Search Results

Search found 18244 results on 730 pages for 'null uniqueidentifier'.

Page 15/730 | < Previous Page | 11 12 13 14 15 16 17 18 19 20 21 22  | Next Page >

  • RasterizerState set to null after calling DrawText in Nuclex

    - by ProgrammerAtWork
    I have the following code in XNA: // class members Text t1; Text t2; Text t3; // init // Debugfont is size 24 vectorfont t1 = MM.DebugFont24.Fill("hello"); t1 = MM.DebugFont24.Extrude("hello"); t2 = MM.DebugFont24.Fill("hello"); t2 = MM.DebugFont24.Extrude("hello"); t3 = MM.DebugFont24.Fill("hello"); t3 = MM.DebugFont24.Extrude("hello"); // Draw TextBatch test = new TextBatch(MM.GD); test.DrawText(t1, Color.Red); test.DrawText(t2, Color.Red); test.DrawText(t3, Color.Red); test.End(); //After the second call to the TextBatch, RasterizerState of the GraphicsDevice is set to null //But I don't get any runtime errors or any indication of that something is wrong. Is this supposed to happen? Or am I doing something wrong? I've discovered that this happened because culling was set to None when I was rendering textures

    Read the article

  • Can't remove software - Installed in NULL

    - by ChosSimbaOne
    I've installed software to our administration machine. The problem is that i cannot start the software or uninstall it, as it is not in any directory on the machine. I tried to install it at /pack/CST/... but it is not there and a locate on CST or cst returns nothing. The software is installed from a DVD and not a repository. I've tried to reboot the machine, as i thought i might had something to do with the software being loaded in some sort of tmpfs but that didn't help. I've looked through the entire /etc to check for any relations to the software, but unsuccessfully. I'm out of ideas, to what can cause this problem, anyone got any ideas?? EDIT: I downloaded the iso wich i mounted with: sudo mount -o loop /path/to/iso.iso /path/to/mountpoint sudo /path/to/mountpoint/install.sh Ran the install GUI via an X-session. I choose to install the software in /pack/CST/... but when it exited it said that the software had been installed to /tmp/... There was nothing in tmp, so i decided to reboot the machine and did a full find to see if there was anything left of the software, removed what looked like it could be related. It had placed a script in all the /etc/rs* folder which I removed with: sudo update-rc.d -f scriptname -r I rebooted the machine again, just to be sure. When i run the installer again, it tells me that the software is installed in NULL and i have to remove before installing it. /pack/ is a mountpoint for /q/system/pack What i expected was that the software would be installed in /pack/CST, but it seems to be lock in the system, but I am unable to locate where.

    Read the article

  • Bug: unable to handle kernel NULL pointer dereference at

    - by maria
    I have recently installed new system on my disc, Ubuntu 12.04. Installation proceeded without problems, I started installing additional software and put data from other discs. I had already two times bug report, it was quite long, and I have no idea how to acces to log file (which probably is somewhere saved) and since I had to switch off the computer using the button, anything else was possible, here is just a small part of it (what I've noted on paper) could not write bytes: Broken pipe speach dicpatcher disabled: edit etc/default/speach-dispatcher saned disabled: edit .... and than: BUG: unable to handle kernel NULL pointer dereference at 0000009c I've run Memory test in GRUB, everything is fine. First time it occured when I was using rsync, second time when I was trying to install texlive. Should I install whole system once again? Or can it be hardware problem? Or something else? If there is any hardware details which may be relevant, please ask, since I have no idea what is happening, I don't know what kind of information could be useful. Thanks P.S. dmesg output:

    Read the article

  • jQuery 1.4.4 - issue with attr('selected', null)

