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  • Invoking callhierarchy for a method

    - by Steven
    hi, I have an object of type IMethod which represents a method .I want to get the Call Hierarchy of this method . Which methods should i call to get the call hierarchy of a method? Is there any method by which i can do it? I know that i can get it by ctrl+alt+H but i want the code or method for invoking it. Thanks

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  • How to avoid the linebreak inside a word (Static Layout

    - by Addev
    I'm trying to make a text as big as I can making it fit a Rect. basically I use a StaticLayout for pre-calculate the text size and make it fit the Rect's height: // Since the width is fixed for the StaticLayout it should only fit the height while (currentHeight>Rect.getHeight()){ size-=2; } textPaint.setTextSize(size); The problem is that if the Rect is very high, the exit condition is reached but breaking the words (see the capture). Is there a way for avoid this? Goal: Actual: Current code: textSize=MAX_TEXT_SIZE do { if (textSize < mMinTextSize) { Log.i(TAG, "Min reached"); textSize = mMinTextSize; textPaint.setTextSize(textSize); fits = true; } else { textPaint.setTextSize(textSize); StaticLayout layout = new StaticLayout(text, textPaint, targetWidth, Alignment.ALIGN_NORMAL, 1.0, 0, true); layout.draw(canvas); float heightRatio= (float) layout.getHeight() / (float) targetHeight; boolean fitsHeight = heightRatio<= 1f; if (fitsHeight) { fits = true; } else { textSize -= 2; } } Log.i(TAG, "textSize=" + textSize + " fits=" + fits); } while (!fits); thanks

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  • Where is the error in my code?

    - by Lulu Larson
    /** Yields: a String that contains each capital Letter (in 'A'..'Z') whose representation is prime */ public static String primeChars() { String s = ""; // inv: s contains each capital in "A'..c-1 whose representation is prime for (char c = 'A'; c <= 'Z'; c=(char)(c+1)) { if (Loops.isPrime((int)c) == true) { s= s+1; } } // s contains each capital in 'A' ..'Z' whose rep is a prime return s; }

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  • Matching Class arrays

    - by frinkz
    I'm writing a routine to invoke methods, found by a name and an array of parameter Class values Matching the Method by getName works, but when trying to match the given Class[] for parameters, and Method.getParameterTypes(), I'm having trouble. I assumed that this would work: Class[] searchParams = new Class[] { float.class, String.class }; Class[] methodParams = m.getParameterTypes(); if(methodParams == searchParams) { m.invoke(this, paramValues); } But apparantly not - m.invoke is never reached. I've checked, and methodParams gives the same classes as searchParams. The code below works, and picks the right method, but it seems like a very dirty way of doing things, I'm sure I'm missing something obvious. Class[] searchParams = new Class[] { float.class, String.class }; Class[] methodParams = m.getParameterTypes(); boolean isMatch = true; for(int i = 0; i < searchParams.length; i++) { if(!searchParams.getClass().equals(methodParams.getClass())) { isMatch = false; } } if(isMatch) { m.invoke(this, paramValues); }

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  • Is this safe on a production server?

    - by Camran
    I have a database application (or search engine) which is called Solr. I connect to it via port 8983. I do this from php code, so I add and remove records from it via php. On my server I have a firewall. I have set this firewall to only allow connections to and from this port (8983) from the ip adress of my own server. In other words, only allow servers IP to access this port. Is that safe? Or am I thinking all wrong here? Will others be able to "simulate" my ip adress and act as the server? This is because otherwise others may add/remove records as they want from their own ip adresses... Thanks

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  • A hard Question ?

    - by the-ifl
    Hi Guys , I try To find a solution to a question .... we have a number , example : 20 ... and we have 6 number :{ a ,b , c , d , e , f} < 20 , t try to find all values of these numbers , but only if we can combinate (whit + or -) whit 2 of this numbers and getting all the value below to 20 : for example we choose 31 : a = 22 b = 21 c = 14 d = 11 e = 9 f = 5 we have : 22 - 21 = 1 ; 11 - 9 = 2 ; 14 - 11 = 3 ; 9 - 5 = 4 ; f = 5 ; 11 - 5 = 6 ; 21 - 14 = 7 ; .... .... .... .... .... 21 + 9 = 30 ; 9 + 22 = 31 ;

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  • Trying to packetize TCP with non-blocking IO is hard! Am I doing something wrong?

