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  • How to persist in order

    - by parhs
    I have two entities: EXAM and EXAM_NORMAL. EXAM @Id @GeneratedValue(strategy=GenerationType.IDENTITY) private Long id; private String name; private String codeName; @Enumerated(EnumType.STRING) private ExamType examType; @ManyToOne private Category category; @OneToMany(mappedBy="id",cascade=CascadeType.PERSIST) @OrderBy("id") private List<Exam_Normal> exam_Normal; EXAM_NORMAL @Id private Long item; @Id @ManyToOne private Exam id; @Enumerated(EnumType.STRING) private Gender gender; private Integer age_month_from; private Integer age_month_to; The problem is that if I put a list of EXAM_NORMAL at an EXAM class if I try to persist(EXAM) I get an error because it tries to persist EXAM_NORMAL first but it cant because the primary key of EXAM is missing because it isn't persisted... Is there any way to define the order? Or should I set null the list, persist and then set the list again? thanks:)

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  • Format String become 0001, 0010 etc

    - by trycatch4j
    Hi all.., I have number : 1, 2, 3, 4, 10 But I wanna print that number 0001 0002 0003 0004 0010 I have search in google, the keyword is number format. but I've got nothing, I just get, frmat decimal such ass 1,000,000.00. hope you can suggest me a reference or give me some problem solving. Thanks,

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  • Is there a way to arbitrarily load Resources at runtime in Android?

    - by Omega
    I've got some XML resources in my Android app. Each one has a different name like "bicycle.xml" and "car.xml". I'd like to know if there's a way to load resources based on conditions during run time. As an example... Say I had a text input in my app. When the user enters "bicycle", my app can look up an XML resource by that name, parse and load it. Whereas if they enter "car", they would end up with the data from the other XML file. I've noticed so far that to load resources, you have to use the autogenerated "R" class, which restricts you to hard-coding resources at compile time.

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  • get Error Message

    - by pAkY88
    I have two servlet: first servlet is similar to a client and creates an HttpURLConnection to call the second servlet. I would like send a special error, formatted like a JSON object, so I call sendError method in this way: response.sendError(code, "{json-object}") But in the first servlet when I read error with getResponseMessage method I just get standard HTTP message and not my json object as a string. How I can get my json string?

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  • Picture.writeToStream() not writing out all bitmaps

    - by quickdraw mcgraw
    I'm using webview.capturePicture() to create a Picture object that contains all the drawing objects for a webpage. I can successfully render this Picture object to a bitmap using the canvas.drawPicture(picture, dst) with no problems. However when I use picture.writeToStream(fos) to serialize the picture object out to file, and then Picture.createFromStream(fis) to read the data back in and create a new picture object, the resultant bitmap when rendered as above is missing any larger images (anything over around 20KB! by observation). This occurs on all the Android OS platforms that I have tested 1.5, 1.6 and 2.1. Looking at the native code for Skia which is the underlying Android graphics library and the output file produced from the picture.writeToStream() I can see how the file format is constructed. I can see that some of the images in this Skia spool file are not being written out (the larger ones), the code that appears to be the problem is in skBitmap.cpp in the method void SkBitmap::flatten(SkFlattenableWriteBuffer& buffer) const; It writes out the bitmap fWidth, fHeight, fRowBytes, FConfig and isOpaque values but then just writes out SERIALIZE_PIXELTYPE_NONE (0). This means that the spool file does not contain any pixel information about the actual image and therefore cannot restore the picture object correctly. Effectively this renders the writeToStream and createFromStream() APIs useless as they do not reliably store and recreate the picture data. Has anybody else seen this behaviour and if so am I using the API incorrectly, can it be worked around, is there an explanation i.e. incomplete API / bug and if so are there any plans for a fix in a future release of Android? Thanks in advance.

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  • How to use CellRenderer for GregorianCalendar?