    - by Renso
    Issue: The code below worked before under version jQuery 1.4.2 but when I upgraded to version 1.4.4 it no longer worked as expected - it did not unselect the list box item, only setting "selectd" worked:         _handleClick: function(elem) {             var self = this; var initElem = this.element;             var checked = $(elem).attr('checked');             var myId = elem.attr('id').replace(initElem.attr('id') + '_chk_', '');             initElem.children('option[value=' + myId + ']').attr('selected', function() {                 if (checked) {                     return 'selected';                 } else { return null; }             });             if ($.isFunction(self.options.onItemSelected)) {                 try {                     self.options.onItemSelected(elem, initElem.children('option').get());                 } catch (ex) {                     if (self.options.allowDebug)                         alert('select function failed: ' + ex.Description);                 }             }         }, Solution: Under jQuery 1.4.4 you need to explicitly remove the attribute as in "removeAttr('selected'):         _handleClick: function(elem) {             var self = this; var initElem = this.element;             var checked = $(elem).is(':checked');             var myId = elem.attr('id').replace(initElem.attr('id') + '_chk_', '');             if (checked) {                 initElem.children('option[value=' + myId + ']').attr('selected', 'selected');             } else {                 initElem.children('option[value=' + myId + ']').removeAttr('selected');             }             if ($.isFunction(self.options.onItemSelected)) {                 try {                     self.options.onItemSelected(elem, initElem.children('option').get());                 } catch (ex) {                     if (self.options.allowDebug)                         alert('select function failed: ' + ex.Description);                 }             }         },

    Read the article

  • zend tool is not working

    - by user362155
    Hi, I've installed ZendStudio 7.2 it creates project normally with no error but when i try to add action(s) in it, it says project profile does not exist. and the error log is as follow: executing zf create action showLatest index-action-included An Error Has Occurred A project profile was not found. Zend Framework Command Line Console Tool v1.10.2 Details for action "Create" and provider "Action" Action zf create action name controller-name[=Index] view-included[=1] module Failed loading ./ZendDebugger.so: (null) PHP Warning: PHP Startup: Unable to load dynamic library './ext/bcmath.so' - (null) in Unknown on line 0 PHP Warning: PHP Startup: Unable to load dynamic library './ext/bz2.so' - (null) in Unknown on line 0 PHP Warning: PHP Startup: Unable to load dynamic library './ext/calendar.so' - (null) in Unknown on line 0 PHP Warning: PHP Startup: Unable to load dynamic library './ext/ctype.so' - (null) in Unknown on line 0 PHP Warning: PHP Startup: Unable to load dynamic library './ext/curl.so' - (null) in Unknown on line 0 PHP Warning: PHP Startup: Unable to load dynamic library './ext/exif.so' - (null) in Unknown on line 0 PHP Warning: PHP Startup: Unable to load dynamic library './ext/fileinfo.so' - (null) in Unknown on line 0 PHP Warning: PHP Startup: Unable to load dynamic library './ext/ftp.so' - (null) in Unknown on line 0 PHP Warning: PHP Startup: Unable to load dynamic library './ext/gd.so' - (null) in Unknown on line 0 PHP Warning: PHP Startup: Unable to load dynamic library './ext/imagick.so' - (null) in Unknown on line 0 PHP Warning: PHP Startup: Unable to load dynamic library './ext/json.so' - (null) in Unknown on line 0 PHP Warning: PHP Startup: Unable to load dynamic library './ext/ldap.so' - (null) in Unknown on line 0 PHP Warning: PHP Startup: Unable to load dynamic library './ext/mbstring.so' - (null) in Unknown on line 0 PHP Warning: PHP Startup: Unable to load dynamic library './ext/mcrypt.so' - (null) in Unknown on line 0 PHP Warning: PHP Startup: Unable to load dynamic library './ext/memcache.so' - (null) in Unknown on line 0 PHP Warning: PHP Startup: Unable to load dynamic library './ext/mhash.so' - (null) in Unknown on line 0 PHP Warning: PHP Startup: Unable to load dynamic library './ext/mime_magic.so' - (null) in Unknown on line 0 PHP Warning: PHP Startup: Unable to load dynamic library './ext/mssql.so' - (null) in Unknown on line 0 PHP Warning: PHP Startup: Unable to load dynamic library './ext/mysql.so' - (null) in Unknown on line 0 PHP Warning: PHP Startup: Unable to load dynamic library './ext/mysqli.so' - (null) in Unknown on line 0 PHP Warning: PHP Startup: Unable to load dynamic library './ext/pcntl.so' - (null) in Unknown on line 0 PHP Warning: PHP Startup: Unable to load dynamic library './ext/pgsql.so' - (null) in Unknown on line 0 PHP Warning: PHP Startup: Unable to load dynamic library './ext/posix.so' - (null) in Unknown on line 0 PHP Warning: PHP Startup: Unable to load dynamic library './ext/shmop.so' - (null) in Unknown on line 0 PHP Warning: PHP Startup: Unable to load dynamic library './ext/soap.so' - (null) in Unknown on line 0 PHP Warning: PHP Startup: Unable to load dynamic library './ext/sockets.so' - (null) in Unknown on line 0 PHP Warning: PHP Startup: Unable to load dynamic library './ext/sqlite.so' - (null) in Unknown on line 0 PHP Warning: PHP Startup: Unable to load dynamic library './ext/sysvmsg.so' - (null) in Unknown on line 0 PHP Warning: PHP Startup: Unable to load dynamic library './ext/sysvsem.so' - (null) in Unknown on line 0 PHP Warning: PHP Startup: Unable to load dynamic library './ext/sysvshm.so' - (null) in Unknown on line 0 PHP Warning: PHP Startup: Unable to load dynamic library './ext/tidy.so' - (null) in Unknown on line 0 PHP Warning: PHP Startup: Unable to load dynamic library './ext/tokenizer.so' - (null) in Unknown on line 0 PHP Warning: PHP Startup: Unable to load dynamic library './ext/wddx.so' - (null) in Unknown on line 0 PHP Warning: PHP Startup: Unable to load dynamic library './ext/xmlreader.so' - (null) in Unknown on line 0 PHP Warning: PHP Startup: Unable to load dynamic library './ext/xmlrpc.so' - (null) in Unknown on line 0 PHP Warning: PHP Startup: Unable to load dynamic library './ext/xsl.so' - (null) in Unknown on line 0 PHP Warning: PHP Startup: Unable to load dynamic library './ext/zip.so' - (null) in Unknown on line 0 please help me to configure latest ZendTool with ZendStudio 7.2 or how can i get rid of this. i am runin ZS 7.2 on my mac os x 10.5.8 thanks.

