "magic numbers" but this is just an attempt to simplify and get the base code working.) int[] set = { 1, 1, 1 }; list = diceroll.recurse(0,0, list, set); ... public ArrayList<Integer> recurse(int index, int i, ArrayList<Integer> list, int[] set){ if(index < 3){ // System.out.print("\n(looping on "+index+")\n"); for(int k=1;k<=3;k++){ // System.out.print("setting i"+index+" to "+k+" "); set[index] = k; dump(set); recurse(index+1, i, list, set); } } return list; } (dump() is a simple method to just display the contents of list[]. The variable i is not used at the moment.) What I'm attempting to do is increment a list[index] by one, stepping through the entire length of the list and incrementing as I go. This is my "best attempt" code. Here is the output: Bold output is what I'm looking for. I can't figure out how to get rid of the rest. (This is assuming three dice, each with 3 sides. Using recursion so I can scale it up to any x dice with y sides.) [1][1][1] [1][1][1] [1][1][1] [1][1][2] [1][1][3] [1][2][3] [1][2][1] [1][2][2] [1][2][3] [1][3][3] [1][3][1] [1][3][2] [1][3][3] [2][3][3] [2][1][3] [2][1][1] [2][1][2] [2][1][3] [2][2][3] [2][2][1] [2][2][2] [2][2][3] [2][3][3] [2][3][1] [2][3][2] [2][3][3] [3][3][3] [3][1][3] [3][1][1] [3][1][2] [3][1][3] [3][2][3] [3][2][1] [3][2][2] [3][2][3] [3][3][3] [3][3][1] [3][3][2] [3][3][3] I apologize for the formatting, best I could come up with. Any help would be greatly appreciated. (This method was actually stemmed to use the data for something quite trivial, but has turned into a personal challenge. :) edit: If there is another approach to solving this problem I'd be all ears, but I'd also like to solve my current problem and successfully use recursion for something useful.

    Read the article

  • Why the generated key size is not constant?

    - by Tom Brito
    The following code prints randomly 634, 635, 636, each time I run it. Why its not constant? public static void main(String[] args) throws Exception { KeyPairGenerator keyPairGen = KeyPairGenerator.getInstance("RSA", "BC"); keyPairGen.initialize(1024); RsaKeyPair keyPair = new RsaKeyPair(keyPairGen.generateKeyPair()); System.out.println(keyPair.getPrivate().getEncoded().length); }

    Read the article

  • Issue with a JPA query

    - by boyd4715
    I am trying to execute the following JPA query: public static final String UPDATE_INVENTORY_CUSTOMER_FOR_AMS_MAPPING = "UPDATE Inventory inventory SET" + " inventory.customer.id = :" + DataAccessConstants.PARAM_CUSTOMER_ID + " ,inventory.lastUpdateUserId = :" + DataAccessConstants.PARAM_USER_ID + " where inventory.amsConsignorName = :" + DataAccessConstants.PARAM_AMS_CONSIGNOR_NAME + " and inventory.amsConsignorOrgCd = :" + DataAccessConstants.PARAM_AMS_CONSIGNOR_ORG_CD + " and inventory.amsConsignorTypeName = :" + DataAccessConstants.PARAM_AMS_CONSIGNOR_TYPE + " and inventory.status.code in (:" + DataAccessConstants.PARAM_STATUS + ")"; but it is seeing the following: update ATL_INVENTORY, set CONSIGNOR_ID=?, LAST_UPDATE_USER_ID=? where AMS_CONSIGNOR_NAME=? and AMS_CONSIGNOR_ORG_CD=? and AMS_CONSIGNOR_TYPE_NAME=? and (CODE in (? , ? , ? , ?)) Any ideal as to why there is a comma after the table name?

    Read the article

  • How do I detect an array

    - by Dan
    OK so, is there an efficient way to detect on what array you're currently on by using the KeyListener? My code: http://www.javadan.pastebin.com/X68VyuGL What I am trying to do here is see if the current tile I am on is BLOCKED. Thanks.

    Read the article

  • Scanner class is skipping lines

    - by user2403304
    I'm new to programing and I'm having a problem with my scanner class. This code is in a loop and when the loop comes around the second, third whatever time I have it set to it skips the first title input. I need help please why is it skipping my title scanner input in the beginning? System.out.println("Title:"); list[i].title=keyboard.nextLine(); System.out.println("Author:"); list[i].author=keyboard.nextLine(); System.out.println("Album:"); list[i].album=keyboard.nextLine(); System.out.println("Filename:"); list[i].filename=keyboard.nextLine();

    Read the article

  • Code example with annotation in JavaDoc

    - by John
    Hello, my JavaDoc doesn't work when I have a code example with an annotation. Any suggestions? /** * <pre> * public class Demo { * @DemoAnnotation * public void demoMethod() { * } * } * </pre> */ @Retention(RetentionPolicy.RUNTIME) @Target({ElementType.METHOD}) public @interface DemoAnnotation {

    Read the article

  • Naked Objects. Good or Bad

    - by Midhat
    I have recently been exposed to naked objects. It looks like a pretty decent framework. However I do not see it in widespread use like say, Spring. So why is this framework not getting any mainstream application credit. What are its shortcomings as you see?

