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  • The Skyline Problem.

    - by zeroDivisible
    I just came across this little problem on UVA's Online Judge and thought, that it may be a good candidate for a little code-golf. The problem: You are to design a program to assist an architect in drawing the skyline of a city given the locations of the buildings in the city. To make the problem tractable, all buildings are rectangular in shape and they share a common bottom (the city they are built in is very flat). The city is also viewed as two-dimensional. A building is specified by an ordered triple (Li, Hi, Ri) where Li and Ri are left and right coordinates, respectively, of building i and Hi is the height of the building. In the diagram below buildings are shown on the left with triples (1,11,5), (2,6,7), (3,13,9), (12,7,16), (14,3,25), (19,18,22), (23,13,29), (24,4,28) and the skyline, shown on the right, is represented by the sequence: 1, 11, 3, 13, 9, 0, 12, 7, 16, 3, 19, 18, 22, 3, 23, 13, 29, 0 The output should consist of the vector that describes the skyline as shown in the example above. In the skyline vector (v1, v2, v3, ... vn) , the vi such that i is an even number represent a horizontal line (height). The vi such that i is an odd number represent a vertical line (x-coordinate). The skyline vector should represent the "path" taken, for example, by a bug starting at the minimum x-coordinate and traveling horizontally and vertically over all the lines that define the skyline. Thus the last entry in the skyline vector will be a 0. The coordinates must be separated by a blank space. If I will not count declaration of provided (test) buildings and including all spaces and tab characters, my solution, in Python, is 223 characters long. Here is the condensed version: B=[[1,11,5],[2,6,7],[3,13,9],[12,7,16],[14,3,25],[19,18,22],[23,13,29],[24,4,28]] # Solution. R=range v=[0 for e in R(max([y[2] for y in B])+1)] for b in B: for x in R(b[0], b[2]): if b[1]>v[x]: v[x]=b[1] p=1 k=0 for x in R(len(v)): V=v[x] if p and V==0: continue elif V!=k: p=0 print "%s %s" % (str(x), str(V)), k=V I think that I didn't made any mistake but if so - feel free to criticize me. EDIT I don't have much reputation, so I will pay only 100 for a bounty - I am curious, if anyone could try to solve this in less than .. lets say, 80 characters. Solution posted by cobbal is 101 characters long and currently it is the best one. ANOTHER EDIT I thought, that 80 characters is a sick limit for this kind of problem. cobbal, with his 46 character solution totaly amazed me - though I must admit, that I spent some time reading his explanation before I partially understood what he had written.

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  • How can I successfully dechiper Instruments Messages for iPhone Leak

    - by dubbeat
    Hi, I have a memory leak in my app. (This is the first of many I'm sure :() I've being trying to use Instruments to find it. Instruments gives me a lot of information but I think I must just not know how to use this information. What I did so far was 1) Run the app with Instruments 2) Memory Leak Occurs named general -stack 16 3) Find general - stack 16 in the object allocations part of instruments 4) The information here says the event type is a malloc, that webcore is responsible and the something named WKSetCurrentGraphicContext is the responsible caller. How can I use this given information to discover where in my code the leak is being caused? If I comment out the following function I don't get the leak warning so I guess it should be in there somewhere but I can't see where -(void)constructFeatured { NSString *imageName =[[NSString alloc] initWithFormat:@"%@%@%@",@"http://myweb/avatar_", featuredValueObject.featured_promo_artistid, @".jpg"]; NSURL *url = [NSURL URLWithString:imageName]; CGRect frame; frame.size.width=100; frame.size.height=100; frame.origin.x=20; frame.origin.y=39; [imageName release]; imageName=nil; SDWebImageManager *manager = [SDWebImageManager sharedManager]; UIImage *cachedImage = [manager imageWithURL:url]; if (cachedImage) { cachedImage =[ImageManipulator makeRoundCornerImage:cachedImage : 10 : 10]; UIImageView *avatarimageview = [[UIImageView alloc]initWithImage:cachedImage ]; avatarimageview.frame=frame; [self.view addSubview:avatarimageview]; UIView *spinny = [self.view viewWithTag:SPINNY_TAG]; [spinny removeFromSuperview]; [avatarimageview release]; } else { [manager downloadWithURL:url delegate:self]; } NSURL *url2 =[NSURL URLWithString:[NSString stringWithFormat:@"%@%@%@",@"http://myweb/", featuredValueObject.featured_promo_artistcountry , @".png"]]; CGRect flagframe; flagframe.size.width=16; flagframe.size.height=11; flagframe.origin.x=130; flagframe.origin.y=40; NSData* data = [[NSData alloc] initWithContentsOfURL:url2]; UIImage* img = [[UIImage alloc] initWithData:data]; UIImageView *imageflagview = [[UIImageView alloc] initWithImage: img]; imageflagview.frame=flagframe; [self.view addSubview:imageflagview]; [imageflagview release]; imageflagview=nil; [data release]; [img release]; [url release]; artistname =[[UILabel alloc]initWithFrame:CGRectMake(130,75, 200, 15)]; [artistname setFont:[UIFont fontWithName:@"Arial" size:(16.0)]]; artistname.backgroundColor= [UIColor clearColor]; artistname.textColor=[UIColor whiteColor]; artistname.text=featuredValueObject.featured_promo_artistname; [self.view addSubview:artistname]; [artistname release]; hasConstructedFeatured=YES; [featuredValueObject release]; featuredValueObject=nil; }