    Read the article

  • Suppress Null Value Types from Being Emitted by XmlSerializer

    - by Ben Griswold
    Please consider the following Amount value type property which is marked as a nullable XmlElement: [XmlElement(IsNullable=true)] public double? Amount { get ; set ; } When a nullable value type is set to null, the C# XmlSerializer result looks like the following: <amount xsi:nil="true" /> Rather than emitting this element, I would like the XmlSerializer to suppress the element completely. Why? We're using Authorize.NET for online payments and Authorize.NET rejects the request if this null element exists. The current solution/workaround is to not serialize the Amount value type property at all. Instead we have created a complementary property, SerializableAmount, which is based on Amount and is serialized instead. Since SerializableAmount is of type String, which like reference types are suppressed by the XmlSerializer if null by default, everything works great. /// <summary> /// Gets or sets the amount. /// </summary> [XmlIgnore] public double? Amount { get; set; } /// <summary> /// Gets or sets the amount for serialization purposes only. /// This had to be done because setting value types to null /// does not prevent them from being included when a class /// is being serialized. When a nullable value type is set /// to null, such as with the Amount property, the result /// looks like: &gt;amount xsi:nil="true" /&lt; which will /// cause the Authorize.NET to reject the request. Strings /// when set to null will be removed as they are a /// reference type. /// </summary> [XmlElement("amount", IsNullable = false)] public string SerializableAmount { get { return this.Amount == null ? null : this.Amount.ToString(); } set { this.Amount = Convert.ToDouble(value); } } Of course, this is just a workaround. Is there a cleaner way to suppress null value type elements from being emitted?

    Read the article

  • Explaining NULL and Empty to your 6-year old?

