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  • Need an efficient algorithm solve this kind of complex structure

    - by Rizvan
    Problem Statement is : Given 2 Dimensional array, print output for example If 4 rows and 6 columns, output would be: 1 2 3 4 5 6 16 17 18 19 20 7 15 24 23 22 21 8 14 13 12 11 10 9 I tried it is looking like square within square but when I attempted this problem, I put so many while and if loops but didn't got exact answer. If row and columns increases how to handle it? This is not homework. I was learning solving complex structure so I need to understand it by some guidance.

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  • 'For' Loop Within a 'For' Loop and Then Another?

    - by BenjaminFranklin
    This has confused me quite a bit, but it's also really interesting! I want to loop through a grid of 9 elements in an array, multiply them all by 1/9. Then, I want to find the sum of those 9 elements and replace each individual element's with the value calculated as the sum. After I've done this, I want to move on to the next nine elements. To clarify, I want all 9 elements to be changed to myVal, in the code below. So far I've got the loop within a loop bit, but I don't know how to then go back and replace each of the values with the sum of all of them combined. Here's my code:- previousx = 0; previousy= 0; for (int x = previousx; x < previousx+4; x++) { for(int y = previousy; y < previousy+4; y++) { y = y*(1/9); yVal += y; } } Any advice would, of course, be greatly appreciated.

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  • Better alternative for PipedReader/PipedWriter?

    - by Esko Luontola
    I need to have a buffered char stream, into which I write in one thread and from which I read in another thread. Right now I'm using PipedReader and PipedWriter for it, but those classes cause a performance problem: PipedReader does a wait(1000) when its internal buffer is empty, which causes my application to lag visibly. Would there be some library which does the same thing as PipedReader/PipedWriter, but with better performance? Or will I have to implement my own wheels?

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  • Creating New Object of Other Class dynamicly ?

    - by Meko
    I am trying to create new object of other class in a for loop. like for(int i =0;i<10;i++){ Computer p1=new Computer(10,20); } and when I try anywhere to reach p1.someAction(); it say you must declare p1. But if I declare it on top of program how can I create again in loop? I also try only Computer p1; but it gave exeption ..

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  • How to access a superclass method from a nested class?

    - by m01
    I hope this code explains the problem: class Foo { void a() { / *stuff */ } } class Bar extends Foo { void a() { throw new Exception("This is not allowed for Bar"); } class Baz { void blah() { // how to access Foo.a from here? } } } I know that I may be doing something wrong, because inheritance perhaps shouldn't be used in such way. But it's the easiest way in my situation. And, beside that, I'm just curious. Is it possible?

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  • Switching application-wide theme programmatically?

    - by Cheezmeister
    EDIT: Related question here: Multi theme support in android app I'm attempting to get a user-chosen theme and feel like I'm frustratingly close. Defining the theme in AndroidManifest.xml works as it should, but (as best I can tell) can't change based on app preferences: <application android:theme="@style/theme_sunshine" android:icon="@drawable/icon" android:label="@string/app_name"> Alternatively, setting it dynamically in each activity also works: someChosenTheme = PreferenceManager.getDefaultSharedPreferences(this).getString("themePreference", "theme_twilight"); setTheme(someOtherChosenTheme); But that seems messy, and I'd rather set the theme for the entire app in one place. My first thought was to grab the application context as soon as my main activity launches and do it there: getApplicationContext().setTheme(R.style.theme_dummy); As best I can tell[0], this ought to do the trick, but in fact it's not doing anything--the entire app has the default Android style. Is the above valid, and if so, might I be doing something else dumb? I'm working in API level 3 if that matters. Prods in the right direction greatly appreciated! [0] http://developer.android.com/reference/android/content/Context.html#setTheme%28int%29 http://developer.android.com/reference/android/content/Context.html#getApplicationContext%28%29

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  • Running 2 threads simultaneously

    - by lamsaitat
    In the case of an IM client. I have made 2 separate threads to handle sending packets (by std io) and receiving packets. The question is how to make these 2 threads run simultaneously so that I can keep prompting for input while at the same time be ready to receive packets at any time? I have already tried setting a timer but the data is always lost receiving.

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  • Positioning child panels using FlowLayout

    - by extro
    I have two panels: main_panel child_panel The main_panel layout is set using: main_panel.setLayout(flowlayout) I then added child_panel to main_panel: main_panel.add(child_panel) The child_panel gets added to main_panel but its position is at the cross-section of horizontal midpoint and top vertical section of screen. I want child_panel to be at the top left corner, something I could have done by using child_panel.setlocation(a,b) method, if I have set the layout of main_panel as null. I have used FlowLayout here because I want components in the JPanel to keep adjusting with the size of JFrame. So can I add child_panel to main_panel at the exact location I want, even if I set the Layout of main_panel as not null?

