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• Struts html:checkbox query

  - by sarah

  Hi All, i have the following code . <td> <html:checkbox name="userForm" property="isActive" /></td> and in Form is have property called isActive of type char ,how would i get the checked value of it ,i am getting some symbols like 'o' if checked. I am using userform.getIsActive() ,where i am going wrong .I want 'y' or 'n' values

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• Why is the table attribute of Hashtable serialized?

  - by ppoliani

  Why is the table field of Hashtable serialized, although it is marked as transient?

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• Does grails use spring's MVC front controller or it has its open implementation?

  - by Blankman

  Does grails use spring's MVC front controller or it has its open implementation?

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• Hibernate Performance Best Practice?

  - by user829237

  Im writing a Web application using Hibernate 3. So, after a while i noticed that something was slow. So i tested hibernate profiler and found that hibernate will make unreasonably many db-calls for simple operation. The reason is ofcourse that i load an Object (this object has several "parents") and these "parents" have other "parents". So basicly hibernate loads them all, even though i just need the basic object. Ok, so i looked into lazy-loading. Which lead me into the Lazyloading-exception, because i have a MVC webapp. So now i'm a bit confused as to what is my best approach to this. Basicly all I need is to update a single field on an object. I already have the object-key. Should I: 1. Dig into Lazy-loading. And then rewrite my app for a open-session-view? 2. Dig into lazy-loading. And then rewrite my dao's to be more specific. E.g. writing DAO-methods that will return objects instanciated with only whats necessary for each use-case? Could be a lot of extra methods... 3. Scratch hibernate and do it myself? 4. Cant really think of other solutions right now. Any suggestions? What is the best practice?

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• How do I declare a variable? [closed]

  - by Guy

  How do I declare a variable? Thanks.

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• Tapestry5 display grid component using a hashmap

  - by Eldred

  Hi there I am trying to attempt to display a hashmap using a grid component. If I use List list = CollectionFactory.newList(MyHashMap) it returns a list however on my template page I see Empty and false when passing my parameter t:souce="list" to my grid component, therefore my grid component only returns one row. Some code snippets would be a great help. Many thanks

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• What is the benefit of using a factory class in the following code?

  - by Emanuil

  Here's the code: SAXParserFactory mySAXParserFactory = SAXParserFactory.newInstance(); SAXParser mySAXParser = mySAXParserFactory.newSAXParser(); Why use that if you can use something like: SAXParser mySAXParser = new SAXParser();

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• 'For' Loop Within a 'For' Loop and Then Another?

  - by BenjaminFranklin

  This has confused me quite a bit, but it's also really interesting! I want to loop through a grid of 9 elements in an array, multiply them all by 1/9. Then, I want to find the sum of those 9 elements and replace each individual element's with the value calculated as the sum. After I've done this, I want to move on to the next nine elements. To clarify, I want all 9 elements to be changed to myVal, in the code below. So far I've got the loop within a loop bit, but I don't know how to then go back and replace each of the values with the sum of all of them combined. Here's my code:- previousx = 0; previousy= 0; for (int x = previousx; x < previousx+4; x++) { for(int y = previousy; y < previousy+4; y++) { y = y*(1/9); yVal += y; } } Any advice would, of course, be greatly appreciated.

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• Are there any production quality JSF 2 implementations yet?

  - by Alex Argo

  Are there any production quality JSF 2 implementations yet? If so what are they?

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• Variable from block is put into a calculation but throws off wrong reading

  - by user2926620

  I am having troubles with trying to retrieve a double variable that is already established outside the block and called inside but I want to return the value of the same variable so that I can apply it to a calculation. the variable that I want returned is: double quarter = 0; but when I plug it into quarter in my first else/if statement, it plugs in 0 and not the value in my switch block. What can I do to retrieve the value? double quarter = 0; //Date entry will be calculated by how much KW user enters switch (input) { case "2/15/13": quarter = kwUsed * 0.10; break; case "4/15/13": quarter = kwUsed * 0.12; break; case "8/15/13": quarter = kwUsed * 0.15; break; case "11/15/13": quarter = kwUsed * 0.15; break; default: System.out.println("Invalid date"); } //Declaring variables for calculations double base = 0; double over = 0; double excess = 0; double math1 = 0; double math2 = 0; //KW Calculations if (kwUsed <= 350) { base = quarter; }else if (kwUsed <= 500) { math1 = ((kwUsed - 350) * quarter); base = ((kwUsed * quarter) - math1); over = ((math1 * 0.1) + math1); }else if (kwUsed > 500) { math2 = ((kwUsed - 350) * 0.1); base = ((kwUsed * 0.1) - math2); math2 = ((kwUsed -350) - 50); over = ((math2 * 0.1) + (15 * 0.1)); double math3 =((kwUsed - 500) * 0.1); excess = ((math3 * 0.25) + math3); } Edited to clarify question.

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• Best practice for an application with GUI

  - by chronosphenomena

  Hi, I'm about to start an application which will have both console and GUI interfaces. What I wan't to achieve is COMPLETE decoupling of application logic from interface. In future, I may also add web interface, and I don't want to change anything in my application. Is there a good example (perhaps some open source project) where I can learn how this should be done properly.... also I'd appreciate advices/guidelines on how to do this. Thanks

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• Ordered Data Structure that allows to efficiently remove duplicate items

  - by devoured elysium

  I need a data structure that Must be ordered (adding elements a, b and c to an empty structure, will make them be at positions 0, 1 and 2). Allows to add repeated items. This is, I can have a list with a, b, c, a, b. Allows removing all ocurrences of a given item (if I do something like delete(1), it will delete all ocurrences of 1 in the structure). I can't really pick what the best data structure could be in here. I thought at first about something like a List(the problem is having an O(n) operation when removing items), but maybe I'm missing something? What about trees/heaps? Hashtables/maps? I'll have to assume I'll do as much adding as removing with this data structure. Thanks

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• What to prefer in the following case?