    - by Atomiton
    I'm thinking in terms of Objects here. I think it's important to simplify ideas. If you can explain this to a 6-year old, you can teach new programmers the difference. I'm thinking that a cookie object would be apropos: public class Cookie { public string flavor {get; set; } public int numberOfCrumbs { get; set; } }

    Read the article

  • Filtering null values with pig

    - by arianp
    It looks like a silly problem, but I can´t find a way to filter null values from my rows. This is the result when I dump the object geoinfo: DUMP geoinfo; ([longitude#70.95853,latitude#30.9773]) ([longitude#-9.37944507,latitude#38.91780853]) (null) (null) (null) ([longitude#-92.64416,latitude#16.73326]) (null) (null) ([longitude#-9.15199849,latitude#38.71179122]) ([longitude#-9.15210796,latitude#38.71195131]) here is the description DESCRIBE geoinfo; geoinfo: {geoLocation: bytearray} What I'm trying to do is to filter null values like this: geoinfo_no_nulls = FILTER geoinfo BY geoLocation is not null; but the result remains the same. nothing is filtered. I also tried something like this geoinfo_no_nulls = FILTER geoinfo BY geoLocation != 'null'; and I got an error org.apache.pig.backend.executionengine.ExecException: ERROR 1071: Cannot convert a map to a String What am I doing wrong? details, running on ubuntu, hadoop-1.0.3 with pig 0.9.3 pig -version Apache Pig version 0.9.3-SNAPSHOT (rexported) compiled Oct 24 2012, 19:04:03 java version "1.6.0_24" OpenJDK Runtime Environment (IcedTea6 1.11.4) (6b24-1.11.4-1ubuntu0.12.04.1) OpenJDK 64-Bit Server VM (build 20.0-b12, mixed mode)

    Read the article

  • conceptually different entities with a few similar properties should be stored in one table or more?

    - by Haghpanah
    Assume A and B are conceptually different entities that have a few similar properties and of course their own specific properties. In database design, should I put those two entities in one big aggregated table or two respectively designed tables. For instance, I have two types of payment; Online-payment and Manual-payment with following definition, TABLE [OnlinePayments] ( [ID] [uniqueidentifier], [UserID] [uniqueidentifier], [TrackingCode] [nvarchar](32), [ReferingCode] [nvarchar](32), [BankingAccID] [uniqueidentifier], [Status] [int], [Amount] [money], [Comments] [nvarchar](768), [CreatedAt] [datetime], [ShopingCartID] [uniqueidentifier], ) And TABLE [ManualPayments] ( [ID] [uniqueidentifier], [UserID] [uniqueidentifier], [BankingAccID] [uniqueidentifier], [BankingOrgID] [uniqueidentifier], [BranchName] [nvarchar](64), [BranchCode] [nvarchar](16), [Amount] [money], [SlipNumber] [nvarchar](64), [SlipImage] [image], [PaidAt] [datetime], [Comments] [nvarchar](768), [CreatedAt] [datetime], [IsApproved] [bit], [ApprovedByID] [uniqueidentifier], ) One of my friends told me that creating two distinct tables for such similar entities is not a well design method and they should be put in one single table for the sake of performance and ease of data manipulations. I’m now wondering what to do? What is the best practice in such a case?

    Read the article

  • C# Automatic Properties - Still null after +=?

    - by Sam Schutte
    This seems like a bug to me... I accept that automatic properties, defined as such: public decimal? Total { get; set; } Will be null when they are first accessed. They haven't been initialized, so of course they are null. But, even after setting their value through +=, this decimal? still remains null. So after: Total += 8; Total is still null. How can this be correct? I understand that it's doing a (null + 8), but seems strange that it doesn't pick up that it means it should just be set to 8... Addendums: I made the "null + 8" point in my question - but notice that it works with strings. So, it does null + "hello" just fine, and returns "hello". Therefore, behind the scenes, it is initializing the string to a string object with the value of "hello". The behavior should be the same for the other types, IMO. It might be because a string can accept a null as a value, but still, a null string is not an initialized object, correct? Perhaps it's just because a string isn't a nullable...

