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  • how to make this in python

    - by user2980882
    The number reduction game Rules of the game: ? The first player to write a 0 wins. ? To start the game, Player 1 picks any whole number greater than 1, say 18. ? The players take turns reducing the number by either: o Subtracting 1 from the number his/her opponent just wrote, OR o Halving the number his/her opponent just wrote, rounding down if necessary. Write a Python program that lets two players play the number reduction game. Your program should: 1. Ask Player 1 to enter the starting number. 2. Use a while-loop to allow the players to take turns reducing the number until someone wins. 3. Each time a player enters a positive number (not 0), inform the other player what his/her choices are and ask him/her to enter the next number. 4. Declare the winner when someone enters 0. Example session: Player 1, enter a number greater than 1: 16 Player 2, your choices are 15 or 8: 15 Player 1, your choices are 14 or 7: 7 Player 2, your choices are 6 or 3:3 Player 1, your choices are 2 or 1:2 Player 2, your choices are 1 or 1:1 Player 1, your choices are 0 or 0:0 Player 1 wins

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  • Fastest method to define whether a number is a triangular number

    - by psihodelia
    A triangular number is the sum of the n natural numbers from 1 to n. What is the fastest method to find whether a given positive integer number is a triangular one? I suppose, there must be a hidden pattern in a binary representation of such numbers (like if you need to find whether a number is even/odd you check its least significant bit). Here is a cut of the first 1200th up to 1300th triangular numbers, you can easily see a bit-pattern here (if not, try to zoom out): (720600, '10101111111011011000') (721801, '10110000001110001001') (723003, '10110000100000111011') (724206, '10110000110011101110') (725410, '10110001000110100010') (726615, '10110001011001010111') (727821, '10110001101100001101') (729028, '10110001111111000100') (730236, '10110010010001111100') (731445, '10110010100100110101') (732655, '10110010110111101111') (733866, '10110011001010101010') (735078, '10110011011101100110') (736291, '10110011110000100011') (737505, '10110100000011100001') (738720, '10110100010110100000') (739936, '10110100101001100000') (741153, '10110100111100100001') (742371, '10110101001111100011') (743590, '10110101100010100110') (744810, '10110101110101101010') (746031, '10110110001000101111') (747253, '10110110011011110101') (748476, '10110110101110111100') (749700, '10110111000010000100') (750925, '10110111010101001101') (752151, '10110111101000010111') (753378, '10110111111011100010') (754606, '10111000001110101110') (755835, '10111000100001111011') (757065, '10111000110101001001') (758296, '10111001001000011000') (759528, '10111001011011101000') (760761, '10111001101110111001') (761995, '10111010000010001011') (763230, '10111010010101011110') (764466, '10111010101000110010') (765703, '10111010111100000111') (766941, '10111011001111011101') (768180, '10111011100010110100') (769420, '10111011110110001100') (770661, '10111100001001100101') (771903, '10111100011100111111') (773146, '10111100110000011010') (774390, '10111101000011110110') (775635, '10111101010111010011') (776881, '10111101101010110001') (778128, '10111101111110010000') (779376, '10111110010001110000') (780625, '10111110100101010001') (781875, '10111110111000110011') (783126, '10111111001100010110') (784378, '10111111011111111010') (785631, '10111111110011011111') (786885, '11000000000111000101') (788140, '11000000011010101100') (789396, '11000000101110010100') (790653, '11000001000001111101') (791911, '11000001010101100111') (793170, '11000001101001010010') (794430, '11000001111100111110') (795691, '11000010010000101011') (796953, '11000010100100011001') (798216, '11000010111000001000') (799480, '11000011001011111000') (800745, '11000011011111101001') (802011, '11000011110011011011') (803278, '11000100000111001110') (804546, '11000100011011000010') (805815, '11000100101110110111') (807085, '11000101000010101101') (808356, '11000101010110100100') (809628, '11000101101010011100') (810901, '11000101111110010101') (812175, '11000110010010001111') (813450, '11000110100110001010') (814726, '11000110111010000110') (816003, '11000111001110000011') (817281, '11000111100010000001') (818560, '11000111110110000000') (819840, '11001000001010000000') (821121, '11001000011110000001') (822403, '11001000110010000011') (823686, '11001001000110000110') (824970, '11001001011010001010') (826255, '11001001101110001111') (827541, '11001010000010010101') (828828, '11001010010110011100') (830116, '11001010101010100100') (831405, '11001010111110101101') (832695, '11001011010010110111') (833986, '11001011100111000010') (835278, '11001011111011001110') (836571, '11001100001111011011') (837865, '11001100100011101001') (839160, '11001100110111111000') (840456, '11001101001100001000') (841753, '11001101100000011001') (843051, '11001101110100101011') (844350, '11001110001000111110') For example, can you also see a rotated normal distribution curve, represented by zeros between 807085 and 831405?

