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  • Grep and Awk in Windows Invalid Char in Expression Error

    - by Nathan
    I am new to grep and awk - using Windows 7 (I downloaded grep and awk for windows from GnuWin). I am have having trouble running this script: grep -Fwf dictionary.txt frequency.txt | awk '{print $2 "," $1}' I get the error: awk: '{print awk: ^ invalid char ''' in expression I believe it might have something to do with having to use double quotes in Windows, but I tried all the combinations I can think of and still it doesn't work. Can anyone help? Thanks

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  • Optimizing Haskell code

    - by Masse
    I'm trying to learn Haskell and after an article in reddit about Markov text chains, I decided to implement Markov text generation first in Python and now in Haskell. However I noticed that my python implementation is way faster than the Haskell version, even Haskell is compiled to native code. I am wondering what I should do to make the Haskell code run faster and for now I believe it's so much slower because of using Data.Map instead of hashmaps, but I'm not sure I'll post the Python code and Haskell as well. With the same data, Python takes around 3 seconds and Haskell is closer to 16 seconds. It comes without saying that I'll take any constructive criticism :). import random import re import cPickle class Markov: def __init__(self, filenames): self.filenames = filenames self.cache = self.train(self.readfiles()) picklefd = open("dump", "w") cPickle.dump(self.cache, picklefd) picklefd.close() def train(self, text): splitted = re.findall(r"(\w+|[.!?',])", text) print "Total of %d splitted words" % (len(splitted)) cache = {} for i in xrange(len(splitted)-2): pair = (splitted[i], splitted[i+1]) followup = splitted[i+2] if pair in cache: if followup not in cache[pair]: cache[pair][followup] = 1 else: cache[pair][followup] += 1 else: cache[pair] = {followup: 1} return cache def readfiles(self): data = "" for filename in self.filenames: fd = open(filename) data += fd.read() fd.close() return data def concat(self, words): sentence = "" for word in words: if word in "'\",?!:;.": sentence = sentence[0:-1] + word + " " else: sentence += word + " " return sentence def pickword(self, words): temp = [(k, words[k]) for k in words] results = [] for (word, n) in temp: results.append(word) if n > 1: for i in xrange(n-1): results.append(word) return random.choice(results) def gentext(self, words): allwords = [k for k in self.cache] (first, second) = random.choice(filter(lambda (a,b): a.istitle(), [k for k in self.cache])) sentence = [first, second] while len(sentence) < words or sentence[-1] is not ".": current = (sentence[-2], sentence[-1]) if current in self.cache: followup = self.pickword(self.cache[current]) sentence.append(followup) else: print "Wasn't able to. Breaking" break print self.concat(sentence) Markov(["76.txt"]) -- module Markov ( train , fox ) where import Debug.Trace import qualified Data.Map as M import qualified System.Random as R import qualified Data.ByteString.Char8 as B type Database = M.Map (B.ByteString, B.ByteString) (M.Map B.ByteString Int) train :: [B.ByteString] -> Database train (x:y:[]) = M.empty train (x:y:z:xs) = let l = train (y:z:xs) in M.insertWith' (\new old -> M.insertWith' (+) z 1 old) (x, y) (M.singleton z 1) `seq` l main = do contents <- B.readFile "76.txt" print $ train $ B.words contents fox="The quick brown fox jumps over the brown fox who is slow jumps over the brown fox who is dead."

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  • How to wrap Java String.format()?

    - by BlinK_
    Hey everyone, I would like to wrap the String.format() method with in my own Logger class. I can't figure a way how to pass arguments from my method to String.format(). public class Logger { public static void format(String format, Object... args) { print(String.format(format, args)); // <-- this gives an error obviously. } public static void print(String s) { System.out.println(s); } }

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  • Finding the nth number of primes

    - by Braxton Smith
    I can not figure out why this won't work. Please help me from math import sqrt pN = 0 numPrimes = 0 num = 1 def checkPrime(x): '''Check\'s whether a number is a prime or not''' prime = True if(x==2): prime = True elif(x%2==0): prime=False else: root=int(sqrt(x)) for i in range(3,root,2): if(x%i==0): prime=False break return prime n = int(input("Find n number of primes. N being:")) while( numPrimes != n ): if( checkPrime( num ) == True ): numPrimes += 1 pN = num print("{0}: {1}".format(numPrimes,pN)) num += 1 print("Prime {0} is: {1}".format(n,pN))

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  • document.write buggy?