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  • Custom UISwitch & App Store approval

    - by pix0r
    After doing some reading, I've found that you can customize the text and color on a UISwitch control. I'm curious if these methods will cause problems trying to get my app approved and included in the App Store. Sample code taken from iPhone Developer's Cookbook Sample Code: // Custom font, color switchView = [[UICustomSwitch alloc] initWithFrame:CGRectZero]; [switchView setCenter:CGPointMake(160.0f,260.0f)]; [switchView setLeftLabelText: @"Foo"]; [switchView setRightLabelText: @"Bar"]; [[switchView rightLabel] setFont:[UIFont fontWithName:@"Georgia" size:16.0f]]; [[switchView leftLabel] setFont:[UIFont fontWithName:@"Georgia" size:16.0f]]; [[switchView leftLabel] setTextColor:[UIColor yellowColor]];

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  • SQL Server 2008, Kerberos and SPN

    - by andrew007
    Hi, I installed SQL Server 2008 on a Win XP SP2 workstation in a AD domain and configured to run with the "Network Service" account. In my error log I have the following message (Event ID:26037): The SQL Server Network Interface library could not register the Service Principal Name (SPN) for the SQL Server service. **Error: 0xd, state: 13**. Failure to register an SPN may cause integrated authentication to fall back to NTLM instead of Kerberos. This is an informational message. Further action is only required if Kerberos authentication is required by authentication policies. The strange thing is that I have another SQL Server 2008 installation in a Win 2003 server configured in the same way and there I do not have this message. My questions are: Does anybody know if there are limitations with Kerberos on Windows XP and SQL Server? Why the SPN is not automatically registered on Win XP when I use the "Network Service" but it works on Windows 2003 server? THANKS!

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  • Error: Bad Base64Coder input character

    - by sebby_zml
    Hi, I am currently facing an error called "Bad Base64Coder input character at ..." Here is my code in java. String nonce2 = strNONCE; byte[] nonceBytes1 = Base64Coder.decode(nonce2); System.out.println("nonceByte1 value : " + nonceBytes1); The problem now is i get Bad Base64Coder input character error and the nonceBytes1 value is printed as null. I am trying to decode the nonce2 from Base64Coder. My strNONCE value is 16 byte[] nonce = new byte[16]; Random rand; rand = SecureRandom.getInstance ("SHA1PRNG"); rand.nextBytes(nonce); //convert byte array to string. strNONCE = new String(nonce); any help is deeply appreciated

