Search Results

Search found 2691 results on 108 pages for 'ross smith ii'.

Page 13/108 | < Previous Page | 9 10 11 12 13 14 15 16 17 18 19 20  | Next Page >

  • SQLAuthority News – Free eBook Download – Introducing Microsoft SQL Server 2008 R2

    - by pinaldave
    Microsoft Press has published FREE eBook on the most awaiting release of SQL Server 2008 R2. The book is written by Ross Mistry and Stacia Misner. Ross is my personal friend and one of the most active book writer in SQL Server Domain. When I see his name on any book, I am sure that it will be high quality and easy to read book. The details about the book is here: Introducing Microsoft SQL Server 2008 R2, by Ross Mistry and Stacia Misner The book contains 10 chapters and 216 pages. PART I   Database Administration CHAPTER 1   SQL Server 2008 R2 Editions and Enhancements CHAPTER 2   Multi-Server Administration CHAPTER 3   Data-Tier Applications CHAPTER 4   High Availability and Virtualization Enhancements CHAPTER 5   Consolidation and Monitoring PART II   Business Intelligence Development CHAPTER 6   Scalable Data Warehousing CHAPTER 7   Master Data Services CHAPTER 8   Complex Event Processing with StreamInsight CHAPTER 9   Reporting Services Enhancements CHAPTER 10   Self-Service Analysis with PowerPivot More detail about the book is listed here. You can download the ebook in XPS format here and in PDF format here. Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: Business Intelligence, Pinal Dave, SQL, SQL Authority, SQL Download, SQL Query, SQL Server, SQL Tips and Tricks, SQLAuthority News, T SQL, Technology

    Read the article

  • SQL SERVER – Download Free eBook – Introducing Microsoft SQL Server 2012

    - by pinaldave
    Database Administration and Business Intelligence is indeed very key area of the SQL Server. My very good friend Ross Mistry and Stacia Misner has recently wrote book which is for SQL Server 2012. The best part of the book is it is totally FREE! Well, this book assumes that you have certain level of SQL Server Administration as well Business Intelligence understanding. So if you are absolutely beginner I suggest you read other books of Ross as well attend Pluralsight course of Stacia Misner. Personally I read this book in last 10 days and I find it very easy to read and very comprehensive as well. Part I Database Administration (by Ross Mistry) 1. SQL Server 2012 Editions and Engine Enhancements 2. High-Availability and Disaster-Recovery Enhancements 3. Performance and Scalability 4. Security Enhancements 5. Programmability and Beyond-Relational Enhancements Part II Business Intelligence Development (by Stacia Misner) 6. Integration Services 7. Data Quality Services 8. Master Data Services 9. Analysis Services and PowerPivot 10. Reporting Services Here are various versions of the eBook. PDF ePub Mobi Amazon Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: Database, PostADay, SQL, SQL Authority, SQL Download, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology

    Read the article

  • Poante cu avocati

    - by interesante
    Avocatul isi intreaba unul din viitorii clienti: - Si aveti banii necesari pentru a va permite sa fiti aparat de mine? - Da, am doua casete cu bijuterii. - Bine, atunci sa vedem...De ce sunteti acuzat? - De furtul celor doua caste cu bijuterii...Relaxeaza-te citind un blog amuzant si haios cu cele mai noi glume si bancuri de tot felul.Intr-un avion, un avocat nimereste langa o blonda super. Bla, bla, tot incerca sa intre in vorba cu ea ... nimic. Blonda se uita pe geam, mai incerca sa doarma ... Avocatul, enervat: - Uite, hai sa jucam un joc ! Eu iti pun tie o intrebare, si daca nu stii imi dai 5$, apoi imi pui tu mie o intrebare, si daca nu stiu iti dau 5 $! Si tot asa ... - Nu, domnule, imi pare rau, sunt obosita. As prefera sa ma odihnesc ... Avocatul, enervandu-se si mai tare: - Bine, uite, jucam alt joc! Eu iti pun tie o intrebare, daca nu stii imi dai 5$; tu imi pui mie o intrebare, si daca nu stiu ... iti dau 500$ ! Blonda accepta, intr-un tarziu. - Care este distanta de la Pamant la Luna ? Blonda deschide geanta si ii da 5$, dupa care il intreaba: - Ce e mic, are 3 picioare si urca dealul ? Avocatul, se gandeste ... scoate laptop-ul, cauta in baza de date ... cauta pe Internet ... trimite mail-uri la toti prietenii ... In sfarsit, dupa o ora, transpirat, ii da blondei 500$. Blonda ii ia, apoi se intoarce si incepe sa se uite plictisita pe geam. Avocatul, isterizat, vrea sa afle raspunsul: - Bine, bine, ce e mic, are trei picioare si urca dealul ? La care, blonda deschide tacticoasa geanta si ii da o hartie de 5$.