    Read the article

  • (NOT) NULL for NVARCHAR columns

    - by Anders Abel
    Allowing NULL values on a column is normally done to allow the absense of a value to be represented. When using NVARCHAR there is aldready a possibility to have an empty string, without setting the column to NULL. In most cases I cannot see a semantical difference between an NVARCHAR with an empty string and a NULL value for such a column. Setting the column as NOT NULL saves me from having to deal with the possibility of NULL values in the code and it feels better to not have to different representations of "no value" (NULL or an empty string). Will I run into any other problems by setting my NVARCHAR columns to NOT NULL. Performance? Storage size? Anything I've overlooked on the usage of the values in the client code?

    Read the article

  • SQL Server JOIN with optional NULL values

    - by Paul McLoughlin
    Imagine that we have two tables as follows: Trades ( TradeRef INT NOT NULL, TradeStatus INT NOT NULL, Broker INT NOT NULL, Country VARCHAR(3) NOT NULL ) CTMBroker ( Broker INT NOT NULL, Country VARCHAR(3) NULL ) (These have been simplified for the purpose of this example). Now, if we wish to join these two tables on the Broker column, and if a country exists in the CTMBroker table on the Country, we have the following two choices: SELECT T.TradeRef,T.TradeStatus FROM Trades AS T JOIN CTMBroker AS B ON B.Broker=T.Broker AND ISNULL(B.Country, T.Country) = T.Country or SELECT T.TradeRef,T.TradeStatus FROM Trades AS T JOIN CTMBroker AS B ON B.Broker=T.Broker AND (B.COUNTRY=T.Country OR B.Country IS NULL) These are both logically equivalent, however in this specific circumstance for our database (SQL Server 2008, SP1) two different execution plans are produced for these two queries with the second version significantly outperforming the first version in terms of both time and logical reads. My question really is as follows: as a general rule would (2) be preferred to (1), or does this just happen to be exploiting some particular idiosyncracy of the optimiser in 2008 SP1 (that could therefore change with future versions of SQL Server).

    Read the article

  • Count The Amount Of Data In An Array Including SOME Null

    - by Josephine
    I'm coding in java and I need to create a function that returns the number of Data objects that are currently in an ArrayList. At the moment I have this: int count = 0; for (int i = 0; i < data.length; i++) { if (data[i] != null) { count ++; } } return count; But the problem is that an array list that includes null data is acceptable, and I have to count their null data towards this counter. How do I include the null data that's in the middle of this array, and not the null data that's not supposed to be counted for? For example, I have some tester code that adds (8),null,null,(23),(25) to the array, and this function should return 5 when the initial array size is 10. Thank you so much

    Read the article

  • Why this code generates different numbers?

    - by frbry
    Hello, I have this function that creates a unique number for hard-disk and CPU combination. DWORD hw_hash() { char drv[4]; char szNameBuffer[256]; DWORD dwHddUnique; DWORD dwProcessorUnique; DWORD dwUniqueKey; char *sysDrive = getenv ("SystemDrive"); strcpy(drv, sysDrive); drv[2] = '\\'; drv[3] = 0; GetVolumeInformation(drv, szNameBuffer, 256, &dwHddUnique, NULL, NULL, NULL, NULL); SYSTEM_INFO si; GetSystemInfo(&si); dwProcessorUnique = si.dwProcessorType + si.wProcessorArchitecture + si.wProcessorRevision; dwUniqueKey = dwProcessorUnique + dwHddUnique; return dwUniqueKey; } It returns different numbers if I format my hard-disk and install a new Windows. Any ideas, why? Thank you. Edit: OK, Got it: This function returns the volume serial number that the operating system assigns when a hard disk is formatted. To programmatically obtain the hard disk's serial number that the manufacturer assigns, use the Windows Management Instrumentation (WMI) Win32_PhysicalMedia property SerialNumber. I should do more research before posting my problems online. Sorry to bother you, let's keep this here in case anybody else can need it.

    Read the article

  • Does query plan optimizer works well with joined/filtered table-valued functions?