    - by proyb2
    Something wrong with the code? I could print Hello on HTML but when I add to getPlayerVersion, the whole string doesn't print. What could be problem be? Leaving me feeling frustrated. <script type="text/javascript"> document.write("Hello"+deconcept.SWFObjectUtil.getPlayerVersion().major); </script>

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  • Is this a valid quine?

    - by fsm
    def start(fileName): fileReader = open(fileName) for row in fileReader: print row, if __name__ == "__main__": import sys if len(sys.argv) <= 1: print "usage quine /path/to/file" sys.exit(-1) fileName = sys.argv[0] start(fileName) python quine.py foo

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  • Regex optional match in python fails

    - by AaronG
    tickettypepat = (r'MIS Notes:.**(//p//)?.**') retype = re.search(tickettypepat,line) if retype: print retype.group(0) print retype.group(1) Given the input. MIS Notes: //p// Can anyone tell me why group(0) is MIS Notes: //p// and group(1) is returning as None?

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  • Python: finding lowest integer

    - by sarah
    I have the following code: l = ['-1.2', '0.0', '1'] x = 100.0 for i in l: if i < x: x = i print x The code should find the lowest value in my list (-1.2) but instead when i print 'x' it finds the value is still 100.0 Where is my code going wrong?

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  • scoping problem in recursive closure

    - by wiso
    why this work: def function1(): a = 10 def function2(): print a function2() but this not: def function1(): a = 10 def function2(): print a a -= 1 if a>0: function2() function2() error: UnboundLocalError: local variable 'a' referenced before assignment

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  • Naming Suggestions For A Function Providing Chaining In A Different Way

    - by sid3k
    I've coded an experimental function which makes passed objects chainable by using high order functions. It's name is "chain" for now, and here is a usage example; chain("Hello World") (print) // evaluates print function by passing "Hello World" object. (console.log,"Optional","Parameters") (returnfrom) // returns "Hello World" It looks lispy but behaves very different since it's coded in a C based language, I don't know if there is a name for this idiom and I couldn't any name more suitable than "chain". Any ideas, suggestions?

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  • how to use @ in python..

    - by zjm1126
    this is my code: def a(): print 'sss' @a() def b(): print 'aaa' b() and the Traceback is: sss Traceback (most recent call last): File "D:\zjm_code\a.py", line 8, in <module> @a() TypeError: 'NoneType' object is not callable so how to use the '@' thanks

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  • Plotter: What is fixed - the height or the width

    - by Jayan
    I am fixing some printing (plotter) problems in our java code(windows 32). The paper is 50 meter roll , loaded on to plotter. The paper It 36 inch "wide". I am printing image 36inch by 108 inch. When I print what is with height and width I can use? [ FYI. The testing is done using print to file, No paper is wasted :) ] Thanks, Jayan

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  • Printing contents of a div

    - by Hulk
    The contents of the following div re derived dynamically. i.e, A table is added dynamically to this div with some button .My question is how to print the content of this div(window.print) and not other things in the page <div id="newdiv" name="newdiv"></div> Thanks..............

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  • read ArrayList elements

    - by Jessy
    Why it print the wrong output? ArrayList<String> loc = new ArrayList<String>(); This arraylist stored the value of: [topLeft, topLeft, topLeft, bottomLeft, topLeft, bottomLeft, topLeft, topLeft, Left, topLeft] the firs index 0 is = topLeft if(loc.get(1)=="topLeft") System.out.println("same") else { System.out.println("not same") } This program print the wrong output not same instead of same

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  • Python Script to backup a directory

    - by rgolwalkar
    Filename:backup_ver1 import os import time 1 Using list to specify the files and directory to be backed up source = r'C:\Documents and Settings\rgolwalkar\Desktop\Desktop\Dr Py\Final_Py' 2 define backup directory destination = r'C:\Documents and Settings\rgolwalkar\Desktop\Desktop\PyDevResourse' 3 Setting the backup name targetBackup = destination + time.strftime('%Y%m%d%H%M%S') + '.rar' rar_command = "rar.exe a -ag '%s' %s" % (targetBackup, ''.join(source)) i am sure i am doing something wrong here - rar command please let me know if os.system(rar_command) == 0: print 'Successful backup to', targetBackup else: print 'Backup FAILED' O/P:- Backup FAILED winrar is added to Path and CLASSPATH under Environment variables as well - anyone else with a suggestion for backing up the directory is most welcome