    Read the article

  • dist-upgrade runs and completes but current kernel stays the same

    - by jaguare22
    I think that my system is staying at an older kernel version. It seems to update when I run dist-upgrade but the current kernel version doesn't change. Is it possible the system is set to install new kernel updates but only load an older version at start up? $ uname -a Linux HTPC 3.2.0-32-generic #51-Ubuntu SMP Wed Sep 26 21:32:50 UTC 2012 i686 athlon i386 GNU/Linux $ dpkg --list | grep linux-image ii linux-image-3.2.0-32-generic 3.2.0-32.51 Linux kernel image for version 3.2.0 on 32 bit x86 SMP ii linux-image-3.2.0-32-generic-pae 3.2.0-32.51 Linux kernel image for version 3.2.0 on 32 bit x86 SMP ii linux-image-3.2.0-32-virtual 3.2.0-32.51 Linux kernel image for version 3.2.0 on 32 bit x86 Virtual Guests dpkg -l 'linux-*' | sed '/^ii/!d;/'"$(uname -r | sed "s/\(.*\)-\([^0-9]\+\)/\1/")"'/d;s/^[^ ]* [^ ]* \([^ ]*\).*/\1/;/[0-9]/!d' linux-headers-3.2.0-36 linux-headers-3.2.0-36-generic-pae linux-headers-3.2.0-37 linux-headers-3.2.0-37-generic-pae linux-headers-3.2.0-38 linux-headers-3.2.0-38-generic-pae linux-headers-3.2.0-39 linux-headers-3.2.0-39-generic-pae linux-headers-3.2.0-40 linux-headers-3.2.0-40-generic-pae linux-headers-3.2.0-41 linux-headers-3.2.0-41-generic-pae linux-headers-3.2.0-43 linux-headers-3.2.0-43-generic-pae linux-headers-3.2.0-44 linux-headers-3.2.0-44-generic-pae linux-headers-3.2.0-45 linux-headers-3.2.0-45-generic-pae linux-headers-3.2.0-48 linux-headers-3.2.0-48-generic-pae

    Read the article

  • dpkg reporting as installed, uninstalled kernels

    - by Tony Martin
    I have run the following command to remove old kernels: dpkg -l 'linux-*' | sed '/^ii/!d;/'"$(uname -r | sed "s/\(.*\)-\([^0-9]\+\)/\1/")"'/d;s/^[^ ]* [^ ]* \([^ ]*\).*/\1/;/[0-9]/!d' | xargs sudo apt-get -y purge and only the current kernel is now installed, which I have confirmed in synaptic and by checking my boot partition. However, when I run: dpkg --list | grep linux-image I get the following response: rc linux-image-3.13.0-30-generic 3.13.0-30.55 amd64 Linux kernel image for version 3.13.0 on 64 bit x86 SMP rc linux-image-3.13.0-32-generic 3.13.0-32.57 amd64 Linux kernel image for version 3.13.0 on 64 bit x86 SMP ii linux-image-3.13.0-34-generic 3.13.0-34.60 amd64 Linux kernel image for version 3.13.0 on 64 bit x86 SMP rc linux-image-extra-3.13.0-30-generic 3.13.0-30.55 amd64 Linux kernel extra modules for version 3.13.0 on 64 bit x86 SMP rc linux-image-extra-3.13.0-32-generic 3.13.0-32.57 amd64 Linux kernel extra modules for version 3.13.0 on 64 bit x86 SMP ii linux-image-extra-3.13.0-34-generic 3.13.0-34.60 amd64 Linux kernel extra modules for version 3.13.0 on 64 bit x86 SMP ii linux-image-generic 3.13.0.34.40 amd64 Generic Linux kernel image Probably not a problem, but just wondering why versions -30 and -32 are reported as present. Can it be rectified? TIA

    Read the article

  • What is the effect of this order_by clause?