    - by Ricket
    Oh how I wish TCP was packet-based like UDP is! But alas, that's not the case, so I'm trying to implement my own packet layer. Here's the chain of events so far (ignoring writing packets) Oh, and my Packets are very simply structured: two unsigned bytes for length, and then byte[length] data. (I can't imagine if they were any more complex, I'd be up to my ears in if statements!) Server is in an infinite loop, accepting connections and adding them to a list of Connections. PacketGatherer (another thread) uses a Selector to figure out which Connection.SocketChannels are ready for reading. It loops over the results and tells each Connection to read(). Each Connection has a partial IncomingPacket and a list of Packets which have been fully read and are waiting to be processed. On read(): Tell the partial IncomingPacket to read more data. (IncomingPacket.readData below) If it's done reading (IncomingPacket.complete()), make a Packet from it and stick the Packet into the list waiting to be processed and then replace it with a new IncomingPacket. There are a couple problems with this. First, only one packet is being read at a time. If the IncomingPacket needs only one more byte, then only one byte is read this pass. This can of course be fixed with a loop but it starts to get sorta complicated and I wonder if there is a better overall way. Second, the logic in IncomingPacket is a little bit crazy, to be able to read the two bytes for the length and then read the actual data. Here is the code, boiled down for quick & easy reading: int readBytes; // number of total bytes read so far byte length1, length2; // each byte in an unsigned short int (see getLength()) public int getLength() { // will be inaccurate if readBytes < 2 return (int)(length1 << 8 | length2); } public void readData(SocketChannel c) { if (readBytes < 2) { // we don't yet know the length of the actual data ByteBuffer lengthBuffer = ByteBuffer.allocate(2 - readBytes); numBytesRead = c.read(lengthBuffer); if(readBytes == 0) { if(numBytesRead >= 1) length1 = lengthBuffer.get(); if(numBytesRead == 2) length2 = lengthBuffer.get(); } else if(readBytes == 1) { if(numBytesRead == 1) length2 = lengthBuffer.get(); } readBytes += numBytesRead; } if(readBytes >= 2) { // then we know we have the entire length variable // lazily-instantiate data buffers based on getLength() // read into data buffers, increment readBytes // (does not read more than the amount of this packet, so it does not // need to handle overflow into the next packet's data) } } public boolean complete() { return (readBytes > 2 && readBytes == getLength()+2); } Basically I need feedback on my code. Please suggest any improvements. Even overhauling my entire system would be okay, if you have suggestions for how better to implement the whole thing. Book recommendations are welcome too; I love books. I just get the feeling that something isn't quite right.

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  • http connection timeout issues

    - by Mark
    I'm running into an issue when i try to use the HttpClient connecting to a url. The http connection is taking a longer time to timeout, even after i set a connection timeoout. int timeoutConnection = 5000; HttpConnectionParams.setConnectionTimeout(httpParameters, timeoutConnection); int timeoutSocket = 5000; HttpConnectionParams.setSoTimeout(httpParameters, timeoutSocket); It works perfect most of the time. However, every once in while, the http connection runs for ever and ignore the setconnectiontimeout, especailly when the phone is connected to wifi, and the phone was idling. So after the phone is idling, the first time i try to connect, the http connection ignores the setconnectiontimeout and runs forever, after i cancel it and try again, it works like charm everytime. But that one time that doesn't work it creates a threadtimeout error, i tried using a different thread, it works, but i know that the thread is running for long time. I understand that the wifi goes to sleep on idle, but i dont understand why its ignoring the setconnectiontimeout. Anyone can help, id really appreciated.

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  • Editing a 1MB file continuously, what's more efficient?

    - by kmels
    I've to be continuously editing a 1MB file, simulating a file system. I've to modify the directory of File Control Blocks, FAT, blocks, etc. Proffesor recommended overwriting the file every time an update is made. 1MB shouldn't take minutes to do that, but I don't like this way. Is it a FileChannel the way to go here? Also, I understand that if I edit a MappedByteBuffer, the content of the mapped file region is also edited immediately? i.e. is reflexive mapped? Thanks.

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  • How to deal with unknown entity references?