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  • servlet ArrayList and HashMap problem witch result

    - by nonameplum
    Hi, I have that code List<Map<String, Object>> data = new ArrayList<Map<String, Object>>(); Map<String, Object> item = new HashMap<String, Object>(); data.clear(); item.clear(); int i = 0; while (i < 5){    item.put("id", i);    i++;    out.println("id: " + item.get("id"));    out.println("--------------------------");    data.add(item); } for(i=0 ; i<5 ; i++){    out.println("print data[" + i + "]" + data.get(i)); } Result of that is: id: 0 -------------------------- id: 1 -------------------------- id: 2 -------------------------- id: 3 -------------------------- id: 4 -------------------------- print data[0]{id=4} print data[1]{id=4} print data[2]{id=4} print data[3]{id=4} print data[4]{id=4} Why only last element is stored?

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  • Noob question about hibernate criteria

    - by Dimitri
    Hello, I have a class called User which has 2 properties : login/password. I am trying to authenticate a user in my application using hibernate criteria but my request doesn't work. [EDIT] The returned value is NULL. I have two users in my database for testing. Here is my code : @Override public User authenticate(String login, String password) throws NullPointerException { Session session = this.getSession(); User user = (User) session .createCriteria(User.class) .add( Restrictions.and( Property.forName("login").eq(login), Property.forName("password").eq(password) )).uniqueResult(); if (user == null){ throw new NullPointerException("User not found"); } return user; } Can someone tells me what is wrong with my code? Happy new Year 2011 !!

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  • what is the difference between MVC1 and MVC2

    - by Alaa
    I am using MVC design pattern in jsp-servlet web application, and want to what is the exact difference between MVC1 and MVC2 , can someone help? EDIT newly I hear that there is 2 versions of using MVC in servlet programming, I hear that in MVC1 there is kind of coupling between controller and view , but in MVC2 they overtake it, if someone know whether this is right or wrong I'll be very thankful.

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  • any way to simplify this with a form of dynamic class instantiation?

    - by gnychis
    I have several child classes that extend a parent class, forced to have a uniform constructor. I have a queue which keeps a list of these classes, which must extend MergeHeuristic. The code that I currently have looks like the following: Class<? extends MergeHeuristic> heuristicRequest = _heuristicQueue.pop(); MergeHeuristic heuristic = null; if(heuristicRequest == AdjacentMACs.class) heuristic = new AdjacentMACs(_parent); if(heuristicRequest == SimilarInterfaceNames.class) heuristic = new SimilarInterfaceNames(_parent); if(heuristicRequest == SameMAC.class) heuristic = new SameMAC(_parent); Is there any way to simplify that to dynamically instantiate the class, something along the lines of: heuristic = new heuristicRequest.somethingSpecial(); That would flatten that block of if statements.

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  • the way to get a value from a hidden type correctly

    - by kawtousse
    hey, in a html table i construct in each row an edit buttton like the following: retour.append("<input type=\"hidden\" id=\"id_"+nomTab+"_"+compteur+"\" value=\""+object.getIdDailyTimeSheet()+"\" name=\"hd_"+compteur+"\" />"); this is the hidden type then i do the following: retour.append("<button id=edit name=edit type=button onClick= editarow()>"); retour.append("<img src=edit.gif />"); retour.append("</button>"); retour.append("</td>"); here i am using the hidden type to differenciate between my rows with it. Now I am trying to get the parameter called here: value=\""+object.getIdDailyTimeSheet() in my servlet to do an update query based on the IdDailyTimeSheet. I didn't untill know find the way to get this value every time i click the edit button (i do its submit with the javascript). thanks for help.

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  • Maven: Re-use a POM file in every project.

    - by Zombies
    My goal is pretty simple actually but since there are multiple (and seemingly complex ways to do this) I wonder what I need to do... So I have certain runtime libraries (ADF libraries in particular) that are needed to be added to every project. This parent pom file will just have JAR dependencies in it. How can I use this pom file from a child pom file?

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  • Choosing an Open Source Application Server for J2EE

    - by Rafael
    Hello, I know this may be a recurring topic, but I have read a lot of articles and I still have doubts. Also, I would like to hear more recent opinions about this. The main requirements of my application server are: flexible configuration, support for a extremely high number of concurrent users. It will be a system for the mobile communications industry, so it must have high availability as well. I am going to develop a J2EE application and Open Source Applications Servers are my only option. I have use GlassFish for a very small project and I really liked it. Thank you very much for your advise.