    - by bread
    I don't understand what this order_by clause is doing and whether I need it or not: select c.customerid, c.firstname, c.lastname, i.order_date, i.item, i.price from items_ordered i, customers c where i.customerid = c.customerid group by c.customerid, i.item, i.order_date order by i.order_date desc; This produces this data: 10330 Shawn Dalton 30-Jun-1999 Pogo stick 28.00 10101 John Gray 30-Jun-1999 Raft 58.00 10410 Mary Ann Howell 30-Jan-2000 Unicycle 192.50 10101 John Gray 30-Dec-1999 Hoola Hoop 14.75 10449 Isabela Moore 29-Feb-2000 Flashlight 4.50 10410 Mary Ann Howell 28-Oct-1999 Sleeping Bag 89.22 10339 Anthony Sanchez 27-Jul-1999 Umbrella 4.50 10449 Isabela Moore 22-Dec-1999 Canoe 280.00 10298 Leroy Brown 19-Sep-1999 Lantern 29.00 10449 Isabela Moore 19-Mar-2000 Canoe paddle 40.00 10413 Donald Davids 19-Jan-2000 Lawnchair 32.00 10330 Shawn Dalton 19-Apr-2000 Shovel 16.75 10439 Conrad Giles 18-Sep-1999 Tent 88.00 10298 Leroy Brown 18-Mar-2000 Pocket Knife 22.38 10299 Elroy Keller 18-Jan-2000 Inflatable Mattress 38.00 10438 Kevin Smith 18-Jan-2000 Tent 79.99 10101 John Gray 18-Aug-1999 Rain Coat 18.30 10449 Isabela Moore 15-Dec-1999 Bicycle 380.50 10439 Conrad Giles 14-Aug-1999 Ski Poles 25.50 10449 Isabela Moore 13-Aug-1999 Unicycle 180.79 10101 John Gray 08-Mar-2000 Sleeping Bag 88.70 10299 Elroy Keller 06-Jul-1999 Parachute 1250.00 10438 Kevin Smith 02-Nov-1999 Pillow 8.50 10101 John Gray 02-Jan-2000 Lantern 16.00 10315 Lisa Jones 02-Feb-2000 Compass 8.00 10449 Isabela Moore 01-Sep-1999 Snow Shoes 45.00 10438 Kevin Smith 01-Nov-1999 Umbrella 6.75 10298 Leroy Brown 01-Jul-1999 Skateboard 33.00 10101 John Gray 01-Jul-1999 Life Vest 125.00 10330 Shawn Dalton 01-Jan-2000 Flashlight 28.00 10298 Leroy Brown 01-Dec-1999 Helmet 22.00 10298 Leroy Brown 01-Apr-2000 Ear Muffs 12.50 While if I remove the order_by clause completely, as in this query: select c.customerid, c.firstname, c.lastname, i.order_date, i.item, i.price from items_ordered i, customers c where i.customerid = c.customerid group by c.customerid, i.item, i.order_date; I get these results: 10101 John Gray 30-Dec-1999 Hoola Hoop 14.75 10101 John Gray 02-Jan-2000 Lantern 16.00 10101 John Gray 01-Jul-1999 Life Vest 125.00 10101 John Gray 30-Jun-1999 Raft 58.00 10101 John Gray 18-Aug-1999 Rain Coat 18.30 10101 John Gray 08-Mar-2000 Sleeping Bag 88.70 10298 Leroy Brown 01-Apr-2000 Ear Muffs 12.50 10298 Leroy Brown 01-Dec-1999 Helmet 22.00 10298 Leroy Brown 19-Sep-1999 Lantern 29.00 10298 Leroy Brown 18-Mar-2000 Pocket Knife 22.38 10298 Leroy Brown 01-Jul-1999 Skateboard 33.00 10299 Elroy Keller 18-Jan-2000 Inflatable Mattress 38.00 10299 Elroy Keller 06-Jul-1999 Parachute 1250.00 10315 Lisa Jones 02-Feb-2000 Compass 8.00 10330 Shawn Dalton 01-Jan-2000 Flashlight 28.00 10330 Shawn Dalton 30-Jun-1999 Pogo stick 28.00 10330 Shawn Dalton 19-Apr-2000 Shovel 16.75 10339 Anthony Sanchez 27-Jul-1999 Umbrella 4.50 10410 Mary Ann Howell 28-Oct-1999 Sleeping Bag 89.22 10410 Mary Ann Howell 30-Jan-2000 Unicycle 192.50 10413 Donald Davids 19-Jan-2000 Lawnchair 32.00 10438 Kevin Smith 02-Nov-1999 Pillow 8.50 10438 Kevin Smith 18-Jan-2000 Tent 79.99 10438 Kevin Smith 01-Nov-1999 Umbrella 6.75 10439 Conrad Giles 14-Aug-1999 Ski Poles 25.50 10439 Conrad Giles 18-Sep-1999 Tent 88.00 10449 Isabela Moore 15-Dec-1999 Bicycle 380.50 10449 Isabela Moore 22-Dec-1999 Canoe 280.00 10449 Isabela Moore 19-Mar-2000 Canoe paddle 40.00 10449 Isabela Moore 29-Feb-2000 Flashlight 4.50 10449 Isabela Moore 01-Sep-1999 Snow Shoes 45.00 10449 Isabela Moore 13-Aug-1999 Unicycle 180.79 I'm not sure what the order_by is doing here and if it's having the intended effects.