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  • C# XP Sound QuickFix

    - by ikurtz
    I have this: ThreadPool.QueueUserWorkItem(new WaitCallback(FireAttackProc), fireResult); and FireAttackProc: private void FireAttackProc(Object stateInfo) { // Process Attack/Fire (local) lock (_procLock) { // build status message String status = "(Away vs. Home)"; // get Fire Result state info FireResult fireResult = (FireResult)stateInfo; // update home grid with attack information GameModel.HomeCellStatusSet(fireResult.FireGridLocation, Cell.cellState.Lock); this.Invoke(new Action(delegate() { RefreshHomeGrid(); })); status = status + "(Attack Coordinate: (" + GameModel.alphaCoords(fireResult.FireGridLocation.Column) + "," + fireResult.FireGridLocation.Row + "))(Result: "; // play audio data if true if (audio) { String Letters; Stream stream; SoundPlayer player; Letters = GameModel.alphaCoords(fireResult.FireGridLocation.Column); stream = Properties.Resources.ResourceManager.GetStream("_" + Letters); player = new System.Media.SoundPlayer(stream); player.PlaySync(); Letters = fireResult.FireGridLocation.Row.ToString(); stream = Properties.Resources.ResourceManager.GetStream("__" + Letters); player = new System.Media.SoundPlayer(stream); player.PlaySync(); stream.Dispose(); player.Dispose(); } if (audio) { SoundPlayer fire = new SoundPlayer(Properties.Resources.fire); fire.PlaySync(); fire.Dispose(); } // deal with hit/miss switch (fireResult.Hit) { case true: this.Invoke(new Action(delegate() { GameModel.HomeCellStatusSet(fireResult.FireGridLocation, Cell.cellState.Hit); status = status + "(Hit)"; })); if (audio) { SoundPlayer hit = new SoundPlayer(Properties.Resources.firehit); hit.PlaySync(); hit.Dispose(); } break; case false: this.Invoke(new Action(delegate() { GameModel.HomeCellStatusSet(fireResult.FireGridLocation, Cell.cellState.Miss); status = status + "(Miss)"; })); GameModel.PlayerNextTurn = NietzscheBattleshipsGameModel.GamePlayers.Home; if (audio) { SoundPlayer miss = new SoundPlayer(Properties.Resources.firemiss); miss.PlaySync(); miss.Dispose(); } break; } // refresh home grid with updated data this.Invoke(new Action(delegate() { RefreshHomeGrid(); })); GameToolStripStatusLabel.Text = status + ")"; // deal with ship destroyed if (fireResult.ShipDestroyed) { status = status + "(Destroyed: " + GameModel.getShipDescription(fireResult.DestroyedShipType) + ")"; if (audio) { Stream stream; SoundPlayer player; stream = Properties.Resources.ResourceManager.GetStream("_home"); player = new System.Media.SoundPlayer(stream); player.PlaySync(); player.Dispose(); stream.Dispose(); string ShipID = fireResult.DestroyedShipType.ToString(); stream = Properties.Resources.ResourceManager.GetStream("_" + ShipID); player = new System.Media.SoundPlayer(stream); player.PlaySync(); player.Dispose(); stream.Dispose(); stream = Properties.Resources.ResourceManager.GetStream("_destroyed"); player = new System.Media.SoundPlayer(stream); player.PlaySync(); player.Dispose(); stream.Dispose(); } } // deal with win condition if (fireResult.Win) { if (audio) { Stream stream; SoundPlayer player; stream = Properties.Resources.ResourceManager.GetStream("_home"); player = new System.Media.SoundPlayer(stream); player.PlaySync(); player.Dispose(); stream = Properties.Resources.ResourceManager.GetStream("_loses"); player = new System.Media.SoundPlayer(stream); player.PlaySync(); player.Dispose(); } GameModel.gameContracts = new GameContracts(); } // update status message if (fireResult.Hit) { if (!fireResult.Win) { status = status + "(Turn: Away)"; LockGUIControls(); } } // deal with turn logic if (GameModel.PlayerNextTurn == NietzscheBattleshipsGameModel.GamePlayers.Home) { this.Invoke(new Action(delegate() { if (!fireResult.Win) { status = status + "(Turn: Home)"; AwayTableLayoutPanel.Enabled = true; } })); } // deal with win condition if (fireResult.Win) { this.Invoke(new Action(delegate() { status = status + "(Game: Home Loses)"; CancelToolStripMenuItem.Enabled = false; NewToolStripMenuItem.Enabled = true; LockGUIControls(); })); } // display completed status message GameToolStripStatusLabel.Text = status + ")"; } } The issue is this: Under Vista/win7 the sound clips in the FireAttackProc plays. But under XP the logic contained within FireAttackProc gets executed but none of the sound clips play. Is there a quick solution to this so the sound will play under XP? I ask for a quick solution because i am happy being able to execute fully in Vista/Win7 but would be great if there was a quick solution so it would be XP compitable also. Thank you.

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  • Alternative to Turbo C

    - by Asad Jibran Ahmed
    My university is hosting a Programming Competition, and have decided to support Turbo C (the 16-bit DOS version) as a valid programming environment. I have just read that PC^2, the software that is going to be used to auto-judge the competition, does not support 16-bit programs. So, is there any alternative to Turbo C that I can use. I need the same header files, and the compiler would need to support all the outdated C standards that Turbo C supports. But the output needs to be 32-bit. Is there any compiler that can satisfy these conditions?

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  • Runtime error of TASM language help!