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  • Subtype polymorphism and arrays

    - by user133466
    Computer[] labComputers = new Computer[10]; with public class Computer { ... void toString(){ // print computer specs } } public class Notebook extends Computer{ ... void toString(){ // print computer specs + laptop color } } each subscripted variable labComputers[i] can reference either a Computer object or a Notebook object because Notebook is a subclass of Computer. For the method call labComputers[i].toString(), polymorphism ensures that the correct toString method is called. I wonder what if we do Notebook[] labComputers = new Notebook[10]; what kind or error would I get if I reference with Computer object and a Notebook object

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  • ant debugging in eclipse

    - by Codenotguru
    I would like to know about the debugging capabilities of ANT using eclipse. Basically I have an ANT build script written by a colleague and I wanted to step through each target to see what are the various tasks that are beings called.

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  • Group Objects by Common Key

    - by Marshmellow1328
    I have a list of Customers. Each customer has an address and some customers may actually have the same address. My ultimate goal is to group customers based on their address. I figure I could either put the customers in some sort of list-based structure and sort on the addresses, or I could drop the objects into some sort of map that allows multiple values per key. I will now make a pretty picture: List: A1 - C1, A1 - C2, A2 - C3, A3 - C4, A3 - C5 Map: A1 A2 A3 C1 C3 C4 C2 C5 Which option (or any others) do you see as the best solution? Are there any existing classes that will make development easier?

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  • Magic squares, recursive

    - by user310827
    Hi, my problem is, I'm trying to permute all posibilities for a 3x3 square and check if the combination is magic. I've added a tweak with (n%3==0) if statement that if the sum of numbers in row differs from 15 it breaks the creation of other two lines... but it doesn't work. Any suggestions? I call the function with Permute(1). public static class Global { //int[] j = new int[6]; public static int[] a= {0,0,0,0,0,0,0,0,0}; public static int[] b= {0,0,0,0,0,0,0,0,0}; public static int count = 0; } public static void Permute(int n) { int tmp=n-1; for (int i=0;i<9;i++){ if (Global.b[i]==0 ) { Global.b[i]=1; Global.a[n-1]=i+1; if ((n % 3) == 0) { if (Global.a[0+tmp]+Global.a[1+tmp]+Global.a[2+tmp] == 15) { if (n<9) { Permute(n+1); } else { isMagic(Global.a); } } else break; } else { Permute(n+1); } Global.b[i]=0; } } }

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  • Enforce "equals" in an interface

    - by Fredrik
    I have an interface and I want everyone who implements this interface to implements an overrridden "equals" method. Is there a way to make sure that happens? The way I guess this will happen is that the class that implements my interface will automatically get the equals from Object therefore making the interface happy.

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  • Why doesn't list.get(0).equals(null) work?

    - by Jessy
    The first index is set to null (empty), but it doesn't print the right output, why? //set the first index as null and the rest as "High" String a []= {null,"High","High","High","High","High"}; //add array to arraylist ArrayList<Object> choice = new ArrayList<Object>(Arrays.asList(a)); for(int i=0; i<choice.size(); i++){ if(i==0){ if(choice.get(0).equals(null)) System.out.println("I am empty"); //it doesn't print this output } }

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  • ontouch - Switching positions of two views(images) in Android

    - by idish
    I've been looking for that 2 days long and haven't found anything related to it. I'll give an example for my goal. Let's say I have 2 images positioned side by side horizontally. I want the user to be able to switch their positions onlongtouch listener. so let's say that the first image was on the left and the second was on the right side, after switching positions between them, the first image would be in the right and the second would be on the left side. Basically, it is just like in the launcher where you can switch apps positions. Please, if anything is not clear for you, I would like to know, and I'll try to explain it better, thank you.

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  • How to deal with the Hibernate hql multi-join query result in an Object-Oriented Way?

    - by EugeneP
    How to deal with the Hibernate hql multi-join query result in an Object-Oriented Way? As I see it returns a list of Objects. yes, it is tricky and only you who write the query know what should the query return (what objects). But are there ways to simplify things, so that it returned specific objects with no need in casting Object to a specific class according to its position in the query ? Maybe Spring can simplify things here? It has the similar functionality for JDBC, but I don't see if it can help in a similar way with Hibernate.

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  • Is it standard behavior for this code to throw a NullPointerException?

    - by Eric
    I've had a big problem in some library code, which I've pinned down to a single statement: System.out.println((String) null); Ok, the code doesn't actually look like that, but it certainly calls println with a null argument. Doing this causes my whole applicaio to throw an unexpected NullPointerException. In general, should println throw this exception under that circumstance, or is this non-standard behavior due to a poor implementation of the out instance?

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