    Read the article

  • Tricky SQL query involving consecutive values

    - by Gabriel
    I need to perform a relatively easy to explain but (given my somewhat limited skills) hard to write SQL query. Assume we have a table similar to this one: exam_no | name | surname | result | date ---------+------+---------+--------+------------ 1 | John | Doe | PASS | 2012-01-01 1 | Ryan | Smith | FAIL | 2012-01-02 <-- 1 | Ann | Evans | PASS | 2012-01-03 1 | Mary | Lee | FAIL | 2012-01-04 ... | ... | ... | ... | ... 2 | John | Doe | FAIL | 2012-02-01 <-- 2 | Ryan | Smith | FAIL | 2012-02-02 2 | Ann | Evans | FAIL | 2012-02-03 2 | Mary | Lee | PASS | 2012-02-04 ... | ... | ... | ... | ... 3 | John | Doe | FAIL | 2012-03-01 3 | Ryan | Smith | FAIL | 2012-03-02 3 | Ann | Evans | PASS | 2012-03-03 3 | Mary | Lee | FAIL | 2012-03-04 <-- Note that exam_no and date aren't necessarily related as one might expect from the kind of example I chose. Now, the query that I need to do is as follows: From the latest exam (exam_no = 3) find all the students that have failed (John Doe, Ryan Smith and Mary Lee). For each of these students find the date of the first of the batch of consecutively failing exams. Another way to put it would be: for each of these students find the date of the first failing exam that comes after their last passing exam. (Look at the arrows in the table). The resulting table should be something like this: name | surname | date_since_failing ------+---------+-------------------- John | Doe | 2012-02-01 Ryan | Smith | 2012-01-02 Mary | Lee | 2012-01-04 Ann | Evans | 2012-02-03 How can I perform such a query? Thank you for your time.

    Read the article

  • Odd SQL Results

    - by Ryan Burnham
    So i have the following query Select id, [First], [Last] , [Business] as contactbusiness, (Case When ([Business] != '' or [Business] is not null) Then [Business] Else 'No Phone Number' END) from contacts The results look like id First Last contactbusiness (No column name) 2 John Smith 3 Sarah Jane 0411 111 222 0411 111 222 6 John Smith 0411 111 111 0411 111 111 8 NULL No Phone Number 11 Ryan B 08 9999 9999 08 9999 9999 14 David F NULL No Phone Number I'd expect record 2 to also show No Phone Number If i change the "[Business] is not null" to [Business] != null then i get the correct results id First Last contactbusiness (No column name) 2 John Smith No Phone Number 3 Sarah Jane 0411 111 222 0411 111 222 6 John Smith 0411 111 111 0411 111 111 8 NULL No Phone Number 11 Ryan B 08 9999 9999 08 9999 9999 14 David F NULL No Phone Number Normally you need to use is not null rather than != null. whats going on here?