    - by dominoos
    .model small .stack 400h .data message db "hello. ", 0ah, 0dh, "$" firstdigit db ? seconddigit db ? thirddigit db ? number dw ? newnumber db ? anumber dw 0d bnumber dw 0d Firstn db 0ah, 0dh, "Enter first 3 digit number: ","$" secondn db 0ah, 0dh, "Enter second 3 digit number: ","$" messageB db 0ah, 0dh, "HCF of two number is: ","$" linebreaker db 0ah, 0dh, ' ', 0ah, 0dh, '$' .code Start: mov ax, @data ; establish access to the data segment mov ds, ax ; mov number, 0d mov dx, offset message ; print the string "yob choi 0648293" mov ah, 9h int 21h num: mov dx, offset Firstn ; print the string "put 1st 3 digit" mov ah, 9h int 21h ;run JMP FirstFirst ; jump to FirstFirst FirstFirst: ;first digit mov ah, 1d ;bios code for read a keystroke int 21h ;call bios, it is understood that the ascii code will be returned in al mov firstdigit, al ;may as well save a copy sub al, 30h ;Convert code to an actual integer cbw ;CONVERT BYTE TO WORD. This takes whatever number is in al and ;extends it to ax, doubling its size from 8 bits to 16 bits ;The first digit now occupies all of ax as an integer mov cx, 100d ;This is so we can calculate 100*1st digit +10*2nd digit + 3rd digit mul cx ;start to accumulate the 3 digit number in the variable imul cx ;it is understood that the other operand is ax ; the result will use both dx::ax ;dx will contain only leading zeros add anumber, ax ;save ;Second Digit mov ah, 1d ;bios code for read a keystroke int 21h ;call bios, it is understood that the ascii code will be returned in al mov seconddigit, al ;may as well save a copy sub al, 30h ;Convert code to an actual integer cbw ;CONVERT BYTE TO WORD. This takes whatever number is in al and ;extends it to ax, boubling its size from 8 bits to 16 bits ;The first digit now occupies all of ax as an integer mov cx, 10d ;continue to accumulate the 3 digit number in the variable mul cx ;it is understood that the other operand is ax, containing first digit ;the result will use both dx::ax ;dx will contain only leading zeros. add anumber, ax ;save ;third Digit mov ah, 1d ;samething as above int 21h ; mov thirddigit, al ; sub al, 30h ; cbw ; add anumber, ax ; jmp num2 ;go to checks Num2: mov dx, offset secondn ; print the string "put 2nd 3 digits" mov ah, 9h int 21h ;run JMP SecondSecond SecondSecond: ;first digit mov ah, 1d ;bios code for read a keystroke int 21h ;call bios, it is understood that the ascii code will be returned in al mov firstdigit, al ;may as well save a copy sub al, 30h ;Convert code to an actual integer cbw ;CONVERT BYTE TO WORD. This takes whatever number is in al and ;extends it to ax, doubling its size from 8 bits to 16 bits ;The first digit now occupies all of ax as an integer mov cx, 100d ;This is so we can calculate 100*1st digit +10*2nd digit + 3rd digit mul cx ;start to accumulate the 3 digit number in the variable imul cx ;it is understood that the other operand is ax ; the result will use both dx::ax ;dx will contain only leading zeros add bnumber, ax ;save ;Second Digit mov ah, 1d ;bios code for read a keystroke int 21h ;call bios, it is understood that the ascii code will be returned in al mov seconddigit, al ;may as well save a copy sub al, 30h ;Convert code to an actual integer cbw ;CONVERT BYTE TO WORD. This takes whatever number is in al and ;extends it to ax, boubling its size from 8 bits to 16 bits ;The first digit now occupies all of ax as an integer mov cx, 10d ;continue to accumulate the 3 digit number in the variable mul cx ;it is understood that the other operand is ax, containing first digit ;the result will use both dx::ax ;dx will contain only leading zeros. add bnumber, ax ;save ;third Digit mov ah, 1d ;samething as above int 21h ; mov thirddigit, al ; sub al, 30h ; cbw ; add bnumber, ax ; jmp compare ;go to compare compare: CMP ax, anumber ;comparing numbB and Number JA comp1 ;go to comp1 if anumber is bigger CMP ax, anumber ; JB comp2 ;go to comp2 if anumber is smaller CMP ax, anumber ; JE equal ;go to equal if two numbers are the same JMP compare ;go to compare (avioding error) comp1: SUB ax, anumber; subtract smaller number from bigger number JMP compare ; comp2: SUB anumber, ax; subtract smaller number from bigger number JMP compare ; equal: mov ah, 9d ;make linkbreak after the 2nd 3 digit number mov dx, offset linebreaker int 21h mov ah, 9d ;print "HCF of two number is:" mov dx, offset messageB int 21h mov ax,anumber ;copying 2nd number into ax add al,30h ; converting to ascii mov newnumber,al ; copying from low part of register into newnumb mov ah, 2d ;bios code for print a character mov dl, newnumber ;we had saved the ascii code here int 21h ;call to bios JMP exit; exit: mov ah, 4ch int 21h ;exit the program End hi, this is a program that finds highest common factor of 2 different 3digit number. if i put 200, 235,312 (low numbers) it works fine. but if i put 500, 550, 654(bigger number) the program crashes after the 2nd 3digit number is entered. can you help me to find out what problem is?

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  • Query for props list with or without values

    - by vitto
    Hi, I'm trying to make a SELECT on three relational tables like these ones: table_materials -> material_id - material_name table_props -> prop_id - prop_name table_materials_props - row_id -> material_id -> prop_id - prop_value On my page, I'd like to get a result like this one but i have some problem with the query: material prop A prop B prop C prop D prop E wood 350 NULL NULL 84 16 iron NULL 17 NULL NULL 201 copper 548 285 99 NULL NULL so the query should return something like: material prop_name prop_value wood prop A 350 wood prop B NULL wood prop C NULL wood prop D 84 wood prop E 16 // and go on with others rows i thought to use something like: SELECT * FROM table_materials AS m INNER JOIN table_materials_props AS mp ON m.material_id = mp.material_id INNER JOIN table_materials_props AS p ON mp.prop_id = p.prop_id ORDER BY p.prop_name the problem is the query doesn't return the NULL values, and I need the same prop order for all the materials regardless of prop values are NULL or not I hope this example is clear!

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  • Best way to represent Bit Arrays in C#??