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  • More than one JPanel in a Frame / having a brackground Image and another Layer with Components on the top

    - by user1905203
    I've got a JFrame with a JPanel in which there is a JLabel with an ImageIcon(). Everything's working perfectly, problem is i now want to add another JPanel with all the other stuff like buttons and so on to the JFrame. But it still shows the background Image on top and nothing with the second JPanel. Can someone help me? Here is an extract of my code: JFrame window = new JFrame("Http Download"); /* * Background Section */ JPanel panel1 = new JPanel(); JLabel lbl1 = new JLabel(); /* * Component Section */ JPanel panel2 = new JPanel(); JLabel lbl2 = new JLabel(); /* * Dimension Section */ Dimension windowSize = new Dimension(800, 600); Dimension screen = Toolkit.getDefaultToolkit().getScreenSize(); public HTTPDownloadGUI() { window.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); panel1.setLayout(null); panel1.setSize(windowSize); panel1.setOpaque(false); panel2.setLayout(null); panel2.setSize(windowSize); panel2.setOpaque(false); lbl1.setSize(windowSize); lbl1.setLocation(0, 0); lbl1.setIcon(new ImageIcon(getClass().getResource("bg1.png"))); panel1.add(lbl1); lbl2.setBounds(0, 0, 100, 100); //lbl2.setIcon(new ImageIcon(getClass().getResource("bg2.png"))); lbl2.setBackground(Color.GREEN); panel2.add(lbl2); panel1.add(panel2); window.add(panel1); int X = (screen.width / 2) - (windowSize.width / 2); int Y = (screen.height / 2) - (windowSize.height / 2); window.setBounds(X,Y , windowSize.width, windowSize.height); window.setVisible(true); }

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  • Is map/collection order stable between calls?

    - by John
    If I have a hash map and iterate over the objects repeatedly, is it correct that I'm not guaranteed the same order for every call? For example, could the following print two lines that differ from each other: Map<String,Integer> map = new HashMap<String,Integer>() {{ put("a", 1); put("b", 2); put("c", 3); }}; System.out.println(map); System.out.println(map); And is this the case for sets and collections in general? If so, what's the best way in case you have to iterate twice over the same collection in the same order (regardless of what order that is)? I guess converting to a list.

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  • Resultset To List

    - by Gnaniyar Zubair
    I want to convert my Resultset to List in my JSP page. and want to display all the values. This is my query: SELECT userId, userName FROM user; I have executed that using preparedstatement and got the Resultset. But how to convert it as a List and want to display the result like this: userID userName ------------------ 1001 user-X 1006 user-Y 1007 user-Z

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  • Simple servlet or filter to process form

    - by David
    Is there a simple framework for processing form submissions via a servlet? For my needs, a framework like STRUTS seems like over kill. My ideal processor would be a servlet that converts form elements into a bean object, possibly using typing information in the form to help with the conversion. Does something like this exist or is there another solution out there geared toward simpler needs? Thanks!

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  • Reference and Value confusion

    - by rgamber
    Hi I read this question on Stack overflow, and tried to do an example. I had the below code: public static void main(String[] args){ int i = 5; Integer I = new Integer(5); increasePrimitive(i); increaseObject(I); System.out.println(i); //Prints 5 - correct System.out.println(I); //Still prints 5 System.out.println(increaseObject2(I)); //Still prints 5 } public static void increasePrimitive(int n){ n++; } public static void increaseObject(Integer n){ n++; } public static int increaseObject2(Integer n){ return n++; } Does the increaseObject print 5 because the value of reference is changing inside that function? Am I right? I am confused why the increasedObject2 prints 5 and not 6. Can anyone please explain?

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  • How to make NOT IN statement via Restrictions

    - by slavig
    I used this trick: List statuses = new ArrayList(); Criteria criteria = session.createCriteria(MessageQueue.class); criteria.add(Restrictions.not(Restrictions.in("message_status", statuses))); and this code creates: ...from MESSAGE_QUEUE mq where not (mq.message_status in (?, ?, ?, ?))... but I need: ...from MESSAGE_QUEUE mq where mq.message_status NOT IN (?, ?, ?, ?) Du you think they are equal statements?

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  • Need help making this code more efficient

    - by Rendicahya
    I always use this method to easily read the content of a file. Is it efficient enough? Is 1024 good for the buffer size? public static String read(File file) { FileInputStream stream = null; StringBuilder str = new StringBuilder(); try { stream = new FileInputStream(file); } catch (FileNotFoundException e) { } FileChannel channel = stream.getChannel(); ByteBuffer buffer = ByteBuffer.allocate(1024); try { while (channel.read(buffer) != -1) { buffer.flip(); while (buffer.hasRemaining()) { str.append((char) buffer.get()); } buffer.rewind(); } } catch (IOException e) { } finally { try { channel.close(); stream.close(); } catch (IOException e) { } } return str.toString(); }

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