    Read the article

  • LibPCL issues on Ubuntu 13.10

    - by user254885
    i wanted to install the Point Cloud Library but it does not work i use an ODROID board(ARM processor) Some packages could not be installed. This may mean that you have requested an impossible situation or if you are using the unstable distribution that some required packages have not yet been created or been moved out of Incoming. The following information may help to resolve the situation: The following packages have unmet dependencies: libpcl-all : Depends: libpcl-1.7-all but it is not going to be installed E: Unable to correct problems, you have held broken packages. by compiling v1.7 , i get these errors : /usr/lib/gcc/arm-linux-gnueabihf/4.8/../../../arm-linux-gnueabihf/libpthread.a(ptw-fcntl.o): In function `__fcntl_nocancel': /build/buildd/eglibc-2.17/nptl/../sysdeps/unix/sysv/linux/i386/fcntl.c:37: undefined reference to `__libc_do_syscall' /usr/lib/gcc/arm-linux-gnueabihf/4.8/../../../arm-linux-gnueabihf/libpthread.a(ptw-fcntl.o): In function `__libc_fcntl': /build/buildd/eglibc-2.17/nptl/../sysdeps/unix/sysv/linux/i386/fcntl.c:53: undefined reference to `__libc_do_syscall' /build/buildd/eglibc-2.17/nptl/../sysdeps/unix/sysv/linux/i386/fcntl.c:57: undefined reference to `__libc_do_syscall' /usr/lib/gcc/arm-linux-gnueabihf/4.8/../../../arm-linux-gnueabihf/libpthread.a(ptw-open64.o): In function `__libc_open64': /build/buildd/eglibc-2.17/nptl/../sysdeps/unix/sysv/linux/open64.c:41: undefined reference to `__libc_do_syscall' /build/buildd/eglibc-2.17/nptl/../sysdeps/unix/sysv/linux/open64.c:45: undefined reference to `__libc_do_syscall' /usr/lib/gcc/arm-linux-gnueabihf/4.8/../../../arm-linux-gnueabihf/libpthread.a(cancellation.o):/build/buildd/eglibc-2.17/nptl/cancellation.c:96: more undefined references to `__libc_do_syscall' follow collect2: error: ld returned 1 exit status make[2]: *** [bin/pcl_convert_pcd_ascii_binary] Error 1 make[1]: *** [io/tools/CMakeFiles/pcl_convert_pcd_ascii_binary.dir/all] Error 2 make: *** [all] Error 2 i could not find anything in google to solve these errors i believe some packages were not ported for ARM processors any help would be appreciated $ dpkg --list | grep headers ii linux-headers-3.0.63-odroidx2 20130215 ii linux-headers-3.0.71-odroidx2 20130415 ii linux-headers-3.0.74-odroidx2 20130417 ii linux-headers-3.0.75-odroidx2 20130426 ii linux-headers-3.1.10-6 3.1.10-6.10 ii linux-headers-3.1.10-6-ac100 3.1.10-6.10 ii linux-headers-ac100 3.1.10.6.2 installing packages did'nt do well sudo apt-get install linux-generic [sudo] password for odroid: Reading package lists... Done Building dependency tree Reading state information... Done The following packages were automatically installed and are no longer required: debugedit libasound2-dev libestools2.1-dev librpmbuild3 librpmsign1 thunderbird-locale-en thunderbird-locale-en-gb thunderbird-locale-en-us thunderbird-locale-ko Use 'apt-get autoremove' to remove them. The following extra packages will be installed: linux-headers-3.11.0-17 linux-headers-3.11.0-17-generic linux-headers-generic linux-image-3.11.0-17-generic linux-image-generic Suggested packages: fdutils linux-doc-3.11.0 linux-source-3.11.0 linux-tools The following NEW packages will be installed: linux-generic linux-headers-3.11.0-17 linux-headers-3.11.0-17-generic linux-headers-generic linux-image-3.11.0-17-generic linux-image-generic 0 upgraded, 6 newly installed, 0 to remove and 0 not upgraded. Need to get 58.2 MB of archives. After this operation, 203 MB of additional disk space will be used. Do you want to continue [Y/n]? y Get:1 http://ports.ubuntu.com/ubuntu-ports/ saucy-updates/main linux-image-3.11.0-17-generic armhf 3.11.0-17.31 [44.5 MB] Get:2 http://ports.ubuntu.com/ubuntu-ports/ saucy-updates/main linux-image-generic armhf 3.11.0.17.18 [2,356 B] Get:3 http://ports.ubuntu.com/ubuntu-ports/ saucy-updates/main linux-headers-3.11.0-17 all 3.11.0-17.31 [12.6 MB] Get:4 http://ports.ubuntu.com/ubuntu-ports/ saucy-updates/main linux-headers-3.11.0-17-generic armhf 3.11.0-17.31 [1,128 kB] Get:5 http://ports.ubuntu.com/ubuntu-ports/ saucy-updates/main linux-headers-generic armhf 3.11.0.17.18 [2,350 B] Get:6 http://ports.ubuntu.com/ubuntu-ports/ saucy-updates/main linux-generic armhf 3.11.0.17.18 [1,726 B] Fetched 58.2 MB in 13s (4,379 kB/s) Selecting previously unselected package linux-image-3.11.0-17-generic. (Reading database ... 258618 files and directories currently installed.) Unpacking linux-image-3.11.0-17-generic (from .../linux-image-3.11.0-17-generic_3.11.0-17.31_armhf.deb) ... Examining /etc/kernel/preinst.d/ Done. Selecting previously unselected package linux-image-generic. Unpacking linux-image-generic (from .../linux-image-generic_3.11.0.17.18_armhf.deb) ... Selecting previously unselected package linux-headers-3.11.0-17. Unpacking linux-headers-3.11.0-17 (from .../linux-headers-3.11.0-17_3.11.0-17.31_all.deb) ... Selecting previously unselected package linux-headers-3.11.0-17-generic. Unpacking linux-headers-3.11.0-17-generic (from .../linux-headers-3.11.0-17-generic_3.11.0-17.31_armhf.deb) ... Selecting previously unselected package linux-headers-generic. Unpacking linux-headers-generic (from .../linux-headers-generic_3.11.0.17.18_armhf.deb) ... Selecting previously unselected package linux-generic. Unpacking linux-generic (from .../linux-generic_3.11.0.17.18_armhf.deb) ... Setting up linux-image-3.11.0-17-generic (3.11.0-17.31) ... Running depmod. update-initramfs: deferring update (hook will be called later) cp: cannot stat ‘/boot/initrd.img-3.11.0-17-generic’: No such file or directory Failed to copy /boot/initrd.img-3.11.0-17-generic to /boot/initrd.img at /var/lib/dpkg/info/linux-image-3.11.0-17-generic.postinst line 730. dpkg: error processing linux-image-3.11.0-17-generic (--configure): subprocess installed post-installation script returned error exit status 2 dpkg: dependency problems prevent configuration of linux-image-generic: linux-image-generic depends on linux-image-3.11.0-17-generic; however: Package linux-image-3.11.0-17-generic is not configured yet. dpkg: error processing linux-image-generic (--configure): dependency problems - leaving unconfigured Setting up linux-headers-3.11.0-17 (3.11.0-17.31) ... No apport report written because MaxReports is reached already No apport report written because MaxReports is reached already Setting up linux-headers-3.11.0-17-generic (3.11.0-17.31) ... Examining /etc/kernel/header_postinst.d. Setting up linux-headers-generic (3.11.0.17.18) ... dpkg: dependency problems prevent configuration of linux-generic: linux-generic depends on linux-image-generic (= 3.11.0.17.18); however: Package linux-image-generic is not configured yet. dpkg: error processing linux-generic (--configure): dependency problems - leaving unconfigured No apport report written because MaxReports is reached already Errors were encountered while processing: linux-image-3.11.0-17-generic linux-image-generic linux-generic E: Sub-process /usr/bin/dpkg returned an error code (1) i had to uninstall these cos they were messing up other packages installation(buildessentials were already installed)