    - by divinci
    Hi all, I am currently building a DHCPMessage class in c#. RFC is available here : http://www.faqs.org/rfcs/rfc2131.html Pseudo public object DHCPMessage { bool[8] op; bool[8] htype; bool[8] hlen; bool[8] hops; bool[32] xid; bool[16] secs; bool[16] flags; bool[32] ciaddr; bool[32] yiaddr; bool[32] siaddr; bool[32] giaddr; bool[128] chaddr; bool[512] sname; bool[1024] file; bool[] options; } If we imagine that each field is a fixed length bit array, what is : The most versitile Best practice way of representing this as a class??? OR.. how would you write this? :)

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  • How to implement SCORM in Objective C

    - by iranjan
    Hey, Do you know how to implement SCORM (Sharable Content Object Reference Model) in Objective C for eLearning content? Let me explain you what exactly I am looking for. I have one MCQ (multiple choice question) application which has 4 questions. On attempting each question I want my application to interact with a SCORM compatible server with result (whether the user has attempted correct one or not). The communication channel should be to and fro. May be at the end of the MCQ I want to show result which will come from the server with some calculations*(like Score : 85% number of attempts : 16 average score:16.7% etc.)*. How should I go about it? Please guide if you have already achieved it regards Ranjan.

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  • SVN: Create a dump file of a folder

    - by DarkJaff
    I'm trying to create a dump file of a folder in my SVN repository.(My goal is to import this dump on another repository, but that's another story). I've read like 20 pages about this and they all tell me to use svndumpfilter but I can't seem to make it work. Here is my command: C:\>svnadmin dump d:/SvnData/TestingSVN/ | svndumpfilter include /TestingSVN/Trunk/Fms/ > d:\FMS.txt The output in the command line is this strange thing: Including prefixes: '/TestingSVN/Trunk/Fms' * Dumped revision 0. Revision 0 com*m iDtutmepde da sr e0v.isi n 1. Revision 1 committed as 1. * Dumped revision 2. Revision 2 committed a*s D2u.mpe revision 3. Revisio*n D3u mcpoemdm irtetveids iaosn 34.. Revision* 4D ucmopmemdi trteevdi saiso n4 .5. Revision 5 com*m iDtutmepde da sr e5v.isi n 6. Revision 6 commi*t tDeudm paesd 6r.evi ion 7. Revisio*n D7u mcpoemdm irtetveids iaosn 78.. Revision *8 Dcuommpmeidt treedv iassi o8n. 9. Revision 9* cDoummmpietdt erde vaiss i9o.n 1 . Revisi*o nD u1m0p ecdo mrmeivtitseido na s1 11.0 . Revision 11 *c oDmummiptetde dr eavsi s1i1o.n 1 . Revision 12 committed* aDsu m1p2e.d r vision 13. Revision 13 committ*e dD uamsp e1d3 .rev sion 14. Revision 14 commit*t eDdu mapse d1 4r.evi ion 15. Revision 15 committed as 15. * Dumped revision 16. Revision 16 committed as 16. Dropped 83 nodes: '/Branches' '/Branches/305' '/Branches/305/New Text Document.txt' '/Fms' '/Fms/ADPropertySheet.cpp'** etc. for 83 nodes... Also, the dump file itself is only 3 kb and contain no real data, only things like that (this is not the complete dump, just a sample) SVN-fs-dump-format-version: 2 UUID: 592fc9f0-5994-e841-a4dc-653714c95216 Revision-number: 0 Prop-content-length: 56 Content-length: 56 K 8 svn:date V 27 2009-06-19T15:05:52.001352Z PROPS-END Revision-number: 1 Prop-content-length: 112 Content-length: 112 K 7 svn:log V 38 This is an empty revision for padding. K 8 svn:date V 27 2009-06-19T15:11:29.378511Z PROPS-END Can anybody help me sort this out?

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  • ASM programming, how to use loop?