    - by Chris
    I'm parsing (a lot of) XML files that contain entity references which i dont know in advance (can't change that fact). For example: xml = "<tag>I'm content with &funny; &entity; &references;.</tag>" when i try to parse this using the following code: final DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance(); final DocumentBuilder db = dbf.newDocumentBuilder(); final InputSource is = new InputSource(new StringReader(xml)); final Document d = db.parse(is); i get the following exception: org.xml.sax.SAXParseException: The entity "funny" was referenced, but not declared. but, what i do want to achieve is, that the parser replaces every entity that is not declared (unknown to the parser) with an empty String ''. Or even better, is there a way to pass a map to the parser like: Map<String,String> entityMapping = ... entityMapping.put("funny","very"); entityMapping.put("entity","important"); entityMapping.put("references","stuff"); so that i could do the following: final DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance(); final DocumentBuilder db = dbf.newDocumentBuilder(); final InputSource is = new InputSource(new StringReader(xml)); db.setEntityResolver(entityMapping); final Document d = db.parse(is); if i would obtain the text from the document using this example code i should receive: I'm content with very important stuff. Any suggestions? Of course, i already would be happy to just replace the unknown entity's with empty strings. Thanks,

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  • Android: The concept for detecting changes of an opened file

    - by niko
    I wrote an application for video recording which stores the recording to a file. Currently I am looking for a way to implement some kind of "listener" to listen for file changes. The concept I would like to implement is the following: Check the file on a set period of time (for example one second), extract changes (get the data that was written in the last period) and do something with these data. I would be very thankful if anyone of you could give any suggestion or point to any useful resource that could help to solve the given problem.

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  • Can we view objets in the JVM memory?

    - by Sebastien Lorber
    Hey, At work we found that on some instances (particulary the slow ones) we have a different behaviour, acquired at the reboot. We guess a cache is not initialized correctly, or maybe a concurrency problem... Anyway it's not reproductible in any other env than production. We actually don't have loggers to activate... it's an old component... Thus i'd like to know if there are tools that can help us to see the different objets present in the JVM memory in order to check the content of the cache... Thank you!

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  • Project Euler #119 Make Faster

    - by gangqinlaohu
    Trying to solve Project Euler problem 119: The number 512 is interesting because it is equal to the sum of its digits raised to some power: 5 + 1 + 2 = 8, and 8^3 = 512. Another example of a number with this property is 614656 = 28^4. We shall define an to be the nth term of this sequence and insist that a number must contain at least two digits to have a sum. You are given that a2 = 512 and a10 = 614656. Find a30. Question: Is there a more efficient way to find the answer than just checking every number until a30 is found? My Code int currentNum = 0; long value = 0; for (long a = 11; currentNum != 30; a++){ //maybe a++ is inefficient int test = Util.sumDigits(a); if (isPower(a, test)) { currentNum++; value = a; System.out.println(value + ":" + currentNum); } } System.out.println(value); isPower checks if a is a power of test. Util.sumDigits: public static int sumDigits(long n){ int sum = 0; String s = "" + n; while (!s.equals("")){ sum += Integer.parseInt("" + s.charAt(0)); s = s.substring(1); } return sum; } program has been running for about 30 minutes (might be overflow on the long). Output (so far): 81:1 512:2 2401:3 4913:4 5832:5 17576:6 19683:7 234256:8 390625:9 614656:10 1679616:11 17210368:12 34012224:13 52521875:14 60466176:15 205962976:16 612220032:17

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  • Can I set a timeout for a InputStream's read() function?

    - by Zombies
    I have a DataInputStream that I obtained from a Socket. Is there any way I can set a timeout for dis.read(...)? Currently I spawn a new thread to do the read. While the parent thread does a thread.join(timeout) to wait before interrupting it. I am aware of nio, but I don't think I want to refactor that much at this point. Thanks.

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  • Question on XJB

    - by Hima
    I have two tables -- INSTALL_BUILD_RESULTS and BUILD_RESULTS. IBR has a primary key called Install_Build_Id and BR has a primary key called Build_Id. Both are numbers A third table, LINK_BUILD_TO_INSTALL_BUILD is a table simply consisting of the two columns mentioned above, used together as a composite key. How can I write an xjb for these 3 tables.

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  • swing layout: vertical flow

    - by pstanton
    Hi All, What LayoutManager should I use to achieve a transposed version of FlowLayout? Essentially, I want a vertical list which occupies multiple columns if it can't fit all of it's components within one column. +------------------------+ | item 1 | | item 2 | | item 3 | | item 4 | | item 5 | | item 6 | | item 7 | | item 8 | +------------------------+ or +------------------------+ | item 1 item 7 | | item 2 item 8 | | item 3 | | item 4 | | item 5 | | item 6 | +------------------------+

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