    Read the article

  • Creating an excel macro to sum lines with duplicate values

    - by john
    I need a macro to look at the list of data below, provide a number of instances it appears and sum the value of each of them. I know a pivot table or series of forumlas could work but i'm doing this for a coworker and it has to be a 'one click here' kinda deal. The data is as follows. A B Smith 200.00 Dean 100.00 Smith 100.00 Smith 50.00 Wilson 25.00 Dean 25.00 Barry 100.00 The end result would look like this Smith 3 350.00 Dean 2 125.00 Wilson 1 25.00 Barry 1 100.00 Thanks in advance for any help you can offer!

    Read the article

  • Simple Select Statement on MySQL Database Hanging

    - by AlishahNovin
    I have a very simple sql select statement on a very large table, that is non-normalized. (Not my design at all, I'm just trying to optimize while simultaneously trying to convince the owners of a redesign) Basically, the statement is like this: SELECT FirstName, LastName, FullName, State FROM Activity Where (FirstName=@name OR LastName=@name OR FullName=@name) AND State=@state; Now, FirstName, LastName, FullName and State are all indexed as BTrees, but without prefix - the whole column is indexed. State column is a 2 letter state code. What I'm finding is this: When @name = 'John Smith', and @state = '%' the search is really fast and yields results immediately. When @name = 'John Smith', and @state = 'FL' the search takes 5 minutes (and usually this means the web service times out...) When I remove the FirstName and LastName comparisons, and only use the FullName and State, both cases above work very quickly. When I replace FirstName, LastName, FullName, and State searches, but use LIKE for each search, it works fast for @name='John Smith%' and @state='%', but slow for @name='John Smith%' and @state='FL' When I search against 'John Sm%' and @state='FL' the search finds results immediately When I search against 'John Smi%' and @state='FL' the search takes 5 minutes. Now, just to reiterate - the table is not normalized. The John Smith appears many many times, as do many other users, because there is no reference to some form of users/people table. I'm not sure how many times a single user may appear, but the table itself has 90 Million records. Again, not my design... What I'm wondering is - though there are many many problems with this design, what is causing this specific problem. My guess is that the index trees are just too large that it just takes a very long time traversing the them. (FirstName, LastName, FullName) Anyway, I appreciate anyone's help with this. Like I said, I'm working on convincing them of a redesign, but in the meantime, if I someone could help me figure out what the exact problem is, that'd be fantastic.

    Read the article

  • Is it possible to use ContainsTable to get results for more than one column?

    - by LockeCJ
    Consider the following table: People FirstName nvarchar(50) LastName nvarchar(50) Let's assume for the moment that this table has a full-text index on it for both columns. Let's suppose that I wanted to find all of the people named "John Smith" in this table. The following query seems like a perfectly rational way to accomplish this: SELECT * from People p INNER JOIN CONTAINSTABLE(People,*,'"John*" AND "Smith*"') Unfortunately, this will return no results, assuming that there is no record in the People table that contains both "John" and "Smith" in either the FirstName or LastName columns. It will not match a record with "John" in the FirstName column, and "Smith" in the LastName column, or vice-versa. My question is this: How does one accomplish what I'm trying to do above? Please consider that the example above is simplified. The real table I'm working with has ten columns and the input I'm receiving is a single string which is split up based on standard word breakers (space, dash, etc.)