    - by chris
    Hello. Im first time here.I am a college student. I've created a simple program by using assembly language. And im wondering if i can use loop method to run it almost samething as what it does below the program i posted. and im also eager to find someome who i can talk through MSN messanger so i can ask you questions right away.(if possible) ok thank you .MODEL small .STACK 400h .data prompt db 10,13,'Please enter a 3 digit number, example 100:',10,13,'$' ;10,13 cause to go to next line first_digit db 0d second_digit db 0d third_digit db 0d Not_prime db 10,13,'This number is not prime!',10,13,'$' prime db 10,13,'This number is prime!',10,13,'$' question db 10,13,'Do you want to contine Y/N $' counter dw 0d number dw 0d half dw ? .code Start: mov ax, @data ;establish access to the data segment mov ds, ax mov number, 0d LetsRoll: mov dx, offset prompt ; print the string (please enter a 3 digit...) mov ah, 9h int 21h ;execute ;read FIRST DIGIT mov ah, 1d ;bios code for read a keystroke int 21h ;call bios, it is understood that the ascii code will be returned in al mov first_digit, al ;may as well save a copy sub al, 30h ;Convert code to an actual integer cbw ;CONVERT BYTE TO WORD. This takes whatever number is in al and ;extends it to ax, doubling its size from 8 bits to 16 bits ;The first digit now occupies all of ax as an integer mov cx, 100d ;This is so we can calculate 100*1st digit +10*2nd digit + 3rd digit mul cx ;start to accumulate the 3 digit number in the variable imul cx ;it is understood that the other operand is ax ;AND that the result will use both dx::ax ;but we understand that dx will contain only leading zeros add number, ax ;save ;variable <number> now contains 1st digit * 10 ;---------------------------------------------------------------------- ;read SECOND DIGIT, multiply by 10 and add in mov ah, 1d ;bios code for read a keystroke int 21h ;call bios, it is understood that the ascii code will be returned in al mov second_digit, al ;may as well save a copy sub al, 30h ;Convert code to an actual integer cbw ;CONVERT BYTE TO WORD. This takes whatever number is in al and ;extends it to ax, boubling its size from 8 bits to 16 bits ;The first digit now occupies all of ax as an integer mov cx, 10d ;continue to accumulate the 3 digit number in the variable mul cx ;it is understood that the other operand is ax, containing first digit ;AND that the result will use both dx::ax ;but we understand that dx will contain only leading zeros. Ignore them add number, ax ;save -- nearly finished ;variable <number> now contains 1st digit * 100 + second digit * 10 ;---------------------------------------------------------------------- ;read THIRD DIGIT, add it in (no multiplication this time) mov ah, 1d ;bios code for read a keystroke int 21h ;call bios, it is understood that the ascii code will be returned in al mov third_digit, al ;may as well save a copy sub al, 30h ;Convert code to an actual integer cbw ;CONVERT BYTE TO WORD. This takes whatever number is in al and ;extends it to ax, boubling its size from 8 bits to 16 bits ;The first digit now occupies all of ax as an integer add number, ax ;Both my variable number and ax are 16 bits, so equal size mov ax, number ;copy contents of number to ax mov cx, 2h div cx ;Divide by cx mov half, ax ;copy the contents of ax to half mov cx, 2h; mov ax, number; ;copy numbers to ax xor dx, dx ;flush dx jmp prime_check ;jump to prime check print_question: mov dx, offset question ;print string (do you want to continue Y/N?) mov ah, 9h int 21h ;execute mov ah, 1h int 21h ;execute cmp al, 4eh ;compare je Exit ;jump to exit cmp al, 6eh ;compare je Exit ;jump to exit cmp al, 59h ;compare je Start ;jump to start cmp al, 79h ;compare je Start ;jump to start prime_check: div cx; ;Divide by cx cmp dx, 0h ;reset the value of dx je print_not_prime ;jump to not prime xor dx, dx; ;flush dx mov ax, number ;copy the contents of number to ax cmp cx, half ;compare half with cx je print_prime ;jump to print prime section inc cx; ;increment cx by one jmp prime_check ;repeat the prime check print_prime: mov dx, offset prime ;print string (this number is prime!) mov ah, 9h int 21h ;execute jmp print_question ;jumps to question (do you want to continue Y/N?) this is for repeat print_not_prime: mov dx, offset Not_prime ;print string (this number is not prime!) mov ah, 9h int 21h ;execute jmp print_question ;jumps to question (do you want to continue Y/N?) this is for repeat Exit: mov ah, 4ch int 21h ;execute exit END Start

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  • I am getting an error when trying to use melt() on a dataframe containing Dates

    - by Dan
    I'd like to melt the dataframe so that in one column i have dates in a second i have username as the variable and finally the value. I'm getting this error: Error in as.Date.numeric(value) : 'origin' must be supplied and while I understand the error I'm not exactly sure how to get around it. A small sample of the data is: structure(list(created_at = structure(c(14007, 14008, 14009, 14010, 14011, 14012), class = "Date"), benjamin = c(16, 0, 0, 0, 0, 0), byron = c(0, 0, 0, 0, 0, 0), cameronc = c(0, 0, 0, 0, 0, 0), daniel = c(0, 0, 0, 0, 0, 0), djdiaz = c(0, 0, 0, 0, 0, 0), gene = c(16, 77, 64, 38, 72, 36), joel = c(0, 0, 0, 0, 0, 2), kerem = c(0, 0, 0, 0, 0, 0), sophia = c(0, 0, 0, 0, 0, 0), SuperMoonMan = c(0, 0, 0, 0, 0, 0)), .Names = c("created_at", "benjamin", "byron", "cameronc", "daniel", "djdiaz", "gene", "joel", "kerem", "sophia", "SuperMoonMan"), row.names = c(NA, 6L), class = c("cast_df", "data.frame")) Thanks for your help.

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  • On-the-fly lossless image compression

    - by geschema
    I have an embedded application where an image scanner sends out a stream of 16-bit pixels that are later assembled to a grayscale image. As I need to both save this data locally and forward it to a network interface, I'd like to compress the data stream to reduce the required storage space and network bandwidth. Is there a simple algorithm that I can use to losslessly compress the pixel data? I first thought of computing the difference between two consecutive pixels and then encoding this difference with a Huffman code. Unfortunately, the pixels are unsigned 16-bit quantities so the difference can be anywhere in the range -65535 .. +65535 which leads to potentially huge codeword lengths. If a few really long codewords occur in a row, I'll run into buffer overflow problems.