    Read the article

  • More swing design & actions

    - by takoi
    Im pretty new to gui programming so i've been reading through every post on this site about swing and design. Whats been answered over and over again is that one should have a class which handles all the action. Like this: (GUI being some JFrame) Now, this works great for one-way actions, like OpenDialog. But the actions for buttons in DialogA and B will have to have access to all the components (there will be many) in its dialog, and the controller. This is where im stuck. The only sane way i can see is to put it in DialogA/B but i would then need to pass the controller all the way down, through classes that dont even need it, and it'll get all spaghetti. Really dont want that. Someone must have encountered this problem before. So where should i put this Action? Or should i just drop the whole design?

    Read the article

  • Refactoring a complicated if-condition

    - by kumar kasimala
    Hi all, Can anyone suggest best way to avoid most if conditions? I have below code, I want avoid most of cases if conditions, how to do it ? any solution is great help; if (adjustment.adjustmentAccount.isIncrease) { if (adjustment.increaseVATLine) { if (adjustment.vatItem.isSalesType) { entry2.setDebit(adjustment.total); entry2.setCredit(0d); } else { entry2.setCredit(adjustment.total); entry2.setDebit(0d); } } else { if (adjustment.vatItem.isSalesType) { entry2.setCredit(adjustment.total); entry2.setDebit(0d); } else { entry2.setDebit(adjustment.total); entry2.setCredit(0d); } } } else { if (adjustment.increaseVATLine) { if (adjustment.vatItem.isSalesType) { entry2.setCredit(adjustment.total); entry2.setDebit(0d); } else { entry2.setDebit(adjustment.total); entry2.setCredit(0d); } } else { if (adjustment.vatItem.isSalesType) { entry2.setDebit(adjustment.total); entry2.setCredit(0d); } else { entry2.setCredit(adjustment.total); entry2.setDebit(0d); } } }

    Read the article

  • Best practice when removing entity regarding mappedBy collections?

    - by Daniel Bleisteiner
    I'm still kind of undecided which is the best practice to handle em.remove(entity) with this entity being in several collections mapped using mappedBy in JPA. Consider an entity like a Property that references three other entities: a Descriptor, a BusinessObject and a Level entity. The mapping is defined using @ManyToOne in the Property entity and using @OneToMany(mappedBy...) in the other three objects. That inverse mapping is defined because there are some situations where I need to access those collections. Whenever I remove a Property using em.remove(prop) this element is not automatically removed from managed entities of the other three types. If I don't care about that and the following page load (webapp) doesn't reload those entities the Property is still found and some decisions might be taken that are no longer true. The inverse mappings may become quite large and though I don't want to use something like descriptor.getProperties().remove(prop) because it will load all those properties that might have been lazy loaded until then. So my currently preferred way is to refresh the entity if it is managed: if (em.contains(descriptor)) em.refresh(descriptor) - which unloads a possibly loaded collection and triggers a reload upon the next access. Is there another feasible way to handle all those mappedBy collections of already loaded entites?

    Read the article

  • How to connect ejb to hibernate in eclipse and glassfish server?

    - by agiles
    I am newer to ejb and hibernate and don't have any idea to how to link or connect those technologies mentioned above. I have just created individual module for ejb, hibernate and servlet. but I need to pass the data from servlet to ejb and then ejb to hibernate and store into MySql database. Problem for me, how to connect ejb to hibernate. I tried some ways and it couldn't work for me. Please someone help me. Thank you

    Read the article

  • For a Chemical Equation Balancer App (Android), how do I count the number of atoms of each element in each term?

    - by Upas
    This is my app: If someone enters "C6H12O6+O2=CO2+H2O", then I have already written code to split the equation into terms, so in an ArrayList called rterms I have the strings: C6H12O6 CO2 and in another ArrayList called pterms, I have: CO2 H2O I need to count the number of C's in each term of the reactants, so 6 for term 1, 0 for term 2, and then the H's and then O's. How would I do this? Any help is appreciated.

    Read the article

  • What GC parameters is a JVM running with?

    - by skaffman
    I'm still investigating issues I have with GC tuning (see prior question), which involves lots of reading and experimentation. Sun Java5+ JVMs attempt to automatically select the optimal GC strategy and parameters based on their environment, which is great, but I can't figure out how to query the running JVM to find out what those parameters are. Ideally, I'd like to see what values of the various GC-related -XX options are being used, as selected automatically by the VM. If I had that, I could have a baseline to begin tweaking. Anyone know to recover these values from a running VM?

    Read the article

< Previous Page | 923 924 925 926 927 928 929 930 931 932 933 934  | Next Page >