    Read the article

  • Parsing complex string using regex

    - by wojtek_z
    My regex skills are not very good and recently a new data element has thrown my parser into a loop Take the following string "+USER=Bob Smith-GROUP=Admin+FUNCTION=Read/FUNCTION=Write" Previously I had the following for my regex : [+\\-/] Which would turn the result into USER=Bob Smith GROUP=Admin FUNCTION=Read FUNCTION=Write FUNCTION=Read But now I have values with dashes in them which is causing bad output New string looks like "+USER=Bob Smith-GROUP=Admin+FUNCTION=Read/FUNCTION=Write/FUNCTION=Read-Write" Which gives me the following result , and breaks the key = value structure. USER=Bob Smith GROUP=Admin FUNCTION=Read FUNCTION=Write FUNCTION=Read Write Can someone help me formulate a valid regex for handling this or point me to some key / value examples. Basically I need to be able to handle + - / signs in order to get combinations.

    Read the article

  • Are there any well known algorithms to detect the presence of names?

    - by Rhubarb
    For example, given a string: "Bob went fishing with his friend Jim Smith." Bob and Jim Smith are both names, but bob and smith are both words. Weren't for them being uppercase, there would be less indication of this outside of our knowledge of the sentence. Without doing grammar analysis, are there any well known algorithms for detecting the presence of names, at least Western names?

    Read the article

  • Ubuntu server 13 hangs on boot

    - by Slava Fomin II
    I formatted my WD30EFRX 3TB SATA HDD as GPT with the following layout: 200 MB FAT32 (BOOTABLE) 50GB EXT4 (Mount point: /) 4 GB SWAP SPACE ~2.9 TB EXT4 (with no mount point) Then i created a Flash USB using Rufus 1.3.3 and the following ISO-image: ubuntu-13.04-server-amd64.iso. I used following configuration to create the USB: GPT partition scheme for UEFI computer FAT32 (16KB) I successfully booted from this USB on my Intel D510MO motherboard in UEFI mode (there were a black and white boot loader menu instead of a colorful GUI) and installed the OS. During the boot loader installation i saw it was grub-efi-amd64 as it must be. After installation i removed the flash drive and tried to boot the system, but just after a BIOS POST it hangs (there is a white blinking cursor at the left top corner of the black screen) and nothing happens. UEFI Mode is enabled in the BIOS configuration and i've updated the BIOS to the latest firmware. What went wrong, how i can confirm that system was installed properly? How can i boot the OS?

    Read the article

  • Revert F3 and F4 behavior in byobu?

    - by James Zimmerman II
    With a fresh 12.04 installation of Ubuntu, byobu's interpretation of the function keys seems to have changed. F3 and F4 will still change the active tab on the current session, but it changes it for all connections. Previously, if you have two active connections to the same user (same session) with User 1 on shell 0/tab 0 and User 2 on shell 0/tab 0, when User 2 pressed F3 , they would be changed to tab 1 while User 1 would remain on tab 0. With the latest version in 12.04, when User 2 presses F3, all connected users are moved to shell 1/tab 1. Is there any way to re-enable the old behavior? I have looked at the /etc/byobu directory and only found backend and socketdir files there. Toggling backend between tmux and screen did not seem to render any difference. Anyone know what, if any, configuration option exist to control this?

    Read the article

  • Need help joining tables...

    - by yuudachi
    I am a MySQL newbie, so sorry if this is a dumb question.. These are my tables. student table: SID (primary) student_name advisor (foreign key to faculty.facultyID) requested_advisor (foreign key to faculty.facultyID) faculty table: facultyID (primary key) advisor_name I want to query a table that shows everything in the student table, but I want advisor and requested_advisor to show up as names, not the ID numbers. so like it displays like this on the webpage: Student Name: Jane Smith SID: 860123456 Current Advisor: John Smith Requested advisor: James Smith not like this Student Name: Jane Smith SID: 860123456 Current Advisor: 1 Requested advisor: 2 SELECT student.student_name, SID, student_email, faculty.advisor_name FROM student INNER JOIN faculty ON student.advisor = faculty.facultyID; this comes out close, but I don't know how to get the requested_advisor to show up as a name.