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  • Downsampling and applying a lowpass filter to digital audio

    - by twk
    I've got a 44Khz audio stream from a CD, represented as an array of 16 bit PCM samples. I'd like to cut it down to an 11KHz stream. How do I do that? From my days of engineering class many years ago, I know that the stream won't be able to describe anything over 5500Hz accurately anymore, so I assume I want to cut everything above that out too. Any ideas? Thanks. Update: There is some code on this page that converts from 48KHz to 8KHz using a simple algorithm and a coefficient array that looks like { 1, 4, 12, 12, 4, 1 }. I think that is what I need, but I need it for a factor of 4x rather than 6x. Any idea how those constants are calculated? Also, I end up converting the 16 byte samples to floats anyway, so I can do the downsampling with floats rather than shorts, if that helps the quality at all.

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  • Code Golf: Zigzag pattern scanning

    - by fbrereto
    The Challenge The shortest code by character count that takes a single input integer N (N = 3) and returns an array of indices that when iterated would traverse an NxN matrix according to the JPEG "zigzag" scan pattern. The following is an example traversal over an 8x8 matrix (referenced from here:) Examples (The middle matrix is not part of the input or output, just a representation of the NxN matrix the input represents.) 1 2 3 (Input) 3 --> 4 5 6 --> 1 2 4 7 5 3 6 8 9 (Output) 7 8 9 1 2 3 4 (Input) 4 --> 5 6 7 8 --> 1 2 5 9 6 3 4 7 10 13 14 11 8 12 15 16 (Output) 9 10 11 12 13 14 15 16 Notes: The resulting array's base should be appropriate for your language (e.g., Matlab arrays are 1-based, C++ arrays are 0-based). This is related to this question.

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  • SOAP Request using Java

    - by user224270
    I have been trying to send a request through soapui and I always keep getting the following error message: <soap:Body> <soap:Fault> <faultcode>soap:Client</faultcode> <faultstring>Failed to process SOAP request. SOAP body not in UTF-16.</faultstring> <detail> <wsdl_ops:error>Failed to process SOAP request. SOAP body not in UTF-16.</wsdl_ops:error> </detail> </soap:Fault> Has anyone run into the same issue before?

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  • Hey Guy , I want ot streaming video by using VideView class . Can anyone tell me what format is it s

    - by eddyxd
    Hi , I am the newbie of android, but i hava seen the tutorial and implement some simple applications. The question i met is that I am tring to stream some video from my server to android, but the android VideoView class just plays the audition sololy without "image"@@!~ Here is my setting and android code : 1. android core code: mVideoView01.setVideoURI(Uri.parse("rtsp://192.168.16.1:8080/test.sdp")); mVideoView01.start(); 2. my streaming server is VLC and the command is: vlc -vvv d:\nobody.mp4 --sout=#transcode{vcodec=h264,width=320,hegiht=240}:rtp{dst=192.168.16.1,port=4444,sdp=rtsp://192.168.16.1:8080/test.sdp} ps: My ip is got from DHCP but I have checked it really can be connected(Android could play audition after all) ps2: I haved trid to stream some video from "http://www.americafree.tv/" and the playing is good!!@@ So I guess that the problem maybe is caused by streaming Video format, but I have almost tried every figument option form VLC, and it still don't workQQ. So Have anyone done the same test as me can give me some advice?? Thanks a lot!!!!! by eddy

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  • migrating from mysql to oracle9i.Equivalent create table syntax

    - by Android_Crazy
    Hi Following is the syntax for creating table in mysql. I want to create table with same properties in oracle9i. Can anyone provide me the equivalent syntax for oracle? CREATE TABLE IF NOT EXISTS "tbl_audit_trail" ( "id" int(11) unsigned NOT NULL, "old_value" text NOT NULL, "new_value" text NOT NULL, "action" varchar(20) CHARACTER SET latin1 NOT NULL, "model" varchar(255) CHARACTER SET latin1 NOT NULL, "field" varchar(64) CHARACTER SET latin1 NOT NULL, "stamp" timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP, "user_id" int(11) NOT NULL, "model_id" varchar(65) CHARACTER SET latin1 NOT NULL, PRIMARY KEY ("id"), KEY "idx_user_id" ("user_id"), KEY "idx_model_id" ("model_id"), KEY "idx_model" ("model"), KEY "idx_field" ("field"), KEY "idx_old_value" ("old_value"(16)), KEY "idx_new_value" ("new_value"(16)), KEY "idx_action" ("action") ) AUTO_INCREMENT=168 ;

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  • I get an Exception when trying to implement reset password with Authlogic