    - by smoothdeveloper
    In SQLSERVER 2005, I'm using table-valued function as a convenient way to perform arbitrary aggregation on subset data from large table (passing date range or such parameters). I'm using theses inside larger queries as joined computations and I'm wondering if the query plan optimizer work well with them in every condition or if I'm better to unnest such computation in my larger queries. Does query plan optimizer unnest table-valued functions if it make sense? If it doesn't, what do you recommend to avoid code duplication that would occur by manually unnesting them? If it does, how do you identify that from the execution plan? code sample: create table dbo.customers ( [key] uniqueidentifier , constraint pk_dbo_customers primary key ([key]) ) go /* assume large amount of data */ create table dbo.point_of_sales ( [key] uniqueidentifier , customer_key uniqueidentifier , constraint pk_dbo_point_of_sales primary key ([key]) ) go create table dbo.product_ranges ( [key] uniqueidentifier , constraint pk_dbo_product_ranges primary key ([key]) ) go create table dbo.products ( [key] uniqueidentifier , product_range_key uniqueidentifier , release_date datetime , constraint pk_dbo_products primary key ([key]) , constraint fk_dbo_products_product_range_key foreign key (product_range_key) references dbo.product_ranges ([key]) ) go . /* assume large amount of data */ create table dbo.sales_history ( [key] uniqueidentifier , product_key uniqueidentifier , point_of_sale_key uniqueidentifier , accounting_date datetime , amount money , quantity int , constraint pk_dbo_sales_history primary key ([key]) , constraint fk_dbo_sales_history_product_key foreign key (product_key) references dbo.products ([key]) , constraint fk_dbo_sales_history_point_of_sale_key foreign key (point_of_sale_key) references dbo.point_of_sales ([key]) ) go create function dbo.f_sales_history_..snip.._date_range ( @accountingdatelowerbound datetime, @accountingdateupperbound datetime ) returns table as return ( select pos.customer_key , sh.product_key , sum(sh.amount) amount , sum(sh.quantity) quantity from dbo.point_of_sales pos inner join dbo.sales_history sh on sh.point_of_sale_key = pos.[key] where sh.accounting_date between @accountingdatelowerbound and @accountingdateupperbound group by pos.customer_key , sh.product_key ) go -- TODO: insert some data -- this is a table containing a selection of product ranges declare @selectedproductranges table([key] uniqueidentifier) -- this is a table containing a selection of customers declare @selectedcustomers table([key] uniqueidentifier) declare @low datetime , @up datetime -- TODO: set top query parameters . select saleshistory.customer_key , saleshistory.product_key , saleshistory.amount , saleshistory.quantity from dbo.products p inner join @selectedproductranges productrangeselection on p.product_range_key = productrangeselection.[key] inner join @selectedcustomers customerselection on 1 = 1 inner join dbo.f_sales_history_..snip.._date_range(@low, @up) saleshistory on saleshistory.product_key = p.[key] and saleshistory.customer_key = customerselection.[key] I hope the sample makes sense. Much thanks for your help!

    Read the article

  • MySql, InnoDB & Null Values

    - by pws5068
    Formerly I was using MyISAM storage engine for MySql and I had defined the combination of three fields to be unique. Now I have switched to InnoDB, which I assume caused this problem, and now NULL != NULL. So for the following table: ID (Auto) | Field_A | Field_B | Field_C I can insert (Field_A,Field_B,Field_C) Values(1,2,NULL) (1,2,NULL) (1,2,NULL) infinitely many times. How can I prevent this behavior?

    Read the article

  • What is the Null Character literal in TSQL?

    - by David in Dakota
    I am wondering what the literal for a Null character (e.g. '\0') is in TSQL. Note: not a NULL field value, but the null character (see link). I have a column with a mix of typical and a null character. I'm trying to replace the null character with a different value. I would have thought that the following would work but it is unsuccessfull: select REPLACE(field_with_nullchar, char(0), ',') from FOO where BAR = 20

    Read the article

  • sql error, NULL??

    - by Luke
    So I have a query, can someone let me know if it looks ok content wise? "INSERT INTO ".TBL_MESSAGES." (NULL, 'Your ranking points have changed', 'Due to your recent activity, your ranking points have increased by $r', '2', '$u', '0', '0', '0', '0', NULL, NULL, NULL, NULL, now())"; I can add further information if the query doesnt appear to have a problem? Thanks

    Read the article

  • SSIS Null Value Questions

    - by Saobi
    I have a table with 5 string columns, all can be NULLs. After I read the data from this table, I want to convert any null values into empty strings. The reason is that I need to compare these columns with columns in another table of the same schema (using conditional split), and null values would cause the comparison to evaluate to NULL. Is there any functionality in SSIS that allows me to convert NULL's to empty strings, or just not having to deal with NULL's at all?