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  • Matplotlib: plotting discrete values

    - by Arkapravo
    I am trying to plot the following ! from numpy import * from pylab import * import random for x in range(1,500): y = random.randint(1,25000) print(x,y) plot(x,y) show() However, I keep getting a blank graph (?). Just to make sure that the program logic is correct I added the code print(x,y), just the confirm that (x,y) pairs are being generated. (x,y) pairs are being generated, but there is no plot, I keep getting a blank graph. Any help ?

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  • identifier token keyword antlr parser

    - by batman_for
    How to handle the case where the token 'for' is used in two different situations in the language to parse? Such as statement and as a "parameter" as the following example: echo for print example for i in {0..10..2} do echo "Welcome $i times" done Output: for print example Welcome 0 times Welcome 2 times Welcome 4 times Welcome 6 times Welcome 8 times Welcome 10 times Thanks.

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  • MS Access MSChart.Graph.8 not printing

    - by Tanj
    Software: Microsoft Access 2007 SP2 Database File Version: Access 2000 I have an access program that I inherited from a previous employee. It uses forms for reports and since I don't have much experience in access I have continued to do this. I have created a copy of the program for another project and modified it to suit. I am having trouble getting more then one chart to print. All the charts display in form view, they all have the same properties (excepting data, position, etc.) For some reason they are not printing. They don't even show up in the print preview. I am thinking it must be something with the graphs themselves as they sometimes lose all information. I have to open the graphs in edit mode and change the data source from column to row and back again so that it gets redrawn. (Refresh doesn't fix it) So right now I don't even have a clue as to where to look so ideas are welcome. Edit #1 It seems to be a problem with linking to an unbound form. Subform Field Linker: Can't build a link between unbound forms. The query for the main form is SELECT tTest.ixTest, tMotorTypes.ixMotorType, tMotorTypes.asMotorType, tMotorTypes.fDeprecated, tTestType.asTest, tTest.asSerialNum, tTest.asOrderNum, tTest.asFrameNum, tTest.asRotorNum, tTest.asOperator, tTest.iStation, tTest.dtTestDate, tTest.ixTestType FROM tMotorTypes INNER JOIN (tTestType INNER JOIN tTest ON tTestType.ixTestType=tTest.ixTestType) ON tMotorTypes.ixMotorType=tTest.ixMotorType; The query for the chart is: SELECT qGraphRSTTemperatures.Frequency, qGraphRSTTemperatures.[Drive End], qGraphRSTTemperatures.[Non Drive End], qGraphRSTTemperatures.[Air In], qGraphRSTTemperatures.Core FROM qGraphRSTTemperatures ORDER BY qGraphRSTTemperatures.ixTemperature; Query qGraphRSTTemperatures: SELECT tElectricalData.dblFrequency AS Frequency, tTemperatures.dblDrvEnd AS [Drive End], tTemperatures.dblNonDrvEnd AS [Non Drive End], tTemperatures.dblAirIn AS [Air In], tTemperatures.dblCore AS Core, tSubTest.ixTest, tTemperatures.ixTemperature FROM (tSubTest INNER JOIN tElectricalData ON tSubTest.ixSubTest = tElectricalData.ixSubTest) LEFT JOIN tTemperatures ON tElectricalData.ixElectrical = tTemperatures.ixElectrical WHERE (((tSubTest.ixSubTestType)=5)) ORDER BY tSubTest.ixTest, tTemperatures.ixTemperature; So how come, in the form view it shows the graph with the correct data when linked thus: Child field: ixTest Master field: ixTest but won't print the graph. The graph will print if I remove the links, but then I have all the data from chart query as it is not limited by ixTest. edit #2 It seems to be a data retrieval/rendering issue in printing. Is there anything in printing that changes the context of records with respect to parent/child relationships?

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