    - by Tam
    Hi, I'm using Ruby on Rails 2.3.5 and Ruby 1.9 and implmeneted Authlogic as my authentication engine. Authlogic works fine. But now I have been trying to implement password reset using the following tutorial: http://www.binarylogic.com/2008/11/16/tutorial-reset-passwords-with-authlogic/ But I'm getting the following exception when I type mysite.com/password_resets/new Processing PasswordResetsController#new (for 127.0.0.1 at 2010-03-13 01:09:45) [GET] Completed in 9ms (DB: 0) | 200 [http://localhost/password_resets/new] [2010-03-13 01:09:45] ERROR TypeError: can't convert Array into String /Users/tammam56/.rvm/gems/ruby-1.9.1-p378/gems/activesupport-2.3.5/lib/active_support/core_ext/string/output_safety.rb:34:in `concat' /Users/tammam56/.rvm/gems/ruby-1.9.1-p378/gems/activesupport-2.3.5/lib/active_support/core_ext/string/output_safety.rb:34:in `concat_with_safety' /Users/tammam56/.rvm/gems/ruby-1.9.1-p378/gems/rack-1.0.1/lib/rack/handler/webrick.rb:63:in `block in service' /Users/tammam56/.rvm/gems/ruby-1.9.1-p378/gems/actionpack-2.3.5/lib/action_controller/response.rb:158:in `each' /Users/tammam56/.rvm/gems/ruby-1.9.1-p378/gems/actionpack-2.3.5/lib/action_controller/response.rb:158:in `each' /Users/tammam56/.rvm/gems/ruby-1.9.1-p378/gems/actionpack-2.3.5/lib/action_controller/string_coercion.rb:16:in `send' /Users/tammam56/.rvm/gems/ruby-1.9.1-p378/gems/actionpack-2.3.5/lib/action_controller/string_coercion.rb:16:in `method_missing' /Users/tammam56/.rvm/gems/ruby-1.9.1-p378/gems/actionpack-2.3.5/lib/action_controller/reloader.rb:22:in `method_missing' /Users/tammam56/.rvm/gems/ruby-1.9.1-p378/gems/rack-1.0.1/lib/rack/handler/webrick.rb:62:in `service' /Users/tammam56/.rvm/rubies/ruby-1.9.1-p378/lib/ruby/1.9.1/webrick/httpserver.rb:111:in `service' /Users/tammam56/.rvm/rubies/ruby-1.9.1-p378/lib/ruby/1.9.1/webrick/httpserver.rb:70:in `run' /Users/tammam56/.rvm/rubies/ruby-1.9.1-p378/lib/ruby/1.9.1/webrick/server.rb:183:in `block in start_thread' Honestly I'm not sure where to start debugging for this. Is it because I'm using Ruby 1.9? some people seem to be having trouble with Authlogic and Ruby 1.9: http://isitruby19.com/authlogic Please advise me how to go about solving/debugging this issues? Thanks, Tam

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  • When I create PDF in PHP, how do I get the browser to render it correctly?

    - by pavun_cool
    I have used following code to create a simple PDF file. It executes fine in browsers, but I am not able to get the PDF file. It gives me some output when I am running the code in the CLI; my doubt is where I specify the PDF's filename. <?php require('fpdf.php'); $pdf=new FPDF(); $pdf->AddPage(); $pdf->SetFont('Arial','B',16); $pdf->Cell(40,10,'Hello World!'); $pdf->Output(); ?> CLI output: 2 0 obj << /Type /Page /Parent 1 0 R /Contents 3 0 R endobj 3 0 obj << /Length 4 0 R stream 2.834646 0 0 2.834646 0 841.9 cm 2 J 0.2 w BT /F1 5.64 Tf ET BT 11 -16.692 Td (Hello World!) Tj ET

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  • What's wront in this iban validation code?

    - by Jackoder
    Hello coders, I'm working on a php iban validator but i have a problem I wrote like this: function IbanValidator($value) { $iban = false; $value= strtoupper(trim($value)); # Change US text into your country code if(preg_match('/^US\d{7}0[A-Z0-9]{16}$/', $value)) { $number= substr($value,4,22).'2927'.substr($value,2,2); $number= str_replace( array('A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z'), array(10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31,32,33,34,35), $number ); $iban = (1 == bcmod($number,97)) ? true; } return $iban; } Thanks. Funny Games

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  • Changing SQL Server Database sorting

    - by plaisthos
    I have a request to change the collation of a SQL Server Database: ALTER DATABASE solarwind95 collate SQL_Latin1_General_CP1_CI_AS but I get this strange error: Meldung 5075, Ebene 16, Status 1, Zeile 1 Das 'Spalte'-Objekt 'CustomPollerAssignment.PollerID' ist von 'Datenbanksortierung' abhängig. Die Datenbanksortierung kann nicht geändert werden, wenn ein schemagebundenes Objekt von ihr abhängig ist. Entfernen Sie die Anhängigkeiten der Datenbanksortierung, und wiederholen Sie den Vorgang. Sorry for the german errror message. I do not know how to switch the language to english, but here is a translation: Translation: Message 5075, Layer 16, Status 1, Row 1 The 'column' object 'CustomPollerAssignment.PollerID' depends on 'Database sorting. The database sorting cannot be changed if a schema bound object depends on it. Remove the dependency of the database sortieren and retry. I got a ton more of the errors like that.

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