    Read the article

  • Replace always replacing null values

    - by Mike
    Why does left(FIELD, replace(nullif(charindex('-', FIELD), 0), null, len(FIELD))) always return null? The idea behind the query is that if charindex() returns 0, then convert the results into null, then convert the null into the length of the field. So if '-' does not exist, show the whole string. For some reason it makes every row equal null. Thank you.

    Read the article

  • Foreign keys and NULL in mySQL

    - by Industrial
    Hi everyone, Can I have a column in my values table (value) referenced as a foreign key to knownValues table, and let it be NULL whenever needed, like in the example: Table: values product type value freevalue 0 1 NULL 100 1 2 NULL 25 3 3 1 NULL Table: types id name prefix 0 length cm 1 weight kg 2 fruit NULL Table: knownValues id Type name 0 2 banana Note: The types in the table values & knownValues are of course referenced into the types table. Thanks!

    Read the article

  • Timestamp Updating Constantly on /dev/null

    - by motorleague
    I've been working on a problem with a /dev/null file on an AIX system (just for background it looks as though it was inadvertently deleted and recreated as a normal file by somebody), but in trying to determine what caused the problem, I noticed that the timestamp on it seems to update every minute. I've observed this on several AIX servers at my workplace. At present I can't entirely rule out this be something specific to the Application being used at my workplace, so I compared with CentOS and Debian based computers at home last night. The CentOS box, which runs 24 hours, had a mod time on /dev/null of around 4 days ago (during which time it was essentially just being used as a web browser and multimedia player, although it would have had active but essentially unused Apache, MySQL and VMM processes running in the background). The timestamp on /dev/null on the Debian machine, which was a just booted laptop, pretty much reflected the boot time, but I tested redirecting STDIN from, and STDOUT to it, and the modification time was unchanged (I'm not sure 100% sure if directing data to /dev/null constitutes "writing to it" in the way it would a normal file). So my question is essentially, could anybody please offer any advice with regards to what circumstances (permissions changes etc.. aside) might cause the timestamp on /dev/null to update? Thanks very much for any suggestions. Alex.

    Read the article

  • Unable to relate two MySQL tables (foreign keys)

    - by KPL
    Hello people, Here's my USER table CREATE TABLE IF NOT EXISTS `users` ( `id` int(11) NOT NULL AUTO_INCREMENT, `username` varchar(100) NOT NULL, `expiry` varchar(6) NOT NULL, `contact_id` int(11) NOT NULL, `email` varchar(255) NOT NULL, `password` varchar(100) NOT NULL, `level` int(3) NOT NULL, `active` tinyint(4) NOT NULL DEFAULT '1', PRIMARY KEY (`id`,`email`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=1 ; And here's my contact_info table CREATE TABLE IF NOT EXISTS `contact_info` ( `id` int(11) NOT NULL AUTO_INCREMENT, `name` varchar(255) NOT NULL, `email_address` varchar(255) NOT NULL, `company_name` varchar(255) NOT NULL, `license_number` varchar(255) NOT NULL, `phone` varchar(30) NOT NULL, `fax` varchar(30) NOT NULL, `mobile` varchar(30) NOT NULL, `category` varchar(100) NOT NULL, `country` varchar(20) NOT NULL, `state` varchar(20) NOT NULL, `city` varchar(100) NOT NULL, `postcode` varchar(50) NOT NULL, PRIMARY KEY (`id`,`email_address`), ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=1 ; The system uses username to login users.I want to modify it in such a way that it uses email for login. But there's no email_address in users table. I have added foreign key - email in user table(which is email_address in contact_info). How should I query database?

    Read the article

< Previous Page | 11 12 13 14 15 16 17 18 19 20 21 22  | Next Page >