  - by GK

  say suppose I have class as : public class Age { private int age; public int getAge() { return this.age; } } In my Main class I am calling the getAge() method many times. So I wanted to know is it advisable to call so many times or call once and assign it to some variable and use that variable. Which is best and why?

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• out-of-the-box way to get an idmap from hibernate for a given entity?

  - by Geert-Jan

  Over and over again I notive myself getting a list from hibernate, and the first thing next is put it in an idmap like: List<House> entities = s.createCriteria(House.class).list(); Map<String,House> entitymap = new HashMap<String,House>(); for(TA_entity e:entities){ entitymap.put(e.getId(), e); } Is there a way to get this directly out of hibenerate? afterall Hibernate is familiar with the id.

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• can we convert integer into character

  - by D.J.

  we can convert character to an integer equivalent to the ASCII value of the same but can we do the reverse thing ie convert a given ASCII value to its character equivalent?

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• How can I create a new folder in my web-app (for upload photo album) with Grails on Tomcat ?

  - by quilovnic

  i want to create a photo album. But I want to organize on the server the albums so I want to create new folders : /myapp /myapp/albums /myapp/albums/1 /myapp/albums/2 ... How can I do that on tomcat with Grails ? It create all new folder in tomcat/bin not in tomcat/webapps/myapp/

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• extra storage merge sort

  - by davit-datuashvili

  I need make a merge sort using an additional array. Here is my code: public class extra_storage{ public static void main(String[]args) { int x[]=new int[]{12,9,4,99,120,1,3,10}; int a[]=new int[x.length]; mergesort(x,0,x.length-1,a); for (int i=0;i<x.length;i++){ System.out.println(x[i]); } } public static void mergesort(int x[],int low,int high, int a[]){ if (low>=high) { return; } int middle=(low+high)/2; mergesort(x,low,middle,a); mergesort(x,middle+1,high,a); int k; int lo=low; int h=high; for (k=low;k<high;k++) if ((lo<=middle ) && ((h>high)||(x[lo]<x[h]))){ a[k]=x[lo++]; } else { a[k]=x[h++]; } for (k=low;k<=high;k++){ x[k]=a[k]; } } } But something is wrong. When I run it the output is this: 1 0 3 0 4 0 9 0 What is the problem?

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• What is the command-line input to produce the javadoc?

  - by Bernard

  After writing all the comments inside the code about the javadoc such as /** * This method compares the student's answer to the standard answer * @param ans The student's answer * @return True for correct answer; False for incorrect answer */ boolean compareAnswer(int ans); I guess it starts with : javadoc [optionss] [packages|files] I'm not sure what is the regular or default [option] and how can I say to produce it in my current home directory?

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• How to avoid wasting time during compilation during development?

  - by user259576

  Hello, I'm working with a small team of developers. My job is to convert a Make project (with Intellij Idea 9.0) into a Maven 2 project. The problem is : we spend a lot of time during the development. With Make, only one complete build was required and then any change did not consume a lot of time (almost instantaneously). On the other hand, with Maven 2, a little change takes a lot of time to run. Any solution ? Thanks.

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• How do I pause main() until all other threads have died?

  - by thechiman

  In my program, I am creating several threads in the main() method. The last line in the main method is a call to System.out.println(), which I don't want to call until all the threads have died. I have tried calling Thread.join() on each thread however that blocks each thread so that they execute sequentially instead of in parallel. Is there a way to block the main() thread until all other threads have finished executing? Here is the relevant part of my code: public static void main(String[] args) { //some other initialization code //Make array of Thread objects Thread[] racecars = new Thread[numberOfRaceCars]; //Fill array with RaceCar objects for(int i=0; i<numberOfRaceCars; i++) { racecars[i] = new RaceCar(laps, args[i]); } //Call start() on each Thread for(int i=0; i<numberOfRaceCars; i++) { racecars[i].start(); try { racecars[i].join(); //This is where I tried to using join() //It just blocks all other threads until the current //thread finishes. } catch(InterruptedException e) { e.printStackTrace(); } } //This is the line I want to execute after all other Threads have finished System.out.println("It's Over!"); } Thanks for the help guys! Eric

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• How can I set hibernate database config from outside config file?

  - by newbie

  I need to have hibernate database config set from outside text file, how can I do it? Is there some kind of method for this, or do I have to make my own?

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• What is the security risk of object reflection?

  - by Legend

  So after a few hours of workaround the limitation of Reflection being currently disabled on the Google App Engine, I was wondering if someone could help me understand why object reflection can be a threat. Is it because I can inspect the private variables of a class or are there any other deeper reasons?

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• What is mean by web services

  - by Fresher

  can anybody tell me what is mean by web services.How it works...and more information about it.

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• Is it possible to edit data in jtable and save it?

  - by Edan

  Hello, I would like to know if it's possible to view my values through JTable and then edit them through there?

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• A typical lifecycle of a Hibernate object in a web app - ?

  - by EugeneP

  Describe please a typical lifecycle of a Hibernate object (that maps to a db table) in a web app. Suppose, you create a new instance of an object and persist in the db. But during the app lifetime you'll be working on a detached object and finally you need to update it in the database, for example on exit. How does it look like with hibernate and spring? p.s. Can transactions and sessions live between servlet transitions? So that we opened 1 session and use it in all servlets without a need to reopen it?

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