    - by HansDampf
    So I have been trying to use the example from Tutorial and change it so it fits my program. The getColumnValue method returns the object that holds the information that is supposed to be displayed. Is this the way to go or should it rather return the actual String to be displayed. I guess not because that way I would mix the presentation with the data, which I was trying to avoid. public class IssueTableFormat implements TableFormat<Appointment> { public int getColumnCount() { return 6; } public String getColumnName(int column) { if(column == 0) return "Datum"; else if(column == 1) return "Uhrzeit"; else if(column == 2) return "Nummer"; else if(column == 3) return "Name"; else if(column == 4) return "letzte Aktion"; else if(column == 5) return "Kommentar"; throw new IllegalStateException(); } public Object getColumnValue(Appointment issue, int column) { if(column == 0) return issue.getDate(); else if(column == 1) return issue.getDate(); else if(column == 2) return issue.getSample(); else if(column == 3) return issue.getSample(); else if(column == 4) return issue.getHistory(); else if(column == 5) return issue.getComment(); throw new IllegalStateException(); } } The column 0 and 1 contain a GregorianCalendar object, but I want column 0 to show the date and 1 to show the time. So I know using cellRenderers can help here. This is what I tried. public class DateRenderer extends DefaultTableCellRenderer { public DateRenderer() { super(); } public void setValue(Object value) { GregorianCalendar g =(GregorianCalendar) value; value=g.get(GregorianCalendar.HOUR); } } But the cell doesnt show anything, what is wrong here?

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  • Key that yields multiple Results

    - by SgtStud
    I'm pretty new to programming so I'm sorry if this is a stupid question. I was wondering if there was a type of data that returns (possibly) more than one answer per key. For example: TestType<int,String> test = new TestType<int,String>(); So if you typed, test.getKey(1), you could get {"hello","this","is","a","test"}. Basically, is there a type of data that can return multiple answers, sort of like a HashMap and List combined?

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  • Color getAlpha() not working as intended

    - by Arvy
    I was making a program where I load an image and after that I do something with opaque pixels. Transparent pixels showed up as black pixels, but after some time I found the cause: Color c = new Color (input.getRGB(x, y)); Works-> if ((input.getRGB(x, y) & 0xFF000000) != 0x00000000) { do_smth();} Returns true at all times-> if (c.getAlpha() != 0) { do_smth(); } So why it does not work?

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  • What exactly is GRASP's Controller about?

    - by devoured elysium
    What is the idea behind Grasp's Controller pattern? My current interpretation is that sometimes you want to achieve something that needs to use a couple of classes but none of those classes could or has access to the information needed to do it, so you create a new class that does the job, having references to all the needed classes(this is, could be the information expert). Is this a correct view of what Grasp's Controller is about? Generally when googling or SO'ing controller, I just get results about MVC's (and whatnot) which are topics that I don't understand about, so I'd like answers that don't assume I know ASP.NET's MVC or something :( Thanks

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  • Why is false being returned in this function

    - by Kay
    Hello all, I have this function below which makes it to the second IF function which sets the variable th as true but what is returned is false? Why?! public boolean nodeExist(TreeNode Tree, T value){ boolean th = false; if(Tree.getValue()!= null){ if(value == Tree.getValue()){ th = true; }else{ if(value.compareTo((T) Tree.getValue()) < 0){ nodeExist(Tree.getLeft(), value); }else{ nodeExist(Tree.getRight(), value); } } }else{ th = false; } return th; }

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  • How do I remove an old JPanel and add a new one?

    - by Roman
    I would like to remove an old JPanel from the Window (JFrame) and add a new one. How should I do it? I tried the following: public static void showGUI() { JFrame frame = new JFrame("Colored Trails"); frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); frame.add(partnerSelectionPanel); frame.setSize(600,400); frame.setVisible(true); } private static void updateGUI(final int i, final JLabel label, final JPanel partnerSelectionPanel) { SwingUtilities.invokeLater( new Runnable() { public void run() { label.setText(i + " seconds left."); } partnerSelectionPanel.setVisible(false); \\ <------------ } ); } So, my code update the "old" JPanel and them it makes the whole JPanel invisible. It was the idea. But it does not work. The compiler complains about the line indicated with "<------------". It writes: <identifier> expected, illegal start of type.

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