    Read the article

  • Setting variables in shell script by running commands

    - by rajya vardhan
    >cat /tmp/list1 john jack >cat /tmp/list2 smith taylor It is guaranteed that list1 and list2 will have equal number of lines. f(){ i=1 while read line do var1 = `sed -n '$ip' /tmp/list1` var2 = `sed -n '$ip' /tmp/list2` echo $i,$var1,$var2 i=`expr $i+1` echo $i,$var1,$var2 done < $INFILE } So output of f() should be: 1,john,smith 2,jack,taylor But getting 1,p,p 1+1,p,p If i replace following: var1 = `sed -n '$ip' /tmp/list1` var2 = `sed -n '$ip' /tmp/list2` with this: var1=`head -$i /tmp/vip_list|tail -1` var2=`head -$i /tmp/lb_list|tail -1` Then output: 1,john,smith 1,john,smith Not an expert of shell, so please excuse if sounds childish :)

    Read the article

  • XUbuntu 12.04 sound becomes distorted on ASUS-computers

    - by Slava Fomin II
    On my XUbuntu 12.04 Desktop from time to time audio becomes distorted, not the audio from some specific applications but every possible sounds are very noisy and barely recognizable. Then i go to: Applications Menu Multimedia PulseAudio Volume Control "Configuration"-tab and change Built-in Audio's Profile from my current profile to something else. After that audio becomes normal, until it breaks again and i have to repeat these steps. It's happening on two different computers: one is an ASUS-based Desktop and other is ASUS notebook. Maybe it's related to some common motherboard audio components. Motherboard is: ASUS P8P67 EVO REV 3.0 Netbook is: ASUS EEPC VX6 Any help will be much appreciated = )

    Read the article

  • XUbuntu won't boot

    - by Slava Fomin II
    I can't properly boot my XUbuntu desktop. It just hangs on the console without any visible errors. The only way i can boot it properly is choosing "recovery mode" in GRUB and then selecting "continue booting" in recovery menu. It's really annoying. I provide some logs here: http://www.sendspace.com/filegroup/mQ%2FzdWvVcrjB3dz4vVqjsw Please advise! If you need some additional information i will be glad to provide it. Any hints and support will be much appreciated.

    Read the article

  • Creating one row of information in excel using a unique value

    - by user1426513
    This is my first post. I am currently working on a project at work which requires that I work with several different worksheets in order to create one mail master worksheet, as it were, in order to do a mail merge. The worksheet contains information regarding different purchases, and each purchaser is identified with their own ID number. Below is an example of what my spreadsheet looks like now (however I do have more columns): ID Salutation Address ID Name Donation ID Name Tickets 9 Mr. John Doe 123 12 Ms. Jane Smith 100.00 12 Ms.Jane Smith 300.00 12 Ms. Jane Smith 456 22 Mr. Mike Man 500.00 84 Ms. Jo Smith 300.00 What I would like to do is somehow sort my data so that everythign with the same unique identifier (ID) lines up on the same row. For example ID 12 Jane Smith - all the information for her will show up under her name matched by her ID number, and ID 22 will match up with 22 etc... When I merged all of my spreadsheets together, I sorted them all by ID number, however my problem is, not everyone who made a donation bought a ticket or some people just bought tickets and nothing us, so sorting doesn't work. Hopefully this makes sense. Thanks in advance.

    Read the article

  • What significant lost advances on side tracks should be revived in the main stream of software?

    - by C.W.Holeman II
    In reading Alan Kay's question on Significant new inventions I was coming up with answers that were not new ideas but old ones that have been passed by in the main stream. So, what significant lost advances that happened on a side track should be revived in the main stream of software? These would be ideas that worked well in their context but a different context appeared and became dominant the context, even though it lacked the idea. It maybe that in the new dominant context one just cannot do something or it requires great effort to be exerted.

    Read the article

  • What significant advances lost on side tracks should be revived in the main stream of software?

    - by C.W.Holeman II
    In reading Alan Kay's question on Significant new inventions I was coming up with answers that were not new ideas but old ones that have been passed by in the main stream. So, what significant lost advances that happened on a side track should be revived in the main stream of software? These would be ideas that worked well in their context but a different context appeared and became dominant the context, even though it lacked the idea. It maybe that in the new dominant context one just cannot do something or it requires great effort to be exerted.

    Read the article

  • How to install MySQL 5.6?

    - by Ross Smith II
    I just installed Ubuntu 12.10 (amd64), and want to install a recent version of MySQL 5.6. If possible, I would like to install (not upgrade) it the "Debian Way' (i.e., using apt-get or dpkg). The only binaries I could find are here. Unfortunately, they are incomplete, as they only install files in /usr/share. If binaries aren't available, how could I install it from source, using the standard Debian method of installing from source. Thanks for any assistance.

    Read the article

  • What significant lost steps forward in side tracks should be revived in the main stream of software?

    - by C.W.Holeman II
    In reading Alan Kay's question on Significant new inventions I was coming up with answers that were not new ideas but old ones that have been passed by in the main stream. So, what significant lost steps forward that happened in a side track should be revived in the main stream of software? These would be ideas that worked well in their context but a different context appeared and became dominant the context, even though it lacked the idea. It maybe that in the new dominant context one just cannot do something or it requires great effort to be exerted.

    Read the article

< Previous Page | 9 10 11 12 13 14 15 16 17 18 19 20  | Next Page >